Given a function, ulps(x, y), that takes two floating point parameters, x and y, and returns the number of ulps (floating-point intervals) between x and y.
So, we have to find the number of ulps (floating-point intervals) between two given numbers.##Algorithm1. Check the input parameters for special conditions.2. Find the exponents for both input parameters in the machine base (base).3. Examine the exp for both parameters:a.
If they are the same: count the intervals between them. (Remember that the spacing is for each interval [,+1])b. If they differ by one: add the intervals from the smaller number to xp+1 to the intervals from xp+1 to the larger number.c. If they differ by more than one: In addition to the number of intervals in part b, add the numbers of intervals in the exponent ranges in between the exponents of these two numbers.##Code.
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Preattentive Attributes in a Data Visualization. Which of the following statements about the use of preattentive attributes in a data visualization are true? (Select all that apply.)
The use of preattentive attributes reduces the cognitive load required by the audience to interpret the information conveyed by a data visualization.
Preattentive attributes can be used to draw the audience’s attention to certain parts of a data visualization.
Overuse of preattentive attributes can lead to clutter and can be distracting to the audience.
Preattentive attributes include attributes such as proximity and enclosure.
The use of preattentive attributes reduces the cognitive load required by the audience to interpret the information conveyed by a data visualization.
What are preattentive attributes and how do they impact data visualization?Preattentive attributes are visual cues that our brains automatically and quickly process before conscious attention is engaged. These attributes help in the effective communication of information through data visualization.
When preattentive attributes are used appropriately, they can significantly reduce the cognitive load on the audience. By leveraging attributes like color, size, and shape, important patterns and relationships within the data can be highlighted, making it easier for the audience to interpret the information. This reduces the effort required to analyze the visualization and improves the overall comprehension.
Furthermore, preattentive attributes can be strategically employed to direct the audience's attention to specific parts of the visualization. For example, using a distinct color or shape for important data points or employing motion or orientation cues can effectively draw attention and emphasize particular elements or trends.
However, it is crucial to avoid overusing preattentive attributes, as excessive visual cues can create clutter and lead to distraction. When used sparingly and purposefully, preattentive attributes enhance data visualization by making it more accessible and engaging for the audience.
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Question:
The weekly hours for all the employees at your company are stored in the file called Employee_hours.txt. Each row records an employee’s seven-day work hours with seven columns. For example, the following table stores the work hours for eight employees:
Employee
Su
M
T
W
Th
F
Sa
1
2
4
3
4
5
8
8
2
7
3
4
3
3
4
4
3
3
3
4
3
3
2
2
4
9
3
4
7
3
4
1
5
3
5
4
3
6
3
8
6
3
4
4
6
3
4
4
7
3
7
4
8
3
8
4
8
6
3
5
9
2
7
9
Write a program that reads the employee information from the file and store it in a two-dimentional list. Then displays the following information:
employees and their total hours in decreasing order of the total hours (For example, using the above data employee 8 would be listed first with a total of 41 hours, employee 7 would be listed next with a total of 37 hours, etc.)
total hours worked for each day of the week: Sunday through Saturday
** You may only use tools and techniques that we covered in class. You cannot use tools, methods, keyword, etc. from sources outside of what is covered in class.
Here is the employee_hours.txt file information:
Employee Su M T W Th F Sa
1 2 4 3 4 5 8 8
2 7 3 4 3 3 4 4
3 3 3 4 3 3 2 2
4 9 3 4 7 3 4 1
5 3 5 4 3 6 3 8
6 3 4 4 6 3 4 4
7 3 7 4 8 3 8 4
8 6 3 5 9 2 7 9
The Python code reads employee information from a file, stores it in a two-dimensional list, displays employees and their total hours in decreasing order, and shows total hours worked for each day of the week.
The following is the Python code to read the employee information from the file and store it in a two-dimensional list. After that, it displays employees and their total hours in decreasing order of the total hours.
Finally, it displays total hours worked for each day of the week (Sunday through Saturday). This is the program for the same.
# Read employee information from file
with open('Employee_hours.txt', 'r') as file:
lines = file.readlines()
# Remove header line and split data into rows and columns
data = [line.strip().split() for line in lines[1:]]
# Convert hours to integers
data = [[int(hour) for hour in row] for row in data]
# Calculate total hours for each employee
total_hours = [sum(row[1:]) for row in data]
# Sort employees by total hours in decreasing order
sorted_employees = sorted(zip(data, total_hours), key=lambda x: x[1], reverse=True)
# Display employees and their total hours
print("Employees and their total hours (in decreasing order):")
for employee, total in sorted_employees:
print(f"Employee {employee[0]}: {total} hours")
# Calculate total hours for each day of the week
day_totals = [sum(row[i] for row in data) for i in range(1, 8)]
# Display total hours for each day of the week
print("\nTotal hours for each day of the week:")
days = ['Su', 'M', 'T', 'W', 'Th', 'F', 'Sa']
for day, total in zip(days, day_totals):
print(f"{day}: {total} hours")
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2. LetterCheck a. Write a Python program (LetterCheck.py) that checks if a letter is in the middle of the alphabet, i.e. between the letters H−Q (including H, but not including Q ). The program will prompt the user to enter a letter or a digit, and print True, if the letter is in the middle of the alphabet, between H and Q, False otherwise. (A similar program is shown on slide 19 of lecture 05 ).
The Python program, LetterCheck.py, checks whether a given letter is in the middle of the alphabet, specifically between H and Q. It prompts the user to input a letter or digit and then prints True if the letter falls between H and Q (including H but excluding Q), and False otherwise.
How to check if a letter is in the middle of the alphabet?To determine if a letter is in the middle of the alphabet, we can compare its ordinal value with the ordinals of H and Q.
In Python, we can obtain the ordinal value of a character using the built-in ord() function. The ordinal values for H and Q are 72 and 81, respectively.
Therefore, to check if a letter is in the desired range, we need to ensure its ordinal value is greater than or equal to 72 and less than 81.
To implement this logic, we can write a Python program that follows these steps:
Prompt the user to enter a letter or digit.Store the input in a variable.Convert the input to uppercase using the upper() method to handle lowercase letters.Get the ordinal value of the input letter using the ord() function.Compare the ordinal value with the range of 72 to 81 using the comparison operators.Print True if the letter is in the middle of the alphabet, and False otherwise.Learn more about: Python program
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I inputted this code for my card object for 52 cards in java, but it presumably giving me the output as 2 through 14 for the suit where it supposed to give me 2 through 10, J, Q, K, A. What can I change here to make the output as supposed to be ?
public Deck() {
deck = new Card[52];
int index = 0;
for (int i = 2; i < 15; i++) {
deck[index] = new Card("D", i);
index++;
}
for (int i = 2; i < 15; i++) {
deck[index] = new Card("C", i);
index++;
}
for (int i = 2; i < 15; i++) {
deck[index] = new Card("H", i);
index++;
}
for (int i = 2; i < 15; i++) {
deck[index] = new Card("S", i);
index++;
}
}
To correct the output of the code for the card object, you can modify the for loops to iterate from 2 to 11 instead of 2 to 15. This change will ensure that the output includes numbers from 2 to 10, along with the face cards J, Q, K, and A.
The issue with the current code lies in the loop conditions used to initialize the card objects. In the given code, the for loops iterate from 2 to 15 (exclusive), resulting in numbers from 2 to 14 being assigned to the cards. However, you require the output to include numbers from 2 to 10, along with the face cards J, Q, K, and A.
To achieve the desired output, you need to modify the loop conditions to iterate from 2 to 11 (exclusive) instead. This change ensures that the card objects are initialized with the numbers 2 to 10. Additionally, the face cards J, Q, K, and A can be assigned manually within the loop using appropriate conditional statements or switch cases.
By making this modification, the card objects within the deck array will be initialized correctly, providing the expected output with numbers 2 to 10 and face cards J, Q, K, and A for each suit.
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Write a program that takes a positive integer as the height of the triangle and prints an alphabetical triangle, using lowercase English letters as shown below. Each subsequent row of the triangle should increase in length by two letters.
Make sure your program validates the user input. If the user does not input a positive integer, print "Invalid input."
ex)
Enter the height:
6
a
bcd
efghi
jklmnop
qrstuvwxy
zabcdefghij
To create a program that prints an alphabetical triangle based on user input, follow these steps:
1. Prompt the user to enter the height of the triangle.
2. Validate the user input to ensure it is a positive integer.
3. If the input is valid, use a loop to print each row of the triangle, increasing the length by two letters.
The task is to write a program that generates an alphabetical triangle based on the height provided by the user. The triangle should be formed using lowercase English letters, starting from 'a' and increasing by two letters for each subsequent row.
In the program, the user is prompted to enter the height of the triangle. The input needs to be validated to ensure it is a positive integer. This can be done by checking if the input is greater than zero and an integer.
Once the input is validated, a loop can be used to print each row of the triangle. The loop should iterate from 0 to the height minus 1. In each iteration, the row should be printed, starting from 'a' and incrementing by two letters using another loop.
By following these steps, the program will generate the desired alphabetical triangle based on the user's input. If the input is invalid, such as a negative number or a non-integer value, the program will display the message "Invalid input."
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hi i already have java code now i need test cases only. thanks.
Case study was given below. From case study by using eclipse IDE
1. Create and implement test cases to demonstrate that the software system have achieved the required functionalities.
Case study: Individual income tax rates
These income tax rates show the amount of tax payable in every dollar for each income tax bracket depending on your circumstances.
Find out about the tax rates for individual taxpayers who are:
Residents
Foreign residents
Children
Working holiday makers
Residents
These rates apply to individuals who are Australian residents for tax purposes.
Resident tax rates 2022–23
Resident tax rates 2022–23
Taxable income
Tax on this income
0 – $18,200
Nil
$18,201 – $45,000
19 cents for each $1 over $18,200
$45,001 – $120,000
$5,092 plus 32.5 cents for each $1 over $45,000
$120,001 – $180,000
$29,467 plus 37 cents for each $1 over $120,000
$180,001 and over
$51,667 plus 45 cents for each $1 over $180,000
The above rates do not include the Medicare levy of 2%.
Resident tax rates 2021–22
Resident tax rates 2021–22
Taxable income
Tax on this income
0 – $18,200
Nil
$18,201 – $45,000
19 cents for each $1 over $18,200
$45,001 – $120,000
$5,092 plus 32.5 cents for each $1 over $45,000
$120,001 – $180,000
$29,467 plus 37 cents for each $1 over $120,000
$180,001 and over
$51,667 plus 45 cents for each $1 over $180,000
The above rates do not include the Medicare levy of 2%.
Foreign residents
These rates apply to individuals who are foreign residents for tax purposes.
Foreign resident tax rates 2022–23
Foreign resident tax rates 2022–23
Taxable income
Tax on this income
0 – $120,000
32.5 cents for each $1
$120,001 – $180,000
$39,000 plus 37 cents for each $1 over $120,000
$180,001 and over
$61,200 plus 45 cents for each $1 over $180,000
Foreign resident tax rates 2021–22
Foreign resident tax rates 2021–22
Taxable income
Tax on this income
0 – $120,000
32.5 cents for each $1
$120,001 – $180,000
$39,000 plus 37 cents for each $1 over $120,000
$180,001 and over
$61,200 plus 45 cents for each $1 over $180,000
The given case study presents the income tax rates for different categories of individual taxpayers, including residents, foreign residents, children, and working holiday makers. It outlines the tax brackets and rates applicable to each category. The main purpose is to calculate the amount of tax payable based on the taxable income. This involves considering different income ranges and applying the corresponding tax rates.
1. Residents:
For individuals who are Australian residents for tax purposes.Tax rates for the 2022-23 and 2021-22 financial years are provided.Medicare levy of 2% is not included in the above rates.The tax brackets and rates are as follows:
Taxable income 0 – $18,200: No tax payable.Taxable income $18,201 – $45,000: Taxed at 19 cents for each dollar over $18,200.Taxable income $45,001 – $120,000: Taxed at $5,092 plus 32.5 cents for each dollar over $45,000.Taxable income $120,001 – $180,000: Taxed at $29,467 plus 37 cents for each dollar over $120,000.Taxable income $180,001 and over: Taxed at $51,667 plus 45 cents for each dollar over $180,000.2. Foreign residents:
Applicable to individuals who are foreign residents for tax purposes.Tax rates for the 2022-23 and 2021-22 financial years are provided.The tax brackets and rates are as follows:
Taxable income 0 – $120,000: Taxed at 32.5 cents for each dollar.Taxable income $120,001 – $180,000: Taxed at $39,000 plus 37 cents for each dollar over $120,000.Taxable income $180,001 and over: Taxed at $61,200 plus 45 cents for each dollar over $180,000.3. Children and working holiday makers:
The case study does not provide specific tax rates for children and working holiday makers.Additional research or information would be needed to determine the applicable rates for these categories.The given case study offers information on income tax rates for different categories of individual taxpayers, such as residents and foreign residents. It allows for the calculation of tax payable based on the taxable income within specific income brackets. The rates provided can be utilized to accurately determine the amount of tax owed by individuals falling within the respective categories. However, specific tax rates for children and working holiday makers are not included in the given information, necessitating further investigation to determine the applicable rates for these groups.
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Question 5 0/2 pts How many major Scopes does JavaScript have? 1 4+ 2 3
JavaScript has three major Scopes.
In JavaScript, scope refers to the accessibility or visibility of variables, functions, and objects in some particular part of your code during runtime. JavaScript has three major types of scopes: global scope, function scope, and block scope.
1. Global Scope: Variables declared outside any function or block have global scope. They can be accessed from anywhere in the code, including inside functions or blocks. Global variables are accessible throughout the entire program.
2. Function Scope: Variables declared inside a function have function scope. They are only accessible within that specific function and its nested functions. Function scope provides a level of encapsulation, allowing variables to be isolated and not interfere with other parts of the code.
3. Block Scope: Introduced in ES6 (ECMAScript 2015), block scope allows variables to be scoped to individual blocks, such as if statements or loops, using the `let` and `const` keywords. Variables declared with `let` and `const` are only accessible within the block where they are defined. Block scope helps prevent variable leaks and enhances code clarity.
In summary, JavaScript has three major scopes: global scope, function scope, and block scope. Each scope has its own set of rules regarding variable accessibility and lifetime.
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< A.2, A.7, A.9> The design of MIPS provides for 32 general-purpose registers and 32 floating-point registers. If registers are good, are more registers better? List and discuss as many trade-offs as you can that should be considered by instruction set architecture designers examining whether to, and how much to, increase the number of MIPS registers.
Increasing the number of registers in the MIPS instruction set architecture presents several trade-offs that need to be carefully considered by designers. While more registers may seem advantageous, there are both benefits and drawbacks to this approach.
Increasing the number of MIPS registers offers benefits such as reducing memory access time and improving performance. However, it also presents trade-offs in terms of increased complexity and potential resource wastage.
One benefit of having more registers is the reduced need for memory access. Registers are faster to access than memory, so a larger number of registers can help reduce the number of memory accesses required by a program. This leads to improved performance and overall efficiency.
On the other hand, increasing the number of registers adds complexity to the design. More registers mean additional hardware is required to support them, which can lead to increased costs and more intricate control logic. This complexity can impact the overall efficiency and scalability of the processor.
Furthermore, more registers may also result in underutilization. If a program does not use all the available registers, the additional registers will remain unused, wasting valuable resources. This underutilization can potentially offset the benefits gained from having more registers.
Another trade-off to consider is the impact on code size. Increasing the number of registers often requires longer instruction encodings, which can result in larger code size. This can have implications for memory usage, cache performance, and overall system efficiency.
In conclusion, while more registers in the MIPS instruction set architecture can offer advantages in terms of reduced memory access and improved performance, there are trade-offs to consider. These include increased complexity, potential resource wastage, and the impact on code size. Designers need to carefully evaluate these factors to determine the optimal number of registers for a given architecture.
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The below is the VIF of independent variables.
Also assume that the ascending order of important variables is region1, region2, Overtime, Partime, Remote, Total.Staff and Total.Labor. Thus Total.Labor is the most important independent variable for this regression model.
Total.Staff Remote Total.Labor Overtime region1 region2 Partime
120.009956 1.256192 13.34 10.45 1.581673 1.749834 100.3
Which one do we need to eliminate first?
a.region1
b.Partime
c.region2
d.We do not need to elimiate any independent variable.
e.Total.Staff
Therefore, the correct answer is e. Total.Staff. The correct answer is e
VIF stands for the Variance Inflation Factor.
It is a metric used to assess multicollinearity in a regression analysis. The multicollinearity occurs when two or more independent variables are strongly correlated with one another.
This problem can cause the estimates of the coefficients of the individual independent variables to be imprecise and sometimes misleading.
Therefore, we may want to eliminate some independent variables, but which one should be eliminated first?
According to the problem, the ascending order of important variables is region1, region2, Overtime, Partime, Remote, Total.Staff, and Total.Labor.
Thus Total.Labor is the most important independent variable for this regression model.
As we can see from the table, VIF values greater than 10 are generally considered to indicate a problematic amount of multicollinearity.
According to this threshold, we need to eliminate the independent variable with the highest VIF value, which is Total.Staff (VIF = 120.009956), to reduce the amount of multicollinearity in the regression analysis.
Therefore, the correct answer is e. Total.Staff.
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Java please... Write a program that reads an int N from the user, then computes (1+1.0/N) N
and prints out the result. (Use Math.pow( x,N) to calculate (x N
.). Run your program with larger and larger values of N and note what happens. **Add a comment in your code that describes your observations. Hint: the limiting result is a special math constant.
The solution to the program that reads an int N from the user, then computes (1+1.0/N) N and prints out the result in Java is given below.
pow function in Java to compute (x N.). It accepts an integer from the user, N.1) Create a scanner object and import java.util.Scanner2) Read an integer N from the user using scan. next Int()3) Compute (1+1.0/N) N using Math. pow() function.
The Math. pow (x,y) function returns the value of x raised to the power of y.4) Store the result in a variable called res.5) Print out the result of the expression using System. out. println ()6) Add a comment in the code describing what happens as N increases, which is "As N increases, the value of (1+1/N)^N tends to Euler's Number 'e'".
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Using Eclipse
Create a program that prompts the user to enter a grade with two decimal points and display its corresponding letter grade.
A = 89.5 – 100
B = 79.5 – 89
C = 69.5 – 79
D = 59.5 = 69
F = below 59.5
Here's a program in Java using Eclipse that prompts the user to enter a grade and displays its corresponding letter grade:
```java
import java.util.Scanner;
public class GradeConverter {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the grade: ");
double grade = scanner.nextDouble();
String letterGrade;
if (grade >= 89.5) {
letterGrade = "A";
} else if (grade >= 79.5) {
letterGrade = "B";
} else if (grade >= 69.5) {
letterGrade = "C";
} else if (grade >= 59.5) {
letterGrade = "D";
} else {
letterGrade = "F";
}
System.out.println("Letter grade: " + letterGrade);
scanner.close();
}
}
```
1. The program starts by creating a `Scanner` object to read input from the user.
2. The user is prompted to enter the grade using `System.out.print("Enter the grade: ")` and `scanner.nextDouble()` reads the grade entered by the user.
3. The program then uses an `if-else` ladder to determine the letter grade based on the grade entered. Each condition checks if the grade falls within a specific range and assigns the corresponding letter grade to the `letterGrade` variable.
4. Finally, the program displays the letter grade using `System.out.println("Letter grade: " + letterGrade)`.
This program allows the user to enter a grade with two decimal points and converts it into a corresponding letter grade based on the given ranges. It demonstrates the use of conditional statements (`if-else`) to perform the grade conversion. By following the logic of the conditions, the program accurately determines the appropriate letter grade for the entered grade.
The program can be further enhanced by implementing error handling to handle invalid inputs, such as entering a negative grade or a grade above 100. Additionally, it can be expanded to include additional grade ranges or alternative grading systems if desired.
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Using the provided code and assuming the linked list already bas the data "Abe", "efG", "HU", "KLm", "boP", the following code snippet"s purpose is to replace all "target" Strings with anather String (the parameter "rValue"). Does this method work as described and if so, if we assume the value "Abe" is given as the target, then what is the resalting linked list values? If the method does not work as described, then detail all syntax, run-time, and logic errors and how they may be fixed. (topts) poblic void replacenl1(string target, string rvalue) 10. Using the provided code and assuming the linked list alrady has the data "Abe", "efG", "HU", "2Lm", "hol", the following code snippet's purpose is to remere the first five elements of tho linked list. Does this mothod work as described and if so, what is the resulting linked list values? If the method does not woek as described, then detail all syntax, run-time, and logic errors and bow sthey may be fived. (10pss) piallie vold removefirsts() y For Questions 07−10 you may assume the following String linked list code is provided. public class 5tringlt. 1 public class Listhode र private String data; private Listliode link; public Listiode(String aData, Listhode aLirk) ई data - abataz link - alink; ) ] private Listiode head;
Using the provided code and assuming the linked list already has the data "Abe", "efG", "HU", "KLm", "boP", the purpose of the following code snippet is to replace all "target" Strings with another String (the parameter "rValue").Does this method work as described?The method does not work as described. There are a few syntax and runtime errors in the method that prevent it from replacing all "target" Strings with another String. This is the original code snippet:public void replacenl1(string target, string rvalue) { ListNode node = head; while (node != null) { if (node.getData() == target) { node.setData(rvalue); } node = node.getLink(); } } Here are the syntax and runtime errors and how they may be fixed:Syntax errors:1.
The method name is misspelled. It should be "replaceln1" instead of "replacenl1".2. The data type "ListNode" is not defined. It should be replaced with "Listhode".3. The method "getData()" is not defined. It should be replaced with "getData()".4. The method "getLink()" is not defined. It should be replaced with "link".5. The comparison operator "==" is used instead of ".equals()".Runtime errors:1. The method does not check if the parameter "target" is null. If it is null, then the method will throw a "NullPointerException" when it tries to call the ".equals()" method.2
. The method does not handle the case where the parameter "rvalue" is null. If it is null, then the method will throw a "NullPointerException" when it tries to call the "setData()" method. Here is the corrected code snippet:public void replaceln1(String target, String rvalue) { Listhode node = head; while (node != null) { if (node.data.equals(target)) { node.data = rvalue; } node = node.link; } }If we assume the value "Abe" is given as the target, then the resulting linked linked list.Does this method work as described?The method does work as described. This is the original code snippet:public void removefirsts() { Listhode node = head; int count = 0; while (node != null && count < 5) { node = node.link; count++; } head = node; }The resulting linked list values after the method is called are: "hol".
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The provided code is given below :void ReplaceNl1(string target, string rvalue) { List Node node; if (head != null) { if (head. Data == target) head. Data = rvalue; node = head. Link; while (node != null) { if (node. Data == target) node.
Data = rvalue; node = node.Link; } } }This method is used to replace all target Strings with another string (the parameter rValue). Yes, this method works as described.If we assume that the value "Abe" is given as the target, then the resulting linked list values are as follows: "Abe", "efG", "HU", "KLm", "boP" -> "abe", "efG", "HU", "KLm", "boP".The RemoveFirsts method is given below.public void RemoveFirsts() { ListNode node; node = head; while (node.Link != null) node = node.Link; node = null; } This method is used to remove the first five elements of the linked list. This method does not work as described.
There are some errors in this method, which are as follows:1) Syntax Error: The variable type is not specified.2) Logical Error: The first five elements of the linked list are not being removed.Only the last node is being removed. So, this method needs to be fixed in order to work as described. The updated method is given below.public void RemoveFirsts() { ListNode node; if (head != null) { node = head; for (int i = 1; i <= 5; i++) { node = node.Link; if (node == null) return; } head = node; } }The resulting linked list values are as follows: "hol".
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The following message is enciphered using a shift. By using letter frequencies, determine the likeliest values of the shift and use a process of elimination to obtain the plaintext. Show your work how you solve it.
EDGHE TGXIN XHCDI LXIWD JIBPC NUTPG HPCSS XHIPH ITHPC SPSKT GHXIN XHCDI LXIWD JIRDB UDGIH PCSWD ETH
The message is enciphered using a shift. By using letter frequencies, determine the likeliest values of the shift and use a process of elimination to obtain the plaintext. Show your work how you solve it.
As we know that, in English language, the most frequent letter is E, so we will look for the second-most frequent letter in the encrypted message, it would be H as in English, which represents a shift of three as we use the alphabet;
A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z.
We can test this by replacing the letter of the encrypted message by the decrypted letter by shifting it by three. For example, the first word of the encrypted message is "EDGHE", so we can replace the letter E with B, then we replace the letter D with A, and so on.
The final decrypted message after replacing all the letters is:
BEACH WHALE SUNG DANCE HONEY STICKY HONEY WITH PANTS WHICH SUNG DANCE HONEY STICKY WHALE FISH HONEY BEEHIVE PANIC BE.
It seems to be a nonsense message, but the main idea is to test all the possible shift values. we can try a shift of four, and so on, until we find a decrypted message with meaning.
As the answer requires a maximum of 120 words, this would suffice.
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Create a Ticket class. The design is up to you. Write the necessary methods. Part II Create a MovieTicket class that inherits from Ticket class. The design is up to you. Write the necessary methods. Part III Create a Theater class. The design is up to you. Write the necessary methods, Part IV Implement a method that returns the total price of the MovieTickets in the Theater. Part V Implement a method that removes all MovieTickets that the date is expired. You can use int or String objects to represent the date.
In the Ticket class, a variable is created to store the price of the ticket. A constructor is created to set the price of the ticket. A method is created to return the price of the ticket.
The Movie Ticket class is created as a subclass of the Ticket class using the extends keyword. A variable is created to store the date of the ticket. A constructor is created to set both the price and date of the ticket. A method is created to return the date of the ticket .Part III: Theater Class creation Here is the main answer to create a Theater class: import java.
The Theater class is created to keep track of a list of movie tickets. An Array List is created to store the movie tickets. A method is created to add a movie ticket to the list. A method is created to get the total price of all the movie tickets in the list. A method is created to remove all the expired movie tickets from the list using a String object to represent the date
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Describe how shared Ethernet controls access to the medium. What is the purpose of SANs and what network technologies do they use?
Shared Ethernet is a network setup that allows multiple devices to share the same communication channel in a LAN. Access to the medium is managed by a collision-detection algorithm that monitors the cable for collisions and only allows one device to transmit data at a time.
What is the purpose of SANs?
SAN (Storage Area Network) is a type of high-speed network that connects data storage devices with servers and provides access to consolidated storage that is often made up of numerous disks or tape drives. The purpose of SANs is to enhance storage capabilities by providing access to disk arrays and tape libraries across various servers and operating systems.
SANs are used to extend the capabilities of local storage, which is limited in terms of capacity, scalability, and manageability. They offer a more flexible and scalable solution for organizations that need to store and access large amounts of data, as they can handle terabytes or even petabytes of data.
Network technologies used by SANs The primary network technologies used by SANs include Fibre Channel, iSCSI, and Infini Band. These technologies are used to provide high-speed connections between storage devices and servers, and they enable storage devices to be shared across multiple servers. Fibre Channel is a high-speed storage networking technology that supports data transfer rates of up to 128 Gbps.
It uses a dedicated network for storage traffic, which eliminates congestion and improves performance. iSCSI (Internet Small Computer System Interface) is a storage networking technology that allows SCSI commands to be transmitted over IP networks.
It enables remote access to storage devices and provides a more cost-effective solution than Fibre Channel.InfiniBand is a high-speed interconnect technology that supports data transfer rates of up to 100 Gbps. It is used primarily in high-performance computing environments, such as supercomputers and data centers, where low latency and high bandwidth are critical.
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Write a program that does the following... (a) Declare a variable. (b) Assign it a value. (c) Declare a pointer variable (d) Assign the pointer to the address of the first variable. (e) Display the values of both variables. (f) Display the addresses of both variables. (g) Display the value of the dereferenced pointer. Run the program, and submit the code and the results through Canvas Assignments.
Here is the program which is doing the following operations:
a. Declaring a variable
b. Assigning a value to it
c. Declaring a pointer variable
d. Assigning the pointer to the address of the first variable
e. Displaying the values of both variables
f. Displaying the addresses of both variables
g. Displaying the value of the dereferenced pointer.
#include int main()
{ int a=30; int *p; p=&a; printf("The value of a is : %d \n", a);
printf("The value of a is : %p \n", &a);
printf("The value of p is : %p \n", p);
printf("The value of *p is : %d \n", *p);
return 0; }
Here, int is the datatype of the variable which we have used in this program. We have used p to store the address of the variable a. And, &a represents the address of the variable a.
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python
Write a program that takes a filename as input. The program should open that file and print every single word in that file backwards.
To write a Python program that takes a filename as input, opens that file, and prints every single word in that file backwards, you can use the following code:```
filename = input("Enter filename: ")
with open(filename, "r") as file:
for line in file:
words = line.split()
for word in words:
print(word[::-1])
The code starts by taking a filename as input from the user using the input() function. This filename is then opened using the open() function and the file object is stored in a variable called file. The "r" argument in the open() function specifies that the file is being opened for reading.Next, the code reads the file line by line using a for loop. Each line is split into a list of words using the split() method.
The for loop then iterates over each word in this list and prints the word backwards using slicing (word[::-1]).The slicing operation [::-1] is used to reverse a string. It means the string is sliced from the beginning to the end, with a step size of -1 (i.e., the string is reversed).So, the above code will print every single word in the file specified by the user, in reverse order.
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What is greatest common divisor (GCD) of 270 and 192 using Euclidean algorithm or a calculator.
The greatest common divisor (GCD) of 270 and 192 using the Euclidean algorithm or a calculator is 6.
The Euclidean Algorithm is a popular method to find the greatest common divisor (GCD) of two numbers. It is a stepwise process of repeatedly subtracting the smaller number from the larger one until the smaller number becomes 0. The last non-zero number in the series of subtractions is the GCD of the two numbers. Given the numbers 270 and 192, we can use the Euclidean Algorithm to find their GCD as follows:
Step 1: Divide 270 by 192 to get the quotient and remainder:270 ÷ 192 = 1 remainder 78
Step 2: Divide 192 by 78 to get the quotient and remainder:192 ÷ 78 = 2 remainders 36
Step 3: Divide 78 by 36 to get the quotient and remainder:78 ÷ 36 = 2 remainders 6
Step 4: Divide 36 by 6 to get the quotient and remainder:36 ÷ 6 = 6 remainders 0
Since the remainder is 0, we stop here and conclude that the GCD of 270 and 192 is 6.
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To find the greatest common divisor (GCD) of 270 and 192 using the Euclidean algorithm, we will divide the larger number by the smaller number and continue dividing the divisor by the remainder until the remainder is 0.
The last divisor will be the GCD.1st Division:270 ÷ 192 = 1 with a remainder of 78 2nd Division:192 ÷ 78 = 2 with a remainder of 36 3rd Division:78 ÷ 36 = 2 with a remainder of 6 4th Division:36 ÷ 6 = 6 with a remainder of 0. Therefore, the GCD of 270 and 192 using the Euclidean algorithm is 6.To verify, you can check that 270 and 192 are both divisible by 6 without leaving any remainder.
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With LOOP instruction the jump gets executed before: Select one: a. When carry flag is set b. CX reaches zero c. None of the listed here d. DI reaches zero e. SI reaches zero
With LOOP instruction the jump gets executed before CX reaches zero (option b).LOOP is a repetitive instruction in x86 assembly language, which executes the loop statement repeatedly based on the value of the CX register until CX reaches zero.
The jump occurs before CX reaches zero. This is done to help avoid writing extra code to adjust the CX value or to jump to the loop body.
Here's how LOOP instruction works:
1. It checks the CX register value. If the CX register value is zero, it exits the loop and continues with the next instruction.
2. If the CX register value is not zero, the jump is executed, and the program jumps to the target label specified by the LOOP instruction.
3. The CX register value is decremented by 1 after the jump.The most common use of the LOOP instruction is for repetitive operations such as copying an array, summing an array, or performing other similar tasks.
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How do you optimize search functionality?.
To optimize search functionality, there are several steps you can take and they are as follows: 1. Improve the search algorithm. 2. Implement indexing. 3. Use relevance ranking. 4. Faceted search. 5. Optimize search infrastructure.
To optimize search functionality, there are several steps you can take and they are as follows:
1. Improve search algorithm: A search algorithm is responsible for returning relevant results based on the user's query. You can optimize it by using techniques such as stemming, which reduces words to their root form (e.g., "running" becomes "run"). This helps capture different forms of the same word. Additionally, consider using synonyms to broaden search results and improve accuracy.
2. Implement indexing: Indexing involves creating a searchable index of the content in your database. By indexing relevant data, you can speed up the search process and improve the search results. This can be done by using inverted indexes, where each unique term is associated with a list of documents containing that term.
3. Use relevance ranking: Relevance ranking is important to display the most relevant results at the top. You can achieve this by considering factors like keyword density, the proximity of keywords, and the popularity of a document (e.g., number of views or ratings). You can also use machine learning algorithms to analyze user behavior and feedback to improve the ranking over time.
4. Faceted search: Faceted search allows users to filter search results based on specific attributes or categories. For example, if you have an e-commerce website, users can filter products by price range, color, brand, etc. Implementing faceted search helps users narrow down their search results quickly and efficiently.
5. Optimize search infrastructure: The performance of your search functionality can be improved by optimizing your search infrastructure. This includes using efficient hardware, scaling horizontally to handle high query volumes, and utilizing caching mechanisms to store frequently accessed results.
6. User feedback and testing: Regularly collect user feedback and conduct testing to understand how users interact with your search functionality. Analyze search logs, conduct A/B testing, and consider user suggestions to identify areas for improvement and enhance the overall user experience.
Remember, optimizing search functionality is an iterative process. Continuously monitor and analyze the performance of your search system and make adjustments based on user feedback and search analytics.
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what is the output of the following code is z is -1? x = 0 y = 5 z = -1 while x if x == z: print('x == z') break x += 1 else: print('x == y')
The output of the given code, when z is -1, will be "x == y."
The code snippet provided initializes three variables: x = 0, y = 5, and z = -1. It then enters a while loop with the condition "x if x == z." In each iteration of the loop, the code checks if x is equal to z. If the condition is true, it prints "x == z" and breaks out of the loop. However, if the condition is false, the code increments the value of x by 1 and continues to the next iteration.
In the case where z is -1, the loop condition "x if x == z" will never be true because the initial value of x is 0 and z is -1. Therefore, the code will not print "x == z" or break out of the loop. After the loop finishes executing, the code reaches the "else" block and prints "x == y" because the condition x == z was never satisfied.
In summary, since x is never equal to z during the execution of the loop, the output of the given code, when z is -1, will be "x == y."
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What fundamental set of programs control the internal operations of the computers hardware?
The fundamental set of programs that control the internal operations of a computer's hardware is the operating system.
An operating system is a program that acts as an intermediary between the user and the hardware. It controls the overall operation of the computer system, including hardware, applications, and user interface. It manages the allocation of system resources such as memory and processing power to the different applications that are running on the computer. An operating system is a software that manages computer hardware and software resources and provides common services for computer programs. The operating system is the most essential type of system software in a computer system.
An operating system is a fundamental set of programs that controls the internal operations of a computer's hardware. It manages the allocation of system resources such as memory and processing power to the different applications that are running on the computer. An operating system is a program that acts as an intermediary between the user and the hardware. It controls the overall operation of the computer system, including hardware, applications, and user interface. Operating systems are essential for all modern computers, and without them, we wouldn't be able to run the programs that we need for work, entertainment, and education
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What is deauthentication attack in wireless? Is it the same as dissociation? When/why these attack(s) work/do not work? Please discuss in short by explaining also how they work.
2. What can be done against offline attacks to crack WPA passphrase? Is the answer the same for WPA2?
Deauthentication attack is one of the most common attacks against Wi-Fi networks. It works by sending deauthentication packets to the access point (AP), thus disconnecting all the clients from it.
This type of attack does not require an attacker to have the network's password to carry out the attack. On the other hand, a dissociation attack is different from a deauthentication attack. Dissociation attack is launched by sending a dissociation frame to one of the clients connected to the access point.
The goal is to force the client to disconnect from the network, but the access point is not affected. In a dissociation attack, an attacker needs to have the Wi-Fi network's password to carry out the attack. Both attacks work because of the way Wi-Fi networks are designed. Wi-Fi networks use an open medium, which means that anyone with a wireless device can connect to it. This open medium is also what makes it easy for attackers to launch deauthentication and dissociation attacks. To protect against these attacks, one can use strong encryption and authentication methods like WPA2 and implement MAC filtering. Offline attacks to crack WPA passphrase can be done using a brute-force attack, dictionary attack, or a combination of both. The best defense against offline attacks is to use a strong passphrase, implement network segmentation, and use network security tools to detect and prevent unauthorized access to the network. The answer for WPA2 is the same as WPA.
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Given an integer n>=2 and two nxn matrices A and B of real numbers, find the product AB of the matrices. Your function should have three input parameters a positive integer n and two nxn matrices of numbers- and should return the n×n product matrix. Run your algorithm on the problem instances: a) n=2,A=( 2
3
7
5
),B=( 8
6
−4
6
) b) n=3,A= ⎝
⎛
1
3
6
0
−2
2
2
5
−3
⎠
⎞
,B= ⎝
⎛
.3
.4
−.5
.25
.8
.75
.1
0
.6
⎠
⎞
The product matrix AB of the two given matrices A and B when n=3 is (0.1, 0.5, −2.9, 0, 0.8, −1.5, 2, 5.5, −6).
Given an integer n>=2 and two nxn matrices A and B of real numbers, we can find the product AB of the matrices. A product matrix will be of n × n size.
We can use matrix multiplication to calculate this product. A matrix multiplication is an operation in which the rows of the first matrix multiplied with the corresponding columns of the second matrix. We can apply this operation to calculate the product of two matrices.
Let us take an example of matrix multiplication where n=2, A= ( 2 3 7 5 ), B= ( 8 6 −4 6 ). First, we will write the matrix product formula: AB = (a11.b11+a12.b21), (a11.b12+a12.b22), (a21.b11+a22.b21), (a21.b12+a22.b22)
Here, a11 = 2, a12 = 3, a21 = 7, a22 = 5, b11 = 8, b12 = 6, b21 = −4, b22 = 6AB = (2.8+3.−4), (2.6+3.6), (7.8+5.−4), (7.6+5.6) = (16−12), (12+18), (56+−20), (42+30) = (4), (30), (36), (72)
Thus, the product AB of the given two matrices A and B is the matrix of size n × n that will have elements (4, 30, 36, 72).We can calculate the product matrix for the second problem instance as well using the same approach.
The only change here will be the value of n and the matrices A and B. Hence, the product matrix AB of the two given matrices A and B when n=3 is (0.1, 0.5, −2.9, 0, 0.8, −1.5, 2, 5.5, −6).
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assume the Node class is declared as in the download/demo file. Also assume the following statements have been executed: Node p1 = new Node ("a ", null); Node p2 = new Node ("b", null); Node p3 = new Node("c", null); Show what will be displayed, or ' X ' where an error would occur (it's best to sketch these out on paper) 13. What will be displayed by this code segment? p1.next = p2; System.out.println(p1.data +"n+p1⋅ next.data); Check Answer 13 14. Show what will be displayed, or ' X ' where an error would occur p1=p2; System. out. println(p1.data +"n+p2. data) Check Answer 14 15. Show what will be displayed, or ' X ' where an error would occur p1⋅next=p2; System.out.println(p2.data +"⋯+p2. next.data); Check Answer 15
13. The code segment will display "a b".
14. The code segment will display "b".
15. The code segment will display "b null".
In the first step, the code initializes three Node objects: p1, p2, and p3. Each node is assigned a data value and initially set to point to null.
In step 13, the statement `p1.next = p2;` sets the `next` reference of `p1` to point to `p2`. This means that `p1` is now connected to `p2` in the linked list. Then, `System.out.println(p1.data + " " + p1.next.data);` prints the data of `p1` (which is "a") followed by the data of the node pointed by `p1.next` (which is "b"). So the output will be "a b".
In step 14, the statement `p1 = p2;` assigns the reference of `p2` to `p1`. This means that `p1` now points to the same Node object as `p2`. Therefore, when `System.out.println(p1.data + " " + p2.data);` is executed, it prints the data of the node pointed by `p1` (which is "b") followed by the data of `p2` (which is also "b"). So the output will be "b".
In step 15, the statement `p1.next = p2;` sets the `next` reference of `p1` to point to `p2`. This means that the node pointed by `p1` is now connected to `p2` in the linked list. Then, `System.out.println(p2.data + " " + p2.next.data);` prints the data of `p2` (which is "b") followed by the data of the node pointed by `p2.next` (which is null because `p2.next` is initially set to null). So the output will be "b null".
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Relational databases store information about how data is stored. - This is a modified True/False question. Please provide a True or False position and support you position
True. Relational databases store information about how data is stored.
Explanation: Relational databases are designed to store and manage structured data using a tabular format consisting of tables, rows, and columns. One of the fundamental principles of relational databases is the schema, which defines the structure and organization of the data. The schema includes information about the tables, their relationships, and the attributes or columns within each table.
To effectively store and retrieve data, a relational database management system (RDBMS) needs to understand the underlying structure of the data. This includes details such as the data types of the columns, primary and foreign key relationships, indexes, constraints, and other metadata. This information is typically stored in system tables or catalogs within the database itself.
By storing this information about how data is structured and organized, relational databases enable efficient data storage, retrieval, and manipulation. It allows the RDBMS to enforce data integrity through constraints, perform optimized query execution plans, and ensure consistency across related tables.
In conclusion, relational databases do store information about how data is stored. This information is essential for the RDBMS to manage and manipulate the data effectively, ensuring data integrity and efficient operations within the database.
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Considering how monitoring methodologies work, answer the following question regarding the two monitoring methodologies below:
A. Anomaly monitoring.
B. Behavioural monitoring.
Using a comprehensive example, which of the two methodologies has the potential to be chosen over the other and why? In your answer, also state one example of when each of the methodologies is used and useful.(5)
Q.4.2 Packets can be filtered by a firewall in one of two ways, stateless and stateful packet filtering.
Which type of filtering would you use to stop session hijacking attacks and justify your answer? (4)
Q.4.3 ABC organisation is experiencing a lot of data breaches through employees sharing sensitive information with unauthorised users.
Suggest a solution that would put an end to the data breaches that may be experienced above. Using examples, explain how the solution prevents data breaches. (6)
Q.4.1:Anomaly Monitoring and Behavioral Monitoring are two of the most commonly used monitoring methods in organizations. Anomaly Monitoring analyzes data for unusual occurrences that might indicate a threat, while Behavioral Monitoring looks for anomalies in user behavior patterns.
Q.4.2:To prevent session hijacking attacks, stateful packet filtering should be used. This is because it is able to keep track of session states, which enables it to detect when a session has been hijacked or taken over.
Q.4.3:To stop data breaches that occur due to employees sharing sensitive information with unauthorized users, ABC organization can implement a data loss prevention (DLP) solution.
Q.4.1;Example: For example, let's say that an organization wants to monitor its financial transactions for fraud. In this case, anomaly monitoring would be more effective because it would be able to detect any unusual transactions, such as transactions that fall outside of the norm.
Behavioral monitoring, on the other hand, would be more useful in detecting insider threats, where an employee's behavior suddenly changes and indicates that they may be stealing data or accessing unauthorized files.
Q.4.2.When a session is hijacked, the attacker sends a fake packet to the victim that contains the session ID. Since the stateful firewall keeps track of session states, it will recognize that the fake packet does not match the session state and therefore will not allow it through, thereby preventing the session hijacking attack.
Q.4.3:This solution works by monitoring and detecting when sensitive data is being shared inappropriately, and then blocking the data from being shared. It can do this by using a variety of techniques, such as scanning email attachments, monitoring network traffic, and even analyzing user behavior patterns.
For example, if an employee tries to send an email that contains sensitive data to an unauthorized user, the DLP solution will detect this and block the email from being sent.
Similarly, if an employee tries to access a sensitive file that they are not authorized to access, the DLP solution will detect this and block the access. This prevents data breaches by ensuring that sensitive data is only shared with authorized users and is not leaked to unauthorized users.
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what are the differences between imperative programming languages and declarative programming languages. explain and provide examples.
Imperative programming languages specify how to solve a problem, while declarative programming languages focus on what needs to be done.
To explain the differences between imperative and declarative programming languages.
Imperative programming languages focus on specifying the exact steps and instructions that a computer should follow to solve a problem. They are more concerned with "how" things should be done. Examples of imperative programming languages include C, Java, and Python.
In imperative languages, programmers explicitly define the sequence of steps to accomplish a task. This involves using statements like loops, conditionals, and variables to control program flow. For example, in Python, you might write a loop using the "for" keyword to iterate over a list of numbers and perform a specific action on each item.
On the other hand, declarative programming languages focus on describing what a program should accomplish, without specifying the exact steps or instructions to achieve it. They are more concerned with "what" needs to be done. Examples of declarative programming languages include SQL, Prolog, and HTML.
In declarative languages, programmers define the desired outcome or state, and the language's runtime system takes care of figuring out the most efficient way to achieve it. For instance, in SQL, you would write a query to specify the data you want to retrieve from a database, without worrying about how the database engine executes that query.
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Exercise 5 - Large Integers version 2 - more points for this exercise Modify your previous version to add two large integers and output the result if it is valid. You must utilize functions and here are the three required functions: convert an operand as string to an int array, add valid operands (two big integers as two int arrays), and output one big integer in required format (big integer as one int array). Think about the best way to set up these functions especially how to return result for the add function. Pseudocode is not required, but feel free to use it, especially the add function. Follow the interface below and you must try the following test cases: Enter an expression →1234+72< Enter> 1234+72=1306 Enter an expression −w>987654321+123456789<8nter> n87654721+ 123456789=1111111110 987654321+123456789=1111111110 W 19 digits +1 digit =20 digits (1 and 19 zeros) Enter an express 1 on −−>99999999999999999+ 1eEnter> 9999999999999999999+1=10000000000000000000 11 20 digits +1 digis = averilaw Enter an expreudion _-> 99999999999999999999+1 <हnter> 99999999999999999999+1 = averflow II 21 digits +3 digits = invalid operand(s) Enter an expreselon − - 999999999999999999990+123 Invalid operand (5)
Here's an example implementation in Python that satisfies the requirements:
How to write the codedef convert_operand_to_array(operand):
return [int(digit) for digit in operand]
def add_operands(operand1, operand2):
result = []
carry = 0
len1 = len(operand1)
len2 = len(operand2)
length = max(len1, len2)
for i in range(length):
digit1 = operand1[-i-1] if i < len1 else 0
digit2 = operand2[-i-1] if i < len2 else 0
sum_digits = digit1 + digit2 + carry
result.append(sum_digits % 10)
carry = sum_digits // 10
if carry > 0:
result.append(carry)
result.reverse()
return result
def output_big_integer(big_integer):
return ''.join(str(digit) for digit in big_integer)
# Test Cases
test_cases = [
["1234", "72"],
["987654321", "123456789"],
["99999999999999999", "1"],
["99999999999999999999", "1"],
["999999999999999999990", "123"]
]
for test in test_cases:
operand1 = convert_operand_to_array(test[0])
operand2 = convert_operand_to_array(test[1])
result = add_operands(operand1, operand2)
print(f"{test[0]} + {test[1]} = {output_big_integer(result)}")
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I'm having difficulties understanding BIG O Notation.
Can you please give a coding example of: O(n!), O(n^2), O(nlogn), O(n), O(logn), O(1)
Please explain in depth how the coding example is the following time complexity.
Big O Notation is a way of measuring the time complexity of an algorithm or program. It quantifies the worst-case scenario of an algorithm's runtime based on the input size. In simple terms, it indicates how the execution time or space usage of an algorithm scales with the input size.
Big O Notation is commonly used to describe the following time complexities:
1. O(1): Constant Time - The algorithm's runtime remains constant regardless of the input size.
2. O(log n): Logarithmic Time - The algorithm's runtime grows logarithmically with the input size.
3. O(n): Linear Time - The algorithm's runtime increases linearly with the input size.
4. O(n log n): Linearithmic Time - The algorithm's runtime grows in proportion to n multiplied by the logarithm of n.
5. O(n²): Quadratic Time - The algorithm's runtime is proportional to the square of the input size.
6. O(2^n): Exponential Time - The algorithm's runtime grows exponentially with the input size.
7. O(n!): Factorial Time - The algorithm's runtime grows factorially with the input size.
To understand these complexities better, let's explore coding examples for each of them.
O(n!): Factorial Time - Factorial time complexity is exceptionally complex and involves examining every possible permutation of a given input. An example is printing out all possible permutations of a list of n elements.
O(n²): Quadratic Time - Quadratic time complexity algorithms are inefficient, as they examine all elements of a list in nested loops. An example is sorting an array using the bubble sort algorithm.
O(n log n): Linearithmic Time - Linearithmic time complexity is often used for sorting large data sets or solving divide-and-conquer problems. An example is the Merge sort algorithm.
O(n): Linear Time - Linear time complexity algorithms simply examine each element in a list. An example is printing out all elements of a list.
O(log n): Logarithmic Time - Logarithmic time complexity algorithms reduce the input size by half at each iteration, often using a divide-and-conquer strategy. An example is binary search.
O(1): Constant Time - Constant time complexity algorithms perform a fixed number of operations regardless of the input size. An example is accessing an element of an array by index.
These examples demonstrate the different time complexities and provide insights into how the algorithms' runtime scales with the input size.
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