Computers And Technology College

Write a function that returns a chessboard pattern ("B" for black squares, "W" for white squares). The function takes a number N as input and generates the corresponding board.
Input The first line of the input consists of an integer- num, representing the size of the chessboard.
Output Print N lines consist of N space-separated characters representing the chessboard pattern.

Answers

Answer 1

Answer:

Here is the C++ program.

#include <iostream> //to use input output functions

using namespace std; // to access objects like cin cout

void chessboard(int N){ // function that takes a number N as parameter generates corresponding board

int i, j;

string black = "B"; // B for black squares

string white = "W"; // W for white squares

for(i=1;i<=N;i++){ //iterates through each column of the board

for(j=1;j<=N;j++){ //iterates through each row of the board

if((i+j)%2==0) // if sum of i and j is completely divisible by 2

cout<<black<<" "; //displays B when above if condition is true

else //if (i+j)%2 is not equal to 0

cout<<white<<" "; } // displays W when above if condition is false

cout<<endl; } } //prints the new line

int main(){ //start of the main function

int num; //declares an integer num

cout << "Enter an integer representing the size of the chessboard: "; //prompts user to enter size of chess board

cin >> num; //reads value of num from user

chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern

Explanation:

The function works as follows:

Lets say that N = 2

two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.

The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop for(j=1;j<=N;j++) iterates through each row of chess board.

At first iteration of outer loop:

N = 2

outer loop:

i=1

i<=N is true because i=1 and 1<=2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+1) % 2 == 0

(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.

2%2 As 2 is completely divisible by 2 so 2%2 == 0

Hence the if condition evaluates to true. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+2) % 2 == 0

(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 3

Now

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop to iterate through the next row.

At second iteration of outer loop:

N = 2

outer loop:

i=2

i<=N is true because i=2 and 2 = 2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+1) % 2 == 0

(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+2) % 2 == 0

(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.

4%2 As 4 is completely divisible by 2 so 4%2 == 0

Hence the if condition evaluates to false. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B W

W B

The value of j is incremented to 1.

j = 3

Now

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3

N = 2

outer loop:

i=3

i<=N is false because i=3 and 3>2

So this outer loop ends.

Now the output of this program is:

B W

W B

Screenshot of this program along with its output is attached.

Write A Function That Returns A Chessboard Pattern ("B" For Black Squares, "W" For White Squares). The

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Answers

Answer:

The program written in C++ is as follows'

#include<iostream>

using namespace std;

int main()

{

string names[3];

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cin>>names[i];

}

for (int i = 2; i>= 0;i--)

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Explanation:

This line declares an array for 3 elements

string names[3];

This line prompts user for three names

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Answers

Answer: Provided in the explanation section

Explanation:

Using Code :-

import java.awt.*;

import java.awt.event.*;

import javax.swing.*;

public class SandwichShop

{

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String breadTypes[] = {"Bloomer", "Cob", "Plait"};

JFrame jf;

JPanel p1, p2, p3, p4, mainP;

JList ingredient, bread;

JLabel ingL, breadL, amountL;

JTextField amountT;

JButton amountB, exitB;

SandwichShop()

{

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p2 = new JPanel();

p3 = new JPanel();

p4 = new JPanel();

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p1.add(ingL);

p1.add(ingredient);

p2.add(breadL);

p2.add(bread);

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p3.add(amountT);

p4.add(amountB);

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mainP.add(p2);

mainP.add(p3);

mainP.add(p4);

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jf.add(mainP);

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{

public void actionPerformed(ActionEvent ae)

{

System.exit(0);

}

});

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{

public void actionPerformed(ActionEvent ae)

{

int indexIngredient = ingredient.getSelectedIndex();

int indexBread = bread.getSelectedIndex();

if(indexIngredient == 0 && indexBread == 0)

amountT.setText("100");

if(indexIngredient == 0 && indexBread == 1)

amountT.setText("120");

if(indexIngredient == 0 && indexBread == 2)

amountT.setText("160");

if(indexIngredient == 1 && indexBread == 0)

amountT.setText("190");

if(indexIngredient == 1 && indexBread == 1)

amountT.setText("205");

if(indexIngredient == 1 && indexBread == 2)

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if(indexIngredient == 2 && indexBread == 1)

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});

}

public static void main(String[] args)

{

new SandwichShop();

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Answers

Answer:

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Answer:

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Answer:

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Answer:

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Answer:

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Answer:

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Answer:

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Answer:

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The label can only display text in one font, but the text can span multiple lines. Furthermore, one of the characters can be highlighted, for example, to indicate a keyboard shortcut.

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Answer:

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Answer:

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Answers

Answer:

Explanation:

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Depending on the programming language, there are several ways we can comments our statements or codes that are not needed in our programmes

In Kotlin and Java Languages we can us the double slash "//" symbol to express single line comment

Example

//This is a comments

We can also us the "/***/" to express multi line comments

Example

/**This is a comment

also*/

Hence we have the

Inline Comments Multiline Comments

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Answers

Answer:

peer to peer connections in a network prevents drop-down of connection when a cable fails

Explanation:

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Answers

Answer:

Explanation:

Answer:

The correct answer is C. hope this helps

Explanation:

I also got a %100 one the test so its right.

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