Due to the satellite's overshooting circular course and movement away from Earth against the pull of gravity, the speed of satellite in such a closed circular orbit would be greater than 8 km/s.
Explain the effect of gravity on satellite in close circular orbit?The direction of gravity always seems to be toward the core of the Earth when a satellite travels around it in a circular orbit.
The satellite will move further before colliding with the Earth if it is assigned speed in either direction that is horizontal to a surface of the planet. This would travel so far if it is provided enough speed that even as it curves it toward the Earth, this should completely miss it. It will circle the Earth if it moves at just the proper pace. An orbit is the term used to describe this kind of motion and indeed the path which a satellite follows.A satellite must move at a speed of 8 km/s (28,000 km/h) or faster to stay its orbit when it is 100 km above the Earth. Satellites do not required to move as quickly at higher altitudes. The higher-altitude, 36,000 km, television communication satellites may fly at a speed of only 3 km/s (11,000 km/h).Thus, due to the satellite's overshooting circular course and movement away from Earth against the pull of gravity, the speed of satellite in such a closed circular orbit would be greater than 8 km/s.
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-A 180 kg hippo is riding a bicycle at a speed of 6. 0
m/s. Out of nowhere, a chimpanzee runs out in the
hippo's path and he must slam on his brakes. If the
bicycle's brakes exert a force of 1600 N, how
long will it take to stop the bicycle? _s
A 180 kg hippo is riding a bicycle at a speed of 6. 0 m/s. 0.135 sec will it take to stop the bicycle
Calculating:The kinetic energy of an object can be calculated using the equation:
KE = (1/2) × m × v^2
where m is the mass of the object, v is its velocity.
The work done by the brakes is given by the force of the brakes multiplied by the distance over which the brakes are applied. This can be written as:
W = F × d
As the force of the brakes is equal to the force that opposes the motion of the object and the force is constant, then,
F × d = KE
W = (1/2) × m × v^2
d = (2 × KE) / F
where d is the distance over which the brakes are applied, F is the force of the brakes and m, v are the mass and velocity of the object
Now we can substitute the known values into this equation:
d = (2 × (1/2) × 180 kg × (6 m/s)^2) / 1600 N = 0.81 m
Now we can find the time it takes to stop the bicycle:
t = d / v = 0.81 m / 6 m/s = 0.135 s
So it will take the hippo 0.135 seconds to stop the bicycle using the brakes.
How does kinetic energy work?The energy that an object has when it moves is called kinetic energy. It is equivalent to the amount of work required to propel an object from rest to its current velocity. The following equation can be used to determine an object's kinetic energy:
where v is the object's speed and m is its mass. The joule (J) is the unit of kinetic energy.
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What is the equivalent resistance of a number of identical resistances (n), each of resistance (R), when
connected in series?
1)nR
2)R/n
3)n/R
4)n*2R
Answer:
Explanation: It's R/n
is a=f/m = 10000/50000 does it equal 0.2 ms to the power of -2
Yes, a=f/m where a is the acceleration, f is the force, and m is the mass of an object, a=0.2m/s^2
According to Newton's 2nd law of motion, According to this law, the rate of change of linear momentum of a body is directly proportional to the external force applied on the body, and this change takes place always in the direction of the force applied. In simple terms, it means that a larger force will change the momentum of an object more quickly as compared to a smaller force.
Mathematically, we can write
F∝ dp/dT
where p is the momentum
F∝ (mv-mu)/t₂-t₁
where v is the final velocity and u is the initial velocity
Now, F∝{m(v-u)}/(t₂-t₁)
F∝ma [∵ a=(v-u)/t]
F=kma
∴ when k=1
F=ma
Now according to this question,
f=10,000 N and m=50,000kg
By applying the formula,
F=ma
10,000=50,000*a
∴ a= 10,000÷50,000
a=0.2 or 2×10⁻¹ m/s²
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the andromeda galaxy is the closest spiral galaxy a little more than 2 million light-years away. the light we see today from the andromeda galaxy was emitted how long ago?
We observe the Andromeda galaxy as it was 2.5 million years ago since it is around 2.5 million light years away.
We observe the Andromeda galaxy as it was 2.5 million years ago since it is around 2.5 million light years away. The Andromeda galaxy's light was first visible 2.5 million years ago. The Andromeda galaxy may have gotten a few thousand light years nearer to us during those 2.5 million years. While the diameter of the Andromeda galaxy itself is roughly 200 thousand light years, the uncertainty in the 2.5 million light year distance estimate is on the order of 100 thousand light years (simply because estimating the distance to other galaxies is difficult).
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electrons are accelerated by a 1000-v potential drop. (a) calculate the de broglie wavelength. (b) calculate the wave- length of the x-rays that could be produced when these elec- trons strike a solid.
The de Broglie wavelength of the electron is 2.212 x 10-11 m.
What is Broglie wavelength?The de Broglie wavelength is a concept in quantum mechanics which states that all matter has a wave-like nature, and can thus be described as a wave.
(a) The de Broglie wavelength (λ) of a particle is given by the equation: λ = h/p, where h is Planck's constant (6.626 x 10-34 J.s) and p is the momentum of the particle.
The momentum of an electron with a 1000-V potential drop is given by the equation p = eV/c,
where e is the electron charge (1.602 x 10-19 C) and c is the speed of light (2.998 x 108 m/s).
Therefore, the de Broglie wavelength of the electron is:
λ = h/(eV/c) = (6.626 x 10-34 J.s) / (1.602 x 10-19 C x 1000 V/2.998 x 108 m/s) = 2.212 x 10-11 m.
(b) X-rays are produced when high-energy electrons strike a solid.
The wavelength of the x-ray is inversely proportional to the energy of the electron.
The energy of the electron is equal to the potential drop, i.e. 1000 eV. Therefore,
the wavelength of the x-ray produced is: λ = hc/eV = (6.626 x 10-34 J.s x 2.998 x 108 m/s)/(1.602 x 10-19 C x 1000 eV) = 1.246 x 10-10 m.
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A 3. 8-mole sample of an ideal gas is gently heated at a constant temperature of 340 K. The gas expands to 2. 3 times its initial volume. What is the change in the internal energy of the gas? Let the ideal-gas constant R=8. 314 (mol x K)
The change in internal energy of an ideal gas is 826.9 J. Internal energy, represented by the symbol U, is the total energy of a system.
The change in internal energy of an ideal gas can be calculated using the equation:
ΔU = nCΔT
where ΔU is the change in internal energy, n is the number of moles of gas, C is the heat capacity at constant volume, and ΔT is the change in temperature.
Since the heat capacity at constant volume for an ideal gas is (3/2)R, we can use the ideal-gas equation to find the number of moles n = PV/RT = (810^-3 m^3)(101325 Pa)/(8.314 J/molK)(340 K) = 0.965 mol
We know that the volume of the gas expanded to 2.3 times its initial volume, thus the change in volume is 2.3 - 1 = 1.3 times
The change in internal energy can be calculated by using the equation:
ΔU = nCv(ΔT) + nRT ln(Vf/Vi)
where Cv is the heat capacity at constant volume = (3/2)R, T is the temperature, and Vf and Vi are the final and initial volume respectively.
So, ΔU = 0.965 x (3/2) x 8.314 x (340) + 0.965 x 8.314 x 340 x ln(2.3) = 826.9 J
Therefore, the change in internal energy of the gas is 826.9 J.
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A hot-air balloon takes off from the ground traveling vertically with a constant upward acceleration of magni- tude g/4. After time interval ∆t, a crew member releases a ballast sandbag from the basket attached to the balloon. How many seconds does it take the sandbag to reach the ground?
The time it takes for the sandbag to reach the ground would depend on the height from which it was released. The value is calculated to be t = √(2 s/(3g/4)).
To find out how long it takes for the sandbag to reach the ground, we can use the equation of motion for a vertically falling object under the influence of gravity:
s = v₀ t + (1/2) g t²
where s is the distance fallen, v₀ is the initial velocity (which is 0 m/s for the sandbag), t is the time elapsed, and g is the acceleration due to gravity (approximately 9.8 m/s²).
We know that the sandbag is being released from the balloon and has an upward acceleration of g/4. So, the equation of motion becomes
s = v₀ t + (1/2)(g - g/4) t²
We also know that s is the distance fallen to the ground, which we can take as the final distance.
Now solving the equation for t, t = √(2 s/(g - g/4))
It is given that the magnitude of the upward acceleration is g/4, so (g - g/4) = 3g/4, so the final equation becomes t = √(2 s/(3g/4))
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at what speed do a bicycle and its rider, with a combined mass of 120 kg , have the same momentum as a 1200 kg car traveling at 5.0 m/s ? express your answer to two significant figures and include the appropriate units.
The speed of a bicycle and its rider with a combined mass of 120 Kg is 50m/s.
It is given that a car of mass 1200 kg is traveling at a speed of 5.0 m/s.momemtum of the car = mass × speed
= 1200 × 5
= 6000 kg m/s
It is given that the bicycle and its rider will also be having the momentum same as the car. Therefore, the momentum of the bicycle = 6000 kg m/s.Mass of the bicycle = 120 kg.
momentum of the bicycle = mass × speed
[tex]speed = \frac{6000}{120} \\\\ speed = 50 m/s[/tex]
Therefore, the speed of the bicycle and its rider = 50 m/s
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In a 24 s interval, 228 hailstones strike a glass
window of area 0. 788 mº at an angle 20° to the
window surface. Each hailstone has a mass of
4g and speed of 8. 3 m/s.
If the collisions are elastic, find the average
force on the window.
Angwar in units of N.
The average force acting on a given area is 21.98 Pa.
What is force?A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.
Here,
Force = Mass X acceleration = 0.004kg x 9.8. This is when the hailstone is not inclined at an angle.
When the hailstone is inclined at an angle of 45, then the component of force along the glass window will be F =0.004kg x 9.8 x sin20= 0.005kg x 9.8 x 0.707= 0.0357N.
Therefore, total force for the 500 hailstones would be 500x0.0357N=17.85N
This force is acting on an area equal to 0.788m2
Pressure = Force per unit area = 17.32N/0.788m2 = 21.98Pa
The force is acting on an area known as average force is 21.98 Pa.
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A 15. 0-cm-long solenoid with radius 0. 750 cm is closely wound with 600 turns of wire. The current in the windings is 8. 00 A. Compute the magnetic field at a point near the center of the solenoid
The windings' current is 8.00 A. A location close to the solenoid's center has a magnetic field of 0.0111 T.
The magnetic field at a point near the center of a solenoid can be calculated using the following formula:
B = (μ₀xnxI) / L
Where:
B is the magnetic field
μ₀ is the permeability of free space, which is 4π x 10^(-7) Tm/A
n is the number of turns per unit length of the solenoid, in turns/m
I is the current flowing through the solenoid, in A
L, length of solenoid
Given the radius of the solenoid as 0.75 cm = 0.0075 m, and the length of the solenoid as 15.0 cm = 0.15 m, the cross-sectional area of the solenoid is:
π*(0.0075 m)² = 1.767 x 10^-5 m²
The number of turns per unit length of the solenoid can be calculated by dividing the total number of turns by the length of the solenoid:
600 turns / 0.15 m = 4000 turns/m
We can now substitute these values into the formula:
B = (4π x 10^(-7) Tm/A) * (4000 turns/m) * (8.00 A) / (0.15 m)
B = 0.0111 T
Therefore, the magnetic field at a point near the center of the solenoid is 0.0111 T.
It is worth noting that this result is valid only when the solenoid is long enough so that its ends do not affect the magnetic field inside. Also, the solenoid is considered as tightly wound and the radius of the solenoid much smaller than the length, so that the magnetic field inside the solenoid is uniform.
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A net force pushing a 15 kg wagon on a level road results in an acceleration of 2 m/s².
What is the net force?
Answer:
30N
Explanation:
As we know that ,
Force = mass * acceleration
so substitute the respective values,
F = 15kg * 2m/s²
F = 30N
and we are done!
when an object reaches terminal velocity its acceleration is
When an object reaches terminal velocity its acceleration becomes zero.
Terminal velocity is also called constant velocity. When there is no acceleration in the moving object. We can take the example of sedimentation.
Sedimentation is the process of settling down the soil particles at the bottom of the water. When soil particles comes down in water there are three forces which act on the particles. Downward force is weight of the particle. Upward force buoyant force of the water, and drag force. When upward forces become equal to the downward force then particles begins to settle down with a constant velocity. which is called terminal velocity.
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the radius of earth is about 6400 km. an 8200 n spacecraft travels away from earth.what is the weight 43200 km above earth's surface?
The weight of an 8200 N spacecraft when it is 43200 km above earth's surface is 136.5 N
The formula for the gravitational force between two objects is:
F = GMm/r²
Where:
G = gravitational constant
M, m = mass of the objects
r = distance between objects.
Notice that the gravitational force is inversely proportional to the square of the distance.
Hence,
F1 : F2 = (r2)² : (r1)²
In this case:
r1 = 6400
r2 = 6400 + 43200 = 49600
The gravitational force between earth and the spacecraft represents the weight of the satellite. Hence,
w1 : w2 = (r2)² : (r1)²
8200 : w2 = 49600² : 6400²
w2 = 136.5 N
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HELPPPP ASPPP PLEASE THA K YOU
In the transverse wave, point D represents the trough of the wave.
option D.
What is the trough of a wave?A wave two important points point, one curves upwards while the other curves downwards.
The maximum value of upward displacement within a cycle of a wave is known as crest. So the crest is a point on a surface wave where the displacement of the medium is at a maximum.
The maximum value of downward displacement within a cycle of a wave is known as trough.
Thus, from the graph, point A represents crest of the wave while point D represents trough of the wave.
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a student does an experiment to measure the charge on various drops of oil and collects the data shown. how do the data relate to the claim that the elementary charge has a value of 1.6
The information supports the assertion that the elementary charge has a value of 1.6. All of the values are more than that number, proving the assertion.
Is my phone capable of measuring?Utilizing augmented reality (AR) technology, the Measure app transforms your iPhone into a tape measure. Objects' sizes can be estimated, the measurements of rectangular objects can be automatically determined, and a photo of the measurement can be saved.
An easy measure is what?Simple measurements are those that just employ one kind of unit. hours and minutes To find all three numbers in seconds, we must use the conversion factors, for instance, if we wish to convert 2 hours, 23 minutes, and 12 seconds into seconds.
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Please help me! I will give brainliest! :(
1. Imagine 50 people walking in straight lines in a room. What would happen to the number of
collisions they would have with the walls if they moved to a room half the size of the original
room but walked at the same speed?
2. Imagine 50 people walking in straight lines in a room. If those 50 people start running, what needs to happen in order for the number of collisions they would have with the walls of the room to remain the same?
Please answer #’s 1 and 2
1) They would collide with the walls more frequently
2) They would collide with the walked more frequently
What is the collision?We know that collisions occur when there is a bump of an object against an obstacle. In the case of the scenario that we have here, we have been told that there are 50 people walking in straight lines in a room. If we move the walls to half the size they would collide with the walls more frequently.
In the second case, if the people that were walking in a straight line now begin to run, the chances are that they would collide with the walls more frequently.
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a pendulum has a period of 1.04 seconds on earth. what is its period on mars, where the acceleration of gravity is about 0.37 that on earth? give the answer in seconds, to 2 decimal places.
Period of the pendulum on Mars is 1.84 seconds (rounded to 2 decimal places).
What is period of a pendulum?Period of any pendulum is the distance from the pivot to center of oscillation.
The period of a pendulum, T:
T = 2 * pi * sqrt(L/g); L is length of pendulum and g is acceleration due to gravity.
On Earth, period of the pendulum is 1.04 seconds. To find the period on Mars, we can use fact that the acceleration due to gravity is 0.37 times that on Earth:
g_mars = 0.37 * g_earth
T_mars = 2 * pi * sqrt(L/g_mars)
Now we know ; T_mars = T_earth * sqrt(g_earth/g_mars)
T_mars = 1.04 * sqrt(1/0.37) = 1.04 * 1.76 = 1.8368 s
Therefore, the period of the pendulum on Mars is 1.84 seconds (rounded to 2 decimal places).
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a 1kg rock suspended above water weighs 9.8n when suspended beneath the surface it weighs 7.8 n what is th buoyant force
The buoyant force exerted on the 1 kg rock by the water is 2 N.
The buoyant force is the force exerted by a fluid (in this case, water) on an object that is submerged in it. To find the buoyant force, we need to subtract the weight of the object when it is submerged in the fluid from the weight of the object when it is suspended above the fluid.
The weight of the rock when it is suspended above water is 9.8 N (the weight of the rock is equal to its mass multiplied by the acceleration due to gravity, which is 9.8 m/s²).
The weight of the rock when it is suspended beneath the surface of the water is 7.8 N.
To find the buoyant force, we can use the following formula:
Buoyant force = weight of object above fluid - weight of object below fluid
Buoyant force = 9.8 N - 7.8 N = 2 N
Therefore, the buoyant force exerted on the 1 kg rock by the water is 2 N.
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if replacing the lights with a fluorescent bulb would save 60 w per night, what savings in kwh does this represent in one year?
The savings in kWh from replacing the lights with a fluorescent bulb in one year is 496.4 kWh/yr.
Evaluating :
Saving power = 60 w per night .
340 J/s ( 4h/d)(3600 sec/h) (365 d/yr)
( 1kWh/ 3.6 x 10 6 J)
= 496.4 kWh/yr
Which unit represents energy?The capacity to perform work is a definition of energy. When energy is released, a body performs the same amount of work as it has energy stored. Scalar energy is a quantity. Joule is the SI unit for energy. 1 joule of energy is the amount of energy required to perform one joule of work.
What is the energy rule?According to the law of conservation of energy, energy can only be changed from one form to another rather than being created or destroyed. Unless energy is added from the outside, a system always has the same amount of energy.
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A soccer player kicks a ball moving in a straight line
towards the field goal, causing it to accelerate into the field
goal.
O Negative work is done on the ball.
Positive work is done on the ball.
O No work was done on the ball.
O Negative work was done on the field.
When the force applied on the ball causes it o accelerate into the field
goal, Positive work is done on the ball.
option B.
What is work done?
A work is said to be done when an applied force causes a displacement of an object.
Mathematically, the formula for work done is given as;
W = Fd
where;
F is the applied forced is the displacement of the objectThus, when a soccer player kicks a ball moving in a straight line
towards the field goal, causing it to accelerate into the field goal, the work done on the ball is a Positive work.
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how do we known the sun rotates
Answer: Through observing the motion of sunspots
Explanation:
Answer:
The Sun spins on its axis once every 27 days. Its rotation had been initially discovered by watching the movement of sunspots. Because the Sun's rotational axis is tilted by around 7.25 degrees first from the direction of the Earth's orbit, humans observe more of the Sun's north pole in September & more of the south pole in March.
How is the electrostatic force (Felect) related to the separation distance (d) the two charges? Keeping the magnitude of charge on both objects constant, conduct a systematic study to collect data relating separation distance to force. The separation distance is defined as the distance between the centers of the two objects; the best strategy involves centering the objects on a gridline and using distances that are a whole number of squares.
Make a claim describing the relationship between Felect and d. Support your claim with evidence (references to the data) and reasoning
Allow two positive charges. Cuban and American two were distantly separated B. Cubans also use force against one another. This is also cute. Thus, the force will be equal to Q1 + Q2 + R^2.
More on electrostatic force and two charges :A characteristic of matter that affects how much force an object experiences when exposed to an electromagnetic field. A substance's charge might be positive, negative, or neutral. Total electric charge is conserved and cannot be created or destroyed, much as energy and matter.
Coulomb's constant, often known as the electric force constant, has a value of
K= [tex]\begin{equation*} 9\times10^9 \end{equation*}[/tex] [tex]\begin{equation*} \frac{Nm^2}{C^2} \end{equation*}[/tex]
Electrostatic force formula
[tex]\begin{equation*} \left|F_{E} \right|=K\left|\frac{q_1q_2}{r^2}\right| \end{equation*}[/tex]
[tex]F_{E}[/tex] is a electric force [tex]q_{1}[/tex] and [tex]q_{2}[/tex] is electric charge in coulomb K is constant, r is the distance between the charges
The magnitude of the electric force between [tex]q_{1}[/tex] and [tex]q_{2}[/tex]
Directly proportional to the size of the charges and inversely proportional to the square of the distance between them is the formula q, start subscript, 2, end subscript. The name of this equation is Coulomb's Law.
Comparing electric force and gravitational force with Newton's law of gravitation:
[tex]\begin{equation*} \left|F_E\right|=K\left|\frac{q_1q_2}{r^2}\right| \end{equation*}[/tex]
[tex]\begin{equation*} \left|F_G\right|=K\left|\frac{q_1q_2}{r^2}\right| \end{equation*}[/tex]
Similar to how gravitational force grows in strength with mass, electric force grows in strength with the size of the charges. Along the fictitious line connecting the items, both forces operate. The inverse-square law states that both forces are inversely proportional to the square of the distance between the objects. Additionally, both forces have constants of proportionality.
The relative intensities of gravitational and electric forces, which are determined by the ratio of K to G, are a disparity between them. The gravitational force between an electron and a proton is much smaller than the electrostatic force between them by several orders of magnitude.
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in what region is the electric field strongest? in what region is the electric field strongest? along the x axis between x
The nearest point to a charged item or the position of a point charge has the greatest electric field. As the distance from the charge grows, the electric field's intensity diminishes.
A force field called an electric field is produced when one electric charge interacts with other charges in the field and either attracts or repels them. The volts per metre (V/m) unit of measurement for the electric field is the letter E. It may be seen as a charge producing lines of force. A positive test charge would be pushed towards the direction of the electric field at a specific spot if it were to be placed there. The strength of the electric field is highest when the lines are close together and weakest when they are far apart.
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A 5. 60 kg bucket of water is accelerated upward by a cord of negligible mass whose breaking strength is 75 N. If the bucket starts from rest, what is the minimum time requiared to raise the bucket a vertical distance of 12 m without breaking the cord
The minimum time required to raise the bucket a vertical distance of 12m without breaking the cord is 2.58s
Given the mass of bucket of water (m) = 5.60kg
The strength acting on bucket is (F) = 75N
The distance bucket is raised (s) = 12m
Let the time taken to raise the bucket = t
So, W = m x g as a force of gravity is always acting on a system.
W = 5.60 x 9.8 such that W = 54.88N
The maximum accelerating force acting on the cord (Fr) = 75 - 54.88 = 20.12N
We know that from Newtons laws of motion F = ma where a is the acceleration and F is the force.
Fr = ma then a = 20.12/5.60 = 3.59m/s^2
Then according to the problem s = ut + 1/2at^2 where u is initial velocity which is 0m/s as at rest initially.
So, s = 1/2at^2 then 12 = 1/2 x 3.59 x t^2
t^2 = 24/3.59 = 6.68
t = 2.58s
Hence the minimum time required to raise the bucket a vertical distance of 12 m without breaking the cord is 2.58seconds.
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cells in the eye detect light
and dark. What word completes the
sentence?
Enter your answer
"Rod cells in the eye detect light and dark." completes the sentence.
What is light?Light is defined as electromagnetic radiation visible to the human eye with wavelengths ranging from 380 to 750 nm. Light is a type of electromagnetic radiation that enables or makes objects visible to the human eye. It's also known as visible radiation to the eye. Light contains photons, which are tiny packets of energy. Lux (lx) (lx) The unit of illumination is the lux, which is equal to one lumen per square metre. The metric equivalent of footcandles is one lux equals 0.0929 footcandles.
Here,
"In the eye, rod cells detect light and dark." completes the sentence.
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Cedric and Insha solved the same equation using the calculations below.
Cedric’s Work
Insha’s Work
z minus 4.5 = negative 1.5. z minus 4.5 + 4.5 = negative 1.5 + 4.5. z = 3.
z minus 4.5 = negative 1.5. z minus 4.5 + (negative 4.5) = negative 1.5 + (negative 4.5). z = negative 6.
Which statement is true about their work?
Cedric is correct because he used the inverse of subtraction and added 4.5.
Cedric is incorrect because he should have subtracted 4.5 from both sides instead of adding.
Insha is correct because she added the opposite if 4.5, which is Negative 4.5, to both sides.
Insha is incorrect because she did not add Negative 1.5 + (negative 4.5) correctly.
Answer:
Explanation:
Cedric is correct because he used the inverse of subtraction and added 4.5
A heat engine of efficiency e that operates between high temperature TH and low temperature TC. What is the range of possible values of e?
The ratio of the engine's work, W, to the heat absorbed from the high-temperature heat source, QH, is the measure of a heat engine's efficiency, or e. In mathematical terms, it looks like:e = W/QH
According to the second law of thermodynamics, the maximum efficiency of a heat engine, also known as the Carnot efficiency, eC, is equal to the difference between the temperatures TH and TC:
eC = 1 - (TC/TH) The Carnot efficiency is the maximum efficiency of a theoretical heat engine, also known as a Carnot engine, which operates between two temperatures TH and TC and is thought to be the most efficient heat engine possible.
Therefore, the following is the range of possible e values for a heat engine operating between TH and TC:
0 e eC = 1 - (TC/TH), indicating that a heat engine's efficiency cannot exceed the Carnot efficiency and cannot fall below 0.
How does Carnot Efficiency work?A heat engine's maximum theoretical efficiency is measured by the Carnot efficiency, after the French engineer Sadi Carnot. The ratio of the heat engine's work to the heat absorbed from the higher-temperature heat source is what is used to define it. It is calculated as follows:
eC is equal to 1 - (TC/TH), where TC is the cold reservoir temperature and TH is the hot reservoir temperature.
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two point charges exert a 5.00 n force on each other. what will the force become if the distance between decreases by a factor of 2 (i.e. distance becomes 1/2 of original)?
Answer:55
Explanation: hope thi heps!
If a battery produces a voltage of 53V and a resistance of 31 Ohms, calculate the current.
a 0.11-kg tin can is resting on top of a 1.7-m high fence post. a 0.0020-kg bullet is fired horizontally at the can. it strikes the can with a speed of 900.0 m/s, passes through it, and emerges with a speed of 720 m/s. when the can hits the ground, how far is it from the fencepost? disregard friction while the can is in contact with the post.
It is 1.93 metres away from the post.
for vertical motion
[tex]S= u t + \frac{1}{2} g t^{2}[/tex]
S = 0 + [tex]\frac{1}{2} g t^{2}[/tex]
1.7 = [tex]\frac{1}{2} 9.8 t^{2}[/tex]
t = 0.589 sec
using law of conservation of momentum, on the horizontal motion
[tex]m_{bullet} \ v_{bullet i} = m_{bullet} \ v_{bullet f} + m_{tin} \ v_{tin}[/tex]
[tex]0.0020 = 0.0020 \ 3 \ 720 + 0.11 \ v_{tin}[/tex]
[tex]v_{tin}[/tex] = 3.273 m/s
S = [tex]v_{tin} \ t[/tex]
= 3.273 m/s * 0.589 s
= 1.93 m
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