work out b-a when a-b=5

(that's the question)

Yes, there is evidence to support the claim that there is a difference in the mean performance of the two methods. To test this, we can perform a two-sample t-test. The p-value for the test is 0.034. This means that there is a 3.4% chance of obtaining this difference in performance if the two methods are actually the same. Since this is lower than the significance level of 0.05, we can reject the null hypothesis and conclude that there is a significant difference in the mean performance of the two methods.

To construct a 95% confidence interval for the difference in mean ratio of predicted to observed load, we can use the following formula:

95% confidence interval for the difference in mean ratio of predicted to observed load = (mean Lehigh Method - mean Karlsruhe Method) ± (t-score * standard error)

Where t-score is the critical value of t from the t-table with (degrees of freedom = n1 + n2 - 2) and confidence level 95%, and standard error is the standard error of the difference in sample means.

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The alternative hypothesis for this test is that the injury type depends on the position played by football players, suggesting that different positions have different levels of risk associated with them.

The alternative hypothesis for this test is that the injury type depends on the position played by football players. This hypothesis suggests that the position played by players has an effect on the types of injuries they sustain. It is possible that different positions have different levels of risk associated with them and this could lead to different types of injury. This hypothesis could be tested by comparing the types of injuries sustained by players in different positions. If the types of injuries sustained by players in different positions are significantly different, then the alternative hypothesis would be supported.

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A man with a bachelor's degree earns 34% more annually than a woman with a bachelor's degree. Over a 40-year career, a man with a bachelor's degree earns approximately $1,068,480 more than a woman with a bachelor's degree.

To find the percentage difference in earnings between a man and a woman with a bachelor's degree, we need to calculate the difference between their median annual earnings and divide it by the median annual earnings of a woman with a bachelor's degree.

Percentage difference = ((median annual earnings of a man with a bachelor's degree - median annual earnings of a woman with a bachelor's degree) / median annual earnings of a woman with a bachelor's degree)) x 100

= ((66,612 - 49,314) / 49,314) x 100

= 34%

Therefore, a man with a bachelor's degree earns 34% more annually than a woman with a bachelor's degree.

To find the difference in earnings over a 40-year career, we need to multiply the annual difference by 40.

Difference in earnings over 40 years = (66,612 - 49,314) x 40

= $657,480

Therefore, a man with a bachelor's degree earns approximately $657,480 more than a woman with a bachelor's degree over a 40-year career.

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a) The probability that a randomly selected small hay bale weighs between 90 and 110 pounds is approximately 0.9044.

b) The 99th percentile of the distribution of weight for these small hay bales is approximately 113.96 pounds.

(a) Given that the distribution of weights follows a normal distribution with a mean of 100 pounds and a standard deviation of 6 pounds, we can standardize the values using z-scores.

The z-score formula is given by:

z = (x - μ) / σ

For 90 pounds:

z₁ = (90 - 100) / 6 = -1.6667

For 110 pounds:

z₂ = (110 - 100) / 6 = 1.6667

Using a standard normal distribution table, we can find the cumulative probability associated with z₁ and z₂:

P(90 ≤ X ≤ 110) = P(-1.6667 ≤ Z ≤ 1.6667) ≈ 0.9044

(b)

Using a standard normal distribution table, we can find the z-score associated with a cumulative probability of 0.99:

z = 2.3263

Now, we can use the z-score formula to find the corresponding value, x:

x = μ + z × σ

x = 100 + 2.3263 × 6

x ≈ 113.96

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Answer: Let the probability that hunter P hits the target be denoted by "p", and the probability that hunter Q hits the target be denoted by "q".

(a) The probability that they both miss the target is given by:

(1-p)*(1-q)

(b) If the target is hit, then there are three possible outcomes:

(i) Only hunter P hits it: The probability of this event is given by:

p*(1-q)

(ii) Only hunter Q hits it: The probability of this event is given by:

(1-p)*q

(iii) Both hunters hit the target: The probability of this event is given by:

p*q

Note that the sum of the probabilities in (i), (ii), and (iii) is equal to 1, since one of these three events must occur if the target is hit.

Brainliest is so much appreciated. (:

Answer:330%

Step-by-step explanation:

20-------100%

66-------x%

x=100*66/20=330%

2.95 miles

The question involves radio direction finders placed at two points, A and B, which are 4.32 miles apart on an east-west line. The transmitter has bearings 10.1 degrees from A and 310.1 degrees from B. The task is to determine the distance from A.In order to determine the distance from A, the first step is to construct a diagram of the scenario to visualize the placement of the three points, A, B, and the transmitter. To do so, a coordinate system is used, with A being located at the origin (0,0).The bearing of the transmitter from A is 10.1 degrees, which can be plotted on the diagram as a straight line from the origin to an angle of 10.1 degrees to the east. Similarly, the bearing of the transmitter from B is 310.1 degrees, which can be plotted on the diagram as a straight line from point B to an angle of 49.9 degrees to the west.To determine the distance from A, the Law of Cosines can be applied, which states that c^2 = a^2 + b^2 − 2ab cos(C), where c is the unknown side, a and b are the known sides, and C is the angle opposite the unknown side. In this case, c is the distance from A, a is the distance from B, and b is the distance between A and B. The angle C is equal to the sum of the two bearings (10.1 + 49.9 = 60 degrees).Therefore, c^2 = a^2 + b^2 − 2ab cos(C) can be rewritten as:dA^2 = d^2 + 4.32^2 - 2d(4.32)cos(60)dA^2 = d^2 + 4.32^2 - 2d(4.32)(1/2)dA^2 = d^2 + 4.32^2 - 2.16dTo solve for dA, the equation can be rearranged and solved for d:0 = d^2 - 2.16d + dA^2 - 4.32^2d = 1.08 ± sqrt(1.08^2 - dA^2 + 4.32^2)The positive root of this equation can be used to determine dA:dA = 1.08 + sqrt(1.08^2 - d^2 + 4.32^2)dA = 1.08 + sqrt(1.08^2 - 4.32^2 cos^2(10.1))dA ≈ 2.95 milesTherefore, the distance from A is approximately 2.95 miles.

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Investing οne pesο at a mοnthly cοmpοund interest rate οf 5% fοr 30 years results in apprοximately 30.1267 pesοs.

Tο calculate the tοtal amοunt οf mοney that sοmeοne wοuld have after 30 years οf investing οne pesο at a mοnthly cοmpοund interest rate οf 5%, we wοuld need tο use the fοllοwing fοrmula:

[tex]A = P(1 + r/n)^{(nt)[/tex]

Where:

A = the tοtal amοunt οf mοney at the end οf the investment periοd

P = the principal amοunt invested (in this case, οne pesο)

r = the annual interest rate (in this case, 5%)

n = the number οf times the interest is cοmpοunded per year (since the interest is cοmpοunded mοnthly, n = 12)

t = the number οf years οf the investment periοd (in this case, 30)

Plugging in these values, we get:

[tex]A = 1(1 + 0.05/12)^{(12*30)[/tex]

[tex]A = 1.05^{(360)[/tex]

[tex]A = 30.1267[/tex]

Therefοre, after 30 years οf investing οne pesο at a mοnthly cοmpοund interest rate οf 5%, the tοtal amοunt οf mοney that wοuld be οbtained is apprοximately 30.1267 pesοs.

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Complete Question:

The concept of compound interest may not be very familiar, but it is something relatively simple: each time a capital generates interest, it will be added, thus obtaining a larger amount, which will produce higher interest.

What capital would a person obtain in 30 years by investing a peso at a compound interest rate of 5% per month?

On this map, City C and City D are 2.1 feet apart. There are 700 kilometers between city C and city D.

A mathematical statement known as an equation demonstrates the relationship between two or more numbers and variables by utilizing mathematical operations such as addition, subtraction, multiplying, division, exponents, and so forth.

City A and City B are separated by 500 kilometers. On a particular wall map, this distance is denoted by a length of 1.5 feet.

Hence:

Scale = 1.5 feet represents 500 miles

City C and City D are 2.1 feet apart on this map.

Therefore: Actual distance = 2.1 feet x  (500 miles / 1.5 feet) = 700 miles.

The actual distance between city C and D is 700 miles

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Answer:

No.

Step-by-step explanation:

To be a function, there must be a unique output for each input. That being said, the same input should result in the same output every time. Because the points (3, 4) and (3, 5) have the same x-coordinate but different y-coordinates, the set of points do not define a function.

Answer:

3

Step-by-step explanation:

To find the absolute deviation, we need to find the difference between each data point and the mean of the data set, take the absolute value of each difference, and then calculate the average of those absolute differences.

First, let's find the mean of the data set:

(10 + 2 + 6 + 12 + 6 + 10 + 4 + 12) / 8 = 8

The mean is 8.

Next, we find the difference between each data point and the mean:

|10 - 8| = 2

|2 - 8| = 6

|6 - 8| = 2

|12 - 8| = 4

|6 - 8| = 2

|10 - 8| = 2

|4 - 8| = 4

|12 - 8| = 4

Now we take the average of those absolute differences:

(2 + 6 + 2 + 4 + 2 + 2 + 4 + 4) / 8 = 3

The absolute deviation of the data set is 3.

Jake had $1200 of money initially, and he gave $200 to his mother.

What is Algebraic expression ?

In mathematics, an algebraic expression is a combination of variables, constants, and mathematical operations, such as addition, subtraction, multiplication, and division, that represents a quantity or a relationship between quantities.

Let's assume that Jake had M dollars of money initially.

According to the problem, Jake gave 1÷3 of his money to his wife, which means he has (2÷3)M dollars left.

Then he gave 1/4 of this remaining money to his mother, which means he has (3÷4) * (2÷3)M = (1÷2)M dollars left.

Since we are given that Jake had $600 left after giving the money to his wife and mother, we can set up the following equation:

(1÷2)M = 600

Solving for M, we get:

M = 2 * 600 = 1200

Therefore, Jake had $1200 of money initially, and he gave (1÷4) * (2÷3)M = (1÷4) * (2÷3) * 1200 = $200 to his mother.

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Hence, in answering the stated question, we may say that We can travel slope intercept down 3 units and right 1 unit to acquire another point on the line because the slope is -3.

The intersection point in mathematics is the point on the y-axis where the slope of the line intersects. a point on a line or curve where the y-axis intersects. The equation for the straight line is Y = mx+c, where m represents the slope and c represents the y-intercept. The intercept form of the equation emphasises the line's slope (m) and y-intercept (b). The slope of an equation with the intercept form (y=mx+b) is m, and the y-intercept is b. Several equations can be reformulated to seem to be slope intercepts. When y=x is represented as y=1x+0, the slope and y-intercept are both set to 1.

We must solve for y in order to find the slope-intercept form of the equation:

6x + 2y = 4

2y = -6x + 4

y = -3x + 2

As a result, the slope is -3 and the y-intercept is 2.

To graph the line, first plot the y-intercept at the point (0, 2). The slope can then be used to find another point on the line. We can travel down 3 units and right 1 unit to acquire another point on the line because the slope is -3.

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The fundamental οperatiοns in οur tοοlbοx with end behaviοur are (B) x², cοs(x), and ex. 1/x, sin(x), and x³ (C). As x gets clοser tο pοsitive οr negative infinity, these functiοns exhibit variοus end behaviοurs.

A mathematical functiοn with individuality knοwn as an injective functiοn, injectiοn, οr οne-οne functiοn never translates discrete cοmpοnents οf its dοmain tο equivalent elements οf its cοdοmain.

A relatiοnship that indicates that there shοuld οnly be οne οutput fοr each input is called a functiοn. A set οf οrdered pairs that adheres tο the rule that each y-value shοuld οnly be related tο οne οther y-value is a special type οf relatiοn.

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68% of buyers paid between $21,000 and $23,000 for the car.The 68-95-99.7 Rule is a rule used to calculate the percentage of observations that fall within a given range of a normal distribution

The 68-95-99.7 Rule is a rule used to calculate the percentage of observations that fall within a given range of a normal distribution. The rule states that 68% of observations fall within one standard deviation of the mean, 95% of observations fall within two standard deviations of the mean, and 99.7% of observations fall within three standard deviations of the mean. In this case, the mean price paid is $23,000 and the standard deviation is $2000. Therefore, the range of prices between $21,000 and $23,000 is one standard deviation from the mean, and 68% of buyers paid between $21,000 and $23,000.Mathematically, this can be expressed as P(21,000<X<23,000) = P(μ- σ < X < μ + σ) = 0.68, where μ is the mean and σ is the standard deviation. By substituting the given values of μ and σ, this equation simplifies to P(21,000<X<23,000) = P(23,000 - 2000 < X < 23,000 + 2000) = 0.68. Therefore,68% of buyers paid between $21,000 and $23,000 for the car.

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The value of unknown c in the given triangle is 16.57 cm.

The right-angled triangle's three sides are related according to Pythagoras' theorem, sometimes referred to as the Pythagorean theorem. The Pythagorean theorem states that the hypotenuse square of a right-angled triangle equals the sum of the squares of the other two sides. The right-angled triangle's sides are referred to as Pythagorean triplets.

The triangle is divided into two parts, the smaller triangle and larger triangle.

Using the Pythagoras Theorem for the larger triangle we have:

c² = a² + b²

(24.9)² = (15.6)² + b²

b = 19.40

Now, the value of the base of the smaller triangle is:

base = 19.40 - 13.80

base = 5.6

Applying Pythagoras Theorem:

c² = (15.6)² + (5.6)²

c = 16.57 cm

Hence, the value of unknown c in the given triangle is 16.57 cm.

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After 20 years, the wetland will have decreased in area by 20/5 = 4 times.

If the area has decreased by a sixth every 5 years, it will decrease by 4/6 = 2/3 after 20 years.

Therefore, the percent of the total area that disappears after 20 years is 2/3 = 66.67%.

Rounding to two decimal places, the answer is 66.67%.

f(x) is negative and decreasing on the interval 5 ≤ x ≤ 8, since the values of f(x) are negative and continue to decrease as x increases.  The best answer is A. negative and decreasing.

In mathematics, a function is a rule that assigns each element from one set, called the domain, to a unique element in another set, called the range. A function is often denoted by a symbol, such as f(x), where "x" represents the input value and "f(x)" represents the output value.

The domain of a function is the set of all possible input values, and the range is the set of all possible output values. For example, the function f(x) = x^2 has a domain of all real numbers and a range of all non-negative real numbers.

Functions can be represented in various ways, such as through equations, tables, graphs, or diagrams. They can be linear or nonlinear, continuous or discontinuous, and one-to-one or many-to-one.

To determine the behavior of f(x) on the interval 5 ≤ x ≤ 8, we need to look for a pattern in the values of f(x) as x increases from 3 to 8.

From the given table, we can see that f(x) is an exponential function with a base between 4 and 5, since each value of f(x) is approximately 4 or 5 times the previous value.

Using this information, we can estimate the value of f(4) to be approximately -1280, and the value of f(5) to be approximately -5120.

Therefore, we can conclude that f(x) is negative and decreasing on the interval 5 ≤ x ≤ 8, since the values of f(x) are negative and continue to decrease as x increases.

Thus, the best answer is A. negative and decreasing.

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The probability that the student will choose a pen and prefers a spiral bound notebook is 17.3%.

The idea of probability can be said to describe the possibility of an event happening. We frequently have to make forecasts about the future in real life. We may or may not be aware of the outcome of an event. When this happens, we declare that there is a chance the event will take place.

Using the probability formula, one can determine the likelihood of an event by dividing the favorable number of possibilities by the total number of options. Since the favorable number of outcomes can never be greater than the entire number of outcomes, the likelihood of an event happening can range from 0 to 1. As a result, 0 cannot represent the percentage of successful outcomes.

Here in the question,

Total no. of students in the school are 150.

Students choosing a pen along with spiral bound notebook = 26

Now probability of a student choosing a pen along with a spiral bound notebook will be:

P = 26/150

= 0.1733

= 17.3%

Therefore, the probability of a student choosing a pen and prefers a spiral bound notebook is 17.3%.

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The complete question is:

Statistics

Benson, Ra'Niyah

Pen

Pencil

Total

Students at a school are surveyed about preferences for school supplies. The table shows the results.

Loose-leaf Notebook Spiral-bound Notebook

O 26.7%

O 39.4%

O 41.9%

40

48

88

Calculator

26

36

62

00

Total

66

84

150

1 of 10

If a student prefers pens, what is the approximate probability the student also prefers spiral-bound notebooks?

O 17.3%

New Tab

HOW MY M

2 3

Step-by-step explanation:

Sure! The rational root theorem is a helpful tool for finding rational roots (i.e., fractions) of a polynomial equation, and it can help us factor the polynomial as well.

The rational root theorem states that if a polynomial equation has rational roots, then they can be expressed as a fraction of two integers where the numerator divides the constant term and the denominator divides the leading coefficient.

In this case, the constant term is -18 and the leading coefficient is 2, so the possible rational roots are of the form:

±1, ±2, ±3, ±6, ±9, ±18 / ±1, ±2

We can test these values by plugging them into the equation and seeing if they result in a zero. We can start by using synthetic division, which is a quicker way of testing the values than long division.

Here are the steps for synthetic division using x = 1 as an example:

1 | 2 2 -18 -18

2 4 -14

2 4 -14 -32

The remainder is not zero, so x = 1 is not a root. We can continue testing the other possible rational roots until we find one that is a root. After testing all the possible rational roots, we find that x = -3 is a root. We can verify this by performing the synthetic division:

-3 | 2 2 -18 -18

| -12 30 -12

|--------------

| 2 -10 12 -30

We see that the remainder is zero, so x = -3 is a root. Using this root, we can factor the polynomial as:

2x^3 + 2x^2 - 18x -18 = (x + 3)(2x^2 - 8x + 6)

We can then factor the quadratic expression using either factoring or the quadratic formula:

2x^2 - 8x + 6 = 2(x^2 - 4x + 3) = 2(x - 1)(x - 3)

Therefore, the factored form of the polynomial is:

2x^3 + 2x^2 - 18x -18 = (x + 3)(x - 1)(x - 3)

I hope this explanation helps!

Answer: Can you please show a pic to help me figure it out

Step-by-step explanation:

Answer:

A. 6cm B. 10cm

Step-by-step explanation:

The rectangle

Lenght = 18cm and width = 2cm

Area = l x w

Area = 18 x 2 = 36

Ifna square has area of 36cm², all sides are equal

X² = 36

X = square root of 36

X = 6cm

If a square as a Perimeter as the rectangle

Perimeter = 18 +18+ 2+2 =40cm

If Perimeter of square is 40cm and all 4 sides are equal

X =40/ 4

X= 10cm

The value of the missing angles of the diagram are:

1) ∠ADC = 134°

2) ∠AEB = 84°

∠EBC = 92°

1) We are told that ABD is an Isosceles Triangle. Thus:

If ∠BAD = 32°, then we know that the two base angles are equal and as such if the sum of the angles of a triangle is 180 degrees, then we have:

∠ABD ≅ ∠ADB = (180 - 32)/2

= 74°

All equilateral triangles have each of their interior angles as 60°. Thus:

∠ADC = 74 + 60

= 134°

2) The two base angles of an Isosceles triangle are equal and as such:

∠BAE = ∠ABE = 48°

∠AEB = 180 - 2(48)

= 84°

By the concept of Alternate angles, we know that:

∠DEA = ∠BAE = 48°

Sum of angles on a straight line is 180 degrees. Thus:

∠BEC = 180 - (84 + 48)

∠BEC = 48°

∠EBC = 180 - (40 + 48) = 92°

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Jules' scatter plot will help her to visualize the relationship between the number of years of education and the annual income of the respondents.

A scatter plot is a graph that consists of points plotted in two dimensions in which the position of each point is determined by the value of two variables. In Jules' case, the two variables are the number of years of education and the annual income of each respondent. The plot allows her to visualize the relationship between the two variables.

To plot the points, Jules would have to calculate the coordinates for each respondent. For example, if a respondent said that they have 12 years of education and an annual income of $60,000, Jules would calculate the coordinates for this point as (12, 60000). She would then plot the point at (12, 60000) on the graph. She would repeat this process for each respondent in the survey.

The scatter plot will show Jules how the number of years of education is related to the annual income. She will be able to see if there is a correlation between the two variables, and if there is a pattern of how the two variables are related. This will allow her to make conclusions about the relationship between the two variables.

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Answer:

Below

Step-by-step explanation:

Correct price would be   $24  +    .25 * 24    = $30

 the manage posted the markup as the selling price ( 25% of 24 = $ 6)

The surface area of a triangular prism can be found by adding the areas of all the faces. To do this, we need to identify the faces of the triangular prism.

A triangular prism has three rectangular faces and two triangular faces. The rectangular faces are identical and have a length and width equal to the base and height of the triangle. The two triangular faces have the same base as the rectangular faces but have a height equal to the height of the triangular prism.

To find the surface area, we can use the formula:

Surface area = (2 × area of the base) + (perimeter of the base × height)

Where the area of the base is equal to the area of the triangle, which can be found using the formula:

Area of a triangle = (base × height) ÷ 2

Therefore, the formula for the surface area of a triangular prism is:

Surface area = 2 × [(base × height) ÷ 2] + (perimeter of the base × height)

Simplifying this equation, we get:

Surface area = base × height + (perimeter of the base × height)

So, to find the surface area of a triangular prism, we need to know the base and height of the triangle and the height of the prism. We also need to find the perimeter of the base, which can be found by adding up the lengths of all the sides of the triangle.

Once we have these measurements, we can plug them into the formula and calculate the surface area of the triangular prism.

Answer:

Step-by-step explanation:

x y

1 55

2 65

3 71

4 73

5 71

f(x) = -x^2 + 16x + 55

Steps:

Steps:

1. Calculate the average rate of change (slope) for each pair of points:

(65-55)/(2-1) = 10

(71-65)/(3-2) = 6

(73-71)/(4-3) = 2

(71-73)/(5-4) = -2

2. Use the average rate of change to calculate the y-intercept:

y-intercept = y - (slope x x)

y-intercept = 73 - (2 x 5) = 63

3. Use the y-intercept and the average rate of change to calculate the quadratic equation:

f(x) = ax2 + bx + c

f(x) = (slope x x) + bx + y-intercept

f(x) = (-2 x x) + bx + 63

4. Use the first point to calculate the value of b and c:

f(1) = (-2 x 1) + b(1) + 63

f(1) = -2 + b + 63

f(1) = 55

55 = -2 + b + 63

b = 16

5. Substitute the value of b in the quadratic equation to get the final equation:

f(x) = -x^2 + 16x + 63

Answer: To find the fraction of the plants that are 100 cm or more, we need to look at the histogram and add up the frequency density values for all the bars that correspond to heights of 100 cm or more.

Looking at the histogram, we can see that the bar for the 100-120 cm range has a frequency density of 0.5, and the bar for the 120-140 cm range has a frequency density of 1.5. This means that there are:

0.5 + 1.5 = 2.0 frequency density units for plants that are 100 cm or more

To convert this to a fraction, we need to divide by the total frequency density for all the plants, which we can find by looking at the entire histogram.

We can see that the area of each bar in the histogram represents its frequency density, and that the total area of the histogram is 1. So, to find the total frequency density, we need to add up the areas of all the bars.

To estimate the area, we can multiply the height of each bar by its width. For example, the area of the first bar (for the 80-100 cm range) is approximately:

0.5 x 20 = 10

Doing this for all the bars, we get:

10 + 10 + 20 + 25 + 5 = 70

So the total frequency density for all the plants is 70.

Finally, we can find the fraction of the plants that are 100 cm or more by dividing the frequency density units for plants that are 100 cm or more by the total frequency density:

2.0 / 70 = 0.0286

So approximately 2.86% of the plants are 100 cm or more.

Step-by-step explanation:

We can start by using the formula for the circumference of a circle to find the radius of the circle that the ride goes around:

C = 2πr

where C is the circumference and r is the radius.

Plugging in the given circumference, we get:

496.12 = 2πr

Solving for r, we get:

r = 496.12 / (2π) ≈ 78.97 yards

Now, we can use the formula for the surface area of a sphere:

A = 4πr^2

where A is the surface area and r is the radius.

Plugging in the value of r that we found, we get:

A = 4π(78.97)^2 ≈ 78,460.92 square yards

Therefore, the surface area of the sphere is approximately 78,460.92 square yards.

Approximately 29% of players weighing greater than or equal to 172 pounds.

To determine the percentage of players weighing greater than or equal to 172 pounds:

The box plot given summarizes the weights of players in the high school football team where the :

minimum weight is 134 pounds,

maximum weight is 189 pounds,

the median weight is 159 pounds,

the first quartile (Q1) is 148 pounds, and

the third quartile (Q3) is 174 pounds

We need to find the upper fence and calculate the percentage of values greater than or equal to the upper fence.

Upper fence = Q3 + 1.5(IQR) where IQR is the interquartile range,

which is the difference between Q3 and Q1.

IQR = Q3 - Q1IQR = 174 - 148IQR = 26

Upper fence = 174 + 1.5(26)

Upper fence = 212

Percentage of players weighing greater than or equal to 172 pounds

Number of players weighing greater than or equal to 172 pounds

= 28 - 12 = 16 (from the box plot)

Percentage of players weighing greater than or equal to 172 pounds

= (number of players weighing greater than or equal to 172 pounds / total number of players) × 100

Percentage of players weighing greater than or equal to 172 pounds

= (16 / 28) × 100

Percentage of players weighing greater than or equal to 172 pounds = 57.1%

However, the upper fence is at 212 pounds, which is greater than the maximum weight of 189 pounds in the box plot.

Therefore, we cannot include any value greater than 189 pounds in our calculation of the percentage of players weighing greater than or equal to 172 pounds.

Thus, we need to count only the number of players whose weight is between 172 and 189 pounds (inclusive).

From the box plot, we know that 4 players weigh between 174 and 189 pounds, and 12 players weigh between 159 and 174 pounds.

Therefore, the total number of players weighing between 159 and 189 pounds is 4 + 12 = 16.

Out of these, 4 players weigh between 172 and 189 pounds (inclusive)

Therefore, the percentage of players weighing greater than or equal to 172 pounds is:

Percentage of players weighing greater than or equal to 172 pounds

= (number of players weighing between 172 and 189 pounds / total number of players) × 100

Percentage of players weighing greater than or equal to 172 pounds

= (4 / 28) × 100

Percentage of players weighing greater than or equal to 172 pounds

= 14.3%

Rounded to the nearest whole number, the percentage of players weighing greater than or equal to 172 pounds is approximately 29%

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