Answer:
[tex]0.060molH_2O[/tex]
Explanation:
Hello there!
In this case, since the chemical reaction between ethanol and oxygen to water and acetic acid is:
[tex]CH_3CH_2OH+O_2\rightarrow CH_3COOH+H_2O[/tex]
Thus, since there is a 1:1 mole ratio between oxygen and water, the produced moles of water are calculated down below:
[tex]0.060molO_2*\frac{1molH_2O}{1molO_2}=0.060molH_2O[/tex]
Best regards!
What is the total number of oxygen atoms on the left-hand side of this chemical equation?
2 Caz(PO4),(s)+48i0,(s) +12C(s) - 4 Casio2(3)+P4($)+12CO(g)
Answer:
Is the answer eight atoms
An experiment requires 66.6 g of ethyl alcohol (density = 0.790 g/mL). What is the volume?
Answer:
Volume = 84.30 mLExplanation:
Mass = 66.6 gram
Density = 0.790 g/mL
Volume = Mass ÷ Density
Volume = 66.6 ÷ 0.790
Volume = 84.30 mL
STEP 5: LEAD
Tare the balance. Put calorimeter (no lid) on the balance.
Measure the mass to the nearest 0.01 g.
12.34 g
Use a graduated cylinder to add approximately 40 mL of
water to the calorimeter. Measure the mass of the
calorimeter (no lid) and water to the nearest 0.01 g.
51.99 g
Subtract to find the mass of the water. 39.65 g
Answer:
the answers are in the pic
Explanation:
Answer:
12.36, 52.49, 40.13
Explanation:
Step 5 for the copper one
What process is represented by the letter on the diagram?
A: ____________________________________________
B: ____________________________________________
C: ____________________________________________
D: ____________________________________________
E: ____________________________________________
Explanation:
I don't really understand the question
The process of shedding an outgrown exoskeleton.
Answer:
Mouthing is the answer to your question
Which type of front is most likely moving through this area?
A. cold front
B. warm front
C. occluded front
D. stationary front
Answer:
Cold front
Explanation:
Determine the number of shared and unshared electrons in the structure. shared (bonding) electrons: unshared (lone, nonbonding) electrons: Determine the number of shared and unshared pairs of electrons in the structure. shared (bonding) pairs of electrons: unshared (lone, nonbonding) pairs of electro
Answer:
Shared (bonding) electrons : 8
Unshared (lone, non-bonding) electrons : 16
Explanation:
The Lewis dot stricture of the molecule attached to this answer shows us all the valence electrons present in the molecule.
Altogether, we have a total number of 24 valence electrons in SO3.
There are eight electrons shared between atoms of elements, these are the bonding electrons.
There are sixteen electrons that are not shared between atoms of elements, These are the lone or non-bonding electrons.
Hence, there are four shared pairs of electrons and eight pairs of unshared electrons.
9. Which of the following is needed as a reactant for cellular
respiration?
A. Carbon dioxide
B. Oxygen
C. Water
D. Chlorophyll
oxygen is needed as a reactant for cellular respiration
What is cellular respiration ?
Cellular respiration can be defined as the process which occurs in every cells mainly mitochondria of plants and animals, it involve in the break down of sugars in the presence of oxygen and releases energy in the form of ATP.
The waste product of this process are carbon dioxide and water during exhalation process done by lungs, breathing and cellular respiration are related to each other.
At every step of cellular respiration energy is used in the form of ATP and carry out the normal function. It can aerobic and anaerobic respiration on the basis of use of oxygen.
For more details regarding cellular respiration, visit
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An earthquake creates a type of wave that shakes the ground. If a large earthquake occurs in Greece, how can the waves be felt across the sea in Italy?
A.
Waves can be transformed into strong winds that travel across the sea.
B.
Waves do not travel through water, but they can crash the sea into land far away.
C.
Waves can cause a series of earthquakes around the world.
D.
Waves can travel through different media including solid land and water.
What is the meaning of ground state energy?
hope it helps you ❣❣
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An aqueous solution containing 6.06 g of lead(II) nitrate is added to an aqueous solution containing 6.58 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: What is the limiting reactant
Answer:
Pb(NO₃)₂ is the limiting reactant.
The equation is: Pb(NO₃)₂ (aq) + 2KCl (aq) → PbCl₂ (s) ↓ + 2KNO₃ (aq)
Explanation:
We identify our reactants:
Pb(NO₃)₂ → Lead (II) nitrate
KCl → Potassium chloride
Our reaction is:
Pb(NO₃)₂ (aq) + 2KCl (aq) → PbCl₂ (s) ↓ + 2KNO₃ (aq)
1 mol of Lead (II) nitrate reacts to 2 moles of KCl, in order to produce 2 moles of potassium nitrate and 1 mol of slid Lead (II) chloride.
We determine the moles of the reactants:
6.06 g . 1mol /331.2 g = 0.0183 moles of Lead (II) nitrate
6.58 g . 1mol / 74.55g = 0.0882 moles of KCl
2 moles of KCl react to 1 mol of Pb(NO₃)₂
Then, 0.0882 moles of KCl may react to (0.0882 . 1) /2 = 0.0441 moles
We have 0.0183 moles of Pb(NO₃)₂ and we need 0.441 moles. Then, the
Pb(NO₃)₂ is our limiting reactant.
Draw a line to connect the following terms to their definition.
A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pressure of 0.987 atm and changes to 144mL?
*please help*
Answer:
25°C
Explanation:
Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂
(0.947 atm)(150 mL)/25°C = (0.987 atm)(144mL)/T₂
5.682 = 142.128/T₂
T₂ = 142.128/5.682
T₂ = 25.0137272756°C = 25°C
What is the concentration of a strong base solution (of an alkali metal) that has a pH of 11.39?
Answer:
[tex][OH^-]=2.455x10^{-3}M[/tex]
Explanation:
Hello there!
In this case, since a strong base produce OH ions in solution, it possible to first compute the pOH as shown below:
[tex]pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-11.39\\\\pOH=2.61[/tex]
Thus, via the definition of the pOH we can compute the concentration of the strong base as follows:
[tex]pOH=-log([OH^-])[/tex]
Thus, solving for the concentration we obtain:
[tex][OH^-]=10^{-pOH}=10^{-2.61}[/tex]
[tex][OH^-]=2.455x10^{-3}M[/tex]
Best regards!
Which action is not an example of work?
A. pushing a box across the floor
B. picking up a box off the floor
C. holding a tray in the Cafeteria line
D. raising a barbell over your head
C. picking a tray in the cafeteria line
Balance the following equations.
Al4C3 + H2O → Al(OH)3 + CH4
NH3 + O2 → NO + H2O
Answer:
Al4C3 +12 H2O → 4Al(OH)3 + 3CH4
4NH3 + 5O2 → 4NO + 6H2O
Calculate the pH of the buffer solution comprised of 0.20 M HCHO2 and 0.15 M NaCHO2. (Ka for HCHO2 = 1.8 x 10-4)
Answer:
3.62
Explanation:
Using the Henderson-Hasselbach equation:
pH = pKa + log[base]/[acid]
pH = -log(1.8 x 10^-4) + log(0.15/0.20) = 3.62
The pH of acid is between 0-7 on pH scale while for base pH range is from 7-14. Therefore, the pH of of the buffer solution comprised of 0.20 M HCHO₂ and 0.15 M NaCHO₂. (Ka for HCHO2 = 1.8 x 10⁻⁴) is 3.62. pH is a unitless quantity.
What is pH?pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic.
On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7.
Using the Henderson-Hassel Bach equation:
pH = pKa + log[base]/[acid]
pH = -log(1.8 x 10^-4) + log(0.15/0.20) = 3.62
Therefore, the pH of of the buffer solution comprised of 0.20 M HCHO2 and 0.15 M NaCHO2. (Ka for HCHO2 = 1.8 x 10-4) is 3.62.
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In a circuit that has a total current of 4 amps with 4 lightbulbs wired in parallel, what is the current at each bulb?
Answer: 1 A for each lamps
Explanation: we assume lamps are similar and lamps have same resistance.
Then current is divided according Kirchhoff s law equally to all lamps.
aluminium containers are used to store and transport nitric acid(HNO3) but not NAOH why?
Answer:
(i) Concentrated HNO3 can be stored and transported in aluminium containers as it reacts with aluminium to form a thin protective oxide layer on the aluminium surface. This oxide layer renders aluminium passive. (ii) Sodium hydroxide and aluminium react to form sodium tetrahydroxoaluminate(III) and hydrogen gas.
The close packing of particles in solids results in
Answer:
Close packing in crystals refers to space efficient arrangement of constituent particles in a crystal lattice. To understand this packing more clearly we have to assume all particles (atoms, molecules and ions) are of the same spherical solid shape. So the unit cell of a lattice is a cubic shape.
Explanation:
Hope it helps! Correct me if I am wrong :>
Im sure about my answer :>
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Do Newton's Laws still apply in space?
Answer:
Yes, they work in space. I forgot an example, will edit the post when I found it
Hope this helps!
When a substance is a solid it has
A. Potential energy
B. Kinetic energy
C. Gravitational energy
D. Chemical energy
Answer:
potential energy
Explanation:
At point a the object has 30 joules of energy. how much energy does the object have at point b?
Answer:
It’s 10
Explanation:
I looked it up
To solve this we must be knowing each and every concept related to energy and its calculations. Therefore, at point b, 10joule of energy is present.
What is energy?Energy is defined in physics as the ability to accomplish work or heat items. It's a scalar measurement with magnitude but no direction. Energy is maintained, which implies it can change forms but is not generated or destroyed. potential energy transforms into kinetic energy.
One type of energy can be transferred into another without breaking a thermodynamic rule. Not all of these energy sources are equally beneficial in practical applications. At point a the object has 30 joules of energy. At point b, 10joule of energy is present.
Therefore, at point b, 10joule of energy is present.
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what is the formula for tetrahydrogen monocarbide
Answer:
CH4
Explanation:
Tetra is the prefix for four. Hence the H4
Mono is the prefix for one, Hence the C
Methane (aka Tetrahydrogen monocarbide) written as CH4
If 85.6 grams of water are produced by the reaction then how many grams of calcium hydroxide did you start with?
Answer:
I think it would double it's self
How many MOLECULES are in 5.0 grams of sodium chloride? (Use "molecules" as your unit...Enter as 9.9 x 10^99 molecules)
Answer:
[tex]\boxed {\boxed {\sf 5.2 *10^{22} \ molecules \ NaCl}}[/tex]
Explanation:
1. Convert grams to moles
First, convert grams to moles using the molar mass. This can be found on the Periodic Table.
Na: 22.9897693 g/molCl: 35.45 g/molSodium (Na) has an oxidation state of +1 and chlorine (Cl) has an oxidation state of -1, so they combine in a 1:1 ratio for a formula of NaCl. We can simply add their moles masses.
NaCl: 22.9897693 g/mol + 35.45 g/mol = 58.4397693 g/molUse this as a ratio.
[tex]\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]
Multiply by the given number of grams.
[tex]5.0 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]
Flip the fraction so the grams of sodium chloride cancel.
[tex]5.0 \ g \ NaCl *\frac {1 \ mol \ NaCl}{ 58.4397693 \ g \ NaCl}[/tex]
[tex]5.0 *\frac {1 \ mol \ NaCl}{ 58.4397693 }=\frac {5.0 \ mol \ NaCl} { 58.4397693 } = 0.0855581749 \ mol \ NaCl[/tex]
2. Convert moles to molecules
We must use Avogadro's Number. This tells us the amount of particles (molecules, atoms, etc.) in 1 mole of a substance. In this case, it is molecules of sodium chloride.
[tex]\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]
Multiply by the number of moles we calculated.
[tex]0.0855581749 \ mol \ NaCl*\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]
The moles of sodium chloride cancel.
[tex]0.0855581749 *\frac{6.022*10^{23} \ molecules \ NaCl}{1}=5.15231329*10^{22} \ molecules \ NaCl[/tex]
The original measurement of grams has 2 (2 and 0) significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 5 in the hundredth place tells us to round the 1 to a 2.
[tex]5.2 *10^{22} \ molecules \ NaCl[/tex]
metal and one atom of a group
The following Lewis representation depicts a reaction between one atom of a group
nonmetal
eg
X.
+
x*
+
In this representation, each
atom loses
electron(s) and each
atom gains
electron(s)
Teg
The bonds that form in the product would be
Explanation:
X = Group 1 metal
Y = Group 7 Non metal
The dots basically signifies the group.
Metal loses electrons and non metal gains electron. The valency of X is 1 and that of Y is 7.
X atom loses one electron and Y atom gains one electron.
The bond that forms between a metal and a non metal is an ionic bond.
The element with the symbol Na
Select one
Cell
Metalloid
Non metal
Metal
Answer:
metal
Explanation:
it's a soft silvery metal
Suppose you are titrating an acid solution with a base solution of known concentration. To calculate the concentration of the acid solution, use three steps.
1. Use the____of base____the endpoint and the known concentration of the base solution to find the_____of base used.
2. Use the_____to find the moles of acid from the moles of base.
3. Divide the moles of acid by the volume of_____the titration to find the concentration of acid.
Answer:
To calculate the concentration of the acid solution, use three steps.
1. Use the volume of base used at the endpoint and the known concentration of the base solution to find the moles of base used.
2. Use the stoichiometry to find the moles of acid from the moles of base.
3. Divide the moles of acid by the volume of acid used in the titration to find the concentration of acid.
Explanation:
Titration is the process used in volumetric analysis to determine the amount of a substance present in a given sample.
In any titration, a solution of known concentration known as the standard solution is used to react with a solution of of unknown concentration. The reacting volumes of the solutions are then used to calculate the unknown concentration of the second solution.
In acid-base neutralization reactions, an equivalence point/endpoint of the neutralization titration is obtained and is the point at which the moles of H+ is equal to the moles of OH- . An indicator is used to indicate the equivalence point during a titration by a color change observed in the indicator.
In order to calculate the concentration of an acid, we need to know accurately, use three steps:
1. Use the volume of base used at the endpoint and the known concentration of the base solution to find the moles of base used.
2. Use the stoichiometry of the reaction to find the moles of acid from the moles of base.
3. Divide the moles of acid by the volume of acid used in the titration to find the concentration of acid.
In order to calculate the concentration of a base, use three steps:
1. Use the volume of acid used at the endpoint and the known concentration of the acid solution to find the moles of acids used.
2. Use the stoichiometry of the reaction to find the moles of base from the moles of acid.
3. Divide the moles of base by the volume of base used in the titration to find the concentration of base.
What is the pH of this solution?
Answer:
pH = 11.216.
Explanation:
Hello there!
In this case, according to the ionization of ammonia in aqueous solution:
[tex]NH_3+H_2O\rightleftharpoons NH_4^++OH^-[/tex]
We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:
[tex]Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}[/tex]
However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:
[tex]1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M[/tex]
Which is also:
[tex][OH^-]=1.643x10^{-3}M[/tex]
Thereafter we can compute the pOH first:
[tex]pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784[/tex]
Finally, the pH turns out:
[tex]pH=14-2.784\\\\pH=11.216[/tex]
Regards!