• William Shakespeare died on his birthday at
age 52. Approximately how many seconds
did Shakespeare live? (Hint: There are
31,536,000 seconds in one year.)

Answer:

Basically this is because division can be thought of as how many times does the divisor have to be multiplied in order to produce the dividend.

So you would need to multiply 1 8 times in order to produce the dividend,

Similarly, 10 goes into 80 8 times. The zeros are simply cancelled out in the division.

Answer:

a

Step-by-step explanation:

Answer:

to solve this problem I would convert -12/5 into the decimal -2.4 so that I could see it more clearly on the line graph.

after doing that it is easy to see that graph A. is the answer because it is the only one with points on -2.4 and -2.8

hope this helps <3

Answer:B

Step-by-step explanation:  ok its B because i need some $$$

Answer:

D and E

Step-by-step explanation:

The question asks which one would always form an image that is congruent to the pre-image.

Note that Translation, Reflection, and Rotation do not change the size or shape of the pre-image while Dilation will change the size of your pre-image.

Therefore, the most likely answer would be options D and E that do not include dilation in their series of transformations so the image will not change its size making it congruent to the pre-image.

Answer:

x ≥ -6

Domain is just all of the possible x values in a list

Answer:

A

Step-by-step explanation:

The inquality is

[tex]x < - 2[/tex]

So x can only be - 5

This question is incomplete, the complete question is;

Suppose that a researcher using data on class size (CS) and average test scores from 100 third grade classes, estimates the following OLS regression. Test-Score = 520.4 - 5.82 × CS, n = 100, R² = 0.08, SER = 11.5

a. A class has 22 students. What is the regression's prediction for this classroom's average test score?

b. Last year, a class had 19 students, and this year it has 23 students. What is the regression's prediction for the change in the classroom average test score?

c. The sample average class size across the 100 classrooms is 21.4. What is the sample average of the test scores across the 100 classrooms?

d. What is the sample standard deviation of test scores across the 100 classrooms?

Answer:

a)

the regression's prediction for this classroom's average test score is 392.36

b)

the regression's prediction for the change in the classroom average test score is -23.28

c)

the sample average of the test scores across the 100 classrooms is 395.852

d)

the sample standard deviation of test scores across the 100 classrooms is 11.92887

Step-by-step explanation:

Given the data in the question;

Test-Score = 520.4 - 5.82 × CS, n = 100, R² = 0.08, SER = 11.5 -----1

the general formula for the average test score is as follows;

Test score = ^β₀ + ( ^β₁ × CS ) -------- 2

the general for change in test score ;

ΔTest Score = β[tex]_{ class-size[/tex] × ΔClass size  -------- 3

General formula for the sum of squared residuals SSR

SSR = ( n - 2 ) SER² ----- 4

General formula for total sum of squares TSS

TSS = SRR / 1 - R² -------- 5

General formula for sample standard deviation;

Sy = √(TSS / (n-1) )  ------ 6

now, from the given formula;

^β₀ = 520.4

aslo, β[tex]_{ class-size[/tex] = ^β₁ =  - 5.82

so

a) A class has 22 students. What is the regression's prediction for this classroom's average test score?

given that class size CS is 22, to get  the regression's prediction for this classroom's average test score, we make use of formula 2 above;

Test score = ^β₀ + ( ^β₁ × CS )

so we substitute

Test score = 520.4 + ( -5.82  × 22 )

Test score = 520.4 + ( - 128.04 )

Test score = 520.4 - 128.04

Test score = 392.36

Therefore,  the regression's prediction for this classroom's average test score is 392.36

b) Last year, a class had 19 students, and this year it has 23 students. What is the regression's prediction for the change in the classroom average test score.

we make use of formula 3 above

ΔTest Score = β[tex]_{ class-size[/tex] × ΔClass size

we substitute

ΔTest Score = -5.82 × ( 23 - 19 )

ΔTest Score = -5.82 × 4

ΔTest Score = -23.28

Therefore,  the regression's prediction for the change in the classroom average test score is -23.28

c) The sample average class size across the 100 classrooms is 21.4. What is the sample average of the test scores across the 100 classrooms?

we make use of formula 2 above;

Test score = ^β₀ + ( ^β₁ × CS )

we substitute

Test score = 520.4 + ( -5.82 × 21.4 )

Test score = 520.4 + ( -124.548 )

Test score = 520.4 - 124.548

Test score = 395.852

Therefore, the sample average of the test scores across the 100 classrooms is 395.852

d) What is the sample standard deviation of test scores across the 100 classrooms.

first we make use of formula 4 above; to calculate the sum of squared residuals SSR

SSR = ( n - 2 ) SER²

we substitute

SSR = ( 100 - 2 ) (11.5)²

SSR = 98 × 132.25

SSR = 12,960.5

Also, for total sum of squares TSS, we use formula 5

TSS = SRR / 1 - R²

we that R² = 0.08; from the given formula

so we substitute

TSS = 12,960.5 / 1 - 0.08

TSS = 12,960.5 / 0.92

TSS = 14087.5

so, the sample standard deviation will be;

from formula 6 above

Sy = √(TSS / (n-1) )

we substitute

Sy = √(14087.5 / (100-1) )

Sy = √(14087.5 / 99)

Sy = √142.297979

Sy = 11.92887

Therefore, the sample standard deviation of test scores across the 100 classrooms is 11.92887

Answer:

what

Step-by-step explanation:

where is the question its not showing

Answer:

chale. necesita. 20 caracteres

Answer:

$2954.91 end of year eight

Step-by-step explanation:

2000 x 1.05^8 = 2000 x 1.04775 = $2954.91

Proof:

2000 x 1.05 = 2100 end of year one

2100 x 1.05 = 2205 end of year two

2205 x 1.05 = 2315.25 end of year three

2315.25 x 1.05 = 2431.01 end of year four

2431.01 x 1.05 = 2552.56 end of year five

2552.56 x 1.05 = 2680.19 end of year six

2680.19 x 1.05 = 2814.20 end of year seven

2814.20 x 1.05 = $2954.91 end of year eight

Answer:

The answer is C!

Step-by-step explanation:

Answer: B

Step-by-step explanation:

The correct answer is B

The population of the bacteria at the value of P (5) is 384, and it represents that the time is 5 pm

Exponential function is the function in which the function growth or decay with the power of the independent variable. The curve of the exponential function depends on the value of its variable.

The exponential function with dependent variable y and independent variable x can be written as,

[tex]y=a^x[/tex]

Here, a is the variable in the power of a number.

The population of a bacterium doubles every hour. At 9 am, the population is 12 bacteria.

The function models the bacteria population t hours after 9 am  is,

[tex]P (t) = 12\times2^t[/tex]

Put the value of t as 5 at P (5) in the above exponential function as,

[tex]P (5) = 12\times2^5\\P(5)=12\times32\\P(5)=384[/tex]

Hence, the population of the bacteria at the value of P (5) is 384, and it represents that the time is 5 pm.

Learn more about the exponential function here;

https://brainly.com/question/15602982

Answer:

4

Step-by-step explanation:

the total height is 12 and the first half of the shape has a height of 8 so the other part is 4.

Answer:

Step-by-step explanation:

maybe D im not sure tho

Answer:

The answer is A)

Answer: Y = -x/2 + 12.5

Step-by-step explanation:

You wrote the equation strange so i don't really know if the end of the equation is a 25 or not

Answer:

263

Step-by-step explanation:

Answer:

answer is 273

Step-by-step explanation:

use the arithmetic sequence

a86=18+(86-1)(3)

a86=18+ (85)(3)

273

Answer:

D

Step-by-step explanation:

Ed2021

Answer: 21.4

Step-by-step explanation:

If you are here from delta math this is the answer

Answer:

Coordinates of G = [tex](2,0)[/tex]

Step-by-step explanation:

Given: Three vertices of parallelogram DEFG are D(-4,-2), E(-3,1) and F(3, 3).

To find: coordinates of G

Solution:

Midpoints of a side joining points [tex](a,b),\,(c,d)[/tex] are given by [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]

Diagonals of a parallelogram bisect each other.

So,

Midpoint of DF = Midpoint of EG

Midpoint of DF = [tex](\frac{-4+3}{2},\frac{-2+3}{2})=(\frac{-1}{2},\frac{1}{2})[/tex]

Midpoint of EG = [tex](\frac{-3+x}{2},\frac{1+y}{2})[/tex]

Let coordinates of G be [tex](x,y)[/tex]

Therefore,

[tex](\frac{-1}{2},\frac{1}{2}) =(\frac{-3+x}{2},\frac{1+y}{2})\\\\\frac{-1}{2}=\frac{-3+x}{2},\,\frac{1}{2}=\frac{1+y}{2}\\\\-1=-3+x,\,1=1+y\\\\x=-1+3,\,y=1-1\\x=2,\,y=0[/tex]

So,

Coordinates of G = [tex](2,0)[/tex]

Answer:

so the answer is 5

Step-by-step explanation:

the equation will be for this is

7x + 20 = 55

7x = 55-22

7x = 35

x = 35÷7

x=5

Answer:

My vote is for choice 3) ∠2, ∠3, ∠6 and ∠7

Step-by-step explanation:

Each of 2,3,6, & 7, when added to angle 5, add up to 180°

Do supplementary angles have to be adjacent to be supplementary?

No.

Explanation:

The answer is no, as for example:

angles on the same side of a non-parallel sides of a trapezoid and

opposite angles of a cyclic quadrilateral can be supplementary.

Answer:

1.32% of students have the chance to attend the charter school.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

This year the mean on the entrance exam was an 82 with a standard deviation of 4.5.

This means that [tex]\mu = 82, \sigma = 4.5[/tex]

a.What is the percentage of students who have the chance to attend the charter school?

Students who achieve a score of 92 or greater are admitted, which means that the proportion is 1 subtracted by the pvalue of Z when X = 92. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{92 - 82}{4.5}[/tex]

[tex]Z = 2.22[/tex]

[tex]Z = 2.22[/tex] has a pvalue of 0.9868

1 - 0.9868 = 0.0132

0.0132*100% = 1.32%

1.32% of students have the chance to attend the charter school.

Answer:

116.4545454545455

Step-by-step explanation:

Answer:

B

promise it's B trust me

Answer:

x = 14.5°

Step-by-step explanation:

A+D = 180°

(8x-11) + (5y+2) = 180°

simplify:

5y + 8x = 189°

5y = 189 - 8x

D = B

(5y+2) = (4x+17)

simplify

5y = 4x + 15

then:

189 - 8x = 4x + 15

12x = 174

x = 14.5°

5y = 4(14.5) + 15

5y = 73

y = 14.6

check:

5(14.6) + 8(14.5) = 189

73 + 116 = 189

189 = 189

Answer:

✓2=1.41421

✓5=2.23607

✓8=2.82842

✓11=3.31662

✓14=3.74166

Step-by-step explanation:

Therefore the numbers are increasing by three so they cant be perfect square

9514 1404 393

Answer:

  squares are of the form 3n or 3n+1; the sequence is of the form 3n-1, so none of the sequence will be a square

Step-by-step explanation:

The given arithmetic sequence has first term 2 and common difference 3, so its explicit formula is ...

  an = 2 +3(n -1) = 3n -1 . . . . for counting numbers n

__

All integers are of one of these forms: 3n-1, 3n, 3n+1, for some integer n. The squares of these are ...

  (3n -1)² = 9n² -6n +1 = 3(3n² -2) +1 = 3k+1 for some k

  (3n)² = 3(3n²) = 3k for some k

  (3n +1)² = 9n² +6n +1 = 3(3n² +2) +1 = 3k+1 for some k

Note that none of these squares is of the form 3n -1.

Hence, the square of an integer cannot be in the given sequence.

Answer:

An arc is a segment of a circle around the circumference. An arc measure is an angle the arc makes at the center of a circle, whereas the arc length is the span along the arc. This angle measure can be in radians or degrees, and we can easily convert between each with the formula  

π

r

a

d

i

a

n

s

=

180

°

.

Step-by-step explanation: