Explanation:
step 1. a diverging lens is "concave" on both side and always has a negative focal length
step 2. so 1/f = 1/s + 1/s' where f is the focal length, s is the object location, and s' is the image location (f, s, s' are all on the left side of the lens)
step 3. 1/-15 = 1/s + 1/-9 (image is virtual (negative))
step 4. 3/-45 = 1/s + 5/-45
step 5. s = 22.5cm (object is 22.5cm from lens)
step 6. s'/s = 9/22.5 ÷ 0.4 (magnification)
step 7. if the object is 4.5cm then the image is 4.5(0.4) = 1.8cm tall.
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An object has a kinetic energy of 50 J and a velocity of 5 m/s, what is the mass of the
object?
A. 4 kg
B. 55 kg
С. 10 kg
D. 1 kg
Answer:
0.5mv^2=50, v=5, 25/2×m=50, m=50×2/25, So, the answer is 4
You've always wondered about the acceleration of the elevators in the 101 story high Empire State Building. One day, while visiting New York, you take your bathroom scale into the elevator and stand on it. The scale reads 177 lb as the door closes. As the elevator moves upward the scale reading varies between a minimum value of 138 lb and a maximum value of 227 lb as the elevator travels 101 floors.
a. What is the magnitude of the acceleration as the elevator starts upward?
b. What is the magnitude of the acceleration as the elevator brakes to a stop?
Answer:
a) 2.8 m/s2
b) 2.2 m/s2
Explanation:
The lecture on the bathroom scale is equal to the normal force that the scale exerts on you, and is directed upward.There is another force acting on you, which is gravity.This force (which we call weight) is the product of the mass times the acceleration due to gravity, g, and is directed downward, opposite to the normal force.When the elevator is at rest, no acceleration takes place, so according Newton's 2nd Law, no net force must be exerted on you.In this condition, the normal force Fn₀ must be equal to the weight:[tex]F_{no} = m * g = 177 lb (1)[/tex]Since the normal force takes any value needed to satisfy Newton's 2nd law, the two extreme lectures can be expressed as follows, in terms of the two forces acting on you while the elevator is moving upward:[tex]F_{n1} = m * (g +a_{1}) = 227 lb (2)[/tex]
[tex]F_{n2} = m * (g +a_{2}) = 138 lb (3)[/tex]
Replacing m by 177lb/g (a given), and rearranging, we can solve (1) for a₁, as follows:[tex]a_{1} = (\frac{227lb}{177lb} *g) - g = 0.28*g = 0.28*9.8m/s2 = 2.8 m/s2 (4)[/tex]
As it can be seen, the normal force takes a larger value in order to be compliant with the upward acceleration that opposes to gravity.In the same way, we can find the magnitude of the downward acceleration when the elevator brakes to a stop, from (3):[tex]a_{2} = (\frac{138lb}{177lb} *g) - g = -0.22*g =- 0.22*9.8m/s2 = -2.2 m/s2 (5)[/tex]
In this case, the normal force takes a lower value than at rest, due to the acceleration has the same direction as gravity.An Atwood's machine consists of two masses, m1 and m2, connected by a string that passes over a pulley. If the pulley is a disk of radius R and mass M , find the acceleration of the masses. Express your answer in terms of the variables m1, m2, R, M, and appropriate constants.
Answer:
Explanation:
Suppose m₂ is greater than m₁ and it is going down . m₁ will be going up.
Let tension in string be T₁ and T₂ . Let common acceleration of system be a
For motion of m₁
T₁-m₁g = m₁a ----- (1)
For motion of m₂
m₂g- T₂ = m₂a ------- (2)
For motion of pulley
(T₂-T₁ )R represents net torque
(T₂-T₁ )R = I x α where I is moment of inertia of disc and α is angular acceleration of disc
(T₂-T₁ )R = 1/2 M R² x a / R
(T₂-T₁ ) = M a /2
Adding (1) and (2)
(m₂-m₁)g = (m₂+m₁)a + (T₂-T₁ )
(m₂-m₁)g = (m₂+m₁)a + Ma/2
(m₂-m₁)g = (m₂+m₁+ 0.5M)a
a = (m₂-m₁)g / ( (m₂+m₁+ 0.5M)
The acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].
Given to us
Masses = m₁, m₂
The radius of the pulley = R
Mass of the pulley = M
Assumption
Let the mass m₁ > m₂. therefore, the mass m₁ is going down due to its weight while m₂ is going up.Assuming the tension in the string be T₁ and T₂, respectively.Also, the common acceleration in the system is a.Tensions in stringsWe know the acceleration due to gravity is denoted by g,
Tension in string 1, T₁[tex]T_1 = m_1(a+g)[/tex]......... equation 1
Tension in string 2, T₂[tex]T_2 = m_2(a-g)[/tex]......... equation 2
Inertia and acceleration of the pulleyThe inertia of the pulley, [tex]I = \dfrac{1}{2}MR^2[/tex]
Acceleration of the pulley, [tex]a = {\alpha }\times {R}[/tex]
Torque in the pulley[tex](T_2-T_1)R = I \times \alpha \\\\[/tex]
Substitute the values we get,
[tex][m_2(a-g)-m_1(a+g)]R = \dfrac{1}{2} MR^2 \times \dfrac{a}{R}\\\\[/tex]
[tex][m_2a-m_2g-m_1a-m_1g]R= \dfrac{1}{2} MR \times a[/tex]
[tex]m_2a-m_1a-m_2g-m_1g= \dfrac{1}{2} M \times a[/tex]
[tex]a(m_2-m_1)-g(m_2+m_1)= 0.5M \times a[/tex]
[tex]a(m_2-m_1)-0.5Ma=g(m_2+m_1)\\\\a(m_2-m_1-0.5M) = g(m_2+m_1)\\\\a = \dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex]
Hence, the acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].
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A5 N object at a height has gravitational potential energy of 30 J. What is the height of the object?
30=5×h then divide both sides by 5 you will get h=6m
If a 5 N object at a height has a gravitational potential energy of 30 J , then the height of the object would be 6 meters.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
As given in the problem a 5 N object at a height has gravitational potential energy of 30 J, then we have to find the height of the object.
Similarly, the total gravitational potential energy of the object,
PE = m × g × h
30 = 5 × h
h = 30 / 5
h = 6 meters
Thus, if a 5 N object at a height has a gravitational potential energy of 30 J, then the height of the object would be 6 meters.
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1. Budding is a way that some very tiny organisms can reproduce.
True
False
____________________________________
Male-female reproduction needs two parent cells to begin.
True
False
Answer:1.. true 2 false
Explanation:
Constructive interference occurs when the crest of 2 waves meet. This can occur when 2 troughs meet as well. When this occurs, water waves look
A- the same (no change)
B- larger
C- invisible
D- smaller
Answer:
B; LargerExplanation:
I took the K-12 quiz, and that was the correct answer. Hope this helped!Plants are known as producers because they can make their own food. Which of the following provides a list of basic needs a plant must have for photosynthesis to happen?
A.
water and oxygen in the air
B.
soil, energy from the sun, and oxygen in the air
C.
energy from the sun, carbon dioxide in the air, water
D.
soil, carbon dioxide in the air, energy from the sun
HELP PLEASE
Answer:
C .energy from the sun, carbon dioxide in the air, water
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An experimental procedure calls for 35.9 g sodium chloride and 15.2 g silver nitrate. What tool should be used to measure these substances?
Answer:
Electronic Balance
Explanation:
You push
on box A with a horizontal
100-N force (Fig. Q4.31). Box A
weighs 150 N, and box B
weighs 50 N. Is the force that
box A exerts on box B equal to 100 N, greater than 100 N, or less than 100 N? Explain.
Electromagnetic waves used in cell phones are called
a. radio waves
b.microwaves
c. Gamma rays
d. Ultraviolet rays
Answer:
A.Radio waves
Explanation:
When light wave strike a red object, what happens to the light waves of all colors except red?
Answer:
the object absorbs all light except for red. the red light is reflected back into your eyes, which is why it looks red.
can someone pls tell me what a force diagram is
Can you please help me with this worksheet I will give BRAINLISET to whoever answers first?
15. Which tectonic boundary would have many normal faults associated
with it?
A. Convergent
B. Divergent
C. Transform
We observe that a moving charged particle experiences no magnetic force. From this we can definitely conclude that: (A) No magnetic field exists in that region of space. (B) The particle must be moving parallel to the magnetic field. (C) Either no magnetic field exists or the particle is moving parallel to B. (D) Either no magnetic field exists or the particle is moving vertical (perpendicular) to B.
Answer:
(C) Either no magnetic field exists or the particle is moving parallel to B.
Explanation:
The moving charged particle tends to show no magnetic forces. Due to its moving in the same direction and will be parallel to the field. As when the magnetic fed and charged particle velocity is parallel then there will be no force. As the magnetic field are made by the generation of the current with the field line concentric to the current-carrying wire.they enjoy being alone for quit small time
A beam of protons is directed in a straight line along the z direction through a region of space in which there are crossed electric and magnetic fields The electric field is 550 V m in the y direction and the protons move at a constant speed of 105 m s 1 What must be the magnitude of the magnetic field such that the beam of protons continues along its straight line trajectory Express your answer using two significant figures
Answer:
B = 5.23 T
Explanation:
Given that,
Electric field, E = 550 V/m
The speed of the proton, v = 105 m/s
We need to find the magnitude of the magnetic field such that the beam of protons continues along its straight-line trajectory.
To move in a straight line, the magnitude of the electric force from the field and the magnetic field must be equal i.e.
[tex]qE=qvB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{550}{105}\\\\B=5.23\ T[/tex]
So, the magnitude of the magnetic field is equal to 5.23 T.
If a force is applied, but the object does
not move, what can we say about the
amount of work that is done?
A. Some work is done.
B. No work is done.
C. The work equals the force.
D. A large amount of work is done.
Answer:
doesn't move, no work is done; if a force is applied and the object moves a distance d in a direction other than the direction of the force, less work is done than if the object moves a distance d in the direction of the applied.
Answer:
B. No work is done.
Explanation:
Work is only done when the object moves in the direction of the force.
Two copper rods are rubbed together will they become charged
Answer:
Explanation:When insulating materials rub against each other, they may become electrically charged . Electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. The material that gains electrons becomes negatively charged.
What is the gravitational potential energy of a 3 kg ball that is 1 meter above the floor?
Answer:
PE=mgh
M= Mass (kg)
G= Gravitational field strength (N/kg)
H= Hight (m)
PE= Gravitational Potential Energy (J)
Explanation:
Gravitational Potential Energy is the energy stored in a object due to its position above the Earth's surface.
The potential energy of the ball is 29.4 joules
The parameters given are;
mass= 3 kg
height= 1 meter
g= 9.8 m/s²
P.E= mgh
= 3 × 9.8 × 1
= 29.4
Hence the potential energy is 29.4 joules
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A U-tube with a cross-sectional area of 1.00 cm2 is open to the atmosphere at both ends. Water is poured into the tube until the water rises part-way along the straight sides, and then 5.00 cm3 of oil is poured into one end. As a result, the top surface of the oil ends up 0.550 cm higher than the water surface on the other side of the U. What is the density of the oil
Answer:
0.89 g/cm^3 = 890 kg/m^3
Explanation:
Cross sectional area of U-tube ( A ) = 1.00 cm^2
volume of oil ( V ) = 5.00 cm^3
change between top surface = 0.550 cm
height of oil = 5 cm ( volume / area )
height of water = 5 - 0.550 = 4.45 cm
pressure at the oil-water junction = Pressure on the second side of the U-tube at same level
Po * g * Hoil = Pw * g * Hwater
Po * 5 = 1 * 4.45
∴ Density of oil ( Po ) = 4.45 / 5 g/cm^3 = 0.89 g/cm^3
Which device increases or decreases voltage as electricity is transmitted from power plants to homes and businesses?
generator
power line
transformer
turbine
Answer:Transformer
Explanation:All the other devices generate their own electricity apart from power line and Transformer, power line just carries electricity. A transformer can be used to step up or step down voltages from a source.
Answer:
transformer!! :)
Explanation:
An airplane of mass 13300 kg is flying in a straight line at a constant altitude and with a speed of 560.0 km/hr. The force that keeps the airplane in the air is provided entirely by the aerodynamic lift generated by the wings. The direction of this force is perpendicular to the wing surface. Calculate the magnitude of the lift generated by the wings of this airplane.
Answer:
The magnitude of the lift generated by the wings of the airplane is 130,340 N.
Explanation:
Given;
mass of the airplane, m = 13,300 kg
speed of the airplane, v = 560 km/h = 155.56 m/s
The magnitude of the lift generated by the wings of the airplane is calculated as;
[tex]F_l = mg\\\\where;\\\\F_l \ is \ the \ magnitude \ of \ the \ lift \ generated\\g \ is \ acceleration \ due \ to \ gravity = 9.8 \ m/s^2\\\\F_l = 13,300 \times \ 9.8\\\\F_l = 130,340 \ N[/tex]
Therefore, the magnitude of the lift generated by the wings of the airplane is 130,340 N.
What is the amount of thermal energy needed to make 5 kg of ice at - 10 °C to
steam at 100 °C? (Heat of fusion of Ice is 3.34 x 10 j/kg, specific heat capacity of
ice is 2.09 x 10 3 J/kg °C, Specific heat capacity of water is 4.186 x 10 ? J/kg° C,
Heat of vaporization of water 2.26 x 10 J/kg)
Answer:
The amount of thermal energy needed is 15167500 joules.
Explanation:
By First Law of Thermodynamics, we see that amount of thermal energy ([tex]Q[/tex]), in joules, is equal to the change in internal energy. From statement we understand that change in internal energy consisting in two latent components ([tex]U_{l,ice}[/tex], [tex]U_{l,steam}[/tex]), in joules, and two sensible component ([tex]U_{s,w}[/tex]), in joules, that is:
[tex]Q = U_{l,ice} + U_{s, w} + U_{s,ice} + U_{l,steam}[/tex] (1)
By definitions of Sensible and Latent Heat, we expanded the formula:
[tex]Q = m\cdot (h_{f,w}+h_{v,w}+c_{ice}\cdot \Delta T_{ice}+c_{w}\cdot \Delta T_{w})[/tex] (2)
Where:
[tex]m[/tex] - Mass, in kilograms.
[tex]h_{f,w}[/tex] - Latent heat of fussion of water, in joules per kilogram.
[tex]h_{v,w}[/tex] - Latent heat of vaporization of water, in joules per kilogram.
[tex]c_{ice}[/tex] - Specific heat of ice, in joules per kilogram per degree Celsius.
[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram per degree Celsius.
[tex]\Delta T_{ice}[/tex] - Change in temperature of ice, measured in degrees Celsius.
[tex]\Delta T_{w}[/tex] - Change in temperature of water, measured in degrees Celsius.
If we know that [tex]m = 5\,kg[/tex], [tex]h_{f,w} = 3.34\times 10^{5}\,\frac{J}{kg}[/tex], [tex]h_{v,w} = 2.26\times 10^{6}\,\frac{J}{kg}[/tex], [tex]c_{ice} = 2.090\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]c_{w} = 4.186\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]\Delta T_{ice} = 10\,^{\circ}C[/tex] and [tex]\Delta T_{w} = 100\,^{\circ}C[/tex], then the amount of thermal energy is:
[tex]Q = 15167500\,J[/tex]
The amount of thermal energy needed is 15167500 joules.
In 1994, Leroy Burrell of the United States set what was then a new world record for the men’s 100 m run. He ran the 1.00 102 m distance in 9.5 s. Assuming that he ran with a constant speed equal to his average speed, and his kinetic energy was 3.40 103 J, what was Burrell’s mass?
Answer:
61.33 Kg
Explanation:
From the question given above, the following data were obtained:
Distance = 1×10² m
Time = 9.5 s
Kinetic energy (KE) = 3.40×10³ J
Mass (m) =?
Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:
Distance = 1×10² m
Time = 9.5 s
Velocity =?
Velocity = Distance / time
Velocity = 1×10² / 9.5
Velocity = 10.53 m/s
Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:
Kinetic energy (KE) = 3.40×10³ J
Velocity (v) = 10.53 m/s
Mass (m) =?
KE = ½mv²
3.40×10³ = ½ × m × 10.53²
3.40×10³ = ½ × m × 110.8809
3.40×10³ = m × 55.44045
Divide both side by 55.44045
m = 3.40×10³ / 55.44045
m = 61.33 Kg
Thus, the mass of Leroy Burrell is 61.33 Kg
At the end of the previous experiment, aclumsy scientist drops the coil, while still in the magnetic field, and still oriented with its plane perpendicular to the magnetic field, denting it and changing its shape to a semi-circle. The new shape has the same perimeter, but a different area, and it takes 0.036s to deform. What isthe average induced EMF during this mishap
Answer:
hello your question has some missing parts below are the missing parts
A Circular, 10-turn coil has a radius of 10.7 cm and is oriented with its plane perpendicular to a 0.2-T magnetic field.
answer : 1 volt
Explanation:
Determine the Average induced EMF during this mishap
A' = A/2 ( for a semi circle )
where A = [tex]\frac{\pi r^2}{2}[/tex]
To determine the Average induced EMF apply the relation below
| E | = η * [tex]\frac{\beta A}{T}[/tex] ----- ( 1 )
Replace A in equation 1 with A = [tex]\frac{\pi r^2}{2}[/tex]
hence equation becomes : | E | = η * βπr^2 / 2T'
where : T' = 0.0365 , β = 0.2 , η = 10 , r = 0.107
∴| E | = 0.999 ≈ 1volts
How much work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s?
50 J,
12.5 J,
25 J,
49 J
Answer:
The correct option is (b).
Explanation:
We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.
We know that, the work done is equal to the kinetic energy of an object i.e.
[tex]W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J[/tex]
So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.
On a spaceship designed to support a multiyear voyage to the outer planets of the solar system, plants will be grown to provide oxygen and to recycle carbon dioxide. Because the spaceship will be so far from the sun, an artificial light source will be needed to support photosynthesis. Which wavelengths of light should be used to maximize plant growth?
Answer:
A mixture of blue & red light.
Explanation:
During photosynthesis, the oxygen delivered emanates from water particles and if a weighty isotope of oxygen atom was noticed in delivered sub-atomic oxygen, the water atoms were marked with the hefty isotope.
In order to maximize the growth rate of the plant, the required wavelength of light to be used is a mixture of blue & red light. This is on the grounds that as the absorption optima of plant's photoreceptors are at wavelength frequency of red and blue light, subsequently the combination of red and blue light would be ideal for plant growth and development.
The productivity of red (650–665 nm) LEDs on plant development is straightforward on the grounds that these wavelength frequencies entirely fit with the retention pinnacle of chlorophylls and phytochrome, while the enhanced blue light presented the possibility that development under regular light could be mirrored utilizing blue and red LEDs with negligible use of energy.
A car wheel turns through 12pi in 10.7s calculate the angular speed of the wheel
Answer:
The answer should be D..
Explanation:
Which of the following parallel plate diagrams would have the greatest electric fields between them?
The greatest electric field between them is Option B.
An electric field is the physical subject that surrounds electrically charged particles and exerts a force on all other charged debris inside the area, either attracting or repelling them. It also refers back to the bodily field of a machine of charged particles.
Reasoning:-
Electric field = Kq/r²
Since the distance is inversely proportional to the square root of the distance between them. therefore decreasing the distance electric field will be the greatest. Hence Option B.
The electrical field is defined mathematically as a vector discipline that can be related to each point in space, the force in step with unit charge exerted on a fine take a look at the price at rest at that factor. the electric field is generated by the electrical rate or through time-varying magnetic fields. electric fields provide us with the pushing force we need to set off the contemporary float.
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