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Related Questions
Slow cooling of magma leads to the formation of large crystals, such as halite and calcite.
Select the correct response:
True
False
Answers
What is the molarity of 42.1 g of AgNO3 dissolved in 1.75 L of solution?
2.31 M
B 0.248 M
C 0.142 M
D 24.1 M
Answers
GUYS HELP PLS QUICK LOTS OF POINTS AND BRAINLIEST!
A 0.250 M solution was prepared from 135 mL of a 7.00 solution. What volume of water (in mL) was required for dilution?
Answers
Answer:
385
Explanation:
0.250m Converted to 250 mL then 250+135+ the answer
I'm not sure?
dlaczego emaliowane garnki rdzewieją w miejscach uszkodzenia emalii
Answers
Answer:
Explanation: I don’t even know what you said
Answer:
so basically
Explanation:
bsuxnssu hhusnn ji
37.2 moles of hydrogen gas would have what mass?
Your answer
Answers
Answer:
74.99g
Explanation:
Mass of a substance can be calculated by using the formula;
mole = mass ÷ molar mass
mass = molar mass × mole
According to this question, 37.2 moles of hydrogen gas is given.
Molar mass of hydrogen gas (H2) = 1.008(2) = 2.016g/mol
mass = 2.016 × 37.2
Mass of H2 = 74.995
Mass = 74.99g
What is the process of old crust sinking back into the mantle? *
a. earthquake
b. transform boundary
c. seafloor spreading
d. subduction
Answers
Answer:
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A gas system has an initial number of moles of 0.693 moles with the volume unknown. When the number of moles changes to 0.928 moles volume is found to be 7.98 L. What was the initial volume in mL?
Answers
Answer:
The initial volume in mL is 5959.2 mL
Explanation:
As the number of moles of a gas increases, the volume also increases. Hence, number of moles and volumes are directly proportional i.e
n ∝ V
Where n is the number of moles and V is the volume
Then, n = cV
c is the proportionality constant
∴n/V = c
Hence n₁/V₁ = n₂/V₂
Where n₁ is the initial number of moles
V₁ is the initial volume
n₂ is the final number of moles
and V₂ is the final volume.
From the question,
n₁ = 0.693 moles
V₁ = ?
n₂ = 0.928 moles
V₂ = 7.98 L
Putting the values into the equation
n₁/V₁ = n₂/V₂
0.693 / V₁ = 0.928 / 7.98
Cross multiply
∴ 0.928V₁ = 0.693 × 7.98
0.928V₁ = 5.53014
V₁ = 5.53014/0.928
V₁ = 5.9592 L
To convert to mL, multiply by 1000
∴ V₁ = 5.9592 × 1000 mL
V₁ = 5959.2 mL
Hence, the initial volume in mL is 5959.2 mL
Calculate the equilibrium constant of the reaction below if the pressures are 1.0atm, 2.0 atm, and 1.0 atm respectively. PCl3 + Cl2 <--> PCl5
Answers
Answer:
K = 0.5
Explanation:
Based on the reaction:
PCl₃ + Cl₂ ⇄ PCl₅
The equilibrium constant, K, is defined as:
K = P PCl₅ / P PCl₃ * P Cl₂
Where P represent the pressure at the equilibrium for each one of the gases involved in the equilibrium.
As:
P PCl₅ = 1.0atm
P PCl₃ = 1.0atm
P Cl₂ = 2.0atm
K = 1.0atm / 1.0atm * 2.0atm
K = 0.5Which reaction type is really part of another type of reaction but treated separately? Explain
Answers
Answer:
Oxidation - reduction reaction which is called redox reaction.
Explanation:
The type of reaction that is a part of another type but treated separately is called Oxidation - reduction reaction.
Thus is because they usually involve 2 separate half reactions which are oxidation reactions that involve loss of electrons and then reduction equations which involve gain of electrons.
They are treated separately for example when sodium reacts with chlorine to form sodium chloride.
2Na + Cl2 = 2NaCl
Now, sodium undergoes oxidation by loosing elctrons and it's half reaction is;
2Na → 2Na^(+) + 2e^(-)
Meanwhile chlorine undergoes reduction by gaining electrons and its half reaction is;
Cl2 + 2e^(-) → 2Cl^(-)
Acid rain due to air pollution when water reacts with sulfur dioxide, nitric oxide, and carbon dioxide, causes
Answers
Answer:
Acid rain is caused by a chemical reaction that begins when compounds like sulfur dioxide and nitrogen oxides are released into the air. These substances can rise very high into the atmosphere, where they mix and react with water, oxygen, and other chemicals to form more acidic pollutants, known as acid rain.
Explanation:
7. A certain hydrocarbon, CxHy, is burned (reacts with O2 gas) and produces 1.955 g of CO2 for every
1.000 g of H20. What is the empirical formula of this hydrocarbon?
CxHy + (X + y/4) O2 -> xCO2 + y/2 H2O
Answers
Answer:
The empirical formula of the hydrocarbon is C₂H₅
Explanation:
The formula for the hydrocarbon is [tex]C_xH_y[/tex]
The mass of CO₂ produced per 1,000 g of H₂O = 1,955 g
The equation for the chemical reaction is given as follows;
[tex]C_xH_y[/tex] + (x + y/4) O₂ → XCO₂ + y/2H₂O
From the given chemical equation, counting the number of atoms on both sides of the equation, we have;
The molar mass of CO₂ = 44.01 g/mol
The molar mass of H₂O = 18.01528 g/mol
The number of moles of H₂O in 1,000 g of H₂O = 1,000 g/(18.01528 g/mol) = 55.5084351 moles
The number of moles of CO₂ in 1,955 g of H₂O = 1,955 g/(44.01 g/mol) = 44.4217223 moles
Therefore, given that X moles of CO₂ is produced alongside Y/2 moles of H₂O. we have;
X = 44.4217223, Y/2 = 55.5084351
∴ Y = 2 × 55.5084351 = 111.0168702
The ratio of X to Y = X/Y = 44.4217223/111.0168702 = 0.40013488238
∴ The ratio of X to Y = X/Y ≈ 0.4 = 4/10
X/Y ≈ 4/10
The empirical formula is the representation of molecular formula in the smallest whole number ratio of the elements of the molecules
Therefore, when X = 4, Y = 10, from which we have the smallest ratio as;
When X = 2, Y = 5
The empirical formula of the hydrocarbon is therefore, [tex]C_xH_y[/tex] = C₂H₅
The given chemical equation becomes;
C₂H₅ + (2 + 5/4) O₂ → 2CO₂ + 5/2H₂O
C₂H₅ + 3.25 O₂ → 2CO₂ + 2.5 H₂O
We then have;
4C₂H₅ + 13 O₂ → 8CO₂ + 10 H₂O
The empirical formula of the hydrocarbon, [tex]C_xH_y[/tex] = C₂H₅.
__M+__Q2----->___MQ3
Answers
Answer: 2M + 3Q2 -----> 2MQ3
Explanation:
2 Ms either side, and 6 Qs either side
If the speed of a wave is 150 m/s and its frequency is 2 Hz, what is its wavelength?
A. 300m
B. 75m
C. 152m
D. 148m
Answers
Answer:
75m
Explanation: