WILL MARK BRAINLIEST! The ratio of the angles in a triangle is 2:3:5. What are the angle measures?
Thank you!
Answers
i added and subtracted the numbers to find out that the ratio between the numbers on B are correct
Related Questions
Which statement is correct?
Thank you for anyone who answers
Answers
Answer:
I believe the correct answer is C
Seven students volunteered for a comparison of study guides for an advanced course in mathematics. They were randomly assigned, four to study guide A and three to study guide B. All were instructed to study independently. Following a two-day study period, all students were given an examination about the material covered by the guides, with the following results:Study Guide A scores: 68; 77; 82; 85Study Guide B scores: 53; 64; 71Perform a randomization test by listing all possible ways that these students could have been randomized to two groups. There are 35 ways. For each outcome, calculate the difference between sample averages. Finally, calculate the two-sided p-value for the observed outcome
Answers
Answer:
Step-by-step explanation:
From the given question; we can use the R software to program the combination function that generates all the combinations.
options(digits =2(
scores<- c(68,77,82,85,53,64,71)
groupA <- combn(scores,4)
groupB <- apply(groupA,2, function(x) scores[! (scores %in% x) ] )
colnames(groupA) <- colnames(groupB) <- paste("G", 1:35, sep"")
The accompanying 35 groupings (G1 to G35) contain all potential ways these understudies can be randomized under the null hypothesis
Group A
[tex]\text{G1 \ G2 \ G3 \ G4 \ G5 \ G6 \ G7 \ G8 \ G9 \ G10\ G11\ G12 \ G13 \ G14}[/tex]
[tex]\text{68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68}[/tex]
[tex]\text{77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 82 \ \ 82 \ \ 82 \ \ 82}[/tex]
[tex]\text{82 \ \ 82 \ \ 82 \ \ 82 \ \ 85 \ \ 85 \ \ 85 \ \ 53 \ \ 53 \ \ 64 \ \ 85 \ \ 85 \ \ 85 \ \ 53}[/tex]
[tex]\text{85\ \ 53 \ \ 64 \ \ 71 \ \ 53 \ \ 64\ \ 71\ \ 64 \ \ 71 \ \ 71 \ \ \ 53 \ \ \ 64 \ \ 71 \ \ 64}[/tex]
[tex]\text{G15 G16 G17 G18 G19 G20 G21 G22 \ G23 \ G24 \ G25 \ G26 \ G27}[/tex]
[tex]\text{68 \ \ \ 68 \ \ \ 68 \ \ \ 68 \ \ \ 68 \ \ \ 68 \ \ \ 77 \ \ \ 77 \ \ \ 77 \ \ \ 77 \ \ \ 77 \ \ \ 77 \ \ \ 77}[/tex]
[tex]\text{82 \ \ \ 82 \ \ \ 85 \ \ \ 85 \ \ \ 85 \ \ \ 53 \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ 85}[/tex]
[tex]\text{53 \ \ \ 64 \ \ \ 53 \ \ \ 53 \ \ \ 64 \ \ \ 64 \ \ \ 85 \ \ \ 85 \ \ \ 85 \ \ \ 53 \ \ \ 53 \ \ \ 64 \ \ \ 53}[/tex]
[tex]\text{71\ \ \ \ 71\ \ \ \ 64\ \ \ \ \ 71\ \ \ \ 71\ \ \ \ 71\ \ \ \ 53\ \ \ \ 64\ \ \ \ 71\ \ \ 64\ \ \ \ 71\ \ \ \ 71\ \ \ \ 64}[/tex]
[tex]\text{G28 G29 G30 G31 G32 G33 G34 \ G35} \\ \\ 77 \ \ \ \ 77 \ \ 77 \ \ \ \ 82\ \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ \ \ 85 \\ \\ 85 \ \ \ 85 \ \ \ 53 \ \ \ \ 85 \ \ \ 85 \ \ \ 85 \ \ \ \ 53 \ \ \ 53 \\ \\ 53 \ \ \ 64 \ \ 64 \ \ \ 53 \ \ \ \ 53 \ \ \ 64 \ \ \ \ 64\ \ \ 64 \\ \\ 71 \ \ 71 \ \ \ 71 \ \ 64 \ \ \ 71 \ \ \ \ 71 \ \ \ \ 71 \ \ \ \ 71[/tex]
Group B
[tex]\text{G1 \ G2 \ G3\ G4\ \ G5\ \ G6\ \ G7\ \ G8 \ \ G9\ \ G10\ \ G11\ \ G12\ \ G13\ G14 \ G15}[/tex]
[tex]\tet{53 \ \ 85 \ \ \ \ 85 \ \ \ \ 85\ \ \ \ 82 \ \ \ \ 82\ \ \ \ 82 \ \ \ \ 82\ \ \ \ 82 \ \ \ \ 82 \ \ \ \ 77\ \ \ \ 77\ \ \ \ 77\ \ \ \ 77\ \ \ \ 77}[/tex]
[tex]\text{64 \ \ \ 64 \ \ \ 53 \ \ \ 53 \ \ \ 64 \ \ \ 53 \ \ \ 53 \ \ \ 85 \ \ \ 85 \ \ \ 85 \ \ \ 64 \ \ \ 53 \ \ \ 53 \ \ \ 85 \ \ \ 85}[/tex]
[tex]\text{71 \ \ \ 71 \ \ \ 71 \ \ \ 64 \ \ \ 71 \ \ \ 71 \ \ \ 64 \ \ \ 71 \ \ \ 64 \ \ \ 53 \ \ \ 71 \ \ \ 71 \ \ \ 64 \ \ \ 71 \ \ \ 64}[/tex]
[tex]\text{G16 \ G17 \ G18 \ G19 \ G20 \ G21 \ G22\ \ G23\ \ G24\ \ G25 \ \ G26 \ \ G27\ \ G28}[/tex]
[tex]\text{77\ \ \ \ 77\ \ \ \ 77\ \ \ \ \ 77\ \ \ \ \ 77\ \ \ \ \ 68\ \ \ \ 68\ \ \ \ 68\ \ \ \ 68\ \ \ \ 68\ \ \ \ \ 68\ \ \ \ \ 68\ \ \ \ \ 68}[/tex]
[tex]\text{85 \ \ \ \ 82\ \ \ \ 82 \ \ \ \ 82 \ \ \ \ 82 \ \ \ \ 64 \ \ \ \ 53 \ \ \ \ 53 \ \ \ \ 85 \ \ \ \ 85\ \ \ \ 85 \ \ \ \ 82\ \ \ \ 82}[/tex]
[tex]\text{53\ \ \ \ 71\ \ \ \ 64\ \ \ \ 53\ \ \ \ 85\ \ \ \ 71\ \ \ \ 71\ \ \ \ 64\ \ \ \ 71\ \ \ \ 64\ \ \ \ 53\ \ \ \ 71\ \ \ \ 64}[/tex]
[tex]\text{ G29 \ G30\ G31 \ G32 \ G33 \ G34 \ G35} \\ \\ \text{68 \ \ \ 68 \ \ \ 68 \ \ \ \ 68 \ \ \ \ 68 \ \ \ 68 \ \ \ \ \ 68} \\ \\ \text{82 \ \ \ 82 \ \ \ \ 77 \ \ \ \ 77 \ \ \ \ 77 \ \ \ \ 77 \ \ \ \ 77} \\ \\ \text{53 \ \ \ 85 \ \ \ \ 71 \ \ \ \ 64 \ \ \ \ 53\ \ \ \ 85 \ \ \ \ 82} \\ \\[/tex]
The accompanying data below computes the distinctions for each group:
[tex]difference <- colMeans(groupA) - colMeans(groupB)[/tex]
[tex]\text{G1 G2 G3 G4 G5 G6 G7 G8 G9 \ G10 G11 G12 G13 G14 G15} \\ \\ \text{15 -3.3 3.1 7.2 -1.6 4.8 8.9 -14 -9.8 -3.3 1.3 \ 7.8 \ 12 \ -11 \ \ -6.8}[/tex]
[tex]\text{G16 G17 G18 G19 G20 G21 G22 G23 G24 G25 G26 G27 G28} \\ \\ \text{-0.42 \ -9.2\ -5.1\ 1.3 \ -17\ \ 6.6 \ \ 13 \ 17 \ \ -5.7\ -1.6 \ \ 4.8 \ \ -3.9 \ \ 0.17}[/tex]
[tex]\text{ G29\ \ G30 \ G31 \ G32 \ \ G33 \ G34 \ \ G35} \\ \\ \text{6.6 \ \ \ -12 \ \ \ -1 \ \ \ 3.1 \ \ \ 9.5 \ \ \ -9.2 \ \ \ -7.4}[/tex]
The two-sided p-value is the extent of contrasts between test midpoints as large or bigger in supreme value than the primary group. The cat function makes the outcomes simpler to peruse.
p <- sum (aba(difference)>=difference[1])/35
cat(p)
= 0.086
the truth table for the formula (X → Y ) ∨ (Z → ¬X)
Answers
Answer:
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
Step-by-step explanation:
Let [tex]A[/tex] denote a Boolean variable.
The negation of [tex]A[/tex] ([tex]\lnot A[/tex]) is false if when [tex]\!A[/tex] is true, and true when [tex]A\![/tex] is false. In a truth table:
[tex]\begin{array}{c||c} A & \lnot A \\ \cline{1-2} \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c||c} A & \lnot A \\ \hline \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].
Let [tex]B[/tex] denote another Boolean variable. The material implication "[tex]A[/tex] implies [tex]\!B[/tex]" ([tex]A \to B[/tex]) is true unless [tex]B\![/tex] is false when [tex]A\![/tex] is true.
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex]
The logical or "[tex]A[/tex] or [tex]B[/tex]" is true when either [tex]A\![/tex] or [tex]B\![/tex] is true (and also when both are true.)
[tex]\begin{array}{c|c||c} A & B & A \lor B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm T \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F\end{array}[/tex]
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].
Start by finding the value of [tex]\lnot X[/tex], [tex](X \to Y)[/tex], and [tex](Z \to \lnot X)[/tex] for each of the [tex]2^3 = 8[/tex] possible combinations of [tex]X[/tex], [tex]Y[/tex], and [tex]Z[/tex].
[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \cline{1-6} \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \cline{1-6} \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].
[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].
The value of [tex](X \to Y) \lor (Z \to \lnot X)[/tex] is true whenever either [tex](X \to Y)[/tex] or [tex](Z \to \lnot X)[/tex] is true (or both.) The combination [tex]X = \rm T[/tex], [tex]Y = \rm F[/tex], and [tex]Z = \rm T[/tex] is the only one among the eight where neither [tex](X \to Y)\![/tex] nor [tex](Z \to \lnot X)\![/tex] is true. [tex](X \to Y) \lor (Z \to \lnot X)\![/tex] would evaluate to true for all other combinations.
Hence, the truth table would be:
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
HELP ME HELP ME PLEASEEE
Answers
Linear Functions Unit Portfolio Directions: Complete each of the tasks outlined below. Cab companies often charge a flat fee for picking someone up and then charge an additional fee per mile driven. Pick a U.S. city and research the rates of two different cab companies in that city. Find companies that charge different amounts per mile and have different flat fees. If you have trouble finding this information for two companies, you can make up what you think would be reasonable prices for a cab's flat rate and a cab's rate per mile. Task 1 a. For the first company, express in words the amount the cab company charges per ride and per mile. b. Write an equation in slope-intercept, point-slope, or standard form. Explain why you chose the form you did. C. What do the slope and y-intercept mean in the context of this problem? Hint: What do you pay when you step into the cab? Task 2 For the second company, express in a table the cost of the cab ride given the number of miles provided. A. Write and equation in slope-intercept, point-slope, or standard form. Explain why you chose the form you did. B. What does the slope mean in the context of the problem? Task 3 Cabs use a valuable commodity—gas! Research average gas prices from 2005-2015 for the city you chose. If you can't find this information for your specific city, you can research national gas price averages instead. A. Create a table showing the average gas price each year. B. Create a scatter plot of the data in your table. C. What equation models the data? What are the domain and range of the equation? Do you think your equation is a good fit for the data? Explain how you determined your answers. D. Is there a trend in the data? Does there seem to be a positive correlation, a negative correlation, or neither? How much do you expect gas to cost in 2020? Explain.
Answers
Answer:
Hope this helps you!!!
Have a great day!!!
At noon, a tank contained 20 cm of water. After several hours, it contained 18 cm of water. What is the
percent decrease of water in the tank?
The percent decrease of water in the tank is
%.
Answers
Answer:
10%Step-by-step explanation:
Percentage decrease = Difference/Original value
So,
Percentage decrease
[tex] = \frac{2}{20} \times 100 \\ = 2 \times 5 \\ = 10[/tex]
So there fore the percentage decrease is 10%
Help me by please this is kinda hard for my child and I forgot it
Answers
When you multiply both the numerator and denominator by the same number, you will have an equivalent to the fraction you started with because the new fraction can be reduced to the original fraction.
2/3 = 4/6 = 6/9 = 8/12 = 10/15 = 12/15 etc.
x2-25 -0
Respuesta y procedimiento
Answers
Answer:
=x2+−25+0
=x2+−25+0
=(x2)+(−25+0)
=x^2+−25
Aqui esta la respuesta y el procedimiento
What is the sum of the interior angles of nonregular hexagons?
Answers
Answer:
They add up to 720 degrees
Answer:
360 I think. Hope i helped! :)
Pleaseeeeeeeeee helppppp
Answers
=10x4/2x8
=160m^3
Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen at random from box A and placed in box B. Now, a poker chip is chosen at random from those now in box B. What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?
Answers
Answer:
0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Coin chosen from box B is red.
Event B: Blue poker chip transferred.
Probability of choosing a red coin:
7/10 of 4/9(red coin from box A)
6/10 of 5/9(blue coin from box A). So
[tex]P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444[/tex]
Blue chip transferred, red coin chosen:
6/10 of 5/9. So
[tex]P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333[/tex]
What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172[/tex]
0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red
Based on the pattern above, how many squares will be in step 4?
15
16
20
25
Answers
Solve for X.
Your answer must be simplified.
-3
Answers
Answer:
x>13
Step-by-step explanation:
Find the positive of x that makes the equation true.
x^2 = 225
Answers
Answer:
x = 15
Step-by-step explanation:
15 * 15 = 225
Answer:
X = 15
Step-by-step explanation:
This is because if you square 15, you get 225.
a dog trainer has 104ft of fencing that will be used to create a retangular work area for dogs. If the trainer wants to enclosed an area of 532ft what will be the dimensions of the work area?
Answers
36 ft by 16 ft
Step-by-step explanation:
To solve this problem, you need to find dimensions of a rectangle such that the perimeter is 104 ft and the area is 576 ft. The perimeter is twice the sum of length and width, so the sum of length and width is 52 ft.
The area is the product of length and width, so if w represents the width, we have ...
w(52 -w) = 576
w² -52w = -576 . . . . . eliminate parentheses, multiply by -1
w² -52w +26² = 26² -576 . . . . . . complete the square
(w -26)² = 676 -576 = 100
w = 26 ±√100 = {16, 36}
If the width is the short dimension, it is 16 feet. Then the length is 36 feet. Let me know if I’m right
Help me ASAP for heart, 5 star rating and comment
There is 8 questions which will be posted one after the other. Questions 1-7 the person who answers correctly and quickly will get a heart and 5 star rating and comment and for the 8th question the correct person will get the rewards + brainiest.
1. If U = 35 and V = 7 and T =4 and V = U + AT. How much Is A worth
This question is worth 10 points numbers WILL get higher
Answers
Answer:
A=-7
Step-by-step explanation:
7=35+A4
4A=-28
A=-7
Evaluate the expression for r=250.
4.5r?
Answers
Answer:
you would do 4.5 * 250 and then you would get an answer of 1125
Step-by-step explanation:
hope this helps have a great rest of your day/night
Which of the following temperatures is the COLDEST?
P: -13
Q: 59
R: -15
S: 32
Answers
Answer:
the temperature which is coldest is R.-15
PLEASE HELP MEEEEE ASAP 100 POINTS
Answers
Answer:
3. D 4. B
Step-by-step explanation:
3. e^2 = g^2 + f^2, answer is d
4. Let a = 3, b = 4, c = 5
2c = 10
2b = 8
2a = 6
10^2 = 8^2 + 6^2
answer is b
3. The Pythagorean theorem states the hypotenuse squared is equal to each side squared added to each other.
The answer is D. E^2 = f^2 + g^2
4.
To keep the proportion you could multiply the sides by the same numbers . The answer would be 2A, 2b, 2c
A row of plaques covers 288 square feet of space along a wall.
If the plaques are 6 feet tall, what length of the wall do they cover?
Answers
Answer:
40 feet
Step-by-step explanation:
Graph the line described.
through (-3,-9); m = 4
Answers
Jasmine spent 2 2 over 3 hours at the park. Kyle spent 1 1 over 3 hours at the same park. How much longer, in hours, did Jasmine spend at the park than Kyle?
Answers
9−z9, minus, z when z = 8z=8z, equals, 8.
Answers
What is the area of the shaded region?
Answers
Answer:
65
Step-by-step explanation:
( (23 * 13) / 2 ) - ( (13 * 13) / 2 ) = ( 299 / 2 ) - ( 169 / 2 ) = 149.5 - 84.5 = 65
Numbers are slightly unclear but I think this is right.
Area of the shaded region:
= 22 x 13 x 1/2
= 286 x 1/2
= 143
The sum of two numbers is less than 4. If we subtract the second number from
the first, the difference is greater than 1.
What is the inequality that would represent: The sum of two numbers is
less than 4?*
1 point
Your answer?
Answers
Answer:
x+y<4
Step-by-step explanation:
let the numbers be x and y
x+y<4
x-y>1
What is the volume of a cone with a radius of 6 inches and a height of 15 inches? (Use 3.14 for π.)
188.4 in. 3
565.2 in. 3
726.8 in. 3
1,695.6 in. 3
Thx
Answers
Answer:
1,695.6 in. 3
Step-by-step explanation:
A chef divided 24.7 grams of salt into two equal piles. How much salt is in each pile? Enter your answer in the box. g
Answers
Answer: 12.35
Step-by-step explanation: Since we know that there is a total of 24.7 grams in both piles, we can find how much salt is in one by dividing 24.7 by 2.
The amount of salt in each pile will be the half amount of 24.7 grams thus 12.35 grams will be in each pile.
What is the arithmetic operator?Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,
Division = divide any two numbers or variables called division.
For example 4/8
As per the given,
Amount of salt available = 24.7 grams.
It needed to divide into two piles.
In one piles = 24.7/2 = 12.35 grams
Hence "The amount of salt in each pile will be the half amount of 24.7 grams thus 12.35 grams will be in each pile".
To learn more about the arithmetic operators,
brainly.com/question/25834626
#SPJ2
What is one thing that you found interesting about future value and present value for compound interest? 100 words ^
Answers
Answer:
Compound interest is that which, once generated, is added to the capital, in order to expand the calculation base on which, in turn, new interests will be generated. Thus, in short, if the interest is, for example, 5 percent, said interest will be added to the initial capital, with which that 5% generated will be increasing, since it will be calculated on an increasingly large basis.
Compound interest is very important for financial investments, as it maximizes the results of said investments, even more so when compared to simple interest, in which the interest generated is not added to the initial capital.
Rewrite the expression with a perfect square: x^2 - 14x + 11
Answers
Factoring x2-14x+11
The first term is, x2 its coefficient is 1 .
The middle term is, -14x its coefficient is -14 .
The last term, "the constant", is +11
Step-1 : Multiply the coefficient of the first term by the constant 1 • 11 = 11
Step-2 : Find two factors of 11 whose sum equals the coefficient of the middle term, which is -14 .
-11 + -1 = -12 -1 + -11 = -12 1 + 11 = 12 11 + 1 = 12
Observation : No two such factors can be found
please help me i really need help please please
Answers
Answer:
it's D all of the above
Step-by-step explanation:
.......