Answer:
ans=10
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
10(4-7) / -(4 - 1)
10(-3) / -(3)
-30 / -3 =
10
Which ordered pair is a solution to the equation below? 3x + 2y = 10
Question 1 options:
(4, 0)
(6, -4)
(-1, 4)
Answer:
(6,-4)
Step-by-step explanation:
I have tried replacing each option with x, y in the equation.
Let's replace (6, -4) with x and y
3x+2y=10
3(6)+2(-4)=10
3(6)= 18 2(-4)= -8
18+(-8)=10
in other words:
18-8=10
The statement is true, so the correct answer is:
(6, -4)
y= -2x+8
what is the value of y when 0 is the value of x?
Not sure what you mean but will be explaining about y = 0 and x =0 anyway.
So for x = 0, that means the value of x is 0.
y = -2(0)+8
y=0+8
y=8
So when x = 0, the value of y is 8 (y = 8) or we can write (0,8)
For y = 0, that means the value of y is 0.
0=-2x+8
-8=-2x
-2x=-8
x=4
So when y = 0, x = 4. We can write as (4,0)
What is the equation of the line that passes through the point (5,2) and has a slope
of -3/5
Answer:y = -0.6x + 5
Step-by-step explanation:
Answer:
yessir the one on top is right btw
Step-by-step explanation:
hope this helped
How do you do these two questions?
Answer:
(x − π)⁷ / 5040
(x − 1)³ / 16
Step-by-step explanation:
Taylor series expansion of a function is:
f(x) = ∑ₙ₌₀°° f⁽ⁿ⁾(x₀) / n! (x − x₀)ⁿ
where f⁽ⁿ⁾(x₀) is the nth derivative evaluated at x₀.
For the first problem, f(x) = sin x and x₀ = π. We want the seventh degree term, so n = 7.
The seventh degree term is therefore: f⁽⁷⁾(π) / 7! (x − π)⁷
Find the seventh derivative of sin x:
f(x) = sin x
f⁽¹⁾(x) = cos x
f⁽²⁾(x) = -sin x
f⁽³⁾(x) = -cos x
f⁽⁴⁾(x) = sin x
f⁽⁵⁾(x) = cos x
f⁽⁶⁾(x) = -sin x
f⁽⁷⁾(x) = -cos x
Evaluated at π, f⁽⁷⁾(x) = 1. So the seventh degree term is (x − π)⁷ / 5040.
For the second problem, f(x) = √x and x₀ = 1. We want the third degree term, so n = 3.
The third degree term is therefore: f⁽³⁾(1) / 3! (x − 1)³
Find the third derivative of √x:
f(x) = √x
f⁽¹⁾(x) = ½ x^-½
f⁽²⁾(x) = -¼ x^-³/₂
f⁽³⁾(x) = ⅜ x^-⁵/₂
Evaluated at 1, f⁽³⁾(x) = ⅜. So the third degree term is (x − 1)³ / 16.
A total of 710 tickets were sold for the school play . They were either adult tickets or student tickets. There were 60 more student tickets sold than adult tickets. How many adult tickets were sold ?
Answer: 325
Explanation:
Let the number of adult tickets be x
( since there are an unknown amount of tickets for adults, we already know how many student tickets there are)
Let the number of student tickets be x+60
710=x+x+60
710=2x+60
-60 -60
650=2x
650/2
= 325
Adult tickets=325
Student tickets=385