Will GIVE BRAINLIEST
A ganza is a percussion instrument used in samba music.
a. Find the surface area of each of the two labeled ganzas in terms of π , rounded to the nearest thousandths and as a decimal, round to the nearest whole number.
Surface area of smaller ganza =
π≈
cm2
Surface area of larger ganza =
π≈
cm2
b. The weight of the smaller ganza is 1.1 pounds. Assume that the surface area is proportional to the weight. What is the weight of the larger ganza to the nearest tenth of a pound?
The weight of the larger ganza is about
pounds.
Answers
Answer:
1036.2 sq. cm
Step-by-step explanation:
The surface area of the smaller ganza = 2πr2 + 2πrh
surface area = 2 x 3.14 x 3.5 x 3.5 + 2 x 3.14 x 3.5x 10
surface area = 76.93+ 219.8
surface area = 296.73 sq. cm
The surface area of the larger ganza = 2πr2 + 2πrh
surface area = 2 x 3.14 x 5.5 x 5.5 + 2 x 3.14 x 5.5x 24.5
surface area = 189.97+846.23
surface area = 1036.2 sq. cm
a. The surface area of the smaller ganza is [tex]296.73cm^{2}[/tex]
The surface area of the larger ganza is [tex]1036.2cm^{2}[/tex]
b. The weight of the larger ganza is [tex]3.84[/tex] pounds.
Surface area :From given figure,
Radius of smaller ganza ,[tex]r_{1}=3.5/21.75cm[/tex]
height of smaller ganza, [tex]h_{1}=10cm[/tex]
a. The surface area of the smaller ganza is,
[tex]S_{1}= 2 \pi r^{2} + 2\pi rh[/tex]
[tex]S_{1}=2 * 3.14 * 3.5 * 3.5 + 2 * 3.14 * 3.5* 10\\\\S_{1}=76.93+ 219.8\\\\S_{1}=296.73cm^{2}[/tex]
The surface area of the larger ganza
[tex]S_{2}= 2\pi r^{2} + 2\pi rh[/tex]
[tex]S_{2}= 2 * 3.14 * 5.5 * 5.5 + 2 * 3.14 * 5.5* 24.5\\\\S_{2}= 189.97+846.23\\\\S_{2} = 1036.2 cm^{2}[/tex]
b. Since, the surface area is proportional to the weight.
and The weight of the smaller ganza is 1.1 pounds.
[tex]\frac{1.1}{w}=\frac{296.73}{1036.2}\\ \\ w=\frac{1036.2*1.1}{296.73}\\ \\w=3.84[/tex]
Learn more about the surface area here:
https://brainly.com/question/16997207
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