Answer:
Hope this helps =)
Explanation:
The current in a short circuit may be very high because the resistance in the short circuit is probably less than the resistance in the original circuit.
The amount of change between the crest or trough of a wave and the normal
What is the typical pH of acid rain?
Answer:
5.0-5.5 is the answer to your question
A block is given an initial velocity of 3.00 m/s up a frictionless incline of angle 20 degrees. How far up the incline does the block slide
Answer:
The distance moved by the block is 1.34 m
Explanation:
Given;
initial velocity of the block, u = 3 m/s
angle of inclination, θ = 20⁰
The net horizontal force acting on the block;
∑Fx = - mgsinθ
Apply Newton's second law of motion, to determine the constant acceleration of the block.
∑Fx = ma
- mgsinθ = ma
-gsinθ = a
Apply the following Kinematic equation, to determine how far up, the block moved before coming to rest.
[tex]V_f^2 = V_i^2 + 2a(x_f -x_i)\\\\0 = V_i^2 + 2[-gsin \theta(x_f-0)]\\\\0 = V_i^2 - 2gsin \theta(x_f)\\\\ 2gsin \theta(x_f) = V_i^2\\\\x_f = \frac{V_i^2}{2gsin \theta} = \frac{(3)^2}{2 \ \times \ 9.8 \ \times \ sin(20)} = 1.34 \ m[/tex]
Therefore, the distance moved by the block is 1.34 m
True or false in order for light to be emitted electrons must move from high energy state to a lower energy state?
1 point
A.True
B.False
Answer:
B
I think it is false.
It does not move to lower energy state.
His eyes are 1.83 m above the floor, and the top of his head is 0.15 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet.
Answer:
y_lower = 0.915 m, y_superior = 1,905 m
Explanation:
In this exercise we use the law of reflection for a flat mirror.
θ’= θ
To see the feet of the person a ray of light that part of them must reach the bottom of the mirror and its reflection has to reach the eyes.
As the law of reflection the incident and reflected angles are equal, the distance from the floor to the point where the two rays (incident and reflected) touch the mirror must be symmetrical, oses from the floor
y = 1.83 / 2
y = 0.915 m
To see the head, a ray of light that comes from the tip of the head and is reflected in the mirror must reach the eyes. As the head is 0.15 m above the eyes and the incident and reflected rays have the same angle, the mirror must be at half the height, that is, the mirror is 0.075 m below the tip of the head.
In summary
* the bottom of the mirror is 0.915 m from the ground
* the top of the mirror is at 1.83 + 0.075
y_superior = 1,905 m
ground
What is the resistance of a rheostat coil, if 0.05 A of current flows through it when 6 V is applied
across it? 1200
Answer:
i have no idea i came here to find out too :(
Explanation:
A wooden block meauring 40cm x 10cm x 5cm has a mass 850gm . find the density of wood?
please answer me.
Answer:
Explanation:
Density = Mass / Volume = 850 / 40*10*5 = 0.425 g /cm^3
Consider a loop of wire with a resistor. In the same plane, (with switch S closed) a long wire has a current I flowing from left to right. R I S If switch S is closed for a long period of time, and then suddenly opened, what is the direction of the induced current through R as the current I rapidly decreases
Solution :
The given figure is a loop of a wire with a resistor.
When the switch S is closed for long time and is suddenly opened, the direction of the induced current can be find out by using the rule of right hand screw. According to the right hand screw rule, the direction of the magnetic field at the loop is in the direction that points outwards. The strength of the current rapidly decreases as it is switch off and the magnetic flux that is linked with the loop wire will also decrease.
According to the Lenz's law, the direction of the induced current must be such [tex]$\text{that it opposes}$[/tex] the decrease in the magnetic flux. It means the direction of the magnetic field must be outwards and also normal to the plane of the screen. The direction of the induced anti clockwise or from right to left in the resistance.
What is Ship Handling, an art or a science? Why?
Ship handling is both a science and an art. Science because it requires knowledge of various forces acting on the ship. Art because it requires the skills of an experienced navigator to use these forces in his favour. We may learn the science part from the various ship handling courses.
please give brainliest
A 1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. The period for small-angle oscillations is 0.940 s. (a) What is the moment of inertia of the wrench about an axis through the pivot
Answer:
[tex]I=0.0987kg.m^2[/tex]
Explanation:
From the question we are told that:
Mass [tex]M=1.80kg[/tex]
Deviation [tex]d=0.250[/tex]
Time [tex]t=0.940s[/tex]
Generally the equation for moment of inertia is mathematically given by
[tex]I=\frac{T}{2\pi}^2(mgd)[/tex]
[tex]I=\frac{0.94}{2.3.142}^2(1.80*9.8*0.250)[/tex]
[tex]I=0.0987kgm^2[/tex]
How do tsunamis cause flooding? Please answer in 4-5 sentences.
PLEASE HELP! GIVING BRAINLIEST!
Answer: YES
Explanation: The main difference between flood and tsunami is that the flood is overflow of water that submerges land and tsunami is a series of water waves caused by the displacement by large volume of a volume of water
Answer:
WEEEEEEEEEEEEEEEEEEEEEEEEE
Explanation:
Which type of energy is demonstrated by a person jogging?
A. electrical energy
B. nuclear energy
C. electromagnetic energy
D. kinetic energy
A uniform electric field exists everywhere in the x,y plane. The electric field has a magnitude of 3500 N/coil, and is directed in the positive x direction. A point charge of -9.0 x 10-9 coil is placed at the origin. Determine the magnitude of the net electric field at: (a) x
Answer:
5525 N/C
Explanation:
Magnitude of electric field ( E ) = 3500 N/c
Direction of electric field : positive X axis
point charge ( q ) = -9.0 * 10^-9
Calculate the Magnitude of the net electric field at (a) x = -0.20 m
Magnitude = 5525 N/C
Electric field due to q = ( 9 * 10^9 * 9 * 10^-9 ) / ( -0.2 )^2
= 81 / 0.04 = 2025 N/c
Therefore the magnitude of the net electric field
= 2025 + 3500
= 5525 N/C
two spheres of radii 5cm and 3cm are given charges on risk volume and 50 calling respectively and then connected by a wire calculate the loss of energy after connection
Answer:
Solution given:
Radius of small sphere[r]=5cm=0.05m
Radius of large sphere[R]=10cm=0.1m
capacitance of small sphere[c]=4πε0r
=[tex]4π*8.85×10^{-12}×0.05=5.56*10^{-12}F[/tex]
Charge for small sphere[Q1]=100C
Charge for small sphere[Q2]=50C
Potential difference [V1]=[tex] \frac{charge}{capacitance}=\frac{100}{5.56*10^{-12}}=1.8×10^{13}[/tex]V
.
again
capacitance of small sphere[C]=4πε0R
=[tex]4π*8.85×10^{-12}×0.1=1.11*10^{-11}F[/tex]
Potential difference [V2]=[tex] \frac{charge}{capacitance}=\frac{50}{1.11*10^{-11}}=4.5×10^{12}[/tex]V
Now
Loss of energy:
[tex] \frac{cC(V1-V2)^{2}}{2(c+C)}[/tex]
=[tex] \frac{5.56*10^{-12}*1.11*10^{-11}(1.8*10^{13}-4.5*10^{12})^{2}}{2(5.56*10^{-12}+1.11*10^{-11})}[/tex]
=25Joule
What is an electron?
(it’s D lol)
Answer:
D
Explanation:
An object with a mass of 2.00 kg is placed at the end of a spring, having a spring constant of 180.0 N/m. The spring is then compressed 0.890 m. What is the maximum velocity of the mass?
Answer:
the velocity of the mass is 8.44 m/s
Explanation:
Given;
mass of the object, m = 2 kg
spring constant, k = 180 N/m
extension of the spring, x = 0.89 m
The maximum velocity of the mass is calculated as follows;
By the principle of conservation of energy;
Elastic potential energy = kinetic potential energy
¹/₂kx² = ¹/₂mv²
kx² = mv²
[tex]v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{180 \times 0.89^2}{2} }\\\\v = 8.44 \ m/s[/tex]
Therefore, the velocity of the mass is 8.44 m/s
I will mark u brainlist
Answer:
DragonFly or a dog
Explanation:
A wave has a speed of 450 m/s and a frequency of 5 Hz. What is its wavelength?
Give you answer to a 1 decimal place.
Your Answer:
Answer
the wavelength is 90
Explanation:
from
Which energy transformation is correct?
O From A to C, kinetic energy is transformed into
gravitational potential energy.
O From C to D, kinetic energy is transformed into
gravitational potential energy.
O From C to E, gravitational potential energy is
transformed into kinetic energy.
O From D to E, gravitational potential energy is
transformed into kinetic energy.
B. The energy transformation that is correct is From C to D, kinetic energy is transformed into gravitational potential energy.
What is law of conservation of energy?The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.
Energy transformation in the pendulum;
At point A, there's only gravitational potential energy and no kinetic energy, because the pendulum is at rest at A. At point C, it has maximum speed since all of the potential energy is transformed into kinetic energy. Therefore, at this point there is only kinetic energy and no potential energy.At point E, it is the same as at point A, but in opposite side. So, at this point there is no kinetic energy.At points B and D there are both kinetic and potential energy. At point B the kinetic energy is increasing and at point D it is decreasing.Thus, the energy transformation that is correct is From C to D, kinetic energy is transformed into gravitational potential energy.
option B is the correct answer.
Learn more about energy transformation here: https://brainly.com/question/2667612
#SPJ1
Answer:
B is Correct
Explanation:
From C to D, kinetic energy is transformed into gravitational potential energy.
You have just landed your first job as a structural engineer and you have been asked to design a regional airport for small planes. Your manager informs you that the planes that will use this runaway must reach a speed before takeoff of at least 28.1 m/s, and can accelerate at 2 m/s2. What is the minimum length your runaway must have to facilitate a safe take off
Answer: [tex]197.40\ m[/tex]
Explanation:
Given
final velocity at takeoff [tex]v=28.1\ m/s[/tex]
Acceleration of the plane can be [tex]a=2\ m/s^2[/tex]
Initial velocity is zero for the plane i.e. [tex]u=0[/tex]
Using the equation of motion
[tex]\Rightarrow v^2-u^2=2as\quad [\text{s=displacement}]\\\text{Insert the values}\\\Rightarrow (28.1)^2-0=2\times 2\times s\\\\\Rightarrow s=\dfrac{789.61}{4}\\\\\Rightarrow s=197.40\ m[/tex]
Thu,s the minimum length must be [tex]197.40\ m[/tex]
In a given cartesian coordinate system a particle is in the position (initial vector position) ( 9.2 , 3.1 ) meters. After 10 seconds, the particle is in the position (final vector position) ( 72.2, 77.2 ) meters. What is the magnitude of the average velocity of the particle during the given time interval, in m/s
Answer:
Thus, the average velocity is 9.73 m/s.
Explanation:
The velocity is given by the rate of change of position.
initial position, A = (9.2, 3.1) m
final position, B = (72.2, 77.2) m
time, t = 10 s
The velocity is given by
[tex]\overrightarrow{v} =\frac{\overrightarrow{B}-\overrightarrow{A}}{t}\\\overrightarrow{v}=\frac{(72.2-9.2)\widehat{i} - (77.2-3.1)\widehat{j}}{10}\\\overrightarrow{v}=\frac{63 \widehat{i} - 74.1\widehat{j}}{10}\overrightarrow{v} =6.3 \widehat{i} - 7.41 \widehat{j}\\v =\sqrt{6.3^{2}+7.41^{2}}v = 9.73 m/s[/tex]
The table shows the relationship between the masses of two objects, the distance between the two objects, and the gravitational force between the objects. A 4-column table with 5 rows. The first column labeled Mass of Object 1 (kilograms) has entries 1, 2, 2, 3, 9. The second column labeled Mass of Object 2 (kilograms) has entries 1, 1, 2, 3, 3. The third column labeled Distance between Objects 1 and 2 (meters) has entries 1, 1, 2, 1, 3. The fourth column labeled Gravitational Force Objects 1 and 2 (Newtons) has entries 1 G, 2 G, 1 G, 9 G, 3G. Which conclusion is supported by the data in the table? An increase in the mass of an object causes the same decrease in the gravitational force. An increase in the distance between the objects causes the same decrease in the gravitational force. An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass. An increase in the mass causes a greater change in the gravitational force than the same increase in the distance between the objects. Brainlyest for correct answer!
Answer:
C
Explanation:
edge 2020... Using elimination it's the only one that makes sense.
The statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.
What is gravitational force?The gravitational force is a force that attracts all mass-bearing objects. The gravitational force is referred to as attractive because it always strives to pull masses together rather than pushing them apart.
As we know, the gravitational force is given by:
[tex]\rm F = \dfrac{Gm_1m_2}{r^2}[/tex]
Where, G is the gravitational constant.
m1 and m2 are masses.
r is the distance between the masses.
From the data given in the table, shows that:
The gravitational force is indirectly proportional to the square of the distance.
Thus, the statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.
Learn more about the gravitational force here:
https://brainly.com/question/12528243
#SPJ2
Explain what happens during stages A and B.
Please help!!! Explain the type of graph that could be used for the data below.
It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's chest with 6.4 g bullets at the rate of 92 bullets/min, and the speed of each bullet is 400 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman's chest from the stream of bullets
Answer:
Magnitude of the average force = 7.85 N
Explanation:
Data given:
Mass of bullets, m = 6.4 g
Rate of bullets/min, r = 92 bullets/min
Speed of each bullet, v = 400 m/s
Change in momentum here, Δ B = Bf - Bi
where f is the final and i is the initial
Note that change in momentum = force X time
So, Δ B = m(vf - vi)
= 2mv
= 2 X 0.0064 kg X 400 m/s (convert g to kg)
= 5.12 kg.m/s (for one bullet)
so for the 92 bullets = 92 X 5.12 kg.m/s
= 471.04 kg.m/s
The force = Δ B ÷ Δt
where t = time measured in 60 seconds
= 471.04 kg.m/s ÷ 60 seconds
= 7.85 N
A physics student mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them, and they appear concentric when viewed from either end). The lenses are identical, each with a positive (converging) focal length of 14.8 cm. They are separated by a distance of 39.4 cm. Lens 1 is to the left of Lens 2.
Required:
a. What is the final image's distance (in cm) from Lens 2?
b. Where is the final image located?
c. What is the overall magnification of the lens pair, considered as a single optical instrument?
Answer:
A) q₂ = 75.98 cm, B) q₂' = 115.38 cm, C)
Explanation:
A) This is an exercise in geometric optics, as the two lenses are separated by a greater distance than their focal lengths from each lens, they must be worked as independent lenses.
Lens 1. More to the left
let's use the constructor equation
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and the image, respectively,
We must assume a distance to the object to perform the calculation, suppose that the object is 50 cm from lens 1 that is further to the left of the system.
[tex]\frac{1}{q_1} = \frac{1}{f} - \frac{1}{p}[/tex]
[tex]\frac{1}{q_1} = \frac{1}{14.8} - \frac{1}{50}[/tex]
1 / q₁ = 0.04756
q₁ = 21.0227 cm
this image is the object for the second lens that has f₂ = 14.8 cm
the distance must be measured from the second lens
p₂ = 39.4 -q₁
p₂ = 39.4 -21.0227
p₂ = 18.38 cm
let's use the constructor equation
1 / q₂ = 1 / f - 1 / p2
[tex]\frac{1}{q_2} = \frac{1}{14.8} - \frac{1}{18.38}[/tex]
[tex]\frac{1}{q_2}[/tex] = 0.01316
q₂ = 75.98 cm
measured from the second lens
B) the position of the final image with respect to the first lens is
q₂’= q₂ + 39.4
q₂'= 75.98 +39.4
q₂' = 115.38 cm
C) the magnification of a lens is
m = - q / p
in this case the image measured from lens 2 is q2 = 75.98 cm
the distance to the object from the first lens is p1 = 50cm
m = - 75.98 / 50
m = -1.5 X
the negative sign indicates that the image is inverted
An engine flywheel initially rotates counterclockwise at 5.03 rotations/s. Then, during 23.5 s, its rotation rate changes to 2.63 rotations/s clockwise. Find the flywheel's average angular acceleration (including its sign) in radians per second squared. Define counterclockwise rotation as positive.
Answer:
the flywheel's average angular acceleration is -2.05 rad/s²
Explanation:
Note: counterclockwise is positive
clockwise is negative
Given;
initial angular velocity, [tex]\omega _i[/tex] = 5.03 rev/s = [tex]5.03\frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 31.61 \ rad/s[/tex]
final angular velocity, [tex]\omega_f[/tex]= -2.63 rev/s = [tex]-2.63 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = -16.53 \ rad/s[/tex]
duration of the flywheel rotation, Δt = 23.5 s
The average acceleration of the flywheel is calculated as;
[tex]a_r = \frac{\Delta \omega}{\Delta t} = \frac{\omega_f - \omega _i}{t_2-t_1} = \frac{-16.53 \ - \ 31.61}{23.5} = -2.05 \ rad/s^2[/tex]
Therefore, the flywheel's average angular acceleration is -2.05 rad/s²
Our Most Plentiful Resources
Which two renewable technologies do not
rely on energy from the Sun?
wind and hydroelectric
What happens to the force between two magnets as the magnets come closer together? *
Explanation:
So if two magnets are pointing with unlike-poles together (north pole to a south pole), then bringing them closer together decreases the energy stored up in the magnetic field. They will be pushed in the direction that decreases the amount of stored-up energy.
Explanation:
depending on the polarity they'll increasingly repel or attract
Si un vector tiene una dirección de 2300 a partir del eje x positivo, ¿Qué signos tendrán sus componentes x y y? Si la la razón de R/R, es negativa. ¿cuáles son los ángulos posibles de R, medidos a partir del eje x positivo?