**Answer:**

The goal of physics is to understand how things work from first principles. ... Courses in physics reveal the mathematical beauty of the universe at scales ranging from subatomic to cosmological. Studying physics strengthens quantitative reasoning and problem solving skills that are valuable in areas beyond physics.

One good reason to study physics is being able to use the information you learned and being able to apply it in the real world. Such jobs that includes Physics are Ballistic Analysis in the Forensic Science field and virtually every type of engineering job there is. As you can see physics is everywhere and everybody should try to learn some even if it’s just a small amount, It goes a long way.

Hope this helped :)

Hope this helped :)

If vector A = 6i - 2j + 3k, determine

(a) A vector in the same direction as A with magnitude 2A

(b) A unit vector in the direction of A

(c) a vector opposite to A with magnitude of 4 m

**Answer:**

(a) [tex]2\vec A=12\hat i-4\hat j+6\hat k[/tex]

(b) [tex]\displaystyle \vec{U_A}=12/7\hat i-4/7\hat j+6/7\hat k[/tex]

(c) [tex]-4\vec{U_A}=-48/7\hat i+16/7\hat j-24/7\hat k[/tex]

**Explanation:**

Vectors

Given a vector

[tex]\vec A=6\hat i-2\hat j+3\hat k[/tex]

We must determine the following:

a) A vector in the same direction as A with double magnitude 2A.

If the vector goes in the same direction but has a different magnitude, we only need to multiply each component by a common factor, in this case, by 2. Thus, the required vector is:

[tex]2\vec A=12\hat i-4\hat j+6\hat k[/tex]

b) A unit vector in the same direction of A.

The unit vector needs to compute the magnitude of the vector:

[tex]\mid A\mid=\sqrt{6^2+2^2+3^2}[/tex]

[tex]\mid A\mid=\sqrt{36+4+9}=\sqrt{49}=7[/tex]

[tex]\mid A\mid=7[/tex]

The unit vector is:

[tex]\displaystyle \vec{U_A}=\frac{\vec A}{\mid \vec A\mid}[/tex]

[tex]\displaystyle \vec{U_A}=\frac{12\hat i-4\hat j+6\hat k}{7}[/tex]

[tex]\displaystyle \vec{U_A}=12/7\hat i-4/7\hat j+6/7\hat k[/tex]

c) A vector opposite to A with magnitude 4 m. We assume the original vector is also expressed in m.

The opposite vector to A is obtained simply by multiplying the unit vector by -1. To make its magnitude equal to 4, also multiply by 4. In all, we multiply the unit vector by -4:

[tex]-4\vec{U_A}=-4(12/7\hat i-4/7\hat j+6/7\hat k)[/tex]

[tex]-4\vec{U_A}=-48/7\hat i+16/7\hat j-24/7\hat k[/tex]

A solid nonconducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a certain distance rl (r
(A) E/8

(B) E 78.

(C) E/2

(D) 2E

(E) 8E

**Answer:**

**A ) E/8**

**Explanation:**

**If the sphere of radius R carries charge Q, then the volumetric charge density is:**

**ρ₁ = [Q/ (4/3)*π*R³]**

**Therefore the net charge inside r ( r < R ) is:**

**q₁ = ρ * (4/3)*π*r³**

**And E = K * q₁/r K = 9,98 *10⁹ [N*m²/C²]**

**E = K * ρ * (4/3)*π*r³/r**

**E = K * ρ * (4/3)*π*r²**

**If now the charge is distributed over a sphere of radius 2R**

**ρ₂ = [Q/ (4/3)*π*(2R)³]**

**ρ₂ = [Q/ (4/3)*π*8*R³]**

**Then ρ₂ < ρ₁ in fact ρ₂ = (1/8)*ρ₁**

**The electric field depends on the net charge enclosed by a gaussian surface, and the distance between the net charge and the considered point, ( considering the net charge as being at the center of the gaussian surface) In this case, there was no distance change then**

**E₂ = E₁/8**

**The right answer is lyrics A ) E/8**

An object is dropped from rest and falls freely 20 m to Earth. When is the speed of the object 9.8 m/s?

At the end of the first second of its fall

At the end of the first second of its fall

During the entire time of its fall

During the entire time of its fall

At no time is the speed 9.8 m/s

At no time is the speed 9.8 m/s

During the entire first second of its fall

During the entire first second of its fall

After it has fallen 9.8 meters

During the entire time of its fall because as soon as it falls that’s what the speed it will be until acted on by a outside force

Two identical items, object 1 and object 2, are dropped from the top of a 50.0m50.0m building. Object 1 is dropped with an initial velocity of 0m/s0m/s, while object 2 is thrown straight downward with an initial velocity of 13.0m/s13.0m/s. What is the difference in time, in seconds rounded to the nearest tenth, between when the two objects hit the ground

**Answer:**

**Δt = 1.1 s**

**Explanation:**

**Given information: **

H= 50.0 m

g= 9.8 m/s²

Object 1v₀ = 0[tex]H = \frac{1}{2} * g* t^{2}[/tex]

Solving for t, we get:

**t₁= 3.2 s**

We can find the final velocity for the object when it hits the ground, using the following expression:

[tex]v_{f}^{2} - v_{o}^{2} = 2*g*H[/tex]

Solving for vf, we get:

vf = 33.9 m/s

Applying the definition of acceleration, being this acceleration the one due to gravity (g), we can write the following equation:

[tex]v_{f} = v_{o} + g*t[/tex]

(Assuming the downward direction to be positive).

Solving for t, we get:

**t₂ = 2.1 s**

So the difference in time when both objects hit the ground, it's simply

**Δt = t₂ - t₁ = 3.2 s - 2.1 s = 1.1 s**

how much power is used if it takes frank (a 450 N boy ) 3 seconds to run 2 meters ?

**Answer:**

300

**Explanation:**

450Newton × 2Meter ÷ 3sec

The acceleration of the spacecraft in which the Apollo astronauts took off from the moon was 3.4 m/s2 m / s 2 . On the moon, g g = 1.6 m/s2 m / s 2 . what's the apparent weight

Complete Question

The acceleration of the spacecraft in which the Apollo astronauts took off from the moon was 3.4 m/s2. On the moon, g = 1.6 m/s2. What was the apparent weight of a 75 kg astronaut during takeoff?

Answer:

The value is [tex]N = 375 \ N[/tex]

Explanation:

From the question we are told that

The acceleration is [tex]a = 3.4 \ m/s^2[/tex]

The acceleration due to gravity in the moon is [tex]g = 1.6 m/s^2[/tex]

The mass of the astronaut is [tex]m = 75 \ kg[/tex]

Generally the apparent weight is mathematically represented as

[tex]W = ma + mg[/tex]

=> [tex]W = 3.4 * 75 + 1.6 * 75[/tex]

=> [tex]W = 375 \ N[/tex]

how are s waves and p waves simuliar?

A.they shake the ground

B.they travel through liquids

C. they arrive at the same time

D.they shake the ground from side to side

**Answer:**

A

**Explanation:**

hope this helps

The answer is A thank me later

The equation that governs the period of a pendulum’s swinging. T=2π√L/g

Where T is the period, L is the length of the pendulum and g is a constant, equal to 9.8 m/s2. The symbol g is a measure of the strength of Earth’s gravity, and has a different value on other planets and moons.

On our Moon, the strength of earth’s gravity is only 1/6th of the normal value. If a pendulum on Earth has a period of 4.9 seconds, what is the period of that same pendulum on the moon?

**Answer:**

The period of that same pendulum on the moon is **12.0** seconds.

**Explanation:**

To determine the period of that same pendulum on the moon,

First, we will determine the value of g (which is a measure of the strength of Earth's gravity) on the Moon. Let the value of g on the Moon be [tex]g_{M}[/tex].

From the question, the strength of earth’s gravity is only 1/6th of the normal value. The normal value of g is 9.8 m/s²

∴ [tex]g_{M}[/tex] = [tex]\frac{1}{6} \times 9.8 m/s^{2}[/tex]

[tex]g_{M}[/tex] = 1.63 m/s²

From the question, T=2π√L/g

[tex]T = 2\pi \sqrt{\frac{L}{g} }[/tex]

We can write that,

[tex]T_{E} = 2\pi \sqrt{\frac{L}{g_{E} } }[/tex] .......... (1)

Where [tex]T_{E}[/tex] is the period of the pendulum on Earth and [tex]g_{E}[/tex] is the measure of the strength of Earth's gravity

and

[tex]T_{M} = 2\pi \sqrt{\frac{L}{g_{M} } }[/tex] .......... (2)

Where [tex]T_{M}[/tex] is the period of the pendulum on Moon and [tex]g_{M}[/tex] is the measure of the strength of Earth's gravity on the Moon.

Since we are to determine the period of the same pendulum on the moon, then, [tex]2\pi[/tex] and [tex]L[/tex] are constants.

Dividing equation (1) by (2), we get

[tex]\frac{T_{E} }{T_{M} } = \sqrt{\frac{g_{M} }{g_{E} } }[/tex]

From the question,

[tex]T_{E} = 4.9secs[/tex]

[tex]g_{E}[/tex] = 9.8 m/s²

[tex]g_{M}[/tex] = 1.63 m/s²

[tex]T_{M}[/tex] = ??

From,

[tex]\frac{T_{E} }{T_{M} } = \sqrt{\frac{g_{M} }{g_{E} } }[/tex]

[tex]\frac{4.9}{T_{M} } = \sqrt{\frac{1.63}{9.8} }[/tex]

[tex]\frac{4.9}{T_{M} } = 0.40783[/tex]

[tex]T_{M} =\frac{4.9}{0.40783 }[/tex]

[tex]T_{M} = 12.01 secs[/tex]

∴ [tex]T_{M} = 12.0secs[/tex]

Hence, the period of that same pendulum on the moon is **12.0** seconds.

**Answer:**

The period of that same pendulum on the moon is **12.0 s**

**Explanation:**

Given;

period of a pendulum’s swinging, T=2π√L/g

the strength of earth’s gravity on moon, g₂ = ¹/₆(g₁)

period of pendulum on Earth, T₁ = 4.9 s

period of pendulum on moon, T₂ = ?

The length of the pendulum is constant, make it the subject of the formula;

[tex]T = 2\pi \sqrt{\frac{L}{g} }\\\\\frac{T}{2\pi} = \sqrt{\frac{L}{g}}\\\\(\frac{T}{2\pi} )^2 =\frac{L}{g}\\\\\frac{T^2}{4\pi^2} = \frac{L}{g}\\\\ L = \frac{gT^2}{4\pi^2}\\\\L_1 = L_2\\\\\frac{g_1T_1^2}{4\pi^2}= \frac{g_2T_2^2}{4\pi^2}\\\\g_1T_1^2 = g_2T_2^2\\\\T_2^2 = \frac{g_1T_1^2}{g_2} \\\\T_2 = \sqrt{\frac{g_1T_1^2}{g_2}}\\\\ T_2 = \sqrt{\frac{g_1T_1^2}{g_1/6}}\\\\ T_2 = \sqrt{\frac{6*g_1T_1^2}{g_1}}\\\\T_2 = \sqrt{6T_1^2}\\\\ T_2 = T_1\sqrt{6} \\\\T_2 = (4.9)\sqrt{6}\\\\ T_2 = 12.0 \ s[/tex]

Therefore, the period of that same pendulum on the moon is **12.0 s**

On what part of the eye are rods and cones found?

They are located in the retina.

**Answer:**

retina.

**Explanation:**

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from zero to 7.63 m/s in 3.94 s. What is the magnitude of the linear impulse experienced by a 73.7 kg passenger in the car during this time? Submit Answer Tries 0/20 What is the average force experienced by the passenger?

**Answer:**

**1. p = 562.3 kg*m/s**

**2. F = 142.7 N**

**Explanation:**

1. The linear impulse (p) is given by:

[tex] p = mv [/tex]

Where:

m: is the passenger's mass = 73.7 kg

v: is the speed = 7.63 m/s

[tex] p = mv = 73.7 kg*7.63 m/s = 562.3 kg*m/s [/tex]

**Hence, the magnitude of the linear impulse experienced by a passenger is 562.3 kg*m/s.**

2. The average force can be calculated using the following equation:

[tex] F = \frac{m(v_{f} - v_{0})}{t} = \frac{73.7 kg(7.63 m/s - 0)}{3.94 s} = 142.7 N [/tex]

**Therefore, the average force experienced by the passenger is 142.7 N.**

I hope it helps you!

Please help

A student plans an investigation to determine the refractive index of glass. The student uses this equipments.

- a ray box

- a rectangular glass block

- a protractor

- a pencil

Describe how the student collect her data.

A ray box is the answer I give

What is the speaker’s power output if the sound intensity level is 102 dBdB at a distance of 25 mm ? Express your answer to two significant figures and include the appropriate units.

**Answer:**

**Power = 124.50 W**

**Explanation:**

Given that:

The Sound intensity of a speaker output is 102 dB

and the distance r = 25 m

For the intensity of sound,

[tex]\beta (dB)= 10 \ log_{10 } (\dfrac{I}{I_o})[/tex]

where;

the threshold of hearing [tex]I_o = 10^{-12} (W/m^2)[/tex]

[tex]\dfrac{102 }{10}= log_{10}( \dfrac{I}{10^{-12}})[/tex]

[tex]10^{10.2} = \dfrac{I}{10^{-12}}[/tex]

[tex]I = 10^{10.2} \times 10^{-12}[/tex]

I = 0.01585 W/m²

If we recall, we know remember that ;

Power = Intensity × A rea

Power = 0.01585 W/m² × 4 × 3.142 × (25 m)²

**Power = 124.50 W**

A ray is incident at at 50 degrees angle on a plane mirror. What will be the deviation after reflection from the mirror?

**Answer:**

**Explanation:**

If the ray were not deviated, it would travel straight through the mirror. Due to the mirror, the incident ray is reflected at 30°. The ray travels 30° + 30° = 60°. The angle of deviation is 180° - 60° = 120°.

(iii) Why do right angle mirrors produce three images of the object?

**Explanation:**

**The two mirrors inclined to each other formed the first two images with are of the same size as the object while the third mirror is produced from the intersection of rays that emanated during the production of the first two images to produce a third image which is smaller than the object and there making the total number of images to be 3.**

**Hence this mirrors produces 3 images due to the third image formed from the intersection of the rays that produces the first two images.**

The formula that relates the image produced by inclined mirror and the angle of inclination is expressed as:

number of images n = 360/θ - 1

θ is the angle of inclination of the two mirrors

n is the number of images

If the mirrors are inclined at right angles, then θ = 90°

Substitute into the formula;

n = 360/90 -1

n = 36/9 -1

n = 4-1

n = 3

A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis

ball moving 30 m/s to the left. After the collision, the tennis ball is moving 34

m/s to the right. What is the velocity of the basketball after the collision?

Assume an elastic collision occurred.

O A. 11.4 m/s to the left

O B. 11.4 m/s to the right

O C. 1.4 m/s to the right

O D. 1.4 m/s to the left

Answer:

1.4 m/s to the left

Explanation:

just took it c:

A pile of bricks of mass M is being raised to the tenth floor of a building of height H = 4y above the ground by a crane that is on top of the building. During the first part of the lift, the crane lifts the bricks a vertical distance h1=3y in a time t1=4T. During the second part of the lift, the crane lifts the bricks a vertical distance h2=y in t2=T. Which of the following correctly relates the power P1 generated by the crane during the first part of the lift to the power P2 generated by the crane during the second part of the lift?

A. P2=4P1

B. P2=43P1

C. P2=P1

D. P2=34P1

E. P2=13P1

Answer:

The correct option is B

Explanation:

From the question we are told that

The mass of the pile is M

The height is H = 4 y

The vertical distance achieve during the first lift is [tex]h_1 = 3 y[/tex]

The time taken is [tex]t_1 = 4T [/tex]

The vertical distance achieve during the second lift is [tex]h_2 = y[/tex]

The time taken is [tex] t_2 = T [/tex]

Generally the velocity of the crane during the first lift is

[tex]v _1 = \frac{h_1}{t_1 }[/tex]

=> [tex]v _1 = \frac{3 y}{4T }[/tex]

Generally the velocity of the crane during the second lift is

[tex]v _2 = \frac{h_2}{t_2 }[/tex]

=> [tex]v _2 = \frac{ y}{T}[/tex]

Generally the power generated by the crane during the first lift is

[tex]P_1 = F_1 * v_1[/tex]

Here [tex]F_1[/tex] is the weight of the brick which is mathematically represented as

[tex]F_1 = M * g [/tex] , g is the acceleration due to gravity

So

[tex]P_1 = Mg * \frac{3y}{4T}[/tex]

Generally the power generated by the crane during the first lift is

[tex]P_1 = F_2 * v_2[/tex]

Here [tex]F_2[/tex] is the weight of the brick which is mathematically represented as

[tex]F_2 = M * g [/tex] , g is the acceleration due to gravity

So

[tex]P_1 = Mg * \frac{y}{T}[/tex]

The ratio of the first power generated to the second power is

[tex]\frac{P_1}{P_2} = \frac{Mg * \frac{3y}{4T} }{ Mg * \frac{y}{T} }[/tex]

=> [tex]\frac{P_1}{P_2} = \frac{3}{4}[/tex]

=> [tex]P_2 = \frac{4}{3} P_1[/tex]

A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much work was done?

**Answer:**

**Explanation:**

The work done by an object can be found by using the formula

workdone = force × distanceFrom the question

distance = 3 meters

force = 15 newtons

We have

workdone = 15 × 3

We have the final answer as

45 JHope this helps you

100 POINTS.

Please provide explanation.

Thank you

Answer:

(a) 0.829 m/s

(b) 3.27 m/s

(c) 0.000153 m²

55.8%

Explanation:

(a) Flow rate equals velocity times cross-sectional area. (1 L = 0.001 m³)

Q = vA

(0.001 m³ / 2.00 s) = v (48 × π (0.002 m)²)

v = 0.829 m/s

(b) Use Bernoulli equation. Choose point 1 to be the exit of the pump, and point 2 to be exit of the shower head. Choose 0 elevation to be at point 1.

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

(1.50 atm × 1.0×10⁵ Pa/atm) + ½ (1000 kg/m³) v² + 0 = (1 atm × 1.0×10⁵ Pa/atm) + ½ (1000 kg/m³) (0.829 m/s)² + (1000 kg/m³) (10 m/s²) (5.50 m)

1.50×10⁵ Pa + (500 kg/m³) v² = 1×10⁵ Pa + 414.5 Pa + 55000 Pa

v = 3.27 m/s

(c) Flow rate is constant.

Q = vA

(0.001 m³ / 2.00 s) = (3.27 m/s) A

A = 0.000153 m²

Flow rate is proportional to the pressure difference and the radius raised to the fourth power.

Q ∝ ΔP r⁴

Q₂/Q₁ = (ΔP₂/ΔP₁) (r₂/r₁)⁴

Q₂/Q₁ = (1.120) (0.840)⁴

Q₂/Q₁ = 0.558

The flow decreases to 55.8% of the original value.

**Answer:**

**Explanation:**

Regarding the point of "Flow rate is proportional to the pressure difference and the radius raised to the fourth power", flow rate depends on pressure, cross-section area and speed. As speed also depends on cross-section area, flow rate becomes dependent on pressure and cross-section area squared.

In a round pipe like blood vessel, the cross-section area is equal to pi*radius squared. So flow rate is proportional to the pressure difference and (radius squared) squared; i.e. the radius raised to the fourth power.

The new flow rate = (1.12)*(0.84)^4

=0.5576 or 55.76% of the original flow rate

A charged isolated metal sphere of diameter 12 cm has a potential of 9200 V relative to V = 0 at infinity. Calculate the energy density in the electric field near the surface of the sphere.

Answer:

0.1 J/m³

Explanation:

We know that

V = k Q / R

We also know that

E = k Q / R²

Joining the two equations together, we have

E = V / R

To solve the question proper, we'd be using the formula

u = 1/2 E• E², substitute for E, we have

u = 1/2 E• (V/R)²

u = 1/2 * 8.85*10^-12 * (9000 / 0.06)²

u = 1/2 * 8.85*10^-12 * 150000²

u = 1/2 * 8.85*10^-12 * 2.25*10^10

u = 1/2 * 0.199125

u = 0.0996

u = 0.1 J/m³

The energy density is 0.1 J/m³

What measurements would you make (assuming you have the money, time, & equipment) to determine a star’s surface temperature? Explain your answer.

**Answer:**

**use special filters on the telescope**

**Explanation:**

Assuming you have access to a very high-grade telescope you would need to **use special filters on the telescope** that allows you to view the star's color spectrum. The color spectrum represents different levels of heat that a star is generating. This spectrum ranges from red to blue. Therefore in order to calculate the surface temperature, you would need to apply both a blue and red filter onto the telescope. Once you have these measurements you would need to compare them in order to pinpoint the correct variation of color which would give a close enough estimate of the surface temperature of the star.

An object, initially at rest, is subject to an acceleration of 45 m/s^2. How long will it take that object to travel 1000m? Round to one decimal place.

**Answer:**

6.7 seconds

**Explanation:**

d=(1/2)at^2

equation

1000=(1/2)45t^2.

substitute

2000=45t^2.

multiply by 2 for both sides

44.44=t^2.

divide both sides by 45

6.7=t

take the square root of both sides

Bird A, with a mass of 2.2 kg, is stationary while Bird B, with a mass of 1.7 kg, is moving due north from Bird A at 3 m/s. What is the velocity of the center of mass for this system of two birds

**Answer:**

1.3 m/s

**Explanation:**

It is given that,

Mass of bird A, [tex]m_A=2.2\ kg[/tex]

Mass of bird B, [tex]m_B=1.7\ kg[/tex]

Initial speed of bird A is 0 as it was at rest

Initial speed of bird B is 3 m/s

**We need to find the velocity of the center of mass for this system of two birds. Let it is V. so,**

[tex]v_{cm}=\dfrac{m_Au_A+m_Bu_B}{m_A+m_B}\\\\v_{cm}=\dfrac{2.2\times 0+1.7\times 3}{2.2+1.7}\\\\v_{cm}=1.3\ m/s[/tex]

**So, the center of mass for this system is 1.3 m/s.**

Which best explains a difference between Einstein’s general theory of relativity and his special theory of relativity?

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

His general theory includes uniform and accelerated motion, but his special theory applies only to accelerated motion.

His general theory applies only to accelerated motion, but his special theory includes uniform and accelerated motion.

His general theory applies only to uniform motion, but his special theory includes uniform and accelerated motion.

**Answer:**

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

**Explanation:**

According to Einstein's 1915 general theory of relativity, the force of gravity arises from the curvature of space and time.

According to theory of special relativity:

1. The laws of physics are the same for all non-accelerating observers

2. The speed of light in a vacuum was independent of the motion of all observers.

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

**Answer:**

for those who dont like to read

the answer is A.

hope i helped

**Explanation:**

A car moving with an intial velocity of 60m/s is brought to rest in 30 seconds calculate the acceleration

**Answer:**

a = 2 [m/s^2]

**Explanation:**

To solve this problem we must use the expressions of kinematics, we must bear in mind that when a body is at rest its velocity is zero.

[tex]v_{f} = v_{i} - (a*t)[/tex]

where:

Vf = final velocity = 0

Vi = initial velocity = 60 [m/s]

a = desacceleration [m/s^2]

t = time = 30 [s]

**Note: the negative sign of the above equation means that the car is slowing down, i.e. its speed decreases.**

0 = 60 - (a*30)

a = 2 [m/s^2]

I WILL MARK YOU AS BRAINLIEST IF RIGHT

What is the magnitude of the net force acting on this object?

**Answer:**

The net force on an object is the total force applied on the object after adding up all the forces

In the given diagram,

we can see that the 2 forces of 4N and 4N will cancel each other out since they are equal and in the opposite direction

Now, we are left with a force of 2N and 10N,

the net force will be the difference of these forces:

Net force = 10N - 2N

Net force = **8N downwards**

**Another way to do it:**

The two 4N forces will be cancelled out,

and we are left with a 2N and a 10N force

*(notice how we cancelled equal and opposite forces for the 4N)*

We can divide the 10N force into (2N + 8N)

Since the 2N forces are equal and opposite, they will be cancelled out

and we will be left with a net force of **8N downwards**

Converting compound units

You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogram/meter3 and the density of silicon in other units: 2.33 gram/centimeter3. You decide to convert the density of silicon into units of kilogram/meter3 to perform the comparison. By which combination of conversion factors will you multiply 2.33 gram/centimeter3 to perform the unit conversion?

**Answer:**

Dividing the silicon density by 1000 and then multiply it by 1000000.

**Explanation:**

A kilogram equals 1000 grams and a cubic meter equals 1000000 cubic centimeters. Hence, we must divide the silicon density by 1000 and then multiply itby 1000000 to convert the value into kilograms per cubic centimeter. That is:

[tex]x = 2.33\,\frac{g}{cm^{3}}\times \frac{1\,kg}{1000\,g}\times \frac{1000000\,cm^{3}}{1\,m^{3}}[/tex]

[tex]x = 2330\,\frac{kg}{m^{3}}[/tex]

In a nutshell, we must multiply the density of silicon by 1000 to obtains its value in kilograms per cubic meter.

There are 5.5 L of a gas present at -38.0 C. What is the temperature if the volume of the gas has changed to 1.30 L?

**Answer:**

**We are given:**

V1 = 5.5L T1 = -38 C or 235 k

V2 = 1.3L T2 = T

**From the gas equation:**

**PV = nRT**

Since the pressure (P) , number of moles (n) and the universal gas constant (R) are constants, we can write the same equation as:

**V / T = k (where k is a constant)**

*so a bit more insight, since the values noted above are constant, when multiplied by each other, they will provide us with a constant number irrespective of the value of the variables*

Changing the variables for the first case:

**V1 / T1 = k** (where k is the same constant) ----------------(1)

Similarly,

**V2 / T2 = k ** (again, k has the same value)----------------(2)

From (1) and (2):

k is the common value

**V1 / T1 = V2 / T2**

Replacing the variables

*5.5 / 235 = 1.3 / T*

*T = 1.3 * 235 / 5.5*

**T = 55.54 k**

Therefore, at 55.54 K the gas will have a volume of 1.3L

What cause objects to move? In three to five sentences .

**Answer:**

Gravity can affect the motion of objects as the force pulls objects closer to earth. Kinetic energy also causes movement in objects as that is energy in motion coming from stored energy known as (potential energy). With almost most importantly is needed is a force as without a force acting upon an objects is moving will continue to move and an object at rest will remain at rest as a gravitational pull or kinetic and potential energy for example are forces.

**Explanation:**

Have a great day :)

What does the principle of superposition help scientists determine?

A) The super powers of a rock layer

B) The exact and absolute age of a rock layer

C) The relative age of a rock layer

D) The position of a fossil

**Answer:**

B

**Explanation:**

the exact and absolute age of a rock layer

**Answer:**

The relative age of a rock layer.

**Explanation:**

The answer is C.

A student creates an electromagnetic wave and then reverses the direction of the current. Which of the following will happen to the magnetic field?

**Answer:**

I believe the electromagnetic field should be reversed.

**Explanation:**

When a student creates an **electromagnetic wave** and then reverses the direction of the current, the direction of the **magnetic field **will be **reversed**.

An **electromagnetic wave** may be defined as a type of wave that is significantly created as a result of **vibrations **between an electric field and a magnetic field. These waves are composed of **oscillating **magnetic and electric fields.

According to the context of this question, when an individual is constructing an electromagnetic wave and then **reverses **the direction of the current, it will eventually **affect **the direction of the magnetic field in the same direction with respect to the current. So, if the **direction **of the current is reversed, the direction of the **magnetic field** would also be reversed.

Therefore, when a student creates an **electromagnetic wave** and then reverses the direction of the current, the direction of the magnetic field will be **reversed**.

To learn more about **Magnetic fields**, refer to the link:

https://brainly.com/question/14411049

#SPJ6

Your question seems incomplete. The most probable complete question is as follows:

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