Answer:
Because they provide information about clouds, oceans, land and ice.
How was our galaxy formed?
Answer:
according to big bang theory our galaxy was formed 13billion years ago and then made the stars and galaxies we see today. ... The universe began as a very hot, small, and dense superforce (the mix of the four fundamental forces), with no stars, atoms, form, or structure (called a "singularity).
100 cm cubic of water is mixed with 50 centimetres cubic of concentrated acid of density 1.2 gram per centimetre cube assuming no change in volume find the average density of the mixture the density of water is 1.0 gram per centimetre cube
Answer:
Average Density = 1.07 g/cm³
Explanation:
The average density of the whole mixture is given by the following formula:
[tex]Average\ Density = \frac{mass\ of\ whole\ mixture}{volume\ of\ whole\ mixture}[/tex]
where,
volume of whole mixture = volume of water + volume of acid
volume of whole mixture = 100 cm³ + 50 cm³ = 150cm³
mass of whole mixture = mass of water + mass of acid
mass of whole mixture = (volume of water)(density of water) + (volume of acid)(density of acid)
mass of whole mixture = (100 cm³)(1 g/cm³) + (50 cm³)(1.2 g/cm³)
mass of whole mixture = 160 g
Therefore,
[tex]Average\ Density = \frac{160\ g}{150\ cm^3}[/tex]
Average Density = 1.07 g/cm³
under which conditions do both convex and concave mirrors form virtual images state whether or not each can form a real image if the mirror can form a real image describe how this occurs
Answer:
Explanation:Concave mirrors can make a real image.when the object is away from the mirror it is called real image and when the object is closer to the mirror it is called virtual mirror.
how does electricity work?
Answer:Electricity works by getting a bunch of conductor elements together and creating a flow of electron-stealing patterns through them. This flow is called a current. ... Once you can control the direction the electrons are going, you can use them to power or charge anything from a light bulb to your TV to your electric car.
Explanation:trust
What is the answer for this question?
Answer:
6 watts
Explanation:
hours against watts
I'm not sure though
Suppose you needed to push a 1,500-N sofa up a frictionless ramp with a 30° angle. How much force would you have to apply to the sofa?Show your work below.
Answer:
1299N
Explanation:
GIven data
Weight W= 1500N
Angle Ф= 30°
The applied force up the frictionless ramp is gotten by applying the formula below
F= WcosФ
substitute
F=1500 cos 30
F = 1500*0.8660
F= 1299N
Hence the applied force is 1299N
The magnetic field of a bar magnet Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a Always points from north to south, whether we look outside the magnet or inside the magnet. b Always points from south to north, whether we look outside the magnet or inside the magnet. c Points from north to south outside the magnet, but south to north inside the magnet. d Points from south to north outside the magnet, but north to south inside the magnet.
Answer:
A: Always points from north to south, whether we look outside the magnet or inside the magnet
Explanation:
When we freely suspend a bar magnet, it's magnetic field will always rest in the north to south direction due to the fact that the Earth's magnetic south pole usually lies in the direction of the geographic north while the Earth's magnetic north pole usually lies in the direction of the geographic south.
Now, we all know that in magnets, like poles will repel and unlike poles will attract. What this now means is that the magnet will always point from the north to the south direction.
In the example of a hammer hitting a nail, which is hit harder? the nail, the hammer, or they both hit equally?
Answer:
both hit qaulity
Explanation:
Newton's Third Law says that every interaction involves two forces - in this case (1) hammer pushes nail, and (2) nail pushes hammer. When a hammer hits a nail, Newton's Third Law says that the force that the hammer exerts on the nail is exactly the same size as the force the nail exerts on the hammer.
5. What is the frequency of a sound wave when the speed of the sound is 340 m/s and has a wavelength of 1.21 m? 263 Hz 281 Hz O 328 Hz O 346 Hz
Answer:
281 Hz
Explanation:
I am so so sorry if this is wrong. But good luck and have a good day
Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked?
Correct question:
Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked?
a. from the bottom of a hill to the top
b. on a circular nature trail
c. on a sidewalk from his house to the mall
d. from the beginning of a straight track to the end
Answer:
b. on a circular nature trail
Explanation:
As it is mentioned that Manny that his reference point from where she started is same as ending point meaning that she moved in a circular path making point B correct answer.
Answer:
on a circular nature trail
Explanation:
An effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.19 m apart are powered by the same function generator producing sine waves at 1,163 Hz frequency. Assume that the speed of sound is 340 m/s. A student walks along a line 12.5 m away and parallel to the line from one speaker to the other speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is the distance between the central maximum and the first maximum (loud) position along this line in m
Answer:
3.04 m
Explanation:
The interference by diffraction of waves is noticeable only when the dimension of the opening through which the wave is passing through is comparable to the wavelength of the passing wave.
It is given that :
Distance between two speakers, d = 1.19 m
Speed of sound, v = 340 m/s
The frequency is f = 1163 Hz
Distance the student walk along the line of the speaker, D = 12.5 m
We know the wavelength of the sound produced by the speakers is given by :
[tex]$\lambda=\frac{v}{f}$[/tex]
[tex]$=\frac{340}{1163}$[/tex]
= 0.29 m
Now the distance between the central maximum and the first maximum position is given by :
[tex]$y=\frac{\lambda D}{d}$[/tex]
[tex]$=\frac{0.29 \times 12.5}{1.19}$[/tex]
= 3.04 m