Answer:
Because integers don't have decimals. An irrational number has a forever repeating decimal (that is random).
Step-by-step explanation:
Find the 20 th term of the given sequence 2, 5, 8, 11,..
Answer:
14,17, 20
Step-by-step explanation:
Kindly see the picture I have solved it as required
Please answer and show your work
Answer:
check online for more information
Use the table below to answer the following question,
2:
хо 1 2 3 4 5 6
y 100 200 400 800 1,600 3,200 6,400
Which equation BEST fits the data given in the table?
se 3:
Of(x) = { (200)*
Of(x) = 100(2)*
uge 4
f(x) = 200)
age 5
Of(x) = 200(2)*
5
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Answer Of(x) = 200(2)
Step-by-step explanation:
Of(x) = 200(2)
Josh volunteers at a library. One weekend, he put 234 returned books back on the shelves. Of those books 2/3 were hardcover books and the rest were paperback books. How many paperback books did Josh put back on the shelves?
Answer: 78 paperback books.
Step-by-step explanation:
1. Since 2/3 of the books are hardcover books, then 1/3 of the books are paperback books.
2. 234/3 = 78 books.
Answer:
78 paperback books
Step-by-step explanation:
234 x (2/3) = 156
234 - 156 = 78
Dylan had 300 5p coins in a box last month. He now has 360 5p coins. Find the percentage increase.
Therefore the percentage increase is 72
72Rachel invests $25,000 at age 25. She hopes the investment will be worth $125,000 when she turns 50. If the interest compounds continuously, approximately what rate of growth will she need to achieve her goal? Round to the nearest tenth of a percent.
The rate of growth will she need to achieve her goal is 2.8%
The formula for finding the compound amount is expressed as:
[tex]A =P(1+\frac{r}{n} )^{nt}[/tex]
P is the amount invested = $25000
t is the time in years = 25 years
A is the amount = $125000
r is the rate in %
Substitute the given parameters into the formula to have:
[tex]125000 =25000(1+r )^{25}\\5 =(1+r)^{25}\\log5=25log(1+r)\\log(1+r)=\frac{log5}{25} \\log(1+r)=0.02796\\1+r = e^{0.02795}\\1+r=1.0283\\r = 1.0283 -1\\r = 0.0283\\[/tex]
Hence the rate of growth will she need to achieve her goal is 2.8%
Learn more about compound amount here: https://brainly.com/question/18442810
Find a 33 matrix Sij so that the product SijA is the same as the matrix A after applying the row operation Ri $ Rj .
Answer:
We want the ith row of the new matrix SijA to be the old jth row of A, so we need the ith row of Sij to extract the jth entry of column of A.
This mean the ith row of Sij must have a 1 in the jth entry and 0's everywhere else.
Similarly, the jth row of Sij must have a 1 in the ith entry and 0's everywhere else.
in the piecewise notation this is
(Sij)kl ={1 if k=i and l=j, 1 if k=k and l=i; 1 if k=l but k#i,j, 0 otherwise
Step-by-step explanation:
Skip count by 100 starting with 95.
95, ____, ____, ____, ____
Answer:
195, 295, 395, 495?
Step-by-step explanation:
Due Tomorrow: Answer question 21 with steps
[tex]\\ \sf\longmapsto tan28=\dfrac{BC}{AC}[/tex]
[tex]\\ \sf\longmapsto 0.5317=\dfrac{BC}{29.3}[/tex]
[tex]\\ \sf\longmapsto BC=29.3(0.5317)[/tex]
[tex]\\ \sf\longmapsto BC=15.5mi[/tex]
Now
[tex]\\ \sf\longmapsto AB^2=29.3^2+15.5^2[/tex]
[tex]\\ \sf\longmapsto AB^2=848.49+240.25[/tex]
[tex]\\ \sf\longmapsto AB^2=1088.74[/tex]
[tex]\\ \sf\longmapsto AB=32.9mi[/tex]
evaluate the expression 5+3
some one answer me with a question not a link
Answer:
8
Step-by-step explanation:
Add 5 and 3
-Lexi
if someone helps me with dis ill def give em brainliest
Answer:
with what?
Step-by-step explanation:
I think you forgot to attach something.
Show all work to identify the asymptotes and zero of the function f of x equals 3 x over quantity x squared minus 9.
Answer:
Asymptotes: x = -3, x = 3, y = 0Step-by-step explanation:
Given function:
f(x) = 3x / (x² - 9)Zero of the function:
f(x) = 03x / (x² - 9) = 0x = 0, x ≠ -3; 3Vertical asymptotes:
x² - 9 = 0x² = 9x = √9x = -3; x = 3Horizontal asymptotes:
The horizontal asymptote is y = 0, since the degree of the numerator is 1, while the degree of the denominator is 2.The graph with asymptotes and zero is attached
7+q+4=4+7+q
What property?
Answer:
Commutative Property of Addition
Step-by-step explanation:
This is because the commutative property of addition and multiplication is
[tex]a+b=b+a\\a*b=b*a[/tex]
and as an example
[tex]5+9=14 \\9+5=14\\10*6=60\\6*10=60[/tex]
which is the correct answer??
geometry
Answer:
SAS || Side - Angle - Side
Step-by-step explanation:
You have 2 sets of congruent sides, and one set of congruent angles between them. (SAS)
That angle is congruent because ∠QRP and ∠TRS are vertical angles, and vertical angles have the same measurement.
Given the function h (x) = –22 - 4, the value of h(-5) would be?
Answer:
At the value of x = 3 the function H(x) is undefined. (answer is 3)
Step-by-step explanation:
h (x) = 1/(x-5)2 + 4 (x-5) +4
Solution :
We know that for the values of x where denominator is zero the function H(x) is not define.
(x -5)2 +4 (x -5 ) +4 = 0
x2 -6x +9 =0
x2 - 3x - 3x +9 = 0
(x - 3)2 = 0
So x= 3
At x = 3 the function H(x) is undefined. (3 is your answer)
Can someone please help me I will mark u brilliant
Answer:
the whole number 5 goes to the left of the decimal
Step-by-step explanation:
so think about it this way...
I have 10 dots .......... that is 1.0 but if I only have 5 of the 10 I have 0.5. if you have anymore questions just ask and ill help
Javier worked 45 hours last week. His hourly rate for hours worked is $ 8.75 . After his 40 hour work week, he is paid time and a half for overtime. What is Javier’s gross pay for last week?
The gross pay that Javier gets for last week is $415.625.
What is rate?Rate is a measurement to determine the change in one quantity with respect to another quantity.
Given that,
Rate for 1 hour = $8.75,
Since, Javier worked 45 hours last week,
So total amount got by Javier = 45×8.75=393.75
According to condition,
Last 5 days Javier is paid half more amount for overtime,
Therefore,
Javier amount of overtime gets by Javier in last 5 days
=8.75×5/2
=21.875
Total amount = 393.75+21.875=415.625
So the gross pay for last week is $415.625.
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Can you help please?
Answer:
Step-by-step explanation:
Sara earns $12.75 per hour at her job. She works 18 hours each week. While at work, she parks her car in a garage that charges $10.50 every 3 hours.
After paying for parking, how much does Sara earn each week?
A.$198.00
B.$229.50
C.$166.50
D.$261.00
9514 1404 393
Answer:
C. $166.50
Step-by-step explanation:
The rate Sara pays for parking is ...
$10.50/(3 hours) = $3.50 /hour
So, Sara's net pay, after paying for parking, is ...
$12.75/hour - 3.50/hour = $9.25 /hour
If she works 18 hours per week, her net earnings are ...
(18 h)($9.25/h) = $166.50 . . . . weekly earnings
Simplify.
81‾‾‾√
18
9
−3
−18
9514 1404 393
Answer:
(b) 9
Step-by-step explanation:
Maybe you want to simplify ...
[tex]\sqrt{81}=\sqrt{9^2} =\boxed{9}[/tex]
I NEED HELP !!!! PLZ HELP ME UNDERSTAND THIS
Answer:
Step-by-step explanation:
pls help me right now!
and pls show your solution properly
I'm not good in math ok bye
A) Atra = 0.5 ( 7 + 3 ) x 3 = 15 cm^2
B) Atri1 = 1/2 x 3 x 2 = 3 cm^2
Atri2 = 1/2 x 3 x 2 = 3 cm^2
Arec = 3 x 3 = 9 cm^2
Atra = Atri1 + Atri2 + Arec = 3 + 3 + 9 = 15 cm^2
ok done. Thank to me :>
A shoe store uses a 40% markup for all of the shoes it sells. What would be the selling price of a pair of shoes that has a wholesale cost of $71?
Answer:
40% * 71 = Markup price
40% of 71 is 28.4, so i added the two together and got 99.4
so...
$28.4 + $71 = $99.40
Hello everybody! Can anybody help me out with this fairly simple multiple choice algebra problem? Thanks!
Answer:
l = P -2w
________ D is the correct choice
2
A high school teacher teaches three classes per day. Her first class has double the number of students as her
second class, while her third class has 13 more students than her second class. In total, she teaches 57
students. The equation 2x + x + (x +13) = 57 represents this scenario, where x is the number of students
in her second class.
How many students are in her second class?
Number
students are in her second class.
Answer:
11
Step-by-step explanation:
2x + x + x + 13 = 57
4x + 13 = 57
4x = 57-13
4x = 44
44/4 = 11
x = 11
Find complex numbers z=(x,y) such that
[tex]z ^{2} = - 5 - 12i[/tex]
Answer:
I don't know..,.............,,.,.......,
an alloy is 70% iron. How much of this alloy do you need if you want to obtain 50.35 lb of iron?
Answer:
1007/20
Step-by-step explanation:
You helped me so i help you. Here you go my friends sorry i dont have an explanation. Good luck !
Use proportions. X is what you want.
70 50.35lb
__ = _____
100 x
Cross multiply to get 70x = 5035
Solve to get about 71.93 lbs of the alloy.
10% of $70 = what is the answer i do not now it.
Answer:
10% 0f 70 is 7
Step-by-step explanation:
70÷10=7
10%=7
what if 5476 divided by 74? i need the working out too please!
I hope that the attachment helps you..
Write the equation of a sine or cosine function to describe the graph.
Answer:
Step-by-step explanation:
Average = (Ymax + Ymin)/2 = (4 + (- 2))/ 2 = 1
Amplitude = (Ymax - Ymin)/2 = (4 - (- 2))/ 2 = 3
y is at a maximum when x = 0, so cosine function is easy.
one cycle (2π radians) is completed in 2π/3
therefore
y = 1 + 3cos(2π(x /(2π/3))
y = 1 + 3cos(3x)
Answer(s):
[tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1 \\ y = 3cos\:3x + 1[/tex]
Step-by-step explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{6}} \hookrightarrow \frac{-\frac{\pi}{2}}{3} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\:3x + 1,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{6}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{6}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{6}} = \frac{-\frac{\pi}{2}}{3}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-\frac{2}{9}\pi, -\frac{1}{2}],[/tex]from there to [tex]\displaystyle [\frac{4}{9}\pi, -\frac{1}{2}],[/tex]they are obviously [tex]\displaystyle \frac{2}{3}\pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{2}{3}\pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.