Why are experimental investigations the best type of scientific investigation o demonstrat cause-and-effect relationships?

Answers

Answer 1

Answer:

Isolation of Variables.

Explanation:

I am just taking a guess but Experimental investigations allow you to isolate variables (making most variables constant, allowing only the independent variable to have an impact on the dependent variable). With other scientific investigations, if they don't isolate the variables it is very possible that an unknown third variable could be skewing the results (which will result in correlation but not causation).

Answer 2

Answer:

Experimental investigations are the best type of scientific investigation to demonstrate cause-and-effect relationships because they allow the investigator to actively manipulate variables and control conditions. The independent variable can be isolated and manipulated, producing a change (or no change) in the dependent variable. This change can be measured to gather evidence to support or refute the cause-and-effect relationship. Experimental investigations also use a control group (a group that does not receive the factor being tested) for comparison.

Explanation:

Automated-response....it's right


Related Questions

A dolphin swims due east for 1.90 km, then swims 7.20 km in the direction south of west. What are the magnitude and direction of the vector that will take the dolphin back to its starting point? (Enter the magnitude in km and the direction in degrees north of east.)

Answers

Answer:

magnitude = 7.446 km, direction = 75.22° north of east

Explanation:

From the questions,

To get the the magnitude of the resultant vector we use Pythagoras theorem

a² = b²+c²

From the diagram,

y² = 1.9²+7.2²

y² = 55.45

y = √(55.45)

y = 7.446 km.

The direction of the dolphin is given as,

θ = tan⁻¹(7.2/1.9)

θ = tan⁻¹(3.7895)

θ = 75.22° north of east

Hence the magnitude of the resultant vector = 7.446 km, and it direction is 75.22° north of east

Which of the following describe a condition or location for the right environment for tropical cyclone formation over the north eastern tropical Pacific Ocean?
A. light surface winds
B. a La Nina event
C. stable air
D. a deep layer of humid air
E. converging surface winds
F. ocean surface temperature greater than 80 °F

Answers

Answer:

E. converging surface winds

Explanation:

For the formation of tropical cyclones to occur in the northeast of the tropical Pacific Ocean, it is necessary to have converging surface winds that present a strong convection. This allows for the formation of vertical movements of an ascending nature that have great strength and are intense and violent. This also allows closed cyclonic circulation to occur at the lower levels which together with a low frontal pressure system over the waters of the Pacific Ocean can form the tropical cyclone.

Question No 1 Find the voltage drop across 24 ohm resistor and current flowing through 22 ohm resistor in the given circuit as shown in figure.

Answers

Answer:

8.25 V

Explanation:

We can ignore the 22Ω and 122Ω resistors at the bottom.  Since there's a short across those bottom nodes, any current will go through the short, and none through those two resistors.

The 2Ω resistor and the 44Ω resistor are in parallel.  The equivalent resistance is:

1 / (1 / (2Ω) + 1 / (44Ω)) = 1.913Ω

This resistance is in series with the 12Ω resistor.  The equivalent resistance is:

1.913Ω + 12Ω = 13.913Ω

This resistance is in parallel with the 24Ω resistor.  The equivalent resistance is:

1 / (1 / (13.913Ω) + 1 / (24Ω)) = 8.807Ω

Finally, this resistance is in series with the 4Ω resistor.  The equivalent resistance of the circuit is:

8.807Ω + 4Ω = 12.807Ω

The current through the battery is:

12 V / 12.807Ω = 0.937 A

The voltage drop across the 4Ω resistor is:

(0.937 A) (4Ω) = 3.75 V

So the voltage between the bottom nodes and the top nodes is:

12 V − 3.75 V = 8.25 V

(a) Calculate the kinetic energy, in joules of a 1200 -kg automobile moving at 18 m/s .
(b) Convert this energy to calories.
(c) When the automobile brakes to a stop is the "lost" kinetic energy converted mostly to heat or to some form of potential energy?

Answers

Answer:

a) The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 194400 joules, b) The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 46440.516 calories, c) the kinetic energy is transformed into work due to friction, which is a non-conservative force. And such work is dissipated in the form of heat.

Explanation:

a) Let be the automobile considered as particle travelling on horizontal ground, so that motion is entirely translational and whose formula for kinetic energy, measured in joules, is:

[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex]

Where:

[tex]m[/tex] - Mass, measured in kilograms.

[tex]v[/tex] - Speed of automobile, measured in meters per second.

If [tex]m = 1200\,kg[/tex] and [tex]v = 18\,\frac{m}{s}[/tex], the kinetic energy of the automobile is:

[tex]K = \frac{1}{2}\cdot (1200\,kg)\cdot \left(18\,\frac{m}{s} \right)^{2}[/tex]

[tex]K = 194400\,J[/tex]

The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 194400 joules.

b) A calory equals 4.186 joules. The kinetic energy in calories is:

[tex]K = 194400\,J \times \left(\frac{1}{4.186}\,\frac{cal}{J} \right)[/tex]

[tex]K = 46440.516\,cal[/tex]

The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 46440.516 calories.

c) When the automobile brakes to a stop, the kinetic energy is transformed into work due to friction, which is a non-conservative force. And such work is dissipated in the form of heat. Hence, such energy cannot be recovered. Potential energies are conservative by nature.

Calculate the radius of each ball to the nearest tenth. Use the formula r = d/2 where r is the radius and d is the diameter. Record the average in Table A of your Student Guide. What is the radius of the table tennis ball? cm What is the radius of the golf ball? cm

Answers

Answer:

What is the radius of the table tennis ball?

 ⇒ 2.1 cm  

What is the radius of the golf ball?

2.0  cm

Explanation:

divide the radius and round it to the nearest 10th place..... but hope that help ;)

Answer:

1) What is the radius of the table tennis ball?

2.1 cm

2) What is the radius of the golf ball?

2.0 cm

Explanation:

Did this on Edge 2023 and got it right. Hope this helps :)

If a planet has an angular size of 0.29 degrees, what will be its angular size in arcminutes?

Answers

Answer:

Angular size in arc-minutes = 17.4 arc-minutes

Explanation:

Given:

Angular size = 0.29

Find:

Angular size in arc-minutes

Computation:

1 degree = 60 arc-minutes

So,

0.29 degree = 60 × 0.29 arc-minutes

0.29 degree = 17.4 arc-minutes

Angular size in arc-minutes = 17.4 arc-minutes

Which equation describes the cosine function for a right triangle?
A. cos(O)
opposite
adjacent
B. cos(2)
adjacent
hypotenuse
C. cos(0)
opposite
hypotenuse
D. cos(e)
hypotenuse
adjacent
SUENT

Answers

Answer:

cosine is adjacent over hypotenuse

Explanation:

How I know? It's just a basic formula for triangles, and my teacher taught me this. Sorry if this didn't help.

Answer:

D.cos(e)

hypotenuse adjacent

SUENT

Explanation:

it is helpful to you

A
is a precise way to represent data, but it does not identify trends in the data.
O graph
O table
Ovariable
O diagram

Answers

Answer: table

Explanation:

Answer:Table

Explanation:

A table is a way to represent data , but does not identify trends in the data

Two cars, P and Q, travel in the same direction on a long, straight section of a highway. car P passes car Q, and is adjacent to car Q at time t (subscript 0).
a) Suppose that car P and car Q each move with constant speed. At time t (subscript 0), is the magnitude of the instantaneous velocity of car P greater than, less than, or equal to the magnitude of the instantaneous velocity of car Q? Explain.
b) Suppose instead that car P is moving with constant speed but car Q is speeding up. At time (subscript 0), is the magnitude of the instantaneous velocity of car P greater than, less than, or equal to the magnitude of the instantaneous velocity of car Q? Explain.

Answers

Answer:

the instantaneous velocity of P is greater that Q because P obviously passes Q at that instant in time t

2. P has greater velocity at that instant (to) because P will need to be at a greater velocity to pass Q

The World Snail Racing Championships have been held in the English village of Congham, Norfolk since the 1960s. The contestants are placed at the center of a circular table covered with a damp tablecloth and race outwards 13 inches (33 cm) towards the finish line. A contestant known only as Archie set the current world record of 2 minutes 20 seconds in 1995. Determine Archie's speed in m/s and km/h.

Answers

Speed = distance / time

Speed = (33 cm) / (2min 20sec)

Speed = (0.33 m) / (140 sec)

Speed = 0.0024 m/s

Speed = (0.0024 m/s) x (3600 sec / 1 hr) x (1 km / 1000 m)

Speed = (0.0024 x 3600 / 1000) (m-sec-km / sec-hr-m)

Speed = 0.0085 km/hr

For the time of 2 min and 20 seconds, Archie's speed in m/s will be 0.0024 m/s and Archie's speed in km/hr will be 0.0085 km/hr.

What is Speed?

The "speed at which an object is traveling," or speed, is a scalar quantity. The speed of an object is the rate at which it moves through space. A fast-moving object covers a considerable distance in a short amount of time while traveling at a high speed. An object moving slowly, on the other hand, moves a comparatively modest distance in the same amount of time. An object with zero speed is one that is not moving at all.

According to the question, the given values are :

Distance, d = 33 inches or,

d = 33 cm

Time, t = 2 minutes 20 seconds, or,

t = 140 seconds.

Speed is the ratio of distance to time.

s = 33/140

s = 0.0024 m/s

Now the distance in km/hr will be :

s = 0.0024 m/s × 3600 sec / 1hr × 1 km/ 1000 m

s= 0.0085 km/hr

Hence, the speed in km/hr is 0.0085 km/hr and in m/s speed is 0.0024 m/s.

To get more information about Speed :

https://brainly.com/question/28224010

#SPJ2

A current of 1.70 A flows in a wire. How many electrons are flowing past any point in the wire per second

Answers

Answer:

1.0625×10¹⁹ electrons

Explanation:

From the question,

Using,

Q = It........................ Equation 1

Where Q = charge, I = current flowing in the wire, t = time (seconds)

Given: I = 1.70 A, t = 1 Seconds.

Substitute these values into equation 1

Q = 1.7(1)

Q = 1.7 C.

But,

1.6×10⁻¹⁹ C = 1 electron

Therefore,

1.7 C = 1.7/(1.6×10⁻¹⁹) electrons

= 1.0625×10¹⁹ electrons

Hence, 1.0625×10¹⁹ electrons flows through the wire per seconds.

A drone is launched with a velocity of 63 m/s, 29 . Three minutes after the drone is launched it suddenly changed its course to 22 m/s, 233 to avoid high trees on its way. Then, it finally goes back at a rate of 98 m/s, 321. Calculate for the total resultant vector of the drone.

Answers

Answer:

   v = 127.66 m / s      θ’= 337.59

Explanation:

For this exercise we must use the speed composition of the drone.

The first speed is 63 m / s in direction 29, three minutes later the speed reaches 22 m / s and direction 233, finally it returns to the launch point with 98 m / s in direction 321, in the attachment you can see a diagram of these speeds.

To find the resulting average velocity, the easiest thing is to decompose each velocity into the x and y coordinate system, then add each velocity

let's break down the speeds

             cos 29 = v₁ₓ / v₁

              sin 29 = [tex]v_{1y}[/tex] / v₁

             v₁ₓ = v₁ cos 29

             v_{1y} = v₁ sin 29

             v₁ₓ = 63 cos 29 = 55.10 m / s

             v_{1y} = 63 sin 29 = 30.54 m / s

speed 2

              cos 22 = v₂ₓ / v₂

              sin 22 = v_{2y} / v₂

               v₂ₓ = v₂ cos 233

               v_{2y} = v₂ sin 233

               v₂ₓ = 22 cos 233 = -13.24 m / s

                v_{2y} = 22 sin 233 = -17.57 m / s

speed 3

              cos 321 = v₃ₓ / v₃

              sin 321 = v_{3y} / v₃

               v₃ₓ = v₃ cos 321

               v_{1y} = vₐ sin 321

               v₃ₓ = 98 cos 321 = 76.16 m / s

               v_{3y} = 98 sin 321 = -61.67 m / s

We already have all the component of the speeds, the resulting speed is

               vₓ = v₁ₓ + v₂ₓ + v₃ₓ

               vₓ = 55.10 -13.24 +76.16

               vₓ = 118.02 m / s

               v_{y} = v_{1y} + v_{2y} + v_{3y}

                v_{y} = 30.54 -17.54 - 61.67

                v_{y} = -48.67 m / s

there are two ways to give the result

               v = (118.02 i -48.67 j) m / s

or in the form of magnitud and angle.

We use the Pythagorean theorem for the module

             v = √ (vₓ² + v_{y}²)

             v = RA (118.02² + 48.67²)

             v = 127.66 m / s

let's use trigonometry for the angle

             tan θ = v_{y} / vₓ

             θ = tan⁻¹ (v_{1} / vₓ)

             θ = tan⁻¹ (-48.67 / 118.02)

             θ = -22.41

if we want to measure the angles with respect to the positive side of the x axis

               θ’= 360 - 22.41

               θ’= 337.59

E
Which is the downward pull on an object due to gravity?
volume
mass
weight
matter

Answers

Answer:

Weight

Explanation:

Weight is the downward pull on an object due to gravity.

For example, the moon has less gravity than Earth so we would weigh less on the moon. Our Mass and volume always stay the same but our weight could change.

Answer:

weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight

Explanation:

URGENT!!!!! I WILL MARK U AS BRAINLIEST!!!!!!! A step-down transformer converts 120 V to 5 V in a phone charger. If the primary coil has 600 turns, how many turns are in the secondary coil? SHOW ALL WORK WITH CORRECT ANSWER WITH CORRECT UNIT AS WELL.

Answers

Answer:

  25 turns

Explanation:

The voltage ratio is the turns ratio:

  secondary turns / primary turns = secondary voltage / primary voltage

  secondary turns / 600 = 5/120

  secondary turns = 600(5/120) = 25 . . . turns

The secondary coil has 25 turns.

water is boiling in a pan at 100c if heat is transferred to the pan at a rate of 2 kw how much water in kg will evaporate in 10min

Answers

Answer:

The mass of water that will evaporate 2.857 kg.

Explanation:

Given;

temperature of the water, T = 100 c

rate of heat transfer,  H = 2 kW = 2000 w

time, t = 10 min = 10 min x 60s = 600s

heat capacity of water is given by;

Q = McΔT

Where;

Q is the quantity of heat transfer to the pan = P x t =  2000 x 600 = 1200000 J.

c is specific heat capacity of water = 4200 J/kg.°C

m = (Q) / (cΔT)

m = (1200000) (4200 x 100)

m = 2.857 kg

Therefore, the mass of water that will evaporate 2.857 kg.

Juliette sets the initial velocity to +10 m/s and the acceleration to −2 m/s2, then clicks "start". How can Shakina describe the subsequent motion of the car?

Answers

Answer:

Shakina can sayThe car moves initially to the right with decreasing speed. Eventually, the car stopsand moves to the left with increasing speed.

Explanation:

Because initially the acceleration is negative during which the car is moving to the right and then it slows down and stops, and once it begins moving to the left, it begins to accelerate faster

1. An insect inside a bus flies from the back toward the front at 2 m/s. The bus is moving in a
straight line at 20 m/s. What is the total speed of the insect as seen by a person standing on the
side of the road?

Answers

Answer:

Total speed of the insect as seen by a person standing on the side of the road is 22 m/s

Explanation:

There i a composition of velocities, since the air inside the bus is moving at the same speed as the bus, and the insect flying relative to it.

So for an observer on the side of the road, the insect is flying at a speed of :

20 m/s + 2 m/s = 22 m/s

Velocity head is the mechanical energy of a fluid per unit weight of the fluid measured relative to the bottom of the channel.
a. True
b. False

Answers

Answer:

b. False

Explanation:

The Bernoulli's equation is given by;

[tex]P + \rho gh + \frac{1}{2} \rho v^2 = constat[/tex]

Divide through by the density of the fluid and acceleration due to gravity (ρg), to obtain energy per unit weight of the fluid known as head;

[tex]\frac{P}{\rho g} + h + \frac{v^2}{2g} = constant[/tex]

where;

[tex]\frac{P}{\rho g}[/tex] is pressure head

h is datum head (mechanical energy due to height of the fluid)

[tex]\frac{v^2}{2g}[/tex] is velocity head (mechanical energy due to velocity of the fluid)

Thus, the mechanical energy of a fluid per unit weight of the fluid, measured relative to the bottom of the channel is datum head.

The correct option is "b. False"

Sapphire has an index of refraction of 1.77. The critical angle for sapphire in air with an index of refraction of 1.0 is _____ degrees.

Answers

Answer:

The  value is  [tex]\theta = 34.40^o[/tex]

Explanation:

From the question we are told that

   The  index of refraction is  [tex]n_s = 1.77[/tex]

   The  refractive index of air is  [tex]n_a = 1.0[/tex]

   

Generally the critical angle is mathematically represented as

      [tex]\theta = sin ^{-1} [\frac{1}{n_s} ][/tex]

=>    [tex]\theta = sin ^{-1} [\frac{1}{1.77} ][/tex]

=>    [tex]\theta = sin ^{-1} [0.565 ][/tex]

=>    [tex]\theta = 34.40^o[/tex]

You are trying to overhear a juicy conversation, but from your distance of 24.0m , it sounds like only an average whisper of 40.0dB . So you decide to move closer to give the conversation a sound level of 80.0dB instead. How close should you come?

Answers

Answer:

The distance is [tex]r_2  =  0.24 \  m[/tex]

Explanation:

From the question we are told that

       The  distance from the conversation is [tex] r_1    =  24.0 \ m[/tex]

       The  intensity of  the sound at your position is  [tex]\beta _1 =  40 dB[/tex]

        The  intensity at the sound at the new position is  [tex]\beta_2 =  80.0dB[/tex]

Generally the intensity in  decibel is  is mathematically represented as

      [tex]\beta  =  10dB log_{10}[\frac{d}{d_o} ][/tex]

The intensity is  also mathematically represented as

      [tex]d =  \frac{P}{A}[/tex]

So

    [tex]\beta  =  10dB *  log_{10}[\frac{P}{A* d_o} ][/tex]

=>   [tex]\frac{\beta}{10}  =  log_{10} [\frac{P}{A (l_o)} ][/tex]

From the logarithm definition

=>    [tex]\frac{P}{A  *  d_o}  =  10^{\frac{\beta}{10} }[/tex]

=>      [tex]P =  A (d_o ) [10^{\frac{\beta }{ 10} } ][/tex]

Here P is the power of the sound wave

 and  A is the cross-sectional area of the sound wave  which is generally in spherical form

Now the power of the sound wave at the first position is mathematically represented as

               [tex]P_1 =  A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ][/tex]

Now the power of the sound wave at the second  position is mathematically represented as

               [tex]P_2 =  A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ][/tex]

Generally  power of the wave is constant at both positions  so  

    [tex]A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]  = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ][/tex]

      [tex]4 \pi r_1 ^2   [10^{\frac{\beta_1 }{ 10} } ]  = 4 \pi r_2 ^2   [10^{\frac{\beta_2 }{ 10} } ][/tex]

        [tex]r_2 =  \sqrt{r_1 ^2 [\frac{10^{\frac{\beta_1}{10} }}{ 10^{\frac{\beta_2}{10} }} ]}[/tex]

       substituting value

        [tex]r_2 =   \sqrt{ 24^2 [\frac{10^{\frac{ 40}{10} }}{10^{\frac{80}{10} }} ]}[/tex]

        [tex]r_2  =  0.24 \  m[/tex]

     

A hole is drilled in a metal plate. When the metal is raised to a higher temperature, what happens to the diameter of the hole?

Answers

Answer:

The diameter of the hole increases

Explanation:

Metals expand and contract with temperature. Whenever metal is heated, it usually expands in relation to its thermal expansivity. This expansion leads to a slight increase in surface area.

Once the surface area of the metal changes, this means that the dimensions of the whole metal surface changed. As a result, the diameter of the hole drilled in the metal plate will change also. In our case, the diameter of the hole will increase.

Multiple choice! To be dimensionally consistent, velocity [L/T], force [ML/T^2], mass [M], and length [L] must be related as follows. Multiple Choice A. velocity^2 = force × length/mass B. velocity^2 = force × length/mass^2 C.velocity = force × length^2/mass D. velocity = force × length/mass

Answers

Answer:

velocity^2=force*length/mass

Explanation:

velocity^2=force*length/mass  is dimensionally consistent

as we know that

unit of force=Newton

unit of length=meter

unit of mass=kilogram so

velocity^2=newton*meter/kilogram

newton=kg*m/sec^2 therefore

v^2=kg*m*m/sec^2*kilogram

v^2=kg*m^2/sce^2*kg

v^2=m^2/sec^2

taking square root on both side

√ v²=√m²/sec²

v=m/s  now the dimensions of V is

v=(L/T)

so option A is dimensionally consistent

It should be related like  velocity^2=force*length/mass

Calculation of the relationship:

Since we know that

unit of force=Newton

unit of length=meter

And,

unit of mass=kilogram

Therefore,

velocity^2=newton*meter/kilogram

Now

newton=kg*m/sec^2

So,

v^2=kg*m*m/sec^2*kilogram

v^2=kg*m^2/sce^2*kg

v^2=m^2/sec^2

Now we take square root on both side

So,

√ v²=√m²/sec²

v=m/s  

v=(L/T)

Therefore, option A is correct

Learn more about velocity here: https://brainly.com/question/24759048

Find the average velocity for the time interval beginning when t = 4 with duration 1 seconds, 0.5 seconds, and 0.05 seconds.

Answers

This question is incomplete, the complete question is;

A student dropped a textbook from the top floor of his dorm and it fell according to the formula s(t) = -16t² + 8√t, where t is the time in seconds and s(t) is the distance in feet from the top of the building.

(a) Write a formula for the average velocity of the ball for t near 4.

(b) Find the average velocity for the time interval beginning when t = 4 with duration 1 seconds, 0.5 seconds, and 0.05 seconds

(c) What is your estimate for the instantaneous velocity of the ball at t = 4

Answer:

a)

Average velocity, (Vavg)  of the ball for t near 4.

Vavg = [s(4) - s(0)] / (4 - 0)

Where s(4) = -16 × 4² + 8 × √4= - 240 m

s(0) = -16 × 0 + 8 * 0 = 0

b)

duration = 1 sec

Vavg = [s(5) - s(4)] / (5 - 4)

s(5) = -16 × 52 + 8 × √5 = - 382 m

s(4) = -16 × 42 + 8  √4 = - 240 m

Vavg = (-382 - (-240)) / (5 - 4)

Vavg = - 142.1 m/s

duration = 0.5 sec

Vavg = [s(4.5) - s(4)] / (4.5 - 4)

s(4.5) = -16 × 4.52 + 8 × √4.5 = - 307 m

s(4) = -16 × 42 + 8 × √4 = - 240 m

Vavg = (-307 - (-240)) / (4.5 - 4)

Vavg= - 134.1 m/s

duration = 0.05 sec

Vavg = [s(4.05) - s(4)] / (4.05 - 4)

s(4.05) = -16 × 4.052 + 8 × √4.05 = - 246 m

s(4) = -16 × 42 + 8 × √4 = - 240 m

Vavg = (-246 - (-240)) / (4.05 - 4)

Vavg= - 126.8 m/s

c)

Instantaneous velocity, v = ds/dt

= - 16 × 2 × t + 8 ×× (0.5 / √t )

= - 32 × t + 4/√t

ds/dt at t = 4 is,

v = - 32 × 4 + 4 / √4

= - 126 m/s

An electron in a region where there is an electric field experiences a force of magnitude 3.1 10-16 N. What is the magnitude of the electric field at the location of the electron?

Answers

Answer:

1.938*10^3N/C

Explanation:

Using F= qE

E= F/q

Where q= 1.6x10-19

So 3.1*10^-16/1.6*10^-19

= 1.938*10^3N/C

Explanation:

A 150 lb diver stands at the end of a rigid 8 ft long diving board. What is the magnitude of the torque the diver exerts on the diving board

Answers

Answer:

1200 lb-ft

Explanation:

Weight of diver W = 150 lb

length of board L = 8 ft  

This board is pivoted at one end therefore, the perpendicular distance from the pivot = 8 ft

Torque = weight x perpendicular distance from pivot

T = WL

Torque = 150 x 8 = 1200 lb-ft

A 0.40 kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.5 m on a frictionless horizontal surface. If the cord will break when the tension in it exceeds 63 N, what is the maximum speed the ball can have?

Answers

Answer:

The maximum speed the ball can have is 15.37 m/s

Explanation:

Given;

mass of the ball, m = 0.4 kg

radius of the chord, r = 1.5 m

maximum tension on the chord, T = 63 N

The maximum tension on the chord is given by;

[tex]T_{max} = \frac{mv_{max}^2}{r} \\\\v_{max}^2 = \frac{T_{max} *r}{m}\\\\ v_{max} = \sqrt{\frac{T_{max} *r}{m}} \\\\ v_{max} =\sqrt{\frac{63 *1.5}{0.4}}\\\\v_{max} = 15.37 \ m/s[/tex]

Therefore, the maximum speed the ball can have is 15.37 m/s

Tell uses of cancave mirror and convex mirror.​

Answers

Answer:

Uses of concave mirror:

Shaving mirrors.

Head mirrors.

Ophthalmoscope.

Astronomical telescopes.

Headlights.

Solar furnaces.

Uses of convex mirror:

Convex mirrors always form images that are upright, virtual, and smaller than the actual object. They are commonly used as rear and side view mirrors in cars and as security mirrors in public buildings because they allow you to see a wider view than flat or concave mirrors.

please give me full points.

How does the decrease in gravitational potential energy of a falling ball compare to its increase in kinetic energy? (Ignore air friction.)

Answers

Answer:

for every decrease in potential energy, a kinetic energy proportional to 2gΔh is gained.

Explanation:

Let us consider a ball falling from its maximum height

For a body falling from its maximum height to a point p

change in height = Δh

The potential energy decrease is then proportional to

ΔPE = mgΔh

where

ΔPE is the decrease in kinetic energy

m is the mass of the ball

g is acceleration due to gravity

Δh is the change in height

For a body falling from its maximum height, the increase change in velocity

Δv = u + 2gΔh    (at maximum height u = 0)

where

u is the initial kinetic energy of the ball

Δv = 0 + 2gΔh

Δv = 2gΔh

The kinetic energy increases by

ΔKE = [tex]\frac{1}{2}[/tex]m(Δv)^2

but Δv = 2gΔh

therefore

ΔKE = [tex]\frac{1}{2}[/tex]m(2gΔh)^2 = 2m(gΔh)^2

comparing the increase in kinetic energy to the decrease in potential energy, we have

(2m(gΔh)^2)/(mgΔh) = 2gΔh

This means that for every decrease in potential energy, a kinetic energy proportional to 2gΔh is gained.

Two campers in a national park hike from their cabin to the same spot on a lake, each taking a different path, as illustrated below. The total distance traveled along Path 1 is 7.5 km, and that along Path 2 is 8.2 km. What is the final displacement of each camper?

Answers

Answer:

Their displacement is 5 Km from the cabin.

Explanation:

The displacement is define is the shortest distance between two points. It is the shortest distance of a line that joins two points together. It quantifies both the distance and direction of the net or total motion along a straight line from the initial position to the final position of the point trajectory. In this case, the straight line joining the cabin to the stream is line S which is equal to 5 Km

A three-phase load has a phase voltage of 240 V and a phase current of 18 A. What is the apparent power of this load

Answers

Answer:

7482.5VA

Explanation:

We have that,

phase voltage of a three phase load is,240v

The phase current of a three phase load is, 18A

So To find apparent load we use

VA= √3*E*I

=√ 3*240*18

=7482.5VA

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