WHOEVER CAN ANSWER 50 POINTS IF U CAN SOLVE IT PLEASE IM DESPERATE

Answer:

Step-by-step explanation:

To determine which option will yield the most money after three years, let's calculate the final amount for each option.

Option #1 - CD for 3 years:

Principal (initial investment) = $1000

Interest rate = 3% per year (compounded monthly)

No additional money can be added

To calculate the final amount, we can use the formula for compound interest:

A = P * (1 + r/n)^(n*t)

Where:

A = Final amount

P = Principal (initial investment)

r = Interest rate (as a decimal)

n = Number of times the interest is compounded per year

t = Number of years

For Option #1:

P = $1000

r = 3% = 0.03 (as a decimal)

n = 12 (compounded monthly)

t = 3 years

A = $1000 * (1 + 0.03/12)^(12*3)

Calculating the final amount for Option #1, we get:

A = $1000 * (1 + 0.0025)^(36)

A ≈ $1000 * (1.0025)^(36)

A ≈ $1000 * 1.0916768

A ≈ $1091.68

Option #2 - CD for 1 year:

Principal (initial investment) = $1000

Interest rate = 2% per year (compounded quarterly)

Money can be added at the end of each year

To calculate the final amount, we need to consider the annual additions and compounding at the end of each year.

First Year:

P = $1000

r = 2% = 0.02 (as a decimal)

n = 4 (compounded quarterly)

t = 1 year

A = $1000 * (1 + 0.02/4)^(4*1)

A ≈ $1000 * (1.005)^(4)

A ≈ $1000 * 1.0202

A ≈ $1020.20

At the end of the first year, the total amount is $1020.20.

Second Year:

Now we add an additional $60 to the previous amount:

P = $1020.20 + $60 = $1080.20

r = 2% = 0.02 (as a decimal)

n = 4 (compounded quarterly)

t = 1 year

A = $1080.20 * (1 + 0.02/4)^(4*1)

A ≈ $1080.20 * (1.005)^(4)

A ≈ $1080.20 * 1.0202

A ≈ $1101.59

At the end of the second year, the total amount is $1101.59.

Third Year:

Again, we add $60 to the previous amount:

P = $1101.59 + $60 = $1161.59

r = 2% = 0.02 (as a decimal)

n = 4 (compounded quarterly)

t = 1 year

A = $1161.59 * (1 + 0.02/4)^(4*1)

A ≈ $1161.59 * (1.005)^(4)

A ≈ $1161.59 * 1.0202

A ≈ $1185.39

At the end of the third year, the total amount is $1185.39.

Comparing the final amounts:

Option #1: $1091.68

Option #2: $1185.39

Therefore, Option #2 - CD for 1 year with an interest rate of 2% compounded quarterly and the ability to add money at the end of each year will yield the most money after three years.

Answer:

Step-by-step explanation:

To find the volume of the solid obtained by rotating the region bounded by the graphs y = (x - 4)^3, the x-axis, x = 0, and x = 5 about the y-axis, we can use the method of cylindrical shells.

The formula for the volume of a solid obtained by rotating a region bounded by the graph of a function f(x), the x-axis, x = a, and x = b about the y-axis is given by:

V = 2π ∫[a, b] x * f(x) dx

In this case, the function f(x) = (x - 4)^3, and the bounds of integration are a = 0 and b = 5.

Substituting these values into the formula, we have:

V = 2π ∫[0, 5] x * (x - 4)^3 dx

To evaluate this integral, we can expand the cubic term and then integrate:

V = 2π ∫[0, 5] x * (x^3 - 12x^2 + 48x - 64) dx

V = 2π ∫[0, 5] (x^4 - 12x^3 + 48x^2 - 64x) dx

Integrating each term separately:

V = 2π [1/5 x^5 - 3x^4 + 16x^3 - 32x^2] evaluated from 0 to 5

Now we can substitute the bounds of integration:

V = 2π [(1/5 * 5^5 - 3 * 5^4 + 16 * 5^3 - 32 * 5^2) - (1/5 * 0^5 - 3 * 0^4 + 16 * 0^3 - 32 * 0^2)]

Simplifying:

V = 2π [(1/5 * 3125) - 0]

V = 2π * (625/5)

V = 2π * 125

V = 250π

Therefore, the volume of the solid obtained by rotating the region bounded by the graphs y = (x - 4)^3, the x-axis, x = 0, and x = 5 about the y-axis is 250π cubic units.

Answer:

The number is 16

Step-by-step explanation:

This follows a multiplication rule,

4 times 1 = 4

4 times 2 = 8

4 times 3 = 12

4 times 4 = 16

So, the number is 16

The vertex of point A' in the dilated triangle A'B'C' is (6, 4.5).

1. Start by calculating the distance between the vertices of the original triangle ABC:

  - Distance between A(4, 3) and B(3, -2):

    Δx = 3 - 4 = -1

    Δy = -2 - 3 = -5

    Distance = √((-[tex]1)^2[/tex] + (-[tex]5)^2[/tex]) = √26

  - Distance between B(3, -2) and C(-3, 1):

    Δx = -3 - 3 = -6

    Δy = 1 - (-2) = 3

    Distance = √((-6)² + 3²) = √45 = 3√5

  - Distance between C(-3, 1) and A(4, 3):

    Δx = 4 - (-3) = 7

    Δy = 3 - 1 = 2

    Distance = √(7² + 2²) = √53

2. Apply the scale factor of 1.5 to the distances calculated above:

  - Distance between A' and B' = 1.5 * √26

  - Distance between B' and C' = 1.5 * 3√5

  - Distance between C' and A' = 1.5 * √53

3. Determine the coordinates of A' by using the distance formula and the given coordinates of A(4, 3):

  - A' is located Δx units horizontally and Δy units vertically from A.

  - Δx = 1.5 * (-1) = -1.5

  - Δy = 1.5 * (-5) = -7.5

  - Coordinates of A':

    x-coordinate: 4 + (-1.5) = 2.5

    y-coordinate: 3 + (-7.5) = -4.5

4. Thus, the vertex of point A' in the dilated triangle A'B'C' is (2.5, -4.5).

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Cara's first error occurred when she simplified the expression (negative 4) squared.

According to the order of operations (PEMDAS/BODMAS), exponentiation should be performed before any other operations. However, Cara incorrectly squared only the negative sign and not the entire number.

As a result, she obtained a value of positive 4 instead of 16.

To correct the error, Cara should have squared the entire value of -4. Squaring a negative number yields a positive result. Thus, (-4) squared is equal to 16. By failing to correctly apply this rule, Cara ended up with an incorrect value in her expression.

The correct evaluation of the expression should have been:

StartFraction 4 (7 minus 13) over 3 EndFraction + (negative 4) squared minus 2 (6 minus 2) = StartFraction 4 (-6) over 3 EndFraction + 16 minus 2 (4) = -8 + 16 - 8 = 0.

Therefore, Cara's first error was in incorrectly squaring only the negative sign and obtaining a value of 4 instead of 16.

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The height of a person whose length of forearm is 24.5 cm is equal to 163.38 centimeters.

In this exercise, we would plot the length of forearm on the x-axis of a scatter plot while height would be plotted on the y-axis of the scatter plot through the use of Microsoft Excel.

On the Microsoft Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display a linear equation for the line of best fit on the scatter plot;

y = 3.01x + 89.63

Based on the equation of the line of best fit above, the height of a person whose length of forearm is 24.5 cm can be determined as follows;

y = 3.01x + 89.63

y = 3.01(24.5) + 89.63

y = 163.375 ≈ 163.38 centimeters.

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[tex]\qquad\displaystyle \rm \dashrightarrow \: let \: \: Sydney's \: \: age \: \: be \: \: 'y'[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: Devaughn's \: \: age \: \: will \: \: be \: \: 3y[/tex]

Sum up ;

[tex]\qquad\displaystyle \tt \dashrightarrow \: 3y + y = 80[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: 4y = 80[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: y = 80 \div 4[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: y = 20[/tex]

So, Sydney's age is 20 years, n that of Devaughn is 20 × 3 = 60 years

Answer:

Sydney= 20, Devaughn= 60

Step-by-step explanation:

Let Sydney's age be 'x'

Devaughn's age = 3 times x = 3x

We Know That

The sum of their ages is 80.

So,

3x + x = 80

4x = 80

If we shift the 4 to the 80 side

x = 80/4

x = 20

So, Sydney's age is 20

Therefore, Devaughn's age =

3x = 3 times x

= 3 times 20

= 60

The data set has two outliers, namely the points (2, 225) and (8, 75).

Based on the given information about the scatterplot, we can observe that most of the points are grouped closely together and show a slight increase.

There are two points that lie outside of this cluster, specifically (2, 225) and (8, 75).

To determine if these points are outliers, we need to consider their deviation from the general pattern exhibited by the majority of the data points.

If these points deviate significantly from the overall trend, they can be considered outliers.

In this case, since (2, 225) and (8, 75) lie outside of the cluster of closely grouped points and do not follow the general pattern, they can be considered outliers.

These points are noticeably different from the majority of the data points and may have influenced the overall trend of the scatterplot.

The data set has two outliers, namely the points (2, 225) and (8, 75).

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Answer:

Step-by-step explanation:

To evaluate the expression {p - q, p - q}, which represents the inner product of the polynomial (p - q) with itself, you can follow these steps:

Given p(x) = 5x^2 - x - 3 and q(x) = 2x^2 + 4x - 3.

Subtract q(x) from p(x) to get (p - q):

(p - q)(x) = (5x^2 - x - 3) - (2x^2 + 4x - 3)

= 5x^2 - x - 3 - 2x^2 - 4x + 3

= (5x^2 - 2x^2) + (-x - 4x) + (-3 + 3)

= 3x^2 - 5x

Now, calculate the inner product of (p - q) with itself using the given inner product formula:

{p - q, p - q} = 5(a1)(a2) + 4(b1)(b2) + 3(c1)(c2)

= 5(3)(3) + 4(-5)(-5) + 3(0)(0)

= 45 + 100 + 0

= 145

Therefore, the value of {p - q, p - q} is 145.

HI Your answer is 42

I have calculated it you can trust me

Well you have marked right in the pic

PLEASE MARK AS BRAINLIEST

The tax charged on Omari's monthly earning of Ksh 24,200 is Ksh 3,340.

To calculate the tax charged on Omari's monthly earning, we need to consider the tax brackets and rates applicable in the specific tax system or country. Since you haven't specified a particular tax system, I will provide a general explanation.

Assuming we have a simplified progressive tax system with three tax brackets:

For the first tax bracket, let's say income up to Ksh 10,000 is taxed at a rate of 10%.

For the second tax bracket, income between Ksh 10,001 and Ksh 20,000 is taxed at a rate of 15%.

For the third tax bracket, income above Ksh 20,000 is taxed at a rate of 20%.

To calculate the tax charged on Omari's monthly earning of Ksh 24,200, we can divide it into the respective tax brackets:

Ksh 10,000 falls in the first tax bracket. So, the tax for this portion is 10% of Ksh 10,000, which is Ksh 1,000.

Ksh 20,000 - Ksh 10,000 = Ksh 10,000 falls in the second tax bracket. The tax for this portion is 15% of Ksh 10,000, which is Ksh 1,500.

The remaining amount, Ksh 24,200 - Ksh 20,000 = Ksh 4,200, falls in the third tax bracket. The tax for this portion is 20% of Ksh 4,200, which is Ksh 840.

Now, we can sum up the taxes for each bracket:

Total Tax = Tax in the first bracket + Tax in the second bracket + Tax in the third bracket

Total Tax = Ksh 1,000 + Ksh 1,500 + Ksh 840

Total Tax = Ksh 3,340

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The given expression, 10f - 5f + 8 + 6g + 4, simplifies to 5f + 12 + 6g when like terms are combined.

To simplify the expression 10f - 5f + 8 + 6g + 4, we can combine like terms by adding or subtracting coefficients that have the same variables:

10f - 5f + 8 + 6g + 4

Combining the terms with 'f', we have:

(10f - 5f) + 8 + 6g + 4

This simplifies to:

5f + 8 + 6g + 4

Next, we can combine the constant terms:

8 + 4 = 12

Thus, the simplified expression is:

5f + 12 + 6g

This expression is equivalent to 10f - 5f + 8 + 6g + 4.

In summary, the expression 10f - 5f + 8 + 6g + 4 simplifies to 5f + 12 + 6g after combining like terms.

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Answer:

- 8a²

Step-by-step explanation:

using the rule of exponents

[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]a^{(m - n)}[/tex]

given

[tex]\frac{80a^9}{-10a^7}[/tex]

= [tex]\frac{80}{-10}[/tex] × [tex]a^{(9-7)}[/tex]

= - 8 × a²

= - 8a²

Combining the results of a given triangle, we can conclude that the value of 'x' must be greater than -22 and also less than 52. So, the possible range for 'x' is -22 < x < 52.

To find the value of 'x' in a triangle with side lengths 'x', 37, and 15, we can use the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the remaining side.

In this case, we have:

x + 37 > 15 (Sum of x and 37 is greater than 15)

x + 15 > 37 (Sum of x and 15 is greater than 37)

37 + 15 > x (Sum of 37 and 15 is greater than x)

From the first inequality, we can subtract 37 from both sides:

x > 15 - 37

x > -22

From the second inequality, we can subtract 15 from both sides:

x > 37 - 15

x > 22

From the third inequality, we can subtract 15 from both sides:

52 > x

Combining the results, we can conclude that the value of 'x' must be greater than -22 and also less than 52. So, the possible range for 'x' is -22 < x < 52.

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The equation to determine the initial amount of money Cecilia had is x = 0.

Let's denote the initial amount of money Cecilia had as "x" dollars.

According to the given information, Cecilia spent one-fourth (1/4) of her money on a book, which is (1/4)x dollars. After buying the book, she had (x - (1/4)x) dollars left.

Next, Cecilia spent half (1/2) of the remaining money on a comic, which is ((1/2)x - 8) dollars. After buying the comic, she had ((x - (1/4)x) - ((1/2)x - 8)) dollars remaining.

Since she had $8 left, we can set up the equation:

((x - (1/4)x) - ((1/2)x - 8)) = 8

To simplify the equation, we can first combine like terms:

(x - (1/4)x - (1/2)x + 8) = 8

Now, let's solve the equation step by step:

(x - (1/4)x - (1/2)x + 8) = 8

Multiplying the fractions by their common denominator, which is 4, we get:

(4x - x - 2x + 32) = 32

Simplifying further:

(x + 32) = 32

Subtracting 32 from both sides:

x = 0

Therefore, the equation to determine the initial amount of money Cecilia had is x = 0.

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a. The  slope of the curve at the point (4,16)   is approximately 1.165, and at the point (16,4)  is approximately -0.496.

b. The   curve has a horizontal tangent line at the points(0,0) and (3,27).

c. The   curve has a vertical tangent lineat the points (0,0) and (65/2, (65/2)³).

a. To find the   slope of the curve given by the equation x³ + y³ - 65xy = 0 at the points (4,16) and (16,4),we can differentiate the equation implicitly with respect to x and solve for dy/dx.

Differentiating the equation with respect to x, we have  -

3x² + 3y²(dy/dx) - 65y - 65x(dy/dx) = 0

To find the slope at a specific point, substitute the x and y coordinates into the equation and solve for dy/dx.

For the point (4,16)  -

3(4)² + 3(16)²(dy/dx) - 65(16) - 65(4)(dy/dx) = 0

48 + 768(dy/dx) - 1040 - 260(dy/dx) = 0

508(dy/dx) = 592

(dy/dx) = 592/508

(dy/dx) ≈ 1.165

For the point (16,4)  -

3(16)² + 3(4)²(dy/dx) - 65(4) - 65(16)(dy/dx) = 0

768 + 48(dy/dx) - 260 - 1040(dy/dx) = 0

(-992)(dy/dx) = 492

(dy/dx) = 492/(-992)

(dy/dx) ≈ -0.496

Thus, the slope of the   curve at the point (4,16) isapproximately 1.165, and at the point (16,4) is approximately -0.496.

b. To find the point where the curve has   a horizontal tangent line, we need to find the x-coordinate(s)where dy/dx equals zero.

This means   the slope is zero and the tangent line is horizontal.

From the derivative we obtained earlier  -

3x² + 3y²(dy/dx) - 65y - 65x(dy/dx) = 0

Setting dy/dx equal to zero  -

3x² - 65y = 0

Substituting y = x³/65 into the equation  -

3x² - 65(x³/65) = 0

3x² - x³ = 0

Factoring out an x²  -

x²(3 - x) = 0

This equation has two solutions  -  x = 0 and x = 3.

hence, the curve has a horizontal   tangent line at the points(0,0) and (3,27).

c. To find the point where the curve has a vertical tangent line, we need to find the x-coordinate(s)   where the derivative is undefinedor approaches infinity.

From the derivative  -

3x² + 3y²(dy/dx) - 65y - 65x(dy/dx) = 0

To find the vertical tangent line, dy/dx should be undefined or infinite. This occurs when the denominator of dy/dx is zero.

Setting the denominator equal to zero:  -

65x = 65y

x = y

Substituting this condition back into the original equation  -

x³ + x³ - 65x² = 0

2x³ - 65x² = 0

x²(2x - 65) = 0

This equation has two solutions  - x = 0 and x = 65/2.

Therefore, the curve has a vertical tangent line   at the points (0,0)

and(65/2, (65/2)³).

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a) The factored expression for h(t) is -16t(t - 10), obtained by factoring out a common factor of -16 and a common factor of t from the original expression -16t^2 + 160t.

b) Both the original expression -16t^2 + 160t and the factored expression -16t(t - 10) yield the same result of 144 when evaluated at t = 1, confirming the correctness of the factoring.

a) To factor out a common factor with a negative coefficient from the expression h(t) = [tex]-16t^2 + 160t[/tex], we can rewrite it as:

h(t) = [tex]-16(t^2 - 10t)[/tex]

Now, let's focus on factoring the quadratic expression inside the parentheses. We can factor out a common factor of t:

h(t) = -16t(t - 10)

Therefore, the factored expression for h(t) is -16t(t - 10).

b) To check the factoring by evaluating both expressions for h(t) at t = 1, we substitute t = 1 into the original expression and the factored expression and compare the results.

Using the original expression:

h(1) = [tex]-16(1)^2 + 160(1)[/tex]

h(1) = -16 + 160

h(1) = 144

Using the factored expression:

h(1) = -16(1)(1 - 10)

h(1) = -16(1)(-9)

h(1) = 144

Both expressions yield the same result of 144 when evaluated at t = 1. Therefore, the factoring is correct.

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Answer:

The question isn't clear. Can you provide more information or context? What is A? Is it a set or a number? Without this information, I can't provide a meaningful answer.

The formula to find the value of a combination is

[tex]C(n, r) = n! / (r!(n-r)!),[/tex]

where n represents the total number of items and r represents the number of items being chosen at a time. 10C0 is 1

In the  combination,

n = 10 and r = 0,

so the formula becomes:

C(10,0) = 10! / (0! (10-0)!) = 10! / (1 x 10!) = 1 / 1 = 1

This means that out of the 10 items, when choosing 0 at a time, there is only 1 way to do so. In other words, choosing 0 items from a set of 10 items will always result in a single set. This is because the empty set (which has 0 items) is the only possible set when no items are chosen from a set of items. Therefore, the value of the combination 10C0 is 1.

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Answer:

The parabola has a vertex at (3, -4), has a p-value of -6 and it opens downwards.

Step-by-step explanation:

The given directrix of the parabola is y = 2, which is a horizontal line.

This means that the parabola is vertical, with a vertical axis of symmetry.

The focus of a parabola is a fixed point located inside the curve. The y-coordinate of the given focus is y = -10. As this is below the directrix, it means that the parabola opens downwards.

The standard form of a vertical parabola is:

[tex]\boxed{(x-h)^2=4p(y-k)}[/tex]

where:

As the focus is (3, -10), then:

[tex](h, k+p)=(3,-10)[/tex]

     [tex]\implies h = 3[/tex]

[tex]\implies k+p=-10[/tex]

As the directrix is y = 2, then:

[tex]k - p=2[/tex]

To find the value of k, sum the equations involved k and p to eliminate p:

[tex]\begin{array}{crcccr}&k &+& p& =& -10\\+&k& -& p& = &2\\\cline{2-6}&2k&&& =& -8\\\cline{2-6}\\\implies &k&&&=&-4\end{array}[/tex]

To find the value of p, substitute the found value of k into one of the equations:

[tex]-4-p=2[/tex]

        [tex]p=-4-2[/tex]

        [tex]p=-6[/tex]

Therefore, the values of h, k and p are:

The parabola has a vertex at (3, -4), has a p-value of -6 and it opens downwards.

The parabola has a vertex at (3, -4), has a p-value of -6 and it opens downwards.

In Mathematics, the standard form of the equation of the directrix lines for any parabola is given by this mathematical equation:

(x - h)² = 4p(y - k).

Where:

Since the directrix is horizontal, the axis of symmetry would be vertical. This ultimately implies that, we would have the following parameters;

directrix is y = 2

Focus, (h, k + p) = (3, -10)

Next, we would determine the value of k as follows;

k + p = -10     .......equation 1

k - p = 2     .......equation 2

By solving the equations simultaneously, we have:

2k = -8

k = -4

For the value of p, we have the following from equation 2:

k - p = 2

-4 - p = 2

p = -4 - 2

p = -6

In conclusion, we can logically deduce that the parabola opens downward because the p-value is negative.

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Answer:

B. Lenghts of the diagonals

Step-by-step explanation:

Answer:

(-4,4)

Step-by-step explanation:

You rewrite the terms:

(x + 4)^2 => [x - (-4)]^2

(y - 4)^2 => [y - (4)]^2

so h = -4 and k = 4

so center of ellipse is (h,k) or (-4,4)

Answer:

Center = (-4, 4)

Step-by-step explanation:

The standard form of the equation of an ellipse with center (h, k) is:

[tex]\boxed{\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1}[/tex]

The given equation is:

[tex]\dfrac{(x+4)^2}{25}+\dfrac{(y-4)^2}{9}=1[/tex]

Comparing the given equation with the standard form, we can see that h = -4 and k = 4. Therefore, the center (h, k) of the ellipse is (-4, 4).

Answer:

m = -3

Step-by-step explanation:

The slope-intercept form is y = mx + b

m = the slope

b = y-intercept

The equation is  y = -3x + 2

m = -3

So, the slope of the line is -3

Answer:

The slope is -3

Step-by-step explanation:

You were given the easiest form of linear equation, the slope-intercept form, because these are the ones that directly tell you the slope and       the y-intercept.

y=mx+b, Where m is the slope and b is the y-intercept.

The correct answer choice is: A. The system has exactly one solution. The solution is (13, 5).

The correct answer choice is: A. all three countries had the same population of 5 thousand in the year 2013.

Based on the information provided above, the population (y) in the year (x) of the counties listed are approximated by the following system of equations:

-x + 20y = 87

-x + 10y = 37

y = 5

where:

By solving the system of equations simultaneously, we have the following solution:

-x + 20(5) = 87

x = 100 - 87

x = 13

-x + 10(5) = 37

x = 50 - 37

x = 13

Therefore, the system of equations has only one solution (13, 5).

For the year when the population are all the same for three countries, we have:

x = 2010 + (13 - 10)

x = 2013

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Answer:

37

Step-by-step explanation:

x=-4

=2(5-(-4)2+1

=2(5+4)2+1

=2(9)2+1

=18(2)+1

=36+1

=37

Answer:

[tex]\dfrac{\sqrt{2}-\sqrt{6} }{4} }[/tex]

Step-by-step explanation:

Find the exact value of cos(105°).

The method I am about to show you will allow you to complete this problem without a calculator. Although, memorizing the trigonometric identities and the unit circle is required.    

We have,

[tex]\cos(105\°)[/tex]

Using the angle sum identity for cosine.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Angle Sum Identity for Cosine}}\\\\\cos(A+B)=\cos(A)\cos(B)-\sin(A)\sin(B)\end{array}\right}[/tex]

Split the given angle, in degrees, into two angles. Preferably two angles we can recognize on the unit circle.

[tex]105\textdegree=45\textdegree+60\textdegree\\\\\\\therefore \cos(105\textdegree)=\cos(45\textdegree+60\textdegree)[/tex]

Now applying the identity.

[tex]\cos(45\textdegree+60\textdegree)\\\\\\\Longrightarrow \cos(45\textdegree+60\textdegree)=\cos(45\textdegree)\cos(60\textdegree)-\sin(45\textdegree)\sin(60\textdegree)[/tex]

Now utilizing the unit circle.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{From the Unit Circle:}}\\\\\cos(45\textdegree)=\dfrac{\sqrt{2} }{2}\\\\\cos(60\textdegree)=\dfrac{1}{2}\\\\\sin(45\textdegree)=\dfrac{\sqrt{2} }{2}\\\\\sin(60\textdegree)=\dfrac{\sqrt{3} }{2} \end{array}\right}[/tex]

[tex]\cos(45\textdegree)\cos(60\textdegree)-\sin(45\textdegree)\sin(60\textdegree)\\\\\\\Longrightarrow \Big(\dfrac{\sqrt{2} }{2}\Big)\Big(\dfrac{1 }{2}\Big)-\Big(\dfrac{\sqrt{2} }{2}\Big)(\dfrac{\sqrt{3} }{2}\Big)[/tex]

Now simplifying...

[tex]\Big(\dfrac{\sqrt{2} }{2}\Big)\Big(\dfrac{1 }{2}\Big)-\Big(\dfrac{\sqrt{2} }{2}\Big)(\dfrac{\sqrt{3} }{2}\Big)\\\\\\\Longrightarrow \Big(\dfrac{\sqrt{2} }{4} \Big)-\Big(\dfrac{\sqrt{6} }{4} \Big)\\\\\\\therefore \cos(105\textdegree)= \boxed{\boxed{\frac{\sqrt{2}-\sqrt{6} }{4} }}[/tex]

Answer:

In Grade 4, students are introduced to the concept of chance and the idea that different situations have different probabilities of occurring. They learn that for many situations, there are a finite number of different possible outcomes. However, at this stage, students are not expected to calculate the probability of events occurring. In Grade 5, students continue to build on their understanding of probability and may begin to learn more advanced concepts and techniques for calculating probabilities.

Step-by-step explanation:

Answer:

(-13, -9) and (-5, -9)

Step-by-step explanation:

The given equation of the hyperbola is:

[tex]\dfrac{(y+9)^2}{25}-\dfrac{(x+9)^2}{16}=1[/tex]

As the y²-term of the given equation is positive, the transverse axis is vertical, and so the hyperbola is vertical (opens up and down).

The standard equation for a vertical hyperbola is:

[tex]\boxed{\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1}[/tex]

where:

Compare the given equation with the standard equation to find the values of h, k, a and b:

The formula for the co-vertices of a vertical hyperbola is (h±b, k).

Substitute the values of b, h and k into the formula:

[tex]\begin{aligned}\textsf{Co-vertices}&=(h\pm b,k)\\&=(-9\pm 4, -9)\\&=(-13,-9)\;\;\textsf{and}\;\;(-5, -9)\end{aligned}[/tex]

Therefore, the co-vertices of the given hyperbola are:

The co-vertices of the hyperbola are (-4, -9) and (-14, -9).

To find the co-vertices of the hyperbola defined by the equation:

[(y + 9)² / 25] - [(x + 9)² / 16] = 1

We can compare the equation to the standard form of a hyperbola:

[(y - h)² / a²] - [(x - k)² / b²] = 1

In this case, we have h = -9 and k = -9.

The co-vertices of a hyperbola lie on the transverse axis, which is the line passing through the center of the hyperbola. The center of the hyperbola is given by (h, k), which in this case is (-9, -9).

For a hyperbola with the equation in this form, the co-vertices are located a units to the right and left of the center. In this case, since the equation is [(y + 9)² / 25] - [(x + 9)² / 16] = 1, we have a = 5.

Therefore, the co-vertices are located at (-9 ± a, -9), which gives us:

(-9 + 5, -9) = (-4, -9)

(-9 - 5, -9) = (-14, -9)

Learn more on co-vertices of hyperbola here;

https://brainly.com/question/15935373

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