Whoever answers this fully will get brainliest. Part A: Using the graph above, create a system of inequalities that only contains points C and F in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A. Part C: Chickens can only be raised in the area defined by y > −4x + 3. Explain how you can identify farms in which chickens can be raised.
Answers
Answer:
Step-by-step explanation:
a. the inequality is x+y >= 2 (red line) that keeps onlythe two farms in the region.
b. substituting the coordinates of the farms in the inequality and see if they are satisfied:
C(2,2) 2+2 = 4 > 2 checks
F(3,4) 3+4 = 7 > 2 checks.
The other farms will not , for example,
D(1,-2) 1-2 = -1 < 2 does not check.
...
c. y > -4x + 3 is shown in blue.
Farms that satisfy given inequality can raise chickens, i.e. to the right of the blue line, or farms C,E and F.
If necessary, we can again check by the coordinates as in part b.
C(2,2) -4(2) + 2 = -8+2 = -6 y=2 > -6, so checks.
...
Related Questions
The snail moved 6 inches in 120 minutes. What was the average speed of the snail in inches per minute?
Answers
Answer:
Option A) Speed = 1/20 of an inch per minute
Step-by-step explanation:
Given:
Distance = 6 inches
Time = 120 mins
Required:
Average Speed = ?
Formula:
Average Speed = Total Distance Covered / Total Time Taken
Solution:
Speed = 6/120
Speed = 1/20 of an inch per minute
Answer:
[tex]\frac{1}{20}[/tex] of an Inch per minute
Step-by-step explanation:
Speed = Distance ÷ Time
So....
6 ÷ 120 = 0.05 or [tex]\frac{1}{20}[/tex]
Also by process of elimination
[tex]\frac{1}{2}[/tex] of an inch per min would complete 6 inches in 12 min.
2 inches per min would complete 6 inches in 3 min
20 inches per minute would complete 6 inches in a few seconds.
simplify this please 41 =12d-741=12d−7
Answers
Answer:
Simplifying
41 = 12d + -7
Reorder the terms:
41 = -7 + 12d
Solving
41 = -7 + 12d
Solving for variable 'd'.
Move all terms containing d to the left, all other terms to the right.
Add '-12d' to each side of the equation.
41 + -12d = -7 + 12d + -12d
Combine like terms: 12d + -12d = 0
41 + -12d = -7 + 0
41 + -12d = -7
Add '-41' to each side of the equation.
41 + -41 + -12d = -7 + -41
Combine like terms: 41 + -41 = 0
0 + -12d = -7 + -41
-12d = -7 + -41
Combine like terms: -7 + -41 = -48
-12d = -48
Divide each side by '-12'.
d = 4
Simplifying
d = 4
5.
Find a solution to the following system of equations.
-2x + y = -3
- x + 2y = 3
(-21, -9).
(3, 3)
(0, 2)
Answers
Answer:
(3,3)
Step-by-step explanation:
I used a graphing tool to graph the two equations. The lines intercept at (3,3). Therefore, (3,3) would be a solution to the system of equations.
Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized
Answers
Answer:
[tex]m = 5 \sqrt{3}[/tex]
[tex]n = 5[/tex]
Step-by-step explanation:
Given
The triangle above
Required
Find the missing lengths
The missing lengths can be calculated by applying trigonometry ratios
From the triangle above,
the Hypotenuse is 10
Angle = 60
Calculating m
The relationship between m, the Hypotenuse and angle 60 is defined as follows;
[tex]sin \theta = \frac{Opp}{Hyp}[/tex]
Where [tex]\theta = 60[/tex]
[tex]Opp = m[/tex]
[tex]Hyp = 10[/tex]
The above formula becomes
[tex]sin60= \frac{m}{10}[/tex]
Multiply both sides by 10
[tex]10 * sin60= \frac{m}{10} * 10[/tex]
[tex]10 * sin60= m[/tex]
In radical from, [tex]sin60 = \frac{\sqrt{3}}{2}[/tex]
[tex]10 * sin60= m[/tex] becomes
[tex]10 * \frac{\sqrt{3}}{2}= m[/tex]
[tex]\frac{10* \sqrt{3}}{2}= m[/tex]
[tex]5 \sqrt{3}= m[/tex]
[tex]m = 5 \sqrt{3}[/tex]
Calculating n
The relationship between n, the Hypotenuse and angle 60 is defined as follows;
[tex]cos\theta = \frac{Adj}{Hyp}[/tex]
Where [tex]\theta = 60[/tex]
[tex]Adj = n[/tex]
[tex]Hyp = 10[/tex]
The above formula becomes
[tex]cos60= \frac{n}{10}[/tex]
Multiply both sides by 10
[tex]10 * cos60= \frac{n}{10} * 10[/tex]
[tex]10 * cos60= n[/tex]
In radical from, [tex]cos60= \frac{1}{2}[/tex]
[tex]10 * cos60= n[/tex] becomes
[tex]10 * \frac{1}{2}= n[/tex]
[tex]\frac{10*1}{2}= n[/tex]
[tex]5 = n[/tex]
[tex]n = 5[/tex]
Karl set out to Alaska on his truck.
The amount of fuel remaining in the truck's tank (in liters) as a function of distance driven (in kilometers) is
graphed.
How much fuel did the truck consume every 100 kilometers
Answers
Answer:
the amount of fuel consumed every 100 kilometers is 62.5 litres.
Step-by-step explanation:
To determine the amount of fuel consumed every 100 kilometers.
Note: since the graph is a straight line graph (linear graph) the amount of fuel consumed every 100 kilometers is constant (i.e the same for every 100 kilometers). So, we only need to derive the amount of fuel consumed any 100 kilometers on the graph.
From the graph, the amount of fuel consumed for the first 100 kilometers is;
[tex]F = F_0 - F_{100} .........................1[/tex]
[tex]F_0 = 500\\F_{100} \simeq 437.5\\[/tex]
substituting into equation 1.
[tex]F = F_0 - F_{100} \\F = 500 - 437.5\\ F = 62.5 litres\\[/tex]
Therefore, the amount of fuel consumed every 100 kilometers is 62.5 litres.
Answer:500
Step-by-step explanation:got it on Kahn
NEED HELP ASAPPP!!! Drag each scenario to show whether the final result will be greater than the original
value, less than the original value, or the same as the original value.
1. A $30 increase followed by a $30 decrease
2. A 20% decrease followed by a 40% increase
3. A 100% increase followed by a 50% decrease
4. A 75% increase followed by a 33% decrease
5. 55% decrease followed by a 25% increase
Answers
Answer:
Greater than the original = 2, 4
Less than the original = 5
Same as the original = 1, 3
Step-by-step explanation:
Let the original value be x.
1. A $30 increase followed by a $30 decrease.
New value [tex]=x+30-30=x[/tex], it is same as original value.
2. A 20% decrease followed by a 40% increase.
Afer 20% decrease.
New value [tex]=x-\dfrac{20}{100}x=x-0.2x=0.8x[/tex]
Afer 40% increase.
New value [tex]=0.8x+\dfrac{40}{100}(0.8x)=0.8x+0.32x=1.12x[/tex], it is greater than original value.
Similarly check the other values.
3. A 100% increase followed by a 50% decrease.
New value [tex]=x+\dfrac{100}{100}x-\dfrac{50}{100}(x+x)=x[/tex], it is same as original value.
4. A 75% increase followed by a 33% decrease
New value [tex]=x+\dfrac{75}{100}x-\dfrac{33}{100}(x+0.75x)=1.1725x[/tex], it is greater than the original value.
5. 55% decrease followed by a 25% increase
New value [tex]=x-\dfrac{55}{100}x+\dfrac{25}{100}(x-0.55x)=0.5625x[/tex], it is less than the original value.
Therefore, Greater than the original = 2, 4, Less than the original = 5, Same as the original = 1, 3 .
A 100% increase followed by a 50% decrease
A $30 increase followed by a $30 decrease
Less Than The Original:55% decrease followed by a 25% increase
Greater Than The Original:A 20% decrease followed by a 40% increase
A 75% increase followed by a 33 1/3% decrease
Find the missing length indicated.
Answers
Answer:
Step-by-step explanation:
x=✓64*36=✓8^2*6^2
x=8*6
x=48
Find the missing segment in the attached image
Answers
Answer:
The length of the missing segment is 36
Step-by-step explanation:
Given
The figure above
Required
Determine the missing segment
Let the missing segment be represented with x
Given that, there exist parallel lines between the two triangles;
The relationship between the sides of the triangles is as follows;
[tex]\frac{20}{24} = \frac{30+20}{24+x}[/tex]
[tex]\frac{20}{24} = \frac{50}{24+x}[/tex]
Cross Multiply
[tex]20 * (24 + x) = 24 * 50[/tex]
[tex]20 * (24 + x) = 1200[/tex]
Divide both sides by 20
[tex]\frac{20 * (24 + x)}{20} = \frac{1200}{20}[/tex]
[tex](24 + x)= \frac{1200}{20}[/tex]
[tex]24 + x= 60[/tex]
Subtract 24 from both sides
[tex]24 - 24 + x = 60 - 24[/tex]
[tex]x = 60 - 24[/tex]
[tex]x = 36[/tex]
Hence, the length of the missing segment is 36
Find the missing side lengths. Leave your answers as radicals in simplest form.
ANSWER QUICK
Answers
Answer:
C
Step-by-step explanation:
It is an iscoceles triangle because there are 180 degrees in a triangle and the right angle plus the 45 degree equals 135 and 180 minus 135 is 45.
Since it is an iscoceles triangle that means that n = 3 and the pythagorean theorom says that a^2 + b^2 = c^2 which means that m = 3^2 plus 3^2 with a root.
3^2 is 9 so you get 18
the root of 18 is infinite, however can be simplified to 3 root to 2 because 3 times 3 equals 9 times 2 equals a root of 18
Hope this helps!
Please could I have some help :)
Answers
Answer:
a) x = 128 degrees
b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc. Therefore angle APD = 128 degrees (and not 116 degrees)
Step-by-step explanation:
Given:
attached diagram
ABC is a straight line
Solution:
a) Find x
ABC is a straight line
angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.
x is the central angle of the arc APD
so angle ABD is the inscribed angle which equals half of the arc angle =>
angle ABD = x/2 = 64 degrees
Solve for x
x/2 = 64
x = 2*64
x = 128 degrees
b.
Angle APD is the arc angle, which is equal to the central angle x subtended by the arc. Therefore angle APD = 128 degrees (and not 116 degrees)
*LAST QUESTION , PLEASE ANSWER TY* (: Quadrilateral ABCD is inscribed in a circle. If angle A measures (3x – 10)° and angle C measures (2x)°, find x.
Answers
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Quadrilaterals.
Basically we know that, the sum of opposite angles of a quadrilateral inscribed in a circle is always 180°.
so applying this law here, we get as,
2X + (3X-10) = 180°
=> 5X - 10° = 180°
=> 5X = 190°
=> X = 190°/5
=> X = 38°
thus the angle X= 38°.
Construct perpendiculars image below
Answers
Answer: draw a straight line trough point B, same thing with the second one,for the third you must draw a straight line from the angle across to the segment. (make sure all of the intersections are 90 degrees
PLEASE HELP! WILL MARK BRAINLIEST! 30 POINTS! ONLY DUE TOMORROW!
1. How many palindromes of length 5 can you form using letters with the following properties: they start with a consonant, and the consonants and vowels alternate; no letter appears more than twice. (Note: assume letters "a", "e", "i", "o", and "u" are the vowels of the English alphabet).
2. How many different words can be formed with the letters AAAABBCCD (not necessarily meaningful words)?
3. How many six-digit numbers have all their digits of equal parity (all odd or all even)?
4. You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this?
5. In how many ways can we put five identical fruits into three bowls? Note that the bowls may be empty.
THANK YOU SO MUCH!
Answers
Answer:
Step-by-step explanation:
5. cut the five fruits into 3 equal parts....
5x3=15 pieces
15/3(bowls)=5 pieces in each bowl
cut the fruits in multiples of 5 divisible by 3....that many ways possible
(similarly 4th qstion can be done)!!
ABCD is a parallelogram.
Given that,
DC = CE
prove that,
area of the ADE triangle is equal to the area of the parallelogram.
need explanation
plzz help!!
will give the brainliest!!
Answers
Drop a perpendicular from [tex]\overline{AK}[/tex] to $\overline {DE}$.
Let $l(AK)=h$ and $l(AB)=l(DC)=L$
$h$ is the height of the parallelogram and the triangle.
$L$ is the length of the base of the triangle and one of the sides of parallelogram.
We have area of parallelogram $=A_{para}=hL$
And the area of triangle is:
$A_{tria}=\frac{1}{2} h\times (L+L)=hL$
Thus we can see that they are equal.
Answer:
See below
Step-by-step explanation:
Given:
ABCD is a parallelogram
DC = CE
To Prove:
area of the ADE triangle is equal to the area of the parallelogram.
Proof:
Let The Point between B and C be F
To prove that area of the ADE triangle is equal to the area of the parallelogram, we'll first prove that ΔADF ≅ ΔECF
Statements | Reason
DC ≅ CE | Given
But, CD ≅ AB | Opposite sides of a ║gm
So, CE ≅ AB | Transitive Property of Equality
∵ ΔABF ↔ ΔECF |
CE ≅ AB | Already Proved
∠CFE ≅ ∠ BFE | Vertical Angles
∠ECF ≅ ∠ABF | Alternate Angles
So, ΔABF ≅ ΔECF | S.A.A. Postulate
Now, |
Area of ║gm = Area of |
quad ADCF + ΔABF |
But, ΔABF ≅ ΔECF | Already Proved
So, |
Area of ║gm = Area of |
quad ABCF + ΔECF |
But Area of ΔADE = Area of |
quad ABCF + ΔECF |
So, |
Area of ║gm = Area of ΔADE | Hence Proved
Please Help!! I will give brainliest to correct answer
A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to the one-way fare, 100 passengers will find other means of transportation. Let x represent the number of $1.00 increases in ticket price.
Choose the inequality to represent the values of x that would allow the carpool service to have revenue of at least $12,000. Then, use the inequality to select all the correct statements.
options:-
The price of a one-way ticket that will maximize revenue is $7.50.
The price of a one-way ticket that will maximize revenue is $12.50.
-100x^2 + 1,500x + 10,000 >/= 12,000
The maximum profit the company can make is $4,125.00.
The maximum profit the company can make is $15,625.00.
100x^2 - 1,500x - 10,000 >/= 12,000
100x^2 + 1,500x - 10,000 = 12,000
(There can be more than one correct answers)
Answers
Answer.
Step-by-step explanation:
Alex, Toby and Samuel are playing a game together.
At the end of the game, they will make a classification with one of them in First
place, one of them in Second place and one of them in Third place.
Work out how many possible outcomes there could be at the end of their game.
Answers
The number of possible outcomes there could be at the end of their game is 6 outcomes
This is a permutation problem since it required arrangement
If Alex, Toby, and Samuel are playing a game together and at the end, they will make a classification with one of them in first place, one of them in Second place and one of them in Third place, this can be done in 3! ways
Since n! = n(n-1)(n-2)!
Hence 3! = 3(3-1)(3-2)
3! = 3 * 2 * 1
3! = 6 ways
Hence the number of possible outcomes there could be at the end of their game is 6 outcomes
Learn more here: https://brainly.com/question/24115376
An outdoor hockey rink has dimensions of 8m long by 5m wide. The wood
surrounding the rink will allow ice to have a height of 20 cm. Calculate the volume
of ice needed to create this rink.
A glass has the shape of a perfect cylinder with a diameter of 8cm and a height of
13 cm. Calculate the surface area of the glass keeping in mind that the glass has
no lid. please show work and will Mark brainliest
Answers
Answer:
First question = 800 cm^3
Second question =120π
Step-by-step explanation:
The formula for volume is base x height x width.
The formula for area of cylinder is 2πrh+2πr^2 but it has no lid so
2πrh+πr^2.
PLEASE HURRY
Quadrilateral ABCD is inscribed in OZ such that AB | DC and Find m
Answers
Answer:
41°
Step-by-step explanation:
First note that m arc BC = m∠BZC
The reason is because a central angle of a circle is always congruent to its
intercepted arc.
Also m∠BAC is one-half m arc BC, as the measure of an inscribed angle is half the measure of its intercepted arc.
Hence, the calculation is given below:
m∠BZC = 82°
m arc BC = m∠BZC
m arc BC = 82°
m∠BAC = 1/2 × 82°
m∠BAC = 41°
It is important to note that
∠DCA ≅ ∠BAC because alternate interior angles are congruent.
So m∠DCA = m∠BAC.
Therefore, m∠DCA = 41°.
What is the factored form of 125a6-64?
Answers
Answer:
(5a^2-4)*(25a^4+20a^2+16)
Step-by-step explanation:
Answer:
Its B, (5a^2-4)(25a^4+20a^2+16)
Step-by-step explanation:
Edge 2020
*PLEASE ANSWER PLS N TY *
Which statement(s) are true about inscribed angles? Statement 1: The vertex of an inscribed angle lies on the circle. Statement 2: The sides of an inscribed angle are tangent lines to the circle. Statement 3: The sides of an inscribed angle are chords of a circle. Statement 4: The vertex of an inscribed angle lies outside a circle.
a.) 4 only
b.) 1 only
c.) 1 & 3 only
d.) 2 & 4 only
Answers
Answer:
1 & 3 only
Step-by-step explanation:
PRE CALC HELP PLEASE
Answers
Answer:
True.
Step-by-step explanation:
The function is indeed a polynomial. We have the single variable [tex]x[/tex] plus a constant [tex]\pi[/tex] (it's irrational, but it's still simply just a constant number). This fits the definition of polynomials.
What is the standard form of 7 + 3i / 2 - 5i
A. -29/21 + 4/21i
B. -29/21 - 4/21i
C. 1/29 - 41/29i
D. -1/29 + 41/29i
Answers
Answer:
Step-by-step explanation:
7 + 3i / 2 - 5i would be clearer if written as (7 + 3i) / (2 - 5i). We must remove the symbol i from the denominator, and that can be accomplished by multiplying both 7 + 3i and 2 - 5i by the conjugate 2 + 5i:
(2 + 5i)(7 + 3i)
--------------------
4 + 29
which simplifies to 14 + 6i + 35i - 15 over 33, or
-1 + 41i
------------
33
Find the area of the shaded polygon
There’s no measurements, use square unit. One square is 1
Answers
Answer:
6 Units squared.
Look at file for explanation.
help! Analyze the diagram below and complete the instructions that follow.
Answers
Answer:
a= 4[tex]\sqrt{6}[/tex]
b= 8[tex]\sqrt{2}[/tex]
c= 4[tex]\sqrt{2}[/tex]
Step-by-step explanation:
45-45-90 triangle
x - x - [tex]\sqrt{2}[/tex]
30-60-90 triangle
x - 2x - x[tex]\sqrt{3}[/tex]
Chicken is normally $2.15/ib.but if you purchase 26 pounds for $41.34,how much do you save per pound
Answers
Answer:
$0.56/lb
Step-by-step explanation:
Given
Cost of a chicken = $2.15 per pound
26 pound of a chicken = $41.34
Required
Calculate how much saved.
The first step is to calculate the unit price of a chicken when 26 pound of chicken was bought.
Unit Price = Price ÷ Weight
Unit Price = $41.34 ÷ 26lb
Unit Price = $1.59/lb
The next step is to calculate the difference between these two prices
Difference = |$1.59/lb - $2.15/lb|
Difference = |-$0.56/lb|
Difference = $0.56/lb
The calculated difference is the amount saved per pound of chicken when I bought 26 pound of chicken.
Evaluate the following when a=2 b=-3 and c=4:
5a -b2 +2c(a-b)
Select one:
a. 41
O b.-41
O c. 135
O d. 270
Answers
Answer:
A. 41
Step-by-step explanation:
5a - b² + 2c(a-b)
Put a = 2, b = -3, and c = 4.
5(2) - (-3)² + 2(4)(2-(-3))
Evaluate.
10 - 9 + 2(4)(2+3)
10 - 9 + 8(5)
10 - 9 + 40
1 + 40
= 41
Answer:
[tex]41[/tex]
Step-by-step explanation:
Given that,
[tex]a = 2 \\ b = - 3 \\ c = 4[/tex]
Let's solve now,
[tex]5a - {b}^{2} + 2c(a - b) \\ 5 \times 2 - ( { - 3}^{2} ) + 2 \times 4(2 - ( - 3)) \\ 10 - ( - 3 \times - 3) + 8(2 + 3) \\ 10 - 9 + 8 \times 5 \\ 10 - 9 + 40 \\ 1 + 40 \\ = 41[/tex]
Points E, F, and D are on circle C, and angle G
measures 60°. The measure of arc EF equals the
measure of arc FD.
Which statements about the arcs and angles are
true? Select three options,
O ZEFD - ZEGD
E
O ZEGD ZECD
ED FD
С
G60°
mEF = 60
OmFD = 120
Mark this and return
Save and Exit
Next
Submit
Answers
Answer:
The correct statements are:
1: mEFD = mEGD
3: mED = mFD
5: mFD = 120°
Step-by-step explanation:
Let's analyse each statement:
1: mEFD = mEGD
Let's find the value of the angle ECD, using the sum of the internal angles of a quadrilateral:
[tex]60 + 90 + 90 + mECD = 360[/tex]
[tex]mECD = 120\°[/tex]
The angle ECD is a central angle, related to the arc ED, so the arc ED also has 120°.
The angle EFD inscribes the arc ED, so we have:
[tex]mEFD = mED/2[/tex]
[tex]mEFD = 120/2 = 60\°[/tex]
So the angles mEFD and mEGD are equal. The statement is TRUE.
2. mEGD = mECD
This statement is FALSE, because mEGD = 60° and mECD = 120°
3. mED = mFD
If mED is 120° and mEF = mFD, we have:
[tex]mED + mEF + mFD = 360[/tex]
[tex]2*mFD = 360 - 120[/tex]
[tex]mFD = 120\°[/tex]
So the statement is TRUE, both arcs have 120°.
4. mEF = 60°
This statement is FALSE, because we calculated before that mEF = mFD = 120°
5. mFD = 120°
This statemente is TRUE, because we calculated before that mFD = 120°.
So the correct statements are 1, 3 and 5
The true statements are: [tex]\angle EFD =\angle EGD[/tex], [tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex]
Start by calculating the measure of angle ECD.
We have:
[tex]\angle ECD = 2 * \angle EGD[/tex]
So, we have:
[tex]\angle ECD = 2 * 60[/tex]
[tex]\angle ECD = 120[/tex]
The above means that:
[tex]\overset{\huge\frown}{ED} = 120[/tex]
So, the measure of angle EFD is:
[tex]\angle EFD = 0.5 * \overset{\huge\frown}{ED}[/tex]
[tex]\angle EFD = 0.5 * 120[/tex]
[tex]\angle EFD = 60[/tex]
From the question, we have:
[tex]\angle EGD = 60[/tex]
So, it is true that:
[tex]\angle EFD =\angle EGD[/tex]
To calculate the measure of arc FD, we have:
[tex]\overset{\huge\frown}{FD} + \overset{\huge\frown}{DE} + \overset{\huge\frown}{EF} =360[/tex]
Lengths EF and DE are congruent.
So, we have:
[tex]2\overset{\huge\frown}{FD} + \overset{\huge\frown}{DE} =360[/tex]
[tex]\overset{\huge\frown}{DE} = \overset{\huge\frown}{ED} = 120[/tex]
So, we have:
[tex]2\overset{\huge\frown}{FD} + 120 =360[/tex]
Divide through by 2
[tex]\overset{\huge\frown}{FD} + 60 =180[/tex]
Subtract 60 from both sides
[tex]\overset{\huge\frown}{FD} =120[/tex]
This means that:
[tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex] are true
Hence, the true statements are: [tex]\angle EFD =\angle EGD[/tex], [tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex]
Read more about cyclic theorems at:
https://brainly.com/question/26168678
Helpppppppppppppp !!!
Answers
Answer:
a) 8
b) 2 1/4 hours
c) 4 7/8 hours
d) 4 1/8 hours
Step-by-step explanation:
a) LCD to be used to solve this problem is calculated as the Lowest common denominator of the above mixed fractions.
We have 1 1/2 hours and 1 1/8 hours
The lowest common denominator is the denominator calculated by
Multiplying the two denominators together and dividing by the common factor of the two denominators
Hence , we have
2 × 8 = 16
The common factor of 2 and 8 = 2
LCD = 16/2 = 8
b) How long did Matt drive?
We are told that Matt drove twice as long as John
John drove for 1 1/8 hours
Hence, the number of hours that Matt drove for =2 × 1 1/8
= 2 × 9/8 = 9/4 hours = 2 1/4 hours
c) How long the Sam, John and Matt drive ?
We are told in the question that
Sam drove for 1 1/2 hours
John drove for 1 1/8 hours
Matt drove for 2 1/4 hours
We would sum up the number of hours that each of them drove.
1 1/2 + 1 1/8 + 2 1/4
The Lowest common multiple of denominators is 8
= (1 + 1 + 2)( 4 + 1 +2/8)
= 4(7/8)
= 4 7/8 hours
d) How many hours is left for Bob to drive
We are told that the entire journey = 9 hours
The number of hours Sam, John and Matt drove for has been calculated in question c as 4 7/8 hours
The number of hours Bob will drive for is calculated as
9 hours - 4 7/8 hours
= 4 1/8 hours
The perimeter of the rectangle below is 74 units. Find the length of side RS
Write your answer without variables.
Answers
Answer:
20 units
Step-by-step explanation:
The perimeter of a rectangle is
P = 2(l+w)
P = 2( 3x+2 + 4x)
Adding like terms
P = 2( 7x+2)
We know the perimeter is 74 units
74 = 2 ( 7x+2)
Divide by 2
74/2 = 2/2 (7x+2)
37 = 7x+2
Subtract 2 from each side
37-2 = 7x+2-2
35 = 7x
Divide by 7
35/7 = 7x/7
5 =x
We want to find the length RS = PQ = 4x
RS = 4x = 4*5 = 20
Determine the approximate area of a sector with a central angle of 75° and a radius of 14 yards. Question 16 options: A) 9.2 yards2 B) 128.3 yards2 C) 40.8 yards2 D) 0.21 yards2
Answers
Answer:
B) 128.3 square yards
Step-by-step explanation:
A = (n/360 deg)(pi)r^2
where n = central angle of sector.
A = (75/360)(3.14159)(14 yd)^2
A = 128.3 yd^2
Answer:
B. 128.3 yards
Step-by-step explanation:
Area of a Sector Formula: A = ∅/360πr²
Simply plug in our variables:
A = 75/360(π)(14)²
A = 5π/24(196
A = 128.3