In 1990, the average duration of long-distance telephone calls originating in one town was A long-distance telephone company wants to perform a hypothesis test to determine whether the average duration of long-distance phone calls has changed from the 1990 mean of The hypotheses are:
Answer:
The null hypothesis is [tex]H_0: \mu = X[/tex]
The alternate hypothesis is [tex]H_1: \mu \neq X[/tex]
Step-by-step explanation:
Mean of X in 1990, test if the mean duration has changed:
At the null hypothesis, we test if the mean duration is still X, that is:
[tex]H_0: \mu = X[/tex]
At the alternate hypothesis, we test if the mean duration has the changed, that is, if it is different of X. So
[tex]H_1: \mu \neq X[/tex]
There are 4 red marbles and 8 blue marbles in a bag. Mark draws a blue marble out of the bag and does not replace. then jake draws another blue marble out of the bag.
Now what are the probabilities of drawing another blue marble?
NEED ANSWER ASAP PLS!!!
Answer:
Probability will be 4 by 6
Find the exact value of x.
Answer:
7[tex]\sqrt{2}[/tex] or 9.89
Step-by-step explanation:
sin45= [tex]\frac{7}{x}[/tex]
x=[tex]\frac{7}{sin 45}[/tex]
x= 7[tex]\sqrt{2}[/tex] or 9.89
The
exact solusion of the IVP
Answer:
[tex]\displaystyle y = \sqrt{2}e^{\frac{1}{2} ln|2 + x^2|}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
|Absolute Value|FunctionsFunction NotationExponential Rule [Multiplying]: [tex]\displaystyle b^m \cdot b^n = b^{m + n}[/tex]Algebra II
Logarithms and Natural LogsEuler's number eCalculus
Derivatives
Derivative Notation
Derivative of a constant is 0
Differential Equations
Separation of VariablesAntiderivatives - Integrals
Integration Constant C
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
U-Substitution
Logarithmic Integration
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y' = \frac{xy}{2 + x^2}[/tex]
[tex]\displaystyle y(0) = 2[/tex]
Step 2: Rewrite
Separation of Variables
Rewrite Derivative Notation: [tex]\displaystyle \frac{dy}{dx} = \frac{xy}{2 + x^2}[/tex][Division Property of Equality] Isolate y's: [tex]\displaystyle \frac{1}{y} \frac{dy}{dx} = \frac{x}{2 + x^2}[/tex][Multiplication Property of Equality] Rewrite Derivative Notation: [tex]\displaystyle \frac{1}{y} dy = \frac{x}{2 + x^2} dx[/tex]Step 3: Find General Solution Pt. 1
Integration
[Equality Property] Integrate both sides: [tex]\displaystyle \int {\frac{1}{y}} \, dy = \int {\frac{x}{2 + x^2}} \, dx[/tex][1st Integral] Integrate [Logarithmic Integration]: [tex]\displaystyle ln|y| = \int {\frac{x}{2 + x^2}} \, dx[/tex]Step 4: Identify Variables
Identify variables for u-substitution for 2nd integral.
u = 2 + x²
du = 2xdx
Step 5: Find General Solution Pt. 2
[2nd Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle ln|y| = \frac{1}{2}\int {\frac{2x}{2 + x^2}} \, dx[/tex][2nd Integral] U-Substitution: [tex]\displaystyle ln|y| = \frac{1}{2}\int {\frac{1}{u}} \, du[/tex][2nd Integral] Integrate [Logarithmic Integration]: [tex]\displaystyle ln|y| = \frac{1}{2} ln|u| + C[/tex][Equality Property] e both sides: [tex]\displaystyle e^{ln|y|} = e^{\frac{1}{2} ln|u| + C}[/tex]Simplify: [tex]\displaystyle |y| = e^{\frac{1}{2} ln|u| + C}[/tex]Rewrite [Exponential Rule - Multiplying]: [tex]\displaystyle |y| = e^{\frac{1}{2} ln|u|} \cdot e^C[/tex]Simplify: [tex]\displaystyle |y| = Ce^{\frac{1}{2} ln|u|}[/tex]Back-Substitute: [tex]\displaystyle |y| = Ce^{\frac{1}{2} ln|2 + x^2|}[/tex]Our general solution is [tex]\displaystyle |y| = Ce^{\frac{1}{2} ln|2 + x^2|}[/tex].
Step 6: Find Particular Solution
Substitute in point: [tex]\displaystyle |2| = Ce^{\frac{1}{2} ln|2 + 0^2|}[/tex]Evaluate |Absolute Value|: [tex]\displaystyle 2 = Ce^{\frac{1}{2} ln|2 + 0^2|}[/tex]|Absolute Value| Evaluate exponents: [tex]\displaystyle 2 = Ce^{\frac{1}{2} ln|2 + 0|}[/tex]|Absolute Value| Add: [tex]\displaystyle 2 = Ce^{\frac{1}{2} ln|2|}[/tex]|Absolute Value| Evaluate: [tex]\displaystyle 2 = Ce^{\frac{1}{2} ln(2)}[/tex][Division Property of Equality] Isolate C: [tex]\displaystyle \sqrt{2} = C[/tex]Rewrite: [tex]\displaystyle C = \sqrt{2}[/tex]Substitute in C [General Solution]: [tex]\displaystyle y = \sqrt{2}e^{\frac{1}{2} ln|2 + x^2|}[/tex]∴ Our particular solution is [tex]\displaystyle y = \sqrt{2}e^{\frac{1}{2} ln|2 + x^2|}[/tex].
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Differential Equations
Book: College Calculus 10e
Randy wants to save $21 to buy a basketball he saved $7 each week which array represents the number of weeks randy needs to save $21
Answer:
he will have to save $7 for 3 weeks to get $21
Step-by-step explanation:
help will give brainliest
Answer:
25 -2
Step-by-step explanation:
Fat Kat's offers a special on large two topping pizzas. In how many different ways can you order a two topping pizza if you can choose from 18 toppings? NO LINKS!!!
=======================================================
Explanation:
There are 18 ways to pick the first topping and 18-1 = 17 ways to pick the next topping. Picking the same topping again doesn't make much sense (though I suppose it could mean that you just want more of that topping than usual?), so that's why we have the 18 drop to 17 when making that second selection.
If the order of toppings mattered, then we'd have 18*17 = 306 permutations. However, the order of toppings doesn't matter. All that matters is the group rather than the individual toppings. When counting out the 306 permutations, we've overcounted by a factor of 2. In other words, we've double counted.
So we must divide by 2 to fix this double count. That leads to 306/2 = 153 combinations
------------------------
The alternative method involves using the nCr combination formula
Use n = 18 and r = 2 in this formula
[tex]_n C _r = \frac{n!}{r!*(n-r)!}[/tex]
the exclamation marks indicate factorial.
WILL GIVE U BRAINLIEST
ABCD is a rectangle. AB = x + 7, BC = 2x + 19. What is the CD?
A. 2x + 133
B. X + 7
C. 5x + 38
D. 2x + 14
Answer:
A rectangle has its Opposite sides Equal.
Draw one so you'd grab it better.
AB=CD
BC= AD
Since CD=AB and We're given AB=x+7...
CD = x + 7
OPTION B IS LEGIT!!
Question 3 of 10
Classify the following triangle. Check all that apply.
+ 1200
D A. Isosceles
DB. Obtuse
C. Acute
D. Scalene
O E. Right
DF. Equilateral
SUBMIT
Answer: A B
Step-by-step explanation: I need one more brainliest for next rank I’d appreciate it
Anna bought 3 types of fruit for a fruit salad. She paid three times as much for blueberries as for pears and $2.50 less for strawberries than for blueberries.
If The total cost was $13.25 how much did Anna spend on each type of fruit
Answer:
Anna spent $ 2.25 on pears, $ 6.75 on blueberries, and $ 4.25 on strawberries.
Step-by-step explanation:
Given that Anna bought 3 types of fruit for a fruit salad, and she paid three times as much for blueberries as for pears and $ 2.50 less for strawberries than for blueberries, if the total cost was $ 13.25, to determine how much did Anna spend on each type of fruit, the following calculation must be performed:
Pears: X
Blueberries: 3X
Strawberries: 3X - 2.5
X + 3X + 3X - 2.5 = 13.25
7X = 13.25 + 2.5
X = 15.75 / 7
X = 2.25
Pears: 2.25
Blueberries: 3 x 2.25 = 6.75
Strawberries: 3 x 2.25 - 2.50 = 6.75 - 2.50 = 4.25
2.25 + 6.75 + 4.25 = 13.25
Therefore, Anna spent $ 2.25 on pears, $ 6.75 on blueberries, and $ 4.25 on strawberries.
PLS HELP ASAP!! need the answer
Answer:
60 degrees
Step-by-step explanation:
A kite is formed by an equilateral triangle with sides 6 cm and an isosceles triangle with legs 5 cm. Find the area of the kite.
Answer:
The area of the kite is 27.6 cm²
Step-by-step explanation:
Given;
dimension of the equilateral triangle, = 6 cm
dimension of the isosceles triangle = 5 cm
Please check the image uploaded for a detailed solution.
An archeologist is digging at a former lake and finds items at the following elevations.
Place the items in order from highest elevation to lowest
________________________________________________
Write the elevation where each item was found as a positive or negative integer:
Arrowhead = _______ feet
Fishbone = ______ feet
Fish Hook = _______ feet
Fossil = _______ feet
Pottery = _______ feet
Shell = ________ feet
Answer:
Fossil > Arrow Head > Pottery > Shell > Fishbone > Fish Hook
Step-by-step explanation:
Arrowhead = ___20___ feet
Fishbone = __-10___ feet
Fish Hook = ___-40__ feet
Fossil = __30___ feet
Pottery = ___10___ feet
Shell = ____0___ feet
If something is above sea level, it would have a positive elevation, and if below sea level, a negative elevation. And at sea level, you have 0 elevation.
After this, just put them in order of decreasing elevation. So, the highest elevation is 30ft with the fossil, then 20 with the arrow head, pottery at 10, shell at 0, fishbone at -10, fish hook at -40.
doctors use gallium in scanning some patients for diseases the table shows the amount of gallium in mg remaining in a patients system after t hours which exponential function best represents the data.
Step-by-step explanation:
no sn as. kojsshsusishheidhsusjjsbsbshsbsjs7ehsjsnkosvsjsishshshsjdjjddyfygyvrcudjdhdudhsjsudhdjs
work out the area of this circle. take pi to be 3.142 and give your answer to be 2 decimal places. 11,2 cm
Answer:
11.2 i think so but you will write 11.2
Suppose N in L(V) is nilpotent. Prove that the minimal polynomial fo N is z^m+1, where m is the length of the longest consecutive strong of 1st that appears on teh line directly aoce the diagonal in teh matrix of N with respect to any jordan basis for N.
Answer: your question is poorly written attached below is the complete and well written question
answer : The minimal polynomial has degree m + 1 hence Z^m+1
Step-by-step explanation:
Given that
N ∈ L(V) is nilpotent
attached below is the required prove
What is the range of y= sec-'(x)? PreCal, send help please!!
Given:
The function is:
[tex]y=\sec^{-1}(x)[/tex]
To find:
The range of the given function.
Solution:
We have,
[tex]y=\sec^{-1}(x)[/tex]
The range of secant inverse function is:
[tex]Range=\{y|0\leq y\leq \pi , y\neq \dfrac{\pi}{2}\}[/tex]
The range of the given function in interval notation is:
[tex]Range=\left[0,\dfrac{\pi}{2}\right)\text{ and }\left( \dfrac{\pi}{2}, \pi\right ][/tex]
Therefore, the correct option is C.
PLEASE HELP!!
Write an equation for the
line on the graph below:
Answer:
x =-1 i think
Step-by-step explanation:
Answer:
x = -1
This is because all values of x is -1 no matter the y value
Feel free to mark this as brainliest :D
Express 5 cm in metre and kilometre.in decimals........................
Answer:
0.05 metre
5×10^5 kilometer
1.9685
Jill bought 3 boxes of ice pops. Each box contains 4 orange ice pops and some cherry ice pops. The number of cherry ice pops in each box was the same. Jill bought 36 ice pops in all. What are the 2 steps of this equation and how many cherry ice pops are in each box?
Answer: 9 cherry ice pops
Step-by-step explanation:
if you bought 3 boxes and there is four orange one in each pack the that is
12 and 36 divided by 4 is 9 so there is 9 cherry ice pops
Please help me I am super confused I would really appreciate it ♥️♥️
will give brainliest
Answer:
respuesta 0.2
Step-by-step explanation:
espero que te sirvan ( ꈍᴗꈍ)
if the simple interest on $1000 for 10 years is $400, then what is the interest rate?
(1 point) Some shrubs have the useful ability to resprout from their roots after their tops are destroyed. Fire is a particular threat to shrubs in dry climates, as it can injure the roots as well as destroy the aboveground material. One study of resprouting took place in a dry area of Mexico. The investigation clipped the tops of samples of several species of shrubs. In some cases, they also applied a propane torch to the stumps to simulate a fire. Of 16 specimens of a particular species, 7 resprout after fire. Estimate with 99% confidence the proportion of all shrubs of this species that will resprout after fire.
Answer:
The answer is "[tex]0.45 \pm 0.18204[/tex]"
Step-by-step explanation:
For the +4 sample proportion[tex]= \frac{(7+2)}{(16+4)} = \frac{9}{20} = 0.45[/tex]
Sample percentage measurements estimated stdev
[tex]= \sqrt{\frac{[(0.45)(1-0.45)]}{[(16+4)]}}\\\\ = \sqrt{\frac{[(0.45)(0.55)]}{[(20)]}}\\\\ = \sqrt{\frac{0.2475}{20}}\\\\= \sqrt{0.012375}\\\\=0.111[/tex]
Calculating the critical z for a=0.1, two-tailed = 1.64
Calculating the confidence interval:
[tex]= 0.45 \pm 0.111 \times 1.64 \\\\= 0.45 \pm 0.18204[/tex]
Please I need it now
A rational number is terminating decimal, if its denominator has
no prime factor other than:
A. 2 and 3 B. 3 and 5 C. 2 and 5 D. 2 and 7
Answer:
it's C. 2 and 5...
Step-by-step explanation:
If the denominator of rational number contains no prime factors other then 2 or 5 or both, then this rational number can be expressed as terminating decimal. So the correct answer is option is C
What is the volume of a sphere with a surface area of 25pi / (d ^ 2)
Answer:
B. [tex] \frac{125}{6}* \pi [/tex] yd³
Step-by-step explanation:
Given:
Surface area of a sphere = 25π yd²
Required:
Volume
Solution:
Let's find the radius (r) first.
S.A of sphere = 4πr²
Substitute
25π = 4πr²
Divide both sides by 4π
25π/4π = r²
25/4 = r²
Take the square root of both sides
√25/√4 = r
5/2 = r
r = 5/2 yd
Find the Volume of the sphere
V = ⁴/3*πr³
V = ⁴/3*π*(⁵/2)³
V = ⁴/3*π*125/8
V = ⅓*π*125/2
V = [tex] \frac{1*125}{3*2}* \pi [/tex]
V = [tex] \frac{125}{6}* \pi [/tex] yd³
What is the Area of the parallelogram?
Answer:
117 sq in
Step-by-step explanation:
fx= ab*2÷t*2, make t the subhect of the formulae
[tex]fx = ab { }^{2} \div t {?}^{2} [/tex]
Answer:
t = √ab²/fx
Step-by-step explanation:
fx= ab*2÷t*2, make t the subject of the formulae
Given the function
fx = ab²/t²
We are to make t the subject of the formula
fxt² = ab²
t² = ab²/fx
Take the square root of both sides
√t² = √ab²/fx
t = √ab²/fx
Hence the required value of t is √ab²/fx
Round off 54951 to the nearest 10,000.
Answer 50,000
Step-by-step explanation:
16 meters of rope, i want to cut pieces of rope 0.2meters long. how many pieces can cut?
Answer:
80
Step-by-step explanation:
because 16 decided by 0.2 is 80
hope this helps!!!!