Which type of electromagnetic radiation had a lower frequency than infrared radiation

Answer:

5.23 moles

Explanation:

How many moles of iron are present in 3.15 × 10^24 atoms of iron?

1 mole has 6.02 X 10^23 particles

so

3.15X10^ 24 atoms =( 3.15 X 10^24)/(6.02 X 10^23) =(3.15/6.02 )X 10 =

5.23 moles

The mass of PbI2 produced from a trace amount of 630mL of 0.268M KI solution is 39.2 g.

The equation of the reaction is; 2KI(aq)+Pb(NO3)2(aq) → PbI2(s) + 2KNO3(aq)​

From the question, number of moles of KI = 630/1000 L × 0.268M = 0.169 moles

Now;

2 moles of KI is required to precipitate 1 mole of PbI2

0.169 moles of KI is required to precipitate 0.169 moles × 1 mole/2 moles

= 0.085 moles

Mass of PbI2 = Number of moles of PbI2 × Molar mass

Mass of PbI2 = 0.085 moles × 461.01 g/mol

Mass of PbI2 = 39.2 g

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Answer: A

Explanation:

Answer:

B. The ballon will repel the paper

Answer:

It is classified as a metal and is expected to be solid at room temperature.

Explanation:

not sure but i guess it is that

Answer:

Bohr model A

Explanation:

It has more valance electrons therefore has more interaction between the atoms and has more electronegativity.

Answer: if it’s a multiple choice then it should be swing dances

Explanation:While the majority of swing dances began in African American communities as vernacular African American dances, some influenced swing-era dances, like Balboa, developed outside of these communities.

Answer:

its that DDDDDD

Explanation:

i know this because its that DDDDDDDD

Answer:

May I assume "ethanol acid is just ethanol (it has one slightly acidic H atom).  If so, the molar mass is 46.02 g/mole.

Explanation:

We have 30 cm^3 [30 ml] of 1.0 M (1 mole/liter)  [1 dm³ = 1 liter].

That is 1 mole/liter.  30 ml would contain (0.030 liter)*(1 mole/1 liter) = 0.03 moles.

Answer:

0.0866 M

Explanation:

answer key

The molarity of the NaOH solution has been 0.0865 M.

The neutralization reaction of the Phosphoric acid and NaOH results in the formation of sodium phosphate and water.

The balanced chemical equation can be given as;

[tex]\rm H_3PO_4\;+\;3\;NaOH\;\rightarrow\;Na_3PO_4\;+\;3\;H_2O[/tex]

Thus for the neutralization of 1 mole of Phosphoric acid, 3 moles of NaOH has been used.

The moles of phosphoric acid in 0.100 grams sample:

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of phosphoric acid = [tex]\rm \dfrac{0.100}{99}[/tex]

Moles of phosphoric acid = 0.001 mol

For the neutralization of 0.001 moles of NaOH:

1-mole Phosphoric acid = 3 moles NaOH

0.001-mole Phosphoric acid =0.003 moles of NaOH.

The molarity of the NaOH solution:

Molarity = [tex]\rm \dfrac{moles}{Volume\;(L)}[/tex]

Molarity of NaOH = [tex]\rm \dfrac{0.003}{0.035}[/tex]

Molarity of NaOH = 0.0865 M

The molarity of the NaOH solution has been 0.0865 M.

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Answer:

B

Explanation:

new oceanic crust will form.

The formation of a new oceanic crust will be the primary result of the continuation of the geologic processes. Therefore, option (B) is correct.

The oceanic crust can be described as the uppermost layer of the oceanic portion of the tectonic plates. The oceanic crust is composed of the upper oceanic crust, with pillow lavas complex, and the lower oceanic crust, made of troctolite, and ultramafic cumulates.

The oceanic crust lies above the rigid uppermost layer of the mantle. The crust and the rigid upper mantle layer together compose the oceanic lithosphere.

The oceanic crust is rich in iron and magnesium and composed of mafic rocks. It is thinner than the continental crust less than 10 Km thick but it is denser with 3.0 g/cm³ as opposed to the continental crust.

The oceanic crust displays a symmetrical pattern of positive and negative magnetic lines emanating from the mid-ocean ridge.

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Answer:

36 eggs

Explanation:

12 eggs in each carton

12 + 12 + 12 = 36 eggs

or 3 * 12 = 36 eggs

Hope this helps, have a nice day/night! :D

Answer:

Must be stable and relatively insoluble in boiling water.

Explanation:

it must be stable and relatively insoluble in boiling water and a must-have vapor pressure in boiling water that is of the order atmosphere at or more compound satisfy these conditions that will generally not separate from each other but we'll be separated from everything else.

Answer:

when you pray you will feel a peace and happiness in your heart

Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, you know:

Replacing:

2 atm× V = 4.745 moles× 0.082[tex]\frac{atmL}{molK}[/tex]× 353 K

Solving:

V = (4.745 moles× 0.082[tex]\frac{atmL}{molK}[/tex]× 353 K)÷ 2 atm

V= 68.67 L

Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

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This problem is providing the ionic radius of an anion, A²⁻ as 0.290 nm and asks for that of the cation A²⁺ in comparison to the former.

Firstly, we need to recall the concept of ionic radius, as the distance between the nucleus and the outermost electron shell of an ion. In such a way, we can have two scenarios:

1. Anions result from the gain of electrons exhibited by a nonmetal, which means they turn out bigger than the neutral atom.

2. Cations result from the loss of electrons exhibited by a metal, which means they turn out smaller than the neutral atom.

With the aforementioned, we infer that the cation A²⁺, will me smaller than the anion A²⁻, which means it will have an ionic radius smaller than 0.290 nm.

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Answer:

hiroghlipical

Explanation:

new word i just made

Answer:

D. Na has a larger radius than Na+ because Na+ has lost its outermost energy shell.

Explanation:

The radius is larger because the diameter of Na+ is larger.

Sodium has smaller atomic  radius than sodium cation because sodium has expanded electron cloud.

Atomic radius is defined as the  distance between outermost shell and the nucleus. Atomic radius varies across the periodic table where in groups it increases due to the fact that new shells are added on moving sown the group.

While in a period it decreases from left to right across the periodic table as electrons are added to the same shell which causes contraction of the atom.In case of comparison between an atom and a cation an atom has smaller atomic radius due to presence of electrons while in case of ions atomic radius is smaller as they have less number of electrons.

Atoms have expanded electron cloud while the electron cloud in case ions is small , the reason being the presence of large number of electrons in case of atoms and less number of electrons in case of ions.

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Answer:

Test answers

1. Water carving out a limestone cave

2. Oxidation

3. Acid rain

(Got 100%)

Explanation:

The primary agents of chemical weathering are water, oxygen and acids. So acid rain is an agent of chemical weathering. Option C is correct.

Water, and many chemical compounds found in water, is the main agent of chemical weathering.  One of the most abundant rock-forming minerals, chemically reacts with water and water-soluble compounds to form clay.

Water contains many weak acids such as carbonic acid. The primary agents of chemical weathering are water, oxygen and acids.

These react with surface rocks to form new minerals that are stable in, or in equilibrium with, the physical and chemical conditions present at the earth's surface.

Hence, option C is correct.

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Answer:

Explanation:

The wavelength of a wave can be found by using the formula

[tex]\lambda = \frac{c}{f} \\[/tex]

where

c is the speed of the wave

f is the frequency

From the question

c = 5 m/s

f = 2.5 Hz

We have

[tex] \lambda = \frac{5}{2.5} = 2 \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

some example includes:

gold, copper, oxygen, chlorine, diamond

Explanation:

Answer:

that is impossible. the atomic number can only go up each group

Answer:

Birds can sit on power lines and not get electric shocks because the electricity is always looking for a way to get to the ground. The birds are not touching the ground or anything in contact with the ground, so the electricity will stay in the power line.

Pls mark as brainliest answer if it helps you

Answer:

Explanation:

Im sorry all i know is that #3 is for sure combustion

Answer:

C

Explanation:

No reaction because not enough moles of silver are present for the reaction to occur.

Answer:  E

1

−

E

4

=

Δ

E

=

−

2.18

×

10

−

18

J

(

1

n

2

f

−

1

n

2

i

)

=

−

2.18

×

10

−

18

J

(

1

1

2

−

1

4

2

)

=

−

2.18

×

10

−

18

J

(

15

16

)

=

−

2.04

×

10

−

18

J

After you obtain the energy, then you can realize that that energy has to correspond exactly to the energy of the photon that came in:

|

Δ

E

|

=

E

photon

=

h

ν

=

h

c

λ

where  

h

is Planck's constant,  

c

is the speed of light, and  

λ

is the wavelength of the incoming photon. Thus, the wavelength is:

⇒

λ

=

h

c

E

photon

=

(

6.626

×

10

−

34

J

⋅

s

)

(

2.998

×

10

8

m/s

)

2.04

×

10

−

18

J

=

9.720

×

10

−

8

m

=

97.20 nm

Explanation:

The heat of vaporization of aluminium at 25 °C is 315.8 kilojoules per mole.

The sublimation is the phase change of a substance from solid to gas, the fusion is the phase change of a substance from solid to liquid and the vaporization is the phase change of a substance from liquid to gas. The heat of vaporization is the difference between the heat of sublimation and the heat of fusion, that is to say:

[tex]h_{v} = 326.4\,\frac{kJ}{mol}-10.6\,\frac{kJ}{mol}[/tex]

[tex]h_{v} = 315.8\,\frac{kJ}{mol}[/tex]

The heat of vaporization of aluminium at 25 °C is 315.8 kilojoules per mole.

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