Which two statements describe organ systems working together to bring
oxygen to cells?
O A. Blood vessels carry oxygen from the lungs to the heart.
B. Cells use oxygen to turn nutrients from food into energy.
C. The lungs allow oxygen from the air to enter the blood.
D. The brain monitors the level of oxygen in arteries.

Answer:

1.44 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of HCl = 0.06 mole

Mass of Mg =?

From the question given above, we discovered the number of mole of HCl is equivalent to the number of mole of Mg. Thus,

Number of mole of Mg = number of mole of HCl

Number of mole of Mg = 0.06 mole

Finally, we shall determine the mass of Mg. This can be obtained as follow:

Number of mole of Mg = 0.06 mole

Molar mass of Mg = 24 g/mol

Mass of Mg =?

Mass = mole × molar mass

Mass of Mg = 0.06 × 24

Mass of Mg = 1.44 g

Therefore, the mass of magnesium is 1.44 g

Answer: C3H8 + 5O2 = 3Co2 +4H2O

Explanation: Equations must be balanced

You must have the same amount of C

H and O on both sides of the equation

Answer:

I think it's B. The ability of water molecules to adhere to the surfaces of objects

Answer:

The activated complex

Explanation:

The activated complex are the species that exists maximum in every energy profile of a reaction.

Activated complex is nothing but an intermediate state of reactants formed during its conversion from a reactant to product state in coarse of reaction.

The activated complex is formed at the maximum energy level in the reaction path. And this difference between energy of the activated complex and the energy of the reactants is only known as activation energy

The final temperature of the gas is 269.9 K, or -3.25 °C, which was calculated with the help of ideal gas equation.

The ideal gas equation gives the relation between pressure, volume and temperature.

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

To find the initial volume of the gas. We can use the fact that the number of moles of gas does not change during the cooling process:

n = 0.850 moles

We can also use the ideal gas law to find the initial volume of the gas:

PV = nRT

V = nRT/P

where R = 0.08206 L atm/K mol is the gas constant.

Convert the initial temperature from Celsius to Kelvin:

T1 = 85 °C + 273.15 = 358.15 K

Substitute the given values into the equation:

V₁ = (0.850 mol)(0.08206 L atm/K mol)(358.15 K)/(1 atm) = 24.03 L

Now we can use the combined gas law to find the final temperature:

(P₁V₁/T₁) = (P₂V₂/T₂)

Substitute the given values into the equation:

(1.25 atm)(24.03 L)/(358.15 K) = (P₂) (17.55 L)/(T2)

Solve for T₂:

T₂ = (P₂)(17.55 L)(358.15 K)/(1.25 atm)(24.03 L)

T₂ = 269.9 K

Therefore, the final temperature of the gas is 269.9 K, or -3.25 °C.

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Answer:

1280.5g

Explanation:

Answer:

[tex]\frac{250}{3}[/tex]

Explanation:

you can expect to get a 3 (theoretically) 1 time every 6 times you roll. A 1/6 chance.

Here's the equation:

[tex]\frac{1}{6} =\frac{x}{500}[/tex]

cross multiply (i think that's what it is called)

500=6x

divide by 6 on both sides:

x=[tex]\frac{250}{3}[/tex] or approx 83 times.

Hope this helps! Lmk if u have more questions <3

50500Nm^2 or 5.05Nm^2

Explanation:

so bring out the parameters

p1= 0.12dm3, T1= 60c , because temperature is in kelvin add 273= 333k, v1= 0.12dm3 , T2= to the same value because the temperature didn't change = 333k, v2= 0.24dm3,P2= ?

general gas equation p1v1 over T1 = P2V2 over T2, when you input everything or make p2 the subject of the formula first you'll get the answer, pressure can have an s.i unit of mmhg but I'm using the same si unit as the question given and always check your units in the question to convert. please if this question has options please check, I don't want you to fail so verify from others if I made a mistake

Answer:

316.227766

Explanation:

Answer:

It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top

Explanation:

Answer:

I dont know

Explanation:

good luck

Answer:

D Both are made of rock ,ice and solar dust from the beginning of the solar system

Answer:

The answer is D

Explanation:

Answer:

An atom with one or two valence electrons more than a closed shell The number of valence electrons of an element can be determined Groups 3-12 (transition metals), 2* (The 4s shell is complete and cannot hold any more electrons)  in explaining the molecular structure of many organic compounds.

Explanation:

The 3.13 g of K would be needed to completely react with the remaining [tex]Cl_2[/tex].

To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.

The balanced chemical equation for the reaction between solid potassium and chlorine gas is:

2 K(s) + [tex]Cl_2[/tex](g) -> 2 KCl(s)

From the equation, we can see that 2 moles of K react with 1 mole of [tex]Cl_2[/tex] to form 2 moles of KCl.

First, we need to convert the masses of K and [tex]Cl_2[/tex] into moles:

moles of K = 15.20 g / 39.10 g/mol = 0.388 mol

moles of [tex]Cl_2[/tex] = 2.830 g / 70.90 g/mol = 0.040 mol

Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:

Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl

Theoretical yield of KCl from [tex]Cl_2[/tex]: 0.040 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) = 0.080 mol KCl

We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from [tex]Cl_2[/tex] is 0.080 mol. Therefore, the limiting reactant is [tex]Cl_2[/tex], since it produces less product.

To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.

We know that 1 mole of [tex]Cl_2[/tex] reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining [tex]Cl_2[/tex] can be calculated as follows:

moles of K needed = 0.040 mol [tex]Cl_2[/tex] x (2 mol K / 1 mol [tex]Cl_2[/tex])

                                = 0.080 mol K

This means that 0.080 moles of K would be needed to completely consume the remaining [tex]Cl_2[/tex]. We can convert this to a mass by multiplying by the molar mass of K:

mass of K needed = 0.080 mol K x 39.10 g/mol

                              = 3.13 g K

Therefore, The 3.13 g of K would be needed to completely react with the remaining.

Example verification:

Suppose we had an additional 0.50 g of [tex]Cl_2[/tex] in the reaction. Would all of the K be consumed, or would there still be excess K?

Moles of additional [tex]Cl_2[/tex] = mass of [tex]Cl_2[/tex] / molar mass of [tex]Cl_2[/tex]

Moles of additional [tex]Cl_2[/tex] = 0.50 g / 70.90 g/mol

Moles of additional [tex]Cl_2[/tex] = 0.0070 mol

The theoretical yield of KCl that can be formed from the additional [tex]Cl_2[/tex] is:

0.0070 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl

Therefore, the total amount of KCl that can be formed from all of the [tex]Cl_2[/tex] is:

5.95 g + 1.04 g = 6.99 g

The amount of K that would be needed to completely consume all of the [tex]Cl_2[/tex].

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Answer:

(J) All organisms are composed of cells

Explanation:

The number of moles of Al2O3 formed is approximately 4.25 moles. Second find the limiting reactant. Since O2 has less value that is 2.126 than Al that is 2.287, O2 is the limiting reactant in this reaction.

Answer:

2.39 atm

Explanation:

We'll begin by calculating the number of mole in 0.41 g of neon (Ne). This can be obtained as follow:

Mass of Ne = 0.41 g

Molar mass of Ne = 20 g/mol

Mole of Ne =.?

Mole = mass / molar mass

Mole of Ne = 0.41 / 20

Mole of Ne = 0.0205 mole

Next we shall convert 200 mL to L.

1000 mL = 1 L

Therefore,

200 mL = 200 mL × 1 L / 1000 mL

200 mL = 0.2 L

Next, we shall convert 11 °C to Kelvin temperature.

T(K) = T(°C) + 273

T(°C) = 11 °C

T(K) = 11 + 273

T (K) = 284 K

Finally, we shall determine the pressure. This can be obtained as follow:

Mole of Ne (n) = 0.0205 mole

Volume (V) = 0.2 L

Temperature (T) = 284 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 0.2 = 0.0205 × 0.0821 × 284

P × 0.2 = 0.4779862

Divide both side by 0.2

P = 0.4779862 / 0.2

P = 2.49 atm

Therefore, the pressure of the gas is 2.39 atm

Covalent bonding involving covalent bonds is depicted between these two atoms as they form diatomic molecule.

Covalent bond is defined as a type of bond which is formed by the mutual sharing of electrons to form electron pairs between the two atoms.These electron pairs are called as bonding pairs or shared pair of electrons.

Due to the sharing of valence electrons , the atoms are able to achieve a stable electronic configuration . Covalent bonding involves many types of interactions like σ bonding,π bonding ,metal-to-metal bonding ,etc.

Sigma bonds are the strongest covalent bonds while the pi bonds are weaker covalent bonds .Covalent bonds are affected by electronegativities of the atoms present in the molecules.Compounds having covalent bonds have lower melting points as compared to those with ionic bonds.

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Answer:

3.0 g

Explanation:

The total mass at the beginning of the reaction is:

Following the law of conservation of mass, this same mass has to be present once the reaction is complete. This means that the mass diference between the contents of the reaction vessel after the reaction and the mass at the beginning of the reaction is the mass of released carbon dioxide:

Answer:

A

Explanation:

Law of conservation of matter

Answer:

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Explanation:

When

H2O2 acts as an oxidizing agent

H2O2 + 2e- 2H+--->   2H2O

Reducing agent

H2O2 --> O2 + 2e + 2H+

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Answer:

See EXPLANATION

Explanation:

We must bear in mind that in balancing chemical reaction equations, the number of atoms of each element on the right hand side must be the same as the number of atoms of the same element on the left hand side of the reaction equation. This follows from the law of conservation of mass.

Based on this;

There are two oxygen atoms on the  left hand side of the reaction equation, thus total mass of oxygen = 2 * 16 amu = 32 amu

There are two oxygen atoms on the product side of the reaction equation, thus the total mass of oxygen = 2 * 16 amu = 32 amu

Answer:

Benzene shows that it is actually unsaturated because it adds hydrogen or chlorine, although only when allowed to react under very vigorous conditions (higher temperature or pressure) compared to those required for alkenes and alkynes.

Explanation:

Answer:

what is the volume of the water at 307 k?

Answer:

[tex]3Mn_2(CO_3)_5+5Ni_3(PO_3)_2\rightarrow 15NiCO_3+2Mn_3(PO_3)_5[/tex]

Explanation:

Hello there!

In this case, for the given reactants side in this chemical reaction, it is possible for us to firstly write the left side of the undergoing chemical equation as shown below:

[tex]Mn_2(CO_3)_5+Ni_3(PO_3)_2\rightarrow NiCO_3+Mn_3(PO_3)_5[/tex]

Which means that the products are nickel (II) carbonate and manganese (V) phosphite. Next, we balance the reaction as shown below:

[tex]3Mn_2(CO_3)_5+5Ni_3(PO_3)_2\rightarrow 15NiCO_3+2Mn_3(PO_3)_5[/tex]

Which makes 15 carbonate ions, 10 phosphite ions, 15 nicked (II) ions and 6 manganese (V) on both sides of the chemical equation.

Best regards!

Answer:

Radioactive decay is a random event.

Explanation:

on edge

Answer:

Radioactive decay is a random event.

Explanation:

Edge 2020

Answer:

Isotopes

Explanation:

iso means the same like in triangles (isosceles) so the atoms are the same element but different in mass. Since the isotopes have the same number of protons and electrons the isotopes have much the same chemical behavior. Since the isotopes have different numbers of neutrons the nuclear behavior differs.

Answer:

258.71 dm³

Explanation:

We'll begin by calculating the number of mole of O₂ produced by the decomposition of 12 moles of KClO₃. This can be obtained as follow:

The balanced equation for the reaction is given below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Therefore, 12 moles of KClO₃ will decompose to produce = (12 × 3)/2 = 18 moles of O₂.

Finally, we shall determine the volume of the O₂. This can be obtained as follow:

Temperature (T) = 325 K

Pressure (P) = 188 KPa

Number of mole (n) = 18 moles

Gas constant (R) = 8.314 KPa.dm³/Kmol

Volume (V) =?

PV = nRT

188 × V = 18 × 8.314 × 325

188 × V = 48636.9

Divide both side by 188

V = 48636.9 / 188

V = 258.71 dm³

Thus, 258.71 dm³ of oxygen were obtained from the reaction.

Answer:

2.09 atm

Explanation:

Step 1: Given and required data

We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.

Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

60.0 g × 1 mol/44.01 g = 1.36 mol

Step 3: Calculate the partial pressure of CO₂

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T/ V

P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm

The partial pressure of [tex]\rm CO_2[/tex] in 25 L fuel combustion vessel has been 2.09 atm.

From the ideal gas equation:

PV =nRT

P= partial pressure

V = volume = 25 L

n = moles of carbon dioxide

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{60}{44}[/tex] mol

Moles of [tex]\rm CO_2[/tex] = 1.36 mol

R = constant = 0.0821 atm.L/mol.K

T = temperature in Kelvin =  468.2 K

Partial pressure of [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{1.36\;\times\0.0821\;\times\;468.2}{25}[/tex]

Partial pressure of [tex]\rm CO_2[/tex] = 2.09 atm.

The partial pressure of [tex]\rm CO_2[/tex] in 25 L fuel combustion vessel has been 2.09 atm.

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