Answer:
a,c,b
Explanation:
What is the ph of a HCl solution with a concentration of 2.51x10^-5M
Answer:
pH = 4.6
Explanation:
As hydrochloric acid (HCl) is a strong acid, the molar concentration of H⁺ species is the same as the molar concentration of the HCl solution. In other words:
[H⁺] = 2.51x10⁻⁵ MWith the information above in mind we can calculate the pH:
pH = -log[H⁺]pH = -log(2.51x10⁻⁵ M)pH = 4.6How many moles of Oxygen atoms are contained in 45.9 mol CO2?
Answer:
Explanation:
10 moles of oxygen atoms.\ \textbf{b)} 91.8 moles of oxygen at
To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. (Hint: be sure to work the problem with both PbS and O2).
Answer: 2.20 g Pb
They gave us the masses of two reactants and asked us to determine the mass of the product. We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 239.27 32.00 207.2
2PbS + 3O₂ ⟶ 2Pb + 2SO₃
m/g: 2.54 1.88
what is the percent composition of calcium fluoride
Answer:
78.07
Explanation:
them seperatly is
Calcium Ca 51.333%
Fluorine F 48.667%
What is the IUPAC name for the following compound?
a. benzenecarbonitrile
b. benzenecyanide
c. phenylcyanide
d. cyanophenyl
Answer:
Option a. Benzenecarbonitrile
Explanation:
You are not providing the picture of the compound. However, I manage to find the picture of it, so I'm gonna answer this with the picture. Its attached here at the end.
As for the IUPAC name of this compound, it would be Benzenecarbonitrile, or simply, benzonitrile.
This compound has the molecular formula C₆H₅CN. It receives this name over the other ones, because this is a aromatic cyanide, and aromatic cyanide has nitriles behavior, (Strength of the nitrogen over the carbon), therefore, this group has priority over the whole molecule. As the principal chain is the benzene, the carbonitrile is the radical of the group, and when cyano groups are as radical and not as principal chains, it has a behavior of nitrile, and it's named as nitrile. therefore, option b, cannot be the name.
phenylcyanide is naming the phenyl as radical, but the benzene is the principal group in this compound, and the cyanide is the radical. It happens the same thing with cyanophenyl.
Hope this helps
A helium-filled balloon contains 0.16 mol He at 101 kPa and a temperature of 23°C. What is
the volume of the gas in the balloon?
V = 3.9 L
Explanation:
Given:
T = 23°C + 273 = 296K
n = 0.16 mol He
P = 101 kPa = 0.997 atm
R = universal gas constant = 0.08205 L-atm/mol-K
V = ?
Using the ideal gas law,
PV = nRT
V = nRT/P
= (0.16 mil He)(0.08205 L-atm/mol-K)(296K)/(0.997 atm)
= 3.9 L
What is the percent yield of a reaction producing 26g Iridium V Sulfate from 30g Lithium Sulfate and 30g Iridium V Carbonate?
When 1 mol of a nonvolatile, nondissociating solute is dissolved in 3 mol of volatile solvent, the ratio of vapor pressure of the solution to that of the pure solvent (at the same temperature) is approximately:________
Answer:
[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]
Explanation:
Hello there!
In this case, since the solvation of a nonvolatile-nondissociating solute in a volatile solvent is modelled via the Raoult's law:
[tex]P_{solution}=x_{solvent}P_{solvent}^{vap}[/tex]
Thus, we can calculate the ratio of the vapor pressure of the solution to that of the pure solvent, mole fraction, as shown below:
[tex]x_{solvent}=\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{n_{solvent}}{n_{solute}+n_{solvent}}[/tex]
Thus, we plug in the moles of solvent and solute to obtain:
[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{3}{3+1}\\\\ \frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]
Regards!
A sample of dry gas is found to occupy 3.650 L at 22.0°C and 740.0 mmHg. How many moles of gas are present?
will mark brainliest
Answer:
0.147
Explanation
PV/RT
can someone answer this
concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature (a) what volume (mL) of this solution is needed to make a 1.00L solution of 1.00M phosphoric acid?
Answer:
82.0 mL
Explanation:
Step 1: Given data
Concentration of concentrated acid (C₁): 12.2 MVolume of concentrated acid (V₁): ?Concentration of dilute acid (C₂): 1.00 MVolume of dilute acid (V₂): 1.00 LStep 2: Calculate the required volume of the concentrated acid
We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated acid using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 1.00 M × 1.00 L / 12.2 M = 0.0820 L = 82.0 mL
Which best describes the total mass of substances before and after a
combustion reaction?
A. The mass is the same because atoms are not created or
destroyed.
B. The mass is greater after the reaction because the number of
atoms increases.
C. The mass is the same because the molecules do not change.
D. The mass is less after the reaction because gases are produced.
Answer:
B. The mass is greater after the reaction because the number of
atoms increases.
Read about reverse osmosis and multistage flash distillation .Then identify at least three advantages and three
disadvantages for each process
Answer:
Meaning, Advantages & Disadvantages of - Osmosis, Multiflash Distillatiob
Explanation:
Osmosis is movement of solvent (like water) through semi permeable membrane (like living cell) into solution of higher solute concentration.Advantages - It assists equalising concentration of solute on two sides of membrane. Reverse Osmosis is used for efficient water softening, it is easy to maintain.
Disadvantages - It needs a lot of energy. A lot of pressure is required for deionisation. Water acidity level increases, as minerals get deionised.
Multistage flash distillation refers to desalination water distilling seawater, by flashing water portions in steams in various stages of concurrent heat exchangers.Advantages - Its Cost efficient , distillation uses waste heat. It has High gain output ratio. Quality of feedwater is less significant, compared to reverse osmosis.
Disadvantages - It has high operating cost in case of waste heat unavailability. High temperature imply high corrosion & scale formation.
On the basis of the information above, what is the approximate percent ionization of HNO2 in a 1.0 M HNO2 (aq) solution?
Answer:
The answer is "2%"
Explanation:
Equation:
[tex]HNO_2\ (aq) \leftrightharpoons H^{+} \ (aq) + NO_2^{-}\ (aq) \\\\\ K_a = 4.0\times \ 10^{-4}[/tex]
[tex]H^{+}=?[/tex]
Formula:
[tex]Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}[/tex]
Let
[tex][H^{+}] = [NO_2^{-}] = x[/tex] at equilibrium
[tex]x^2 = (4.0\times 10^{-4})\times 1.0\\\\x = ((4.0\times 10^{-4})\times 1.0)^{0.5} = 2.0 \times 10^{-2} \ M\\\\[/tex]
therefore,
[tex][H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M[/tex]
Calculating the % ionization:
[tex]= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\[/tex]
The approximate percent ionization of HNO₂ in a 1.0 M HNO₂ (aq) solution is 2%.
How we calculate the % ionization?% ionization of any compound will be calculated as follow:
% ionization = ([ion]/[acid or base]) ₓ 100
Given chemical reaction with ICE table will be represented as:
HNO₂(aq) → H⁺(aq) + NO₂⁻(aq)
initial 1 0 0
change -x +x +x
equilibrium 1-x x x
Equilibrium constant will be represented as:
Ka = [H⁺][NO₂⁻] / [HNO₂]
Acid dissociation constant for HNO₂ = 4×10⁻⁴
Putting all values in the above equation, we get
4×10⁻⁴ = x² / 1-x
Value of changeable quantity is very less, so we neglect from the concentration of HNO₂.
4×10⁻⁴ = x²
x = 2 × 10⁻²
So, the concentration of H⁺ ion = 2 × 10⁻²M
Now we put all these values in the % ionization equation, we get
% ionization = (0.02/1) × 100 = 2%
Hence , % ionization is 2%.
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What is the initial and final mass of the zinc and copper?
Answer:the final mass of copper is 3.84 g. There was an increase in mass of 1.84 g from the initial mass of 2.0 g.
Explanation:
determine the maximum amount of NaN03 that was produced during the experiment. Explain how you determined the amount
Answer:
9 moles of NaNO3 is obtained
Explanation:
The balanced chemical reaction equation for the reaction is;
Al(NO3)3 + 3NaCl-------> 3NaNO3 + AlCl3
Now, we have to determine the limiting reactant. The limiting reactant yields the least amount of NaNO3.
1 mole of Al(NO3)3 yields 3 moles of NaNO3
4 moles of Al(NO3)3 yields 4 * 3/1 = 12 moles of NaNO3
Also,
3 moles of NaCl yields 3 moles of NaNO3
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO3
Hence, NaCl is the limiting reactant and 9 moles of NaNO3 is obtained.
9 moles of NaNO₃ is obtained.
Balanced chemical reaction:
[tex]Al(NO_3)_3 + 3NaCl-----> 3NaNO_3 + AlCl_3[/tex]
From the reaction, it is seen that the limiting reactant yields the least amount of NaNO₃.
1 mole of Al(NO₃)₃ yields 3 moles of NaNO₃
4 moles of Al(NO₃)₃ yields 4 * 3/1 = 12 moles of NaNO₃
Also,
3 moles of NaCl yields 3 moles of NaNO₃
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO₃
Hence, NaCl is the limiting reactant and 9 moles of NaNO₃ is obtained.
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What is [H⁺] in a 0.330 M solution of acrylic acid, CH₂CHCOOH (Ka = 3.16 × 10⁻⁵)?
Answer:
[H⁺] = 3.23x10⁻³ M
Explanation:
For a weak monoprotic acid, such as acrylic acid, we can calculate [H⁺] using the following formula if the solution concentration is significantly higher than the Ka:
[H⁺] = √(C * Ka)Where C is the weak acid concentration.
We input the data:
[H⁺] = [tex]\sqrt{0.330 M * 3.16x10^{-5}}[/tex]And solve for [H⁺]:
[H⁺] = 3.23x10⁻³ MA balloon is inflated with 1.25 L of helium at a temperature of 298K. What is
the volume of the balloon when the temperature is 310K?
Answer:
What is
the volume of the balloon when the temperature is 310K?
When calcium forms an ion that has the same number of outer electrons as which noble gas?
1. neon
2. helium
3. argon
4. krypton
BRAINLIEST FOR HELP ASAP!!!!
What is the pH of a house cleaning solution with molar hydrogen ion concentration [H+] of 1.0 x 10-8? please explain. Thank you so much!
[tex]pH = - log({H}^{ + } ) \\ pH = - log(1.0 \times {10}^{ - 8} ) \\ pH = 8[/tex]
pH is the measure of acidity and alkalinity of a solution. A pH value less than 7 means the solution is acidic. A pH value greater than 7 means the solution is basic. A pH value of 7 means the solutions is neutral.
12 moles of sodium into grams
Answer:
12 moles sodium= 275.87724000000003 grams
Explanation:
1 moles sodium = 0.043497607849056.
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 5.0L flask with 4.5 atm of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be 1.1 atm. Calculate the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.
Answer:
Kp = 7.4727
Explanation:
Let's write the balanced equilibrium reaction:
2NH₃ <-------> N₂ + 3H₂ Kp = ??
Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:
2NH₃ <-------> N₂ + 3H₂
I. 4,5 0 0
C. -2x +x +3x
E. 4,5-2x x 3x
According to this chart, the Kp expression should be:
Kp = (PH₂)³ * (PN₂) / (PNH₃)² (1)
The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:
Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²
Kp = 39.5307 / 5.29
Kp = 7.4727Hope this helps
What volume is occupied by 2.0 mol of gas at 3.0 atm
and 27 °C?
What is the mass, in grams, of a piece of aluminum if its temperature changes from 25.0 ºC to 31.5 ºC when it absorbs 42.2 joules of energy? The specific heat for aluminum is 0.89J/gºC
Answer:
m = 7.29 grams
Explanation:
Given that,
Initial temperature, T₁ = 25ºC
Final temperature, T₂ = 31.5ºC
The specific heat of the metal is 0.89 J/gºC.
We know that the heat released due to the change in temperature is given by :
[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{42.2 }{0.89\times (31.5-25)}\\\\m=7.29\ g[/tex]
So, the mass of the piece is equal to 7.29 grams.
What answer is it and how ? please help !!!!!! ill mark brainlyest if right
Answer:
The answer is B
Brainliest please!
Compute the number of electrons that each lead atom donates, on average, to a bulk piece of lead metal. Room temperature data for lead: The conductivity of lead is 4.90 × 104 1/(Ω·m) The electron mobility of lead is 2.3 cm2/(V·s) The mass density of lead is 11.4 g/cm3 The atomic weight of lead is 207 g/mol
Answer:
4 electrons/atom
Explanation:
The conductivity of the lead σ = neμ where n = electron density, e = electron charge = 1.602 × 10⁻¹⁹ C and μ = electron mobility of lead = 2.3 cm²/(V·s) = 2.3 × 10⁻⁴ m²/(V.s)
Making n subject of the formula, we have
n = σ/eμ
Since σ = 4.90 × 10⁶ (Ω·m)⁻¹
Substituting the values of the variables into the equation, we have
n = σ/eμ
n = 4.90 × 10⁶ (Ω·m)⁻¹/(1.602 × 10⁻¹⁹ C × 2.3 × 10⁻⁴ m²/(V.s))
n = 4.90 × 10⁶ (Ω·m)⁻¹/(3.6846 × 10⁻²³ Cm²/(V.s))
n = 1.33 × 10²⁹ electrons/m³
We now find the number of moles of lead present in 1 m³ of lead.
So n' = ρ/M where ρ = density of lead = 11.4 g/cm³ = 11.4 g/cm³ × 10⁶ cm³/m³ = 11.4 × 10⁶ g/m³ and M = atomic weight of lead = 207 g/mol
So, n' = ρ/M
N = 11.4 × 10⁶ g/m³/207 g/mol
n' = 0.0551 × 10⁶ mol/m³
n' = 5.51 × 10⁴ mol/m³
Since n' = N/N' where N = number of atoms of lead in 1 m³ of lead and N = Avogadro's constant = 6.022 × 10²³ mol⁻¹
N = n'N' = 5.51 × 10⁴ mol/m³ × 6.022 × 10²³ mol⁻¹
N = 33.18 × 10²⁷ atoms/m³
N = 3.318 × 10²⁸ atoms/m³
So, the number of electron per atom is N" = n/N
= 1.33 × 10²⁹ electrons/m³ ÷ 3.318 × 10²⁸ atoms/m³
= 0.4 × 10¹ electrons/atom
= 4 electrons/atom
According to the kinetic molecular theory which substances are made of particles ?
Answer:
The kinetic molecular theory of matter states that: Matter is made up of particles that are constantly moving. All particles have energy, but the energy varies depending on the temperature the sample of matter is in. This in turn determines whether the substance exists in the solid, liquid, or gaseous state.
Explanation:
Kinetic molecular theory explains the properties of solids, liquids and gases. As per this theory, matter is made of particles.
What is kinetic theory?
Kinetic molecular theory explains the properties of different states of matter. According to this theory matter is made up of particles. But the theory is mostly applies for gases.
According to kinetic theory of gases, gaseous substances consists of tiny spherical particles which are located apart from each other and hence no intermolecular force acts between them. They are in random motion and gains kinetic energy.
The kinetic energy of particles are temperature dependant and it increase as temperature rises. The collision between the particles and the particle and wall of the container in which they are will be elastic collision.
These concepts are applicable only for ideal gases. An less applicable for other states of matter.
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2+4 help please i will fail 6th grade
Answer:
6
Explanation:
lol
A certain reaction has an activation energy of 51.02 kJ/mol. At what Kelvin temperature will the reaction proceed 4.50 times faster than it did at 365 K
Answer:
[tex]T_2=400.73K[/tex]
Explanation:
From the question we are told that:
Activation energy [tex]E_a= 51.02 kJ/mol.=>51.02*10^3J/mol[/tex]
Reaction Ratio [tex]\triangle K=4.50[/tex]
Initial Temperature [tex]T_1=365K[/tex]
Generally the equation for Final Temperature [tex]T_2[/tex] is mathematically given by
[tex]log \triangle K=\frac{E_a}{2.303R}*(\frac{T_2-T_1}{T_1T_2})[/tex]
Where
[tex]R=Gas constant[/tex]
[tex]R =8.3143[/tex]
Therefore
[tex]log 4.50=\frac{51.2*10^3}{2.303*8.31432}*(\frac{T_2-365}{365*T_2})[/tex]
[tex]log 4.50=7.328*\frac{T_2-365}{T_2}[/tex]
[tex]0.0892=\frac{T_2-365}{T_2}[/tex]
[tex]0.0892T_2=T_2-365[/tex]
[tex]365=T_2-0.0892T_2[/tex]
[tex]365=0.91T_2[/tex]
[tex]T_2=\frac{365}{0.91}[/tex]
[tex]T_2=400.73K[/tex]
Determine the number of molecules of C2CI4 contained in 73.1g of C2CI4
Answer:
2.35x10²³ molecules of C2Cl4 are present
Explanation:
To solve this question we must convert, as first, the mass of C2Cl4 to moles using its molar mass (C2Cl4 = 165.83g/mol). Then, using Avogadro's number we can find the number of molecules:
Moles C2Cl4:
73.1g * (1mol / 165.83g) = 0.441 moles C2Cl4
Molecules:
0.441 moles C2Cl4 * (6.022x10²³molecules / 1mol) =
2.35x10²³ molecules of C2Cl4 are present