The statement true about the rectangle and scale factor is
A scale factor of 2.5 was applied to create the enlargement
Given data ,
A rectangle with a long side of 3 and an arrow points to a larger rectangle with a long side of 7.5
Now , the long side of the original rectangle is 3 units, and the long side of the enlarged rectangle is 7.5 units.
And , the ratio of the long sides is 7.5/3 = 2.5, which indicates that the rectangle was enlarged by a factor of 2.5.
Hence , the scale factor of dilation is d = 2.5
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can someone me with this real quick
a) The two plans will cost the same for 250 minutes of call
b) The cost when the two plans cost the same is $40.50
Determining when the two call plans will cost the sameFrom the question, we are to determine when the two plans will cost the same
From the given information,
Plan A costs $23 plus an additional $0.07 for each minute of calls.
Plan B costs $18 plus an additional $0.09 for each minute of calls.
Let x represent minute of calls.
Then,
We can write that
Plan A:
Cost = $23 + $0.07x
Plan B:
Cost = $18 + $0.09x
To determine the amount of calling when the two plans will cost the same, we will equate the equations and then determine the value of x
23 + 0.07x = 18 + 0.09x
23 - 18 = 0.09x - 0.07x
5 = 0.02x
Divide both sides by 0.02
5/0.02 = x
250 = x
Therefore,
x = 250 minutes
The two plans will cost the same for 250 minutes of call
b)
To determine the cost when the two plans cost the same, we will substitute the value of x into any of the equations
Substitute x = 250 into Cost = $23 + $0.07x
Cost = $23 + $0.07(250)
Cost = $23 + $17.50
Cost = $40.50
Hence,
The cost is $40.50
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Suppose Andrew earns $45,000 EC per month. The average salary for everyone in Andrew's company is $41, 000 EC per month with a standard deviation of $7,000 EC. Suppose David earns $38, 000 EC in his company, for which the average salary is $35,000 EC with a standard deviation of $1,700 EC. Suppose the monthly salary in Andrew's and David's company follows a normal distribution, explain who is doing better in comparison to their coworkers and why?
In terms of deviation from the average salary, David is doing better in his company than Andrew is in his. However, it's important to note that there may be other factors that impact their overall job performance and success within their respective companies.
To determine who is doing better in comparison to their coworkers, we need to calculate the z-scores for both Andrew and David. The z-score measures the number of standard deviations a data point (in this case, their salaries) is away from the mean (average salary). The formula for the z-score is:
z = (X - μ) / σ
where X is the individual's salary, μ is the average salary, and σ is the standard deviation.
For Andrew:
X = $45,000 EC
μ = $41,000 EC
σ = $7,000 EC
z = ($45,000 - $41,000) / $7,000
z = $4,000 / $7,000
z = 0.5714
For David:
X = $38,000 EC
μ = $35,000 EC
σ = $1,700 EC
z = ($38,000 - $35,000) / $1,700
z = $3,000 / $1,700
z = 1.7647
Comparing these deviations, we can see that David is doing better in comparison to his coworkers than Andrew is. David's deviation is larger than Andrew's, which means that his salary is further above the average salary in his company than Andrew's is in his.
A higher z-score indicates a better position compared to coworkers. In this case, David has a higher z-score (1.7647) compared to Andrew (0.5714), meaning that David is doing better in comparison to their coworkers.
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how many arrangements can be made using 4 letters of the word hyperbolas if no letter is to be used more than once?
5,040 arrangements can be made using 4 letters of the word hyperbolas if no letter is to be used more than once.
To find the number of arrangements that can be made using 4 letters of the word "hyperbolas" without repeating any letters, we need to use the formula for permutations.
The formula for permutations of n objects taken r at a time is:
P(n,r) = n! / (n-r)!
Where "n" is the total number of objects and "r" is the number of objects we are choosing.
In this case, we have 10 letters in the word "hyperbolas" and we need to choose 4 of them without repetition. So we can plug in the values:
P(10,4) = 10! / (10-4)!
P(10,4) = 10! / 6!
P(10,4) = (10 x 9 x 8 x 7 x 6!) / 6!
P(10,4) = 10 x 9 x 8 x 7
P(10,4) = 5,040
Therefore, there are 5,040 different arrangements that can be made using 4 letters of the word "hyperbolas" without repeating any letters.
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Un grupo de amigos asiste dos veces al mes al cine. La primera vez pagaron $630 por 5 palomitas y 7 refrescos. La segunda vez compraron 11 refrescos y 8 palomitas pagando un total de $1,000. ¿Cuánto sería el precio unitario de las palomitas y del refresco?
Answer: El precio unitario de las palomitas es de $60 y el precio unitario del refresco es de $70.
Primero, podemos descomponer el costo total de la primera visita al cine en el costo de las palomitas y el costo de los refrescos:
- 5 palomitas + 7 refrescos = $630
- Palomitas = $x, Refrescos = $y
- 5x + 7y = 630
Luego, podemos descomponer el costo total de la segunda visita al cine en el costo de las palomitas y el costo de los refrescos:
- 8 palomitas + 11 refrescos = $1000
- Palomitas = $x, Refrescos = $y
- 8x + 11y = 1000
Ahora podemos resolver este sistema de ecuaciones para encontrar el precio unitario de las palomitas y del refresco. Primero, despejamos y de la primera ecuación:
- 5x + 7y = 630
- 5x = 630 - 7y
- x = (630 - 7y) / 5
Luego, sustituimos esta expresión para x en la segunda ecuación:
- 8x + 11y = 1000
- 8[(630 - 7y) / 5] + 11y = 1000
- 504 - 45.6y + 11y = 1000
- 65.4y = 496
- y = 7.58
Finalmente, podemos sustituir este valor para y en la primera ecuación para encontrar el valor de x:
- 5x + 7(7.58) = 630
- 5x = 578.86
- x = 115.77
Por lo tanto, el precio unitario de las palomitas es de $60 y el precio unitario del refresco es de $70.
Step-by-step explanation:
True or false. When evaluating a square root (i.e. √8), you only acknowledge the positive root
When evaluating a square root, you should acknowledge both the positive and negative roots. Hence, the given statement is false.
The square of a number is the value that is obtained when we multiply the number by itself, while the square root of a number is obtained by finding a number that when squared gives the original number.
When evaluating a square root, you should acknowledge both the positive and negative roots.
Example: √8
= √(4×2)
= ±2√2
Hence, the given statement is false.
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Can two numbers have 16 as their HCF and 380 as their LCM? Give reason
Yes, two numbers could have 16 as their HCF and 380 as their LCM.
Right here's how you could find those two numbers:
Step 1: prime Factorization
Write the high factorization of the LCM, 380, because the manufactured from its prime elements:
[tex]380 = 2^2 * 5 * 19[/tex]
Step 2: HCF Calculation
The HCF of numbers is the highest common element that divides each numbers evenly. since the HCF of the 2 numbers is 16, every of the two numbers have to be divisible by means of 16.
Step 3: number Formation
permit the two numbers be 16a and 16b, in which a and b are co-top (meaning they haven't any common elements aside from 1).
Step 4: LCM Calculation
The LCM of numbers is the smallest variety this is divisible by way of each numbers. because the LCM of the two numbers is 380, we will write:
LCM(16a, 16b) =[tex]2^2 * 5 * 19[/tex]
To find the values of a and b, we need to discover the smallest viable values of a and b such that their product is identical to 19. considering the fact that a and b are co-top, a × b can most effective be 19 or 1.
Case 1: a × b = 1
If a × b = 1, then a = 1 and b = 1, which means that that the 2 numbers are 16 and 16. but, 16 isn't divisible by using 19, so this case is not valid.
Case 2: a × b = 19
If a × b = 19, then the two numbers are 16 × 1 and 16 × 19, which can be 16 and 304, respectively.
Step 5: Verification
We will verify that the two numbers, 16 and 304, have 16 as their HCF and 380 as their LCM as follows:
HCF(16, 304) = 16 (seeing that 16 is the largest common factor of 16 and 304)
LCM(16, 304) = 3040/sixteen = 380 (due to the fact 3040 is the smallest multiple of 16 and 304)
Consequently, the 2 numbers with 16 as their HCF and 380 as their LCM are 16 and 304.
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Oxford Company uses a job order costing system. In the last month, the system accumulated labor time tickets totaling $26,000 for direct labor and
$5,700 for indirect labor. The journal entry to record indirect labor consists of a:
Multiple Choice
The journal entry to record indirect labor consists of A. Debit Factory Overhead $ 5, 700, credit Factory Wages Payable $ 5, 700.
How to record the indirect labor ?Indirect labor charges, like those for factory supervisors or maintenance crew, cannot be exclusively attributed to a given product or job.
Instead, they are typically allotted to all jobs depending on predetermined rates/bases in job order costing, by debiting a Factory Overhead account and crediting an accounting option such as Factory Wages Payable or Accrued Wages Payable.
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Use the definition of a Taylor series to find the first four nonzero terms of the series for f(x) centered at the given value of a. (Enter your answers as a comma-separated list.)f(x) = 4/(1+x), a = 2Use the definition of a Taylor series to find the first four nonzero terms of the series for f(x) centered at the given value of a. (Enter your answers as a comma-separated list.)f(x) = 3xe^x, a = 0
For f(x) = 4/(1+x), a = 2, the Taylor series is given by:
f(x) = f(a) + f'(a)(x-a) + (f''(a)/2!)(x-a)^2 + (f'''(a)/3!)(x-a)^3 + ...
We first need to find the derivatives of f(x):
f(x) = 4/(1+x)
f'(x) = -4/(1+x)^2
f''(x) = 8/(1+x)^3
f'''(x) = -48/(1+x)^4
f''''(x) = 384/(1+x)^5
Now, we can evaluate the Taylor series at x = 2:
f(2) = 4/(1+2) = 4/3
f'(2) = -4/(1+2)^2 = -4/9
f''(2) = 8/(1+2)^3 = 8/27
f'''(2) = -48/(1+2)^4 = -16/81
Substituting these values into the Taylor series, we get:
f(x) = 4/3 - 4/9(x-2) + 8/27(x-2)^2 - 16/81(x-2)^3 + ...
Therefore, the first four nonzero terms of the Taylor series for f(x) centered at a = 2 are:
4/3, -4/9(x-2), 8/27(x-2)^2, -16/81(x-2)^3
For f(x) = 3xe^x, a = 0, the Taylor series is given by:
f(x) = f(a) + f'(a)x + (f''(a)/2!)x^2 + (f'''(a)/3!)x^3 + ...
We first need to find the derivatives of f(x):
f(x) = 3xe^x
f'(x) = 3e^x + 3xe^x
f''(x) = 6e^x + 3xe^x
f'''(x) = 9e^x + 3xe^x
f''''(x) = 12e^x + 3xe^x
Now, we can evaluate the Taylor series at a = 0:
f(0) = 0
f'(0) = 3
f''(0) = 6
f'''(0) = 9
Substituting these values into the Taylor series, we get:
f(x) = 3x + 3x^2 + 3x^3 + 9/2x^4 + ...
Therefore, the first four nonzero terms of the Taylor series for f(x) centered at a = 0 are:
3x, 3x^2, 3x^3, 9/2x^4
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Confused on my math assignment. Can anyone help?
Answer:
Step-by-step explanation:
Here are the match-ups:
Han: x+2<20
Mai: x-2<20
Tyler: 2x<20
Priya: 1/2<20
The circumference of a circle is 2 pi meters. Find its radius, in meters.
Answer:
1 meter
Step-by-step explanation:
Circumference of circle = 2 · r · π
Circumference = 2π
Let's solve
2π = 2 · r · π
2 = 2 · r
r = 1 meter
So, the radius is 1 meter
In which of the following situations can you approximate the sampling distribution with the given values of p and n by using a normal distribution? Op = 24 and n = 30 Op = .90 and n = 32 O More than one of the above Op = .08 and n = 50 O p = .70 and n=9
The situation where we can approximate the sampling distribution with a normal distribution is Op = .90 and n = 32.
In order to approximate the sampling distribution with a normal distribution, both of the following conditions must be satisfied:
The sample size n must be large enough (typically, n >= 30).
The population proportion p and the sample size n must satisfy np >= 10 and n(1-p) >= 10.
Let's check these conditions for each of the given situations:
Op = 24 and n = 30: Since np = 24*30/100 = 7.2 < 10 and n(1-p) = 22.8 < 10, we cannot approximate the sampling distribution with a normal distribution in this case.
Op = .90 and n = 32: Since np = 28.8 >= 10 and n(1-p) = 3.2 >= 10 are both satisfied, we can approximate the sampling distribution with a normal distribution in this case.
Op = .08 and n = 50: Since np = 4 < 10 and n(1-p) = 46 >= 10 are not both satisfied, we cannot approximate the sampling distribution with a normal distribution in this case.
Op = .70 and n=9: Since np = 6.3 >= 10 and n(1-p) = 2.7 < 10 are not both satisfied, we cannot approximate the sampling distribution with a normal distribution in this case.
Therefore, the situation where we can approximate the sampling distribution with a normal distribution is Op = .90 and n = 32.
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A student is painting a brick for his teacher to use as a doorstop in the classroom. He is only painting the front of the brick. The vertices of the face are (−4, 2), (−4, −11), (4, 2), and (4, −11). What is the area, in square inches, of the painted face of the brick?
42 in2
52 in2
104 in2
128 in2
The area of the painted face of the brick is 104 square inches units
What is the area of the painted face of the brick?The vertices of the face are (−4, 2), (−4, −11), (4, 2), and (4, −11)
The distance between the coordinates are
√[(-4 + 4)^2 + (2 + 11)^2] = 13
√[(-4 - 4)^2 + (-11 + 11)^2] = 8
So, we have
Area = 13 * 8
Area = 104
Hence, the area is 104 square inches units
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Answer: The answer is C
Step-by-step explanation:
Graph the line whose y-intercept is 8 and whose x-intercept is -7.
10.
Answer:
y=(8/7)x+8
Step-by-step explanation:
calculate the slope: rise over run, 8/7 and add the y intercept of 8.
Solve for n in the proportion. 215/370=344/n
This simple proportion equation will result to 592
Understanding proportionIn mathematics, a proportion is a statement that two ratios or fractions are equal. It expresses the relationship between two quantities or sets of quantities that are proportional or have a constant ratio to each other.
For example, the statement "2/3 = 4/6" is a proportion, which means that the ratio of 2 to 3 is the same as the ratio of 4 to 6. This proportion can be simplified by dividing both sides by 2, giving "1/3 = 2/3", which means that one-third is equal to two-thirds.
Proportions are commonly used in various fields such as finance, science, and engineering to solve problems related to scaling, measurement, and comparison.
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From his home, Rudy would have to walk due north to get to his friend Javier's house and
due east to get to his friend Steve's house. It is 1 mile from Rudy's house to Steve's house
and a straight-line distance of 3 miles from Javier's house to Steve's house. How far is Rudy's
house from Javier's house? If necessary, round to the nearest tenth.
miles
Answer:
Rudy's house is approximately 2.8 miles away from Javier's house.
Step-by-step explanation:
We can use the Pythagorean theorem to solve this problem. Let x be the distance from Rudy's house to Javier's house. Then, we can set up the following equations based on the given information:
x^2 + 1^2 = 3^2 (using the distance between Javier's and Steve's houses)
x^2 = 9 - 1
x^2 = 8
x ≈ 2.8
Therefore, Rudy's house is approximately 2.8 miles away from Javier's house.
consider the following two statements: i ) the derivative of a sum is the sum of the derivatives. ii) the derivative of a difference is the difference of the derivatives. select the correct response below
a. Neither i or ii is true. b. Only statement ii is true. c. Only statement i is true d. Both i and ii are true.
there is a related property known as the chain rule which can be used to differentiate a difference of functions.
The correct response is: c. Only statement i is true.
Statement i is known as the linearity of differentiation and is a fundamental property of derivatives. It states that the derivative of a sum of functions is equal to the sum of their derivatives.
On the other hand, statement ii is not true in general. The derivative of a difference of functions is not equal to the difference of their derivatives. However, there is a related property known as the chain rule which can be used to differentiate a difference of functions.
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Can someone please help me with this
The equation of the axis of symmetry for the parabola is x = 4.
How to find the axis of symmetry of a parabola
In this problem we find the representation of a parabola whose axis of symmetry is parallel with the y-axis, the formula of the parabola is:
y = a · x² + b · x + c
Where:
a, b, c - Real coefficients.x - Independent variable.y - Dependent variable.And the axis of symmetry of the parabola is shown below:
x = h
Where h is the x-coordinate of the vertex.
If we know that vertex has coordinates (h, k) = (4, - 1), then the equation of the axis of symmetry is x = 4.
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one tenth of a number decreased by four is eight
The awnesr is
= 120
10(8+4)
WILL MARK BRAINLIEST!!!
Simplify the system.
Answer:
[tex] \frac{6 {x}^{2} - 12x - 48 }{3 {x}^{2} - 12x - 36 } = \frac{6( {x}^{2} - 2x - 8)}{3( {x}^{2} - 4x - 12)} = \frac{6(x + 2)(x - 4)}{3(x + 2)(x - 6)} = \frac{2(x - 4)}{x - 6} = \frac{2x - 8 }{x - 6} [/tex]
!!HELP ASAP DUE TODAY!! I need help with this math problem.
The value of x in the expression is x = - 14
How to determine the value?Remember that an algebraic expression is an equation that contains one or more variables. It is built up from constant algebraic numbers, variables, and the algebraic operations (addition, subtraction, multiplication, division and exponentiation by an exponent that is a rational number)
The given equation is
-1/2 x + 6 = 4x - 3
Collecting the like terms to have
- 1/2 x - 4x = -3 -6
(2x - 8)/ 4 = - 9
Cross and multiply to have
2x -8 = -36
2x = -36 +8
2x = -28
Making x the subject of the relation we have
x = -28/2
Therefore the value of x = - 14
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I SUCK AT MATH HELP!giving 11. Points
The unit of measurement that Mia should use for the surface area of the prism is B. in ².
Why is this unit best ?Determining the surface area of an object requires calculating the total measure of its covered space. This figure is quantified in square units, as it consists of deriving two-dimensional lengths and widths from its surfaces, which are then multiplied to arrive at the entire area.
As dimensions only concern a flat outline, it follows that all recorded measurements will take on some form of squared units like m² or in² - invariably pegged to the realm of two-dimensionality.
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in the land of oz, 20% of the residents are members of the lollipop guild (80% are not members), and 75% of the residents have a home in emerald city (25% live outside the city). suppose that lollipop guild membership is independent of having a home in emerald city. what is the probability that a randomly selected resident from the land of oz is a member of the lollipop guild and has a home in emerald city?
So the probability that a randomly selected resident from the land of Oz is a member of the lollipop guild and has a home in emerald city is 0.15.
Since lollipop guild membership is independent of having a home in emerald city, we can find the probability of both events occurring by multiplying their individual probabilities:
P(lollipop guild and emerald city) = P(lollipop guild) * P(emerald city)
P(lollipop guild) = 0.20 (given)
P(emerald city) = 0.75 (given)
Therefore,
P(lollipop guild and emerald city) = 0.20 * 0.75
= 0.15
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T/F : If the first and second rows of an augmented matrix are (1,1,0) and (0,1,0) respectively, then the matrix is not in reduced row echelon form.
False.
the given augmented matrix is in reduced row echelon form.
The augmented matrix is said to be in reduced row echelon form (RREF) if it satisfies the following conditions:
1. The first nonzero element in each row (called the "pivot") is 1.
2. The pivot in each row is to the right of the pivot in the previous row.
3. All entries above and below each pivot are zero.
In the given augmented matrix, the first row is (1,1,0) and the second row is (0,1,0). Since the first nonzero element (the pivot) in the first row is 1, and the pivot in the second row is to the right of the pivot in the first row, the matrix satisfies conditions (1) and (2) for being in RREF.
Also, since the entry below the pivot in the first row is 0, and all entries in the third column are 0, the matrix satisfies condition (3).
Therefore, the given augmented matrix is in reduced row echelon form.
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HELP PLEASE IM TIMED
The amount of fabric that is needed for the tent is 18350 in² (optionC)
What is area of prism?A prism is a solid shape that is bound on all its sides by plane faces. The surface area of a prism is expressed as ;
SA = 2B +pH
where B is the base area , p is the perimeter of the base and H is the height of the prism.
Base area =1/2bh
= 1/2 × 50× 70
= 25 × 70
= 1750in²
Perimeter of the base = 74+74+50
= 198 in
height = 75in
Therefore SA = 2×1750 +198 × 75
= 3500 + 14850
= 18350 in²
therefore the amount of fabric that will be needed nis 18350 in²
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the sample space contains 6 as and 4 bs. what is the probability that a randomly selected set of 3 will include 1 a and 2 bs?
The probability that a randomly selected set of 3 will include 1 A and 2 Bs is 0.3 or 30%.
To find the probability that a randomly selected set of 3 will include 1 a and 2 bs, we first need to determine the total number of possible sets of 3 that can be selected from the sample space.
Since the sample space contains 6 as and 4 bs, the total number of possible sets of 3 that can be selected is:
10C3 = (10!)/(3!*(10-3)!) = 120
This means there are 120 different ways to select a set of 3 from the sample space.
Next, we need to determine the number of sets of 3 that include 1 a and 2 bs. To do this, we can use the combination formula:
6C1 * 4C2 = (6!)/(1!*(6-1)!) * (4!)/(2!*(4-2)!) = 6*6 = 36
This means there are 36 different sets of 3 that include 1 a and 2 bs.
Finally, we can calculate the probability of selecting a set of 3 that includes 1 a and 2 bs by dividing the number of sets that meet this condition by the total number of possible sets:
36/120 = 3/10
Therefore, the probability that a randomly selected set of 3 will include 1 a and 2 bs is 3/10.
Given that the sample space contains 6 As and 4 Bs, let's find the probability that a randomly selected set of 3 will include 1 A and 2 Bs.
1. First, calculate the total number of ways to choose 3 elements from a set of 10 (6 As and 4 Bs). We use the combination formula:
C(n, r) = n! / (r!(n-r)!)
C(10, 3) = 10! / (3!(10-3)!) = 10! / (3!7!) = 120
2. Next, find the number of ways to choose 1 A from the 6 As and 2 Bs from the 4 Bs:
C(6, 1) = 6! / (1!(6-1)!) = 6! / (1!5!) = 6
C(4, 2) = 4! / (2!(4-2)!) = 4! / (2!2!) = 6
3. Multiply the number of ways to choose 1 A and 2 Bs:
Number of favorable outcomes = C(6, 1) × C(4, 2) = 6 × 6 = 36
4. Finally, calculate the probability:
Probability = Number of favorable outcomes / Total number of outcomes = 36 / 120 = 3/10 or 0.3
So, the probability that a randomly selected set of 3 will include 1 A and 2 Bs is 0.3 or 30%.
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write an equation
m = - 1/13
B= -8
Based on the given information, you are likely looking for the equation of a straight line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
Given m = -1/13 and b = -8, the equation of the line is:
y = (-1/13)x - 8
(1 point) 1. In a study of red/green color blindness, 800 men and 2100 women are randomly selected and tested. Among the men. 72 have red green color blindness. Among the women, 6 have red/green color blindness. Test the claim that men have a higher rate of red/green color blindness. (Note: Type w. m n for the symbol p p m, for example p − m not =p − w for the proportions are not equal, p − m>p − w for the proportion of men with color blindness is larger, p.m
To test the claim that men have a higher rate of red/green color blindness. If p_ m > p_ w, the claim is supported, indicating that the proportion of men with color blindness is larger.
To test the claim that men have a higher rate of red/green color blindness, we need to compare the proportions of color blindness in men and women. Let p-m be the proportion of men with red/green color blindness and p-w be the proportion of women with red/green color blindness.
We can set up the null hypothesis as H0: p-m = p-w, meaning there is no difference in the proportions of color blindness between men and women. The alternative hypothesis is Ha: p-m > p-w, meaning the proportion of men with color blindness is larger.
To test this claim, we can use a two-sample proportion z-test. The formula for the test statistic is:
z = (p-m - p-w) / sqrt(p-hat * (1 - p-hat) * (1/n-m + 1/n-w))
where p-hat is the pooled sample proportion:
p-hat = (x-m + x-w) / (n-m + n-w)
In this case, x-m = 72, x-w = 6, n-m = 800, and n-w = 2100. Plugging in the values, we get:
p-hat = (72 + 6) / (800 + 2100) = 0.024
z = (0.09 - 0.002) / sqrt(0.024 * 0.976 * (1/800 + 1/2100)) = 3.09
Using a significance level of 0.05, the critical z-value for a one-tailed test is 1.645. Since our calculated z-value of 3.09 is greater than the critical value, we can reject the null hypothesis and conclude that there is evidence to support the claim that men have a higher rate of red/green color blindness than women.
In the study of red/green color blindness, 800 men and 2100 women were randomly selected and tested. Among the men, 72 have red/green color blindness, and among the women, 6 have red/green color blindness. To test the claim that men have a higher rate of red/green color blindness, compare the proportions: p_ m (proportion of men with color blindness) and p_ w (proportion of women with color blindness). If p_ m > p_ w, the claim is supported, indicating that the proportion of men with color blindness is larger.
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How do you find x to find angles?
X is used as a Place holder for the value(s) in math. Oh and angle BAG should be around 135!
Name of Stock Symbol High Low Close
105.19 103.25 103.38
145.18 143.28 144.05
Stock A
Stock B
A
B
Last year, an investor purchased 120 shares of stock A at $90 per share and 35 shares of stock B at $145 per share. What is the difference in
overall loss or gain between selling at the current day's high price or low price?
O The difference in overall gain is $299.30.
O The difference in overall loss is $299.30.
The difference in overall gain is $293.90.
O The difference in overall loss is $293.90.
The difference in overall gain is $299.30.
How to solve for differenceFor Stock A:
Purchase price: $90 per share
Number of shares: 120
Total purchase cost: 120 * $90 = $10,800
Selling at high price: $105.19
Selling at low price: $103.25
High price sale proceeds: 120 * $105.19 = $12,622.80
Low price sale proceeds: 120 * $103.25 = $12,390
Profit/loss at high price: $12,622.80 - $10,800 = $1,822.80
Profit/loss at low price: $12,390 - $10,800 = $1,590
Difference for Stock A: $1,822.80 - $1,590 = $232.80
For Stock B:
Purchase price: $145 per share
Number of shares: 35
Total purchase cost: 35 * $145 = $5,075
Selling at high price: $145.18
Selling at low price: $143.28
High price sale proceeds: 35 * $145.18 = $5,081.30
Low price sale proceeds: 35 * $143.28 = $5,014.80
Profit/loss at high price: $5,081.30 - $5,075 = $6.30
Profit/loss at low price: $5,014.80 - $5,075 = -$60.20
Difference for Stock B: $6.30 - (-$60.20) = $66.50
total difference in overall gain between selling at the current day's high price or low price:
Difference for Stock A + Difference for Stock B = $232.80 + $66.50 = $299.30
So, the correct statement is:
The difference in overall gain is $299.30.
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Given vector � = < − 5 , − 3 > , v=⟨−5,−3⟩, find 2 � . 2v.
The vector 2v is ⟨-10, -6⟩ when the vector v is ⟨-5, -3⟩ we get by multiplying
To find 2v, we simply need to multiply each component of the vector v by 2:
2v = 2⟨-5, -3⟩
Multiply 2 with the vector v
= ⟨2(-5), 2(-3)⟩
= ⟨-10, -6⟩
Therefore, the vector 2v is ⟨-10, -6⟩ when the vector v is ⟨-5, -3⟩
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