Which statement best describes network security?
Network security means all information is open to the public, the network is not compromised, and everyone has access to the network.
Network security means personal information is kept safe, the network is not compromised, and only authorized users have access.
Network security means everyone has access to the network, the network is not compromised, and no one has authorization to use it.
Network security means everyone has access to the information, the network is not compromised, and only a handful of people are authorized users.

Answer:

Explanation:

The following code snippet is a leap year checker written in Haskell which checks to see if the year is a leap year and then outputs a boolean value.

isDivisibleBy :: Integral n => n -> n -> Bool

isDivisibleBy x n = x `rem` n == 0

leap_n :: Integer -> Bool

leap_n year

 | divBy 400 = True

 | divBy 100 = False

 | divBy   4 = True

 | otherwise = False

where

  divBy n = year `isDivisibleBy` n

Answer:

magine a coordinate plane. Let’s say we want to draw an angle that’s 144° on our plane. We start on the right side of the x-axis, where three o’clock is on a clock. We rotate counterclockwise, which starts by moving up. We keep going past the 90° point (the top part of the y-axis) until we get to 144°. We draw a ray from the origin, which is the center of the plane, to that point. Now we have a ray that we call the terminal side. But we need to draw one more ray to make an angle. We have a choice at this point. Our second ray needs to be on the x-axis. If we draw it from the origin to the right side, we’ll have drawn an angle that measures 144°. If we draw it to the left, we’ll have drawn an angle that measures 36°. This second angle is the reference angle. It’s always the smaller of the two angles, will always be less than or equal to 90°, and it will always be positive. Here’s an animation that shows a reference angle for four different angles, each of which is in a different quadrant. Notice how the second ray is always on the x-axis.

Explanation:

The start frame delimiter found in the Ethernet frame is A preamble and begin body delimiter are a part of the packet on the bodily layer. The first  fields of every body are locations and supply addresses.

Frame delimiting, Addressing, and Error detection. Frame delimiting: The framing procedure affords essential delimiters which might be used to pick out a set of bits that make up a body. This procedure affords synchronization among the transmitting and receiving nodes.

The Preamble (7 bytes) and Start Frame Delimiter (SFD), additionally referred to as the Start of Frame (1 byte), fields are used for synchronization among the sending and receiving devices. These first 8 bytes of the body are used to get the eye of the receiving nodes.

Read more about the Ethernet :

https://brainly.com/question/1637942

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Explanation:

DNS uses the User Datagram Protocol (UDP) on port 53 to serve DNS queries. UDP is preferred because it is fast and has low overhead. A DNS query is a single UDP request from the DNS client followed by a single UDP reply from the server.

The transport layer protocol that DNS normally use is the User Datagram Protocol (UDP).

The Internet Protocol (IP) is a network layer protocol, and the Transmission Control Protocol (TCP) is a transport layer protocol.

A network communication between applications is established and maintained according to the Transmission Control Protocol (TCP) standard. The Internet Protocol (IP), which specifies how computers send data packets to one another, works with TCP.

User Datagram Protocol (UDP) on port 53 is how DNS serves DNS requests. Due to its speed and low overhead, UDP is recommended. A single UDP request from the DNS client and a single UDP response from the server makes up a DNS query.

Therefore, the transport layer protocol used by DNS is User Datagram Protocol (UDP).

To learn more about transport layer protocol, refer to the link:

https://brainly.com/question/4727073

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Answer:

The answer is "Choice C".

Explanation:

In this question, the choice C is correct because all the other options will the output "5 4 3 2 1" and it will given "5 2 3 4 1" as output which is defined in the attached file. please find it.

Answer:

Explanation:

The following switch statement takes in the variable button as a parameter and outputs a statement saying what the character did due to the button being pushed.

switch (Character.toLowerCase(button.charAt(0))) {

           case 'a': System.out.println("Your character has Jumped"); break;

           case 'b': System.out.println("Your character has Crouched"); break;

           case 'x': System.out.println("Your character has Punched"); break;

           case 'y': System.out.println("Your character has Flown"); break;

           default: System.out.println("Pause Menu has appeared"); break;

       }

answer is b

rtyujhygtrcdxrtgyhgtfr

Answer:

systemctl restart firewalld

Explanation:

The command that will most likely resolve the communication issue being experienced by Alex ( i.e. his inability to communicate on port 80 ) is

systemctl restart firewalld  given that the host-based firewall's configuration has been changed

Answer:

Explanation:

The following derived class called StringInstrument extends the Instrument class and creates the necessary private variables for number of Strings and number of Frets. Then it creates getter and setter methods for each of the variables. This allows them to be called within the main method that has already been created and output the exact sample output as seen in the question.

class StringInstrument extends Instrument {

   private  int numStrings, numFrets;

   public int getNumOfStrings() {

       return numStrings;

   }

   public void setNumOfStrings(int numStrings) {

       this.numStrings = numStrings;

   }

   public int getNumOfFrets() {

       return numFrets;

   }

   public void setNumOfFrets(int numFrets) {

       this.numFrets = numFrets;

   }

}

Answer:

CPU is known as Central Processing Unit.

Answer:

The given statement is "True".

Explanation:

Thus the above is the correct response.

Answer:

A tablet keyboard

Explanation:

This would be the device used

Answer:

Explanation:

The following python code loops through each line within a file called text.txt and counts all the words, then it divides this count by the number of sentences in the text file. Finally, output the average number of words per sentence.

f = open("text.txt", "r")

all_words = 0

sentences = 0

for x in f:

   list = x.split(' ')

   all_words += len(list)

   sentences += 1

average = all_words / sentences

print("There are an average of " + str(average.__round__()) + " words in each sentence.")

Answer:

Explanation:

The following program creates a function called region_Matches that takes in two strings as arguments as well as an int for starting point and an int for amount of characters to compare. Then it compares those characters in each of the words. If they match (ignoring case) then the function outputs True, else it ouputs False. The test cases compare the words "moving" and "loving", the first test case compares the words starting at point 0 which outputs false because m and l are different. Test case 2 ouputs True since it starts at point 1 which is o and o.

class Brainly {

   public static void main(String[] args) {

       String word1 = "moving";

       String word2 = "loving";

       boolean result = region_Matches(word1, word2, 0, 4);

       boolean result2 = region_Matches(word1, word2, 1, 4);

       System.out.println(result);

       System.out.println(result2);

   }

   public static boolean region_Matches(String word1, String word2, int start, int numberOfChars) {

       boolean same = true;

       for (int x = 0; x < numberOfChars; x++) {

           if (Character.toLowerCase(word1.charAt(start + x)) == Character.toLowerCase(word2.charAt(start + x))) {

               continue;

           } else {

               same = false;

               break;

           }

       }

       return same;

   }

}

Answer: See explanation

Explanation:

Navigational search - This occurs when the user is looking for a certain website. Then the name of the website will be entered into the search bar.

Informational search - This occurs when the user wants to get a certain information. For example, if user enters "what is computer" into the search bar, different results relating to the word "computer" will be gotten.

Transactional search - This occurs when the user wants a website that is interactive it which possess more interaction. An example is when the user wants to buying something, register for something or maybe download something

Answer:

Nothing much is wrong

Explanation:

Nothing much is wrong with it but then again I'm a full on computer geek, I assume you need to go back and re-read it and edit whatever you feel is wrong or incorrect it's like a gut feeling and you will have doubts on certain parts of what you are doing

Solution :

public class [tex]$\text{Stock}$[/tex] {

private [tex]$\text{String}$[/tex] stockName, [tex]$\text{purchaseDate}$[/tex];

private [tex]$\text{int}$[/tex] nShares;

private [tex]$\text{double}$[/tex] price;

public [tex]$\text{Stock}()$[/tex]

{

this.stockName = "";

this.purchaseDate = "";

this.nShares = 0;

this.price = 0.0;

}

public Stock(String stockName, String purchaseDate, int nShares, double price) {

this.stockName = stockName;

this.purchaseDate = purchaseDate;

this.nShares = nShares;

this.price = price;

}

public String getStockName() {

return stockName;

}

public void setStockName(String stockName) {

this.stockName = stockName;

}

public String getPurchaseDate() {

return purchaseDate;

}

public void setPurchaseDate(String purchaseDate) {

this.purchaseDate = purchaseDate;

}

public int getnShares() {

return nShares;

}

public void setnShares(int nShares) {

this.nShares = nShares;

}

public double getPrice() {

return price;

}

public void setPrice(double price) {

this.price = price;

}

public String toString()

{

return("Stock name: " + this.stockName + "\nPurchase date: " + this.purchaseDate

+ "\nNumber of shares of stock: " + this.nShares + "\nPrice: $" + String.format("%,.2f", this.price));

}

public void printStock()

{

System.out.println("Stock name: " + this.stockName + "\nPurchase date: " + this.purchaseDate

+ "\nNumber of shares of stock: " + this.nShares + "\nPrice: $" + String.format("%,.2f", this.price)

+ "\n");

}

}

StockTester.java (Driver class)

import [tex]$\text{java.io.}$[/tex]File;

import [tex]$\text{java.io.}$[/tex]File[tex]$\text{NotFound}$[/tex]Exception;

import [tex]$\text{java.util.}$[/tex]ArrayList;

import [tex]$\text{java.util.}$[/tex]Scanner;

[tex]$\text{public}$[/tex] class StockTester {

private static final String FILENAME = "StockInfo[tex]$.$[/tex]csv";

public static [tex]$\text{void}$[/tex] main([tex]$\text{String}[]$[/tex] args)

{

ArrayList[tex]$<\text{stock}>$[/tex] dataStock = [tex]$\text{readData}$[/tex](FILENAME);

System.out.println("Initial stocks:");

for(Stock s : dataStock)

s.printStock();

System.out.println("Adding a new Stock object to the list..");

Stock newStock = new Stock("Gamma", "03/01/20", 100, 50.5);

dataStock.add(newStock);

System.out.println("\nStocks after adding the new Stock..");

for(Stock s : dataStock)

s.printStock();

Stock targetStock = dataStock.get(3);

double reqReturn = requiredReturn(targetStock, 4000, 3);

System.out.println("Required rate of return = " + String.format("%.2f", reqReturn) + "%");

}

private static ArrayList<Stock> readData(String filename)

{

ArrayList<Stock> stocks = new ArrayList<>();

Scanner fileReader;

try

{

fileReader = new Scanner(new File(filename));

while(fileReader.hasNextLine())

{

String[] data = fileReader.nextLine().trim().split(",");

String stockName = data[0];

String purchaseDate = data[1];

int nShares = Integer.parseInt(data[2]);

double price = Double.parseDouble(data[3]);

stocks.add(new [tex]$\text{Stock}$[/tex](stockName, [tex]$\text{purcahseDate}$[/tex], nShares, price));

}

fileReader.close();

}catch(FileNotFoundException fnfe){

System.out.println(filename + " cannot be found!");

System.exit(0);

}

return stocks;

}

private static double requiredReturn(Stock s, double targetPrice, int years)

{

double reqReturn;

double initialPrice = s.getPrice() * s.getnShares();

reqReturn = ((targetPrice - initialPrice) / initialPrice * years) * 100;

return reqReturn;

}

}

Answer:

FFTH Fiber to the home, FFTB Fiber to the building.

Answer:

Explanation:

The following Java code creates the program which calls asks the user for an input and then passes that input into two methods toInches, and toGallons. Then the main method saves the returned values in variables and prints out a statement for each.

import java.util.Scanner;

class Brainly {

   static Scanner in = new Scanner(System.in);

   public static void main(String[] args) {

      System.out.println("Enter a value: ");

      int answer = in.nextInt();

      double inches = toInches(answer);

      double gallons = toGallons(answer);

       System.out.println("There are " + inches + " inches in " + answer + " centimeters");

       System.out.println("There are " + gallons + " gallons in " + answer + " liters");

   }

   public static double toInches(int centimeters) {

       return (centimeters / 2.54);

   }

   public static double toGallons(int liters) {

       return (liters / 3.7854);

   }

}

Answer:

Short, technical, include a call to action.

Relevant, short, entertaining.

Short, entertaining, include a call to action.

Explanation:

Answer:

hecks

Explanation:

nah

Answer:

Explanation:

The following class is written in Python, it has the three instance variables that were requested. It also contains a constructor that takes in those variables as arguments. Then it has functions to update the positions of the Dot and change its color. The class also has functions to output current position and color.

class Dot:

   """Class Dot"""

   x_coordinate = 0

   y_coordinate = 0

   color = ""

   def __init__(self, x_coordinate, y_coordinate, color):

       """Constructor that takes x and y coordinates as integers and a string for color. It ouputs nothing but saves these argument values into the corresponding instance variables."""

       self.x_coordinate = x_coordinate

       self.y_coordinate = y_coordinate

       self.color = color

   def moveUp(self, number_of_spaces):

       """Moves the Dot up a specific number of spaces that is passed as a parameter. Updates y_position"""

       self.y_coordinate += number_of_spaces

       return ""

   def moveDown(self, number_of_spaces):

       """Moves the Dot down a specific number of spaces that is passed as a parameter. Updates y_position"""

       self.y_coordinate -= number_of_spaces

       return ""

   def moveLeft(self, number_of_spaces):

       """Moves the Dot left a specific number of spaces that is passed as a parameter. Updates x_position"""

       self.x_coordinate -= number_of_spaces

       return ""

   def moveRight(self, number_of_spaces):

       """Moves the Dot right a specific number of spaces that is passed as a parameter. Updates x_position"""

       self.x_coordinate += number_of_spaces

       return ""

   def dot_position(self):

       """Print Dot Position"""

       print("Dot is in position: " + str(self.x_coordinate) + ", " + str(self.y_coordinate))

       return ""

   def dot_color(self):

       """Print Current Dot Color"""

       print("Dot color is: " + self.color)

Answer:

9.2. Métodos del Objeto File (Python para principiantes)

Explanation:

Answer:

Answered below

Explanation:

//Python code

numberOfCasts = 3

j = 0

fishingPoints = 0

sum = 0

while j < numberOfCasts:

dieNum = randint(1 , 6)

if dieNum ==1:

fishingPoints = 2

elif dieNum == 2:

fishingPoints = 4

elif dieNum == 3:

fishingPoints = 6

elif dieNum == 4:

fishingPoints = 8

elif dieNum == 5:

fishingPoints = 10

elif dieNum ==6:

fishingPoints = 12

sum += fishingPoints

j++

if sum > 30:

print ("Great catch")

elif sum > 10 and sum <= 30:

print("Good catch")

else:

print ("Bad day")

Answer:

Explanation:

The following Python code asks the user for inputs for the name to remove and add in the set. It then tries to remove the given name from the list. If it fails it prints out to the user saying that the name does not exist. If it does exist then it removes the name and adds the new name. Finally it prints out the current list of names.

male_names = {'oliver', 'Declan', 'Henry'}

name_to_remove = input("Enter name to remove: ")

name_to_add = input("Enter name to add: ")

try:

   male_names.remove(name_to_remove)

   male_names.add(name_to_add)

except:

   print("Name that you are trying to remove does not exist")

print("List of Names: ")

print(male_names)

In this exercise we have to use the knowledge of the python language to write the code, so we have to:

The code is in the attached photo.

So to make it easier the code can be found at:

male_names = {'oliver', 'Declan', 'Henry'}

name_to_remove = input("Enter name to remove: ")

name_to_add = input("Enter name to add: ")

try:

  male_names.remove(name_to_remove)

  male_names.add(name_to_add)

except:

  print("Name that you are trying to remove does not exist")

print("List of Names: ")

print(male_names)

See more about python at brainly.com/question/26104476

Solution :

1.

a). Candidate keys : [tex]$B$[/tex]

b). R is in [tex]$2F$[/tex] but not [tex]$3NF$[/tex]

c). C → [tex]$D$[/tex] and C → [tex]$A$[/tex], both causes violations of [tex]$BCNF$[/tex]. The way to obtain the join preserving decomposition is to decompose [tex]$R$[/tex] into [tex]$AC, BC$[/tex] and CD.

2.

a). Candidate keys : [tex]$BD$[/tex]

b). [tex]$R$[/tex] is in [tex]$1NF$[/tex] but not [tex]$2NF$[/tex].

c). Both B → [tex]$C$[/tex] and D → [tex]$A$[/tex] cause [tex]$BCNF$[/tex] violations. The decomposition : [tex]$AD $[/tex], [tex]$BC, BD$[/tex] is [tex]$BCNF$[/tex] and lossless and the join preserving.

3.

a). Candidate keys : [tex]$ABC, BCD$[/tex]

b). R is in [tex]$3NF$[/tex] but not [tex]$BCNF$[/tex]

c).[tex]$ABCD$[/tex] is not in [tex]$BCNF$[/tex] since D → [tex]$A$[/tex] and [tex]$D$[/tex] is not a key. But if we split up the [tex]$R$[/tex] as [tex]$AD,BCD$[/tex] therefore we cannot preserve dependency [tex]$ABC$[/tex] → D. So there is no [tex]$BCNF$[/tex] decomposition.

4.

a). Candidate keys : [tex]$A$[/tex]

b). R is in [tex]$2NF$[/tex] but not [tex]$3NF$[/tex]

c). BC → [tex]$D$[/tex] violates [tex]$BCNF$[/tex] since [tex]$BC$[/tex] does not contain the key. And we split up R as in [tex]$BCD, ABC$[/tex].

5.

a). Candidate keys : [tex]$AB, BC, CD, AD$[/tex]

b). [tex]$R$[/tex] is in [tex]$3NF$[/tex] but not [tex]$BCNF$[/tex].

c). C → [tex]$A$[/tex] and D → [tex]$B$[/tex] both causes a violations. The decomposition into [tex]$AC,BCD$[/tex] but this will not preserve [tex]$AB$[/tex] → C and [tex]$AB$[/tex] → D, and [tex]$BCD$[/tex] is still not [tex]$BCNF$[/tex] because [tex]$D$[/tex] → [tex]$B$[/tex]. So we need to decompose further into [tex]$AC,BD,CD$[/tex] However when we try to revive the lost functional dependencies by adding [tex]$ABC$[/tex] and [tex]$ABD$[/tex], we that these relations are not in [tex]$BCNF$[/tex] form. Therefore, there is no [tex]$BCNF$[/tex] decomposition.

Answer:

which cell reference:-|

Answer:

absolute reference: the cell remains constant when copied or moved.

mixed reference: the cell has a combination of two other types of cell references.

relative reference: the cell changed based on the position of rows and columns.

Answer:

Cloud computing and applications

Explanation:

Answer: Cloud computing

Applications

Explanation: