Answer:
the answer is d. frequency
How did you organize the tiles in part A? Describe the method that you used.
Periodic table of numbers tiles
Answer:
I ordered the tiles from left to right and top to bottom as the numbers kept increasing. The tiles were also organized based on the color and shape that they were. The tiles with the same color and shape were arranged in the same column.
Explanation:
In the modern periodic table, the elements are listed in order of increasing atomic number and elements having similar chemical properties naturally line up in the same column (group).
Suppose that you are a scientist who studies climate changes. While examining the rings of tree trunks, you notice several very large tree rings. What can you conclude about the climate during those years?
Answer:
The climate was wet and cold
Explanation:
Answer:
The large tree rings allow you to conclude that the climate was either very warm or wet during those growing seasons, because greater than normal growth occurred.
Explanation: It is the edge sample response
Which describes a speed?
O A. Moving 8 meters in 2 seconds
O B. Falling down at 100 miles/hr
O C. Moving north at 40 km/hr
O D. Speed changing from 2 km/hr to 5 km/hr
2. Which test for iron(II) ions is conclusive
Answer:
please brainlist answer
Explanation:
The addition of K 3 Fe(CN) 6 to a solution causes the formation of a deep blue precipitate which indicates that iron(II) ions are present.
The conclusive test for iron(II) ions is the test by the use of potassium hexacyanoferrate III solution.
In qualitative analysis certain reagents are used to test for the presence of certain cations or anions. Those reagents react in a certain way with those reagents. Usually, a positive test may involve a color change, formation of a precipitate or evolution of a gas.
In the case of iron(II) ions, potassium hexacyanoferrate III solution is used in the conclusive qualitative test for the ion. A positive test involves the appearance of a deep blue precipitate.
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Determine the wavelength of the energy that needs to be absorbed for a 3p electron in chlorine to be promoted to the 4s subshell. Assume that Zeff=6 for a chlorine atom.
Answer:
The wavelength of the energy that needs to be absorbed = 52.36 nm
Explanation:
For this study;
Let consider the Rydgberg equation from Bohr's theory of atomic model:
i.e.
[tex]\dfrac{1}{\lambda} = R_H (Z^*)^2( \dfrac{1}{n_1^2}-\dfrac{1}{n_2^2})[/tex]
where
Z* = effective nuclear charge of atom = Z - σ = 6
n₁ = lower orbit = 3
n₂ = higher orbit = 4
[tex]R_H[/tex] = Rydyberg constant = 1.09 × 10⁷ m⁻¹
λ = wave length of the light absorbed
∴
[tex]\dfrac{1}{\lambda} = 1.09 \times 10^7}(6)^2( \dfrac{1}{3^2}-\dfrac{1}{4^2})[/tex]
[tex]\dfrac{1}{\lambda} = 1.09 \times 10^7}(36)( \dfrac{1}{9}-\dfrac{1}{16})[/tex]
[tex]\dfrac{1}{\lambda} = 392400000\times0.0486111111[/tex]
[tex]\dfrac{1}{\lambda} =19075000[/tex]
[tex]\lambda = \dfrac{1}{19075000}[/tex]
[tex]\lambda = \dfrac{1}{1.91\times 10^7 \ m^{-1}}[/tex]
[tex]\lambda = 5.236 \times 10^{-8} m[/tex]
[tex]\lambda = 52.36 \times 10^{-9} m[/tex]
[tex]\lambda = 52.36\ n m[/tex]
Therefore, the wavelength of the energy that needs to be absorbed = 52.36 nm
trioxocarbonate iv acid
Answer:
Trioxocarbonate (iv) are salts derived from trioxocarbonate (iv) acid when it reacts with metals and metallic oxides. All trioxocarbonate (iv) salts of Sodium (Na), Potassium (K) and Ammonium(NH4+) are soluble while all others are insoluble.
The definition of having to do with the physical properties and terrain of an area refers to the
term
environmental
forecasting
meticulous
topographical
adjacent
Answer:
Topographical
Explanation:
When it comes to questions such as this one, the thing that could help you the most is a dictionary. A dictionary is an alphabetically arranged listing of words that contains various information about those words, such as their definitions, examples, origin, pronunciation, etc.
The term the given definition refers to is topographical. Topography is the study of the forms and features of land surfaces. The topography of an area refers to its physical properties and terrain or their description (e.g. how they're shown on a map).
Which is a valid reason why total dissolved solids (TDS) cannot be accurately calculated by conductivity alone?
Global warming has significantly increased the conductivity of water.
Big blobs of algae do not conduct electricity.
Fish poop changes the conductivity.
Ionic compounds may behave differently based on ion characteristics (e.g. charge or size).
Some dissolved solids may be nonelectrolytes.
Answer:
The correct option is the last option (Some dissolved solids may be nonelectrolytes)
Explanation:
Total dissolved solids (TDS) cannot be calculated by conductivity alone because conductivity involves ionic charges and there are solids that dissolve in water but do not carry ionic charges (and thus form non-electrolytes). Examples include sucrose (common sugar) and glucose. These two solids will dissolve in water but would not form ions that will carry ionic charges which are responsible for conductivity. Thus, if TDS only depends solely on conductivity, then a solution that contains dissolved sucrose will be wrongly accounted for as the sucrose will be omitted from the dissolved substances.
A valid reason why total dissolved solids (TDS) cannot be accurately
calculated by conductivity alone because some dissolved solids may be
non-electrolytes.
Conductivity means the ability of electric current to pass through a
substance and an electrolyte has a high conductivity when dissolved in
water.
Dissolved solids can't be measured by conductivity because not all
dissolved solids are electrolytes.
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In an aqueous solution, a 0.100 M solution of glucose is prepared with a total volume of 0.150 Liters. If the molar mass of glucose is 180.16 g/mol how many grams must the solution contain?
Answer:
2.70 g of glucose.
Explanation:
The following data were obtained from the question:
Molarity of the glucose solution = 0.1 M
Volume of solution = 0.15 L
Molar mass of glucose = 180.16 g/mol
Mass of glucose =.?
Next, we shall determine the number of mole of glucose in the solution. This can be obtained as follow:
Molarity of the glucose solution = 0.1 M
Volume of solution = 0.15 L
Mole glucose =?
Molarity = mole /Volume
0.1 = Mole of glucose /0.15
Cross multiply
Mole of glucose = 0.1 × 0.15
Mole of glucose = 0.015 mole
Finally, we shall determine the mass of glucose in the solution as follow:
Mole of glucose = 0.015 mole
Molar mass of glucose = 180.16 g/mol
Mass of glucose =.?
Mole = mass /molar mass
0.015 = mass of glucose /180.16
Cross multiply
Mass of glucose = 0.015 × 180.16
Mass of glucose = 2.70 g
Therefore, the solution contains 2.70 g of glucose.
The grams that the solution must contain is :
- 2.70 g of glucose.
Mole ConceptGiven:
Molarity of the glucose solution = 0.1 M
Volume of solution = 0.15 L
Molar mass of glucose = 180.16 g/mole
Molarity of the glucose solution = 0.1 M
Volume of solution = 0.15 L
Molarity = mole /Volume
0.1 = Mole of glucose /0.15
Mole of glucose = 0.1 × 0.15
Mole of glucose = 0.015 mole
Mole of glucose = 0.015 mole
Molar mass of glucose = 180.16 g/mol
Mass of glucose =.?
Mole = mass /molar mass
0.015 = mass of glucose /180.16
Mass of glucose = 0.015 × 180.16
Mass of glucose = 2.70 g
The solution contains 2.70 g of glucose.
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410X
412
412
410
183
186
183R
Which two are isotopes?
Hat is the answer for this
Answer:
C
Explanation:
Answer:
I think is A
Explanation:
Hope it helps
What two subatomic particles add up to make the mass?
very
Which of the
following mineral
characteristics are
associated with
gold?
A. it is a compound
B. it is made of many elements
C. it is man made
D. it is a solid
Answer:
D,B
Explanation:
there are 79 elements in gold
Which is the Lewis structure for H3PO4? An upper P is single bonded above to an O, and to the left, right, and below to an O single bonded to an H. The O above the P has three pairs of dots to the left, above, and below; the O's to the sides have pairs of dots above and below, and the O below the P has pairs of dots right and left. A central upper P is single bonded left, right, above, and below to upper Os. The O above the P is single bonded to upper H on the left and the right, and has two electron dots above it. The O below the P is single bonded to an H below, and has pairs of electron dots to the left and right. A central upper P is double bonded to an O above, and single-bonded to an upper O single-bonded to an upper H to the left and the right. The O above the P has three pairs of electron dots, to the left, above, and to the right; the O's to the right and left have pairs of dots above and below. A central upper P is bonded to an upper H above, an upper O below, and upper O's bonded to upper H's to the left and the right. The O below the P has three pairs of electron dots, to the left, right, and below; the other two O's have pairs of dots above and below. A central upper P is double bonded to an O above, and single-bonded to an upper O single-bonded to an upper H to the left and the right. The O above the P has three pairs of electron dots, to the left, above, and to the right; the O's to the right and left have pairs of dots above and below.
Answer:
It is A.
Explanation:
I took the test.
The Lewis structure shows the arrangement of valence electrons in H3PO4.
The Lewis structure gives us a picture of the number of valence electrons in a molecule. This is because, in a Lewis structure, the electrons in the molecule are shown as dots. A single line may be used to show shared electrons in a covalent bond.
The correct Lewis structure of H3PO4 is an upper P is single bonded above to an O, and to the left, right, and below to an O single bonded to an H. The O above the P has three pairs of dots to the left, above, and below; the O's to the sides have pairs of dots above and below, and the O below the P has pairs of dots right and left.
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If 8.500 g CH is burned and the heat produced from the burning is added to 5691 g of water at 21 °C, what is the final
temperature of the water?
The final temperature = 36 °C
Further explanationThe balanced combustion reaction for C₆H₆
2C₆H₆(l)+15O₂(g)⇒ 12CO₂(g)+6H₂O(l) +6542 kJ
MW C₆H₆ : 78.11 g/mol
mol C₆H₆ :
[tex]\tt \dfrac{8.5}{78.11}=0.109[/tex]
Heat released for 2 mol C₆H₆ =6542 kJ, so for 1 mol
[tex]\tt \dfrac{0.109}{2}\times 6542=356.539~kJ/mol[/tex]
Heat transferred to water :
Q=m.c.ΔT
[tex]\tt 356.539=5.691~kg\times 4.18~kj/kg^oC\times (t_2-21)\\\\t_2-21=15\rightarrow t_2=36^oC[/tex]
How does the number of atoms or molecules in a system affect its thermal energy?
A. A system with fewer atoms and molecules has more thermal energy.
B. A system with more atoms and molecules has more thermal energy.
C. The number of atoms or molecules does not affect the thermal energy of a system.
D. Thermal energy increases as the atoms and molecules in a system move more.
Answer:
D. Thermal energy increases as the atoms and molecules in a system move more.
Explanation:
Thermal energy is a form of kinetic energy possessed by molecules of a system. The measure of this kinetic energy in an atom is called heat.
The average kinetic energy of a system is the temperature.
According to the kinetic theory, the more the particles move, the more their thermal energy. Thermal energy is often predicated on the velocity of the particles of the medium.1. Sugar in a jar has a volume of 750 cubic centimeters and a mass of 690 grams.
Calculate its density. Write your answer to the hundredths place.
Answer:
The answer is 0.92 g/cm³Explanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\ [/tex]
From the question we have
[tex]density = \frac{690}{750} = \frac{69}{75} = \frac{23}{25} \\ [/tex]
We have the final answer as
0.92 g/cm³Hope this helps you
Determine the volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of
aluminum to produce aluminum sulfate.
Answer:
167 mL.
Explanation:
We'll begin by calculating the number of moles in 45 g of aluminum (Al). This can be obtained as follow:
Mass of Al = 45 g
Molar mass of Al = 27 g/mol
Mole of Al =?
Mole = mass /Molar mass
Mole of Al = 45/27
Mole of Al = 1.67 moles
Next, the balanced equation for the reaction. This is given below:
2Al + 3H2SO4 → Al2(SO4)3 + 3H2
From the balanced equation above,
2 moles of Al reacted with 3 moles of H2SO4.
Next, we shall determine the number of mole of H2SO4 needed to react with 45 g (i.e 1.67 moles) of Al. This can be obtained as:
From the balanced equation above,
2 moles of Al reacted with 3 moles of H2SO4.
Therefore, 1.67 moles of Al will react with = (1.67 × 3)/2 = 2.505 moles of H2SO4.
Thus 2.505 moles of H2SO4 is needed for the reaction.
Next, we shall determine the volume of H2SO4 needed for the reaction. This can be obtained as follow:
Molarity of H2SO4 = 15.0 M
Mole of H2SO4 = 2.505 moles
Volume =?
Molarity = mole /Volume
15 = 2.505 / volume
Cross multiply
15 × volume = 2.505
Divide both side by 15
Volume = 2.505/15
Volume = 0.167 L
Finally, we shall convert 0.167 L to mL. This can be obtained as follow:
1 L = 1000 mL
Therefore,
0.167 L = 0.167 L × 1000 mL / 1 L
0.167 L = 167 mL
Thus, 0.167 L is equivalent to 167 mL.
Therefore, 167 mL H2SO4 is needed for the reaction.
________________naturally helps cold-blooded animals warm up so that they can function.
Question 5 options:
Radiation
Convection
Warm Water
Heating pad
Answer:
Warm Water
Explanation:
In warm temperatures, cold-blooded animals are more active and can travel more quickly. This occurs because heat activated reactions provide energy to move muscles. In the absence of heat the animal becomes slow and sluggish. So they are usually inactive and rest when it is cold. As they do not need to feed much, they spend less time looking for food, so this life strategy works for them.
Brainliest?
Answer warm water Explanation:i have the same question
The density of a substance is 1.63 grams per milliliter. What is the volume, in ml, of a sample of the substance with a mass of 5.40Kg? 1000 g = 1 kg
Answer:
############################
Explanation:
Question 1 (1 point)
A chemical reaction is when substances are changed into other substances.
True or False
How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?
a. 45 mL of a 0.10 M solution:
mL
b. 330 mL of a 0.074 M solution:
mL
Answer:
a. Approximately [tex]1.3\; \rm mL[/tex].
b. Approximately [tex]7.2\; \rm mL[/tex].
Explanation:
The unit of concentration "[tex]\rm M[/tex]" is equivalent to "[tex]\rm mol \cdot L^{-1}[/tex]", which means "moles per liter."
However, the volume of both solutions were given in mililiters [tex]\rm mL[/tex]. Convert these volumes to liters:
[tex]\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L[/tex].
[tex]\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L[/tex].
In a solution of volume [tex]V[/tex] where the concentration of a solute is [tex]c[/tex], there would be [tex]c \cdot V[/tex] (moles of) formula units of this solute.
Calculate the number of moles of [tex]\rm NaCl[/tex] formula units in each of the two solutions:
Solution in a.:
[tex]n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol[/tex].
Solution in b.:
[tex]n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol[/tex].
What volume of that [tex]3.4\; \rm M[/tex] (same as [tex]3.4 \; \rm mol \cdot L^{-1}[/tex]) [tex]\rm NaCl[/tex] solution would contain that many
For the solution in a.:
[tex]\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L[/tex].
Convert the unit of that volume to milliliters:
[tex]\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL[/tex].
Similarly, for the solution in b.:
[tex]\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L[/tex].
Convert the unit of that volume to milliliters:
[tex]\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL[/tex].
the illustration shows how sonar can be used to study the deep ocean which type of waves does sonar use
Answer:
d
Explanation:
Is mass conserved when 40 g of sodium hydroxide undergoes a chemical change during an interaction with 37g of hydrogen chloride? Use complete sentences to support your answer by explaining how this can be demonstrated. (10 points)
Answer:
Mass is conserverd
Explanation:
Any chemical reaction must follow the law of conservation of mass. Meaning that mass cannot be created nor destroyed. Since all chemical reactions must follow this law, no matter what reaction happens, mass is conserved.
HURRY PLEASE HELP
Four students are discussing the benefits and problems associated with using nuclear energy as alternative energy source. Which student has the strongest argument about using nuclear energy?
A. Nuclear power plants pollute the environment and causes cancer in populations that use nuclear energy instead of traditional electricity.
B. Nuclear power plants provide more energy than traditional coal plants; however, nuclear power plants also produce more greenhouse gases.
C. Nuclear power plants run a high risk of nuclear meltdown killing all the organisms in a 20 mile radius.
D. Nuclear power plants provide more energy than traditional coal plants and these plants do not produce greenhouse gases.
Answer:
A
Explanation:
its A
facts o.o
Nuclear power plants pollute the environment and causes cancer in populations that use nuclear energy instead of traditional electricity. Hence option A is correct.
What is nuclear power plant?Nuclear power plant is defined as a particular kind of power plant that produces electricity by nuclear fission. Nuclear power plants use the heat generated by nuclear fission to transform water into steam in a controlled environment, which then powers generators to produce electricity. Low-enriched uranium fuel is used in nuclear power plants to generate electricity through a process known as fission, which involves breaking uranium atoms in a nuclear reactor.
A clean energy source with no emissions is nuclear. It produces energy by fission, which is the splitting of uranium atoms to release energy. Without the toxic consequences that come from burning fossil fuels, electricity is produced using the heat from fission to produce steam, which turns a turbine.
Thus, nuclear power plants pollute the environment and causes cancer in populations that use nuclear energy instead of traditional electricity. Hence option A is correct.
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#SPJ2
the layering of rock horizontally is for the __________ only.
A. relative age
B. same age
C. absolute age
Answer:
A
Explanation:
A sample is found to contain 2.98x10^-10 g of salt. Express this quantity in nanograms.
This quantity = 0.298 nanograms(ng)
Further explanationMass is one of the principal quantities, which is related to the matter in the object
The main mass unit consists of 7 units of other than other units of mass such as quintals, tons, pounds, ounces:
Kilogram, kg
Hectogram, hg
Decagram, dag
gram, g
Desigram, with
centigram, cg
milligram, mg
Each unit descends then multiplied by 10, and if one unit increases then divided by 10
Conversion of other mass units:
10⁻³ g ⇒mg-milligrams
10³ g ⇒kg-kilograms
10⁻⁶ g ⇒µg-micrograms (mcg)
10⁶ g ⇒Mg-megagrams (tons)
10⁻⁹ g ⇒ng-nanograms
10⁹ g ⇒Gg-gigagram
10⁻¹² g ⇒pg-pikogram
2.98 x 10⁻¹⁰ g to nanograms(ng)
[tex]\tt 2.98\times 10^{-10}\times 10^9=0.298~ng[/tex]
5. Psilocybin is made of C 50.70%, H 6.03%, N 9.86%, 22.51%, P 10.90%. a. Find the empirical formula.
The empirical formula : C₁₂H₁₇N₂O₄P
Further explanationThe empirical formula is the smallest comparison of atoms of compound =mole ratio of the components
The principle of determining empirical formula
Determine the mass ratio of the constituent elements of the compound. Determine the mole ratio by by dividing the percentage by the atomic massC
[tex]\tt \dfrac{50.7}{12}=4.225[/tex]
H[tex]\tt \dfrac{6.03}{1}=6.03[/tex]
N[tex]\tt \dfrac{9.86}{14}=0.704[/tex]
O[tex]\tt \dfrac{22.51}{16}=1.407[/tex]
P[tex]\tt \dfrac{10.9}{31}=0.352[/tex]
Divide by the smallest mole ratio(0.352)
C : H : N : O : P
[tex]\tt C\rightarrow \dfrac{4.225}{0.352}=12[/tex]
[tex]\tt H\rightarrow \dfrac{6.03}{0.352}=17[/tex]
[tex]\tt N\rightarrow \dfrac{0.704}{0.352}=2[/tex]
[tex]\tt O\rightarrow \dfrac{1.407}{0.352}=4[/tex]
[tex]\tt P\rightarrow \dfrac{0.352}{0.352}=1[/tex]
22. In 4f12, the 12 stands for the
The 12 stands for the number of electrons that fill the f orbital
Further explanationIn an atom there are levels of energy in the shell and sub shell
This energy level is expressed in the form of electron configurations.
Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f. The maximum number of electrons for each sub shell is
• s: 2 electrons
• p: 6 electrons
• d: 10 electrons and
• f: 14 electrons
4f¹² :
4 : number of shell
12 : the number of electrons that fill the f orbital
11) Nitrogen oxides undergo many interesting reactions in the environment and in industry. Given the following information, calculate H for the overall equation:
2 NO2(g) + 1/2 O2(g) N2O5(s).
N2O5(s) 2 NO(g) + 3/2 O2(g), deltaH = 223.7 kJ
NO2(g) NO(g) + 1/2 O2(g), delataH = 57.1 kJ
delataH = ______kJ
12))))Write all coefficients, even if they are fractions or 1.)
(a) (Apply fractions as needed.)
______ _____(s) + ______ ______ (g) 5 NaCl(s)
(b) (Use the lowest possible coefficients.)
_______ _____ (s) + ______ _____(g) _____CaCl2(s)
(c) (Apply fractions as needed.)
_____ _____(g) _____O3(g)
(d) (Apply fractions as needed.)
______Mg(s) + _____ ______(s) + _____ ____(g) _____Mg3(PO4)2(s)
Answer:
one more time
Explanation:
shpuld i go