Which one of the following produces hydrogen ions in a water solution?
A. Acids
B. Bases
C. Hydroxide ions
D. Chemical compounds

Answer:

Explanation:

Yes , it is a redox reaction .

3O₂ + 4Fe → 2Fe₂O₃.

Increase of oxidation number shows oxidation and decrease of oxidation number shows reduction .

Neutral atoms have zero oxidation number .

O₂ and Fe are neutral atoms so their oxidation number is zero.

In Fe₂O₃ , charge on each Fe atom is + 3 . So its oxidation number is + 3 . Similarly charge on each of O in this compound is - 2 . So its oxidation number is -2 .

Oxidation number of Fe increases from 0 to + 3 . Hence it is oxidized .

Oxidation number of O decreases from 0 to  -2  . Hence it is reduced  .

Fe is oxidized by O ( oxygen ) so oxygen is the oxidizing agent .

O is reduced  by Fe ( iron  ) so iron  is the reducing agent .

Answer: Only one molecular structure is possible.

Answer:

Explanation:

The atomic number of uranium (see periodic table) is 92, and the mass number of the isotope is given as 238. Therefore, it has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons

Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5. The number of neutrons can vary from 141 to 146.

Chemical element uranium has the atomic number 92 and the letter U. It is an actinide metal in the periodic table's silvery-gray series. There are 92 protons and 92 electrons in an atom of uranium, of which 6 are valence electrons.

Since uranium has an atomic number of 92, its atomic structure consists of 92 protons and 92 electrons. The nucleus of U-238 contains 146 neutrons, but this number can range from 141 to 146.

With 92 protons and 146 neutrons, Uranium-238 is the heaviest element in nature. The overall mass and charge of the nucleus are 238 nucleons, or +92.

Thus, Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5.

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[tex]\text{N}_{2}\text{O}_{3}=\text{nitrogen trioxide}\\\text{N}_{2}=\text{nitrogen}\\\text{O}_{2}=\text{oxygen}[/tex]

Answer:

3.3 * 10^-12

Explanation:

The balanced equation of the reaction is;

2H+(aq) + Cu(s) ---------> H2(g) + Cu2+(aq)

Hence two electrons were transferred so n=2

E°cell = E°cathode - E°anode

E°cell = 0 V - 0.34 V

E°cell = - 0.34 V

Then;

E°cell = 0.0592/n log K

Substituting values;

- 0.34 = 0.0592/2 log K

- 0.34/0.0296 = log K

-11.486 = log K

K = Antilog (-11.486)

K = 3.3 * 10^-12

Answer:

it is already balanced

c5h12+8O2-->5CO2 +6h2o

Explanation:

Answer:

91.41 g of LiClO₃.

Explanation:

We'll begin by calculating the number of mole of O₂ that occupied 33.8 L. This can be obtained as follow:

22.4 L = 1 mole of O₂

Therefore,

33.8 L = 33.8 L × 1 mole / 22.4 L

33.8 L = 1.51 mole of O₂

Next, the balanced equation for the reaction.

2LiCl + 3O₂ —> 2LiClO₃

From the balanced equation above,

3 moles of O₂ reacted to produce 2 moles of LiClO₃.

Therefore, 1.51 mole of O₂ will react to produce = (1.51 × 2)/3 = 1.01 mole of LiClO₃.

Finally, we shall determine the mass of 1.01 mole of LiClO₃. This can be obtained as follow:

Mole of LiClO₃ = 1.01 mole

Molar mass of LiClO₃ = 7 + 35.5 + (3×16)

= 7 + 35.5 + 48

= 90.5 g/mol

Mass of LiClO₃ =?

Mass = mole × molar mass

Mass of LiClO₃ = 1.01 × 90.5

Mass of LiClO₃ = 91.41 g

Thus, 91.41 g of LiClO₃ were obtained from the reaction.

The heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ

From the question, we are to calculate the heat of reaction for the reaction

2H₂O₂ → 2H₂O +O₂               ∆H=?

Using Hess's law

Hess's Law of constant heat summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes

From the given equations,

2H₂ +O₂ → 2H₂O                   ∆H= -572 KJ ---------- (1)

2H₂O₂ → 2H₂ + 2O₂              ∆H= 376 KJ ----------- (2)

Adding equations (1) and (2), we get

2H₂O₂ → 2H₂O +O₂               ∆H= -572 KJ + 376 KJ

2H₂O₂ → 2H₂O +O₂               ∆H= -196 KJ

Hence, the heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ.

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Answer: The pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.

Explanation:

Given: Pressure = 12.2 psi

According to the standard conversion of units, 14.7 psi = 1 atm = 760mmHg.

Therefore, 1 psi equal to how many mm Hg is calculated as follows.

[tex]14.7 psi = 760 mm Hg\\1 psi = \frac{760}{14.7} mm Hg\\= 51.7149 mm Hg[/tex]

Hence, 12.2 psi will be converted into mm Hg as follows.

[tex]1 psi = 51.7149 mm Hg\\12.2 psi = 12.2 psi \times \frac{51.7149 mm Hg}{1 psi}\\= 630.9221 mm Hg[/tex]

Thus, we can conclude that the pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.

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b. a positive cation and a negative anion

✏ Anions are negative in nature while cations are positive in nature. Together they come together by an attractive electrostatic force to form an ionic bond.

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Answer:

2.13 M

Explanation:

To solve this problem we need to keep in mind the definition of molarity:

As the problem gives us both the number of moles and the volume of solution, we can proceed to calculate the molarity:

The answer is 2.13 M.

Answer:

C. A scientific approach to answering questions

Explanation:

Answer:

[tex]V_2=4667mL[/tex]

Explanation:

Hello there!

In this case, based on the given information, it is possible for us to provide an answer to this question by using the Boyle's law as directly proportional relationship between volume and pressure:

[tex]P_2V_2=P_1V_1[/tex]

Thus, by solving for the final volume, V2, as required, we obtain the following:

[tex]V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{5,000mL*742atm}{795atm}\\\\V_2=4667mL[/tex]

Regards!

Answer: Element is P, phosphor

Explanation:  Phosphor has oxidation number -III and it has 15 protons. So it is possible to have 16 neutrons. Other elements having oxidation number -III are N and As which can not have an isotope with 16 neutrons.

Answer:  Molality = concentration = 0,33 mol/l

Explanation: Concentration c = n/V   and  n = m/M

M = 55,44 g/mol  and m = 1.9 g , V = 0.100 l

c = m/(MV)

Explanation:

Ionic product of water, Kw

[tex]Kw = [OH {}^{ - } ][H _{3} O {}^{ + } ] \\ 1.0 \times {10}^{ - 14} = (1 \times {10}^{ - 11} )[H _{3} O {}^{ + } ] \\ [H _{3} O {}^{ + } ] = \frac{(1.0 \times {10}^{ - 14}) }{(1 \times 10 {}^{ - 11}) } \\ ][H _{3} O {}^{ + } ] = 0.001 \: M[/tex]

Answer:

Explanation:

u are right

Answer:

An icicle

Explanation:

An icicle is heavier and has more mass making it fall quicker then a smaller and lighter item like a snow flake.

Answer:

108 g

Explanation:

First we convert 6.00 moles of H₂ into moles of H₂O, using the stoichiometric coefficients of the reaction:

Then we can convert 6.00 moles of H₂O into grams, using the molar mass of water:

The answer is 108 grams of water.

Answer: Hello,  there! your Answer is Below

My Answer Would be A. Two

Explanation:

Structural Isomers are molecules which have the same molecular formula but have different connectivities

Hope this helps you!!

Have a great day!!!

Answer:

answer is what is the pH number is that Our New account last name is Our brothers name he will be happy to

The pOH of the solution is 10.4

The pH of the solution is 3.6

From the question, we are to determine the pOH and pH of the solution

pOH can be calculated by using the formula

pOH = -log[OH⁻]

From the question,

[OH⁻] = 4×10⁻¹¹ M

∴ pOH = -log(4×10⁻¹¹)

pOH = 10.4

Hence, the pOH of the solution is 10.4

Now, for the pH

Using the formula,

pH + pOH = 14

Then, we can write that

pH = 14 - pOH

∴ pH of the solution is

pH = 14 - 10.4

pH = 3.6

Hence, the pH of the solution is 3.6

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Answer:

A basic solution such as hydroxyls

Answer:

A. 4-ethyl-hex-3,5-dien-2-ol.

B. 2-chloro-3-methyl-5-tert-butylphenol.

Explanation:

Hello there!

In this case, according to the given problems, it is possible to apply the IUPAC rules to obtain the following names:

A. 4-ethyl-hex-3,5-dien-2-ol because we have an ethyl radical at the fourth carbon and the beginning of the parent chain is on the Me (CH3) because it is closest to first OH.

B. 2-chloro-3-methyl-5-tert-butylphenol: because we start at the alcohol and have a chlorine atom on the second carbon, a methyl radical on the third carbon, a tert-butyl on the fifth carbon and the parent chain is benzene which is phenol as an alcohol.

Regards!

Answer: (a) The products are [tex]Be(NO_{3})_{2}[/tex] and AgCl. The balanced equation is [tex]BeCl_{2}(aq) + 2AgNO_{3}(aq) \rightarrow Be(NO_{3})_{2}(aq) + 2AgCl(s)[/tex].

(b) The type of reaction is double displacement reaction.

Explanation:

(a) The complete reaction equation will be as follows.

[tex]BeCl_{2}(aq) + 2AgNO_{3}(aq) \rightarrow Be(NO_{3})_{2}(aq) + 2AgCl(s)[/tex]

Number of atoms on reactant side are as follows.

Number of atoms present on product side are as follows.

Here, number of atoms on both reactant and product side are the same. Hence, it is a balanced chemical equation.

(b) A reaction in which two reactant species tend to change their ions with each other and form new compounds. This type of reaction is called double displacement reaction.

As the given reaction is as follows.

[tex]BeCl_{2}(aq) + 2AgNO_{3}(aq) \rightarrow Be(NO_{3})_{2}(aq) + 2AgCl(s)[/tex]

This shows that ions are being exchanges by the reactants [tex]BeCl_{2}[/tex] and

[tex]AgNO_{3}[/tex]. The ions are [tex]Be^{2+}[/tex], [tex]Cl^{-}[/tex], [tex]Ag^{2+}[/tex] and [tex]NO^{2-}_{3}[/tex].

Therefore, this reaction is a double displacement reaction.

The elemental particles like the atoms, molecules and compounds present in a given substance is called an Avogadro's number. This number is expressed as [tex]N_{A}[/tex] and is equal to [tex]6.022 \times 10^{23} \;\rm mol^{-1}[/tex].

[tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].

Given,

We have 135 g, so moles will be:

[tex]\begin{aligned}\rm Moles (n) &=\dfrac{ \rm Mass }{\;\rm Molar \;\rm mass}\\\\\rm n &= \dfrac{135 \rm g }{100.02 \rm g/mol} \\\\\rm n &= 1.34 \;\rm mole\end{aligned}[/tex]

Hence,

1 mole contains [tex]6.022140857 \times 10^{23}[/tex] (Avogadro's number)

So 1.34 moles will contain,

[tex]\begin{aligned}&=1.34 \times 6.022140857 \times 10^{23}\\\\&= 8.06 \times 10 ^{23}\;\rm molecules\end{aligned}[/tex]

Therefore, [tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].

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Answer:

I don't know.

Explanation:

I actually don't know the answer so I wrote the answer is "I don't know" or simply "I dunno".