Answer:
Special land use basically include all land parcels that cannot be defined in terms of residential and commercial land uses.
Answer:
Applying pesticides
Explanation:
there is a limit on the use of pesticides and it is the only one that is truly applied water is naturally occuring same with rocks and trees and you are applying things to the soil not the other way around
A 3.0 kg object moving 8.0 m/s in the positive x-direction has a one-dimensional elastic collision with an object of mass, M, initially at rest. After the collision the object of unknown mass has a velocity of 6.0 m/s in the positive x direction. What is M
Answer:
1kgExplanation:
According to law of conservation of momentum
m1u1+ m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are their initial velocities
v is their common velocity
Given
m1 = 3kg
m2 = M
u1 = 8m/s
u2 = 0m/s (object at rest)
v = 6.0m/s
Substitute and get M
3(8) + M(0) = (3+M)6
24 = 18+6M
24-18 = 6M
6 = 6M
M = 1kg
Hence the mass M is 1kg
Which kind of wave interaction is shown?
Answer:
where?
Explanation:
ill edit my answer when see it
If a 25 kg lawnmower produces 347 w and does 9514 J of work, for
how much time did the lawnmower run?
Steps 1 and 2)
The variables are W = work, P = power, and t = time. In this case, W = 9514 joules and P = 347 watts.
The goal is to solve for the unknown time t.
-----------------------
Step 3)
Since we want to solve for the time, and we have known W and P values, we use the equation t = W/P
-----------------------
Step 4)
t = W/P
t = 9514/347
t = 27.4178674351586
t = 27.4 seconds
-----------------------
Step 5)
The lawn mower ran for about 27.4 seconds. I rounded to three sig figs because this was the lower amount of sig figs when comparing 9514 and 347.
-----------------------
Note: we don't use the mass at all
One atomic mass unit is defined as 1.66 x 10^-27 kg. If a proton has a mass of one atomic mass unit and a density of approximately 5.8 x 10^27 kg/m3^ . What is the diameter of a proton if we assume it is a sphere?
Answer:
The diameter is [tex]d = 8.18*10^{-19} \ m[/tex]
Explanation:
From the question we are told that
The value of one atomic mass unit is [tex]u = 1.66 *10^{-27} \ kg[/tex]
The density of the proton is [tex]\rho = 5.8 *10^{27} \ kg/m^3[/tex]
Generally the volume of the proton (sphere)is mathematically represented as
[tex]V = \frac{4}{3} * \pi * r^3[/tex]
Generally this volume can also be evaluated as
[tex]V = \frac{u}{\rho}[/tex]
=> [tex]V = \frac{1.66 *10^{-27}}{5.8*10^{27}}[/tex]
=> [tex]V = 2.862 *10^{-55} \ m^3[/tex]
So
[tex]2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3[/tex]
=> [tex]r^3 = 6.832 *10^{-56}[/tex]
=> [tex]r = 4.088 *10^{-19} \ m[/tex]
Now the diameter is mathematically represented as
[tex]d = 2 * r[/tex]
=> [tex]d = 2 * 4.088 *10^{-19}[/tex]
=> [tex]d = 8.18*10^{-19} \ m[/tex]
Bru challenge with the physics.
Answer:
WHATATATATTAT
Explanation:
What is the main function of an earthworm organ
Answer:
brain
Explanation:
brain and blood
Two balls collide in a head-on elastic collision and rebound in opposite directions. One ball has velocity 1.2 m/s before the collision, and −2.3 m/s after. The other ball has a mass of 1.1 kg and a velocity of −4.2 m/s before the collision. (a) What is the mass of the first ball? (b) What is the velocity of the second ball after the collision?
Answer:
If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .
Explanation:
Mark me as brainliest and follow me
Our school needs to offer healthier options in the lunchroom. Elever High School has recently updated its cafeteria menu to include whole wheat pasta and breads, a fresh salad bar, and other healthy menu items. Students there claim that they have more energy and focus throughout their school day. Let's encourage healthier menus in our lunchroom!
What type of evidence does the writer of this passage use to support her claim?
statistics
statistics
an expert's opinion
an expert's opinion
examples
examples
the writer's opinion
Answer:
b
Explanation:
A 1400 kg car traveling in the positive direction takes 11.0 seconds to slow from 25.0 meters per second to 12.0 meters per second. What is the average force on the car during this time?
Answer:
–1652 N. The negative sign indicate that the force is in opposite direction to car.
Explanation:
The following data were obtained from the question:
Mass (m) of car = 1400 kg
Time (t) = 11 s
Initial velocity (u) = 25 m/s
Final velocity (v) = 12 m/s
Force (F) applied on the car =?
Next, we shall determine the acceleration of the car. This can be obtained as follow:
Time (t) = 11 s
Initial velocity (u) = 25 m/s
Final velocity (v) = 12 m/s
Acceleration (a) =?
a = (v – u) /t
a = (12 – 25) /11
a = –13/11
a = –1.18 m/s²
Finally, we shall determine the force on the car as follow:
Acceleration (a) = –1.18 m/s²
Mass (m) of car = 1400 kg
Force (F) applied on the car =?
F = ma
F = 1400 × –1.18
F = –1652 N
Thus, the force on the car is –1652 N. The negative sign indicate that the force is in opposite direction to car.
The rotational inertia of a thin rod about one end is 1/3 ML2. What is the rotational inertia of the same rod about a point located 0.40 L from the end
Answer:
The value is [tex]I = 0.0932 ML ^2[/tex]
Explanation:
From the question we are told that
The rotational inertia about one end is [tex]I_R = \frac{1}{3} ML^2[/tex]
The location of the axis of rotation considered is [tex]d = 0.4 L[/tex]
Generally the mass of the portion of the rod from the axis of rotation considered to the end of the rod is [tex]0.4 M[/tex]
Generally the length of the rod from the its beginning to the axis of rotation consider is
[tex]k = 1 - 0.4 L = 0.6L[/tex]
Generally the mass of the portion of the rod from the its beginning to the axis of rotation consider is
[tex]m = 1- 0.4 M = 0.6 M[/tex]
Generally the rotational inertia about the axis of rotation consider for the first portion of the rod is
[tex]I_{R1} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]
[tex]I_{R1} = \frac{1}{3} (0.6 M )L^2 0.6^2[/tex]
Generally the rotational inertia about the axis of rotation consider for the second portion of the rod is
[tex]I_{R2} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]
=> [tex]I_{R2} = \frac{1}{3} (0.4 M )(0.4L)^2[/tex]
=> [tex]I_{R2} = \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]
Generally by the principle of superposition that rotational inertia of the rod at the considered axis of rotation is
[tex]I = \frac{1}{3} (0.6 M )L^2 0.6^2 + \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]
=> [tex]I = \frac{1}{3} ML ^2 [0.6 * (0.6)^2 + 0.4 * (0.4)^2 ][/tex]
=> [tex]I = 0.0932 ML ^2[/tex]
Describe the difference between simply taking measurements and doing a scientific experiment.
In 2-3 sentences
A piece of wood from a nearby construction site floats near the shore of a lake. It floats in very calm water with half of its volume just above the surface. What is the density of this piece of wood
Answer:
Explanation:
The density of a substance can be described as the mass per volume of the substance. The density of the piece of wood described in the question can be calculated as the mass of the wood divided by the volume of the water the wood displaced (which was referred to in the question as making half of the wood's volume i.e half of the thickness of the wood was in the water).
How do you calculate the net force when there are multiple forces in different directions?
To find [tex]F_{net}[/tex] we need to use vector addition and use the x and y components. First we subtract vector 2 from vector 5 which results in a vector with a length of 3 pointing directly east, then we use the distance formula to find the length of the net force [tex]F_{net} = \sqrt{(3)^2+(4)^2} \\[/tex] which gives [tex]F_{net} = 5[/tex]. We now have a magnitude but we also need a direction, since vector 4 and vector 5 are perpendicular. Using [tex]\theta = \tan^{-1} (\frac{4}{3})[/tex] where tan^-1(y/x) we get an angle of 53 degrees. The resultant force vector is 5 distance with an angle of 53 degrees north east.
Is any force exerted on the vertical sides of the loop that you used in the experiment and how does it affect the apparent mass?
a. There is a force exerted on each side of the loop that are equal in magnitude and opposite in direction.
b. No force is exerted on the sides of the loop.The lengths of the sides of the loop are much smaller than the bottom section and therefore the force on the sides are negligible.
c. The force on the sides are not in the same direction in which the mass is measured and therefore it does not affect the results.
d. The force exerted on the sides of the loop cancel each other out.
The force on the sides is not in the same direction in which the mass is measured and therefore it does not affect the results. Option c is correct.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The force on the sides does not alter the results since it is not in the same direction as the mass being measured. The forces acting on the loop's sides cancel one another out.
The force on the sides is not in the same direction in which the mass is measured and therefore it does not affect the results.
Hence option c is correct.
To learn more about the force refer to the link;
https://brainly.com/question/26115859
answer pls urgent pls
Answer:
record vibrations of earthquake
Answer:
[tex]\huge\boxed{\sf Option \ 2}[/tex]
Explanation:
Seismograph is an instrument with is used to record vibrations of earthquake.
Seismographs are basically used to detect seismic waves by which scientists can detect the earth's interior and also can find the depths of earthquakes and their intensity.
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AnonymousHelper1807You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
30°
110
34°
120
38°
128
42°
133
46°
127
50°
119
54°
109
At which angle will the performer travel the shortest distance?
A. 44°
B. 54
Ο Ο Ο Ο
C. 32
D. 50°
Answer:
128
Explanation:
Answer:
54 degrees
Explanation:
an inductive argument guarantees its conclusion
True
False
Answer:
False
Explanation:
inductive arguments have some evidence but do not have full assurance of truth of the conclusion
three properties of an ideal fluid that obey Bernoulli’s principle
Answer:
Bernoulli's theorem, in fluid dynamics, relation among the pressure, velocity, and elevation in a moving fluid (liquidor gas), the compressibility and viscosity (internal friction) of which are negligible and the flow of which is steady, or laminar.
Three properties of an ideal fluid that obey Bernoulli’s principle are :
1) incompressible
2) subjected to conservative forces
3) non - viscous
What is Bernoulli's principle ?Bernoulli's principle states that as the speed of moving fluid increases , the pressure within fluid decreases or it states that if the fluid flows horizontally so that no change in gravitational potential energy occurs, then a decrease in fluid pressure is associated with an increase in fluid velocity.
As we know that Bernoulli's principle is only valid for ideal fluids which have following properties :
1) Should be incompressible
2) subjected to conservative forces
3) It should be non - viscous which means there is no internal friction in the flow .
learn more about Bernoulli's principle :
https://brainly.com/question/2249706?referrer=searchResults
#SPJ3
a. With what speed must a ball be thrown vertically from ground level to rise to a maximum height of 45m?
b. How long will it be in the air?
Answer:
A. 29.7 m/s
B. 6.06 s
Explanation:
From the question given above, the following data were obtained:
Maximum height (h) = 45 m
A. Determination of the initial velocity (u)
Maximum height (h) = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 m/s (at maximum height)
Initial velocity (u) =.?
v² = u² – 2gh (since the ball is going against gravity)
0² = u² – (2 × 9.8 × 45)
0 = u² – 882
Collect like terms
0 + 882 = u²
882 = u²
Take the square root of both side
u = √882
u = 29.7 m/s
Therefore, the ball must be thrown with a speed of 29.7 m/s.
B. Determination of the time spent by the ball in the air.
We'll begin by calculating the time take to reach the maximum height. This can be obtained as follow:
Maximum height (h) = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) to reach the maximum height =?
h = ½gt²
45 = ½ × 9. 8 × t²
45 = 4.9 × t²
Divide both side by 4.9
t² = 45/4.9
Take the square root of both side
t = √(45/4.9)
t = 3.03 s
Finally, we shall determine the time spent by the ball in the air. This can be obtained as follow:
Time (t) to reach the maximum height = 3.03 s
Time (T) spent by the ball in the air =?
T = 2t
T = 2 × 3.03
T = 6.06 s
Therefore, the ball spent 6.06 s in the air.
who plays adopt me on rob.lox!! plz answer people only if you play though tell me your best pet and your user name so we can play!!
Answer: I don't do adopt me but I do have a Ro.blox username its Nvm i cant but my user name
Explanation:
Answer:
adopt me sucks but my best pet was an albino monkey I think or a king monkey
Explanation:
PLEASE PROVIDE AN EXPLANATION.
THANKS!!!
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
Suppose that the space shuttle Columbia accelerates at 14.0 m/s2 for 8.50 minutes after takeoff.
A. What will be the speed of the shuttle at the end of 8.50 minutes?
B. How far will the shuttle have traveled during this time?
Answer:
A. speed = 7.14 Km/s
B. distance = 1820.7 Km
Explanation:
Given that: a = 14.0 m/[tex]s^{2}[/tex], t = 8.50 minutes.
But,
t = 8.50 = 8.50 x 60
= 510 seconds
A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;
v = u + at
where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
u = 0
So that,
v = 14 x 510
= 7140 m/s
The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.
B. the distance traveled can be determined by applying second equation of motion.
s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]
where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.
u = 0
s = [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]
= [tex]\frac{1}{2}[/tex] x 14 x [tex](510)^{2}[/tex]
= 7 x 260100
= 1820700 m
The distance that the shuttle has traveled during the given time is 1820.7 Km.
A car starts from rest and uniformly acceleration to find speed of 20.0m/s in a time of 15.0 s . How far does the car travel during this time ?
Answer:
The answer is:
150 m
Explanation:
find acceleration first.
Vf = at + Vi
20 = a(15) + 0
a = 1.33m/s^2
x = 1/2at^2
x = 1/2 (1.33) (15)^2
x = 149.625m or round it to 150m
hope this helps
Answer:
1.33
Explanation:
We know
speed =distance travelled
time taken
so here distance travelled is 20.0 m/s
and time taken is 15.0s
now simplify
s=20.0/15.0
=4/3
=1.33
hope you understood it!
What is the difference in
momentum between a 0.216 kg bird
flying 5.87 m/s and a 7.29 kg baby
crawling 0.234 m/s?
Answer:
0.438kg/ms-¹
Explanation:
Momentum, denoted by p, can be calculated by using the formula;
p = mv
Where;
m = mass (kg)
v = velocity (m/s)
Momentum (p) of bird = 0.216 kg × 5.87 m/s = 1.268kg/ms-¹
Momentum (p) of crawling baby = 7.29 kg kg × 0.234 m/s = 1.706kg/ms-¹
Having calculated the momentum of the bird to be 1.268kg/ms-¹, and the momentum of the baby to be 1.706kg/ms-¹, the difference in momentum between the flying bird and the crawling baby is:
{1.706kg/ms-¹ - 1.268kg/ms-¹} = 0.438kg/ms-¹
What must happen to an atom of magnesium in order to become a magnesium ion Mg+2?
It must lose two neutrons and become a different isotope.
It must gain two neutrons and become a different isotope.
It must lose two electrons and become an ion.
It must gain two electrons and become an ion.
Answer:
Answer is: c. It must lose two electrons and become an ion.
Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).
Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.
Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.
Explanation:
Answer:
the third option
Explanation:
A 30kg boxed is pushed with a force of 20N. What is the boxes acceleration. Please show work
Answer:
The answer is 0.67 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{20}{30} = \frac{2}{3} \\ = 0.6666666...[/tex]
We have the final answer as
0.67 m/s²Hope this helps you
Which state of matter does this model represent?
Image of particles tightly packed
Solid
Liquid
Gas
Plasma
Answer:
gas
Explanation:
it is gas because the particles are floating up none of the above would be floating up.
Answer:
Solid
Explanation:
A: Solid- Solids have the particles tightly packed. They have a definite shape and volume
B: Liquid- Liquids have particles not to tightly packed but kind of loose. They have an indefinite shape but a definite volume
C: Gas- Gas has particles freely all around. Indefinite shape and volume
D: Plasma- Plasma is different and should be explained with an example; think of lighting....
Since the image shows tightly packed particles, it is clear the answer is a solid.
If a car is able to accelerate a 500kg truck at 50m/s^2 what is the force applied by the engine on the car? Please show work
Answer:
The answer is 25,000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 500 × 50
We have the final answer as
25,000 NHope this helps you
Answer:
Force applied by the engine on the car = 25 kN
Explanation:
Mass (m) = 500 kg
Acceleration (a) = 50 m/s²
The force (F) is equated to the product of the mass times the acceleration.
[tex] \boxed{ \bf{F = ma}}[/tex]
By substituting values, we get:
[tex] \longrightarrow [/tex] F = 500 × 50
[tex] \longrightarrow [/tex] F = 25000 N
[tex] \longrightarrow [/tex] F = 25 kN
What kind of food would you expect a turtle with a hard, sharp beak and short neck to eat?
MULTIPLE CHOICE
Newton’s first law of motion is also known as the law of ______ while the Newton’s 2nd law of motion is known as the law of _____ and Newton’s third law is also known as the law of ______
Answer:
1st law known as low of inertial
2nd law of acelaration and force relationship
3rd law of action and reaction