Which of these tables (if any) represent a proportional relationship?

The null hypothesis for the sample data set is given by H₀ : μ = 2 and the alternate hypothesis for the data is H₁ : μ > 2 .

a)H₀ : μ = 2

H₁ : μ > 2

We cannot reject the null hypothesis and conclude that no significant evidence exists to confirm that the mean tree-planting time differs from two hours.

Given :

X = 23.71,17.79, 29.87,18.78,28.76

b)Sample mean, x = Σx / n = 22/10 = 2.2

c) Standard deviation, s = 0.516

H0 : μ = 2

H1 : μ > 2

Test statistic :

(x - μ) ÷ (s/√(n))

n = 10

d) Test statistic :

=(2.2 - 2) ÷ (0.516/√(10))

=0.2 / 0.1631735

Test statistic = 1.23

Using the P-value from T-score we get the degrees of freedom:

df

= n - 1

= 10 - 1

= 9

P-value (1.23, 9) = 0.1249

e) Since, P-value > α ; We fail to reject the null and conclude that no significant evidence exists to support that mean tree-planting time differs from two.

A hypothesis is thetheory put up to explain a phenomenon. If a hypothesis cannot be tested by the scientific method, it cannot be referred to as a scientific hypothesis.

Scientific theories frequently start with historical observations that can't be adequately explained by the body of knowledge at this time. A hypothesis is a tested assertion regarding the relationship between two or more variables in the scientific area or a theory put out to explain an observed phenomena.

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The formula to convert the sample mean to a z score is, z = (x−μ)/σ/√n

a) Probability that the sample average sediment density is at most 3 is 0.9525 and probability between 2.69 and 3.00 is 0.4525..

b) Large Sample size is approx. 4 ..

We have given that,

Suppose the sentiment density of a randomly selected specimen from a certain region is normally distributed with

Sample mean , X-bar = 2.69

Sample size , n = 25

Standard deviations, σ = 0.74

a) we have to see what's the probability that the sample average setiment is at most 3 and then we're going to calculate between 2.69 and 3 point, so the firstly we have to calculate the standard error.

standard error = σ/√n = 0.74/√25

=> standard error = 0.148

the probability that x is between 2.69 and 3 in the probability of 2.69, i.e P (2.69<z <3)

P(at most 3 ) = P( X-bar <3) = P( X-bar - u /σ /√n<( 3 - 2.69) /0.74/5 )

=> P(z< 1.67) = 0.9525

P (2.69<z <3) = P( 2.69 - 2.69/0.74/5<z< 1.67)

=> P( <z< 1.67) = 0.4525

b) A large sample size is needed to make sure the first probability is 0.99.

If P(X-bar <3) = 0.99

=> P( 0<z<(3-2.69)/0.74/√n ) = 0.99

=> (3 - 2.69 )/0.74 /√n = 2.33

=> 0.31 √n /0.25 = 2.33

=> n = ( 2.33×0.25/0.31)² = 3.5 ~ 4

Hence, sample size is 4 and P( <z< 1.67) is 0.4525

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The value used for the parameter p is 0.544.

The number of successes in a sample of size n drawn with replacement from a population of size N is typically modeled using the binomial distribution. The mean for this type of distribution is computed by multiplying the number of trials (n) by the probability that they will succeed (p). Then, mean = n×p. The variance is n×p×q, where q is the probability that the event fails. The standard deviation is √(n×p×q).

Here, given that the percentage of tickets sold with popcorn is 54.4% and those not sold is 45.6%, the parameter (p) we used to calculate when the event occurs is 0.544. Because it is the probability that the sale of movie tickets with popcorn occurs.

The answer is 0.544.

The complete question is -

Consider how the following scenario could be modeled with a binomial distribution, and answer the question that follows.

54.4% of tickets sold to a movie are sold with a popcorn coupon, and 45.6% are not.

You want to calculate the probability of selling exactly 6 tickets with popcorn coupons out of 10 total tickets (or 6 successes in 10 trials).

What value should you use for the parameter p?

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Yes, These data suggest a statistically significant difference between the proportions of drug-resistant cases in the two cities.

In first city, the drug-resistant proportion is significant while In other city, It is not significant.

What is Ratio and proportion ?

A ratio is an ordered pair of numbers a and b, expressed as a / b, where b is not equal to 0. A percentage is an equation in which two ratios are made equal to one another.

Let the first city to be City A and the other city as City B.

In city A, 14 cases are of drug-resistant out of total 221 cases.

In city B, 6 cases are of drug-resistant out of total 322 cases.

We'll find the proportion of drug-resistant cases of both cities,

City A = 14 / 221 = 0.06 > 0.02

City B = 6 / 322 = 0.018 < 0.02

If use a 0.02 level of significance then,

City A has significant drug-resistant cases while City B does not have significant cases.

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In a periodic review system when an order is placed  every 14 days, the uncertainty period is 22 days.

Lead time is the time that passes from the start to the conclusion.  It helps in measuring the time taken to complete a project. It varies from industry to industry.

It is normally calculated as:

Lead time = processing time + post-processing time.

Given,

lead time = 8 days

Order place date = 14 days

uncertainty period  = order date + lead time

uncertainty period = 14 + 8 = 22 days

So, we can say that in a periodic review system when an order is placed  every 14 days, the uncertainty period will be 22 days.

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Answer:

1/2x+3/4y=10

ANS:

x=

−3

2

y+20

Let's solve for x.

1

12

12x+

12x+3

12x+34

12x+34y=10

Step 1: Add (-3)/4y to both sides.

1

12

12x+

12x+3

12x+34

12x+34y+

12x+34y+−3

12x+34y+−34

12x+34y+−34y=10+

12x+34y+−34y=10+−3

12x+34y+−34y=10+−34

12x+34y+−34y=10+−34y

12x+34y+−34y=10+−34y1

12x+34y+−34y=10+−34y12

12x+34y+−34y=10+−34y12x=

12x+34y+−34y=10+−34y12x=−3

12x+34y+−34y=10+−34y12x=−34

12x+34y+−34y=10+−34y12x=−34y+10

Step 2: Divide both sides by 1/2.

1

2

x

x1

x12

x12=

x12=−3

x12=−34

x12=−34y+10

x12=−34y+101

x12=−34y+1012

x12=−34y+1012x=

x12=−34y+1012x=−3

x12=−34y+1012x=−32

x12=−34y+1012x=−32y+20

Answer:

Answer:x=

Answer:x=−3

Answer:x=−32

Answer:x=−32y+20

question

Answer:

Usually we write the final answer with positive exponents.

[tex]\frac{1}{x^{2} }[/tex]

Step-by-step explanation:

[tex]\frac{x^{5} }{x^{7} }[/tex]

When we are dividing powers with the same bases, we subtract the exponents.

[tex]x^{5-7}[/tex] = [tex]x^{-2}[/tex] or [tex]\frac{1}{x^{2} }[/tex]

Answer: 350 meters

Step-by-step explanation: if she can run 2100 meters in 6 minutes to get 1 minute you can to divide by 6. so 6 minutes turn to 1 minute and 350 meters.

Answer:

a mixed fraction or decimal

Answer:

The answer is 1.4

The error is not using PEMDAS in right order and the answer is 75.

PEMDAS is a method of operation in which operations are done in the order of parentheses first , then exponents, multiplication, division, addition and subtraction in the respective manner.

Given expression, 62 + 3 + 5 x 2

By using PEMDAS,

Step.1 - Firstly do the multiplication;

             62 + 3 + 5 x 2 = 62 + 3 + 10

Step.2 - Now add the remaining terms;

             62 + 3 + 10 = 75

Therefore, the answer is 75 .

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5.94 minutes is the half-life, or the amount of time it takes to half the substance to degrade (about 6 minutes).

When we use the formula A = A0(1 - r)t,

(1/2)A₀ = A₀(1 - 0.11)t

[Divide both sides by A₀ results in:

1/2 = (0.87)t

Using the log of both sides;:

log(1/2) = log(0.87)t

Using a logarithm property, we can bring the "t" to the front, giving us:

log(1/2) = t.log(0.89)

[Dividing both sides with log(0.89) gets us:

t =  log(1/2)/log(0.89)

Using calculator for soling the values.

t = 5.94 seconds

Thus, 5.94 minutes is the half-life, or the amount of time it takes to half the substance to degrade (about 6 minutes).

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[tex]~~~~~~ \stackrel{\textit{\LARGE Monica}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$100\\ r=rate\to 3.3\%\to \frac{3.3}{100}\dotfill &0.033\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (100)(0.033)(1) \implies I = 3.3 \\\\[-0.35em] ~\dotfill[/tex]

[tex]~~~~~~ \stackrel{\textit{\LARGE Paul}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$200\\ r=rate\to 2.1\%\to \frac{2.1}{100}\dotfill &0.021\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (200)(0.021)(1) \implies I = 4.2[/tex]

well, Monica needs to check more closely what was in that last cup of coffee she drank, she's hallucinating.

Answer:

$8.75 for one ticket

Step-by-step explanation:

Since this is just plain division, you'd divide 52.50 by 6 and get your answer of 8.75.

Hope I helped!

Answer:

30

Step-by-step explanation:

9-(-21) = 9+21 = 30

Answer to question 1:
2/5

Explanation:
This square is a 10 by 10 graph, meaning there is 100 total blocks, and 40 of the squares are shaded in, making 40/100 of the squares shaded. 40/100 is then simplified to 2/5.

Answer to question 2:
0.6

Explanation:
As previously stated, the graph has a total of 100 squares, and 60 of the squares are not shaded, making it 60/100 squares unshaded. 60/100 is then converted to a decimal of 0.6.

The solution to this question is  27 units the perimeter of kite OBDE.

The perimeter of a shape is the entire length of the shape's boundary as used in geometry. A form's perimeter can be calculated by adding the lengths of all of its sides and edges. In order to calculate it, linear distances such as centimeters, meters, inches, or feet are used.

Here

This is because 15x15 =225

8x8 = 64

225+64=289 and

the square root of 289 is 17 and that is the diameter of the circle and the hypotenuse of the triangle and since the kite has two congruent sides which are both radii or  can be written as half of a diameter times two would be the same as the length of the diameter which is17+the two bottom sides (which are both 5 and 5 )

So 5+ 5 = 10 and

10 + 17 =27 or the perimeter of the kite.

Therefore ,the perimeter of kite OBDE is 27 units.

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Answer:39cm

Step-by-step explanation:

The basketball player made 15 errors in  100 games as of the given condition.

Given that,
A baseball player made 9 errors in 60 games, how many errors would we expect the player to make in 100 games is to be determined.

The ratio can be defined as the proportion of the fraction of one quantity towards others. e.g.- water in milk.

Here,
Let the error be x, for 100 games,
Now, according to ot the question,
9/60= x / 100
x = 15

Thus, the basketball player made 15 errors in  100 games.

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Answer:

-4

Step-by-step explanation:

Answer:

-4

Step-by-step explanation:

g(x) tells us what the variable is and what variable should be replaced with a value.

g(1) tells us the value that will replace x.

Plug in 1 to the equation:

-5(1) + 1 = g(1)    (multiply)

-5 + 1 = g(1)       (combine like terms)

-4 = g(1)

Therefore, g(1) is equal to -4

The recent college graduate upon passing her exam with a probability will be as follows:

(a) Let the event where she passes the exam be denoted as [tex]E_{i}[/tex] and by i-th exam.

P(passes all exams) = P([tex]E_{3} E_{2} E_{1}[/tex]) = P([tex]E_{3} | E_{2} E_{1}[/tex])P([tex]E_{2} | E_{1}[/tex])P([tex]E_{i}[/tex])

= (0.7)(0.8)(0.9)

= 0.504

(b) By calculating,

[tex]P (E_{1} E_2^{c} | (E_{1} E_{2} E_{3})^{c})[/tex] = [tex]\frac{P (E_{1} E_2^{c} | (E_{1} E_{2} E_{3})^{c})}{P((E_{1} E_{2} E_{3})^{c})}[/tex]

= [tex]\frac{P(E_{1} E^{c}_{2}) }{P((E_{1} E_{2} E_{3})^{c})}[/tex]

= [tex]\frac{P(E^{c}_{2} | E_{1)}P(E_{1 )} } {{P((E_{1} E_{2} E_{3})^{c})}}[/tex]

= [tex]\frac{(1- P (E_{2}|E_{1})) P(E_{1})}{1-P(E_{1} E_{2} E_{3} }[/tex]

= [tex]\frac{(1-0.8) X 0.9}{1-0.504}[/tex]

where we know the denominator from part (a)

≈ 0.3629

Probability theory deals with numerical representations of the likelihood that an event will happen or that a statement is true. A probability is a number between 0 and 1, where 0 essentially signifies an event's impossibility and 1 generally denotes certainty. The likelihood that something will happen is what is commonly referred to as probability. We can talk about the likely of one outcome, or the likelihood of a few outcomes, when we don't know how an event will turn out. An event's probability distribution is studied in statistics.

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Answer:

  GCF = 6; sum = 6(1 +3)

Step-by-step explanation:

You want the greatest common factor of 6 and 18.

The greatest common factor is the largest factor common to both numbers. Here, we can factor the numbers as ...

  6 = 6·1

  18 = 6·3

The factor 6 is common to both numbers. (Other numbers, such as 1, 2, and 3 are also common factors, but 6 is the largest.)

The GCF is 6.

In terms of the GCF, the sum can be written ...

  6 +18 = 6(1 +3)

__

Additional comment

If the smaller number is not a factor of the larger, then the next value to check is the difference between the larger and smaller.

Euclid's algorithm tells you the remainder from division of the larger by the smaller will be zero when the divisor is the GCF. Otherwise, the remainder can be used to replace the larger number for trying again.

Here, 18/6 = 3 r 0, so 6 is the GCF.

The histogram's best summary is option (D), "there are a total of 12 snacks with the same amount of sugar."

While bar charts show categorical variables, histograms show quantitative or numerical data.

The majority of the time, a histogram's numerical data will be continuous (having infinite values).

It would be ridiculous to try and show all possible values of a continuous variable along an axis.

So, the y-axis displays the number of snacks.

The x-axis displays how much sugar is in each snack.

The histogram's first column reveals that 2 snacks each contain between 220 and 224 mg of sugar.

The second column reveals that around 3 snacks have 224–228 mg of sugar.

The third column reveals that 8 snacks range in sugar content from 228 to 232 mg.

Twelve snacks are identified in the fourth column as having between 232 and 236 mg of sugar.

Twelve snacks are identified in the fourth column as having between 232 and 236 mg of sugar.

The fifth column reveals that 11 snacks range in sugar content from 236 to 240 mg.

Three snacks are shown to contain between 240 and 244 mg of sugar in the sixth column.

According to the seventh column, 2 snacks contain 244–248 mg of sugar.

The total number of observations is 41 nibbles, or 2+3+8+12+11+3+2.

So, the best statement that describes the histogram is "The most snacks with the same quantity of sugar are 12 in total."

Therefore, the histogram's best summary is option (D), "there are a total of 12 snacks with the same amount of sugar."

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Complete question:
Data were collected for a sample of organic snacks. The amount of sugar (in mg) in each snack is summarized in the histogram below. Which statement best describes the meaning of one of the bars in the histogram?

2

4

6

8

10

12

amount of sugar (mg)

220

224

228

232

236

240

244

248

Frequency

a. 2 snacks have about 226 mg of sugar.

b. 226 snacks have 2 mg of sugar.

c. 226 snacks have between 224 and 228 mg of sugar.

d. The largest number of snacks have 12 mg of sugar

Answer: x > -3

Steps:

5x > -15                       Bring 5 to the other side (multiplication ---> division)

x > -15/5                      Divide

x > -3

The solution of the inequality 5x > -15 after solving the inequality expression is x > -3.

Given an inequality expression:

5x > -15

It is required to find the value of x after solving the expression.

In order to solve this, it is required to isolate the value of the variable, in this case, x, on one side and the constant terms on the other side.

In order to isolate the variable:

Divide both sides by 5.

x > [tex]\frac{-15}{5}[/tex]

x > -3

Hence, the solution of the inequality expression is x > -3.

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The distance between the point H= (−9, 0) and J= (−1,−8) in the coordinate plane is 8√2 units.

For the stated question-

Distance formula;

d = √(x2 -x1)² + (y2 - y1)²

H(x1, y1) = (−9, 0)

and J(x2, y2) = (−1,−8)

Put the values;

HJ = √(-1 + 9)² + (-8 - 0)²

HJ = √(64 + 64)

HJ = 8√2

Thus, the distance between the point H= (−9, 0) and J= (−1,−8) in the coordinate plane is 8√2 units.

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Answer:

y=35

Step-by-step explanation:

3y+25+2y+30+2y-5+y+30=360

Combine like terms then you will get
8y+80=360
8y=280

y=35

Answer:

35°

Step-by-step explanation:

the sum of the angles in a quadrilateral is 360 degrees

let 's make and solve the equation

3y + 25 + 2y + 30 + 2y - 5 + y +30 = 360

Combine like terms then you will get

(3y + 2y + 2y + y) + (25 + 30 - 5 + 30) = 360

8y + 80 = 360

8y + 80 - 80 = 360 - 80

8y = 280

y = 280:8

y= 35

Answer:  B=90 degrees maybe

Step-by-step explanation:

Answer:

Amy will get detention if she is tardy

Step-by-step explanation:

The lengths of the bamboo sticks obtained using the quadratic formula are;

33.06 cm and 16.94 cm

The quadratic formula used to find the solution of quadratic equations can be presented as follows;

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4\times a \times c} }{2 \times a}[/tex]

The area of the rhombus = 280 cm²

The length of the stick = 50 cm

Let x represent a length of the sticks , therefore;

The length of the other stick = 50 - x

The rhombus consists of two  triangles

The height of the triangles is half the length of the diagonal of the rhombus, therefore;

Area =  x × (50 - x) × 0.5 = 280

-0.5·x² + 25·x = 280

x² - 50·x + 560 = 0

x = (50 ± √((-50)² - 4 × 1 × (560))/(2)

x ≈ 33.06, or x ≈ 16.94

The lengths of the bamboo sticks are;

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1) the maximum number of different 2 letter words = 650

2) 3901 words that should be printed to be sure of having at least 7 identical words on the list.

3) if there are 5201 words on the list, then there are 11 identical words

In this question, we have been given a list of randomly generated 2-letter words printed on a paper and he letters cannot be repeated.

1)the maximum no. of different 2 letter words would be,

using permutation,

^(26)P_2 =  650

2) the least number of words that should be printed to be sure of having at least 7 identical words on the list.

650 * 6 = 3900

3900 + 1 = 3901

to sure 7 identical words 3901 words should be printed.

3) the least number of identical words are printed if there are 5201 ""words"" on the list.

5201 = (520 * 10) + 1

so, there are at least 11 identical words.

Therefore, 1) the number of different 2 letter words = 650

2)  the least number of words that should be printed to be sure of having at least 7 identical words on the list = 3901

3) if there are 5201 words on the list, 11 identical words should be printed.

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