Which of these shows equivalent fractions?
а
=
4.
8
=
AN
alw
10
2 - 3
3. 6

Answer:

  ratio

Step-by-step explanation:

The levels of measurement are ...

Both interval and ratio level measurements deal with numerical data. The difference is that ratio-level measurements use a numerical scale that includes an absolute zero, and scale values are proportional to the quantity they represent.

Price data is a ratio level of measurement.

Answer:

If Avery decides to deposit $7,000 for 5 years, the bank would be the better deal would be bank is offering a rate of 3%

compounded annually

Step-by-step explanation:

In order to calculate which bank would be the better deal If Avery decides to deposit $7,000 for 5 years, we would have to make the following calculation:

simple interest rate of 32%.

Therefore, I= P*r*t

=$7,000*32%*5

=$11,200.

compound interest rate of 3%

Therefore, FV=PV(1+r)∧n

FV=$7,000(1+0.03)∧5

FV=$8,114.

If Avery decides to deposit $7,000 for 5 years, the bank would be the better deal would be bank is offering a rate of 3%

compounded annually

Answer:

9x^2-25

Step-by-step explanation:

You can solve this problem by using FOIL:

    - FOIL (First, Outer, Inner, Last)

First: 3x*3x= 9x^2

Outer: 3x*-5= -15x

Inner: 3x*5 = 15x

Last: 5*-5= -25

Now add what we got together:

9x^2 -15x +15x -25

Answer: 9x^2 - 25

Note: Whenever when we see conjugates(coefficients of variables are same but real numbers are opposites) like these we can ignore the outer and inner of the foil process as they cancel out.

Hope this helps!

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[tex]9x^2 - 25[/tex]

Explanation:

[tex]( a + b) ( a - b ) = a^2 - b^2[/tex]

Substitute with 3x and b with 5:

[tex](3x + 5) (3x - 5) = (3x)^2 - 5^2\\[/tex]

[tex]= 9x^2 - 25[/tex]

∴ [tex]( 3x + 5) ( 3x - 5) = 9x^2 - 25[/tex]

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

Answer:

18107.32

Step-by-step explanation:

Set up the exponential function in the form:

       [tex]P = P_0(R)^t[/tex]

so P is the new population, [tex]P_0[/tex] is the original population, R is the rate of increase in population, and t is the time in years.

You have to use the information given to find the rate that the population is increasing and then use that rate to find the new population after more time passes.

[tex]13000 = 6000(R)^7\\\\\\frac{13000}{6000} = R^7\\\\\sqrt[7]{\frac{13000}{6000} } = R\\\\\\ R = 1.116786872[/tex]

Now that you found the rate, you can use the function to find the population after another 3 years.

[tex]P = 13000(1.116786872)^3\\P = 18107.32317\\[/tex]

So the population is 18107, rounded to the nearest whole number.

Answer:

The value of "x" is 34 and the value of "y" is 17.

Step-by-step explanation:

"x" is shown as 34 and "y" is shown on the rectangular shape in the number form of 17. If your trying to find the area of the rectangle the area is 578.

"can't exceed 975" means this is the largest value possible for C. So we could have C = 975 or smaller. We write this as [tex]C \le 975[/tex] which is read as "C is less than or equal to 975".

Answer:

5

Step-by-step explanation:

Answer:

The fraction that is equivalent to 2/6 is 1/3

Answer:

The 99% confidence interval for the proportion of adults who regularly lie to people conducting surveys is (0.116, 0.19).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 623, \pi = \frac{95}{623} = 0.153[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.153 - 2.575\sqrt{\frac{0.153*0.848}{623}} = 0.116[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1525 + 2.575\sqrt{\frac{0.153*0.845}{623}} = 0.19[/tex]

The 99% confidence interval for the proportion of adults who regularly lie to people conducting surveys is (0.116, 0.19).

Answer:

2 is not a solution

False

Step-by-step explanation:

8m - 6 < 10

Add 6 to each side

8m -6+6 < 10+6

8m < 16

Divide by 8

8m/8 <16/8

m < 2

m must be less than 2

2 is not a solution

Answer:

FALSE

Step-by-step explanation:

Trust Me

The α = 0.05 and the p-value (0.034) is less than α, we reject the null hypothesis. There is sufficient evidence to support the researcher's contention that last-minute filers  receive lower average tax refunds than early filers. Since the test statistic is more extreme than the critical value, we reject the null hypothesis.

a.

Hypotheses:

Null Hypothesis [tex](H_0)[/tex]: There is no difference in the average tax refund amount between early filers and last-minute filers .

Alternative Hypothesis [tex](H_a)[/tex]: Last-minute filers  receive lower average tax refunds than early filers.

Mathematically:

[tex]H_0[/tex]: μ_last_minute = μ_early

[tex]H_a[/tex]: μ_last_minute < μ_early

where:

μ_last_minute = population mean refund for last-minute filers

μ_early = population mean refund for early filers

b.

Given information:

Sample mean for last-minute filers = $910

Population standard deviation (σ) = $1600

Sample size (n) = 400

To calculate the test statistic and the p-value, use the formula:

[tex]z = (\bar x - \mu) / (\sigma / \sqrt n)[/tex]

Where:

[tex]\bar x[/tex] = sample mean

μ = hypothesized population mean under the null hypothesis

σ = population standard deviation

n = sample size

Plugging in the values:

z = ($910 - $1056) / ($1600 / √400)

z = ($910 - $1056) / ($1600 / 20)

z = -$146 / 80

z ≈ -1.825

c.

To find the p-value associated with the test statistic, use a standard normal distribution table. For a one-tailed test with a z-score of -1.825, the p-value is approximately 0.034.

d.

Critical value approach:

To perform the hypothesis test using the critical value approach, we first need to find the critical value corresponding to α = 0.05 and a one-tailed test.

For a significance level (α) of 0.05, the critical value is approximately -1.645.

Now, the test statistic we calculated previously was -1.825.

Conclusion: The p-value is less than α, we reject the [tex](H_0)[/tex].There is sufficient evidence to support the researcher's contention that last-minute filers  receive lower average tax refunds than early filers. Since the test statistic is more extreme than the critical value, we reject the null hypothesis.

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Answer:

10 mph

Step-by-step explanation:

The top speed you will ever need to go in a parking lot is 10 mph.

15 mph is the fastest you should ever drive in a parking lot. The right answer is D.

The National Motorists Association was established in 1982 and is a divisive nonprofit advocacy group representing drivers in North America.

The Association promotes engineering standards that have been demonstrated to be effective, justly drafted and applied traffic legislation, and full due process for drivers.

Given to give information about the top speed you will ever need

to go into a parking lot is,

A group of drivers came together to form the National Motorists Association, Inc., a non-profit organization, to defend drivers' rights in the legal system, on the highways, and inside our cars.

Usually, there are marked speed limits in parking lots. Obey speed limits when you see them to avoid tickets and to keep everyone safe.

The National Motorists Association advises driving no faster than 15 miles per hour at all times when there are no written speed limits.

Therefore, the correct option is D.

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Answer:

x² + 9x + 8

Step-by-step explanation:

Step 1: FOIL

x² + 8x + x + 8

Step 2: Combine like terms

x² + 9x + 8

Answer:

x^2 + 9x + 8

Step-by-step explanation:

(x + 1)(x + 8)

x(x + 1) +8(x + 1)

x^2 + x + 8x +8

x^2 + 9x + 8

Answer:

1. [tex]Area=16\,\pi=50.265[/tex]

2.- [tex]\frac{b}{a} =-8[/tex]

3.  [tex]y=\frac{1}{2} x^2+3x+\frac{5}{2}[/tex]

4.  [tex]a+b+c=\frac{17}{4}[/tex]

5.   the vertex is located at: (3, 10)

Step-by-step explanation:

1. If we rewrite the formula of the conic given by completing squares, we can find what conic we are dealing with:

[tex](x^2-2x)+(y^2+6y)=6\\\,\,\,\,\,\,+1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+9\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+10\\(x-1)^2+(y+3)^2=16\\(x-1)^2+(y+3)^2=4^2[/tex]

which corresponds to a circle of radius 4, and we know what the formula is for a circle of radius R, then:

[tex]Area=\pi\,R^2=\pi\,4^2=16\,\pi=50.265[/tex]

2.

If x=4 is the axis of symmetry of the parabola

[tex]y=ax^2+bx+c[/tex]

then recall the formula to obtain the position of the x-value of the vertex:

[tex]x_{vertex}=-\frac{b}{2a} \\4=-\frac{b}{2a}\\4\,(-2)=\frac{b}{a} \\\frac{b}{a} =-8[/tex]

3.  

From the graph attached, we see that the vertex of the parabola is at the point: (-3, -2) on the plane, so we can write the general formula for a parabola in vertex form:

[tex]y-y_{vertex}=a\,(x-x_{vertex})^2\\y-(-2)=a\,(x-(-3))^2\\y+2=a(x+3)^2[/tex]

and now find the value of the parameter "a" by requesting the parabola to go through another obvious point, let's say the zero given by (-1, 0) at the crossing of the x-axis:

[tex]y+2=a\,(x+3)^2\\0+2=a(-1+3)^2\\2=a\,2^2\\a=\frac{1}{2}[/tex]

So the equation of the parabola becomes:

[tex]y+2=\frac{1}{2} (x+3)^2\\y+2=\frac{1}{2} (x^2+6x+9)\\y+2=\frac{1}{2} x^2+3x+\frac{9}{2} \\y=\frac{1}{2} x^2+3x+\frac{9}{2} -2\\y=\frac{1}{2} x^2+3x+\frac{5}{2}[/tex]

4.

From the location of the focus of the parabola as (4, 3) and the directrix as y=1,  we conclude that we have a parabola with dominant vertical axis of symmetry, displaced from the origin of coordinates, and responding to the following type of formula:

[tex](x-h)^2=4\,p\,(y-k)[/tex]

with focus at: [tex](h,k+p)[/tex]

directrix given by the horizontal line [tex]y=k-p[/tex]

and symmetry axis given by the vertical line [tex]x=h[/tex]

Since we are given that the focus is at (4, 3), we know that [tex]h=4[/tex], and that [tex]k+p=3[/tex]

Now given that the directrix is: y = 1, then:

[tex]y=k-p\\1=k-p[/tex]

Now combining both equations with these unknowns:

[tex]k+p=3\\k=3-p[/tex]

[tex]1=k-p\\k=1+p[/tex]

then :

[tex]1+p=3-p\\2p=3-1\\2p=2\\p=1[/tex]

and we now can solve for k:

[tex]k=1+p=1+1=2[/tex]

Then we have the three parameters needed to write the equation for this parabola:

[tex](x-h)^2=4\,p\,(y-k)\\(x-4)^2=4\,(1)\,(y-2)\\x^2-8x+16=4y-8\\4y=x^2-8x+16+8\\4y=x^2-8x+24\\y=\frac{1}{4} x^2-2x+6[/tex]

therefore: [tex]a=\frac{1}{4} , \,\,\,b=-2,\,\,and\,\,\,c=6[/tex]

Then [tex]a+b+c=\frac{17}{4}[/tex]

5.

The vertex of a parabola can easily found because they give you the roots of the quadratic function, which are located equidistant from the symmetry axis. So we know that is one root is at [tex]x=3+\sqrt{5}[/tex]and the other root is at [tex]x=3-\sqrt{5}[/tex]

then the x position of the vertex must be located at x = 3 (equidistant from and in the middle of both solutions. Then we can use the formula for the x of the vertex to find b:

[tex]x_{vertex}=-\frac{b}{2a}\\3=-\frac{b}{2\,(-2)}\\ b=12[/tex]

Now, all we need is to find c, which we can do by using the rest of the quadratic formula for the solutions [tex]x=3+\sqrt{5}[/tex]  and [tex]x=3-\sqrt{5}[/tex] :

[tex]x=-\frac{b}{2a} +/-\frac{\sqrt{b^2-4\,a\,c} }{2\,a}[/tex]

Therefore the amount [tex]\frac{\sqrt{b^2-4\,a\,c} }{2\,a}[/tex],  should give us [tex]\sqrt{5}[/tex]

which means that:

[tex]\sqrt{5}=\frac{\sqrt{b^2-4\,a\,c} }{2\,a} \\5=\frac{b^2-4ac}{4 a^2} \\5\,(4\,(-2)^2)=(12)^2-4\,(-2)\,c\\80=144+8\,c\\8\,c=80-144\\8\,c=-64\\c=-8[/tex]

Ten the quadratic expression is:

[tex]y=-2x^2+12\,x-8[/tex]

and the y value for the vertex is:

[tex]y=-2(3)^2+12\,(3)-8=-18+36-8=10[/tex]

so the vertex is located at: (3, 10)

Answer:

The correct option is (B).

Step-by-step explanation:

The median (m) is a measure of central tendency. To obtain the median, we assemble the data in arising order. If the data is odd, the median is the mid-value. If the data is even, the median is the arithmetic-mean of the two mid-values.

The mean of a data set is:

[tex]\bar X=\frac{1}{n}\sum\limits^{n}_{x=0}{X}[/tex]

For the three kittens it is provided that the weights are in the range 147 g to 159 g.

So, the mean and median weight for the 3 kittens lies in the middle of this range.

Now a fourth kitten is born, with weight 57 g.

Now the range of the weight of 4 kittens is, 57 g to 159 g.

The mean is going to decrease as one more value is added to the data and the value is the least.

The median will also decrease because now the median will be mean of the 2nd and 3rd values.

But the mean would decrease more than the median because a smaller value is added to the data.

Thus, the correct option is (B).

Answer:

136°

Step-by-step explanation:

x and 44° represents the measures of opposite angles of a cyclic quadrilateral.

Since, opposite angles of a cyclic quadrilateral are supplementary.

[tex] \therefore \: x + 44 \degree = 180 \degree \\ \therefore \: x = 180 \degree - 44 \degree \\ \therefore \: x = 136 \degree[/tex]

Answer:

x = 136°

Step-by-step explanation:

180° = x + 44°

180 - 44 = x + 44-44

136° = x

= 136°

Answer:

B.

Step-by-step explanation:

Let's call x the number of pens and y the number of notebooks that Monique can buy.

If each pen costs $2 and each notebook costs $3, so she is going to spend 2*x on pens and she is going to spend 3*y on notebooks.

Additionally, she is going to spend a maximum of $36. so:

2x + 3y [tex]\leq[/tex] 36

It means that the line that  separated the region is:

2x + 3y = 36

This is the same that a line that passes for the points (0,12) and (18,0) or the line of the region B

Answer:

(Option A) . No, because the histogram of the data is not bell shaped, there is more than one outlier, and line points in the normal quantile plot do not lie reasonably close to a straight line.

Step-by-step explanation:

After plotting the histogram, you will see that the data does not represent the normal distribution because the histogram is not bell shaped and there are two outliers.

Answer:

1/3( x-5)= -2/3

Multiply both sides by 3

x = 3

Step-by-step explanation:

1/3( x-5)= -2/3

Multiply both sides by 3

3*1/3( x-5)= -2/3*3

x-5 = -2

Add 5 to each side

x-5+5 = -2+5

x = 3

Answer:

1/3( x-5)= -2/3

Multiply both sides by 3

x = 3

Step-by-step explanation:

1/3( x-5)= -2/3

Multiply both sides by 3

3*1/3( x-5)= -2/3*3

x-5 = -2

Add 5 to each side

x-5+5 = -2+5

x = 3

Hope this helps!

Answer:

50 deg

Step-by-step explanation:

In an right triangle, the acute angles are complementary. That means their measures have a sum of 90 deg.

m<C + m<B = 90

7x - 20 + 4x = 90

11x = 110

x = 10

m<ACB= 7x - 20

m<ACB = 7(10) - 20

m<ACB = 70 - 20

m<ACB = 50

Answer: m<ACB = 50 deg

Answer:

Using a 90% confidence level

A. A sample size of 68 should be used.

B. A sample size of 98 should be used.

Step-by-step explanation:

I think there was a small typing mistake and the confidence level was left out. I will use a 90% confidence level.

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.9}{2} = 0.05[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.05 = 0.95[/tex], so [tex]z = 1.645[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

A. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 72 seconds, what sample size should be used?

We have the standard deviation in minutes, so the margin of error should be in minutes.

72 seconds is 72/60 = 1.2 minutes.

So we need a sample size of n, and n is found when M = 1.2. We have that [tex]\sigma = 6[/tex]. So

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1.2 = 1.645*\frac{6}{\sqrt{n}}[/tex]

[tex]1.2\sqrt{n} = 6*1.645[/tex]

[tex]\sqrt{n} = \frac{6*1.645}{1.2}[/tex]

[tex](\sqrt{n})^{2} = (\frac{6*1.645}{1.2})^{2}[/tex]

[tex]n = 67.65[/tex]

Rounding up.

A sample size of 68 should be used.

B. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 1 minute, what sample size should be used?

Same logic as above, just use M = 1.

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = 1.645*\frac{6}{\sqrt{n}}[/tex]

[tex]\sqrt{n} = 6*1.645[/tex]

[tex](\sqrt{n})^{2} = (6*1.645)^2[/tex]

[tex]n = 97.42[/tex]

Rounding up

A sample size of 98 should be used.

Answer:

(y-9)8

Step-by-step explanation:

you first solve 8-9, and then multiply is by 8.

Eight times the difference of y and nine will be 8(y - 9).

It should be noted that eight times the difference of y and nine simply means that one has to subtract 9 from y and then multiply the difference by 8.

Therefore, eight times the difference of y and nine will be 8(y - 9).

In conclusion, the correct option is 8(y - 9).

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Answer:

2/3

Step-by-step explanation:

There are 4 numbers that fit the rule, 3, 4, 7, 8 since they are either less than 5 or greater than 6. There are 6 numbers so the chance would be 4/6 or simplified, 2/3.

Answer:

2/3

Step-by-step explanation:

There are 6 options, 2 of them > 6 and 2 of them < 5

P (greater than 6 or less than 5)= 4/6= 2/3

Answer:

Given: A right triangle in which an altitude is drawn from the right angle vertex to the hypotenuse.

To find: 'x' the larger leg of triangle

Solution,

Using let rule for similarity in right triangle:

[tex] \frac{leg}{part} = \frac{hypotenuse}{leg} \\ or \: \frac{x}{27} = \frac{3 + 27}{x} \\ or \: x \times x = 27(3 + 27) \\ or \: x \times x = 81 + 729 \\ or \: {x}^{2} = 810 \\ or \: {x}^{2} = 81 \times 10 \\ or \: {x} = \sqrt{81 \times 10} \\ or \: x = \sqrt{81} \times \sqrt{10} \\ or \: x = \sqrt{ {(9)}^{2} } \times \sqrt{10} \\ \: x = 9 \sqrt{10} [/tex]

Hope this helps...

Good luck on your assignment..

Answer:

[tex]P = \frac{1}{3}[/tex]

Step-by-step explanation:

The calculation of the value of p minimizes is shown below:-

We will assume the probability of coming heads be p

p(H) = p

p(T) = 1 - P

Now, H and T are only outcomes of flipping a coin

So,

P(TTH) = (1 - P) = (1 - P) (1 - P) P

= (1 + P^2 - 2 P) P

= P^3 - 2P^2 + P

In order to less N,TTH

we need to increase P(TTH)

The equation will be

[tex]\frac{d P(TTH)}{dP} = 0[/tex]

3P^2 - 4P + 1 = 0

(3P - 1) (P - 1) = 0

P = 1 and 1 ÷ 3

For P(TTH) to be maximum

[tex]\frac{d^2 P(TTH)}{dP} < 0 for\ P\ critical\\\\\frac{d (3P^2 - 4P - 1)}{dP}[/tex]

= 6P - 4

and

(6P - 4) is negative which is for

[tex]P = \frac{1}{3}[/tex]

Answer:

Se pagará $7200.

Step-by-step explanation:

La ecuación del costo puede descomponerse en dos factores que luego se multiplican:

1) Siendo A el area del del muro, la parte del costo que depende del área se calcula como un tercio (1/3) del doble (2) del área A. Este factor se puede escribir como:

[tex]C_1=(1/3)\cdot 2 \cdot A=(2/3)\cdot A[/tex]

2) Siendo T el número de trabajadores, el siguiente factor es el triple del numero de trabajadores T. Esto es:

[tex]C_2=3T[/tex]

Multiplicando ambos factores, tenemos la ecuacion del costo en función de A y T:

[tex]C=C_1\cdot C_2=(2/3)A\cdot 3T=2 AT[/tex]

Si se planea pintar un muro de 1200m² y se contrataran a 3 trabajadores, el costo será:

[tex]C=2AT=2(1200)(3)=7200[/tex]

Answer:

122.6 pounds

Step-by-step explanation:

Let's call the weight of the largest fish from lake A 'x', and the weight of the largest fish from lake B 'y'.

If x is 208.2 pounds less than seven times y, we have that:

[tex]x = 7y - 208.2[/tex]

We know that x is equal 650 pounds, so we can find y:

[tex]650 = 7y - 208.2[/tex]

[tex]7y = 650 + 208.2[/tex]

[tex]7y = 858.2[/tex]

[tex]y = 122.6\ pounds[/tex]

So the weight of the largest fish caught in Lake B is 122.6 pounds

Step-by-step explanation:

81

I think this should be the answer

Answer: [tex]C. f(x) = 3(2^x)[/tex].

Step-by-step explanation:

If the graph of function y=f(x) is vertically stretched by a scale factor of 'k', then the new function will be :

[tex]Y=kf(x)[/tex]

The given function : [tex]f(x)=2^x[/tex]

If the given function vertically stretched by a scale factor of '3', then the new function will be :

[tex]Y=3f(x)=3(2^x)[/tex]

Hence, the correct option is [tex]C. f(x) = 3(2^x)[/tex].

Answer:

[tex]\displaystyle x=- \frac{5}{7}[/tex]

Step-by-step explanation:

[tex]5(2x-7)+42-3x=2[/tex]

Expand brackets.

[tex]10x-35+42-3x=2[/tex]

Combine like terms.

[tex]10x-3x+42-35=2[/tex]

[tex]7x+7=2[/tex]

Subtract 7 on both sides.

[tex]7x+7-7=2-7[/tex]

[tex]7x=-5[/tex]

Divide both sides by 7.

[tex]\frac{7x}{7} =\frac{-5}{7}[/tex]

[tex]x=- \frac{5}{7}[/tex]

Answer:

[tex] \boxed{\sf x = - \frac{5}{7}} [/tex]

Step-by-step explanation:

[tex] \sf Solve \: for \: x: \\ \sf \implies 5(2x-7)+42-3x=2 \\ \\ \sf 5(2x - 7) = 10x - 35 : \\ \sf \implies \boxed{ \sf 10x - 35} - 3x + 42 = 2 \\ \\ \sf Grouping \: like \: terms, \: 10x - 35 - 3x + 42 = \\ \sf (10x - 3x) + ( - 35 + 42) : \\ \sf \implies \boxed{ \sf (10x - 3x) + ( - 35 + 42)} = 2 \\ \\ \sf 10x - 3x = 7x : \\ \sf \implies \boxed{ \sf 7x} + ( - 35 + 42) = 2 \\ \\ \sf 42 - 35 = 7 : \\ \sf \implies 7x + \boxed{ \sf 7} = 2 \\ \\ \sf Subtract \: 7 \: from \: both \: sides: \\ \sf \implies 7x + (7 - \boxed{ \sf 7}) = 2 - \boxed{ \sf 7} \\ \\ \sf 7 - 7 = 0 : \\ \sf \implies 7x = 2 - 7 \\ \\ \sf 2 - 7 = - 5 : \\ \sf \implies 7x = \boxed{ \sf - 5} \\ \\ \sf Divide \: both \: sides \: of \: 7x = - 5 \: by \: 7: \\ \sf \implies \frac{7x}{7} = \frac{ - 5}{7} \\ \\ \sf \frac{7}{7} = 1 : \\ \\ \sf \implies x = - \frac{5}{7} [/tex]

Answer: 375%

Step-by-step explanation:

375%.  Simply do 2250/600 to get 3.75, or 375%.

Hope it helps <3