Answer:
options?!?
Explanation:
give us some options
Displacement a combination of
Answer:
Displacement a combination of distance
Explanation:
I'm not sure eh
Which graph shows a vehicle traveling at a constant speed?
(look at the attached photo)
4. Premature wrinkling due to overexposure to the Sun, what am I?
Premature Aging
Mark as brainlist
An electric iron is connected to the mains power supply of 220 V. When the electric iron is
adjusted at 'minimum heating' it consumes a power of 360 W but at 'maximum heating' it takes a
power of 840 W. Calculate the current and resistance in each case.
Answer:
Given: V = 220V, Pmin = 360W, Pmax = 840W
For minimum heating case:
We know that
Pmin = VI
360 = 220 X I
I = 1.63 amp
R = V/I
R = 220/1.63
R = 134.96ohms
For maximum heating case:
We know that
Pmax = VI
840 = 220 X I
I = 3.81 amp
R = V/I
R = 220/3.81
R = 57.74 ohms
Brad has three beakers of water. Each beaker contains 500 mL of water. The temperature of the water in the first beaker is 40°C. The water in the second beaker is at 100°C, and the water in the third beaker is at 60°C. As part of a lab experiment he will carefully combine the water in all three beakers. He predicts that the combined water will have a final temperature of 50°C.
Evaluate Brad’s claim and clearly state whether he is correct or not. Explain your answer to support your evaluation.
Explanation:
uasjwwbwjwbwia GJ wkwkjwnwnwjwjjwjwd7beba s
4. Determine the net force for the free-body
diagram
Fnorm = 40N
Ffrict =28N
Fapp =44N
Fgrav = 40N
Answer:
Fapp =44N is the correct answer
Explanation:
Please mark brainliest
in a nuclear plant, 1 * 10 ^27 J of energy is available from mass conversion How much mass was lost ?
Answer:
[tex]1.2\times 10^{10}\ kg[/tex]
Explanation:
Given that,
The energy of the nuclear plant, [tex]E=10^{27}\ J[/tex]
We need to find how much mass wast lost.
The relation between energy and mass is given by :
[tex]E=mc^2[/tex]
Where
c is speed of light
[tex]m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg[/tex]
So, [tex]1.2\times 10^{10}\ kg[/tex] of mass was lost.
help fast plssssssssssss
Answer:
star
Explanation:
because that is what our sun is.
1/2 means that the voltage (or charge) of the system will increase to half more of what is left in a time equal to t1/2 seconds. Therefore if a system is already at half charge (t1/2 seconds after starting) then after t1/2 more seconds the system will be charged to 50% plus half of 50%. That is 25% more, or 75% of the entire charge. Let's say that four t1/2's have gone by. That means that the charge (or voltage) is at (50% + 1/2*50% + 1/2*1/2*50% + 1/2*1/2*1/2*50%) = 93.75% of maximum charge. Yikes! Now look in your manual for a more simple mathematical derivation of this concept. Given t1/2 to be 0.4406 seconds, how long should it take to reach 75% of maximum charge? answer in seconds.
Answer:
The answer is "0.047".
Explanation:
Given value:
[tex]\to t_{\frac{1}{2}}= 0.4406\\\\\to V=0.9375 V_{max}[/tex]
Calculating the capacitance:
[tex]\to V=V_{max} (1-e^{\frac{-t}{Rc}})[/tex]
In this, the t = time, which is taken to calculates its maximum voltage.
[tex]\to 0.9375 V_{max} = V_{max}(1-e^{- \frac{t}{103\times(165.279\times10^{-6})}})\\\\\to e^{- \frac{t}{103\times(165.279\times10^{-6})}}= 0.0625\\\\\to - \frac{t}{103\times(165.279\times10^{-6})} = \ln(0.0625)\\\\\to -t= 0.01702\times(-2.77258) \\\\ \to -t = -0.04719 \\\\ \to t= 0.04719 \approx 0.047 \ s[/tex]
Why does thunder come before lightning?
Answer:
That is because light travels much faster than sound waves. … It takes approximately 5 seconds for the sound to travel 1 mile.
Explanation:
If the thunder follows the lightning almost instantly, you know the lightning is too close for comfort.
1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
a.) Maximum height of the projectile.
b.) The time it takes to reach the maximum height
c.) Time of flight
d.) Range
Answer:
a.) Maximum height of the projectile. =32.5m
b.) The time it takes to reach the maximum height=2.6s
c.) Time of flight=2.6s
d.) Range=99.5m
Explanation:
define amoeba what are your plans
Answer:
Amoeba (plural = amoebae) is a well known genus of unicellular organism, a protist. One of its most common species, the Amoeba Proteus, is about 0.2 to 0.3 mm large. The amoeba was first discovered by August Von Rosenhof in 1757.[1] It is a genus of protozoa that moves with false feet, called pseudopodia.
It's a single - called animal that catches good and moves around by extending fingerlike projections of protoplasm
The period of the sound waves produced by the motor is 8.3 milliseconds.
Calculate the frequency of the sound waves.
Answer:
120.48hz
Explanation:
f=1/t..........
Either the wavelength, velocity, or wave period—the amount of time it takes for a wave cycle to complete—must be known. If you know the period, divide 1 by it and, if necessary, convert it to seconds. The outcome will be the frequency in Hertz.
What frequency of the sound waves?As with all waves, the relationship between the speed of sound, its frequency, and its wavelength is vw=f, where vw is the speed of sound, f is the frequency, and is the wavelength.It is necessary to know either the wavelength, the velocity, or the wave period, which is the duration of a wave cycle.
Therefore, More oscillations are produced at higher frequencies. Hertz are the frequency measurement units (Hz). Noises between 20 Hz and 20,000 Hz can be heard by those with normal hearing. Ultrasound is a term for frequencies greater than 20,000 Hz.
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Anyone able to help with these questions, will give brainliest to first correct anwser
Answer:
b
Explanation:
I did this question earlier
So.. This is science.. I would ask the kids from my school but I have no friends and I don't know any of them.
Answer:
8 N force
Explanation:
12 N forward, 4 N backwards
12-4=8
HELP ASAP PLS
A locomotive with a rocket engine is being tested on a smooth horizontal track. The mass of the
locomotive is unknown. Starting from rest, the engines are fired for 20 s. During this time
they expel 500 kg of oxidized kerosene. The kerosene particles are expelled at an average
velocity of 1200 m/s. At the end of the 20-s period the speed of the locomotive is 50 m/s.
What is its mass?
Answer:
The mass of the locomotive is 288,000 kg
Explanation:
The question relates to the law of conservation of energy
The given parameters are;
The form of engine on the locomotive = Rocket engine
The mass of the locomotive = m
The initial velocity of the locomotive, v = 0 m/s
The duration at which the engine is fired = 20 s
The mass of the kerosene expelled, m₁ = 500 kg
The average speed with which the kerosene is expelled, v₁ = 1,200 m/s
The final speed of the locomotive engine after 20-s, v₂ = 50 m/s
Kinetic energy, K.E. = 1/2·m·v²
The total kinetic energy of the kerosene particles, K.E.[tex]_k[/tex] = 1/2 × 500 × 1,200² = 360,000,000
∴ K.E.[tex]_k[/tex] = 360,000,000 J
By the conservation of energy, the kinetic energy of the expelled kerosene particles is equal to the kinetic energy gained by the moving locomotive
Therefore, we have;
K.E.[tex]_L[/tex] = K.E.[tex]_k[/tex]
K.E.[tex]_L[/tex] = 1/2 × m × v₂² = 1/2 × m × 50²
∴ K.E.[tex]_L[/tex] = 1/2 × m × 50² = K.E.[tex]_k[/tex] = 360,000,000 J
1/2 × m × 50² = 360,000,000 J
m = 360,000,000 J/(1/2 × (50 m/s)²) = 288,000 kg
m = 288,000 kg
The mass of the locomotive, m = 288,000 kg
1 watt is the same as the transfer of ____
joules per second. What number completes the sentence?
Answer:
1 watt is the same as the transfer of 1 joules per second.
1 watt is the same as the transfer of energy at a rate of 1 joule per second.
A watt is a unit of power, representing the amount of energy transferred or converted per unit of time. Specifically, 1 watt is equivalent to 1 joule of energy being transferred every second. It is a common metric used to measure the rate of energy flow or work done in various systems. For example, a 100-watt light bulb converts electrical energy into light and heat at a rate of 100 joules per second. Understanding power in terms of watts helps us quantify and compare the efficiency and performance of different devices and processes.
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A human cannonball act uses springy bungee cords instead of gunpowder to launch a person through a long cylindrical tube into the air. If a cannon is capable of launching a 55 kg test dummy 11 m into the air when launched straight up, how much energy is stored in the bungee cords? *
A. 539J
B. 605 J
C. 2965J
D. 5929 J
Answer:
Energy stored, E = 5929 J
Explanation:
Given that,
The mass of a test dummy, m = 55 kg
It is launched 11 m into the air.
We need to find the energy stored in the bungee cords. It can be calculated as follows :
[tex]E=mgh\\\\E=55\times 9.8\times 11\\\\E=5929\ J[/tex]
So, 5929 J of energy is stored in the bungee cords.
So if any of ya got like, screenshots of all the answers for Edge, 2020. Lab-Kinetic Energy-student guide, That would be really helpful. If you could help me, then I will mark you brainliest. And for you trollers out there who just want the points, could you not steal them for this one? Anyways, thanks ya'll!
Answer:
has any one finished the lab yet?????
Explanation:
How could you measure the strength of static electricity compared to the strength of an
electromagnet?
Answer:
Lines of Force around an ElectromagnetExplanation:
The magnetic field strength of an electromagnet is therefore determined by the ampere turns of the coil with the more turns of wire in the coil the greater will be the strength of the magnetic field
4. A substance is cut into several piece and compared to the density of the
original sample. The density of each piece will be:-
areater
bl the same
Answer:
The density pf each piece will be the same, since density is defined as a mass per unit volume, so even when you cut an object it will not change
Describe how different energy stores are changed by the boiler.
[3 marks]
Answer:
Energy can remain in the same store for millions of years or sometimes just for a fraction of a second. There are energy transfers going on all the time - whenever a system changes there is a change in the way some or all of the energy is stored.
Transferring energy
In each of these examples, energy is transferred by one of the following four types of energy transfer:
mechanical work - a force moving an object through a distance
electrical work - charges moving due to a potential difference
heating - due to temperature difference caused electrically or by chemical reaction
radiation - energy tranferred as a wave, eg light and infrared - light radiation and infrared radiation are emitted from the sun
Doing 'work' is the scientific way of saying that energy has been transferred. For example, a grazing cow, a firing catapult and a boiling kettle are all doing 'work', as energy is being transferred.
Energy flow diagrams
Diagrams can be used to show how energy is transferred from one store to another. Two examples are the transfer diagram and the Sankey diagram.
Transfer diagrams
In transfer diagrams the boxes show the energy stores and the arrows show the energy transfers.
For example, a transfer diagram for a child at the top of a slide may be:
Energy transfer diagram of a child on a slide
Gravitational energy stored in the child at the top of the slide is transferred as mechanical work done to speed up and to do work against friction. The result of this is a shift of energy from gravitational potential energy to kinetic energy and internal energy (raising the temperature of the child and the slide).
Sankey diagrams
Sankey diagrams start off as one arrow that splits into two or more points. This shows how all of the energy in a system is transferred into different stores.
Sankey diagram of a child on a slide
Sankey diagrams are really useful when the amount of energy in each of the energy sources is known. The width of the arrow is drawn to scale to show the amount of energy.
Explanation:
!
☻︎
ℍ ꨄ︎
Between steel and iron which is more suitable for making permanent magnets electromagnet and magnetic screen give reason for your answer
Answer:
steel is suitable for making permanent magnet
as still has hi factor coercity.
iron is for electromagnet and magnetic screen as iron loses its magnetism as soon as the switch is open and a current is switched off.
Steel is better suitable for making permanent magnets than soft iron since it has higher retentivity and lower coercivity. Compared to soft iron, steel has a lower retentivity and higher coercivity. Compared to soft iron, steel is more resilient and coercive.
What is retentivity and coercivity ?Retentivity : The ability to retain the generated magnetization in a magnetic material when the magnetizing force is removedCoercivity : A measure of the ability of a material to withstand an external magnetic field without becoming demagnetized.What is Permanent magnet and Electromagnet?Permanent magnet : To be suitable for permanent magnet, material should retain its magnetism for longer time, since steel have high retentivity and coercivity . Electromagnet : To be suitable for electromagnet , material should have magnetization and demagnetizing property .
Since , steels have high remanence which means it will remain magnetized even after magnetic field is removed which is not suitable for electromagnetic . iron has high permeability so magnetization is larger and have low retentivity so that material will not retain the magnetic properties . Magnetic screen , Iron has high permeability hence it can shield better than steel
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which of these is NOT a metamorphic rock?
Basalt
Slate
Marble
Explanation:
Basalt is not a metamorphic rocks
. A boy wishes to throw a ball through a house via two small openings, one in the front and the other in
the back window, the second window being directly behind the first. If the boy stands at a distance of 5m
in front of the house and the house is 6m deep and if the opening in the front window is 5m above him
and that in the back window 2m higher, calculate the velocity and the angle of projection of the ball that
will enable him to accomplish his desire.
Answer:
1) The angle of projection of the ball is approximately 52.496° above the horizontal
2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s
Explanation:
In the projectile motion of the ball, the parameters are;
The distance the boy stands from the front of the house = 5 m
The depth of the house, front to back = 6 m
The height of the opening of the front window above him = 5 m
The height of the back window = 2 m higher than the front window
Therefore, the height of the back window = 5 m + 2 m = 7 m
1) The general formula for the vertical height of a parabolic projectile motion is given as follows;
y = a·x² + b·x + c
At y = 0, x = 0, therefore, c = 0
At y = 5, x = 5, we have;
5 = a·5² + b·5
∴ 5 = 25·a + 5·b...(1)
At y = 7, x = 11, we have;
7 = a·11² + b·11
7 = 121·a + 11·b...(2)
Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;
For equation (1);
a = (5 - 5·b)/25 = 1/5 - b/5
a = 1/5 - b/5
For equation (2);
a = (7 - 11·b)/121 = 7/121 - b/11
a = 7/121 - b/11
∴ 1/5 - b/5 = 7/121 - b/11
1/5 - 7/121 = b/5 - b/11
86/605 = 6·b/55
b = (86/605) × (55/6) = 43/33
b = 43/33
a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33
∴ y = (-2/33)·x² + (43/33)·x
The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33
The slope of the curve at any point on the projectile = -4/33·x + 43/33
The slope at the origin is given by plugging x = 0 as follows
The slope at the origin = -4/33 × 0 + 43/33 = 43/33
The slope at the origin = tan(θ) = 43/33
Where;
θ = The angle of projection of the ball
∴ θ = arctan(43/33) ≈ 52.496°
The angle of projection of the ball, θ ≈ 52.496° above the horizontal
2) At the back widow, the equation for the vertical height, 'h', is given as follows;
[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]
Where;
h = The vertical height of the back window = 7 m
tan∠θ = 43/33
x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m
g = The acceleration due to gravity = 9.8 m/s²
v₁ = The velocity with which the boy throws the ball
cos²∠θ = cos²(arctan(43/33)) = 1089/2938
Plugging in the values gives;
[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]
[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]
[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]
The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.
Whatb19 ÷117= some help me with this
Answer:
0.16239316239316239316239
Explanation:
ang haba nang solve ko dito hehe
The speed of a 1200 kg car increases from 5 to 29 m/s in 12 s.
What force accelerated the car?
Answer:I think I’m not sure But I think that the force that would be accurated the car would be friction or something like that and to solve the equation you would do f/m
Explanation:
It just makes sense
When the distance between two objects doubles, what happens to the gravitational attraction between these two objects?
Answer:
As indicated by Newton's law of attraction each article or body in the universe draws in every single item towards one another and that power of fascination is straightforwardly relative to the result of their masses and contrarily corresponding to the square of the distance between them.
The power of gravity between two articles will diminish as the distance between them increments. The two most significant elements influencing the gravitational power between two items are their mass and the distance between their focuses. As mass increments, so does the power of gravity, however an increment in distance mirrors a reverse proportionality, which makes that power decline dramatically.
At that point by Newton's All inclusive Law of Attractive energy;
F=GMm/R^2
Mm= result of the majority
R=Distance Between the two masses by focus.
On the off chance that R is multiplied, new force=GMm/(2R)^2
=GMm/4R^2
Unique Power/New Force=4/1
F/4=New Power
Which one of the following best describes a fuse?
Which has more potential energy: a baseball held 1 m above the ground or a baseball held 2 m above the ground?
The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.
The potential energy can be calculated with the following equation:
[tex] E_{p} = mgh [/tex]
Where:
m: is the mass of the baseball
g: is the acceleration due to gravity
h: is the height
We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:
Potential energy above 1 m[tex] E_{p_{1}} = mg*1 = mg [/tex] (1)
Potential energy above 2 m[tex] E_{p_{2}} = mg*2 = 2mg [/tex] (2)
By entering equation (1) into 2 we have:
[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]
Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.
Therefore, the baseball held 2 m above the ground has more potential energy.
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