Which of these is a harmful interaction

Answers

Answer 1

Answer:The five major types of species interactions, summarized in Figure 10, are competition, predation, parasitism, mutualism, and commensalism.

Explanation:


Related Questions

can u pls help me with this question ​

Answers

Answer:

B

Explanation:

What is the mass of 8.50 × 1022 molecules of NH3?

Answers

Answer:

The mass of 8.50 × 10²² NH₃ molecules is ≈ 1.84 g.

One mole of a molecule contains 6.02 × 10²³ molecules. The mass of  8.50 × 10²² molecules of NH₃ is 2.39 g.

What is ammonia (NH3)?

Ammonia is an inorganic compound formed by hydrogen and nitrogen. Ammonia exists in gaseous state.

One mole of every element or compound contains 6.02 × 10²³ molecules. This number is called Avogadro number. The molar mass of ammonia is 17 g/l

It is given that the number of molecules of ammonia here, is 8.50 × 10²².

The no.of moles of ammonia = 8.50 × 10²²/ 6.02 × 10²³

                                                = 0.141 moles.

If one mole ammonia is 17 g/l, the mass of 0.141 moles of NH₃ is calculated as follows: 0.141 × 17 = 2.39 g. Hence the mass of NH3 which contains 8.50 × 10²² molecules is 2.39 g.

To learn more about ammonia, find the link below:

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In the following pair, determine whether the two represent resonance contributors of a single species or depict different substances. If two structures are not resonance contributors, explain why. Select the single best answer.

N-N ≡ N: and N=N=N:

Answers

Answer:

They are resonance contributors

Explanation:

Resonance structures are structures that differ only in the distribution or placement of electrons.

Considering the two structures, we can easily see that the two species have the same total number of bonds and electrons differing only in the distribution of these electrons.

Hence, they are resonance contributors.

For the following reaction, 22.5 grams of iron are allowed to react with 35.0 grams of chlorine gas . iron(s) chlorine(g) iron(III) chloride(s) What is the maximum mass of iron(III) chloride that can be formed

Answers

Answer:

53.31g of FeCl3

Explanation:

The equation of the reaction is given as;

2Fe(s)  + 3Cl2(g) --> 2FeCl3(s)

From the stochiometry of the reaction;

2 mol   :    3 mol       :   2 mol

112g     :      213g      :     324.4g

Converting the masses given to moles;

Number of moles of Fe = mass / molar mass = 22.5 / 56 = 0.4018

Number of moles of Cl2 = mass / molar mass = 35 /  71 = 0.4930

In this reaction, the limiting reactant is Cl2

213 g of Cl2 produces 324.4g of FeCl3,

35g of Cl2 would produce xg of FeCl3

213 = 324.4

35 = x

x = (35 * 324.4) / 213 = 53.31g

Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and characteristic colors by which we can identify them. Therefore, in the analysis of mixtures of metal ions, it is very common to precipitate the metal ions by using dihydrogen sulfate (commonly called hydrogen sulfide), H2S. Suppose you had a mixture of Fe2+, Cr3+, and Ni2+. Complete the net ionic equations for the precipitation of these metal ions by the use of H2S. (Type your answers using the format Fe2+ for Fe2+.)

Answers

Answer:

See explanation

Explanation:

For Fe;

Fe2+(aq) + 2H+(aq) + S2-(aq) ----> FeS(s) + H2(g)

For Ni

Ni2+(aq) + 2H+(aq) + S2-(aq) ----> NiS(s) + H2(g)

For Cr

2Cr3+(aq) + 6H+(aq) + 3S2-(aq) ----->Cr2S3(s) + 3H2(g)

We must remember that in writing these equations, the number of electrons lost or gained must be balanced. The number of electrons lost by the metal must equal the number of electrons gained by hydrogen. This rule was followed in writing all the equations above.

In a lab, you produce a quantity of the radioactive isotope thorium-234. Over the course of several weeks, the unstable isotope decays, and you measure the amount of thorium-234 remaining in the sample. You obtain the following data. What is the half life of Thorium-234? How much Thorium 234 will there be after two half lives?
Days Elapsed Grams of Thorium 234 Remaining
0 16
12 11
24 8
36 6
a. 36 days
b. 12 days
c. 24 days / 4 grams

Answers

Answer:

Option C. 24 days / 4 grams

Explanation:

From the question given above, the following data were obtained:

Days Elapsed >>>> Mass Remaining

0 >>>>>>>>>>>>>>> 16

12 >>>>>>>>>>>>>>> 11

24 >>>>>>>>>>>>>>> 8

36 >>>>>>>>>>>>>>> 6

A. Determination of the half-life of Thorium-234.

To determine the half-life, it is important to know the definition of half life.

Half-life is defined as the time taken for a substance to reduce to half its original mass.

From the table given above, we can see that the original mass of the isotope is 16 g (i.e at 0 day). By day 24, the mass of the isotope is 8 g (i.e half the original mass). Thus, the half-life of the isotope is 24 days.

B. Determination of the mass of the isotope remaining after 2 half lives.

Original amount (N₀) = 16 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 16

N = 1/4 × 16

N = 4 g

Thus, 4 g of the isotope is remaining after 2 half lives.

Summay:

Half-life = 24 days

Amount remaining after 2 half-lives = 4 g

Option C gives the correct answer to the question.

Calculate the number of grams of solid aluminium chloride that will form when a mixture containing 0.150 g of aluminum powder and 1.00 g of chlorine gas is allowed to react.

2Al (s) + 3Cl2 (g) ---> 2AlCl3 (s)

a. 741 g AlCl3
b. 471 g AlCl3
c. 0.741 g AlCl3
d. 246 g AlCl3

Answers

Answer:

the answer is B:) have a good day

Element X has two naturally occurring isotopes, 65X (isotopic mass 65.0457 amu, abundance 20.53%) and 67X (isotopic mass 66.9704 amu, abundance 79.47%). Calculate the atomic mass of element X.

Answers

Answer:

66.5753 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A (⁶⁵X):

Mass of A = 65.0457 amu

Abundance of A = 20.53%

Isotope B (⁶⁷X):

Mass of B = 66.9704 amu

Abundance of B = 79.47%

Atomic mass of X =?

The atomic mass of X can be obtained as follow:

Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100]

= [(65.0457 × 20.53)/100] + [(66.9704 × 79.47)/100]

= 13.3539 + 53.2214

= 66.5753 amu

Therefore, the atomic mass of X is 66.5753 amu.

Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu,  79.47%).

What is the average atomic mass?

The average atomic mass (atomic mass) of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.

Element X has 2 isotopes:

⁶⁵X with an isotopic mass of 65.0457 amu and an abundance of 20.53% (0.2053).⁶⁷X with an isotopic mass of 66.9704 amu and an abundance of 79.47% (0.7947).

We can calculate the average atomic mass of X using the following expression.

mX = m⁶⁵X × ab⁶⁵X + m⁶⁷X × ab⁶⁷X

mX = 65.0457 amu × 0.2053 + 66.9704 amu × 0.7947

mX = 66.58 amu

Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu,  79.47%).

Learn more about atomic mass here: https://brainly.com/question/6200158

Calculate the molar mass of adrenaline (C9H13NO3C9H13NO3), a hormone responsible for regulating heart rate and other functions of the sympathetic nervous system. Express your answer to five significant figures.

Answers

Answer:

[tex]M_{C_9H_{13}NO_3}=183.23g/mol[/tex]

Explanation:

Hello!

In this case, since the molar mass of a chemical compound is computed by averaging the atomic mass of each element in the molecule and the amount of atoms; which in this case there are 9 carbon atoms, 13 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms; thus, we compute the average as shown below:

[tex]M_{C_9H_{13}NO_3}=m_C*9+m_H*13+m_N+m_O*3[/tex]

Now, we plug in the atomic masses to obtain:

[tex]M_{C_9H_{13}NO_3}=12.01*9+1.01*13+14.01+16.00*3\\\\M_{C_9H_{13}NO_3}=183.23g/mol[/tex]

Best regards!

In the Lewis symbol for a sulfur atom, there are __________ paired and __________ unpaired electrons. A) 2, 2 B) 4, 2 C) 2, 4 D) 0, 6 E) 5, 1 Answer: B

Answers

Answer:

C) 2, 4.

Explanation:

Hello!

In this case, since the sulfur atom has six electrons at its outer shell, it suggests it needs to gain two electrons in order to attain a complete octet, that is why it has 2 paired electrons.

Moreover, since two electrons are paired, then 4 electrons will remain unpaired; therefore the answer would be C) 2, 4.

Best regards!

A photon of light has an energy of 1.83 x 10-18). What is the wavelength of this light? Does this light fall in the IR, visible, or UV region of the electromagnetic spectrum?​

Answers

Answer:

1.09 × 10⁻⁷ m

UV region

Explanation:

Step 1: Given and required data

Energy of the photon of light (E): 1.83 × 10⁻¹⁸ J

Planck's constant (h): 6.63 × 10⁻³⁴ J.s

Speed of light (c): 3.00 × 10⁸ m/s

Step 2: Calculate the wavelength (λ) of this photon of light

We will use the Planck-Einstein's relation.

E = h × c/λ

λ = h × c/E

λ = 6.63 × 10⁻³⁴ J.s × (3.00 × 10⁸ m/s)/1.83 × 10⁻¹⁸ J = 1.09 × 10⁻⁷ m

This wavelenght falls in the UV region of the electromagnetic spectrum.

QUESTION 20
A slice of pizza contains 17 g of fat, 25 g of carbohydrate, and an unknown amount of protein. If the piece of pizza contains a total of 750 kcal,
how many grams of protein does the slice of pizza contain? (The accepted caloric values for foods are 4.0 kcal/g for carbohydrate, 9.0 kcalg
for fat, and 4.0 kcal/g for protein.) Report the answer to 2 significant figures.
429
O Can not be determined from the given information.
O 649
O 749
120 g
Save All Answ
MacBook Pro

Answers

Answer:

Explanation:

Let the protein contained in pizza be m gram .

calories contained by 17 g of fat = 17 x 9  kcals = 153  kcals .

calories contained by 25 g of carbohydrate = 25 x 4  kcals = 100 kcals .

calories contained by m  g of protein  = m  x 4  kcals = 4 m  kcals .

Total calories of slice of pizza = 153 + 100 + 4m kcals

= 253 + 4m kcals

Given ,

253 + 4m = 750

4m = 497

m = 124.25 g .

120 g ( rounded to two significant  figures )

During the process of condensation, water vapor:____________.
(1) releases 334 J/g of heat energy
(2) releases 2260 J/g of heat energy
(3) gains 334 J/g of heat energy
(4) gains 2260 J/g of heat energy

Answers

Answer: (2) releases 2260 J/g of heat energy

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.

Latent heat of condensation is energy released when 1 mole of  vapor condenses to form liquid droplets.

The temperature does not change during this process, so heat released goes into changing the state of the substance, thus it is called latent which means hidden. The energy released in this process is same in magnitude as latent heat of vaporization. The heat of condensation of water vapour is about 2,260 J/g.

Phase transition refers to the changes in the states of matter between gas, liquids, and solids.

The correct answer is:

Option 2. releases 2260 J/g of heat energy

The process can be explained as:

1. Condensation is the process of conversion of water vapor into the liquid state.

2. Latent heat of vaporization is defined as the amount of heat required for 1 mole of liquid to convert into a gaseous phase at atmospheric pressure.

3. The change in the temperature does not occur during the condensation, and the heat required for the phase transition is latent heat. The heat of condensation of water vapor is 2,260 J/g.

Thus, the correct answer is Option 2.

To know more about condensation, refer to the following link:

https://brainly.com/question/15563071

Analysis of a salt results in the following composition: 3.47 g of Sodium; 2.12 g of Nitrogen; and 7.27 g of Oxygen. What is the simplest formula for this salt

Answers

Answer:

NaNO₃

Explanation:

Data obtained from the question include:

Mass of sodium (Na) = 3.47 g

Mass of nitrogen (N) = 2.12 g

Mass of oxygen (O) = 7.27 g

Simplest (empirical) formula =?

The simplest formula for the salt can be obtained as follow:

Na = 3.47 g

N = 2.12 g

O = 7.27 g

Divide by their molar mass

Na = 3.47 / 23 = 0.151

N = 2.12 / 14 = 0.151

O = 7.27 / 16 = 0.454

Divide by the smallest

Na = 0.151 / 0.151 = 1

N = 0.151 / 0.151 = 1

O = 0.454 / 0.151 = 3

Simplest formula = NaNO₃

Thus, the simplest formula for the salt is NaNO₃

At a given set of conditions 241.8 kJ of heat is released when one mole of H2O forms from its elements. Under the same conditions 285.8 KJ is released when one mole of H2O is formed from its elements. Find Delta h of the vaporization of water at these conditions

Answers

Answer:

44Kj

Explanation:

These are the equations for the reaction described in the question,

Vaporization which can be defined as transition of substance from liquid phase to vapor

H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H

-241.8kj -------eqn(1)

H2(g)+ 1/2 O2(g) ------>H2O(l).

Δ H =285.8kj ---------eqn(2)

But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as

H2O(l) ------>>H2O(g)---------------eqn(3)

But the equation from eqn(2) the eqn does go with vaporization so we can re- write as

H2O ------> H2(g)+ 1/2 O2(g)

Δ H= 285.8kj ---------------eqn(4)

To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)

Δ H=285.8kj +(-241.8kj)= 44kj

2055 Q. No. 10^-2
mole of KOH is dissolved in 10 litres of
water. What will be the pH of the solution?
12
Ans: pH = 11​

Answers

Answer:

11

Explanation:

Moles of KOH = [tex]10^{-2}[/tex]

Volume of water = 10 liters

Concentration of KOH is given by

[tex][KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}[/tex]

[tex][KOH][/tex] is strong base so we have the following relation

[tex][KOH]=[OH^{-}]=10^{-3}\ \text{M}[/tex]

[tex]pOH=-\log [OH^{-}]=-\log10^{-3}[/tex]

[tex]\Rightarrow pH=14-3=11[/tex]

So, pH of the solution is 11

If the average basal rate of oxygen consumption for an adult is 15 L/hour, then calculate how many hours of oxygen use will you get from the 4.7 L tank? Round your answer to 1 decimal place.

Answers

Answer:

0.3 hours of oxygen use will be obtained from the 4.7 L tank.

Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three.

To solve a direct rule of three, where a, b and c are known data and x is the value to be calculated  the following formula must be followed:

a ⇒ b

c ⇒ x

So [tex]x=\frac{c*b}{a}[/tex]

A value of 15 L/hour indicates that 15 L is consumed in 1 hour. The following rule of three can then be applied: if the average basal rate of oxygen consumption for an adult is 15 L in 1 hour, then 4.7 L in how long will it be consumed?

[tex]time=\frac{4.7 L*1 hour}{15 L}[/tex]

time= 0.3 hours

0.3 hours of oxygen use will be obtained from the 4.7 L tank.

Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 3.00 molesmoles of aluminum sulfate, Al2(SO4)3Al2(SO4)3. Express the number of moles of AlAl, SS, and OO atoms numerically, separated by commas.

Answers

Answer:

[tex]n_{Al}=6.00molAl\\\\n_{S}=9.00molS\\\\n_{O}=36.0molO[/tex]

Explanation:

Hello!

In this case, when analyzing the moles of an element inside a compound, we need to keep in mind that a mole ratio should be set up; thus, for aluminum sulfate, we have the following ones:

[tex]\frac{2molAl}{1molAl_2(SO_4)_3} \\\\\frac{3molS}{1molAl_2(SO_4)_3} \\\\\frac{12molO}{1mol1molAl_2(SO_4)_3}[/tex]

Thus, starting by 3.00 moles of aluminum sulfate, the moles of each element turn out:

[tex]n_{Al}=3.00molAl_2(SO_4)_3*\frac{2molAl}{1molAl_2(SO_4)_3} =6.00molAl\\\\n_{S}=3.00molAl_2(SO_4)_3*\frac{3molS}{1molAl_2(SO_4)_3} =9.00molS\\\\n_{O}=3.00molAl_2(SO_4)_3*\frac{12molO}{1molAl_2(SO_4)_3}=36.0molO[/tex]

Best regards!

can u pls help me with this question ​

Answers

Answer:

I think the answer is b

Explanation:

the paragraph states, that it is an experiment to see if there is any oxygen in the water

I’m pretty sure it’s B

Part II: Covalent Bonding 1. Now, you will investigate diatomic molecules, those that are made up of two of the same type of atom. Select 2 fluorine atoms. a. How many valence electrons are in each fluorine atom

Answers

Answer:

Seven electrons.

Explanation:

There are seven valence electrons in each fluorine atom because it belongs to halogens. Fluorine atom requires one electron to complete its valence shell to become stable so for that it form both ionic and covalent bonds with different atoms. It makes ionic bond with alkali metals by accepting one electron to complete its valence shell and also make covalent bond by sharing of electrons.

What was a key discovery in the advancement me up early information transfer

Answers

Answer:

The transfer was essential to understand the mutation and the possibility of new, more resistant strains in microorganisms.

Explanation:

the transfer of microorganisms is based on the transfer of genetic data through conductive pathways that penetrate the membranes, called pili or genetic bridges.

These mutated genes with higher resistance are transmitted and resistance is generated in entire populations and even species.

What is the answer to this?

Answers

one if them is phosphate

For this experiment you will need to perform a serial dilution of CO(NO3)2 solutions, meaning that you will begin with a stock solution, dilute it to make a new solution, and then use that new solution as the stock solution for the next dilution. You will start with a 0.25 M CO(NO3)2 solution. Using the values below, calculate the volume of solution and water needed at each step of the dilution.

Concentration of original solution mL of original solution required mL of water required Concentration of new solution
0.25M 0.1M
0.1M 0.05M
0.05M 0.01M

Answers

Answer:

See answer below

Explanation:

In this case, I will put the original photo of this exercise, because we are missing one data. The first picture is the original exercise.

Now, according to this, we need to make a serial dilution of CO(NO₃)₂. We don't know the volume of this solution, but we do know the total volume of the preparing solution (In the picture states that the total volume will be 10 mL).

So, we know the final volume of the solutions to be prepared, so, le'ts use the expression that will help us to solve this:

C₁V₁ = C₂V₂

Where:

C₁: Concentration of the given solution (stock)

V₁: volume required to prepare the dilluted solution

C₂; Concentration of the dilluted solution

V₂: Total volume of the dilluted solution.

Now that we know the expression to use and the meaning of each value, let's prepare the solutions:

To prepare 10 mL of 0.1 M using a 0.25 M, we will replace these values in the above expression; from there, we will solve for V₁, that value will tell us the required volume to prepare solution 2, and then, by difference we can calculate the volume of water:

Volume of water (Vw) =V₂ - V₁  

Now replacing the values:

0.25V₁ = 0.1 * 10

V₁ = 1/0.25 = 4 mL

V₁ = 4 mL

This means that we need 4 mL of the stock to prepare the 0.1 M of dilluted solution, therefore, the volume of water required is:

Vw = 10 - 4

Vw = 6 mL

Using these same steps for the other two solutions we will get V1 and V2 for both of them. In this case, I will go straight to the procedure without further explanation because it's the same of this one.

For solution 2:

0.1V₁ = 0.05 * 10

V₁ = 0.5/0.1

V₁ = 5 mL

Vw = 10 - 5

Vw = 5 mL

Finally for solution 3:

V₁ = 0.01 * 10 / 0.05

V₁ = 2 mL

Vw = 10 - 2 mL

Vw = 8 mL

Hope this helps

Calculate the following:
1. Mass of 4.3x10-3 mol of lead
2. Mass of 3.8x1022 antimony atoms
3. Number of atoms in 15.5 kg of tungsten

Answers

Answer:

1) Mass =  890.96 g

2) Mass =  7.67 g

3) 507.65 ×10²³ atoms

Explanation:

1) Given data:

Number of moles of lead = 4.3×10⁻³ mol

Mass of lead = ?

Solution:

Mass = number of moles × molar mass

Molar mass of lead = 207.2 g/mol

by putting values,

Mass = 4.3×10⁻³ mol × 207.2 g/mol

Mass =  890.96 g

2) Given data:

Number of atoms of antimony = 3.8×10²² atoms

Mass of antimony = ?

Solution:

1 mole contain 6.022 ×10²³ atoms

3.8×10²² atoms × 1 mol / 6.022 ×10²³ atoms

0.63×10⁻¹ mol

0.063 mol

Mass:

Mass = number of moles × molar mass

Molar mass of lead = 121.76 g/mol

Mass = 0.063 mol ×  121.76 g/mol

Mass =  7.67 g

3) Given data:

Mass of tungsten = 15.5 Kg (15.5 kg × 1000 g/ 1kg = 15500 g)

Number of atoms = ?

Solution:

Number of moles of tungsten:

Number of moles = mass/molar mass

Number of moles = 15500 g / 183.84 g/mol

Number of moles = 84.3 mol

1 mole contain 6.022 ×10²³ atoms

84.3 mol  × 6.022 ×10²³ atoms / 1mol

507.65 ×10²³ atoms

Xander is gaining weight. Which best describes what he can do to prevent obesity? exercise every day and also make healthy choices in his diet excercise once a week but make no change in his diet exercise once a week and also make healthy choices in his diet exercise every day but make no change in his diet

Answers

Answer:

exercise every day and also make healthy choices in his diet

Explanation:

This is going to prevent Xander from getting more overweight and will help him lose some pounds.

This is also something I need to do lol

<3

Answer:

A

Explanation:

Exercise every day and also make healthy choices in his diet

What is the answer to this?

Answers


I think C is the correct answer

Which gas is most abundant in Earth’s atmosphere?

Answers

Answer:

nitrogen

Explanation:

The atmosphere contains many gases, most in small amounts, including some pollutants and greenhouse gases. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere. Why do I care?

nitrogen is the most abundant gas in the atmosphere

Question 1 of 10
Where is a tomado most likely to form?
O A. Where warm, moist air masses traveling north collide with cool,
dry air masses traveling south
O B. On the northwestern side of a low-pressure system
C. Where a high-pressure system is lingering over an area
OD Over warm, tropical ocean water
SUBMIT

Answers

Answer:

A Where warm, moist air masses traveling north collide with cool,

dry air masses traveling south

what would be a logical explanation for why carbon dioxide increased over the time shown in the graph.
A. the area of land for crops incresed
b. the amount of plants eaten by animal increased
c. the amount of fossil fuels being burned increased
d. the amount of wood being burned by pepole increased

Answers

Answer:

c. the amount of fossil fuels being burned increased

Explanation:

Carbon dioxide gas concentration increased over the time due to burning of fossil fuels increased. Fossil fuels are organic compounds which releases carbondioxide gas as a result of burning of fossil fuels in the engines of vehicles and industries. With the passage of time, number of vehicles increases in the world which needs more fossil fuels and due to burning of that fossil fuels, more carbondioxide gas is released.

A covalent bond forms when

Answers

It happens when H20 gets dislocated back into the atmosphere to an massive heat level
it’s the second answer
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