Which of the following types of energy is not associated with a car engine?
A. Kinetic
B. Heat
C. Sound
D. Light

Answers

Answer 1

Answer:

D

Explanation:

Does not assosicate with Light


Related Questions

What is the instantaneous velocity of the hummingbird at t=1s?

Answers

The distance - time graph of the humming bird is missing, so i have attached it.

Answer:

Instantaneous velocity = 0.5 m/s

Explanation:

From the attached graph, at time t = 1 s, the corresponding distance is 0.5 m.

Instantaneous velocity is the velocity at that point.

Thus;

Instantaneous velocity = 0.5/1

Instantaneous velocity = 0.5 m/s

POR FAVOR AYUDENME A RESOLVER ESTO:

Halla el coeficiente de dilatación lineal de una varilla que a 10 grados centígrados mide 125 metros y cuya longitud a 85 grados centígrados es 125.20 m. ¿De qué material será?

Answers

Answer:

 α = 2.13 10⁻⁵ C⁻¹    ,  the closest material is ALUMINUM

Explanation:

The expression for thermal expansion is

          ΔL = α L₀ ΔT

temperatures are

         ΔT = 85 - 10 = 75 ° C

the length of the rod is L₀ = 125 m and L_f = 125.20 m

        ΔL = 125.20 - 125 = 0.20 m

        α = [tex]\frac{1}{L_o} \frac{\Delta L }{\Delta T}[/tex]

        α = [tex]\frac{ 1}{125} \ \frac{0.20 }{75}[/tex]

        α = 2.13 10⁻⁵ C⁻¹

When reviewing the table, the closest material is ALUMINUM

A car travels 140 miles in 3 hours. What is its velocity?

Answers

Answer:

46.67 miles/s

Explanation:

...........

A 150 g pinball rolls towards a springloaded launching rod with a velocity of 2.0 m/s to the west. The launching rod strikes the pinball and causes it to move in the opposite direction with a velocity of 10.0 m/s. What impulse was delivered to the pinball by the launcher?

Answers

Answer:

  I = 1.8 N s,  it is directed towards the right  

Explanation:

For this exercise we use the relationship between momentum and moment

         I = Δp

         F t = p_f - p₀

in this case the initial velocity is v₀ = - 2,0 m / s and final velocity v_f = 10,0 m / s, we assume the positive right direction

          I = m (v_f - v₀)

let's calculate

         I = 0.150 (10.0 - (-2.0))

         I = 0.150 (10 + 2)

         I = 1.8 N s

as the impulse is positive it is directed towards the right

Which statement explains why 49 is a perfect square?

Answers

It’s the product of 7 x 7. The square root of 49 is 7

Answer:

It’s the product of 7 x 7. The square root of 49 is 7

Explanation:

It’s the product of 7 x 7. The square root of 49 is 7

Find the density of a 2 cm x 2 cm x 2 cm cube with a mass of 64 g.

Answers

Answer:

8 g/cm³

Explanation:

density=mass/volume

volume=2*2*2=8 cm³

mass=64 g

density=64/8=8 g/cm³

The density of a 2 cm x 2 cm x 2 cm cube with a mass of 64 g is equal to 8 g/cm³.

What is the density?

Density can be defined as the material mass per unit of volume. The symbol commonly used to represent density ρ and the letter 'D' can also be used.

The mathematical equation of the density can be represented as written below:

Density = Mass /Volume

or,   ρ = m/V

The density of a material varies with pressure and temperature. There is a small variation for solids and liquids of any material but much larger for gases. Increasing the pressure of material decreases the volume and thus increases its density.

Given the volume of the cube =  2 cm x 2 cm x 2 cm

V = 8 cm³

The mass of the cube, m = 64 g

The density of the cube can be calculated from the above-mentioned formula:

Density = Mass of cube/volume

D = 64/8

D = 8 g/cm³

Therefore, the density of the cube is 8 g/cm³.

Learn more about density, here:

brainly.com/question/15164682

#SPJ2

PLEASE HELP ME I AM TIMED!

Answers

Answer:

they all need a source of oxygen

Answer:

B

Explanation:

find the torque when the work done to more through an angel of 1/4π radians is 3j​

Answers

Answer:

The torque is approximately 3.82 N·m

Explanation:

The relationship between work done, 'W', and the applied torque, 'τ' can be presented as follows;

W = τ × Δθ

Where;

W = The work done by the torque

τ = The magnitude of the torque

Δθ = The angle through which the object is turned

The parameters for 'W' and 'Δθ' are;

W = 3j

Δθ = 1/4 × π

From W = τ × Δθ, we have;

τ = W/Δθ

∴ τ = 3j/(1/4 × π) ≈ 3.81971863421 N·m

The torque, τ ≈ 3.82 N·m

Can someone pls answer

Answers

Answer:

im still in elementry so you got to do it yo self

Explanation:

so me confused

Write the SI unit of time and temperature

Answers

Answer:

The SI unit of time is second (s) and temperature is Kelvin (K)

Explanation:

hope it is helpful to you

Compare the motions of transverse, longitudinal, and combined waves.

Answers

Explanation:

transfer to babes are always at your advice by a particular motion being a particular wave motion along didn't wave is a wave which particular is a medium move a direction parallel to the direction of the wave moves something that is similar in the surveys on the medium moves of the same direction and bathe an accident to one or two Dimensions do in London killing babe attacks in one dimension and transverse waves attacks in two Dimensions the Waze cannot be paralyzed or organized

a 5.2kg bowling ball is accelerated from rest to a velocity of 12 m/s as the bowler covers 5.0m of approach before releasing the ball. what force is exerted on the ball during this time?

Answers

Answer:

74.88N

Explanation:

From the question,

F = ma................... Equation 1

Where F = force exerted on the ball, m = mass of the ball, a = acceleration

But,

v² = u²+2as.............. Equation 2

Where v = final velocity, u = initial velocity, s = distance.

Given: v = 12 m/s, u = 0 m/s (from rest), s = 5.0 m

Substitute into equation 2 and solve for a

12² = 0²+2×a×5

144 = 10a

10a = 144

a = 144/10

a = 14.4 m/s²

Also Given: m = 5.2 kg,

Substitute into equation 1

F = 5.2×14.4

F = 74.88 N

Hence the force exerted on the ball is 74.88 N

This force on compass dials is an example of a force that _______.

Answers

It’s an example of a force of the magnetic field

The plates on a vacuum capacitor have a radius of 3.0 mm and are separated by a distance of 1.5 mm. What is the capacitance of this capacitor?

Answers

Link provided in other answer is a SCAM, don’t click on the link !!!!

How many calories are released when 6 grams of 100°C steam turns to 0°C ice?

Answers

Answer: 4276.2 calories

Explanation:

Given

mass of steam is 6 gm at [tex]100^{\circ}C[/tex]

Conversion of steam to ice involves

steam to water at [tex]100^{\circ}C[/tex]water at [tex]100^{\circ}C[/tex] to water at [tex]0^{\circ}C[/tex]water to the ice at [tex]0^{\circ}C[/tex]

Calories released during the conversion of steam to water at [tex]100^{\circ}C[/tex]

[tex]E_1=mL_v\quad [L_v=\text{latent heat of vaporisation}]\\E_1=6\times 533=3198\ cal.[/tex]

Calories released during the conversion of water at [tex]100^{\circ}C[/tex] to water at [tex]0^{\circ}C[/tex]

[tex]E_2=mc(\Delta T)\quad [c=\text{specific heat of water,}1\ cal./gm.^{\circ}C]\\E_2=6\times 1\times 100=600\ cal.[/tex]

Calories released during the conversion of water to the ice at [tex]0^{\circ}C[/tex]

[tex]E_3=mL_f\quad [L_f=\text{latent heat of fusion}]\\E_3=6\times 79.7=478.2\ cal.[/tex]

The total energy released is

[tex]E=E_1+E_2+E_3\\E=3198+600+478.2=4276.2\ cal.[/tex]

A runner starts at position A. He runs 40 m North, 10 m East and 40 m
South. Where does he end up in relation the starting position?
a. 40 m North
b. 40 m South
c. 10 m East
d. Position

Answers

The answer is C.) 10 m East

1:How are energy and amplitude of a wave related
2:Define Wavelength
3:What unit is the frequency of a wave measured in?

Please help this is due in 25 minutes

Answers

Answer:

2

Explanation:

wave length is the distance between corresponding points of two consecutive waves

3. hertz

Please help, I do NOT need any links.​

Answers

Answer:

P since without a host the parasite won't be able to survive they would start decreasing as well but if the hosts were no more then they would go extinct. But since it is just decreasing then it should be P

an airplane has a maximum velocity of 160km/h in still air. calculate its maximum velocity when it travels in air with a crosswind of 30km/h

Answers

Answer:

Velocity can be directly added or subtracted.

For example, if a boat has a velocity V in still water.

And now you put the boat in a river with a current that has a velocity V'

The total velocity of the boat in that river is just the addition of these two velocities.

Velocity in the river  = V + V'

Where the only tricky part is that the velocity is a vector, so you need to take in account the directions of each vector.

In this case, we have a plane with a maximum velocity of 160km, let's assume a direction for this velocity, let's say that is in the positive x-direction.

Then we can write the velocity in the vector form:

velocity  = (vel in x-axis, vel in y-axis)

The velocity of the plane can be written as:

v = (160km/h, 0)

Now we add a crosswind of 30km/h

crosswind means that it is perpendicular, then it acts on the y-axis.

Then the total velocity of the plane will be:

velocity = (160km/h, 0) + (0, 30km/h)

velocity = (160km/h, 30km/h)

Now you can compute the total velocity of the airplane as the module of that vector.

Remember that for a vector (x, y) the module is:

mod = √(x^2 + y^2)

Then the module of the velocity is:

v = √( (160km/h)^2 + (30km/h)^2) = 162.8 km/h

What is the relationship between the valence electrons of an atom and the chemical bonds the atom can form?​

Answers

Answer:

Valence electrons are outer shell electrons with an atom and can participate in the formation of chemical bonds. In single covalent bonds, typically both atoms in the bond contribute one valence electron in order to form a shared pair. The ground state of an atom is the lowest energy state of the atom.

An entertainer pulls a table cloth off a table leaving behind the plates and sliverware undisturbed is an example of
A.
the law of balanced forces
B.
Newton's second law
C.
Newton's third law
D.
Newton's first law

Answers

Answer:

D. Newton's first law

Explanation:

Newton's first law of inertia says that an object will remain how it is, unless affected by an outside force. In this case, the plates want to remain stationary(not moving). Therefore, if you pull the table cloth fast enough, the force of friction produced will be small enough so that the Inertia of the plates will overcome the force of friction.

a body is moving with uniform acceleration, has initial velocity 45km/hr. and acceleration 20cm/s^2. find its velocity after 25 seconds​

Answers

That’s hard wow!!!!!!

the moon's mass is ____?​

Answers

Answer:

7.35..kg

Explanation:

Hope this will help you

Please,Mark me as Brainllist .

A Scooter travelling at 10m/s speed up to 20m/s in 4 sec.find the acceleration of scooter​

Answers

Answer:

2.5 m/s²

Explanation:

Given,

Initial speed ( u ) = 10 m/s

Final speed ( v ) = 20 m/s

Time ( t ) = 4 seconds

To find : Acceleration ( a ) = ?

Formula : -

a = ( v - u ) / t

a = ( 20 - 10 ) / 4

= 10 / 4

= 5 / 2

a = 2.5 m/s²

Therefore,

The acceleration of the scooter is 2.5 m/s²

I will mark you brainlist!

What mythical creature do you think is possibly real, and not actually a myth? Why?

Examples of mythical creatures: Mermaids/Merman, Fairies/ Pixie, Nymphs, Dragons, Unicorn, Leprechauns, Werewolf, Loch Ness Monster, Sphinx, Centaur, Griffin, Yeti, Pegasus, Basilisk, Chimera, Ghoul, Imp, Gnome, Manticore, Troll, Bigfoot, Phoenix, Vampire etc.

You can choose one that is listed or not listed.

Answers

Explanation:

With most of our blue planet covered by water, it's little wonder that, centuries ago, the oceans were believed to hide mysterious creatures including sea serpents and mermaids. Merfolk (mermaids and mermen) are, of course, the marine version of half-human, half-animal legends that have captured human imagination for ages. One source, the "Arabian Nights," described mermaids as having "moon faces and hair like a woman's but their hands and feet were in their bellies and they had tails like fishes."

C.J.S. Thompson, a former curator at the Royal College of Surgeons of England, notes in his book "The Mystery and Lore of Monsters" that "Traditions concerning creatures half-human and half-fish in form have existed for thousands of years, and the Babylonian deity Era or Oannes, the Fish-god ... is usually depicted as having a bearded head with a crown and a body like a man, but from the waist downwards he has the shape of a fish." Greek mythology contains stories of the god Triton, the merman messenger of the sea, and several modern religions including Hinduism and Candomble (an Afro-Brazilian belief) worship mermaid goddesses to this day.

The 500-N force F is applied to the vertical pole as shown(1) Determine the scalar components of the force vector F along the x'- and y'-axes. (2) Determine the scalar components of F along the x- and y'-axes.

Answers

Solution :

Given :

Force, F = 500 N

Let [tex]$ \vec F = F_x\ \hat i + F_y\ \hat j$[/tex]

      [tex]$|\vec F|=\sqrt{F_x^2+F_y^2}$[/tex]

∴ [tex]$F_x=F \cos 60^\circ = 500 \ \cos 60^\circ = 250 \ N$[/tex]

  [tex]$F_y=-F \cos 30^\circ = -500 \ \cos 30^\circ = -433.01 \ N$[/tex]   (since [tex]$F_y$[/tex] direction is in negative y-axis)

[tex]$F=250 \ \hat i - 433.01 \ \hat j$[/tex]

So scalar components are : 250 N and 433.01 N

     vector components are : [tex]$250 \ \hat i$[/tex] and [tex]$-433.01\ \hat j$[/tex]

1.  Scalar components along :

 x' axis = 500 N, since the force is in this direction.

 [tex]$F_{x'}= F \ \cos \theta = 500\ \cos \theta$[/tex]

  Here, θ = 0° , since force and axis in the same direction.

So, cos θ = cos 0° = 1

∴ [tex]$F_{x'}=500 \times 1=500\ N$[/tex]

[tex]$F_{y'}= F \ \sin \theta = 500\ \sin 0^\circ=500 \times 0=0$[/tex]

[tex]$F_{y'}=F\ cos \theta$[/tex] but here θ is 90°. So the force ad axis are perpendicular to each other.

[tex]$F_{y'}=F\ \cos 90^\circ= 500 \ \cos 90^\circ = 500 \times 0=0$[/tex]

∴ [tex]$F_{x'}= 500\ N \text{ and}\ F_{y'}=0\ N$[/tex]

2. Scalar components of F along:

x-axis :

[tex]$F_x=F\ \cos \theta$[/tex],   here θ is the angle between x-axis and F = 60°.

[tex]$F_x=500 \times \cos60^\circ=250\ N$[/tex]

y'-axis :

[tex]$F_{y'}=F\ \cos \theta$[/tex],   here θ is the angle between y'-axis and F = 90°.

[tex]$F_{y'}=500 \times \cos90^\circ=500\times 0=0\ N$[/tex]

∴ [tex]$F_{x}= 250\ N \text{ and}\ F_{y'}=0\ N$[/tex]

True or False: The northern & southern lights are caused by solar wind particles interacting with gases in our atmosphere.

Answers

Answer:

False.

Explanation:

An aurora is a natural electric phenomenon that creates bright and colorful light displays in the sky. These dramatic and colorful lights are created when electrically charged particles from solar winds enter the Earth's atmosphere and interact with gases in the atmosphere.

A rectangular loop with dimensions 4.20 cm by 9.50 cm carries current I. The current in the loop produces a magnetic field at the center of the loop that has magnitude 3.10×10−5 T and direction away from you as you view the plane of the loop. What are the magnitude and direction (clockwise or counterclockwise) of the current in the loop?

Answers

Answer:

1.63 A and in clockwise direction

Explanation:

The magnetic field due to the rectangular loop is :

[tex]$B=\frac{2 \mu_0 I}{\pi}\left(\frac{\sqrt{L^2+W^2}}{LW}\right)$[/tex]

Given : W = 4.20 cm

                [tex]$=4.20 \times 10^{-2} \ m$[/tex]

            L = 9.50 cm

               [tex]$= 9.50 \times 10^{-2} \ m$[/tex]

            [tex]$B = 3.40 \times 10^{-5} \ T $[/tex]

   Rearranging the above equation, we get

[tex]$I=\frac{B \pi LW}{2 \mu_0\sqrt{L^2+W^2}}$[/tex]

[tex]$I=\frac{(3.40 \times 10^{-5}) \pi(9.50 \times 10^{-2})(4.20 \times 10^{-2})}{2(4 \pi \times 10^{-7})\sqrt{(9.50 \times 10^{-2})^2+(4.20 \times 10^{-2})^2}}$[/tex]

I = 1.63 A

So the magnitude of the current in the rectangular loop is 1.63 A.

And the direction of current is clockwise.

Convert 0.0779 kg to g

Answers

I think it would be 77.9 grams

Mass of trolley (m):
(1)
0,9
kg
Mass
m xa
Acceleration
(a)
(mos)
Applied
Force (N)
0
4,04
O112
Tabulate your measurements in the table below.
At from A to B (s)
Average
Kg
At (s)
1
2
3
Hanger only
4,07 4,00
HOS
Hanger +
1 mass piece
10
3,09
3,04 3,10
3,14
Hanger +
2 mass pieces
ao
2,00
Hanger +
3 mass pieces 30
1196
1,91
Hanger +
4 mass pieces
168 1,69 1,TO 1,69
(5)
0,21
2,1 x 103 0, 098
O #4
8,8X10
2,22 2,14
0, 196
01 SS
0102
o zau
0103
01392
0/ 70
(5)
(5)
QUESTIONS AND ANALYSIS
1.
In this experiment identify the...
1.1
independent variable
(1)
1.2 dependent variable
3 E
1.3
controlled variable
Ар со
2.
3
Describe how the effect of friction was minimised in the experiment.
(1)
Use the recorded data to plot a graph that will show the relationship
between the acceleration and the applied force on the trolley. Use a (8)
graph paper.
Ilse the cranh to determine the mass of the trolley.
(4)​

Answers

Answer:

ij

Explanation:

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