The following solutions are buffers:
A solution made by mixing 100 ml of 0.100 M HCOOH and 50 ml of 0.100 M KCl, and a solution made by mixing 100 ml of 0.100 M HCOOH and 500 ml of 0.100 M NaOH.
Let's learn more about buffer solutions:
1. Buffer solutions can withstand or resist pH changes, even when adding a strong acid or base. A buffer solution comprises a weak acid and its conjugate base or a weak base and its conjugate acid. The pH change is insignificant when an acid or a base is added to a buffer solution.
2. The chemical equation for the ionization of HCOOH in water is as follows:
HCOOH + H2O ⇌ H3O+ + HCOO-
The salt made from the acid and the base in the buffer solution must be able to act as a source of ions to neutralize either the excess H3O+ ions or OH- ions introduced into the solution. For example, KCl and NaOH are used in the buffer solutions listed above, as they produce K+ and Na+ ions, which can interact with HCOO- ions in the first buffer and HCOO- ions and HCOOH molecules in the second buffer.
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To earn full credit for your answers, you must show the appropriate formula, the correct substitutions , and your answer including the correct units.
At the end of 2018, there were 371.2 million people living in the United States. The United States covers an area of 3.697 million square miles. What is the population density of the United States?
Three different species of microscopic, thread-like worms are responsible for the parasitic disease lymphatic filariasis. Adult worms can only survive in the lymphatic system of humans.
What regions are affected by lymphatic filariasis?Nowadays, it is indigenous to Madagascar, many Western Pacific Island countries and territories, Sub-Saharan Africa (with the exception of the southernmost region of the continent), and parts of the Caribbean. South America, India, and Southeast Asia are also infrequent regions where Bancroftian filariasis can be found. Brugman spp.
What kind of mosquito carries dengue?by way of mosquito bites. The mosquito aedes aegypti. When an infected Aedes species mosquito (Ae. aegypti or Ae. albopictus) bites a human, the virus that causes dengue is transmitted.
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A soda can has an internal pressure of 8.7 atm at a temperature of 4.9 °C. If the can is heated or cooled to 79.7 °C, what is the new pressure inside the can?
Answer: 11.04 atm
Explanation:
P1/T1 = P2/T2 this is the Gay-Lussac law
Temperature must be in kelvin
P2=P1T2/T1
8.7 X 352.85 /278.05
Iodine- 131 Is a radioactive isotope, and is often used in certain medical treatments. It has a short half life of about 8 days. It a hospital has a 1050 mg sample of it’s available, how much would be absolute after 72 days
After 72 days, a 1050 mg sample of Iodine-131 would have decayed to approximately 46.87 mg.
What is a half-life and how does it relate to the decay of radioactive isotopes?A half-life is the time it takes for half of a sample of a radioactive isotope to decay. It is a characteristic property of each isotope and can be used to predict how long it will take for a given sample to decay to a certain amount. The amount of an isotope remaining after a certain amount of time can be calculated using the half-life and the formula N = N0 * (1/2)^(t/T).
Why is Iodine-131 used in medical treatments and how does its short half-life factor into its use?Iodine-131 is used in medical treatments because it emits beta particles that can destroy cancerous cells. Its short half-life is an advantage because it allows for a higher dose of radiation to be delivered to the tumor while minimizing the amount of radiation exposure to healthy tissues. After a few weeks, the Iodine-131 decays to a negligible amount and the patient is no longer radioactive.
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Ag2S forms a black precipitate and CdS forms a dark yellow precipitate. A solution of CdS is prepared by dissolving 0. 25 moles of solid CdS in distilled water. When equilibrium is established, a small amount of dark yellow solid remains on the bottom. A 0. 25 mol if solid AgNO3 is then stirred into the beaker, and the dark yellow precipitate is replaced with a black precipitate.
I. Did the following equilibrium shift after the AgNO3 was added? Explain using 2-3 sentences.
CdS (s) equilibrium arrows Cd 2+ (aq) + S 2- (aq)
II. Which compound has the larger Ksp value? Justify your answer
Yes, the equilibrium shifted after the AgNO₃ was added and Ag₂S having a larger Ksp value as compared to CdS.
The addition of AgNO₃ provides Ag⁺ ions, which react with S₂⁻ ions in the solution to form insoluble Ag₂S, causing the equilibrium to shift towards the products. This results in the formation of a black precipitate, indicating the presence of Ag₂S.
Ag₂S has a larger Ksp value compared to CdS. This is because Ag₂S has a lower solubility product constant (Ksp) than CdS, which means it is less soluble in water. The Ksp value for Ag₂S is 8.5 x 10⁻⁵¹, while the Ksp value for CdS is 4.0 x 10⁻²⁷. Therefore, Ag₂S has a larger Ksp value and is less soluble in water than CdS.
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- Which of the following is a reason that Lewis electron dot diagram only show electrons in the outermost orbital of an atom?
A reason that Lewis electron dot diagram only show electrons in the outermost orbital of an atom
(d) Only outer shell electrons can be involved in chemical bonds.
What does the Lewis electron dot diagram show?The Lewis electron dot diagram shows only the valence electrons or outer shell electrons of an atom because these are the electrons that are involved in chemical bonding.
In a chemical reaction, atoms try to achieve a stable electron configuration by either gaining, losing, or sharing electrons. The valence electrons are located in the highest energy level of an atom and are the ones that are involved in chemical bonding with other atoms.
Therefore, the Lewis dot diagram is a visual representation of the valence electrons of an atom, which shows how the valence electrons are shared, gained, or lost in chemical bonding.
Thus, option (d) is the correct answer.
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complete question
Which of the following is a reason that Lewis electron dot diagram
only show electrons in the outermost orbital of an atom?
(a) Outer- shell electrons have energy than inner-shell electrons.
(b) Lewis electron dot diagram would get too complicated if each atom showed all of its electrons.
(C) inner-shell electrons cannot be proven to exist and thus should not be included in a Lewis electron dot structure.
(d) Only outer shell electrons can be involved in chemical bonds.
Which choice shows the image of Figure 1
1
being transformed with a translation of 4
4
units down followed by a rotation of 90°
90
°
counterclockwise around the origin?
The middle-placed graph illustrates the appropriate transformation.
What is the name for a chemical change?Chemical transitions, also called chemical reactions, are the processes by which one or more chemicals are changed into one or more novel and separate substances. In other words, a catalyst involving atom rearrangement is referred to as a chemical transformation.
How does transformation work?An transformation is a significant modification of form or appearance. A significant life change can result from an event like acquiring your driver's license, enrolling in college, or getting married. A transformation is indeed a significant, dramatic change.
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Answer: number 2
Explanation:
well you see if the bottom left corner of the shape which we are going to call Q first starts at (5,2) and we move it 4 down then we have (5,-2).
Now for the tricky part if we are moving it 90° counterclockwise around the origin. to put it simple and a easy way to understand is if you just turn your head sideways to the left and just put what you had in the first (top right) box and copy onto the top left box.
So instead of Q being (5,-2), Q would be (2,5).
I hope this helps and if I'm too late and you alertly answered it then I hope this helps anyone else who might have this problem and stumbles upon this.
A gas at 300 k and 4. 0 atm is moved to a new location with a temperature of 250 k. The volume changes from 5. 5 l to 2. 0 l. What is the pressure of the gas at the new location? use the formula: p1v1 t1 = p2v2 t2
The pressure of the gas at the new location is approximately 7.92 atm.
To solve this problem using the formula provided, we need to plug in the given values for the initial state (denoted by subscript 1) and the final state (denoted by subscript 2) of the gas:
p₁v₁t₁ = p₂v₂t₂
where:
p₁ = 4.0 atm (initial pressure)
v₁ = 5.5 L (initial volume)
t₁ = 300 K (initial temperature)
p₂ = ? (what we are solving for)
v₂ = 2.0 L (final volume)
t₂ = 250 K (final temperature)
We can rearrange the equation to solve for p₂:
p₂ = p₁v₁t₁ / v₂t₂
Substituting the given values:
p₂ = (4.0 atm) x (5.5 L) x (300 K) / (2.0 L) x (250 K)
p₂ = 7.92 atm
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Answer:
its 9.2 atm
Explanation:
If 1.90 g of silver are produced from the reaction, how many moles of copper(II) nitrate are also produced?
If 1.90 g of silver are produced from the reaction, then 0.0176 moles of copper(II) nitrate are also produced.
Why is a chemical reaction?A chemical reaction occurs when moving molecules hit each other, breaking their bonds and producing an exchange of atoms that form new products. Another way a chemical reaction can occur is through the vibration of substances; when they do so with sufficient energy, they can be broken down into smaller molecules.
we need to use the balanced chemical equation,
3Cu(NO3)2 + 2Al → 3Cu + 2Al(NO3)3
we can see that 3 moles of Cu(NO3)2 react with 2 moles of Al to produce 3 moles of Cu. Therefore, the molar ratio of Cu(NO3)2 to Cu is 3:3 or 1:1.
m(Ag) = 1.90 g
M(Ag) = 107.87 g/mol
n(Ag) = m(Ag) / M(Ag)
n(Ag) = 1.90 g / 107.87 g/mol
n(Ag) = 0.0176 mol
The molar ratio of Cu(NO3)2 to Cu is 1:1, the moles of Cu produced in the reaction is also 0.0176 mol. So, the number of moles of Cu(NO3)2 produced is also 0.0176 mol.
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Devise a synthesis of CH3CH2CH2CHO from two-carbon starting materials. Be sure to answer all parts. Step 1: Intermediate 1:
Initially, retrosynthesis The target molecule is the ultimate outcome of this process, and the intermediates and raw materials utilised to create the product are determined by a stepwise breakdown.
The chemical route can also be established using a retrosynthetic investigation.
Second step: retrosynthesis of CH3,CH2;CH2;CHO
To create a pathway where starts off as a two-carbon compound.
Step 3: CH3,CH2,CH2;CHO synthesis
The entire synthetic pathway of manufacturing depends on the retrosynthetic analysis.
Hydrocarbons with the carbonyl substituents are known as aldehydes. A hydrogen atom is also present in the material to which the quintuple oxygen is bonded. Aldehydes' carbonyl atoms are thus present at the hydrocarbon's terminal elements.
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"Complete question"
Deeply Devise a synthesis of CH3CH2CH2CHO from two-carbon starting materials. Be sure to answer all parts of the question Step 1: Intermediate 1?