Which of the following situations describes a continuous distribution? A probability distribution showing the number of vaccines given to babies during their first year of life A probability distribution showing the average number of days mothers spent in the hospital A probability distribution showing the weights of newborns A probability distribution showing the amount of births in a hospital in a month

Answers

Answer 1

Answer:

Continous distributions:

- A probability distribution showing the average number of days mothers spent in the hospital.

- A probability distribution showing the weights of newborns.

Step-by-step explanation:

A probability distribution showing the number of vaccines given to babies during their first year of life will have a discrete distribution as only a natural number can represent the number of vaccines (0, 1, 2 vaccines and so on).

A probability distribution showing the average number of days mothers spent in the hospital can be described as continous because we are averaging days and this average can be fractional, so it is not discrete.

A probability distribution showing the weights of newborns is continous, as the weights are a continous variable (physical measurement), not discrete.

A probability distribution showing the amount of births in a hospital in a month is a discrete distribution, as the number of births can only be represented by natural numbers.

Answer 2

The option that describes a continuous distribution include:

A probability distribution showing the average number of days mothers spent in the hospital.A probability distribution showing the weights of newborns.

A continuous distribution simply means the probabilities of the values of a continuous random variable.

Learn more about probability on:

https://brainly.com/question/24756209


Related Questions

What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3 . A.x - 3y - 7 = 0 B.x - 3y + 7 = 0 C.3x - y - 7 = 0

Answers

Answer:

The answer is option A

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

Equation of the line using point (1 , - 2) and slope 1/3 is

y + 2 = 1/3( x - 1)

Multiply through by 3

That's

3y + 6 = x - 1

Simplify

x - 3y - 1 - 6 = 0

We have the final answer as

x - 3y - 7 = 0

Hope this helps you

find the coordinates of Q' after a reflection across parallel lines; first across the line y= -2 and then across the x-axis​

Answers

Answer: new Q = (-4, 5)

Step-by-step explanation:

Given: Q = (-4, 1)

Reflected across y = -2:    

Q is 3 units above y = -2 so a reflection is 3 units below y = -2 --> Q' = (-4, -5)

Reflected across x-axis:    

Q' is 5 units below x-axis so a reflection is 5 units above x-axis --> Q'' = (-4, 5)

Simplify the expression . 39*x / 13

Answers

Answer:

3x

Step-by-step explanation:

39*x / 13

39/13 * x

3*x

3x

Answer:

3x

Step-by-step explanation:

We are given the expression:

39*x /13

We want to simplify this expression. It can be simplified because both the numerator (top number) and denominator (bottom number) can be evenly divided by 13.

(39*x /13) / (13/13)

(39x/13) / 1

3x / 1

When the denominator is 1, we can simply eliminate the denominator and leave the numerator as our answer.

3x

The expression 39*x/13 can be simplified to 3x

Lengths of pregnancies​ (in humans) have a mean of 267.6 days and a standard deviation of 15.4 days. A woman tracked her pregnancy and found it to be 309 days. Find the z score for 309 days. Is such a length​ unusual?

Answers

Answer:

The z-score is  [tex]z = 2.65[/tex]

The length of days is not unusual

Step-by-step explanation:

From the question we are told that

     The population mean is  [tex]\mu = 267.6 \ days[/tex]

     The standard deviation is  [tex]\sigma = 15.4 \ days[/tex]

      The value considered is  [tex]x = 309 \ days[/tex]

The z-score is mathematically represented as

           [tex]z = \frac{x - \mu}{\sigma }[/tex]

            [tex]z = \frac{309 - 267.6}{15.6 }[/tex]

           [tex]z = 2.65[/tex]

Now given that the z-score is not greater than 3  then we can say that the length of days is not unusual

(reference khan academy)

At what point does the line
Y = -1/2 X + 2 intercept the Y-axis?

A. - 1
B. -1/2
C. 1
D. 2
E. -2

Answers

Answer:

D. 2

Step-by-step explanation:

The y-intercept is when the graph crosses the y-axis when x = 0. In that case, simply plug in x as 0:

y = -1/2(0) + 2

y = 2

Therefore, the graph crosses the y-axis at 2.

Answer:

D

Step-by-step explanation:

our equation is y= [tex]\frac{-1}{2}[/tex] x +2

-1/2 is the slope 2 is the y-intercept

so the answer is 2

if we want to verify our answer we can follow these steps

the y-intercept is given by calculating the image of 0

y= -1/2*0+2 = 2

so it's right

Explain the relationship between variance and standard deviation. Can either of these measures be​ negative? Explain. Choose the correct answer below. A. The variance is the positive square root of the standard deviation. The standard deviation and variance can never be negative. Squared deviations can never be negative. B. The standard deviation is the positive square root of the variance. The standard deviation and variance can never be negative. Squared deviations can never be negative. C. The variance is the negative square root of the standard deviation. The variance can be negative but the standard deviation can never be negative. D. The standard deviation is the negative square root of the variance. The standard deviation can be negative but the variance can never be negative.

Answers

Answer:

A. The variance is the positive square root of the standard deviation. The standard deviation and variance can never be negative. Squared deviations can never be negative.

Step-by-step explanation:

As we know that

The standard deviation is the square root of the variance and on the other side the variance is the square of the standard deviation

In mathematically

[tex]\sigma = \sqrt{variance}[/tex]

And,

[tex]variance = \sigma^2[/tex]

Moreover, the standard deviation and the variance could never by negative neither the squared deviation is negative. All three are always positive

Hence, the correct option is a.

Answer:

B. The standard deviation is the positive square root of the variance. The standard deviation and variance can never be negative. Squared deviations can never be negative.

2.35=11x Equals What

Answers

Answer:

x=0.2136

Step-by-step explanation:

Answer:

x=0.214 rounded to the thousandths

Step-by-step explanation:

2.35=11x

divide each side by 11 to isolate the x

x=0.214 rounded to the thousandths

Perform the indicated operation. kyz * 1/kyz answer choices is 0 1 and k^2 y^2 z^2

Answers

Answer:

1

Step-by-step explanation:

[tex]\frac{kyz}{1}*\frac{1}{kyz} =\frac{kyz}{kyz}=1[/tex]

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Answers

Answer:

acute isosceles triangle

vertex angle, y =  44.0 degrees. (smallest angle)

Step-by-step explanation:

If the sides are in the ratio 4:4:3,

two of the sides have equal lengths, so it is an isosceles triangle.

Also, the sum of square of the two shorter sides is greater than the square of the longest side, so it is an acute triangle.

To find the smallest angle, we draw the perpendicular bisector of the base (side length 3) and form two right triangles.

The base angle x is given by the ratio

cos(x) = 1.5/4 = 3/8

Consequently the base angle is  arccos(3/8) = 68.0 degrees.

The vertex angle equals twice the complement of 68.0

vertex angle, y = 2 (90-68.0) = 44.0 degrees. (smallest angle)

Use the Chain Rule to find ∂z/∂s and ∂z/∂t. (Enter your answer only in terms of s and t. Please use * for multiplication between all factors.)
z = x8y9, x = s cos(t), y = s sin(t)
∂z/∂s =
∂z/∂t =

Answers

Answer:

Step-by-step explanation:

Using chain rule to find the partial deriviative of z with respect to s and t i.e ∂z/∂s and ∂z/∂t, we will use the following formula since it is composite in nature;

∂z/∂s = ∂z/∂x*∂x/∂s +  ∂z/∂y*∂y/∂s

Given the following relationships z = x⁸y⁹, x = s cos(t), y = s sin(t)

∂z/∂x = 8x⁷y⁹, ∂x/∂s = cos(t), ∂z/∂y = 9x⁸y⁸ and ∂y/∂s = sin(t)

On substitution;

∂z/∂s = 8x⁷y⁹(cos(t)) + 9x⁸y⁸ sin(t)

∂z/∂s = 8(scost)⁷(s sint)⁹(cos(t)) + 9(s cost)⁸(s sint)⁸ sin(t)

∂z/∂s = (8s⁷cos⁸t)s⁹sin⁹t + (9s⁸cos⁸t)s⁸sin⁹t

∂z/∂s = 8s¹⁶cos⁸tsin⁹t + 9s¹⁶cos⁸tsin⁹t

∂z/∂s = 17s¹⁶cos⁸tsin⁹t

∂z/∂t =  ∂z/∂x*∂x/∂t +  ∂z/∂y*∂y/∂t

∂x/∂t = -s sin(t) and ∂y/∂t = s cos(t)

∂z/∂t  = 8x⁷y⁹*(-s sint) + 9x⁸y⁸* (s cos(t))

∂z/∂t = 8(scost)⁷(s sint)⁹(-s sint) + 9(s cost)⁸(s sint)⁸(s cos(t))

∂z/∂t = -8s¹⁷cos⁷tsin¹⁰t + 9s¹⁷cos⁹tsin⁸t

∂z/∂t = -s¹⁷cos⁷tsin⁸t(8sin²t-9cos²t)

What is the y-intercept of the line described by the equation below? Y=3x - 6

Answers

We are given the equation y = 3x - 6

The slope-intercept form of a line is y = mx + b where m is the slope and b is the y-intercept.

The b value in this equation is -6, thus the y-intercept is -6.

Let me know if you need any clarifications, thanks!

Data was collected for a sample of organic snacks. The amount of sugar (in mg) in each snack is summarized in the histogram below. 2 4 6 8 10 amount of sugar (mg) 180 182 184 186 188 190 192 194 Frequency What is the sample size for this data set?

Answers

Answer:

The sample size is 30.

Step-by-step explanation:

The sample size of a histogram can be calculated by summing up all the frequencies of all the occurrences in the data set

From the question the frequency is given as

Frequency = 2 4 6 8 10

The sample size n =

2 + 4 + 6 + 8 + 10

= 30

Therefore the sample size n of the data set = 30

(a) Plot the following function ona Karnaugh map.(Do not expand to minterm form before plotting.)
F(A,B,C,D)=A‘B’+CD’+ABC +A’B’CD’+ABCD’
(b) Find the minimum sum of products.
(c) Find the minimum product of sums

Answers

Answer:

a) the K-map is in the attachment

f = Σm(0,1,2,3,6,10,14,15)

b) from the k-map, the minimum sum of products is

F = A'B' + CD' + ABC

c) the minimum product of sums is

F = (B' + C)(A' + C)(A+ B' +D')(A' + B + D')

Step-by-step explanation:

A Karnaugh map (K-map) is a pictorial framework used to limit the Boolean expressions without utilizing Boolean algebra theorems and equation controls.

a) the given function is f(A,B,C,D)=A‘B’+CD’+ABC +A’B’CD’+ABCD’

expanding the function as four variable terms

f(A,B,C,D)=A‘B’+CD’+ABC +A’B’CD’+ABCD’

= A'B'(C + C')(D + D')+(A + A')(B + B")CD' + ABC(D + D') + A'B'CD' + ABCD'

= A'B'CD + A'B'CD' + A'B'C'D' + ABCD' +AB'CD' + A'BCD' + A'B'CD' + ABCD +ABCD' + A'B'CD' + ABCD'

=A'B'CD + A'B'CD' + A'B'C'D + A'B'C'D' + ABCD' + AB'CD' + A'BCD' +ABCD

f = Σm(0,1,2,3,6,10,14,15)

note: diagram is in the attachment

b) the minterms for the minimum sum of product are

f = Σm(0,1,2,3,6,10,14,15)

simplifying the K-map(done in the attachment)

from the k-map, the minimum sum of products is

F = A'B' + CD' + ABC

c) the maxterms for the minimum product of sums are

f = ПM(4,5,7,8,9,11,12,13)

plot the K-map to find minimum product of sums(done in the attachment)

the minimum product of sums is

F = (B' + C)(A' + C)(A+ B' +D')(A' + B + D')

Find all x in set of real numbers R Superscript 4 that are mapped into the zero vector by the transformation Bold x maps to Upper A Bold x for the given matrix A.

Answers

Answer:

 [tex]x_3 = \left[\begin{array}{c}4&3&1\\0\end{array}\right][/tex]

Step-by-step explanation:

According to the given situation, The computation of all x in a set of a real number is shown below:

First we have to determine the [tex]\bar x[/tex] so that [tex]A \bar x = 0[/tex]

[tex]\left[\begin{array}{cccc}1&-3&5&-5\\0&1&-3&5\\2&-4&4&-4\end{array}\right][/tex]

Now the augmented matrix is

[tex]\left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\2&-4&4&-4\ |\ 0\end{array}\right][/tex]

After this, we decrease this to reduce the formation of the row echelon

[tex]R_3 = R_3 -2R_1 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\0&2&-6&6\ |\ 0\end{array}\right][/tex]

[tex]R_3 = R_3 -2R_2 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\0&0&0&-4\ |\ 0\end{array}\right][/tex]

[tex]R_2 = 4R_2 +5R_3 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&4&-12&0\ |\ 0\\0&0&0&-4\ |\ 0\end{array}\right][/tex]

[tex]R_2 = \frac{R_2}{4}, R_3 = \frac{R_3}{-4} \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&1\ |\ 0\end{array}\right][/tex]

[tex]R_1 = R_1 +3 R_2 \rightarrow \left[\begin{array}{cccc}1&0&-4&-5\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&-1\ |\ 0\end{array}\right][/tex]

[tex]R_1 = R_1 +5 R_3 \rightarrow \left[\begin{array}{cccc}1&0&-4&0\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&-1\ |\ 0\end{array}\right][/tex]

[tex]= x_1 - 4x_3 = 0\\\\x_1 = 4x_3\\\\x_2 - 3x_3 = 0\\\\ x_2 = 3x_3\\\\x_4 = 0[/tex]

[tex]x = \left[\begin{array}{c}4x_3&3x_3&x_3\\0\end{array}\right] \\\\ x_3 = \left[\begin{array}{c}4&3&1\\0\end{array}\right][/tex]

By applying the above matrix, we can easily reach an answer

Evan wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn, so he needs no fence on that side. The other three sides will be enclosed with wire fencing. If Evan has 1000 feet of fencing, you can find the dimensions that maximize the area of the enclosure. a) Let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn). Write an function for the area A of the enclosure in terms of w . (HINT first write two equations with w and l and A . Solve for l in one equation and substitute for l in the other). A(w) = ___________ b) What width would maximize the area? w = __________ c) What is the maximum area? A = _________ square feet

Answers

Answer:  A.   A=(1000-2w)*w      B. 250 feet

C.  125 000 square feet

Step-by-step explanation:

The area of rectangular is A=l*w    (1)

From another hand the length of the fence is 2*w+l=1000        (2)

L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.

Express l from (2):

l=1000-2w

Substitude l in (1) by 1000-2w

A=(1000-2w)*w        (3)   ( Part A. is done !)

Part B.

To find the width w  (Wmax) that corresponds to max of area A   we have to dind the roots of equation (1000-2w)w=0  ( we get it from (3))

w1=0  1000-2*w2=0

w2=500

Wmax= (w1+w2)/2=(0+500)/2=250 feet

The width that maximize area A is Wmax=250 feet

Part C.   Using (3) and the value of Wmax=250 we can write the following:

A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets

when a stone falls freely, the time taken to hit the ground varies as the square root of the distance fallen. If it takes four seconds th fall 78.4m, find how long would it takefor a stone to fall 500m​

Answers

Answer:

The stone would take approximately 10.107 seconds to fall 500 meters.

Step-by-step explanation:

According to the statement of the problem, the following relationship of direct proportionality is built:

[tex]t \propto y^{1/2}[/tex]

[tex]t = k\cdot t^{1/2}[/tex]

Where:

[tex]t[/tex] - Time spent by the stone, measured in seconds.

[tex]y[/tex] - Height change experimented by the stone, measured in meters.

[tex]k[/tex] - Proportionality constant, measured in [tex]\frac{s}{m^{1/2}}[/tex].

First, the proportionality constant is determined by clearing the respective variable and replacing all known variables:

[tex]k = \frac{t}{y^{1/2}}[/tex]

If [tex]t = 4\,s[/tex] and [tex]y=78.4\,m[/tex], then:

[tex]k = \frac{4\,s}{(78.4\,m)^{1/2}}[/tex]

[tex]k \approx 0.452\,\frac{s}{m^{1/2}}[/tex]

Then, the expression is [tex]t = 0.452\cdot y^{1/2}[/tex]. Finally, if [tex]y = 500\,m[/tex], then the time is:

[tex]t = 0.452\cdot (500\,m)^{1/2}[/tex]

[tex]t \approx 10.107\,s[/tex]

The stone would take approximately 10.107 seconds to fall 500 meters.

About 5% of the population has a particular genetic mutation. 500 people are randomly selected. Find the standard deviation for the number of people with the genetic mutation in such groups of 500.

Answers

Answer:

4.87

Step-by-step explanation:

According to the given situation, for calculation of standard deviation for the number of people first we need to calculate the variance which is shown below:-

Variance is

[tex]np(1 - p)\\\\ = 500\times (0.05)\times (1 - 0.05)[/tex]

After solving the above equation we will get

= 23.75

Now the standard deviation is

[tex]= \sqrt{\sigma} \\\\ = \sqrt{23.75}[/tex]

= 4.873397172

or

= 4.87

Therefore for computing the standard variation we simply applied the above formula.

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 11 ft high

Answers

Answer:

0.0526ft/min

Step-by-step explanation:

Since the gravel being dumped is in the shape of a cone, we will use the formula for calculating the volume of a cone.

Volume of a cone V = πr²h/3

If the diameter and the height are equal, then r = h

V = πh²h/3

V = πh³/3

If the gravel is being dumped from a conveyor belt at a rate of 20 ft³/min, then dV/dt = 20ft³/min

Using chain rule to get the expression for dV/dt;

dV/dt = dV/dh * dh/dt

From the formula above, dV/dh = 3πh²/3

dV/dh =  πh²

dV/dt = πh²dh/dt

20 = πh²dh/dt

To calculate how fast the height of the pile is increasing when the pile is 11 ft high, we will substitute h = 11 into the resulting expression and solve for dh/dt.

20 = π(11)²dh/dt

20 = 121πdh/dt

dh/dt = 20/121π

dh/dt = 20/380.133

dh/dt = 0.0526ft/min

This means that the height of the pile is increasing at  0.0526ft/min

Construct the confidence interval for the population mean mu. c = 0.90​, x = 16.9​, s = 9.0​, and n = 45. A 90​% confidence interval for mu is:______.

Answers

Answer:

The  90%  confidence interval for population mean is   [tex]14.7 < \mu < 19.1[/tex]

Step-by-step explanation:

From the question we are told that

   The sample mean is  [tex]\= x = 16.9[/tex]

    The confidence level is  [tex]C = 0.90[/tex]

     The sample size is  [tex]n = 45[/tex]

     The standard deviation

Now given that the confidence level is  0.90 the  level of significance is mathematically evaluated as

       [tex]\alpha = 1-0.90[/tex]

       [tex]\alpha = 0.10[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex]  from the standardized normal distribution table. The values is  [tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]

The  reason we are obtaining critical values for [tex]\frac{\alpha }{2}[/tex]  instead of  that of  [tex]\alpha[/tex]  is because [tex]\alpha[/tex]  represents the area under the normal curve where the confidence level 1 - [tex]\alpha[/tex] (90%)  did not cover which include both the left and right tail while [tex]\frac{\alpha }{2}[/tex]  is just considering the area of one tail which is what we required calculate the margin of error

  Generally the margin of error is mathematically evaluated as

        [tex]MOE = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

         [tex]MOE = 1.645* \frac{ 9 }{\sqrt{45} }[/tex]

         [tex]MOE = 2.207[/tex]

The  90%  confidence level interval is mathematically represented as

      [tex]\= x - MOE < \mu < \= x + MOE[/tex]

substituting values

     [tex]16.9 - 2.207 < \mu < 16.9 + 2.207[/tex]

    [tex]16.9 - 2.207 < \mu < 16.9 + 2.207[/tex]

     [tex]14.7 < \mu < 19.1[/tex]

         

6th grade math help me, please :))

Answers

Answer:

[tex]\sf a) \ 2.5\\b) \ 7.5[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{250}{100}[/tex]

[tex]\sf Express \ as \ a \ decimal.[/tex]

[tex]=2.5[/tex]

[tex]\sf Multiply \ 3\% \ with \ 250.[/tex]

[tex]\displaystyle 250 \times \frac{3}{100}[/tex]

[tex]\displaystyle \frac{750}{100}=7.5[/tex]

A table of values of a linear function is shown below. Find the output when the input is N. Type your answer in the space provide

Answers

Answer:

[tex] -3n - 7 [/tex]

Step-by-step explanation:

Considering the linear function represented in the table above, to find what output an input "n" would give, we need to first find an equation that defines the linear function.

Using the slope-intercept formula, y = mx + b, let's find the equation.

Where,

m = the increase in output ÷ increase in input = [tex] \frac{-13 - (-10)}{2 - 1} [/tex]

[tex] m = \frac{-13 + 10}{1} [/tex]

[tex] m = \frac{-3}{1} [/tex]

[tex] m = -3 [/tex]

Using any if the given pairs, i.e., (1, -10), plug in the values as x and y in the equation formula to solve for b, which is the y-intercept

[tex] y = mx + b [/tex]

[tex] -10 = -3(1) + b [/tex]

[tex] -10 = -3 + b [/tex]

Add 3 to both sides:

[tex] -10 + 3 = -3 + b + 3 [/tex]

[tex] -7 = b [/tex]

[tex] b = -7 [/tex]

The equation of the given linear function can be written as:

[tex] y = -3x - 7 [/tex]

Or

[tex] f(x) = -3x - 7 [/tex]

Therefore, if the input is n, the output would be:

[tex] f(n) = -3n - 7 [/tex]

Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases.

a. Central area = 0.95, df = 10
b. Central area = 0.95, df = 20
c. Central area = 0.99, df = 20
d. Central area = 0.99, df = 60
e. Upper-tail area = 0.01, df = 30
f. Lower-tail area = 0.025, df = 5

Answers

Answer:

a) Central area = 0.95, df = 10 t = (-2.228, 2.228)

(b) Central area = 0.95, df = 20 t= (-2.086, 2.086)

(c) Central area = 0.99, df = 20 t= ( -2.845, 2.845)

(d) Central area = 0.99, df = 60 t= (-2.660, 2.660)

(e) Upper-tail area = 0.01, df = 30 t= 2.457

(f) Lower-tail area = 0.025, df = 5 t= -2.571

Step-by-step explanation:

In this question, we are to determine the t critical value that will capture the t-curve area in the cases below;

We can use the t-table for this by using the appropriate confidence interval with the corresponding degree of freedom.

The following are the answers obtained from the table;

a) Central area = 0.95, df = 10 t = (-2.228, 2.228)

(b) Central area = 0.95, df = 20 t= (-2.086, 2.086)

(c) Central area = 0.99, df = 20 t= ( -2.845, 2.845)

(d) Central area = 0.99, df = 60 t= (-2.660, 2.660)

(e) Upper-tail area = 0.01, df = 30 t= 2.457

(f) Lower-tail area = 0.025, df = 5 t= -2.571

Find the value of a A.130 B.86 C.58 D.65

Answers

Answer:

Option (B)

Step-by-step explanation:

If two chords intersect inside a circle, measure of angle formed is one half the sum of the arcs intercepted by the vertical angles.

Therefore, 86° = [tex]\frac{1}{2}(a+c)[/tex]

a + c = 172°

Since the chords intercepting arcs a and c are of the same length, measures of the intercepted arcs by these chords will be same.

Therefore, a = c

⇒ a = c = 86°

Therefore, a = 86°

Option (B) will be the answer.

he numbers of regular season wins for 10 football teams in a given season are given below. Determine the​ range, mean,​ variance, and standard deviation of the population data set. 2​, 10​, 15​, 3​, 13​, 9​, 14​, 7​, 2​, 9 The range is nothing.

Answers

Answer:

Range = 13

Mean = 8.4

Variance= 21.24

Standard deviation= 4.61

Step-by-step explanation:

2​, 10​, 15​, 3​, 13​, 9​, 14​, 7​, 2​, 9

For the range

Let the set of data be arranged inn ascending order

Range= higehest value- lowest value

Range = 15-2

Range= 13

For the mean

Mean = (2+2+3+7+9+9+10+13+14+15)/10

Mean = 84/10

Mean = 8.4

For variance

Variance=((2-8.4)²+(2-8.4)²+(3-8.4)²+(7-8.4)²+(9-8.4)²+(9-8.4)²+(10-8.4)²+(13-8.4)²+(14-8.4)²+(15-8.4)²)/10

Variance= (40.96+40.96+29.16+1.96+0.36+0.36+2.56+21.16+31.36+43.56)/10

Variance= 212.4/10

Variance= 21.24

Standard deviation= √variance

Standard deviation= √21.24

Standard deviation= 4.609

Approximately = 4.61

Write these as normal numbers

Answers

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A.) 7.2 x 10^-5 = 0.000000072

B.) 6.3 x 10^-9 = 0.0000000063

C.) 4.54 x 10^-5 = 0.0000454

D.) 7.041 x 10^-10 = 0.0000000007041

Hope this helped!!  ٩(◕‿◕。)۶

The numbers can be written as;

A.) 7.2 x 10^{-5} = 0.000000072

B.) 6.3 x 10^{-9} = 0.0000000063

C.) 4.54 x 10^{-5} = 0.0000454

D.) 7.041 x 10^{-10} = 0.0000000007041

What is the fundamental principle of multiplication?

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

We are given the parameters

We need to Write these as normal numbers

A.) 7.2 x 10^{-5} = 0.000000072

B.) 6.3 x 10^{-9} = 0.0000000063

C.) 4.54 x 10^{-5} = 0.0000454

D.) 7.041 x 10^{-10} = 0.0000000007041

Learn more about multiplications;

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I need help with this problem.​

Answers

________________________Alike______________________

→ Both of the lines are proportional meaning they go through the origin.

→ Both of the lines have a positive slope meaning the slope goes towards the top right corner.

__________________________________________________

_____________________Difference_____________________

→ The 2 lines have different slopes, the first one has a slope of 1/3x whereas the 2nd one has a slope of 3x.

→ The points that create the lines are totally different, no two points are the same.

__________________________________________________

A club is holding a raffle. Ten thousand
tickets have been sold for $2 each. There
will be a 1st prize of $3000, 3 second prizes
of $1000 each, 5 third prizes of $500 each
and 20 consolation prizes of $100 each.
Find the expected winnings of a single ticket.

Answers

Answer: Other answer is incorrect. It’s asking for the expected winnings of a single ticket. The answer is -.95

Step-by-step explanation:

1/10,000

3/10,000

5/10,000

20/10,000

9971/10,000

-

2998

998

498

98

-2

-

2998+2994+2490+1960-1992 =

-9500/10000 = -.95

A catering service offers 11 appetizers, 12 main courses, and 8 desserts. A customer is to select 9 appetizers, 2 main courses, and 3 desserts for a banquet. In how many ways can this be done?

Answers

Answer:  203,280

Step-by-step explanation:

Given: A catering service offers 11 appetizers, 12 main courses, and 8 desserts.

Number of combinations of choosing r things out of n = [tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]

A customer is to select 9 appetizers, 2 main courses, and 3 desserts for a banquet.

Total number of ways to do this: [tex]^{11}C_9\times ^{12}C_2\times^{8}C_3[/tex]

[tex]=\dfrac{11!}{9!2!}\times\dfrac{12!}{2!10!}\times\dfrac{8!}{3!5!}\\\\=\dfrac{11\times10}{2}\times\dfrac{12\times11}{2}\times\dfrac{8\times7\times6}{3\times2}\\\\= 203280[/tex]

hence , this can be done in 203,280 ways.

Identify an equation in point-slope form for the line perpendicular to
y= - 1/3x - 6 that passes through (-1,5).

O A. y + 1 = 3(x - 5)
O B. y + 5 = 1/3(x - 1)
O C. y - 5 = 3(x + 1)
O D. y - 5 = - 1/3(x + 1)

Answers

Answer:

hope you get it....sorry for any mistake calculations

About 9% of the population has a particular genetic mutation. 600 people are randomly selected.

Find the standard deviation for the number of people with the genetic mutation in such groups of 600.

Answers

Answer:

The mean for all such groups randomly selected is 0.09*800=72.

Step-by-step explanation:

The value of the standard deviation is 7.

What is the standard deviation?

Standard deviation is defined as the amount of variation or the deviation of the numbers from each other.

The standard deviation is calculated by using the formula,

[tex]\sigma = \sqrt{Npq}[/tex]

N = 600

p = 9%= 0.09

q = 1 - p= 1 - 0.09= 0.91

Put the values in the formulas.

[tex]\sigma = \sqrt{Npq}[/tex]

[tex]\sigma = \sqrt{600 \times 0.09\times 0.91}[/tex]

[tex]\sigma[/tex] = 7

Therefore, the value of the standard deviation is 7.

To know more about standard deviation follow

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