The question his incomplete, the complete question is;
Which of the following required Bohr's model of the atom to need modification
A. energies of electrons are quantized
b. electrons do not follow circular orbits around the nucleus
c. Quantized electrons energies are responsible for emission spectra lines
d. an electrons energy increases the farther it moves from the nucleus
Answer:
electrons do not follow circular orbits around the nucleus
Explanation:
Neils Bohr's model of the atom closely follows the planetary model of Rutherford, hence is it sometimes referred to as the Bohr-Rutherford's model of the atom. Its main points are that;
Electrons are found in circular orbits
Electronic transition within the atom leads to spectral lines
The energy of an orbit is related to its size.
One major refinement of the Bohr's model of the atom is the Bohr-sommerfield model. Sommerfeld added that electrons are found in elliptical rather than circular orbits. This Bohr-sommerfield model was able to explain atomic spectral effects, such as the Stark effect in spectral line splitting.
Hence, the fact that electrons are found in elliptical rather than circular orbits was a major failure of Bohr's original proposition.
Answer:
Electrons do not follow circular orbits around the nucleus
Explanation:
The Ka of hypochlorous acid (HClO) is 3.00 x 10-8. What is the pH at 25 ∘C of an aqueous solution that is 0.0200 M in HClO?
Answer:
[tex]pH=4.6[/tex]
Explanation:
Hello,
In this case, the dissociation of hypochlorous acid is:
[tex]HClO_4\rightleftharpoons H^++ClO_4[/tex]
Therefore, the law of mass action for equilibrium is written as:
[tex]Ka=\frac{[H^+][ClO_4^-]}{HClO_4} =3.00x10^{-8}[/tex]
And can also be written introducing the reaction extent ([tex]x[/tex]):
[tex]3.00x10^{-8}=\frac{x*x}{0.0200-x}[/tex]
Thus, solving for [tex]x[/tex] we obtain:
[tex]x=2.45x10^{-5}M[/tex]
Which is also equal to the concentration of H⁺ in the solution. Thereby, the pH turns out:
[tex]pH=-log([H^+])=-log(2.45x10^{-5})\\\\pH=4.6[/tex]
Which is substantiated by the fact it is about an acid (pH lower than 7).
Regards.
pH=4.6
Given:
Ka= [tex]3.00*10^{-8}[/tex]
[HClO]=0.0200 M
The dissociation of hypochlorous acid is:
[tex]HOCl[/tex] ⇌ [tex]ClO^- +H^+[/tex]
Therefore, the law of mass action for equilibrium is written as:
[tex]K_a= \frac{[H^+] [ClO^-]} {[HOCl]} \\[/tex]
At equilibrium [tex][H^+] \text{and} [ClO^-][/tex]be x and [HClO] be [0.0200-x]
On substituting the values in given equation we will get:
[tex]3.00 * 10^{-8}=\frac{[x]*[x]}{[0.0200-x]}\\\\3.00 * 10^{-8}=\frac{x^2}{[0.0200-x]}\\\\x=2.45*10^{-5} M[/tex]
This is also equal to the concentration of H⁺ in the solution. Therefore, the pH turns out:
[tex]pH= -log[H^+] \\\\pH= -log [2.45 * 10^{-5}]\\\\pH=4.6[/tex]
Hence, the pH of an aqueous solution is 4.6.
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when dissolved in water, an acid or a base breaks down into a. a proton and an electron b. two negative ions c. a positive and a negative ion d. a positive ion and a proton
Answer:
C. A positive and a negative ion
Explanation:
Acids and bases are made up of charged particles known as ions. The ions present in acids are oppositely charged and are held together by strong electrostatic forces. When acids or bases are dissolved in water, the electrostatic forces holding their individual molecules together are weakened and these ions are free to move apart in a process known as dissociation. Dissociation occurs because of the attraction between the positive and negative ions in the acid and bases and the negative and positive polarity of water.
For example, when an acid like hydrochloric acid is dissolved in water it dissociates into positive and negative ions as follows:
HCl(aq) -----> H+ + Cl-
When a base like sodium hydroxide is dissolved in water, it dissociates into positive and negative ions as follows:
NaOH(aq) ----> Na+ + OH-
Answer:
yeah C is correct
Explanation:
Rubidium has two naturally occurring isotopes. The average atomic mass of Rb is 85.4678 amu. If 72.15% of Rb is found as Rb-85 (84.9117 amu), what is the mass of the other isotope?
Answer:
x = 86.908 amu
Explanation:
Average mass of isotope = 85.4678 amu
Rb-85 = 84.9117 amu, Percentage = 72.15% = 0.7215
Other isotope = x, Percentage = 100 - 72.15 = 27.85% = 0.2785
Average mass = (Percentage * Mass of Rb-85) + (Percentage * Mass of Rb-87)
85.4678 = (0.7215 * 84.9117) + (0.2785 * x)
85.4678 = 61.2638 + 0.2785x
0.2785x = 24.204
x = 24.204 / 0.2785
x = 86.908 amu
86.908 amu
It is given that:
Average atomic mass of Rb = 85.4678 amu.
Also the mass of Rb-85 = 84.9117 amu and its Percentage = 72.15% = 0.7215
Let the mass of other isotope (Rb-87) = x
So, Percentage of other isotope (Rb-87) = 100 - 72.15 = 27.85% = 0.2785
Average mass = (Percentage * Mass of Rb-85) + (Percentage * Mass of Rb-87)
85.4678 = (0.7215 * 84.9117) + (0.2785 * x)
85.4678 = 61.2638 + 0.2785x
0.2785 x = 24.204
x = 24.204 / 0.2785
x = 86.908 amu
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What is ductility in a solid?
Answer:
Ductility is the how stretchable a solid is under tension. If a solid is ductile, then it can be stretched into wire-like (think rubber band). Ductility is similar to malleability and physical components of solids.
Explanation:
Why Graphite is Diamagnetic?
Answer: Through years of studying and research ;
Graphite has shown that in weak and quantizing magnetic fields it is material is a highly anisotropie diamagnetic substance whose non-oscillating part of the magnetic suscepti- bility weakly depends on magnetic field.
Explanation:
Diamagnetism is a (very) weak form of magnetism which is caused (induced) by a change in the orbital motion of electrons mostly due to an applied magnetic field.
Each of these geometric shapes has a different number of sides. Arrange the shapes in order from the shape with the greatest number of sides to the shape with the fewest number of sides.
1. triangle
2. square
3. rectangle
4. octagon
5. hexagon
6. pentagon
Given that a theoretical yield for isolating Calcium Carbonate in this experiment would be 100%. From that information and based on the results you obtained in this experiment, describe your success in the recovery of calcium carbonate and suggest two possible sources of error that would have caused you to not obtain 100% yield.
Answer:
It's well Explained below.
Explanation:
First of Excess product of CaCO_3 would be produced due to the fact that there would not be enough CaCl_2 to react with Na_2•CO_3. The main purpose of having stoichiometric quantities is for us to know the correct amount or near the correct amount of each reactant in order to create a product that will be close to the theoretical amount and thus have a higher percent yield.
Among the following bonds, which would be the least polar? Electronegativity values are: Na = 0.9, O = 3.5, F = 4.0, Cl = 3.0, Br = 2.8, I = 2.5
Answer:
e. Na_I
Explanation:
a. Na–O
b. Na–F
c. Na–Cl
d. Na–Br
e. Na–I
Bond polarity can be calculated, examining the Pauling scale electronegativity values of the two atoms. The difference between these values will determine the predominant type of bond between the respective atoms.
Therefore, Na-I would be least polar bond. (The difference in the electronegativies of the two atom is least)
Dinitrogen tetraoxide, a colorless gas, exists in equilibrium with nitrogen dioxide, a reddish brown gas.
One way to represent this equilibrium is:
N2O4(g)----------> 2NO2(g)
<----------
Indicate whether each of the following statements is true or false
At equilibrium at a fixed temperature, we can say that:
1. The concentration of NO2 is equal to the concentration of N2O4.
2. The rate of dissociation of N2O4 is equal to the rate of formation of N2O4.
3. The rate constant for the forward reaction is equal to the rate constant of the reverse reaction.
4. The concentration of NO2 divided by the concentration of N2O4 is equal to the same constant (regardless of initial concentrations)
Explanation:
N2O4(g) <----------> 2NO2(g)
Before proceeding,
A chemical equilibrium can be defined as a condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs.
Statement 1.
This statement is false. Equilibrium is not about equal concentrations but rather zero change in concentration of the reactants and products.
Statement 2.
This statement is True in chemical equilibrium; the forward and reverse reactions occur at equal rates.
Statement 3.
This statement is False. The rate constant for the forward reaction is not equal to the rate constant of the reverse reaction.
Statement 4.
The concentration of NO2 divided by the concentration of N2O4 is NOT equal to a constant. To obtain a constant value irregardless of the concentrations, the concentration of NO2 must be squared. This comes from the stoichiometry of the reaction
Kc= [NO2]2 / [N2O4]
This statement is false.
Which pair of factors affects the force of gravity between objects
Answer:
The Answer is B. Mass and distance
Explanation:
Trust me lol
Answer:mass and distance
Explanation:
Select all the true statements regarding chemical equilibrium.
At equilibrium...
A. the concentrations of reactants and products are equal.
B. the concentrations of reactants and products remain constant.
C. reactants are still being converted to products (and vice versa).
D. the rates of the forward and reverse reactions are equal.
Answer:
Choice B, C, and D.
Explanation:
Choice A is not true in general. Here's a way to think about that. Consider a very special equilibrium where the concentration of reactants and products are indeed equal. When one of the external factors (such as temperature) changes, the equilibrium will shift towards either side of the reaction. More products will be converted to reactants, or vice versa. Either way, in the new equilibrium, the concentration of the reactants and products will not be equal any more.
Choice B should be considered with choice C and D in mind.
Choice C is indeed correct. The reaction rate would not be zero unless all the reactants were used up or taken out of the system. That's not what happens in an equilibrium. Instead, when reaction rate is plotted against time, the graph for reactions in both directions will eventually flat out at a non-zero value.
Choice D explains why even though choice C is correct, the concentration of a system at equilibrium stays the same. At the equilibrium, reactions in both directions are still happening. However, during the time it takes for the forward reaction use up some reactant particles, the reverse reaction would have produced these particles again. On a large scale, there would be no observable change to the concentration of each species in the equilibrium. Therefore, choice B is also correct.
Using the volumes of sodium thiosulfate solution you just entered, the mass of bleach sample, and the average molarity of the sodium thiosulfate solution entered earlier, calculate the mass percent of NaClO for each bleach sample. Enter the calculated mass percent of NaClO in each of the 3 acceptable trials (For the first trial, the volume of sodium thiosulfate =10.1, mass of bleach is 0.496g, and average molarity of sodium thiosulfate=0.042M)
Answer:
3.18 (w/w) %
Explanation:
In the problem, you can find mass of NaClO knowing the reaction of NaClO with Na₂S₂O₃ is:
NaClO + 2Na₂S₂O₃ + H₂O → NaCl + Na₂S₄O₆ +2NaOH + NaCl
Where 1 mole of NaClO reacts with 2 moles of Na₂S₂O₃
Moles of thiosulfate in the titration are:
0.0101L ₓ (0.042mol / L) = 4.242x10⁻⁴ moles of Na₂S₂O₃
Thus, moles of NaClO in the initial solution are:
4.242x10⁻⁴ moles of Na₂S₂O₃ ₓ (1mol NaClO / 2 mol Na₂S₂O₃) = 2.121x10⁻⁴ moles NaClO
As molar mass of NaClO is 74.44g/mol, mass of 2.121x10⁻⁴ moles are:
2.121x10⁻⁴ moles ₓ (74.44g / mol) = 0.0158g of NaClO
As mass of bleach is 0.496g, mass percent is:
0.0158g NaClO / 0.496g bleach ₓ 100 =
3.18 (w/w) %Question 14 of 25
2 Points
Which of the following is a cost of mining aluminum from new bauxite
deposits?
A. It helps preserve plants and animals in rain forests.
O O O
B. It requires a large amount of energy.
C. It takes less energy to transport this lightweight metal
D. It can be recycled over and over again.
Answer:
it can be recycled over and over again
Answer:
It requires a large amount of energy
Explanation:
You are provided with a compound fertilizer, 40-15-10.Calculate the quantity of fertilizer to add to a one hectare field supply (a) Nitrogen at 120kg/ha (b) Nitrogen at 90kg/ha (c) Phosphorus at a rate of 60kg/ha (d) Potassium at a rate of 60kg/ha
Answer:
a. 300 kg of Fertilizer
b. 225 kg of fertilizer
c.400 Kg of fertilizer
d.600 Kg of fertilizer
Explanation:
The percentage composition ratio of Nitrogen, Phosphorus and Potassium bag of the given fertilizer is 40:15:10.
The percentages can be expressed as fractions as follows:
For nitrogen; 40/100 = 0.4
For phosphorus; 15/100 = 0.15
For potassium; 10/100 = 0.1
To find the quantity of fertilizer required to add to a hectare to supply the given amount of nutrients, the amount to be provided is divided by the percentage or fractional compostion of each nutrient.
Quantity of fertilizer required to add to a hectare to supply;
a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer
b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer
c. Phosphorus at 60 kg/ha = 60/0.15 = 400 Kg of fertilizer
d. Potassium at 60 kg/ha = 60/0.1 = 600 Kg of fertilizer
Electrons in atoms exist in particular energy level. A ___ must be emitted or absorbed to move between energy levels.
Answer:
Photon of light
Explanation:
According to Bohr's model of the atom, electrons in atoms are found in specific energy levels. These energy levels are called stationary states, an electrons does not radiate energy when it occupies any of these stationary states.
However, an electron may absorb energy and move from one energy level or stationary state to another. The energy difference between the two energy levels must correspond to the energy of the photon of light absorbed in order to make the transition possible.
Since electrons are generally unstable in excited states, the electron quickly jumps back to ground states and emits the excess energy absorbed. The frequency or wavelength of the emitted photon can now be measured and used to characterize the transition. This is the principle behind many spectrometric and spectrophotometric methods.
why is copper and iron are used for cooking utensils
Answer:
because according to the electron sea model they are good conductor of heat so,they can be used for cooking.
An aqueous solution____
Answer:
A solution in which the solvent is water.
Explanation:
Something is dissolved in water.
(-)-Cholesterol has a specific rotation of -32o. A mixture of ( )- and (-)-cholesterol was analyzed by polarimetry, and the observed rotation was 14o. What is the percent composition of the ( ) isomer in this mixture
Answer:
(+)-cholesterol = 71.88%
(-)-cholesterol = 28.12%
Explanation:
Asuming 1 gram of sample is dissolved in 1mL of water and the sample cell was 1dm long.
Enantiomeric excess is defined as the amount of pure enantiomer in a sample. The formula is:
ee = [α]mixture / [α]pure enantiomer.
Replacing:
ee = 14° / 32°×100 = 43.75%
As the sample is 14°, There is an excess of (+)-cholesterol and 56.25% is a 1:1 mixture of enantiomers.
That means percent composition of enantiomers is:
(+)-cholesterol = 43.75% + 56.25%/2 = 71.88%(-)-cholesterol = 56.25%/2 = 28.12%Is the production of ammonium sulfate from sulfuric acid a redox reaction? Explain using oxidation numbers.
Answer:
Explanation:
HSO4 --> (NH4)2SO4
Yes it is a redox reaction.
H is +1
S is +7
on the other side..
N is -3
H is +1 (always +1, thats part of the oxidation rule)
S is +6
O is always -2
So what happened? Sulfur lost one electron, so it is reduced. This is why is a redox reaction.
A small amount of red paint is mixed with water. When a laser pointer shines through the mixture, the beam is clearly visible in the mixture. This mixture is a .
Answer: Heterogeneous (Colloid)
Explanation: This is because your solution is a colloid. A colloidal solution has particles between 40 and 900 nm and as the laser light shines through the paint and Water mixture, the paint particles scatter the light because of the Tyndall Effect (Named after the physicist John Tyndall). A Colloidal Solution is a heterogeneous solution that looks like its homogeneous but is a mixture of very small particles that don't really become a solution.
A small amount of red paint is mixed with water. When a laser pointer shines through the mixture, the beam is clearly visible in the mixture. This mixture is a Heterogeneous.
What is mixture?A mixture is a substance made by combining two or more dissimilar chemical compounds that are not chemically linked in chemistry. When two or more substances are physically combined, their identities are maintained, and the mixture takes the shape of solutions, suspensions, or colloids.
Chemical elements and compounds, among others, can be mechanically blended or mixed to create mixtures without causing any chemical bonding and other chemical change, preserving the chemical characteristics and makeup of each ingredient. A small amount of red paint is mixed with water. When a laser pointer shines through the mixture, the beam is clearly visible in the mixture. This mixture is a Heterogeneous.
Therefore, the mixture is Heterogeneous mixture.
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Which element has the largest atomic radius
Answer:
Francium
Explanation:
The atomic radius increases from top to bottom in a group, and decreases from left to right across a period.
so francium (Fr) is the largest atom or has highest radii.
Hope this helps & please mark as brainiest!
Answer:
Francium has the largest atomic radius.
The general trend for atomic radii is increasing from top to bottom and decreasing from left to right so the one with the largest atomic radius will be in the bottom left of the periodic table.
In the reaction C+02 arrow C02 which element is reduced in the reaction? C O2 CO2
Answer:
O2
Explanation:
Answer:
o2
Explanation:
edge
Describe the formation of an aqueous libr solution when solid libr dissolves in water
Fill in the blanks with words given below.
K and I atoms
K and IF ions
dissociation
atoms
KI molecules
polar dilution
hydration
molecules ions
nonpolar
At the_______ surface of the solid _____________are pulled into solution by___________ the water molecules, where the______________ process surrounds separate with water molecules.
Answer and Explanation:
The water is a polar solvent which dissolves into the LiBr molecules and converts into [tex]Li^+[/tex] and [tex]Br^-[/tex] ions far from the solid also into the solution, when they are hydrated.
Now, the complete words are as given below:-
The [tex]K^+[/tex] and [tex]I^-[/tex] ions at the surface of the solid are pulled into the solution by the polar water molecules, where the hydration process surrounds separate ions with water molecules.
LiBr has been the ionic compound and has been dissociated in the water by the force of the polar water molecules. The water molecules that have been polar in nature exert the force onto the ionic compounds and help in the dissociation.
At the dissociation surface of the solid KI molecules, are pulled into the solution by the polar water molecules, where the hydration process surrounds ions and separates them with water molecules.
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Identify which of the following are carbohydrates.
Check oh that apply
Answer:
3d and 4th
Explanation:
Carbohydrates general formula (CH2O)n.
Not 1st one because it has NH2-group.
2nd - C3H6O4, also it is acid.
3d - C3H6O3
4th - C6H12O6
Among the given compounds only compound present in 3rd option is a carbohydrate.
What are carbohydrates?Carbohydrates are the organic molecules which are made up of oxygen atom, carbon atom and hydrogen atom and general molecular formula of carbohydrates is CₙH₂ₙOₙ, where n is the number of atoms.
In the carbohydrate molecule, alcoholic group and aldehyde groups may present.
First given compound is not a carbohydrates as in that NH₃ group is present.Second given compound is also not a carbohydrate as in that carboxylic (-COOH) group is present.Third compound is a carbohydrate as in that compound same number of carbon and oxygen atoms are present and number of hydrogen atom is double to C & O atom.Fourth compound is also not a carbohydrate, as in that molecule number of carbon and oxygen atom is same but number of hydrogen is not double with respect to C & O.Hence compound C is carbohydrate.
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Consider the following four solutions: a. NaCl in water b. Acetic acid in water c. Acetic acid in benzene d. Naphthalene in benzene Which of these solutions has the strongest solute-solvent interactions and the interaction is of which type?1. Acetic acid in water; hydrogen bonding2. Acetic acid in benzene; dipole-induced dipole interaction3. NaCl in water; ion-dipole interaction4. Naphthalene in benzene; London Dispersion Forces5. NaCl in water; hydrogen bonding
Answer:
NaCl in water; ion-dipole interaction
Explanation:
Sodium chloride is an ionic solid. Ionic solids dissolve in water due to ion dipole interaction. Ionic solids are composed of an ion pair which are strongly bound by electrostatic interaction between the oppositely charged ions in the solid state.
When an ionic substance is dissolved in water, the positive ion interacts with the negative end of the dipole in water while the negative ion interacts with the positive end of the dipole in water. Hence the ions are pulled apart by this ion-dipole interaction and the crystal structure of the solid collapses as the ionic solid dissolves in water.
Sodium chloride is an ionic solid. Interaction between the sodium ion and the negative end of the dipole in water as well as chloride ion and the positive end of the dipole in water leads to the dissolution of sodium chloride solid in water. This is the strongest solute-solvent interaction in the list.
When The strongest solute-solvent interactions and the interaction the correct option is A NaCl in water; ion-dipole interaction
What is Sodium chloride?
Sodium chloride is an ionic solid. Ionic solids liquefy in water due to ion-dipole interaction. Ionic solids are formed of an ion team that is strongly bound by electrostatic interaction between the differently delegated ions in the solid-state.
When an ionic substance is disbanded in water, the positive ion interacts with the negative end of the dipole in the water while the opposing ion interacts with the positive end of the dipole in water. Therefore the ions are dragged apart by this ion-dipole interaction and also when the crystal configuration of the solid collapses as the ionic solid dissolves in water.
Sodium chloride is an ionic solid. The interchange between the sodium ion and the negative future of the dipole in water as well as the chloride ion and the positive end of the dipole in water leads to the abolishment of sodium chloride solid in water. This is the strongest solute-solvent exchange on the list.
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A student wants to make a 0.250 M aqueous solution of silver nitrate, AgNO3, and has a bottle containing 15.89 g of silver nitrate. What should be the final volume of the solution? When you give your numerical answer, what is the correct significant figures and how do you know that is the correct amount?
Answer:
0.374 L
Explanation:
Step 1: Given data
Mass of silver nitrate (solute): 15.89 g
Molarity of the solution: 0.250 M
Step 2: Calculate the moles of silver nitrate
The molar mass of silver nitrate is 169.87 g/mol.
[tex]15.89g \times \frac{1mol}{169.87g} = 0.09354mol[/tex]
Step 3: Calculate the volume of the solution
The molarity is equal to the moles of solute divided by the liters of solution.
[tex]M = \frac{moles\ of\ solute }{volume\ of\ solution} \\volume\ of\ solution = \frac{moles\ of\ solute}{M} = \frac{0.09354mol}{0250mol/L} = 0.374 L[/tex]
Due to the significant figures rules, we keep 3 significant figures.
Answer:
0.37416 L
Explanation:
M = mol/L
molar mass ( for AgNO₃ ) = 169.87 g
moles = given mass/molar mass
15.89 g/169.87 = .09354
.250 = .09354/L
= 0.37416
The Solvay process is used to manufacture baking soda, NaHCO3. In the process, CO2, NH3, HzO, and NaCl react to produce baking soda. If 15.0 L CO2 and 10.0 L NH3 react at STP, with excess water and sodium chloride, what is the limiting reactant
Answer:
The limiting reactant between is NH₃.
Explanation:
The reaction of the Solvay process is:
CO₂(g) + NH₃(g) + H₂O(l) + NaCl(s) ⇄ NaHCO₃(s) + NH₄Cl(aq) (1)
Since the water and the sodium chloride are in excess we need to find the number of moles of CO₂ and NH₃ at STP (1 amt, 273 K).
[tex] PV = nRT \rightarrow n = \frac{PV}{RT} [/tex]
Where:
n: is the number of moles
P: is the pressure = 1 atm
V: is the volume
T: is the temperature = 273 K
R: is the gas constant = 0.082 L*atm(K*mol)
For CO₂ we have:
[tex] n = \frac{PV}{RT} = \frac{1 atm*15.0 L}{0.082 L*atm/(K*mol)*273 K} = 0.67 moles [/tex]
And for NH₃ we have:
[tex] n = \frac{PV}{RT} = \frac{1 atm*10.0 L}{0.082 L*atm/(K*mol)*273 K} = 0.45 moles [/tex]
From the equation (1) we have that 1 mol of CO₂ reacts with 1 mol of NH₃, so from that ratio we have:
[tex] n_{CO_{2}} = \frac{\eta_{CO_{2}}}{\eta_{NH_{3}}}*n_{NH_{3}} = \frac{1}{1}*0.45 moles} = 0.45 moles [/tex]
From above we have that 1 mol of NH₃ reacts with 0.45 moles of CO₂, and we have 0.67 moles of CO₂, hence the limiting reactant is NH₃.
Therefore, the limiting reactant between CO₂ and NH₃ is NH₃.
I hope it helps you!
if 2.22 moles of ammonia (NH3) decomposes according to the reaction shown how many moles of hydrogen (H2) are formed?
Answer:
five(5) hydrogen are formed
what is the molarity of a solution that contains 49.8 grams of nai and is dissolved in enough water to make 1.50 liters
Answer: The molarity of solution is 0.221 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in L
moles of [tex]NaI[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{49.8g}{149.89g/mol}=0.332mol[/tex]
Now put all the given values in the formula of molality, we get
[tex]Molarity=\frac{0.332mol}{1.50L}[/tex]
[tex]Molarity=0.221mol/L[/tex]
Therefore, the molarity of solution is 0.221 M
chromate is sparingly soluble in aqueous solutions. The Ksp of Ag2CrO4 is 1.12×10−12 . What is the solubility (in mol/L) of silver chromate in 1.00 M potassium chromate aqueous solution?
Answer:
[tex]6.5X10^-^5~\frac{mol}{L}[/tex]
Explanation:
For this question, we have to start with the ionization equation for [tex]Ag_2CrO_4_(_s_)[/tex], so:
[tex]Ag_2CrO_4_(_s_)~<->~2Ag^+~_(_a_q_)~+~CrO_4^-^2_(_a_q_)[/tex]
With this in mind we can write the Ksp expression:
[tex]Kps~=~[Ag^+]^2[CrO_4^-^2][/tex]
Additionally, for every mole of [tex]CrO_4^-^2[/tex] formed, 2 moles of [tex]Ag^+[/tex] are formed. We can use "X" for the unknown concentration of each ion, so:
[tex][CrO_4^-^2]~=~X[/tex] and [tex][Ag^+]~=~2X[/tex]
Now, we can plug the values into the Ksp expression:
[tex]1.12x10^-^1^2~=~(2X)^2(X)[/tex]
Now we can solve for "X" :
[tex]1.12x10^-^1^2~=~4X^3[/tex]
[tex]X^3=\frac{1.12X10^-^1^2~}{4}[/tex]
[tex]X=(\frac{1.12X10^-^1^2~}{4})^(^1^/^3^)[/tex]
[tex]X=6.5X10^-^5~\frac{mol}{L}[/tex]
I hope it helps!