Which of the following pairs of elements have valence electrons
in the same energy level?

Answer:

to something in action there is always a equal and opposite reaction. Like if you bounce a bounce ball on the ground, it will bounce back.

Explanation:

Answer:

a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis

b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction

c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis

Explanation:

For this exercise we draw a Cartesian coordinate system in this system: East coincides with the positive part of the x-axis and North with the positive part of the y-axis.

a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis

b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction

c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis

In the attachment we can see the representation of the three vectors

Answer:

Objetos que se encuentran en movimiento:

1) Un automóvil pasando por la calle.

2) Una crustácea que se acerca a mi casa.

3) Un avión volando en el cielo.

4) Un repartidor de comida desplazándose en una bicicleta.

5) Las aspas del ventilador en rotación.

6) Una hojarasca afuera de la casa.

7) La puerta de mi habitación abrirse.

8) Un mosquito entrando por la ventana.

9) Un metrónomo en movimiento.

10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.

Objetos que se encuentran en reposo:

1) El semáforo de la esquina.

2) El automóvil de mi madre.

3) Las sillas del comedor.

4) Un jarrón de porcelana.

5) La nevera de la cocina.

6) La mesa de noche de mi habitación.

7) El automóvil de policía en la calle.

8) La impresora de memes.

9) El estante de libros.

10) El cesto de galletas.

Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:

(i) Traslación.

(ii) Rotación.

(iii) Deformación.

Explanation:

Objetos que se encuentran en movimiento:

1) Un automóvil pasando por la calle.

2) Una crustácea que se acerca a mi casa.

3) Un avión volando en el cielo.

4) Un repartidor de comida desplazándose en una bicicleta.

5) Las aspas del ventilador en rotación.

6) Una hojarasca afuera de la casa.

7) La puerta de mi habitación abrirse.

8) Un mosquito entrando por la ventana.

9) Un metrónomo en movimiento.

10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.

Objetos que se encuentran en reposo:

1) El semáforo de la esquina.

2) El automóvil de mi madre.

3) Las sillas del comedor.

4) Un jarrón de porcelana.

5) La nevera de la cocina.

6) La mesa de noche de mi habitación.

7) El automóvil de policía en la calle.

8) La impresora de memes.

9) El estante de libros.

10) El cesto de galletas.

Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:

(i) Traslación.

(ii) Rotación.

(iii) Deformación.

Answer:

1. Equal and opposite reaction

2. Pairs

3. That is equal

Explanation:

I have tried my best but without knowing your curriculum or the possible answers it is difficult to know exactly what the answer would be... :(

Please mark as branliest ;)

- Hope this helped!

Answer: The microwaves are reflected within the metal interior of the oven where they are absorbed by food. Microwaves cause water molecules in food to vibrate, producing heat that cooks the food.

Explanation:

Answer:

A sound wave that has a higher frequency is a wave that makes 12 cycles per second.

Explanation:

The frequency of a wave is the same as the frequency of the vibrations that caused the wave. This takes more energy, so a higher-frequency wave has more energy than a lower-frequency wave with the same amplitude.

Answer:

30 30 30 yuhhhhhhhhhhhh

Answer:

20N

Explanation:

mass=weight/gravitational pull

mass=120/10

mass=12Kg

weight=mass×gravitational pull

=12× (⅙of 10)

=12×1.666666666667

=20N

Answer:

the answer is 12 second easy

Answer:

True

Explanation:

When the periodic time increases the frequency is lower.

Answer:

See explanation below

Explanation:

Recall that the force of static friction is the product of the coefficient of static friction between surface and object, times the force applied perpendicular to the surface.

In our case, that perpendicular force has magnitude equal to the centripetal acceleration times the mass m of the block. The centripetal acceleration is defined as the quotient between the square of the tangential velocity divided by the radius at which the rotating mass is located (in our case R).

In order to estimate the tangential velocity given the angular velocity ω, we simply multiply it by R:  

[tex]v_t=\omega\,R[/tex]

and therefore the force acting on the surface of the cylinder is:

[tex]F=m\,*\,a_c=m\,*\,\frac{v_t^2}{R} =m\,*\, \frac{\omega^2\,R^2}{R} =m\,*\,\omega^2\,*R[/tex]

The force of friction between the block and the inner wall of the hollow cylinder will then be:  [tex]f=\mu\, *\,m\,*\omega^2\,*\,R[/tex]

In order for this force of static friction to be able to prevent the mass to slide down due to gravity, we need that the friction force is at least equal to the gravitational force. That is:

[tex]f\geq F_g\\f\geq m\,*\,g\\\mu\,*\,m\,*\,\omega^2\,*\,R\geq m\,*\,g\\\mu\geq \frac{g}{\omega^2\,*\,R}[/tex]

The force of static friction to prevent the mass to slide down due to gravity, the friction force is must be equal or greater than to the gravitational force.

The force of static friction is the product of the coefficient of static friction between surface,and force applied perpendicular to the surface.

The tangential velocity,

[tex]\bold {V_t = \omega R}[/tex]

So,  the force acting on the surface of the cylinder,

[tex]\bold {F= m\times a_c}\\\\\bold {F= m \times \dfrac {V_t^2 }{R}}\\\\\bold {F = m \times \dfrac {\omega ^2R2}{R}}}\\\\\bold {F = m \times \omega ^2 \times R}[/tex]

The force of friction between the block and the inner wall of the hollow cylinder,

[tex]\bold {F_f = \mu \times m \times \omega ^2 \times R}[/tex]

Therefore, the force of static friction to prevent the mass to slide down due to gravity, the friction force is must be equal or grater than to the gravitational force.

To know more about static friction,

https://brainly.com/question/8790433

Answer:

a) The distance each child ran is approximately 0.232 m

b) The angular acceleration is 0.21[tex]\overline 6[/tex] rad/s²

Explanation:

The given parameters of the merry-go-round are;

The mass of the merry-go-round, m = 240-kg

The diameter of the merry-go-round, d = 4.00 m

The number of children pushing tangentially on the merry-go round = Four children

The spinning rate of the merry-go-round, n = 2.14 rev/minute

a) Given that the force exerted by each child = 26 N, we have;

The total force applied by the four children, F = 26 N × 4 = 104 N

The tangential acceleration, [tex]a_t[/tex] = F/m = 104 N/240-kg = 0.4[tex]\overline 3[/tex] m/s²

The angular acceleration, α = [tex]a_t[/tex]/r

Where, the radius of the merry-go-round, r = d/2

∴ r = 4.00 m/2 = 2.00 m

α = 0.4[tex]\overline 3[/tex] m/s²/(2.00 m) = 0.21[tex]\overline 6[/tex] rad/s²

We have;

ω² = ω₀² + 2·α·Δθ

The merry-go-round starts from rest, therefore; ω₀ = 0 rad/s

ω² = 2·α·Δθ

Δθ = ω²/(2·α)

n = 2.14 rev/minute

∴ ω = 2·π×2.14/60 rad/s ≈ 0.22410 rad/s

∴ Δθ = (0.22410 rad/s)²/(2 × 0.21[tex]\overline 6[/tex] rad/s²) ≈ 0.11589 rad

Therefore, the angle each child ran, θ = 0.11589 rad

The distance each child ran = r·θ

∴ The distance each child ran = 2.00 m × 0.11589 rad ≈ 0.232 m

b) From part 'a' above, the tangential acceleration, [tex]a_t[/tex] = 0.4[tex]\overline 3[/tex] m/s²

Angular acceleration, α = [tex]a_t[/tex]/r

∴ α = 0.4[tex]\overline 3[/tex] m/s²/(2.00 m) = 0.21[tex]\overline 6[/tex] rad/s²

The angular acceleration = 0.21[tex]\overline 6[/tex] rad/s²

understand friend

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Answer:

9.2m/s sir Thank me later

Answer:

Given

mass (m) =985 ☓ 0.001 , 0.985 kg

velocity (v) =3.82m/s

kinetic energy(k. e) =?

Form equation

[tex]k.e = \frac{1}{2} mv {}^{2} \\ = \frac{1}{2} \times 0.985 \times 3.82 {}^{2} \\ = 7.1868kj \\ kinetic \: enegy = 7.1868kj[/tex]

I hope this help

Answer:

z3

Explanation:

Thus 1 cm–3 = 1/cm3 and the units for our densities could be written as gcm3, g/cm3, or g cm–3. In each case the units are read as grams per cubic centimeter, the per indicating division.) We often abbreviate "cm3" as "cc", and 1 cm3 = 1 mL exactly by definition.

...

1.9: Density.

Answer:

5

Explanation:

density = mass/volume

density = 25g /5 mL

density = 5

Answer:

yes!

Explanation:

Answer:

yes!!

Explanation:

Answer:

20 N/m

Explanation:

From the question,

The ball-point pen obays hook's law.

From hook's law,

F = ke............................ Equation 1

Where F = Force, k = spring constant, e = compression.

Make k the subject of the equation

k = F/e........................ Equation 2

Given: F = 0.1 N, e = 0.005 m.

Substitute these values into equation 2

k = 0.1/0.005

k = 20 N/m.

Hence the spring constant of the tiny spring is 20 N/m

Answer:

A liquid becomes a gas.

Explanation:

I hope this helps a bit.

Answer:

Explanation:

Answer: None of the above I got it right on my test

Answer:

The magnitude of swing's tension is 0.71 N.

Explanation:

Given;

mass of the ball, m = 18 g = 0.018 kg

angular speed of the ball, ω = 1 rev/s

radius of the motion, r = 1 m

Angular speed in rad/s is calculated as follows;

[tex]\omega = \frac{2\pi \ rad}{rev} \times \frac{1 \ rev}{s} \\\\\omega = 2 \pi \ rad/s[/tex]

Linear speed of the ball, v;

v = ωr

v = 2π x 1

v = 2π  m/s

The magnitude of swing's tension is calculated as the centripetal force keeping the ball in circular motion.

[tex]F_c =T = \frac{mv^2}{r} \\\\T= \frac{0.018 \ \times (2\pi )^2}{1} \\\\T = 0.71 \ N[/tex]

Therefore, the magnitude of swing's tension is 0.71 N.

Answer:

It would be. Quarter dark

Explanation:

Sun's lights going all the way to the moon but there will still a dark part of it

it's obviously won't be neither complete light nor completely dark

so the right answer is: Quarter dark

Answer:

is this math of science

Explanation:

Answer:

C. Sternal Head, Clavicular Head

Answer:This is also known as the law of inertia.     EXPLANATION:  Inertia is the tendency of an object to remain at rest or remain in motion.

Answer: Euglena are photosynthetic

Explanation: USA test prep