Answer:
D. Kb = 1.8 × 10⁻⁵
Explanation:
The strongest base has the largest Kb value.
The largest Kb value has the smallest negative exponent.
So, the strongest base has Kb = 1.8 × 10⁻⁵.
The value of base dissociation constant (Kb) which represents the strongest base is 1.8×10⁻⁵.
What is strong base?Strong bases are those bases which completely dissociates into their ions and have high pH value in between 7 and 14.
pH value of any base is directly proportional to the value of base disssociation constant (Kb), means high value of Kb will indicates high value of pH i.e. hing basic strength. So, highest value of Kb is 1.8×10⁻⁵.
Hence 1.8×10⁻⁵ Kb value shows strong base.
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which of the following elements would you expect to behave most like magnesium?
a) sodium
b) calcium
c) aluminum
d) scandium
The element that would behave most likely magnesium is calcium. The correct option is b.
What is an element?An element is a material whose atoms all contain the same number of protons: that is, all atoms of each element have the same amount of protons.
Elements are the most basic chemical forms and thus cannot be broken down chemically.
A chemical element is something that cannot be broken down further through any chemical reaction. Every element's atom encompasses a distinct number of protons.
A pure element is defined in chemistry as a substance whose atoms all (or almost all) have the same atomic number, or number of protons.
Beryllium and Calcium exhibit chemical reactions similar to Magnesium.
Thus, the correct option is b.
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Can anyone help need answer asap
Answer:
Rises, sinks
the correct answer is B
Answer:
rises, sinks
Explanation:
Hot magma rises because as the temperature increases, it expands and becomes less dense. As it reaches the top, it cools down and becomes more dense, which means it will sink. Therefore, hot magma rises and cool magma sinks in convection mantle mechanism.
Given:
N2 + 3H2 → 2NH3
In the chemical reaction, how many grams of nitrogen are needed to completely react with 24.3 grams of hydrogen? Use the periodic table to get the weights of the elements.
Drag each number to the correct location to complete the analysis.
Answer:
113.4g of N2
Explanation:
Step 1:
The balanced equation for the reaction.
N2 + 3H2 —> 2NH3
Step 2:
Determination of the mass of N2 and H2 that reacted from the balanced equation. This is illustrated below:
Molar mass of N2 = 2x14 = 28g/mol
Mass of N2 from the balanced equation = 1 x 28 = 28g
Molar mass of H2 = 2x1 = 2g/mol
Mass of H2 from the balanced equation = 3 x 2 = 6g
From the balanced equation above, 28g of N2 reacted with 6g of H2.
Step 3:
Determination of the mass N2 required to react with 24.3g of H2.
The mass of N2 required to react with 24.3g of H2 can be obtained as follow:
From the balanced equation above, 28g of N2 reacted with 6g of H2.
Therefore, Xg of N2 will react 24.3g of H2 i.e
Xg of N2 = (28 x 24.3)/6
Xg of N2 = 113.4g
Therefore, 113.4g of N2 is required to react completely with 24.3g of H2.
24.3g H2 × 1 mol H2/2.016g H2 × 1 mol N2/3 mol H2 × 28.014 g N2/1 mol N2 = 113g N2
The reaction, C2H6) (l) + 3)2 (g) produces 2CO2 (g) + 3H2) (g), is the combustion of ethanol. What occurs as the reaction proceeds.
Answer:
So as the reaction proceeds we lose energy as the reaction is exothermic due to the delta H being negative, this shows that heat flows from the system to its surroundings.
Explanation:
2H6O (l) + 3O2 (g) = 2CO2 (g) + 3H2O (g)
2CH3CH2OH(l) + 3O2(g) = 2CO2(g) + 3H2O(g) ΔH = -1234.8kJ/mol
I'm pretty sure this is what your equation is supposed to be, seems to be an error where you've pasted it and it's replaced the O's with )
So as the reaction proceeds we lose energy as the reaction is exothermic due to the delta H being negative, this shows that heat flows from the system to its surroundings.
Determine the overall energy change for the reaction between hydrogen and oxygen shown in Question 13. Use Figure 2.
Answer:
–500KJ
Explanation:
Data obtained from the question include the following:
Heat of reactant (Hr) = 800KJ
Heat of product (Hp) = 300KJ
Enthalphy change (ΔH) =..?
The enthalphy change is simply defined as the difference between the heat of product and the heat of reactant i.e
Enthalphy change = Heat of product – Heat of reactant
ΔH = Hp – Hr
With the above formula, we can easily calculate the enthalphy change as follow
ΔH = Hp – Hr
ΔH = 300 – 800
ΔH = –500KJ.
Therefore, the overall energy change for the reaction between hydrogen and oxygen shown in the diagram above is –500KJ
1.46 g H2 is allowed to react with 10.5 g N2, producing 2.72 g NH3. What is the theoretical yield in grams for this reaction under the given conditions?
Express your answer to three significant figures and include the appropriate units.
Answer : The theoretical yield in grams for this reaction under the given conditions is, 8.28 grams.
Explanation : Given,
Mass of [tex]H_2[/tex] = 1.46 g
Mass of [tex]N_2[/tex] = 10.5 g
Molar mass of [tex]H_2[/tex] = 2 g/mol
Molar mass of [tex]N_2[/tex] = 28 g/mol
First we have to calculate the moles of [tex]H_2[/tex] and [tex]N_2[/tex].
[tex]\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}[/tex]
[tex]\text{Moles of }H_2=\frac{1.46g}{2g/mol}=0.73mol[/tex]
and,
[tex]\text{Moles of }N_2=\frac{\text{Given mass }N_2}{\text{Molar mass }N_2}[/tex]
[tex]\text{Moles of }N_2=\frac{10.5g}{28g/mol}=0.375mol[/tex]
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
[tex]3H_2+N_2\rightarrow 2NH_3[/tex]
From the balanced reaction we conclude that
As, 3 mole of [tex]H_2[/tex] react with 1 mole of [tex]N_2[/tex]
So, 0.73 moles of [tex]H_2[/tex] react with [tex]\frac{0.73}{3}=0.243[/tex] moles of [tex]N_2[/tex]
From this we conclude that, [tex]N_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]H_2[/tex] is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of [tex]NH_3[/tex]
From the reaction, we conclude that
As, 3 mole of [tex]H_2[/tex] react to give 2 mole of [tex]NH_3[/tex]
So, 0.73 mole of [tex]H_2[/tex] react to give [tex]\frac{2}{3}\times 0.73=0.487[/tex] mole of [tex]NH_3[/tex]
Now we have to calculate the mass of [tex]NH_3[/tex]
[tex]\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3[/tex]
Molar mass of [tex]NH_3[/tex] = 17 g/mole
[tex]\text{ Mass of }NH_3=(0.487moles)\times (17g/mole)=8.28g[/tex]
Therefore, the theoretical yield in grams for this reaction under the given conditions is, 8.28 grams.
How does water's dissolving power support life on Earth?
all but one is a method of passve transport in cells
osmosis
sodium/potassium pump
facilitated transport
Answer:
The answer is Osmosis........
Answer:
osmosis
Explanation:
osmosis is a method of passive transport in cells. osmosis in passive transport cells is of water
For the acids, use the formula pH = -log[H+). (Because HCl has 1 H+ ion per formula unit, [H+] equals the
molarity.) For water, use what you know about the pH of neutral solutions. For the bases, examine and
extend the pattern. DONE
0.1 M
НСІ
0.001 M
НСІ
0.00001 M
НСІ
Distilled
Water
0.00001 M
NaOH
0.001 M
NaOH
0.1 M
NaOH
pH
pH:
pH:
pH: 7
pH:
pH:
pH:
Answer:
pH = 1
pH = 3
pH = 5
pH = 9
pH = 11
pH = 13
Explanation:
The pH is defined as log [H⁺]. HCl in solution produce H⁺. That means HCl concentration is equal to H⁺ concentration. Thus:
- 0.1M HCl. pH = -log 0.1 = 1
- 0.001M HCl. pH = -log 0.001 = 3
- 0.00001M HCl. pH = -log 0.00001 = 5
For a base that produce OH⁻ in solution you can define a pOH as pOH = -log [OH⁻] knowing (For water equilibrium) pH = 14 - pOH
Thus, for the NaOH solutions:
- 0.00001M NaOH: pOH = -log 0.00001M = 5. pH = 14 - 5 = 9
- 0.001M NaOH: pOH = -log 0.001M = 3. pH = 14 - 3 = 11
- 0.00001M NaOH: pOH = -log 0.1M = 1. pH = 14 - 1 = 13
Answer:
pH = 1
pH = 3
pH = 5
pH= 7
pH = 9
pH = 11
pH = 13
Explanation:
Just did the test :)
2
The ware function
of
the particle is normalized. why?
Answer:
The probability of finding the particle somewhere in the universe must be equal to 1.