Answer:
B.) They affect the reproductive cells.
Which one of the following describes the molecular geometry of a molecule with four electron groups with only bonded pairs?
Answer:
correct answer is D
Explanation:
In the covalent bond, a pair of electrons is shared between two atoms, in this case we have 4 electrons in one atoms and they are shared in pairs, so for these as far apart as possible due to electron-electron repulsion between the electrons of different bonds it must have a TETRAHEDRAL geometry
the correct answer is D
the official world land speed record is1228.0km/h are on October 15,1997,by Andy green in the jet engine car then express the speed in the meters per second
Answer:
v = 341.11 m/s
Explanation:
Given that,
The official world land speed was recorded as 1228.0km/h on October 15,1997.
We need to find the speed in m/s.
We know that,
1 km = 1000 m
1 h = 3600 s
So,
[tex]v=1228\ km/h\\\\=1228\times \dfrac{1000\ m}{3600\ s}\\\\v=341.11\ m/s[/tex]
So, the required speed is 341.11 m/s.
Write a method which prevents ice from melting quickly.
Answer:
blocks of ice are usually covered with cloth or sawdust while being stored
The 5 kg red book is about to fall from a 2.1 m high bookshelf.
What is its PE?
Use g = 9.8 m/s2 for the acceleration due to gravity.
Answer:
w = d×f = 2.1 × ( 5×9.8)= 102.9J
Explanation:
because the question is asking for the energy PE
Answer:
[tex]\boxed {\boxed {\sf 102.9 \ J}}[/tex]
Explanation:
Potential energy is the energy an object possesses due to position. The formula is:
[tex]PE= m \times g \times h[/tex]
where m is the mass, g is the acceleration due to gravity, and h is the height.
We know the book is 5 kilograms and is on a 2.1 meter high bookshelf. Since this is on Earth, the acceleration due to gravity is 9.8 meters per square second.
m= 5 kg g= 9.8 m/s²h= 2.1 mSubstitute the values into the formula.
[tex]PE= 5 \ kg \times 9.8 \ m/s^2 \times 2.1 \ m[/tex]
Multiply the numbers together.
[tex]PE= 49 kg *m/s^2 *2.1 \ m[/tex]
[tex]PE= 102.9 \ kg*m^2/s^2[/tex]
1 kilogram square meter per square second ( 1 kg*m²/s²) is equal to 1 Joule (J). So, our answ er of 102.9 kg*m²/s² is equal to 102.9 J[tex]PE= 102.9 \ J[/tex]
The book has 102.9 Joules of gravitational potential energy.
SOMONE PLEASE HELP ASAP!!!!
I believe the answer is purple
What is gravitational force? -,-
Answer:
The force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface is called gravitational force.
A flying stationary kite is acted on by a force of 9.8 N downward. The wind exerts a force of 45 N at an angle of 50.0 degrees above the horizontal. Find the force that the string exerts on the kite.
Answer:
38 N, 40.0° below the horizontal
Explanation:
Force exerted by an object equals mass times acceleration of that object: F = m ⨉ a. To use this formula, you need to use SI units: Newtons for force, kilograms for mass, and meters per second squared for acceleration.
A rubber ball is dropped from a height of 1.5 m
(a) How long does it take to hit the ground?
Answer:
t =0.6
Explanation:
So this is just a basic kinematics where the only force acting on the ball is gravity (9.8 m/s2 [down] and air resistance is negligible.
∆d=vi∆t+1/2at2
Because you're dropping the ball, initial velocity is 0
1.5= 0*(∆t) + 1/2a*t2
After some rearranging, t= root ((2*∆d)/a) Therefore t= 0.5532833352 or root(15)/7 t=0.6s
Explain how newtons first law applies to the image to the left.
For variables control, a circuit voltage will be measured using a sample of five circuits. The past average voltage for samples of 5 units has been 3.4 volts, and the range has been 1.3 volts.
Required:
What would the upper and lower control limits be for the resulting control charts (average and range)?
Answer:
Average :
UCL = 4.15
LCL = 2.65
Range :
UCL = 2.75
LCL = 0
Explanation:
Given :
Sample size, n = 5
Average, X = 3.4
Range, R = 1.3
A2 for n = 5 ; equals 0.577 ( X chart table)
For the average :
Upper Control Limit (UCL) :
X + A2*R
3.4 + 0.577(1.3) = 4.1501
Lower Control Limit (LCL) :
X - A2*R
3.4 - 0.577(1.3) = 2.6499
FOR the range :
Upper Control Limit (UCL) :
UCL = D4*R
D4 for n = 5 ; equals = 2.114
UCL = 2.114*1.3 = 2.7482
Lower Control Limit (LCL) :
LCL = D3*R
D3 for n = 5 ; equals = 0
LCL = 0 * 1.3 = 0
A scientist is asking you what would happen to Radon-226 (represented by Ra on the graph and 226 is the atomic mass) if instead of a purple arrow after Radon-226 there was a single green arrow. What would the result of this reaction on Radon be?
A 60-W light bulb radiates electromagnetic waves uniformly in all directions. At a distance of 1.0 mm from the bulb, the light intensity is Io, the average energy density of the waves is u0, and the rms electric and magnetic field values are Eo and Bo, respectively.
Required:
a. What is the light intensity?
b. What is the average energy density of the waves?
c. What is the rms magnetic field value?
Answer:
The appropriate solution is:
(a) [tex]\frac{1}{4}(I_o)[/tex]
(b) [tex]\frac{1}{4} (u_o)[/tex]
(c) [tex]\frac{1}{2}B_o[/tex]
Explanation:
According to the question, the value is:
Power of bulb,
= 60 W
Distance,
= 1.0 mm
Now,
(a)
⇒ [tex]\frac{I}{I_o} =\frac{r_o_2}{r_2}[/tex]
On applying cross-multiplication, we get
⇒ [tex]I=I_o\times \frac{1_2}{2^2}[/tex]
⇒ [tex]=I_o\times \frac{1}{4}[/tex]
⇒ [tex]=\frac{1}{4} (I_o)[/tex]
(b)
As we know,
⇒ [tex]\frac{u}{u_o} =\frac{I}{I_o}[/tex]
By putting the values, we get
⇒ [tex]u=\frac{1}{4}(u_o)[/tex]
(c)
⇒ [tex]\frac{B^2}{B_o^2} =\frac{u}{u_o}[/tex]
[tex]=\frac{I}{I_o}[/tex]
⇒ [tex]B=B_o\times \sqrt{\frac{1}{4} }[/tex]
⇒ [tex]=\frac{1}{2}(B_o)[/tex]
A student pushes a laptop cart down the hallway by applying 20 Newtons force. The student pushes it 10 meters and
then stops at the water fountain with the cart and haves a sip of water. While he drinks from the water fountain, what
type of work is being done to the laptop cart.
Answer:
None.
Explanation:
By definition, work is a process that it happens when an applied forcecauses an object to change its position, i.e. to have a displacement.
Since the laptop cart is at rest while he stops at the water fountain, no
net work done is on the laptop cart.
What is the period of a wave, with a frequency of 0.75 Hertz?
Answer:
wavelength 4 cm
Explanation:
WILL MARK BRAINLIEST PLS HELP. A 3.33 x 10-6 F capacitor stores
8.15 x 10-4 J of energy. What is the
voltage across the capacitor?
(Pic shown)
Answer:
15.64 V
Explanation:
From the question given above, the following data were obtained:
Capacitor (C) = 3.33x10¯⁶ F
Energy (E) = 8.15×10¯⁴ J
Voltage (V) =?
The voltage across the capacitor can be obtained as follow:
E = ½CV²
8.15×10¯⁴ = 3.33x10¯⁶ × V²
Divide both side by 3.33x10¯⁶
V² = 8.15×10¯⁴ / 3.33x10¯⁶
Take the square root of both side
V = √(8.15×10¯⁴ / 3.33x10¯⁶)
V = 15.64 V
Thus, the voltage across the capacitor is 15.64 V
Answer:
22.12
Explanation:
on accellus
Q: Winding roads and sharp curves are inherently dangerous
because -
A- You can't see far ahead
B- The speed limit is so slow
C- There may be other vehicles traveling in the
opposite direction
D- You may struggle to stay at the same speed
Answer:
A) you can't see far ahead
D. You may struggle to stay at the same speed.
Winding roads and sharp curves are dangerous because of centrifugal forces while taking curves, whose classic formula is described below:
[tex]F = m\cdot \frac{v^{2}}{r}[/tex] (1)
Where:
[tex]F[/tex] - Centrifugal force, in newtons.[tex]v[/tex] - Speed, in meters per second.[tex]r[/tex] - Radius of curvature, in meters per second.Sharps curves are characterized by low radii of curvature. Given that centrifugal force is inversely proportional to the square radius of curvature and it is opposed to friction force between tires and pavement, if centrifugal force is higher than maximum static friction force, then a car accident could if driver does not decelerate.
Therefore, correct choice is D.
We kindly invite to see this question on centrifugal forces: https://brainly.com/question/545816
what is the focalength of the combination of two thin renses of power -5D and -2D placeci in contact with each other?
Answer:
f = - 0.143 m = - 14.3 cm
Explanation:
First, we will calculate the power of the combination of lenses:
P = P₁ + P₂
where,
P = Power of Combination = ?
P₁ = Power of first lens = - 5D
P₂ = Power of second lens = - 2D
Therefore,
P = - 5D - 2D
P = - 7D
Now, the focal length can be given as:
[tex]f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\[/tex]
f = - 0.143 m = - 14.3 cm
Negative focal length indicates that combination will act as diverging lens.
Smoke detectors fall into two major classes. Ionization detectors, the most common units, contain two parallel electrodes that are typically separated by 3 cm with a 5-V potential difference across them. The air molecules between the electrodes are ionized by collisions with helium nuclei that are produced by a radioactive source. Most units are initially fueled with 60 million nuclei of radioactive americium 241 (half-life 430 years). The now-ionized air molecules drift toward one of the electrodes with an average speed of 0.1 m/s and thus support a small current between the two electrodes. Smoke particles that enter and combine with the ions reduce the current and initiate an alarm.
Photoelectric detectors, by contrast, contain a light-emitting diode that sends a beam of unpolarized light across a small chamber. The light beam usually has a wavelength of 6.0 × 10–7m and has an intensity of 1.0 × 10–3 W. When smoke particles enter the chamber, the light scatters in all directions. A photocell then senses either the increase in the scattered light or the reduced intensity of the light beam and sets off the alarm. The speed of light in air is 3.0 × 108 m/s.
Ionization detectors respond faster to the large smoke particles of flaming fires; photoelectric detectors sense the small particles of smoldering fires more quickly. Modern units have both types of detectors.
When fewer than 3.75 × 106 americium nuclei remain, the ionization smoke detector will not operate due to insufficient ionization. How much time will pass before there are this many nuclei remaining?
a. 1720 years
b. 2150 years
c. 4300 years
d. 6880 years
Answer:
1720 years is the amount of time that will pass.
Option a) 1720 years is the correct answer
Explanation:
Given the data in the question;
Number of nuclei initially N₀ = 60 million = 60,000,000
After time t, Number of nuclei remaining N[tex]_{rem[/tex] = 3.75 × 10⁶
Also given that; half-life of radioactive americium [tex]t_{1/2[/tex] = 430 years.
so;
λ = ln2 / [tex]t_{1/2[/tex]
we substitute
λ = ln2 / 430 years
N[tex]_{rem[/tex] = N₀e^(-λt)
solve for t
t = 1/λ × ln( N₀/N[tex]_{rem[/tex] )
so we substitute
t = 1 / (ln2 / 430 years) × ln( 60,000,000 / ( 3.75 × 10⁶ ) )
t = ( 430 years / ln2 ) × ln( 60,000,000 / ( 3.75 × 10⁶ ) )
t = ( 430 years / 0.693147 ) × ln( 16 )
t = 620.359 years × 2.7725887
t = 1720.0003 ≈ 1720 years
Therefore, 1720 years is the amount of time that will pass.
Option a) 1720 years is the correct answer
how hot can the desert get
Answer:
134 f
Explanation:
The hottest temperature ever reliably measured in a desert was 134 degrees F, in Death Valley of the Mojave Desert in 1913.
Temperature. During the day, desert temperatures rise to an average of 38°C (a little over 100°F). At night, desert temperatures fall to an average of -3.9°C (about 25°F). At night, desert temperatures fall to an average of -3.9 degrees celsius (about 25 degrees fahrenheit).
Desert surfaces receive a little more than twice the solar radiation received by humid regions and lose almost twice as much heat at night. Many mean annual temperatures range from 20-25 degrees Celsius. The extreme maximum ranges from 43.5-49 degrees Celsius. Minimum temperatures sometimes drop to -18 degrees Celsius.
in which reaction is there a transformation of mass into energy
Answer:
There is a transformation of mass into energy un nuclear fusion
A box has base dimensions of 30 cm x 30 cm and a mass of 3 kg. Calculate to what
depth it sinks when placed in a tank of water (assume the sides are sufficiently high,
so that it floats). Density of water = 1000 kgm-3. Assume g=10 ms-2 for this problem.
Answer:
60
Explanation:
A box has base dimensions of 30 cm x 30 cm and a mass of 3 kg. Calculate to what
depth it sinks when placed in a tank of water (assume the sides are sufficiently high,
so that it floats). Density of water = 1000 kgm-3. Assume g=10 ms-2 for this problem.
HELP: I’ve been stuck on this problem for a while now.
Answer:
a.work done=force *displacement
=500N*46m
=23000 Joule
b.power=work done/time taken
=23000/25
=920 watt
c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)
=60kg*9.8m/s*14m
=8232 joule
Explanation:
How expensive is genetic counseling and reproductive technology?
Answer:
Genetic counseling without testing cost on average $213, whereas counseling, testing, and disclosure of results totaled $2057. A brief physician-based counseling instead of genetic counselor-based counseling would produce only small reductions in total costs.
hope it helps, please give me brainliest.
Explain how Law 1 applies to the image to the left.
Answer:
12
Explanation:
Answer:
12?
Explanation:
Water droplets forming on the outside of a cold glass of water on a hot, summer day is a example of which part of the water cycle?
Answer:
Condensation can also produce water droplets on the outside of soda cans or glasses of cold water. When warm air hits the cold surface, it reaches its dew point and condenses. This leaves droplets of water on the glass or can.
Explanation:
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 49.0 cm. The explorer finds that the pendulum completes 99.0 full swing cycles in a time of 125 s. What is the value of the acceleration of gravity on this planet?
Answer:
"12.122 m/s²" is the appropriate solution.
Explanation:
The given values in the question are:
Length,
l = 49.0 cm
or,
= [tex]49.0\times 10^{-2} \ m[/tex]
Time taken,
[tex]T = \frac{125}{99.0}[/tex]
[tex]=1.2626 \ s[/tex]
Now,
As we know,
⇒ [tex]T = 2 \pi\sqrt{\frac{l}{g} }[/tex]
or,
⇒ [tex]T^2=4 \pi^2[\frac{l}{g} ][/tex]
[tex]g = 4\pi^2[\frac{l}{T^2} ][/tex]
By substituting the above given values, we get
[tex]=\frac{4\times (3.14)^2\times (49.0\times 10^{-2})}{(1.2626)^2}[/tex]
[tex]=\frac{39.4384\times 49.0\times 10^{-2}}{1.59415876}[/tex]
[tex]=\frac{19.324816}{1.59415876}[/tex]
[tex]=12.122 \ m/s^2[/tex]
A block with mass M is placed on an inclined plane with slope angle q and is connected to a second hanging block with mass m by a cord passing over a small, frictionless pully. The coefficient of static friction μs and the coefficient of kinetic friction is μk. For what range values of of m will the blocks remain at rest if they are released from rest.
Answer:
The mass of the block m is:
[tex]m=M(sin(\theta)+\mu_{s}cos(\theta))[/tex]
Explanation:
Let's analyze the block by parts
For the block M
[tex]T-W_{x}-f_{f}=0[/tex] (1)
Where:
T is the tensionW(x) is the component of the weight in the x-directionF(f) is the friction force[tex]T-Mgsin(\theta)-\mu_{s}N=0[/tex]
[tex]T-Mgsin(\theta)-\mu_{s}Mgcos(\theta)=0[/tex]
For the block m
[tex]T-W=0[/tex]
[tex]T=mg[/tex] (2)
Now, let's combines equation (1) and (2):
[tex]mg-Mgsin(\theta)-\mu_{s}Mgcos(\theta)=0[/tex]
Finally, let's solve it for block m.
[tex]mg-Mg(sin(\theta)+\mu_{s}cos(\theta))=0[/tex]
[tex]m=M(sin(\theta)+\mu_{s}cos(\theta))[/tex]
I hope it helps you!
PLEASE HELP ME ASAP!!!!
If stretching a spring 3.50m causes a force of 20.0N, what is the spring constant of the spring?
A. 5.71 N/m
B. 70.O N/m
C. 16.5 N/m
D. 23.5 N/m
Answer:
A
Explanation:
Remark
One of the handiest things to know in physics is something called dimensional analysis.
Look at the answers you are given. All of them are in N/m. That means 2 things.
No conversions are necessary
You divide Newtons / meters. You don't need to worry too much about a formula.
But if need a formula, it is F = k * x and you need k
x = 3.5 m
F = 20.0 N
k = F / x
k = 20.0/3.5
k = 5.71 to 3 places.
Clara is volunteering at NASA where scientists use telescopes to learn more about our universe. Scientists use tools that look at different types of electromagnetic radiation. The tools are used to form images of objects in space out of the radiation.
Different types of telescopes detect different types of electromagnetic radiation. Choose the four types of electromagnetic radiation.
A. gamma rays
B. X-rays
C. spectrum
D. radio waves
E. visible light
F. complement
Answer:
A gamma rays
B x-rays
D radio waves
E visible light
The four types of electromagnetic radiation are: gamma rays, X-rays, radio waves, and visible light.
What is electromagnetic radiation?
A flow of energy in which the electrical and magnetic fields change simultaneously is known as electromagnetic radiation. Electromagnetic radiation includes radio waves, microwaves, infrared, visible, ultraviolet, X, and gamma rays among others.
Through oscillating magnetic and electrical fields produced by their particles, electromagnetic radiation travels through space and vacuum. Sir James Clerk Maxwell, a Scottish scientist, presented the Electromagnetic Radiation theory in the early 1870s.
Heinrich Hertz, a German physicist, confirmed it experimentally. According to Maxwell, as an electrically charged particle accelerates, alternating electrical and magnetic fields are created, aiding the particle's propagation.
Gamma rays, X-rays, radio waves, and visible light are four types of electromagnetic radiation.
Learn more about electromagnetic radiation here:
https://brainly.com/question/10759891
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