Which of the following is not a characteristic of electrical potential energy?

Answer: An jack makes changing a tire easier because it lifts up the car to get the tire off of the ground.

Explanation:

Answer:

Pressure of water = Voltage

Flow rate of water = Current

Obstructions present in the river = Resistance

Explanation:

We can describe Ohm's Law by using the river analogy,

(a) The velocity is "6.2 m/s".

(b) The average force is "800.83 N".

According to the question,

Force,

Deflection,

           = [tex]1.2\times 10^{-2} \ m[/tex]

As we know,

The work done,

→ [tex]W = F\times d[/tex]

       [tex]= 800\times 1.2\times 10^{-2}[/tex]

       [tex]= 9.6 \ J[/tex]

(a)

Given:

Mass of hand,

Now,

→ [tex]\frac{1}{2} mv^2 = 9.6 \ J[/tex]

         [tex]v = \sqrt{\frac{2\times 9.6}{0.50} }[/tex]

            [tex]= 6.2 \ m/s[/tex]

(b)

→ [tex]v^2 = u^2 +2ax[/tex]

→ [tex]a= \frac{v^2}{2x}[/tex]

     [tex]= \frac{(6.2)^2}{2\times 1.2\times 10^{-2}}[/tex]

     [tex]= 1601.67 \ m/s^2[/tex]

hence,

The average force will be:

→ [tex]F_{avg} = m\times a[/tex]

           [tex]= 0.50\times 1601.67[/tex]

           [tex]= 800.83 \ N[/tex]

Thus the above answers are correct.

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Answer:

b. inverse

Explanation:

[tex]E = \frac{V}{d} \\ d \: is \: the \: distance \\ [/tex]

Explanation:

Newton's second law of motion states F=ma which means force is equal to mass multiplied by acceleration which in simple terms means If you give mass force it will accelerate the concept of force in physics is any interaction that when unopposed will change the motion of an object.

Answer:

250w

Explanation:

W=Fd

W= 250 x 4= 1000J

P=E/t=1000/4s=250w

Answer:

Copper atoms lose electrons to sulfur atoms

Explanation:

a p e x (:

Answer:

I1 = ε/R1

I2 = ε/R2

I3 = ε/R3

Explanation:

From the image, we see that the resistors are connected in parallel. This means that the voltage passing through them is the same.

Now, formula for current is; I = V/R

In this case, V which is voltage is denoted by ε.

Thus;

I1 = ε/R1

I2 = ε/R2

I3 = ε/R3

Answer:

the magnitude of the magnetic field is 1.23 × 10⁻⁸ T  { in the +y direction }

Explanation:

Given the data in the question;

the relation between the electric field and the magnetic field in an electromagnetic wave can be written as follows;

c = E₀/B₀

where c is speed of light, E₀ is the amplitude of the electric field and B₀ is the amplitude of the magnetic field.

given that;  E₀ = 4.70 V/m, we know that; speed of light c = 3 × 10⁸ m/s

so from our relation; c = E₀/B₀

B₀ = E₀/c

we substitute

B₀ = 4.70 / 3 × 10⁸

B₀ = 1.23 × 10⁻⁸ T  { in the +y direction }

Therefore, the magnitude of the magnetic field is 1.23 × 10⁻⁸ T  { in the +y direction }

Answer:

Option B

Explanation:

Forces acting on the skier-

F1 [tex]= -mg sin(30)[/tex] down the slope  

F2 [tex]= -mg cos(30)[/tex]

F3 = friction force  [tex]= 0.74 mg cos(30)[/tex]  

Net force, down the slope  

[tex]= -mg sin(30)+ 0.74 mg cos(30)\\= mg(.74 cos(30)-sin(30))\\= 0.14mg\\= 1.38m[/tex]

Acceleration [tex]= F/m= 1.38[/tex] m/s2  

Acceleration remains constant, initial speed is 20 m/s

Speed at time t is [tex]1.38t- 20[/tex] m/s

Distance down the slope at time t is [tex]0.69t^2- 20t[/tex]

When the skier stops, her speed is 0. Thus,  

, [tex]1.38t- 20= 0\\t= 20/1.38\\= 14.5[/tex] seconds

Distance travelled in 14.5 seconds [tex]= (0.69)(14.52- 20(14.5)= -145 m[/tex](negative because it is down the slope).

Option B is correct

Seasonal change in the angle of sunlight, caused by the tilt of the Earth's axis, is the basic mechanism that results both in warmth of the weather and in length of the day.

Answer:

please give me brainlist and follow

Explanation:

Whilst first impressions can be important, your body language during the interview can make or break your overall performance. With experts saying that between 75-90% of communication is non-verbal, it is important to think about what your body is saying about you during an interview.

Answer:

Approximately [tex]281.25\; \rm m[/tex]. (Assuming that the drag on this ball is negligible, and that [tex]g = 10\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Assume that the drag (air friction) on this ball is negligible. Motion of this ball during the descent:

The horizontal velocity of this ball is constant during the descent. The horizontal distance that the ball has travelled during the descent is also given: [tex]x(\text{horizontal}) = 30\; \rm m[/tex]. Combine these two quantities to find the duration of this descent:

[tex]\begin{aligned}t &= \frac{x(\text{horizontal})}{v(\text{horizontal})} \\ &= \frac{30\; \rm m}{4\; \rm m \cdot s^{-1}} = 7.5\; \rm s\end{aligned}[/tex].

In other words, the ball in this question start at a vertical velocity of [tex]u = 0\; \rm m \cdot s^{-1}[/tex], accelerated downwards at [tex]g = 10\; \rm m \cdot s^{-2}[/tex], and reached the ground after [tex]t = 7.5\; \rm s[/tex].

Apply the SUVAT equation [tex]\displaystyle x(\text{vertical}) = -\frac{1}{2}\, g \cdot t^{2} + v_0\cdot t[/tex] to find the vertical displacement of this ball.

[tex]\begin{aligned}& x(\text{vertical}) \\[0.5em] &= -\frac{1}{2}\, g \cdot t^{2} + v_0\cdot t\\[0.5em] &= - \frac{1}{2} \times 10\; \rm m \cdot s^{-2} \times (7.5\; \rm s)^{2} \\ & \quad \quad + 0\; \rm m \cdot s^{-1} \times 7.5\; s \\[0.5em] &= -281.25\; \rm m\end{aligned}[/tex].

In other words, the ball is [tex]281.25\; \rm m[/tex] below where it was before the descent (hence the negative sign in front of the number.) The height of this cliff would be [tex]281.25\; \rm m\![/tex].

Answer:

(a)  0.273 A

(b) 4.368 V

(c) 1.638 V

Explanation:

From the question,

(a) Applying ohm's law

V = IR'...................... Equation 1

Where V = Voltage of the battery, I = Current in each of the resistor, R' = Total resistance of the combined resistors

Since the Two resisstors are connected in series,

(i) The same current flows through both resistors

(ii) The total resistor (R') = R₁+R₂

Therefore,

V = (R₁+R₂)I

Make I the subject of the equation

I = V/(R₁+R₂)................. Equation 2

Given: V = 6 V, R₁ = 16 Ω, R₂ = 6 Ω

Substitute into equation 2

I = 6/(16+6)

I = 6/22

I = 0.273 A

(b) The potential difference across the first resisto

V₁ = IR₁...................... Equation 3

Given: I = 0.273 A, R₁ = 16 Ω

Substitute these values into equation 3

V₁ = 0.273(16)

V₁ = 4.368 V

(c) The Potential difference across the second resistor is

V₂ = IR₂.................... Equation 4

V₂ = 0.273×6

V₂ = 1.638 V

The distance of the object to the lens will be a) 7.2 cm

The distance between the convex lens or a concave mirror and the focal point of a lens or mirror is called the focal length. It is the point where parallel rays of light meet or converge.

magnification (m) = h(image )/ h(object ) = image distance / object distance

given

h(image ) = 2.5 * h(object)

m =  2.5 * h(object)  /  h(object )  = 2.5

2.5 =  image distance / object distance

2.5 = v / u

v = 2.5 u

using lens formula

given

focal length (f) = + 12cm

1/v - 1/u = 1/focal length

1/2.5 u  - 1/u = 1/12

u = - 7.2 cm

correct option a)7.2 cm

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#SPJ2

Given the wavelength of the visible light photon, the energy of the photon is 3.54 × 10⁻¹⁹J

Given the data in the question;

Wavelength of visible light; [tex]\lambda = 560.6 nm = 5.606*10^{-7}m[/tex]

Speed of light; [tex]c = 2.998 * 10^8 m/s[/tex]

Planck's constant; [tex]h = 6.626 * 10^{-34} J.s[/tex]

The energy and wavelength of light are related by the equation:

[tex]E = \frac{hc}{\lambda}[/tex]

Where E is energy of photon in Joules, h is Planck's constant, c is the speed of light and λ is the wavelength,

We substitute our given value into the equation

[tex]E = \frac{(6.626*10^{-34}J.s)(2.998*10^8m/s)}{5.606*10^{-7}m} \\\\E = \frac{(1.986*10^{-25}J.m}{5.606*10^{-7}m}\\\\E = 3.54 * 10^{-19}J[/tex]

Therefore, given the wavelength of the visible light photon,  the energy of the photon is 3.54 × 10⁻¹⁹J

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Answer:

C

[tex]6 = \frac{3}{2} \lambda \\ wavelength : \: \lambda = 4 \: m \\ from \: wave \: equation \\ v = f\lambda \\ v = 8 \times 4 \\ v = 24 \: {ms}^{ - 1} [/tex]

The speed of the waves will be =  [tex]24\dfrac{m}{s}[/tex]

Given data is frequency f = 8.0 Hz

As we know that the speed of the wave is given by the formula below

[tex]V=f\times \lambda[/tex]

Since

[tex]6=2 \lambda[/tex]

[tex]\lambda =3m[/tex]

now

[tex]V=8\times3[/tex]

[tex]V=24m[/tex]

The speed of the waves will be = [tex]24\dfrac{m}{s}[/tex]

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Explanation:

F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

...

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

a) Determine the principal stresses and shear stress

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

Hence principal stresses = 32.0060 ± 0.62

б1 = 32.62mPa  

б2 = 31.38mPa

attached below is the remaining part of the solution

Answer:

K.E. = ½ × mv²

= ½ × 120 × (2.5)²

= 60 × 6.25

= 375 J

Answer:

Explanation:

Money is used to cover the explicit cost. They're what we're used to seeing, and they're easy to identify. There are several classifications for explicit costs; we can distinguish between fixed and variable costs, as well as direct and indirect costs. Raw materials, manpower, indirect production costs, and so on are all factors that contribute to its expense.

The opportunity cost of using a resource is the amount of money paying for it that might have been used on something else.

Alternative benefit options or money that we miss earning by doing such business acts are referred to as opportunity costs.

When a corporation foregoes an alternative action but does not make a bill, it incurs implicit costs. These are a company's hidden costs:

1. The use of the firm's own funds (money or assets).

2. The owner's capital, savings, and financial services are used.

From the given information:

The total explicit cost = Rent + office supplies + office staff + telephone expense

=$( 14000 + 1000 + 24000 + 4500)

= $43500

The total implicit cost = forgone salary + forgone interest

= $40000 + 7% of $5000

= $40000 + 350

=$40350

Answer:

Option B. –80 J

Explanation:

From the question given above, the following data were obtained:

Heat (Q) released = –30 J (negative sign because the heat is being released to the surrounding)

Work (W) = 50 J

Change in internal energy (ΔU) =?

We can obtain the change in the internal energy as follow:

ΔU = Q – W

ΔU = –30 – 50

ΔU = –80 J

Therefore, the change in the internal energy is –80 J

Thus, option B gives the correct answer to the question.

Answer:

- the power rating of the resistance heater is 24139.5 W

- the inner surface temperature of the pipe at the exit is 96.34°C

Explanation:

Given the data in the question;

Flow rate of water in the tube V" = 5L/min = 8.333 × 10⁻⁵ m³/s        

The water is to be heated from 10°C to 80°C;

so Average or mean temperature [tex]T_{avg[/tex] will be;

[tex]T_{avg[/tex] = (T₁ + T₂) / 2 = (10 + 80) / 2 = 90/2 = 45°C

Now, from the Table " Properties of Water " at average temperature;

at [tex]T_{avg[/tex] = 45°C

density p = 990.1 kg/m³

specific heat [tex]C_p[/tex] = 4180 J/kg-k

thermal conductivity k = 0.637 W/m-°C

Now, we determine the mass flow;

m" = pV"

we substitute

m" = 990.1 × 8.333 × 10⁻⁵

m" = 0.08250 kg/s

we know that the power rating of the resistance heater is equal to the heat transfer rate to the water;

Q' = m"[tex]C_p[/tex]( T₂ - T₁ )

we substitute

Q' = (0.08250 × 4180 ) ( 80 - 10 )

Q' =  344.85 × 70

Q' = 24139.5 W

Hence, the power rating of the resistance heater is 24139.5 W

Next, we determine the average velocity of water in the tube;

[tex]V_{avg[/tex] = V" / [tex]A_c[/tex]

[tex]V_{avg[/tex] = V" / ( [tex]\frac{1}{4}[/tex]πD² )

given that;  flows through a 2-cm-internal-diameter; D = 0.02 m

we substitute

[tex]V_{avg[/tex] = (8.333 × 10⁻⁵) / ( [tex]\frac{1}{4}[/tex]π × (0.02)² )

[tex]V_{avg[/tex] = (8.333 × 10⁻⁵) / ( 3.14159 × 10⁻⁴ )

[tex]V_{avg[/tex] =  0.265 m/s

Also, from table " saturated water property table "

At 45°C

viscosity μ = 0.596 × 10⁻³ kg/m-s

Prandtl number Pr = 3.91

Now, we determine the kinematic viscosity

v = μ / p

we substitute

v = ( 0.596 × 10⁻³ ) / 990.1

v = 6.01959 × 10⁻⁷ m²/s

so, Reynolds number in the flow region will be;

Re = ([tex]V_{avg[/tex] × D) / v

we substitute

Re = ( 0.265 × 0.02) / (6.01959 × 10⁻⁷)

Re = 8804.586

we can see that our Reynolds number (  8804.586 ) more than 2300 and less than 10,000.

Hydraulic and thermal entry length are equal in this flow region,

such that;

[tex]L_h[/tex] = [tex]L_t[/tex]

⇒ 10 × D = 10 × 0.02 = 0.2 m

we can see that the entry length ( 0.2 m ) is smaller than the given length ( 13 m ) in the question; the flow is a turbulent flow.

So we the Nuddelt number

Nu = [tex]0.023Re^{0.8} Pr^{0.4[/tex]

Nu = 0.023 × [tex]8804.586^{0.8[/tex] × [tex]3.91^{0.4[/tex]

Nu = 56.8

Hence, the heat transfer coefficient h will be;

h = [tex]\frac{k}{D}[/tex] × Nu

we substitute

h = [tex]\frac{0.637}{0.02}[/tex] × 56.8

h = 31.85 × 56.8

h = 1809.1 W/m²-°C

Now, area of the heat transfer will be

A[tex]_s[/tex] = πDL

we substitute

A[tex]_s[/tex] = π × 0.02 × 13

A[tex]_s[/tex] = 0.8168 m²

Finally we determine the inner temperature of the pipe at exit. using the relation;

Q' = hA[tex]_s[/tex]( T₃ - T₂ )

we substitute

24139.5 = 1809.1 × 0.8168( T₃ - 10 )

24139.5 = 1477.67288( T₃ - 80 )

24139.5 = 1477.67288T₃ - 118213.8304

24139.5 + 118213.8304 = 1477.67288T₃

1477.67288T₃ = 142353.3304

T₃ = 142353.3304 / 1477.67288T

T₃ = 96.34°C

Therefore, the inner surface temperature of the pipe at the exit is 96.34°C

Answer:

It is a colorless crystalline compound which is the main nitrogenous breakdown product of protein metabolism in mammals and is excreted in urine.

Answer:

Urea is a compound of nitrogen that is the chief solid substance dissolved in the urine of a mammal and is formed by the breaking down of protein.

(Hope this helps! Btw, I answered first. Brainliest please! :D)

Answer:

The correct answer is "517.7 lb/in²".

Explanation:

The given values are:

Woman's mass,

m = 53 kg

Area,

A = 1.45 cm²

   = [tex]1.45\times 10^{-4}[/tex] m²

Now,

The weight of woman will be:

⇒  [tex]W=mg[/tex]

On substituting the values, we get

⇒       [tex]=53\times 9.8[/tex]

⇒       [tex]=519.4 \ N[/tex]

Pressure will be:

⇒  [tex]P=\frac{W}{A}[/tex]

⇒      [tex]=\frac{519.4}{1.45\times 10^{-4}}[/tex]

⇒      [tex]=3.57\times 10^6 \ N/m^2[/tex]

or,

⇒      [tex]=3.57\times 10^6 \ Pa[/tex]

As we know,

⇒  1 pound per sq. inch = 6895 Pascal's

hence,

⇒  [tex]P=\frac{3.57\times 10^6}{6895}[/tex]

⇒      [tex]=517.7 \ lb/in^2[/tex]

Answer:

Final speed after 2 seconds = 34.6 m/s

Explanation:

Given:

Initial speed of coin (u) = 15 m/s

Time taken = 2 seconds

Find:

Final speed after 2 seconds

Computation:

Gravitational acceleration of earth = 9.8 m/s²

Using first equation of motion;

v = u + at

or

v = u + gt

where,

v = final velocity

u = initial velocity

g = Gravitational acceleration

t = time taken

v = 15 + 9.8(2)

v = 15 + 19.6

Final speed after 2 seconds = 34.6 m/s

Answer:

Either heat added or mechanical work done.

Explanation:

Since he found stirring rod on the desk and a cigarette lighter. This means that the beaker was probably either heated with the aid of fire from the lighter.

Also, the stirring rod could have been used to stir the water which will increase the kinetic energy which also means an increase in temperature.

Thus, it's either heat was added or mechanical work was done as a result of stirring.