The element whose atom may likely make a -3 ion is P.
Elements in the periodic table are classified into groups and periods. The elements in the same group have similar physical and chemical properties.
Phosphorus (P) is a member of group 15 in the periodic table. The most common ion formed by the members of this group is the -3 ion.
It is formed by accepting three electrons to complete their octet since they have five electrons on their outermost shell.
Hence P is most likely to form a -3 ion.
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A student dissolved a 40-gram block of a salt in 100 grams of warm water at 45°C. The solution was allowed to cool down to 24°C. The student noticed that some of the salt came out of the solution and settled to the bottom of the beaker. It is later determined that 12 grams of the salt came out of the solution. How many grams of the salt were dissolved in the solution at 24°c 100 grams of warm water , PLEASE HELP ME FAST I ONLY HAVE A COUPLE MIN LEFT TO
FINISH I WILL GIVE YU BRAINLIEST!
Answer:
28
Explanation:
The grams of salt dissolved in the solution was 28, because 40 minus 12 would be 28. I know I'm suppose to subtract 40 by 12 considering the fact, it is 12 grams of salt that came out. The rest of the numbers are irrelevant. (apologies this is a week late.)
The amount of salt that was dissolved in the water is 28 grams of the salt.
What is solubility?The term solubility refers to the amount of a substance that dissolves in solution. In this case we are told that about 40-grams of salt was added to water but about 12 grams of the salt came out of the solution.
In this case, the amount of salt that was dissolved in the water is 40 g - 12 g = 28 grams of the salt.
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The neutralization of a 0.455 g sample of recrystallized aspirin required 38.6 mL of 0.100 M NaOH solution. An additional 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The solution was heated. Phenolphthalein was added to the cooled solution and was back-titrated with 11.2 mL of 0.100 M HCl. Which of the following statements is true
A) Before the solution is titrated with HCl it is pink and when the color changes from pink to colorless, the moles of H*(aq) equals the moles of OH"(aq) used in the hydrolysis of the neutralized aspirin.
B) Before the solution is titrated with HCl it is colorless and when the color changes from colorless to pink, the moles of H*(aq) equals the excess moles of OH(aq) added.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with HCl allows us to determine the moles of excess OH(aq) added. Once we determine the moles of excess OH(aq), we can determine moles of OH"(aq) used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin.
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the 0.100 M NaOH to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the 0.100 M HCl is to confirm the moles of aspirin in the recrystallized aspirin.
E) Two of the above statements are true.
Answer:
E) Two of the above statements are true.
Explanation:
The options are:
A) Before the solution is titrated with HCl it is pink and when the color changes from pink to colorless, the moles of H*(aq) equals the moles of OH"(aq) used in the hydrolysis of the neutralized aspirin. TRUE. Before the solution is titrated, there is an excess of NaOH (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of HCl, the pH is acidic and phenolphtalein is colorless.
B) Before the solution is titrated with HCl it is colorless and when the color changes from colorless to pink, the moles of H*(aq) equals the excess moles of OH(aq) added. FALSE. As was explained, before the titration, the solution is pink.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with HCl allows us to determine the moles of excess OH(aq) added. Once we determine the moles of excess OH(aq), we can determine moles of OH"(aq) used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. TRUE. Aspirin requires an excess of base (NaOH) for a complete dissolution (Hydrolysis). Then, we add H+ as HCl to know the excess moles of OH-. As we know the added moles of OH-, we can find the moles of OH that reacted = Moles of aspirin.
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the 0.100 M NaOH to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the 0.100 M HCl is to confirm the moles of aspirin in the recrystallized aspirin. FALSE. NaOH can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely
E) Two of the above statements are true. TRUE
Right option is:
E) Two of the above statements are true.In this exercise it is necessary to identify the true alternatives and the false alternatives. Thus, classifying these alternatives we have:
A) True
B) False
C) True
D) False
E) True
So we can say that: Two of the above statements are true.
The options are:
A) Before the solution is titrated with [tex]HCl[/tex] it is pink and when the color changes from pink to colorless, the moles of [tex]H*(aq)[/tex] equals the moles of [tex]OH"(aq)[/tex] used in the hydrolysis of the neutralized aspirin. TRUE. Before the solution is titrated, there is an excess of [tex]NaOH[/tex] (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of [tex]HCl[/tex], the pH is acidic and phenolphtalein is colorless.
B) Before the solution is titrated with [tex]HCl[/tex] it is colorless and when the color changes from colorless to pink, the moles of [tex]H*(aq)[/tex] equals the excess moles of [tex]OH(aq)[/tex] added. FALSE. As was explained, before the titration, the solution is pink.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with [tex]HCl[/tex] allows us to determine the moles of excess [tex]OH(aq)[/tex] added. Once we determine the moles of excess [tex]OH(aq)[/tex], we can determine moles of [tex]OH"(aq)[/tex] used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. TRUE. Aspirin requires an excess of base [tex](NaOH)[/tex] for a complete dissolution (Hydrolysis). Then, we add [tex]H+[/tex] as [tex]HCl[/tex] to know the excess moles of [tex]OH-[/tex]. As we know the added moles of [tex]OH-[/tex], we can find the moles of [tex]OH[/tex] that reacted (Moles of aspirin).
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the [tex]0.100 M NaOH[/tex] to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the [tex]0.100 M HCl[/tex] is to confirm the moles of aspirin in the recrystallized aspirin. FALSE. [tex]NaOH[/tex] can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely
E) Two of the above statements are true. TRUE
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how do I name cycloalkanes?
Answer:
[tex]{ \tt{aromatic \: alkanes}} \\ \\ { \underline{ \blue{ \tt{becker⚜jnr}}}}[/tex]
1. Determine the number of sides of the cyclic compound.
2. Use IUPAC theory, determine the functional group and its position.
Please help me I need help with this questions I’m very confused fused as to what the answer is please
liquid mass has a volume of 9.2 and density of 0.75
Answer:
6.9
Explanation:
Mass(m)=?
Density (D)=0.75
Volume (v)=9.2
M=D×V
M=0.75×9.2
M=6.9
Which sentence best describes why MnSO4→MnO+SO3 is not a synthesis reaction?
The equation is not balanced.
The reaction has more than one product.
Oxygen is not a reactant in this reaction.
Energy is not a product in this reaction.
Answer:
The reaction has more than one product.
Explanation:
Answer:
The reaction has more than one product.
Explanation:
What is exactly the pH value of distilled water?
Which of the following combination of elements would result in covalent compound? * W X Y Z Vand X Wand Z Y and Z Wand y
Answer:
C. Y & Z
Explanation:
V, W are imaginary metals here because their valence electrons are typically less than 4. X, Y, Z are non-metals and have higher valence electrons. Here, if V or W bind with X, Y, or Z we make ionic bond (because metal + non metal = ionic). But, if X binds with Y or Z or any combinations of any two of the three non-metals results in covalent bond (non metal + non metal = covalent).
Thus, Y and Z make covalent.
A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.656-g sample of the mixture, the mass of precipitate collected is 1.658 g. What is the mass percentage of barium chloride in the mixture
Answer:
[tex]\% m=40.46\%[/tex]
Explanation:
Hello there!
in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:
[tex]BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl[/tex]
Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:
[tex]m_{BaCl_2}=1.658gBaSO_4*\frac{1molBaSO_4}{233.38 gBaSO_4} *\frac{1molBaCl_2}{1molBaSO_4}*\frac{208.23 gBaCl_2}{1molBaCl_2}\\\\m_{BaCl_2}=1.479gBaCl_2[/tex]
Thus, the mass percentage is calculated as shown below:
[tex]\% m=\frac{1.479g}{3.656g}*100 \% \\\\\% m=40.46\%[/tex]
Regards!
Hydrolysis of the compound B5H9 forms boric acid, H3BO3. Fusion of boric acid with sodium oxide forms a borate salt, Na2B4O7. Part A Without writing complete equations, find the mass (in grams) of B5H9 required to form 148 g of the borate salt by this reaction sequence.
Answer:
37.09 g of B₅H₉ is required to form 148 g of borate salt( Na₂B₄O₇ )
Explanation:
Given the data in the question;
B₅H₉ → H₃BO₃ → Na₂B₄O₇
find the mass (in grams) of B5H9 required to form 148 g of the borate salt by this reaction sequence.
S M.W
B₅H₉ 63
H₃BO₃ 62
Na₂B₄O₇ 201
So, moles of Na₂B₄O₇ = 148 / 201 = 0.736
Since Boron will be conserved,
Moles of Boron atoms in Na₂B₄O₇ will be;
⇒ 4 × 0.736 = 2.944
Now, Moles of Boron in Na₂B₄O₇ = Moles of Boron in H₃BO₃ = Moles of Boron in B₅H₉
Hence,
Moles of Boron in B₅H₉ = 2.944
Moles of B₅H₉ = 2.944 / 5 = 0.5888
Mass of B₅H₉ = 0.5888 × 63 = 37.09 g
Therefore, 37.09 g of B₅H₉ is required to form 148 g of borate salt( Na₂B₄O₇ )
At 1115 degrees Celcius, where iron is still a solid (melting point 1538 degrees Celcius), the unit cell for the most stable crystal lattice of the metal is face- centered cubic (fcc) with an edge length of 362 pm. What is the atomic radius of iron at this temperature?
Answer: The atomic radius of iron is 128 pm.
Explanation:
To calculate the radius of the metal having FCC crystal lattice, the relationship between edge length and radius follows:
[tex]4r=\sqrt{2}a[/tex]
Where,
a = edge length = 362 pm
r = atomic radius of iron = ?
Plugging values in above equation, we get:
[tex]r=\frac{\sqrt{2}\times 362}{4}\\\\a=128pm[/tex]
Hence, the atomic radius of iron is 128 pm.
What is the general trend in electro negativity as you move from left to right across the periodic table
Answer:
On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you go down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.
Explanation:
Answer:
The Electronegativity increases
Explanation:
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Use the following balanced equation to answer the questions below.
propanoyl chloride reacts with LiAlH4, what will be the product
You can hear sounds around the corner of a door due to the wave interaction called diffraction.
Answer:
Sorry I didn't get it
Explanation:
Where is the question?
Extension: Cedric has been in the hospital for 15 weeks, how many minutes is that? Use
conversion factors with units to solve the problem and show your work
Answer:
151200 minutes.
Explanation:
From the question given above, the following data were obtained:
Time (in week) = 15 weeks
Time (in min) =?
Next, we shall convert 15 weeks to days. This can be obtained as follow:
1 week = 7 days
Therefore,
15 weeks = 15 weeks × 7 days / 1 week
15 weeks = 105 days
Next, we shall convert 105 days to hours. This can be obtained as follow:
1 day = 24 h
Therefore,
105 days = 105 days × 24 h / 1 day
105 days = 2520 h
Finally, we shall convert 2520 h to mins. This can be obtained as follow:
1 h = 60 mins
Therefore,
2520 h = 2520 h × 60 mins / 1 h
2520 h = 151200 mins
Thus, 15 weeks is equivalent to 151200 minutes.
A student performs an experiment three times. The results are 4.52 g/mL, 4.54 g/mL, and 4.39 g/mL. Which of the following best describes these results with only the information given in this question?
a. high accuracy
b. high accuracy and high precision
c. high accuracy and low precision
d. high precision
Substance
Number of Protons
Number of
Electrons
2.
3
lithium
fluorine
9
10
19
potassium
sulfur
19
18
16
19. Which substance is electrically neutral?
A. lithium
B. fluorine
Β
C. potassium
D. sulfur
20. Which substance has an overall I'charge?
Answer:
lithium 3
Explanation:
This is because lithium has three protons
PLEASE ANSWER ASAP I WILL GIVE YOU BRAINLIEST AND GIVE FREEE POINTSSS AFTER
Describe each of the following types of reactions and give one example of each: combustion, synthesis, decomposition, single replacement, double replacement.
Explanation:
Combustion Reaction:-A kind of chemical reaction in which a reaction between any combustible substance and an oxidizer takes place in order to form an oxidized product.
Eg: Fuel + O2 → CO2 + H2O.
The burning of charcoal is a combustion reaction.
Synthesis Reaction:-A synthesis reaction occurs when two or more reactants combine to form a single product.
Eg: Na + Cl → NaCl
An example of a synthesis reaction is the combination of sodium (Na) and chlorine (Cl) to produce sodium chloride (NaCl).
Decomposition Reaction:-A decomposition reaction occurs when one reactant breaks down into two or more products.
Eg: NaCl → Na + Cl
An example of a decomposition reaction is the breakdown of Sodium chloride to give sodium and chloride.
Single Replacement Reaction:-A single replacement reaction, sometimes called a single displacement reaction, is a reaction in which one element is substituted for another element in a compound.
Eg: Zn + 2 HCl → 2 ZnCl + H2
The reaction between zinc metal and hydrochloric acid to produce zinc chloride and hydrogen gas is an example of a single-displacement reaction.
Double Replacement Reaction:-A double replacement reaction is a type of chemical reaction that occurs when two reactants exchange cations or anions to yield two new products.
Eg: AgNO 3 + NaCl → AgCl + NaNO
The reaction between silver nitrate and sodium chloride to produce silver chloride and sodium nitrate is an example of a double-displacement reaction.
For each of the scenarios, determine if the ionic strength of the solution would increase, decrease, or not change. Ignore any effects caused by the change in volume.
1) If a solution of HNO3 were added to a solution of KOH , the ionic strength of the KOH solution would:_____.
A. Increase.
B. Decrease.
C. Not change.
2) If a dilute solution of KOH were added to a solution of CaCl2 (Ca(OH)2 (s) is formed), the ionic strength would:____.
A. Increase.
B. Decrease.
C. Not change.
3) If a dilute solution of benzoic acid were titrated with a solution of KOH the ionic strength would:____.
4) If a solution of NaOH were added to a solution of iron(II) chloride, the ionic strength would:____. A. Increase.
B. Decrease.
C. Not change.
Answer:
1) increases
2) decrease
3) increase
4) decrease
Explanation:
When ionic compounds dissolve in water, the concentration of ions in solution increases since ionic substances dissociate into ions in solution. The greater the concentration of ions in a solution, the greater the ionic strength of that solution.
Hence, if HNO3 is added to KOH solution, the ionic strength of the solution is increased due to an increase in the number of ions in the solution.
Also, when benzoic acid is titrated against KOH, potassium benzoate (an ionic substance) is formed thereby increasing the ionic strength of the solution.
However, when KOH is added to CaCl2, a precipitate (Ca(OH)2) is formed. Also, when NaOH is added to FeCl2, a precipitate (Fe(OH)2) is formed. In both cases, the formation of the precipitate decreases the concentration of ions in the solution thereby decreasing the ionic strength of the solution.
Please help
Calculate the sodium ion (Na+) concentration for a 0.812 M Na3PO4 solution.
[Na+]=____M
Explanation:
Correct option is
B
0.750 M
Na3PO4 dissociates as:
Na3PO4⇌3Na++PO43−
∴ conc. of Na+ would be =3×0.250=
hope help
Determine which of these properties would distinguish these two substances: (a) boiling point; (b) combustion analysis results; (c) molecular weight; (d) density at a given temperature and pressure. You can check on the properties of these two compounds
Answer:
(a) boiling point
(d) density at a given temperature and pressure.
Explanation:
Isomers are compounds that have the same molecular formula but different structural formulas. They differ in chemical and physical properties depending on the type of isomerism displayed by the compounds.
The compounds stated here are structural or constitutional isomers hence they possess different boiling points and densities at a given temperature and pressure owing to structural differences in the molecules.
Since they have the same molecular formula, they must yield the same result during combustion analysis and they must have the same molecular weight.
The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7
Answer:
Answer is in the explanation.
Explanation:
Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7
That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7
A pure copper cube has an edge length of 1.76 cm. How many copper atoms does it contain? (volume of a cube = (edge length)^3; density of copper = 8.96 g/cm^3 )
A suspension is
•A heterogenous mixture where the solid particles are large enough to be filtered out.
•A homogenous mixture where the solid particles are large enough to be filtered out.
•A heterogenous mixture where the solid particles are too small to be filtered out.
•A homogenous mixture where the solid particles are too small to be filtered out
Answer:
A heterogeneous mixture where the solids particles are large enough to be filtered out.
Explanation:
how many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?
Answer:
0.012288122055459
Explanation:
i might be wrong
This unit describes volume, and may be used to describe liquids or gases.
O A. Meter
O B. Liter
O C. Gram
O D. Mole
Answer: aaaaaaaaaaa
The basic SI unit for volume is the cubic meter (m3), but smaller volumes may be measured in cm3, and liquids may be measured in liters (L) or milliliters (mL).
Explanation:
Which of the following can be mixed in solution with H2CO3 to make a buffer?
Answer:
Sodium hydroxide solution.
Explanation:
because it is a strong base. Since carbonic acid is a weak acid, a solution formed resists change in pH on addition hence buffer formed.
Sodium hydroxide solution can be can be mixed in solution with H2CO3 to make a buffer.
What is buffer?A buffer would be a solution that could withstand pH changes when acidic as well as basic components are added.
What is solution ?The term "solution" was most frequently associated with the liquid form of matter, however gases as well as solids can also form solutions.
A traditional buffer is made up of a weak acid including its conjugate salts, such as carbonic acid (H2CO3) as well as sodium bicarbonate (NaHCO3) or sodium bicarbonate with calcium carbonate.
Sodium hydroxide solution can be can be mixed in solution with H2CO3 to make a buffer.
To know more about buffer and solution.
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If one of your samples had a mass of 25.62 g and a volume of 21.9 cm3, would this sample also be the same material you have been working with
Answer:
If the density of the material is equal to the density of the material you have been working with it is possible that the samples are the samples
Explanation:
Density is an intensive property of the matter (Doesn't depends of its amount) that is widely used to identify a substance. Density is the ratio between the mass of the substance (In this case 25.62g) and the volume this amount occupies (21.9cm³). The density is:
25.62g / 21.9cm³ =
1.17g/cm³.
If the density of the material is equal to the density of the material you have been working with it is possible that the samples are the samplesHow many atoms are in 54.4 g of carbon-12?
Answer:
12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).
Explanation:
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