a. Find the mean, median, and mode of 12, 9, 17, 15, 10.
mean:
median:
6
Answer:
Mean: 12.6
Median: 12
Mode: None
Step-by-step explanation:
To find the mode, add everything up.
12 + 9 + 17 +15 + 10 = 63. Then, divide by five.
63 ÷ 5 = 12.6
To find the median, put the numbers from least to greatest. Then, highlight the one in the middle.
9, 10, 12, 15, 17
To find the mode, look for the number that appears the most. Because each number appears once. So, put "none" in the box.
Have a wonderful day!
Which has a slope of 4 and a y-intercept of -2
Answer:
C
Step-by-step explanation:
Have a good day :)
*7. Admission to a museum is $8.20 per adult and $4.10 per child. The expression
8.2a + 4.1c represents the total cost in dollars for admission for a adults and a
children
A group of friends, consisting of 6 adults and 6 children attend the museum. One of
the adults has a coupon for one free adult admission and one child's admission at half
price. What is the total cost for the whole group to enter the museum?
Answer:
$63.55
Step-by-step explanation:
if one of the adults has a free coupon for adult admission, then we have 5 adults
8.20 x 5 = $41
We have 6 children and one with half pay
= (5 x 4.1) + (4.1/2 )
= 20.5 + 2.05
=$22.55
41 + 22.55 = $63.55
The diameter of a circle is 24 miles. What is the circle's area?
d=24 mi
Use 3.14 for n.
square miles
Submit
Answer:
24÷2=12
3.14×12×12=452.16
Answer is 452.16
Answer:
The circle's area above is 452.39 I believe.
Step-by-step explanation:
Use A = pie*r^2 and d = 2 * r to solve this problem.
A = 1/4*pie*d^2 = 1/4*pie*24^2 = 452.38
Round and you have the area of the circle: 452.39
I’m failing and areas aren’t my best subject, please help!
A rate or ratio with a denominator of one is called
Answer:
Unit rate
Step-by-step explanation:
Help with this please!!
Answer:
First choice
Step-by-step explanation:
a is - 2
Open downward
Answer:
first answer choice
Step-by-step explanation:
because in the equation a is less then 0 which makes the parabola open downward
also if ur struggling just search up Desmos that calculator is going to save ur life
Shelly bought 53.6 gallons of orange juice and used 18.3 gallons of it to make popsicles how much orange juice dose shelly have left
Find the circumference of the circle to the nearest hundredth
11cm
Question: Find the circumference of the circle to the nearest hundredth
d = 11cm
Answer:
34.54 cm
Step-by-step explanation:
Applying,
P = πd...................... Equation 1
Where P = Circumference of perimeter of the circle, d = diameter of the circle, π = pie
From the question
Given: d = 11 cm
Constant: π = 3.14
Substitute these values into equation 1
P = (3.14×11)
P = 34.54 cm
9x+y=9=3x-2y=-11 i need the answer
Answer:
x= 1/28+y + 11/84
Step-by-step explanation:
What is the median of this data set?
Answer:
4.5
Step-by-step explanation:
Why do you sometimes finish the square (ex.[tex]x^{2} + 4x=1[/tex]) and sometimes you make one side zero(ex[tex]x^{2} -12x=-35[/tex])? How should I know the difference? Any help is appreciated! TIA
Answer:
Lets say there's a quadratic equation → ax² + bx = -c
Lets make one side zero which gives → ax² + bx + c = 0
From the above equation ,
if you can split b into 'p' & 'q' (some real numbers) such that p + q = b & pq = ac ; then the quadratic equation can be easily solved by using factorisation method. Here the easiest way to guess the values of 'p' & 'q' is to find out the prime factors of 'ac' and taking any two prime numbers in random , just check whether the sum of those two primes is equal to 'b' (excluding their signs).if you can't split b into 'p' & 'q' (some real numbers) such that p + q = b & pq = ac ; then try solving quadratic equation by completing the squares method.For example :- x² - 12x = -35.
Lets make one side zero → x² - 12x + 35 = 0 . Now, lets break -12x into two real numbers 'p' & 'q' such that p + q = -12x & pq = 35. Prime factors of 35 are 1 , 5 & 7. If we take 5 & 7 as 'p' & 'q' then p + q = 5 + 7 = 12. but as we need -12 , the values of 'p' & 'q' are -5 & -7.
⇒ [tex]x^2 -5x - 7x + 35 = 0[/tex]
⇒ [tex]x(x - 5) - 7(x - 5) = 0[/tex]
⇒ [tex](x - 5)(x - 7) = 0[/tex]
⇒ [tex]x = 5 \: or \: 7[/tex]
Lets take another example :- x² + 4x = 1.
Lets make one side zero → x² + 4x - 1 = 0 . Now , lets split +4x into into two real numbers 'p' & 'q' such that p + q = +4x & pq = -1 . Prime factors of 4 are 1 & 2 only. But there's no such combination of its primes such that their sum would be equal to 4. So, the quadratic equation can't be solved by factorisation method. Now, lets bring -1 to Right Hand Side & try solving by completing squares method.
⇒ [tex]x^2 + 2 \times x \times 2 + 2^2 = 1 + 2^2[/tex]
⇒ [tex](x + 2)^2 = 1 + 4 = 5[/tex]
⇒ [tex]x + 2 = +\sqrt{5} \: \: or \: -\sqrt{5}[/tex]
⇒ [tex]x = (\sqrt{5} - 2) \: or \: (-\sqrt{5} -2)[/tex]
Conclusion:
First try making one side zero and try to solve the equation by factorisation method. If it got factorised , then you are done and if it didn't get factorised , then solve it by completing squares method.
Answer:
I'm assuming we're asking about the difference between:
[tex]ax^2 + bx + c = 0[/tex]
and
[tex]ax^2 + bx = -c[/tex]
Let's preface this by stating the obvious: there's no actual difference. Both equations are equivalent.
Now, it has a lot to do with our goal. Sometimes our goal is to write an equation concisely (then the "no-zero" way uses less characters), and sometimes we're dealing with a quadratic function of
[tex]y = ax^2 + bx + c[/tex]
in the second case, we wouldn't write
[tex]y - c = ax^2 + bx[/tex]
because it'd be confusing. That means that when we're looking for y=0 points of a quadratic equation, the way to convey that goal is that we're looking for the point where [tex]ax^2 + bx + c = 0[/tex] - so we preserve the structure of the quadratic function.
what is the mean median mode range of 1 1 2 1 1 3 3 4
Answer:
16 is mean
median is 2
mode is 1
range is 3
Step-by-step explanation:
mean is total added
median is the middle- 1+1
mode- occurs most
and range is the biggest minus smallest #'s
What is the measure of Zy?
139 yº
Answer:
y = 41°
Step-by-step explanation:
∡ y and 139° are adjacent angles and sum to 180° , that is
∠ 1 + 139° = 180° ( subtract 139° from both sides )
∠ 1 = 41°
can someone do my math homework pls its on (quadratics)
I want to try but I am tooooo much bad in math
The ages in years of a study group are 12,13,13,13,14 and 15. Another 12- year old joins their group
What is the average rate of change for this quadratic function for the interval from x = 0 to x = 2?
A. 4
B. 2
C. -4
D. -2
Answer:
Option B
Step-by-step explanation:
Average rate of change of a function between x = a and x = b will be,
Average rate of change = [tex]\frac{f(b)-f(a)}{b-a}[/tex]
We have to calculate average rate of change of the given quadratic function between x = 0 and x = 2.
From the given graph,
f(2) = 6
f(0) = 10
Therefore, average rate of change = [tex]\frac{f(2)-f(0)}{2-0}[/tex]
= [tex]\frac{10-6}{2-0}[/tex]
= 2
Option B will be the answer.
Can you help me on unmber 2 or 3 Plzz show work
Step-by-step explanation:
In,
Question 2 I have already answered,
Q. 3)
Given Question:[tex] \frac{ {c}^{2} }{d} [/tex]
Given values:-
c = 6 , d = 3
By putting the values in the question,
[tex] \frac{ {6}^{2} }{3} [/tex]
[tex] = \frac{36}{3} [/tex]
= 12 (Ans)
What is 4x/7 - 2/3
Fraction help
Answer:
2/21 * (6x-7)
Step-by-step explanation:
1/21 * (3*4x - 14)
1/21* (12x-14)
1/21* 2(6x-7)
2*1/21 * (6x-7)
2/21* (6x-7)
8.
Write the slope-intercept form of the equation for the line.
A. y = 2x – 1
B. y = – 2x – 1
C. y =[tex]\frac{1}{2}x-1[/tex]
D. y = [tex]\frac{1}{2}x+1[/tex]
Answer:
y = 2x – 1
Step-by-step explanation:
i got a 100%
Answer:
A. y = 2x - 1
Step-by-step explanation:
First, find the slope. You can either use the rise/run method or use the slope formula, y2-y1/x2-x1. For the rise/run method, the rise is 4 and the run is 2, so... 4/2 = 2. If you want to use the slope formula, use the two coordinate sets, (1, 1) and (-1, -3). -3-1/-1-1 = -4/-2 = 2. Next, find your y-intercept. Use the slope-intercept formula, y = mx + b. M stands for the slope and b stands for your y-intercept. You can use either the coordinates (1, 1) or (-1, -3) to plug in for the x and y. In this scenario, I'll use (1, 1).y = mx + b
Plug in your values. (2 for m)
1 = 2(1) + b
Simplify.
1 = 2 + b
Subtract 2 from both sides.
-1 = b
Finally, form your equation together.
y = 2x - 1
Convert the following equation into slope intercept form y-6=2(x+4)
Answer:
y = 2x +14
Step-by-step explanation:
We need to convert the given equation into slope intercept form ,
=> y - 6 = 2(x+4)
=> y -6= 2x + 8
=> y = 2x +8+6
=> y = 2x + 14
• Hence the required answer is y = 2x + 14can yall or someone help
Answer:
x would equal 40
Step-by-step explanation:
x+(2x-5)+(x+25)=180
4x+20=180
x=40
11,22,22,13,24,22 find the hunderds too
Answer:
excuse me, but how do we answer this? This question is unanswerable without it being a question!
Step-by-step explanation:
Kelly subtracts 60° from 90° to find the measure of a missing
angle in an angle pair. What type of angle pair is she working
with?
Answer:
acute
Step-by-step explanation:
Answer:
Complementary angle pair is here working
Hope you satisfyedFind the area of the shaded region.
Round to the nearest tenth.
Answer:
The area of the shaded region is 11.606 square centimeters.
Step-by-step explanation:
The area of the shaded region is obtained by subtracting the area of the triangle from the area of the circular section. The area of the triangle ([tex]A_{t}[/tex]), in square centimeters, can be calculated by the Heron's formula:
[tex]A_{t} = \sqrt{s\cdot (s-a)\cdot (s-b)\cdot (s-c)}[/tex] (1)
[tex]s = \frac{a + b + c}{2}[/tex] (2)
Where:
[tex]a[/tex], [tex]b[/tex], [tex]c[/tex] - Lengths of the sides of the triangle, in centimeters.
[tex]s[/tex] - Semiperimeter, in centimeters.
If we know that [tex]a = 10.50\,cm[/tex] and [tex]b = c = 9.28\,cm[/tex], then the area of the triangle is:
[tex]s = \frac{10.50\,cm + 2\cdot (9.28\,cm)}{2}[/tex]
[tex]s = 14.53\,cm[/tex]
[tex]A_{t} = \sqrt{(14.53\,cm)\cdot (14.53\,cm - 10.50\,cm)\cdot (14.53\,cm - 9.28\,cm)^{2}}[/tex]
[tex]A_{t} \approx 40.174\,cm^{2}[/tex]
And the area of the circular section ([tex]A_{c}[/tex]), in square centimeters, is determined by the following formula:
[tex]A_{c} = \left(\frac{\theta\cdot \pi}{360} \right)\cdot r^{2}[/tex] (3)
Where:
[tex]r[/tex] - Radius of the circle, in centimeters.
[tex]\theta[/tex] - Internal angle, in sexagesimal degrees.
If we know that [tex]r = 9.28\,cm[/tex] and [tex]\theta = 68.9^{\circ}[/tex], then the area of the circular section is:
[tex]A_{c} = \left(\frac{68.9}{360}\right)\cdot \pi\cdot (9.28\,cm)^{2}[/tex]
[tex]A_{c} \approx 51.780\,cm^{2}[/tex]
Finally, the area of the shaded region ([tex]A[/tex]), in square centimeters, is:
[tex]A = A_{c} - A_{t}[/tex] (4)
[tex]A = 51.780\,cm^{2}- 40.174\,cm^{2}[/tex]
[tex]A = 11.606\,cm^{2}[/tex]
The area of the shaded region is 11.606 square centimeters.
In the diagram shown, m_3 = 3x - 16 and m_4 = x + 84. Find the value of x. o 25 50 34 28
Answer:
50
Step-by-step explanation:
m3 and m4 are going to be equaivalent due to some law I don't remember the name of.
So, 3x-16 = x+84
(do some rearranging)
2x=100
x=50
What is the initial value of the function represented by this table?
A. 0
B. 2
C. 3
D. 5
Answer:
C... 3
Step-by-step explanation:
What is the average rate of change for this quadratic function for the interval from x = 0 to x = 2?
A. –2
B. 2
C. 4
D. –4
Evaluate the expression for the given value.
3x(x−2), when x=7 .
Answer:
[tex]\huge\boxed{Answer\hookleftarrow}[/tex]
Given,
[tex]x = 7[/tex]
Substitute the value of 'x' in the equation 3x (x - 2).
One way :-
[tex]3x(x - 2) \\ = 3 \times 7(7 - 2) \\ = 21(5) \\ = 21 \times 5 \\ = 105[/tex]
Second way :-
[tex]3x(x - 2) \\ = 3x {}^{2} - 6x \\ = 3 \times (7) {}^{2} - 6(7) \\ = (3 \times 49) - (6 \times 7) \\ = 147 - 42 \\ = 105[/tex]
✐ The answer is 105.
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
# ꧁❣ RainbowSalt2²2² ࿐
please help mee!!! tia
Answer:
D. 3y + 1
Step-by-step explanation:
Hi there!
»»————- ★ ————-««
I believe your answer is:
Option D) [tex]3y + 1[/tex]
»»————- ★ ————-««
Here’s why:
The phrase for the expression is 'one more than three times a number', where 'y' is the unknown number.⸻⸻⸻⸻
[tex]\boxed{\text{Breaking The Phrase Down:}}\\-------------\\! - \text{Three times a number 'y'} \rightarrow \text{the product of 3 and y} \rightarrow \boxed {3y}\\! - \text{One more than....}\rightarrow \boxed{ + 1}\\--------------\\\boxed{\text{Putting it all together:}}\\\\!-\text{One more than three times a number 'y'} \rightarrow \boxed{3y+1}\\\\\text{The correct answer should be }\boxed{\text{Option D}}.[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.