Which of the following is an example of potential energy?

Answer:

15000 Kilograms/Cubic Meters (kg/m3) = 15 Grams/Cubic Centimeters (g/cm3)

Explanation:

1 g/cm3 is equal to 1000 kilogram/cubic meter. To convert 100 gram into kg then divide it by 1000 i.e. 100/1000 = 0.1 kg. To convert any value of gm/cm3 into kg/m3 then multiply it by 1000.

15000 kg / m^3 =

15000 × 10^3 g / m^3 =

15000 × 10^3 × 10^3 mg / m^3 =

15 × 10^9 mg / m^3 =

15 × 10^9 × 10^(-3) mg / dm^3 =

15 × 10^9 × 10^(-3) × 10^(-3) mg / cm^3 =

15 × 10^9 × 10^(-6) mg / cm^3 =

15 × 10^( 9 - 6 ) mg / cm^3 =

15 × 10^3 mg / cm^3 =

15000 mg / cm^3 =

Look : We found the exact thing we had ...

WoW ...

We got a point ;

Remember from now on :

kg / m^3 = mg / cm^3

a particle of violet light has exactly the same energy as a particle of red light

Answer:

An example of positive velocity is throwing a ball upwards

An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height

Explanation:

In a vertical movement the acceleration is always downwards, therefore negative since it is created by the attraction of the Earth on the body.

An example of positive velocity is throwing a ball upwards

An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height

Answer:

the answer should be D

Explanation:

Because if you want to earn your goals you must complete small goals to earn big goals

Answer:

The battery is charging and has a current of 2Amps passing through.

Explanation:

Given;

EMF of the battery, E = 12 V

internal resistance, r = 0.5 ohms

terminal voltage of the battery, ΔV = 13 volts

When the terminal voltage is greater than the EMF of the battery, the battery is being charged, allowing currents to pass in a reverse direction.

ΔV = E - Ir

ΔV - E = -Ir

13 - 12 = -0.5I

1 = -0.5I

I = 1 / -0.5

I = -2 A

The negative sign indicates the reverse direction of the current.

Therefore, the battery is charging and has a current of 2Amps passing through.

Answer:

2.2 s

Explanation:

Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point =  mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)

So, T = 2π√(I/mgh)

T = 2π√(mL²/3 /mgL/2)

T = 2π√(2L/3g)

substituting the values of the variables into the equation, we have

T = 2π√(2L/3g)

T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))

T = 2π√(3.66 m/(29.4 m/s² ))

T = 2π√(0.1245 s² ))

T = 2π(0.353 s)

T = 2.22 s

T ≅ 2.2 s

So, the period of the man's leg is 2.2 s

Answer:

The sensitivity of the device = 1.234 Hz per km

Explanation:

Given  

Frequency (f) = 10 gHz

Speed of the car = 120 Km/h

As per the doppler’s effect

V = (change in frequency /frequency) *(c/2)

Substituting the given values, we get –  

Change in frequency = {(2*10^9*120)/(3*10^8)} * (1000/3600)

Change in frequency =  37.03 Hz

b) speed of light = wavelength * frequency

3*10^8 = wavelength * 10*10^9

Wavelength = 0.03 m

Sensitivity = change in frequency /wavelength = 37.03/0.03 = 1234 Hz/m

1.234 Hz per km

Answer:

[tex](x \times 1) = (400 \times 2.5) \\ x = 1000 \: newtons[/tex]

[tex]y = 0[/tex]

Answer:

Greater than

Explanation:

Answer:

you can simply answer p1v1=p2v2 p2 = p1v1÷ p2 then inter what given in the formula you get it pl=1.20x 105pa vl= 0.40m3 v2=0.025m3

Explanation:

this is your answer I hope it is helpful please mark me brainly

Answer:

Physical adaptation

Explanation:

This is because the powerful legs of jackrabbit is an example of physical or structural adaptations because they are the physical features or characteristics that help jackrabit to survive or adapt in its natural environment. It makes it to run away from predators that might want to affect them. The structural adaptions help the animal to move ,eats and so on.

Answer:

Mater's Mass is the Answer

Answer:

We should not try to park the car because its rest length is greater than the space available.

The car seems to be approximately equal to the friend (L = 3.16 m). Due to this reason he is sure to park.

Explanation:

We should not try to park the car because its rest length is greater than the space available.

The friend is sure about parking because the car appears short in length to him. For this, we will solve Einstein's length contraction formula from theory of relativity:

[tex]L = L_o\sqrt{1-\frac{v^2}{c^2}}[/tex]

where,

L = Relative length observed by friend = ?

L₀ = rest length = 6 m

v = relative speed = 85% of speed of light = 0.85c

Therefore,

[tex]L = (6\ m)\sqrt{1-\frac{(0.85c)^2}{c^2}}[/tex]

L = 3.16 m

Hence, the car seems to be approximately equal to the friend. Due to this reason he is sure to park.

Answer:

Answer to An object moves clockwise around a circle centered at the origin with radius 6 m beginning at ... 6 M Beginning At The Point (0,6) B. Find A Position Function R That Describes The Motion If It Occurs With Speed E T A. R(t)= S The Motion Of The Object Moves With A Constant Speed, Completing 1 Lap Every 12 S.

Explanation:

Answer:

If we convert a circuit into a current source with parallel load it is called source transformation

Answer:   A 7.8 ·10^22 J  B   1.6 times  C 3.9 ·10^15 $

Explanation: A : Speed of light c =  3.0·10^8 m/s,  0.12·c = 3.6·10^7 m/s  

Mass is 120·10^6 kg . Change of kinetic energy

E = ½mv² =  0.5 · 120·10^6 kg · (3.6·10^7 m/s)² = 7.776·10^22 J

B  exponent is same , 7.776 / 5 = 1,55 times of energy use of Earth in year.

C  Energy is  7.776·10^22 J / 10^6  = 7.776·10^16 MJ

Price is 0.05 $ · 7.776·10^16 MJ = 3.888·10^15 $

A. The energy required to get to the cruising speed is 7.8×10²² J

B. The energy needed will be 1.56 times the total world energy

C. The cost price required to generate the energy needed by the spaceship is $ 3.9×10⁵

A. Determination of the energy

Mass (m) = 120×10⁶ Kg

Velocity of light = 3×10⁸ m/s

Velocity of spaceship = 0.12 × 3×10⁸ = 3.6×10⁷ m/s

E = ½mv²

E = ½ × 120×10⁶ × (3.6×10⁷)²

Thus, the energy needed is 7.8×10²² J

B. Comparing the energy needed to the total world energy.

Energy needed = 7.8×10²² J

World energy = 5×10²² J

Energy needed / World energy = 7.8×10²² / 5×10²²

Energy needed / World energy = 1.56

Cross multiply

Thus, the energy needed is 1.56 times the World energy

C. Determination of the cost required to generate the energy

1×10⁶ J = $ 0.05

Therefore,

7.8×10²² J = (7.8×10²² × 0.05) / 1×10⁶

7.8×10²² J = $ 3.9×10⁵

Therefore, the cost required to generate the energy is $ 3.9×10⁵

Learn more: https://brainly.com/question/10703928

Answer:

1. 0.57 m/s

2. 25 Watts

Explanation:

1. Determination of the speed.

We'll begin by converting 1.5 hp to watt (W). This can be obtained as follow:

1 hp = 745.7 W

Therefore,

1.5 hp = 1.5 hp × 745.7 W / 1 hp

1.5 hp = 1118.55 W

Next, we shall determine the force. This can be obtained as follow:

Mass (m) = 200 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = m × g

F = 200 × 9.8

F = 1960 N

Finally, we shall determine the speed. This can be obtained as follow:

Power (P) = 1118.55 W

Force (F) = 1960 N

Speed (v) =?

P = F × v

1118.55 = 1960 × v

Divide both side by 1960

v = 1118.55 / 1960

v = 0.57 m/s

Thus, the speed is 0.57 m/s

2. Determination of the power.

We'll begin by calculating the velocity. This can be obtained as follow:

Displacement = 10 m up

Time = 20 s

Velocity =?

Velocity = Displacement / time

Velocity = 10 / 20

Velocity = 0.5 m/s

Finally, we shall determine the power. This can be obtained as follow:

Velocity (v) = 0.5 m/s

Force (F) = 50 N

Power (P) =?

P = F × v

P = 50 × 0.5

P = 25 Watts

Therefore, the power required to lift the bucket is 25 Watts

Answer: The mutual inductance of these solenoids is [tex]2.88 \times 10^{-7} H[/tex].

Explanation:

Given: Length = 50.0 cm (1 cm = 0.01 m) = 0.50 m

[tex]N_{1}[/tex] = 6750

[tex]N_{2}[/tex] = 15

Radius = [tex]\frac{0.120 cm}{2} = 0.6 cm = 6 \times 10^{-4} m[/tex]

As inner of a solenoid resembles the shape of a circle. So, its area is calculated as follows.

[tex]Area = \pi \times r^{2} = \pi \times (6 \times 10^{-4})^{2}[/tex]

Formula used to calculate mutual conductance of two solenoids is as follows.

[tex]M = \frac{\mu_{o} \times A \times N_{1} \times N_{2}}{l}[/tex]

where,

M = mutual conductance

A = area

[tex]\mu_{o}[/tex] = relative permeability = [tex]4 \pi \times 10^{-7} Tm/A[/tex]

[tex]N_{1}[/tex] = no. of coils in outer solenoid

[tex]N_{2}[/tex] = no. of coils in inner solenoid

l = length

Substitute the values into above formula as follows.

[tex]M = \frac{\mu_{o} \times A \times N_{1} \times N_{2}}{l}\\= \frac{4 \pi \times 10^{-7} Tm/A \times \pi (6 \times 10^{-4})^{2} \times 6750 \times 15}{0.5 m}\\= 2.88 \times 10^{-7} H[/tex]

Thus, we can conclude that the mutual inductance of these solenoids is [tex]2.88 \times 10^{-7} H[/tex].

a = (dx / dt)²

Explanation:  Unit of distance is m (metres) and unit of time is s (seconds) speed v is  first derivative of distance x versus time:

  v = dx / dt, unit is m/s.    Acceleration is second derivative of

 speed versus time  a = (dx / dt)² = (dv/dt) , unit is m/s²

Answer:

Explanation:

Acceleration is derived unit because it has two fundamental units involved i.e. meter and second square.

Answer:

w= p∆v 50000 ( 0.55-0.40) and calculate and you get it

The work done on the system by its environment is 7,500J.

To find the work done, we need to know about the work done on an ideal gas during isobaric process.

When the pressure is remained constant throughout a process, then the process is called isobaric process.

Here, Final volume= 0.55 m³

         Initial volume= 0.40 m³

         Pressure= 50,000 Pa

Work done = 50,000 × (0.55 - 0.40)

                  = 7,500 J

Thus, we can conclude that 7,500 J of  work is done on the system by its environment.

Learn more about worn done on a system here:

https://brainly.com/question/23902763

#SPJ2

Answer:

a)  [tex]v=181.497m/s[/tex]

b)  [tex]\lambda=1.2[/tex]

c)  [tex]F=151.248hz[/tex]

Explanation:

From the question we are told that:

Linear density [tex]\rho=8.5 x 10-3 kg/m[/tex]

Tension [tex]T= 280 N[/tex]

Length of string [tex]l= 1.8 m[/tex]

a)

Generally the equation for Speed of travelling wave is mathematically given by

 [tex]v=\sqrt{\frac{T}{\rho}}[/tex]

 [tex]v=\sqrt{\frac{280}{8.5*10^{-3}}[/tex]

 [tex]v=181.497m/s[/tex]

b)

From the Drawing

Wavelength is given as

 [tex]\lambda=\frac{2L}{3}[/tex]

 [tex]\lambda=\frac{2*1.8}{3}[/tex]

 [tex]\lambda=1.2[/tex]

c)

Generally the equation for Frequency of travelling wave is mathematically given by

 [tex]F=\frac[v}{\lambda}[/tex]

 [tex]F=\frac[181.497}{1.2}[/tex]

 [tex]F=151.248hz[/tex]

Answer:

Explanation:

Answer:

[tex]v_{0,new} = v0\sqrt{}2[/tex]

Explanation:

Initial work done on the proton is given by, [tex]\DeltaW0 = q V_o[/tex]

we know that, [tex]\DeltaW = \DeltaK.E[/tex]

[tex]qV0 = (1/2) m v_0^2[/tex]

[tex]v_0 = \sqrt{}2 q V_0 / m[/tex]                                                        { eq.1 }

If it were accelerated instead through a potential difference of 2V0, then it would gain a speed will be given as :

using the above formula, we have

[tex]v_{0,new} = \sqrt{}2 q (2V0) / m[/tex]    

[tex]v_{0,new} = \sqrt{}4 q V0 / m[/tex]    

[tex]v_{0,new} = v0\sqrt{}2[/tex]

The elevator accelerates upward at an acceleration, then the magnitude of the force is 148.84 N.

The force is the action of push or pull which makes an object to move or stop.

Given the mass of child m =13.9 kg, acceleration a =0.898 m/s², then the force will be given by

F = m(g-a)

F = 13.9 x (9.81 - (-0.898))

F = 148.84 N

Thus, the magnitude of the force is  148.84 N.

Learn more about force.

https://brainly.com/question/13191643

#SPJ2

Answer:

 K = 7.56 10⁻⁴ J

Explanation:

The rotational kinetic energy is

        K = ½ I w²

They ask us for the kinetic energy of the wheel, which can be approximated as a thin ring, its moment of inertia is

         I = M r²

the linear speed of the gerbils is equal to the linear speed of the wheel. The linear and rotational variables are related

          v = w r

          w = v / r

   we substitute

         K = ½ (M r²) v² / r²

         K = ½ M v²

let's calculate

         K = ½ 5 10⁻³ 0.55²

         K = 7.56 10⁻⁴ J

Answer:

13.09 s

Explanation:

From the question given above, the following data were obtained:

Power (P) = 275 W

Work (W) = 3600 J

Time (t) =?

Power is defined as the rate at which work is done. Mathematically, it can be expressed:

Power (P) = Work (W) / time (t)

P = W/t

With the above formula, we can obtain the time taken for the swimmer to accomplish the work. This can be obtained as follow:

Power (P) = 275 W

Work (W) = 3600 J

Time (t) =?

P = W/t

275 = 3600/t

Cross multiply

275 × t = 3600

Divide both side by 275

t = 3600 / 275

t = 13.09 s

Thus, it will take the swimmer 13.09 s to accomplish the work.