Someone plssss help meeee !!!! How much energy is required to vaporize 112 g of water? ???
Answer:
6.05 × 10⁴ cal
Explanation:
Step 1: Given and required data
Mass of water (m): 112 g
Enthalpy of vaporization of water (ΔHvap): 540 cal/g
Step 2: Calculate how much energy is required to vaporize 112 g of water
Vaporization is a physical change in which a substance goes from the liquid state to the gaseous state. We can calculate the energy required (Q) using the following expression.
Q = ΔHvap × m
Q = 540 cal/g × 112 g = 6.05 × 10⁴ cal
Provide the IUPAC names for
the following structures
CH2CH3
w
CH2CH:
(b) H-C-N
CH.CH
H-EN
N
H
(c)
OCH2CH3
Answer:
For a: The IUPAC name of the compound is N-ethylethaneamide.
For b: The IUPAC name of the compound is N,N-diethylmethaneamide.
For c: The IUPAC name of the compound is ethyl pentanoate
Explanation:
To name a compound, first look for the longest possible carbon chain.
For a:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'
Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N-ethylethaneamide.
For b:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'
Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.
For c:Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.
These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.
In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'
Also, an ethyl group forms the alcoholic part.
Hence, the IUPAC name of the compound is ethyl pentanoate
A solution has a [H3O+] 1 x 10^-3 what is the [OH-] of the solution
Answer:
OH- is 1x 10^ + 3
Explanation:
- and - = +
Why should a science teacher know how to prepare stock solution
Answer:
because they were thought in college
Explanation:
hope that helps
What is 0.29km in mm
The percent to by mass of chlorine
Answer: 100.000%
Explanation:
.
A mixture of sodium hydroxide and strontium hydroxide contains a total of 0.19 moles of the two compounds. It requires 100.0 mL of 2.969 M HCl to neutralize all of the base. How many moles of sodium hydroxide were in the original mixture
Answer:
0.0831 moles of NaOH were in the original mixture
Explanation:
The strontium hydroxide, Sr(OH)2, requires 2 moles of HCl per mole of hydroxide to be neutralized.
The sodium hydroxide, NaOH, requires 1 mol of HCl per mol of hydroxide.
To solve this question we must write 2 equations:
(1) 0.19mol = X + Y
Where X = Moles NaOH; Y = Moles Sr(OH)2
The moles of HCl required are:
0.100L * (2.969mol / L) = 0.2969 moles HCl
0.2969 mol = X + 2Y(2)
Replacing (1) in (2):
0.19mol - Y = X
0.2969 mol = (0.19mol - Y) + 2Y
0.1069mol = Y
Moles X = Moles NaOH:
0.19mol = X + 0.1069mol
X = 0.0831 moles of NaOH were in the original mixture
A 300 g sample of copper is heated to 285°C and then placed into 1000 g of water at 26.5°C period what was the final temperature of the water?
Answer:
33.4 °C
Explanation:
The final temperature of water will be the equilibrium temperature. This can be obtained as follow:
Mass of copper (M꜀) = 300 g
Initial temperature of copper (T꜀) = 285 °C
Specific heat capacity of copper (C꜀) = 0.385 J/gºC
Mass of water (Mᵥᵥ) = 1000 g
Initial temperature of water (Tᵥᵥ) = 26.5 °C
Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC
Equilibrium temperature (Tₑ) =?
Heat lost by copper = Heat gained by water
M꜀C꜀(T꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
300 × 0.385 (285 – Tₑ) = 1000 × 4.184 (Tₑ – 26.5)
115.5(285 – Tₑ) = 4184(Tₑ – 26.5)
Clear the bracket
32917.5 – 115.5Tₑ = 4184Tₑ – 110876
Collect like terms
32917.5 + 110876 = 4184Tₑ + 115.5Tₑ
143793.5 = 4299.5Tₑ
Divide both side by 4299.5
Tₑ = 143793.5 / 4299.5
Tₑ = 33.4 °C
Therefore, the final temperature of water is 33.4 °C.
How many tons are contained in 825 megagrams?
Answer:909
Explanation:
Cual es la flora de los Bancos Aluviales?
Por favor necesito ayuda
Answer:
Un río aluvial es aquel en el que el lecho y las riberas están formados por sedimentos móviles y / o suelo.
Explanation:
If the pH of a solution increases from 4.0 to 6.0, the hydronium ion concentration.
A) increases by a factor of 100.
B) decreases by a factor of a 100.
C) decreases by a factor of 1.5
D) increases by a factor of 1.5
Answer:
decrease by a factor of 1.5
Calcium carbonate is often used as an antacid. Your stomach acid is composed of HCl at a pH of 1.5. If you ate toooo much Turkey and need to neutralize 15.0 mL of stomach acid, how many grams of calcium carbonate would you need to take
Answer: 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl
Explanation:
pH is defined as the negative logarithm of hydrogen ion concentration present in the solution
[tex]pH=-\log [H^+][/tex] .....(1)
Given value of pH = 1.5
Putting values in equation 1:
[tex]1.5=-\log[H^+][/tex]
[tex][H^+]=10^{(-1.5)}=0.0316M[/tex]
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(2)
We are given:
Volume of solution = 15.0 mL
Molarity of HCl = 0.0316 M
Putting values in equation 2:
[tex]0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol[/tex]
The chemical equation for the reaction of HCl and calcium carbonate follows:
[tex]2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2[/tex]
By the stoichiometry of the reaction:
2 moles of HCl reacts with 1 mole of calcium carbonate
So, [tex]4.74\times 10^{-4}mol[/tex] of HCl will react with = [tex]\frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol[/tex] of calcium carbonate
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Moles of calcium carbonate = [tex]2.37\times 10^{-4}mol[/tex]
Molar mass of calcium carbonate = 100.01 g/mol
Putting values in the above equation:
[tex]\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g[/tex]
Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl
Gold crystallizes in a face-centered cubic structure. What is the edge length of the unit cell if the atomic radius of gold is 144 pm?
407 pm
333 pm
204 pm
288 pm
Answer:
407 pm
Explanation:
For any elemental face-centered cubic structure, the relationship between the edge length of the unit cell and the atomic radius of its element is:
√2 * L = 4rWhere L is the edge length and r is the atomic radius.
With that in mind we can calculate the edge length:
√2 * L = 4 * 144 pmL = 407 pmWhich of the following will increase solubility the rate of the dissolving process of a gaseous solute in solvent? (mark all that apply) please help!
Answer: The increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:
Increasing agitationIncreasing temperatureIncreasing solute's partial pressure over the solventIncreasing solute's surface areaExplanation:
When agitation is increased then there will occur an increase in kinetic energy of the molecules of a substance. As a result, more number of collisions will take place due to which more amount of solute will dissolve into the solvent.
Similarly, increasing the temperature will further increase the kinetic energy of molecules. Hence, this will lead to more solubility of gaseous solute into the liquid solvent.
As solubility of a gas is directly proportional to the pressure of the gas above surface of the solution. So, an increase in solute's partial pressure over solvent will also lead to an increase in solubility of gaseous solute into liquid solvent.
When surface area of solute is increased then there will be more solute particles available for reaction. Hence, more collisions will take place. As a result, rate of reaction is more due to which there will be an increase in solubility.
Thus, we can conclude that the increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:
Increasing agitationIncreasing temperatureIncreasing solute's partial pressure over the solventIncreasing solute's surface area2Al + 6HCl → 2AlCl3 + 3H2
If 12 moles of Al completely react, how many moles of H2 are produced?
Answer:
18 moles of H₂.
Explanation:
The balanced equation for the reaction is given below:
2Al + 6HCl –> 2AlCl₃ + 3H₂
From the balanced equation above,
2 moles of Al reacted to produce 3 moles of H₂.
Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:
From the balanced equation above,
2 moles of Al reacted to produce 3 moles of H₂.
Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.
Thus, 18 moles of H₂ were obtained from the reaction.
This kind of bond is formed when an atom with low electronegativity donates electrons to an
atom with high electronegativity.
Answer:
Ionic Bond
Explanation:
The atom with the higher electronegativity wants to fill its valence electron shell (meaning it wants 8 electrons in this shell). The atom with lower electronegativity will want to empty or donate an electron so that it can have an empty valence shell.
Draw the diagram of 4-propylnonane
im missing something though
Which is equal to a temperature of 50°F?
Answer:
10⁰C
Explanation:
10⁰C is equal to 50⁰F
what is the correct symbol for the element copper
Answer:
the correct symbol for copper is:CUAnswer:Cu
Explanation
First letter is usually capital then the other letters are usually in small letters
True or false
Bases will have a relatively high concentration of hydroxide ions and a pH around 10.
Answer:
false
Explanation:
It is because the pH for Hydroxide ions is 7
Answer:
True
Explanation:
Acids have a low concentration of hydroxide ions and a pH of 1-6, while bases have a high concentration of hydroxide ions and a pH of 8-14
Practice by predicting what would happen if the following underwent alpha decay: (2 points each)
i. Radium-226 ________+ _____
ii. Plutonuim-240 __________+ _____
iii. Uranium-238 __________+ _____
Answer:
See explanation and image attached
Explanation:
During alpha decay, the mass number of the daughter nucleus is less than that of the parent nucleus by 4 units while the atomic number of the daughter nucleus is less than that of the parent nucleus by two units.
Hence, the daughter nucleus is found two places before the parent in the periodic table.
The alpha decay of the species shown in the question are described in the image attached to this answer.
How many molecules are contained in 52.5 moles of C2H8?
please explain if you can
Answer:
3.1621 × 10²⁵ molecules
Explanation:
From the given information:
Moles of C2H8 = 52.5 moles
number of moles = mass/molar mass
molar mass of C2H8 = (6 *2) + (1*8)
= 12 + 8
= 20 g/mol
∴
52.5 moles = mass of C2H8 / 20 g/mol
mass of C2H8 = 52.5 moles × 20 g/mol
mass of C2H8 = 1050 grams
Recall that;
1 mole = 6.023 × 10²³ molecules
∴ 52.5 moles of C2H8 = (52.5 × 6.023 × 10²³) molecules
=3.1621 × 10²⁵ molecules
A sample of O2 gas is put into a bottle at STP. If the volume of the bottle is 0.52 L, how many moles of O2 will the bottle contain?
please help!!
Answer:
Explanation:
So,at STP or NTP, one mole of any gas occupies 22.4 litres of volume. To find mass,firstly we have to calculate the no. Of moles present in 11.2 litres of O2 gas which can be calculated as ;
No. Of moles = Given Volume ÷ 22.4 Litre (provided that gas is at STP)
= 11.2 Litre / 22.4 Litre
= 0.5 moles
Now, mass can be calculated by;
Mass = no. Of moles × Molecular mass
= 0.5 × 32 (Molecular mass of O2 is 32u or 32 g, if you are calculating in Grams, also called Gram Molecular Mass)
= 16 g
This is the answer
what is the relationship between Celsius scale and Kelvin scale of temperature ? very sort answer
Answer:
Celsius + 273 = Kelvin
Explanation:
Practice by predicting what would happen if the following underwent beta decay: (2
iv. Carbon -10 __________+ _____
v. Cesium-137 __________+ _____
vi. Thorium-234 __________+ _____
Answer:
See explanation and image attached
Explanation:
During beta emission, neutrons are converted into protons and electrons. The anti neutrino balances the spins.
When a nucleus undergoes beta emission, the mass number of the daughter nucleus produced in the process is the same as that of the parent nucleus but the atomic number of the daughter nucleus increases by one unit.
The product of the beta decay of the nuclides shown in the question is described in the image attached to this answer.
The solubility of a gas is 0.890 8/1 at a pressure of 121 kPa. What
is the solubility of the gas if the pressure is increased to 150 kPa,
given that the temperature is held constant?
Answer:
1.10 g/L
Explanation:
Step 1: Calculate Henry's constant (k)
The solubility of a gas (C) is 0.890 g/L at a pressure (P) of 121 kPa. Solubility and pressure are related through Henry's law.
C = k × P
k = C / P
k = (0.890 g/L) / 121 kPa = 7.36 × 10⁻³ g/L.kPa
Step 2: Calculate the solubility of the gas if the pressure is increased to 150 kPa
We will use Henry's law.
C = k × P
C = (7.36 × 10⁻³ g/L.kPa) × 150 kPa = 1.10 g/L
Solubility of the gas, if the temperature is held constant and pressure is increased to 150 kPa from 121 kPa, is 1.10 g/L.
What is Henry's law?Henry's law of gas states at solubility (C) of the dissolved gas is directly proportional to the partial pressure (P) of the gas.
C ∝ P
C = kP, where
k = Henry's constant
Let first we calculate the Henry's constant, when the solubility of a gas is 0.890 g/L at a pressure of 121 kPa is:
k = (0.890 g/L) / (121 kPa)
k = 7.36 × 10⁻³ g/L.kPa
Now we calculate the solubility of the gas, if the pressure is increased to 150 kPa as:
C = (7.36 × 10⁻³ g/L.kPa) (150 kPa)
C = 1.10 g/L
Hence, required solubility is 1.10 g/L.
To know more about Henry's constant, visit the below link:
https://brainly.com/question/7007748
Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a catalyst in organic reactions. Calculate the number of moles of HCl in 62.85 mL of 0.453 M hydrochloric acid.
Answer: 0.0285 moles of HCl is present in given amount of solution.
Explanation:
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)
Given values:
Molarity of HCl = 0.453 M
Volume of solution = 62.85 mL
Putting values in equation 1, we get:
[tex]0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles[/tex]
Hence, 0.0285 moles of HCl is present in given amount of solution.
1. Make ___________________
Observe an event. State only what we can
________ or ____________.
2. Ask ___________________
Ask a question that helps us find out _______ and _______ the event happened. We must be
able to answer the question with ________, or ________. We may need to __________ our question several times before it is__________.
3. Construct a_____________________
State the answer we think we’ll get when we ask
our question. This is called a
_________________. It’s based on our best
understanding of the event.
4. Test the hypothesis with an
_______________________
Test whether the hypothesis is ___________.
During the investigation, we collect _______ that
answers the testable question we asked.
Answer:
Explanation:
ANCHOR ANCHOR ANCHOR ANCHOR
How many molecules are in 4.44 mol of CF4? 4.44 mol CF4 =
I am not sure abt the ans
molar mass= 88
1 molecule = 6.022×10^23
4.44 moles = 6.022×10^23×4.44/88
= 26.73768 × 10^23/88
= 0.3038372727 ×10^23
Neap tides happen when ?