Which of the following determines protein structure and function? O TRNA ORNA O The presence of oxygen Genes No answers are correct

Answers

Answer 1

The structure and function of proteins are determined by their amino acid sequence. The sequence of amino acids in the polypeptide chain is dictated by the nucleotide sequence of the gene that encodes the protein.

The nucleotide sequence is transcribed into RNA, which is then translated into a polypeptide by the ribosome using tRNA as the adapter molecule that brings the correct amino acid to the ribosome. The amino acid sequence of a protein determines how it will fold into its unique three-dimensional shape and interact with other molecules in the cell. The shape of a protein is critical for its function because it determines which molecules it can bind to and how it can catalyze chemical reactions.

Any change in the amino acid sequence can alter the shape and function of the protein, leading to genetic disorders and diseases. Therefore, it is essential to understand the factors that influence protein structure and function. Answer: The amino acid sequence of a protein determines its structure and function.

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Related Questions

In early animal development, the ball of cells resulting from cleavage will hollow out to form a central fluid-illed chamber. This common embryonic structure is called A. gastrula B. blastula C. zygote D. gametophyte

Answers

The correct answer to the given question is option B: blastula. The blastula is the ball of cells resulting from cleavage that hollows out to form a central fluid-filled chamber.

The ball of cells resulting from cleavage in early animal development that hollows out to form a central fluid-filled chamber is called blastula. Embryonic development of animals is an intriguing subject that has been studied and researched by scientists for many years.

In animals, the zygote divides via mitosis to form a ball of cells known as the blastula. This structure undergoes gastrulation to form a gastrula. The blastula is a hollow sphere of cells, which results from the cleavage of a fertilized egg. It is considered the first stage of development after fertilization.The blastula is a critical stage in early embryonic development since it establishes the structure that ultimately develops into the embryo. It is during the blastula stage that a key process, gastrulation, occurs.

This process involves the formation of a central fluid-filled cavity within the blastula. This cavity is called the blastocoel, which acts as a precursor to the gut of the developing organism.The process of gastrulation occurs when the blastula undergoes a series of cell movements. The cells of the blastula move inward, pushing towards the center of the sphere. This leads to the formation of a structure called the blastopore.

The blastopore is the opening through which the developing organism will eventually take in food and eliminate waste. It is considered a common embryonic structure in early animal development that ultimately establishes the structure that develops into the embryo.

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Analgesics are used for the relief of:___ A Pain B. Ulcers C. Congestion

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Analgesics are medications used for the relief of pain. Analgesics are a class of medications commonly used to alleviate pain.

Analgesics work by targeting the body's pain receptors and reducing the perception of pain signals. Analgesics are available in various forms, including over-the-counter (OTC) drugs and prescription medications. Common OTC analgesics include acetaminophen (Tylenol) and non-steroidal anti-inflammatory drugs (NSAIDs) like ibuprofen (Advil) and naproxen (Aleve).

These medications are effective for mild to moderate pain relief and are commonly used for headaches, muscle aches, and menstrual cramps. Prescription analgesics, such as opioids, are more potent and are typically used for severe pain management, such as post-surgical pain or chronic pain conditions.

It is important to use analgesics as directed and consult a healthcare professional if the pain persists or worsens. Some analgesics may have side effects and can interact with other medications, so it is crucial to follow proper dosage guidelines and consult a healthcare provider if there are any concerns.

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What differentiates adaptive immunity from innate immunity? (select two answers)
1) Adaptive immunity is a response to a specific pathogen whereas innate immunity is a response to a pathogen-associated pattern.
2) Innate immunity is a response to a specific pathogen whereas adaptive immunity is a response to a pathogen-associated pattern.
3) The adaptive immune response is more vigorous on repeated exposure to the same pathogen.
4) The innate immune response is more vigorous on repeated exposure to the same pathogen.
5) Adaptive immunity acts much faster than innate immunity.

Answers

Two key differences between adaptive immunity and innate immunity are: (1) Adaptive immunity is a response to a specific pathogen, while innate immunity is a response to a pathogen-associated pattern.

(2) The adaptive immune response is more vigorous on repeated exposure to the same pathogen, whereas the innate immune response is more vigorous upon initial exposure.

Adaptive immunity is a response to a specific pathogen, while innate immunity is a response to a pathogen-associated pattern. Adaptive immunity involves the recognition of specific antigens presented by the pathogen, which triggers a targeted response. In contrast, innate immunity relies on pattern recognition receptors that recognize conserved patterns associated with pathogens, such as bacterial cell wall components or viral nucleic acids. This allows the innate immune system to respond rapidly to a wide range of pathogens without requiring prior exposure.

The adaptive immune response is more vigorous on repeated exposure to the same pathogen. This is due to the immunological memory developed by the adaptive immune system. Upon initial exposure to a pathogen, the adaptive immune response takes time to develop, but subsequent exposures to the same pathogen elicit a faster and more robust response. This memory response is mediated by B and T lymphocytes, which undergo clonal expansion and differentiation into effector cells upon re-encountering the specific pathogen.

In contrast, options 2, 4, and 5 are incorrect. Innate immunity is not specific to a particular pathogen, and the innate immune response is generally more rapid and immediate upon initial exposure to a pathogen.

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A phagocyte lacking TLRs (or PRRs) will be defective at which stage? O Digesting pathogens. O engulfing pathogens O Stimulating inflammation. O Displaying antigens. O binding to pathogens

Answers

A phagocyte lacking Toll-like receptors (TLRs) or pattern recognition receptors (PRRs) will be defective at the stage of recognizing and binding to pathogens.

TLRs and PRRs are integral components of the innate immune system and are responsible for detecting specific molecular patterns on pathogens. They serve as the first line of defense by initiating the immune response upon pathogen recognition. Without functional TLRs or PRRs, the phagocyte would be unable to recognize the presence of pathogens and initiate the process of engulfing them.

This defect would impair the phagocyte's ability to effectively respond to infections and eliminate pathogens. Thus, the absence of TLRs or PRRs hinders the crucial step of pathogen recognition and binding, compromising the phagocyte's overall immune function.

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You are working in a laboratory with primary focus on cell cycle. You are given following cell lines:
a) p53 knockout cells
b) Mad2 knockout cells
c) Rb knockout cells
Your aim is to analyze the behavior of these cells under following conditions.
i. Exposure to UV radiation
ii. Lack of mitogens
iii. Treatment with nocodazole (a microtubule depolymerizing drug)
What phenotypes do you expect to see? Explain for each cell type under each condition. (hint: your primary focus is cell cycle)

Answers

The cell cycle is a tightly regulated process involving multiple checkpoints to ensure accurate cell division. Any disruption in the cell cycle can lead to various phenotypes in different cell types.

In this scenario, we have three different cell lines with specific gene knockouts and three different conditions that may affect the cell cycle. Let's analyze each cell type under different conditions: p53 knockout cells: p53 is a tumor suppressor gene that is activated in response to DNA damage. In the absence of p53, cells are more prone to DNA damage-induced mutations and uncontrolled cell division. Exposure to UV radiation: UV radiation can cause DNA damage by creating pyrimidine dimers that are repaired by the nucleotide excision repair pathway.

In the absence of p53, cells are more likely to undergo DNA damage-induced cell cycle arrest, apoptosis or continue to divide with mutations, leading to cancer. Lack of mitogens: Mitogens are signaling molecules that stimulate cell division by activating CDKs and promoting Cyclin synthesis. In the absence of p53, cells may continue to divide without proper cell signaling, leading to aneuploidy and chromosomal instability. Treatment with nocodazole: Nocodazole is a microtubule depolymerizing drug that arrests cells in mitosis by disrupting the spindle fiber formation. In the absence of p53, cells may undergo mitotic slippage and exit mitosis without proper segregation of chromosomes, leading to aneuploidy and polyploidy. Mad2 knockout cells: Mad2 is a protein that is essential for proper spindle checkpoint signaling during cell division.

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during hyper polarization, when the charge is below -70 mv and the soduim-potassium pump begins to work, how does it make sense that the charge is brought up if 3+Na charged ions are leaving the cell and 2+ K are entering? shouldnt it continue to go down since more positve ions are leaving then entering ? how exactly does that balance it

Answers

During hyperpolarization, when the charge is below -70 mv and the sodium-potassium pump begins to work, the charge is brought up in the cell by the action of the pump.

Although the sodium-potassium pump pushes out more positive sodium ions than it brings in positive potassium ions, it does not cause the charge to decrease. This is because the cell is constantly permeable to certain ions (such as K+), which diffuse into the cell and help balance the charge.

K+ enters the cell, it helps to bring the charge back up towards its resting potential of -70 mV.In conclusion, even though more positive ions are leaving the cell than entering during hyperpolarization, the cell is constantly permeable to ions such as K+ which diffuse into the cell and help to balance the charge. This causes the charge to increase and the cell returns to its resting potential of -70 mV.

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If bacteria produce superoxide dismutase, we would expect it to
be made at ribosomes.
a) True
b) False

Answers

If bacteria produce superoxide dismutase, we would expect it to be made at ribosomes. This statement is False.

Superoxide dismutase is a metalloenzyme that catalyzes the conversion of superoxide anions to hydrogen peroxide and molecular oxygen. Superoxide dismutase is a metalloenzyme, which means that it contains metal ions as part of its functional structure.

Because superoxide dismutase is a protein, it is synthesized on ribosomes, as are all proteins. As a result, the bacterial species that manufacture superoxide dismutase can manufacture it on their ribosomes, and any organism with a sufficiently similar genetic code could potentially manufacture it on its ribosomes.

The term "superoxide dismutase" refers to a specific protein, and its production requires the action of ribosomes. It is also believed that these proteins are localized to the cytoplasm in some bacteria. As a result, the statement "If bacteria produce superoxide dismutase, we would expect it to be made at ribosomes" is incorrect.

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What is plasmid DNA, and what is its function in
bacteria? (4 pts)

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Plasmid DNA is a circular, double-stranded DNA that is typically found in bacteria. They are not part of the chromosome of the organism and are much smaller than it. Plasmids have varying sizes, ranging from a few thousand to millions of base pairs in length.

They usually carry genes that are not essential for the survival of the bacteria that harbors them, but they often contain genes that give the bacteria some type of advantage, such as antibiotic resistance genes.Plasmid DNA functions in bacteria by providing genetic diversity through horizontal gene transfer. It is essential to their survival because they enable bacteria to share genetic information, which can enhance their adaptability and ability to evolve. Bacteria can exchange plasmids through a process known as conjugation, in which two bacterial cells form a physical connection that allows the plasmids to move from one to the other. Plasmids can carry genes that code for functions such as antibiotic resistance or heavy metal detoxification, which are essential for survival in harsh environments.Moreover, some bacteria can also carry a plasmid with genes that produce bacteriocins. These genes may code for proteins that are toxic to bacteria from other species, allowing them to gain an advantage in the microbial competition.

Thus, plasmid DNA has an essential role in bacterial adaptation, evolution, and ecology, making them an essential tool for genetic engineering and biotechnology research.

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In the follicular phase of the ovarian cycle, in the ovary Select one: a. the follicle matures b. a corpus luteum forms c. progesterone is produced as the primary hormone d. insulin is produced as the

Answers

In the follicular phase of the ovarian cycle, in the ovary, the follicle matures (Option A).

What is the ovarian cycle?

The ovarian cycle is the cycle that occurs in the ovary, leading to the release of a mature ovum. The ovarian cycle is regulated by the hypothalamus, pituitary gland, and the ovary. The ovarian cycle occurs in two phases, namely the follicular phase and the luteal phase.

In the follicular phase of the ovarian cycle, which is the first phase, the primary follicles mature. The follicular phase begins on the first day of menstruation and ends with the release of the ovum. During this phase, the follicle-stimulating hormone (FSH) secreted by the anterior pituitary gland stimulates the follicles in the ovary to mature. The follicles, in turn, secrete estrogen. The estrogen produced promotes the thickening of the endometrium (uterine lining) to prepare for implantation in case fertilization occurs.

As the follicles continue to mature, one of them becomes dominant and secretes more estrogen. The high estrogen levels cause a surge of luteinizing hormone (LH), which leads to the release of the ovum. Therefore, in the follicular phase of the ovarian cycle, the follicle matures.

Thus, the correct option is A.

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Currently, the average fat intake in the U.S. is about 35% of total calories consumed. The U.S. Dietary Goals recommend that Americans limit fat calories to 30% of total calories, with no more than 1/3 of the fat from saturated sources. (The predominant effect of saturated fat is to raise LDL cholesterol levels. Animals fats provide most of the saturated fat in the American diet.) Eating less fat will help you reduce the number of calories you consume each day as well as reduce the risk of cancer and heart disease. Eating less total fat is an effective way to eat less saturated fat. Look at the display demonstrating the amount of fat (in grams) in selected foods, and answer the following questions. NOTE: One tube full of fat is equal to 11 grams. 1. In terms of fat content, 2% milk is halfway between whole (4%) and skim (0%) milk. How much fat is in 1 cup of 2% milk? 2. You're craving potato chips. Which is better for you, the '1/3 less fat' potato chips or the regular potato chips? What is the difference in fat grams? 3. How many grams of fat are in a Milky Way Candy Bar. 4. Which has more fat, 3 oz. fish, 3 oz. roasted chicken without skin, or 3 oz. 90% lean ground beef? 5. How many grams of fat are there in a Quarter Pounder or a Whopper? 6. Does adding a piece of cheese really make a difference in a burger when it comes to fat?

Answers

1. In 1 cup of 2% milk, there would be approximately 5.5 grams of fat. This is halfway between the fat content of whole milk (4%) and skim milk (0%).

2. The "1/3 less fat" potato chips would be a better option compared to regular potato chips. The difference in fat grams would depend on the specific brands and serving sizes being compared. However, the "1/3 less fat" version typically contains approximately one-third less fat than the regular version.

3. The number of grams of fat in a Milky Way Candy Bar can vary depending on the specific size and brand. On average, a regular-sized Milky Way Candy Bar contains around 8-9 grams of fat.

4. Out of the options given, 3 oz. 90% lean ground beef would have the most fat. Ground beef is generally higher in fat compared to fish and chicken. The specific amount of fat would depend on the specific cut and preparation method.

5. The exact amount of fat in a Quarter Pounder or a Whopper can vary depending on the specific ingredients and preparation methods used. On average, a Quarter Pounder from a fast food restaurant can contain around 20-30 grams of fat, while a Whopper can contain around 40-50 grams of fat.

6. Adding a piece of cheese to a burger can increase the fat content. Cheese is generally high in fat, so adding it to a burger will contribute additional fat grams. The amount of fat added would depend on the type and size of cheese used.

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Review the phospholipid bilayer. Understand the fluid mosaic
model of plasma membranes. Make sure you know what molecules
make-up the membrane and the functions of membrane proteins.

Answers

The phospholipid bilayer and its associated molecules, including proteins, cholesterol, and carbohydrates, form a dynamic structure that regulates the movement of substances in and out of the cell, provides structural support, and facilitates cell communication and recognition.

The phospholipid bilayer is a fundamental component of cell membranes. It is composed of two layers of phospholipid molecules arranged with their hydrophilic (water-loving) heads facing outward and their hydrophobic (water-repelling) tails facing inward. This arrangement creates a barrier that separates the internal contents of the cell from the external environment.

The fluid mosaic model describes the dynamic nature of the plasma membrane. It suggests that the membrane is fluid-like, with individual phospholipids and proteins able to move laterally within the membrane. The mosaic aspect refers to the diverse array of molecules embedded in the membrane, including proteins, lipids, and carbohydrates.

The main molecules that make up the membrane are:

Phospholipids: These are the primary structural components of the bilayer. They consist of a hydrophilic head (containing a phosphate group) and two hydrophobic tails (composed of fatty acid chains). The arrangement of phospholipids forms a stable barrier while allowing for fluidity and flexibility.

Proteins: Membrane proteins have various functions, including transport of molecules across the membrane, cell signaling, enzymatic activity, and structural support. Integral membrane proteins are embedded within the lipid bilayer, while peripheral membrane proteins are associated with the surface of the membrane.

Cholesterol: Cholesterol molecules are interspersed within the phospholipid bilayer. They help regulate membrane fluidity and stability by reducing the permeability of the membrane to small water-soluble molecules.

Carbohydrates: Carbohydrates are present on the outer surface of the plasma membrane in the form of glycolipids and glycoproteins. They play roles in cell recognition, immune response, and cell-cell communication.

Membrane proteins can be classified into two main types:

Integral proteins: These span the entire phospholipid bilayer, with portions exposed on both the extracellular and intracellular sides of the membrane. They are involved in various functions such as transport, signal transduction, and enzymatic activity.

Peripheral proteins: These are loosely attached to the membrane surface, often associated with integral proteins or lipid molecules. They play roles in cell signaling, cytoskeletal organization, and cell shape.

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Consider Cytochrome P450 (CYP).
a) Draw the structure of the resting state active site and that of a typical heme protein (e.g. myoglobin; you need not draw amino acids except for the relevant, metal-coordinating groups).
b) What is the generic reaction catalyzed by cytochromes P450? Why are there so many forms and biological sources of this enzyme?
c) Draw the structure of the catalytically reactive form of cytochrome P450 active site. What are two formalisms for counting oxidation state in this reactive intermediate? How could you distinguish between them spectroscopically?
d) Why is there interest in CYPs by the pharmaceutical industry?

Answers

Cytochrome P450 is an enzyme a. myoglobin, b. endogenous and exogenous compounds, c. oxidation state and ferric/ferrous state,  it distinguish between characteristic absorption, d. interest drug metabolism

The reactive form of the CYP active site can be characterized by its structure and oxidation state, which can be counted using different formalisms and distinguished spectroscopically. The pharmaceutical industry is interested in CYPs due to their involvement in drug electrophilic metabolism and their potential as targets for drug development.

a) The structure of the resting state active site of cytochrome P450 consists of a heme group coordinated to the protein, along with relevant amino acids that contribute to its binding and stability. A typical heme protein, such as myoglobin, contains a heme group with an iron atom coordinated by a histidine residue.

b) Cytochromes P450 catalyze a generic reaction known as monooxygenation, where a substrate molecule is oxidized using molecular oxygen (O2) to introduce an oxygen atom into the substrate. There are numerous forms and biological sources of this enzyme due to its involvement in various metabolic pathways and its ability to metabolize a wide range of endogenous and exogenous compounds.

c) The catalytically reactive form of the cytochrome P450 active site involves the binding of a substrate to the heme iron center, resulting in the formation of a reactive intermediate. Two formalisms for counting the oxidation state of this intermediate are the ferric/ferrous state (Fe3+/Fe2+) or the iron(IV)-oxo state (Fe(IV)=O). Spectroscopic techniques such as UV-visible absorption spectroscopy and resonance Raman spectroscopy can be used to distinguish between these formalisms based on the characteristic absorption bands and vibrational frequencies.

d) The pharmaceutical industry is interested in cytochromes P450 due to their crucial role in drug metabolism. CYPs are responsible for the metabolism and elimination of many drugs, and their activity can impact drug efficacy, toxicity, and drug-drug interactions. Understanding the specific CYP isoforms involved in drug metabolism is essential for optimizing drug dosing and minimizing potential adverse effects. Additionally, CYPs are potential targets for drug development, as modulating their activity can provide therapeutic benefits for various diseases. Therefore, studying and characterizing CYPs is of great interest to the pharmaceutical industry.

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3. (5 Points) What is the effect on the body's center of gravity when the shoulder/GH joint is at 90 degrees of flexion? Where is it as compared to its normal position in the adult human body? 1

Answers

When the shoulder/GH joint is at 90 degrees of flexion, the effect on the body's center of gravity is that it moves forward.

The body's center of gravity is normally located around the pelvis, but when the shoulder/GH joint is at 90 degrees of flexion, the center of gravity moves forward towards the feet.The human body is designed to function properly with the center of gravity directly above the pelvis, which makes it easy to maintain balance.

However, when the shoulder/GH joint is at 90 degrees of flexion, it can cause an imbalance by shifting the center of gravity forward, making it more difficult to maintain balance and potentially leading to falls and injuries.

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25. The nurse needs to administer oxygen to a patient who has an oxygen level of 2L/min prescribed. Which of the following oxygen devices should the nurse choose? A. Simple face mask B. Venturi mask C

Answers

The nurse should choose Venturi mask to administer oxygen to the patient with a prescribed oxygen level of 2L/min. So, option B is accurate.

A. Simple face mask: While a simple face mask can deliver oxygen, it is not the most suitable option for precise oxygen delivery at a specific flow rate like 2L/min.

B. Venturi mask: A Venturi mask is designed to deliver a precise oxygen concentration by mixing oxygen with room air. It has different color-coded adapters or valves that allow for specific oxygen flow rates. This makes it suitable for delivering oxygen at a prescribed rate of 2L/min.

C. Surgical Masks: Surgical masks are not designed for oxygen delivery. They are primarily used to protect others from respiratory droplets expelled by the wearer.

D. General N95 Respirator Precautions: N95 respirators are also not used for oxygen delivery. They are respiratory protective devices designed to filter out airborne particles and provide a secure facial fit for individuals working in environments with respiratory hazards.

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The complete question is:

The nurse needs to administer oxygen to a patient who has an oxygen level of 2L/min prescribed. Which of the following oxygen devices should the nurse choose?

A. Simple face mask

B. Venturi mask

C. Surgical Masks.

D. General N95 Respirator Precautions.

1. Explain the reason why pulp sensation diminishes as age
progresses.

Answers

As an individual grows older, the pulp sensation diminishes. There are several explanations for why this happens. Pulp is a delicate and vulnerable tissue that is located in the center of a tooth.

It's composed of blood vessels, nerves, and other soft tissue that nourish the tooth's growth and development. Pulp has a critical role in protecting the tooth from external and internal stressors. External stressors such as trauma, deep decay, or fractures might injure the pulp, while internal stressors such as inflammation or infection may also result in pulp damage. If the pulp becomes infected or inflamed, it may cause severe pain that can affect a person's ability to eat, sleep, or even speak.

It is referred to as pulpitis in dentistry. The causes of pulpitis may vary, but the most common ones are deep decay, trauma, or extensive dental work. Furthermore, as a person grows older, the blood flow and nerve function to the pulp decreases, causing pulp tissue to shrink, and eventually, the pulp will die. The pulp's diminished sensation is due to the aging process's effects on blood supply and nerve function. The effects of aging include a reduction in the size and number of blood vessels that supply the pulp with nutrients, as well as a reduction in nerve sensitivity.

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Which vessels significantly affect neither preload nor afterload when the sympathetic nervous system is activated?

Answers

When the sympathetic nervous system is activated, the vessels that do not significantly affect preload or afterload are the capillaries and venules.

The sympathetic nervous system plays a key role in regulating cardiovascular functions. Activation of the sympathetic nervous system leads to vasoconstriction, which primarily affects arterioles and larger vessels. Vasoconstriction of arterioles increases systemic vascular resistance and afterload, while vasoconstriction of larger vessels (such as arteries and veins) affects preload. However, capillaries and venules, which are smaller vessels, do not significantly contribute to changes in preload or afterload when the sympathetic nervous system is activated.

Capillaries are responsible for the exchange of oxygen, nutrients, and waste products between the blood and surrounding tissues. Their primary function is to facilitate the exchange of substances, rather than regulate preload or afterload. Venules, on the other hand, collect blood from capillaries and transport it back to the heart. While venules can undergo some degree of constriction, their effect on preload and afterload is relatively minimal compared to larger vessels.

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Persistent pulmonary hypertension of the newborn (PPHN) is characterized by elevated pulmonary vascular resistance resulting in right-to-left shunting of blood and hypoxemia. PPHN is often secondary to parenchymal lung disease (such as meconium aspiration syndrome, pneumonia or respiratory distress syndrome) or lung hypoplasia (with congenital diaphragmatic hernia or oligohydramnios) but can also be idiopathic. The diagnosis of PPHN is based on clinical evidence of labile hypoxemia often associated with differential cyanosis. The diagnosis is confirmed by the echocardiographic demonstration of – (a) right-to-left or bidirectional shunt at the ductus or foramen ovale and/or, (b) flattening or leftward deviation of the interventricular septum and/or, (c) tricuspid regurgitation, and finally (d) absence of structural heart disease. Management strategies include optimal oxygenation, avoiding respiratory and metabolic acidosis, blood pressure stabilization, sedation and pulmonary vasodilator therapy. Failure of these measures would lead to consideration of extracorporeal membrane oxygenation (ECMO); however decreased need for this rescue therapy has been documented with advances in medical management. While trends also note improved survival, long-term neurodevelopmental disabilities such as deafness and learning disabilities remain a concern in many infants with severe PPHN.

Answers

The echocardiographic demonstration of the right-to-left or bidirectional shunt at the ductus or foramen ovale, flattening or leftward deviation of the interventricular septum and/or tricuspid regurgitation confirms the diagnosis of Persistent pulmonary hypertension of the newborn (PPHN).

PPHN stands for persistent pulmonary hypertension of the newborn. This is a severe and potentially life-threatening lung condition that affects infants. This occurs when the circulation changes after birth. As a result, blood flow bypasses the baby's lungs, decreasing the baby's oxygen levels.

PPHN diagnosisThe diagnosis of PPHN is confirmed by the echocardiographic demonstration of:

a) right-to-left or bidirectional shunt at the ductus or foramen ovale and/or

b) flattening or leftward deviation of the interventricular septum and/or

c) tricuspid regurgitation, and finally

d) absence of structural heart disease.

Management of PPHN- Management strategies include optimal oxygenation, avoiding respiratory and metabolic acidosis, blood pressure stabilization, sedation, and pulmonary vasodilator therapy.

However, decreased need for this rescue therapy has been documented with advances in medical management. If these measures fail, extracorporeal membrane oxygenation (ECMO) should be considered. Despite trends towards improved survival, many infants with severe PPHN suffer long-term neurodevelopmental disabilities such as deafness and learning disabilities.

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Needing 2-3 sentences
Describe your current personal view on the relationship between
science and faith. Be sure to include any qualifiers or limits that
may exist within your personal view.

Answers

My current personal view on the relationship between science and faith is that they are both important and can coexist peacefully.

Science helps us understand the natural world around us and provides evidence-based explanations for phenomena. Faith, on the other hand, deals with the spiritual realm and provides a moral compass for our lives.However, I do acknowledge that there are limitations to both science and faith. Science cannot answer questions about the supernatural or spiritual world, while faith cannot provide empirical evidence for its claims. Therefore, I believe that both science and faith have their respective domains and should not be used to encroach on the other.

Ultimately, the relationship between science and faith is complex and multifaceted, and it is up to each individual to determine how they reconcile the two in their own lives.

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Explain how gene expression in eukaryotes is regulated by 2.1 acetyl groups, histone proteins and proteins containing bromodomains (15) 2.2 methyl groups and DNA

Answers

Gene expression in eukaryotes is regulated by various mechanisms, including acetyl groups, histone proteins, proteins containing bromodomains, methyl groups, and DNA. The following is a brief explanation of how these mechanisms regulate gene expression.

2.1 Acetyl Groups, Histone Proteins, and Proteins Containing Bromodomains In eukaryotic cells, histones are proteins that organize DNA into chromatin. The amino terminus of histones protrudes from the nucleosome and can be modified by various chemical groups, including acetyl groups, which neutralize the positively charged lysine residue. Acetylation of histone tails opens up the chromatin structure, allowing transcriptional machinery to access the DNA and facilitating gene expression. The bromodomain is a protein domain that binds acetylated lysine residues in histones. Bromodomains are present in a variety of proteins, including transcriptional co-activators. By binding to acetylated histones, these proteins can facilitate gene expression by recruiting other transcriptional machinery.

2.2 Methyl Groups and DNA, The methylation of DNA at CpG sites, which are DNA regions where a cytosine nucleotide is adjacent to a guanine nucleotide, is another epigenetic mechanism that can regulate gene expression. DNA methylation can inhibit transcriptional machinery from binding to the DNA, resulting in gene silencing. Chromatin is organized into two different forms of chromatin: heterochromatin and euchromatin. Euchromatin is more relaxed and accessible to transcriptional machinery, whereas heterochromatin is tightly packed and inaccessible. DNA methylation can convert euchromatin to heterochromatin, resulting in gene silencing.

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Part B: Essay Question 1. In the space provided, construct a table comparing the biological characteristics of the five classes of immunoglobulins

Answers

The five classes of immunoglobulins are IgG, IgM, IgA, IgE, and IgD. They all play a vital role in the immune system's function. Below is a table comparing the biological characteristics of the five classes of immunoglobulins.

IgG:IgG is the most common class of antibodies, accounting for about 80% of all circulating antibodies in humans. IgG provides long-term protection against bacterial and viral infections. IgG can cross the placenta and offer passive immunity to the fetus. IgG has a long half-life, which means it can remain in the bloodstream for several weeks.IgM:IgM is the first antibody produced in response to an infection. It is responsible for activating the complement system, which leads to the destruction of bacteria.

IgM is also present on the surface of B cells, where it acts as an antigen receptor. IgM is a pentamer, which means it consists of five monomers linked together by disulfide bonds.IgA:IgA is found in high concentrations in bodily fluids such as saliva, tears, and breast milk. It protects mucosal surfaces from bacterial and viral infections. IgA can exist in two forms: secretory IgA (sIgA) and serum IgA (sIgA). sIgA is found in secretions, while sIgA is found in the bloodstream. IgA can form dimers, which means it consists of two monomers linked together by a J chain.

IgE:IgE is responsible for allergic reactions and is found in low concentrations in the bloodstream. IgE binds to allergens and triggers the release of histamine, causing an inflammatory response. IgE is also involved in defending against parasitic infections.IgD:IgD is found on the surface of B cells, where it acts as an antigen receptor. Its function is not entirely understood, but it may play a role in the activation of B cells. IgD is present in low concentrations in the bloodstream.

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miRNA dysregulation has been associated with the development of many human diseases, give example(s) and discuss the mechanisms and the diagnostic and therapeutic applications of miRNA dysregulation. Use the Biomarkers to discuss in detail.

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miRNA dysregulation has been associated with the development of various human diseases, including cancer, cardiovascular diseases, and neurological disorders. Mechanistically, miRNAs can act as oncogenes or tumor suppressors, regulating gene expression and influencing crucial cellular processes. The dysregulation of specific miRNAs can serve as biomarkers for disease diagnosis, prognosis, and response to treatment, offering potential therapeutic applications through miRNA-based therapies and interventions.

miRNAs play a critical role in post-transcriptional gene regulation by binding to target mRNAs, leading to their degradation or inhibition of translation. Dysregulated miRNA expression or function can disrupt normal cellular processes, contributing to disease development and progression. For example, in cancer, aberrant miRNA expression profiles have been linked to tumor initiation, metastasis, and drug resistance. These dysregulated miRNAs can serve as diagnostic biomarkers to detect early-stage cancers or monitor disease progression. Additionally, targeting specific miRNAs using antisense oligonucleotides or miRNA mimics holds therapeutic potential in restoring miRNA homeostasis and regulating disease-associated gene expression.

The dysregulation of miRNAs has emerged as a promising area of research in understanding the pathogenesis of human diseases. By elucidating the mechanisms underlying miRNA dysregulation and harnessing the diagnostic and therapeutic applications of miRNAs, we can potentially improve disease detection, prognosis, and treatment strategies, paving the way for personalized medicine approaches.

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Edgarian bacteria was identified to be the causative agent of an outbreak in Univen community, with your laboratory knowledge, how would you go about finding the etiological agent responsible for the outbreak

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To identify the etiological agent responsible for the outbreak caused by Edgarian bacteria in the Univen community, several steps can be taken in a laboratory investigation.

The general outline of the process:

1. Collect and document clinical information: Gather detailed information about the affected individuals, including symptoms, onset, duration, and any commonalities among the cases. This information will help in designing appropriate laboratory tests.

2. Collect and analyze clinical specimens: Obtain relevant clinical specimens from the affected individuals, depending on the suspected mode of transmission or site of infection. Examples include blood, urine, respiratory secretions, stool, or tissue samples.

3. Perform initial diagnostic tests: Conduct initial screening tests to identify potential bacterial pathogens. This may involve Gram staining, microscopy, and culture techniques to isolate bacteria from the clinical specimens.

4. Conduct biochemical tests: Perform biochemical tests to characterize the isolated bacteria further. These tests can help identify specific metabolic characteristics, enzymatic activities, and other properties of the bacteria.

5. Perform molecular tests: Use molecular techniques such as polymerase chain reaction (PCR) or DNA sequencing to detect and identify the specific genetic markers or sequences associated with the suspected bacteria. This can provide a more accurate identification and differentiation of the etiological agent.

6. Test for antibiotic susceptibility: Determine the antibiotic susceptibility of the identified bacteria using methods like disk diffusion or automated systems. This information is crucial for selecting appropriate treatment options.

7. Compare findings with known pathogens: Compare the laboratory findings with known pathogens, including Edgarian bacteria, to confirm the identity of the etiological agent responsible for the outbreak. This can involve consulting databases, scientific literature, or reference laboratories.

8. Epidemiological investigation: Combine laboratory findings with epidemiological data, including person-to-person contact, common exposures, or environmental factors, to establish the source and mode of transmission for the outbreak.

9. Report and take appropriate action: Communicate the laboratory findings to relevant public health authorities, healthcare providers, and stakeholders involved in outbreak management. Implement necessary control measures to prevent further spread of the bacteria.

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A single stranded sequence of a gene is shown below. An investigator wants to amplify and isolate this small gene using PCR. Design two PCR primers, each 15 nucleotides long, that can be used to amplify this DNA segment. (remember that DNA sequences are written 5' to 3' by convention) ACTTTCCAAACGCCCCGTGTCGATACTGAACGAATCGATGCACGCTCCC TTCCTTGAAAACGCATAAACATACAAGTGGGCAGATGATGCGTACGCCC CTCTAATACATCCAACACTCTACGCCCTCTTCAAGAGCTGGAAGGGCA CCCTGCACTTGGATAGGGGATTATCTCGTAAGGCAAGCTCGTACCGTC ATTCATGCGGAAGAGTTAACACGATTGGAAGTAGGGATAGTTTCGAA CCTCGGTTACTAGTCCTAATAAGGGAACGCTGTCTGAAGGATGAGTGT CAGCCAGTGTA

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The primers are designed to be 15 nucleotides long and are complementary to the target sequence. The forward primer (Primer 1) binds to the template DNA strand in the 5' to 3' direction, starting at the sequence "TTCCTTGAAAACGCAT".

The reverse primer (Primer 2) binds to the complementary DNA strand in the 5' to 3' direction, starting at the sequence "CTGTTAACTTCCGCAT". These primers provide specific binding sites for the DNA polymerase to initiate DNA amplification through PCR. When the primers bind to their respective target sequences, the DNA polymerase can extend the primers by adding nucleotides to amplify the gene of interest. It's important to note that the actual efficiency and specificity of the primers would depend on various factors, including the specific requirements of the PCR reaction, such as the annealing temperature and the presence of any specific nucleotide motifs in the target sequence.

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Explain what effect taking St. John's wort as a nutritional
supplement might have in women also taking combination estrogen and
progesterone birth control pills. What is the physiological
mechanism an

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Taking St. John's wort as a nutritional supplement while also taking combination estrogen and progesterone birth control pills can have an impact on the effectiveness of the birth control pills.

St. John's wort is known to induce certain enzymes in the liver that metabolize drugs, including contraceptive medications. This can lead to a decreased concentration of the hormones in the bloodstream, potentially reducing the contraceptive effectiveness of the birth control pills. The physiological mechanism behind this interaction involves the induction of liver enzymes, specifically cytochrome P450 enzymes, by St. John's wort. These enzymes are responsible for the metabolism and breakdown of various substances, including drugs. St. John's wort can increase the activity of these enzymes, thereby increasing the rate at which the contraceptive hormones are metabolized and eliminated from the body. This faster metabolism can result in lower hormone levels, which may reduce the contraceptive effects of the birth control pills.

It's important for women taking combination estrogen and progesterone birth control pills to be aware of this potential interaction and consult with their healthcare provider before starting St. John's wort or any other herbal or dietary supplements. The healthcare provider can provide guidance on alternative contraceptive methods or adjust the dosage of the birth control pills if needed to maintain their effectiveness.

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Parts of the world that have a high prevalence of helminth infections in humans, have
A  High levels of allergies B  Low levels of mast cells C. Low levels of autoimmune disorders D. High levels of autoimmune disorders QUESTION 15 A mother's IgE production during pregnancy is directly related to the antigens present in her environment. If the mother is exposed to parasitic worms during pregnancy, her baby is likely to have
A. Allergies to the same things its mother is allergic to
B. Worm-specific IgE antibodies C. Only maternal IgE antibodies O
D. Autoimmune disorders

Answers

The correct answer is option B. If a mother is exposed to parasitic worms during pregnancy, her baby is likely to have worm-specific IgE antibodies.

During pregnancy, a mother's immune system can influence the immune development of the baby. If the mother is exposed to parasitic worms (helminths) during pregnancy, her immune system may produce specific antibodies, known as IgE antibodies, in response to the worm antigens. These IgE antibodies can be transferred to the baby through the placenta. Option B accurately reflects this relationship. The baby is likely to have worm-specific IgE antibodies, indicating an immune response specific to the antigens presented by the parasitic worms. This response helps the baby develop a defense mechanism against the worms. Options A, C, and D are incorrect. The baby is not necessarily allergic to the same things its mother is allergic to (option A). The presence of parasitic worms does not necessarily lead to low levels of mast cells (option B) or high levels of autoimmune disorders (option D). The focus here is on the specific immune response to the worms rather than general allergies or autoimmune disorders.

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29.
Most bone in the human body can be divided into two types. __bone makes of some of the most dense parts of the body, such as the shaft of the femur, and therefore is more often preserved after death.

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The most appropriate term to fill in the blank is "Compact".The human body has two kinds of bone: compact and spongy. Compact bone is a kind of hard tissue that forms the outside shell of most bones in the body, including the shafts of long bones like the femur and humerus. Spongy bone is found in the ends of bones and within flat bones like the skull, ribs, and pelvis.

Compact bone is the most dense and strong kind of bone in the body. It provides support and protection for the internal organs and allows for movement by serving as an anchor for the muscles. Compact bone, also known as cortical bone, forms the hard outer shell of bones and is composed of closely packed mineralized tissue. It contains few spaces and is more solid than spongy bone.

Compact bone makes up about 80 per cent of the human skeleton, while spongy bone makes up the remaining 20 per cent.

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PPO (polyphenol oxidase) is responsible for enzymatic browning of fruits and potatoes and is a thylakoid protein with a thylakoid targeting signal "RREVLLGCGGAAAAGLA".
a) Where is PPO synthesized?
b) Is this thylakoid targeting signal sufficient for the enzyme to get to the thylakoid?

Answers

PPO (polyphenol oxidase) is synthesized in the cell's cytoplasm. No, the thylakoid targeting signal is not sufficient for the enzyme to get to the thylakoid.

PPO (polyphenol oxidase) is synthesized in the cell's cytoplasm. It is initially produced as an inactive form called the pre-proenzyme.

PPO catalyzes the oxidation of phenolic compounds, such as catechols and o-diphenols, leading to the formation of brown pigments known as melanins.

No, the thylakoid targeting signal "RREVLLGCGGAAAAGLA" alone is not sufficient for the enzyme to reach the thylakoid.

After synthesis in the cytoplasm, the pre-proenzyme of PPO undergoes a process called protein targeting and translocation to reach its final destination in the thylakoid membrane.

The thylakoid targeting signal helps in guiding the enzyme to the thylakoid membrane, but it requires additional signals for successful translocation into the membrane.

Thus, the synthesis of polyphenol oxidase takes place in the cell's cytoplasm, and the thylakoid targeting signal is not sufficient for the enzyme to get to the thylakoid.

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List THREE (3) process involved in the central dogma of molecular biology. [3 Marks]

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The central dogma of molecular biology refers to the fundamental principles that describe the relationship between DNA, RNA, and protein.

There are three main processes involved in the central dogma,

and they are DNA replication,

transcription,

and translation.

This process takes place in the nucleus of the cell,

where the two strands of the DNA molecule unwind and separate.

The enzyme DNA polymerase then attaches to each strand and adds nucleotides to create new strands.

This process results in the formation of two identical copies of the DNA molecule.

Transcription is the process by which the genetic information encoded in DNA is used to create a complementary RNA molecule.

This process takes place in the nucleus of the cell,

where an enzyme called RNA polymerase attaches to the DNA molecule and begins to read the sequence of nucleotides.

The RNA polymerase then creates a complementary RNA strand by adding nucleotides one at a time.

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Can our destructive behavior toward nature be explained by the
fact that we are mentally ill - that is, we as a society or
culture, not we as individuals?

Answers

The argument that our destructive behavior toward nature can be explained by the fact that we are mentally ill - that is, we as a society or culture, not we as individuals, is not entirely correct.

This is because mental illness cannot be used to explain such behavior towards nature, but rather, human attitudes, values, and beliefs regarding nature.

Destructive behavior toward nature refers to acts that cause harm, damage, or destruction to the natural environment. Such behaviors may include pollution, deforestation, overfishing, and the exploitation of natural resources without proper conservation measures in place.

Can our destructive behavior toward nature be explained by the fact that we are mentally ill - that is, we as a society or culture, not we as individuals?Destructive behavior towards nature can be traced to various human attitudes, values, and beliefs regarding nature. Such attitudes may be cultural, historical, or religious.

For instance, certain cultures may have a belief that nature is a resource to be exploited for their benefit. In contrast, other cultures may view nature as sacred, and, therefore, require respect and protection.

Mental illness is not a sufficient explanation for our destructive behavior towards nature. Instead, the solution lies in promoting a better understanding of the importance of nature and adopting policies and practices that protect the environment while still meeting human needs.

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The initial entrance of carbon into the web of life is through:
a. O chemosynthesis
b. aerobic respiration
c. O photosynthesis
d. anaerobic respiration

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The initial entrance of carbon into the web of life is through is  photosynthesis.

Plants and other living things employ a process called photosynthesis to transform light energy into chemical energy that may then be released through cellular respiration to power the organism's activities. Carbohydrate molecules like sugars and starches, which are created from carbon dioxide and water, contain some of this chemical energy. Photoautotrophs are creatures that perform photosynthesis, including most plants, algae, and cyanobacteria. The majority of the energy required for life on Earth is produced and maintained through photosynthesis, which is also substantially responsible for creating and maintaining the oxygen concentration of the atmosphere.

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Determine the index n Given that At State 1, T = 40C = 313 K and P = 2 bar At State 2, T = 80C = 353 K and P = 5 bar T = ( P ) 313 ( 2 ) --- --- ----- = -- n = ? T P 353 5 1. If you refine the microstructure of a dielectric so that the average grain size goesfrom 1 x 10-6 m to 10x10-9 m what do you expect will happen with respect to its dielectricproperties?a. The ionic polarization will become unityb. The interfacial polarization will decreasec. The electronic polarization will decreased. The interfacial polarization will increasee. a and bf. a and c2. Electronic polarizability scales with the number of electrons per atoms or Za. Trueb. False3. As the frequency of operation increases a magnetic ceramic materialsa. Permeability approaches unityb. Permittivity approaches unityc. a and bd. Permeability approaches infinitye. Permittivity approaches infinityf. d and f How does the choroid in the cow eye differ from the choroid in the human eye? Draw the elution curve (A at 280 nm vs elution volume) obtained by passing a mixture of following proteins through the column G-100(range 4,000-150,000) Determine the approximate molecular weight of an unknown protein with and elution volume of 16 ml Myoglobin(MW:16,000 D, elution volume:40 ml) Serum albumin (MW 68,000 D, elution volume: 30 ml) subunit (mW: 98,000 D, elution volume: 15 ml) Myosin submit (MW: 120,000 D, elution Volume: 10ml) 10. Why is urinalyis a useful diagnotic tool foe Mecalifytng certain alsemen asd infection? 11. Why is it useful to determine the specific erwity of a urine ample? QUESTIONS 12 AND 13: ldentify a poss Explain why it is important to validate the periodicity ofgrowth ring formation in otoliths before age and growth can bemodeled? A doctor injects a patient with what the doctor thinks is an isotonic saline solution. The patient experiences an abrupt drop of blood pressure and their kidneys start to fail. These are common symptoms of dehydration. What do you think may have caused the sudden dehydration of this patient? Select one: a. The doctor must have injected the patient with a hypertonic solution (higher concentration of salts than in the individual's cells). b. The doctor must have injected the patient with a hypotonic solution (lower concentration of salts than in the individual's cells).. c. The symptoms of the patient were unrelated to the solution injected by the doctor, more research is necessary.