Answer:
D. blinking ofeyea
Explanation:
not really sure
A force of 500N Is applied to a steel wire of goss_sectional area 0.2m2 the tensele stress is a. 2.5x10 1nm-2 b. 1 0x102nm-2 c. 2.5x103nw-3 d. 1.0x103nm-2
Answer:
the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
Explanation:
Given;
applied force, F = 5000 N
cross sectional area of the steel wire, A = 0.2 m²
The tensile stress of the steel wire, is calculated as;
[tex]\sigma = \frac{F}{A} \\\\\sigma = \frac{500}{0.2} \\\\\sigma = 2500 \ N/m^2\\\\\sigma = 2.5 \ \times \ 10^3 \ Nm^{-2}[/tex]
Therefore, the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?
Answer:
The net charge on each sphere is -1.5 q
Explanation:
Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]
The net charge on each sphere, Q = -1.5 q.
The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
What is charge?Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]
Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
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Sound waves are a type of compression wave. In a compression wave, we have areas of compaction and also areas of rarefaction. In
the areas of compression, particles are pushed together and in areas of rarefaction, particle spread apart. Sound waves are different
from light waves in several ways and one is in the type of wave. Light waves are transverse waves that have crests or peaks and
troughs or dips. Which model best shows us a light or transverse wave with very high crests and very low troughs?
Answer: C
Explanation:
The model which represents best of transverse wave with very high crests and low troughs is the third graph. Hence, option C is correct.
What is Sound?Sound is a physical perturbation from an equilibrium position that travels through an elastic medium of material. It is also possible to define sound solely subjectively, as that which is regarded by the ear, but this definition lacks clarity and is overly constrictive because it is useful to discuss sounds that are produced by devices other than the human ear, such as dog whistles and sonar hardware, which cannot be done here by the auditory system.
The characteristics of sound waves should be examined first in any study of sound. Transverse and longitudinal waves are the two fundamental forms of waves, and they differ by the direction wherein they move.
The first graph is uniform trough and crest, but the third one has higher crest but lower trough.
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A surfer paddles to where the waves are sinusoidal with crests 14 m apart. He bobs a vertical distance 3.6 m from trough to crest, which takes 1.5 s. Find the wave speed, & describe the wave.
Answer:
v = 9.34 m/s
Explanation:
Given that,
The distance between crests, [tex]\lambda=14\ m[/tex]
The vertical distance from trough to crest = 3.6 m
Time taken, t = 1.5 s
The amplitude of wave = vertical distance from trough to crest /2
= 3.6/2
= 1.8 m
The speed of the wave is given by :
[tex]v=f\times \lambda\\\\=\dfrac{\lambda}{T}\\\\=\dfrac{14}{1.5}\\\\=9.34\ m/s[/tex]
So, the speed of the wave is 9.34 m/s.
What is the mathematical relationship between height, mass, gravity, and gravitational potential energy?
Sometimes, a crackling sound is heard while taking off a sweater during winters. Explain
Answer:
it is somewhat frozen
Explanation:
Which process causes the transfer of energy by air currents within the Earth's atmosphere?
Answer:
Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface
An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?
Answer:
i. 15.6 m/s
ii. I = 1.44 KNs
Explanation:
The impulse, I, on a body is the product of force applied on it and the time it acts.
i.e I = F x t
Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.
i. mass, m, of the player = 92 kg
initial velocity of the player, u = 9.4 m/s
final velocity of the player, v = 6.2 m/s
Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.
So that,
change in velocity of the player = final velocity - initial velocity
= 6.2 - (-9.4)
= 6.2 + 9.4
= 15.6 m/s
change in velocity of the player is 15.6 m/s
ii. Impulse, I = m(v - u)
= 92 x 15.6
= 1435.2
Impulse on the player is 1.44 KNs.
If the small piston has an area of .004 square
meters and Bob pushes down on it with 225 N of
force, how much weight can he lift on the car
side of the system, if that piston's area is 3.5
square meters?
F₂ = 1.723 x 10⁸ N
Further explanationGiven
Area of small piston : 0.004 m²
Area of large piston : 3.5 m²
Force 225 N
Required
Force applied
Solution
Pascal Law :
F₁/A₁=F₂/A₂
225/0.004 m² = F₂/3.5² m²
F₂ = 1.723 x 10⁸ N
John slides down a hill at a 4 m height initially at rest. If all energy is conserved and friction is excluded, what is John's velocity at the bottom of the ramp?
The velocity at the bottom : v = 8.85 m/s
Further explanationGiven
height of the hill = 4 m
Required
The velocity at the bottom
Solution
The law of conservation energy :
ME₁=ME₂
(PE+KE)₁ = (PE+KE)₂
initially at rest⇒vo=0⇒KE₁=0
At the bottom⇒h=0⇒PE₂=0
So the equation becomes :
PE₁=KE₂
mgh=1/2.mv²
gh = 1/2v²
[tex]\tt v=\sqrt{2gh}[/tex]
v = √2x9.8x4
v = 8.85 m/s
A 1600 kg car with the brakes applied comes to a stop in 4.20 seconds. During these 4.20 seconds the force of friction slowing down the car is 3900 N. What is the change in momentum of the car?
Answer:
The change in momentum of the car is 16380.8 kg.m/s
Explanation:
Given;
mass of the car, m = 1600 kg
time of motion, t = 4.20s
force of friction on the car, F = 3900 N
final velocity of the car after the brakes were applied, v = 0
The initial velocity of the car during the motion is calculated as;
[tex]F = ma = \frac{mu}{t} \\\\mu = Ft\\\\u = \frac{Ft}{m} \\\\u = \frac{3900\times 4.2}{1600} \\\\u = 10.238 \ m/s[/tex]
The change in momentum of the car is calculated as;
ΔP = mu
ΔP = 1600 x 10.238
ΔP = 16380.8 kg.m/s
2. What is the y-component of a 95.3 N force that is exerted at 57.1
degree to the horizontal, *
Answer: 80N
Explanation:
The y-component would be the magnitude of the force multiplied by the sine of the angle.
[tex]95.3*\sin(57.1)=80N[/tex]
The y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
What is Force?Force is defined as an external agent which is capable of changing the state of rest or motion of a body with magnitude and direction. The direction towards which the force is applied is known as the direction of the force, and the point of application of the force is where the force is applied.
It can be expressed as:
F = m a
Where, F= Force
m= mass of the object
a= acceleration
In the given example, the force acts as vector which is broken down into the components. Given the angle θ along the horizontal axis,
so, For x component [tex]F_x[/tex] = Fcosθ
For y component [tex]F_y[/tex] = F sinθ
Given, F= 95.3 N ; θ= 57.1 °
[tex]F_y = (95.3) * (sin 57.1)\\ F_y= 80.0N[/tex]
Thus, the y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
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If a man with
with long-sighted eye want to
a' text book, what shoðld be the distance between
book and the lens? Give reason
A student is preparing to take a bath when she realizes the hot water tap in the bathroom is not working. The student goes to the kitchen and prepares 10 of 100°C water to mix with 10 L of 10°C water.
Answer:
(10 L)(100° C) + (90 L)(10°) = (100 L)T
1,000 + 900 = 100T
1,900 = 100T
100T = 1,900
T = 1,900/100
Explanation:
You weigh 580 N on Earth. If you were to go to Mars, where its gravitational pull is 3 . 7 11 m /s 2 , what would you weigh? (Hint: gravity on Earth is 9.8 m /s 2 .
Answer:
59.18 kg
Explanation:
use f=ma
f= 580 N
a = 9.8 m/s 2
weigh(m) doesn't change only force(F) changes
Answer: 219.6N
Explanation:
Find the mass of this person by dividing his weight by the accelleration. Remember, F=ma
580 = m*9.8
m = 59.18kg
Then multiply the mass by the new gravitational acceleration on Mars.
59.18*3.711 = 219.6N
Complete play the table by writing the location orientation size and type of image formed by the lenses below.
Please help me guyss!! :(
Answ
Explanation:
HOPE IT HELPS..
The image formed by the location of object is beyond 2F the image by convex lenses is between F and 2F and is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real.
What is a convex lens ?A convex lens is a type of lens that is projected outwards and shows the real image of an object. Whereas a concave lens is curved inwards and shows virtual image of objects.
The image formed at by the location of convex lenses beyond 2F is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real. If the lens is placed between F and 2F the image formed is beyond 2F and it will be inverted, enlarged and real.
If the object is at F , no image will be formed. If it at between F and the lens, then the image forms beyond 2 F which is upright, enlarged and virtual.
The object be at any position with respect to the focal length of lens, the image formed by a concave lens is between F and the lens and upright, small and virtual.
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5.Which graph above shows an object's acceleration? 1pt
6. Why did you choose that graph in question above (explain why)? 1pt
The first charge is pulling on the second. Is the second pulling on the first? Explain your reasoning
Answer:
law of action and reaction.
Explanation:
In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.
In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.
Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body
An electric force is an attractive or repulsive interaction. Newton's laws of motion define how it affects things, just like any other force. Yes, the second pulling on the first.
How does Newton's third law explain in terms of electricity?An electric force is an attractive or repulsive interaction between any two charged things. Newton's laws of motion define how it affects things, just like any other force.
The motion of objects under the influence of such a force or combination of forces is studied using Newton's laws.
The analysis generally starts with the creation of a free-body diagram in which the kind and direction of the various forces are represented by vector arrows.
Newton's laws of motion define how it affects things, just like any other force. Hence Yes, the second pulling on the first.
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Two free charges +q and +4q are a distance l apart. A third charge is placed so that the entire system is in equilibrium. Find the location, magnitude and sign of the third charge.
Answer:
the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position x= l/3
Explanation:
The forces in this system are given by Coulomb's law
F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]
As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .
Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge
Let's find the location of charge 3 so that it is in balance
∑ F = F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
we seek every force
F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]
F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]
the distances are
x₁₃ = x-0 = x
x₂₃ = l -x
we substitute
k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}
we solve
(l-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
l² - 2lx + x² = \frac{4q}{q} x²
3x² + 2l x - l² = 0
we solve the quadratic equation
x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)
x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6
x₁ = -l
x₂ = l / 3
as charge 3 must be between the two charges the correct answer is
x = l / 3
with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.
now let's analyze the force on the other charges
charge 1 so that it is in balance
∑F = F₁₃ - F₁₂ = 0
F₁₃ = F₁₂
[tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]
l² q₃ = q₂ (l/3)²
q₃ = q₂ / 9
q₃ = 4q / 9
q₃ = [tex]\frac{4}{9} q[/tex]
in summary the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q
in the position x= l/3
a car takes 4 hours to cover a distance if it takes at a speed of 40mph. what should be it's speed to cover the same distance in 1.5 hours
Answer:
Speed = 106.67mph
Explanation:
Let the first motion be A.
Given the following data;
Speed A = 40mph
Time A = 4 hours
To find the distance covered in A;
Distance = speed * time
Distance = 40 * 4
Distance = 160 miles.
To find the speed required to cover the above distance in 1.5 hours;
Speed = distance/time
Speed = 160/1.5
Speed = 106.67mph
If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain using Newton's second law
Answer:
The bike would have more acceleration
Explanation:
Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.
Eg.
F=50N
Motorbike M=200kg
F=ma
50=200 x a
50/200=a
0.25m/s/s =a
Bike M=35kg
F=ma
50=35 x a
50/35= a
1.43m/s/s=a
Answer:
the bike
Explanation:
it has less mass than the motorcycle so so it would have more acceleration
Part C
How many combined bits of storage are there on the two tablets?
Answer:
IVE BEEN TRYNA FIND THE ANSWER FOR THE PAST HOUR T-T
Explanation:
Answer:
3.2 x10^11 bits of storage
Explanation:
Need help ASAP
Thanks + BRAINLIST only for correct answer
1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves
2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above
3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna
Answer:
Explanation:
1.electric
2.radio wave
3.broadcast
Hope it helped you.
A force of 20N acted on a ball thereby imparting an impulse of 70N's to the ball. For how long did the force act on the ball?
Answer:3.5 seconds
Explanation:
Suman with a mass of 45kg climbs in 3m heigh ladder in 10 seconds. Calculate her power. Plz help me
Answer:
work done=fdcosø
f=mg=450N
d=+3m
ø=180
450×3×cos(180°) power=work done/
time taken
1350×-1 p=135watts
Need help with physics.
Question: A 65 kg child riding a Ferris wheel has a tangential speed of 9.5 m/s. Find the magnitude of the centripetal force on the child if the distance from the child to the axis of the wheel is 20 m.
The centripetal force : F = 293.3125 N
Further explanationGiven
mass = 65 kg
v = 9.5 m/s
r = 20 m
Required
the centripetal force
Solution
Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle
[tex]\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}[/tex]
F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
Input the value :
F = 65 x 9.5² / 20
F = 293.3125 N
Which of the following technologies would produce the most energy in light
waves?
A. Infrared sensor on a DVD player
B. Wireless communications transmitter
C. Microwave industrial drying equipment
D. Compact fluorescent lightbulb
Answer:
D. Compact fluorescent lightbulb
Explanation:
Compact fluorescent lightbulb
A compact fluorescent light bulb would produce the most energy in light
waves, therefore the correct option is D.
What is electromagnetic radiation?Electromagnetic radiation is a type of energy radiation produced by the propagation of electromagnetic waves that are produced for natural as well as anthropogenic reasons. This radiation does not need any kind of medium to propagate. The electromagnetic wave has components of light as well as heat in them.
Different kinds of electromagnetic radiation have varied levels of energy for example solar radiation is also a form of electromagnetic radiation and gamma radiation is electromagnetic radiation with very high energy.
Most energy in the form of the light wave is produced by the Compact fluorescent lightbulb, therefore the correct option is D.
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Suppose 2 C of positive charge is distributed evenly throughout a sphere of 1.27 cm radius. (a) What is the charge per unit volume for this situation? C/m3 (b) Is the sphere insulating or conducting? How do you know? The sphere is conducting. If it were insulating, none of the charge would be in the interior of the sphere; it would only be on the surface. The sphere is insulating. If it were conducting, none of the charge would be in the interior of the sphere; it would only be on the surface. The sphere is conducting. If it were insulating, all of the charge would be in the interior of the sphere; not on the surface. The sphere is insulating. If it were conducting, all of the charge would be in the interior of the sphere; not on the surface.
Answer:
a) ρ = 2.33 10⁵ C / m³, b) INSULATING
Explanation:
a) For this exercise we use the important concept of density
ρ = Q / V
The volume of a sphere is
V = 4/3 πr3
V = 4/3 π (1.27 10⁻²)³
V = 8.58 10⁻⁶ m³
let's calculate
ρ = 2 / 8.58 10⁻⁶
ρ = 2.33 10⁵ C / m³
b) in a conductor the charges are mobile, therefore due to electoral repulsion all the charges must concentrate on the surface.
In an insulator the charges are fixed, therefore they are distributed throughout the volume
Consequently the sphere must be INSULATING
The height of a transverse waves is known as its?
Answer:
amplitude
Explanation:
wave is a called the crest, and the low point is called the trough. For longitudinal waves, the compressions and rarefactions are analogous to the crests and troughs of transverse waves. The distance between successive crests or troughs is called the wavelength. The height of a wave is the amplitude.…
If 59.1 g of pure metal uses 890.9 j of energy to heat it from 26.1 c to 59.6 c, identify the metal
Answer: The metal is iron.
Explanation:
We have 59.1 grams of a given metal.
We need 890.9 joules of energy to heat the metal from 26.1°C to 59.6°C
First, we need to see the net increase in temperature, which is equal to the difference between the final temperature and the initial temperature.
ΔT = 59.6°C - 26.1°C = 33.5°C
Now we can find the specific heat, which is calculated as:
c = Ε/(ΔT*m)
Where:
E = energy given to the material = 890.9 J
m = mass of the material = 59.1 gr
ΔT = change in temperature = 33.5°C
Replacing these in the above equation we get:
c = 890.9 J/(33.5°C*59.1 gr) = 0.45 J/(gr*°C)
Now we need to look at a table of specific heats and see which metal has this specific heat.
We can see that iron is the best match, so we can assume that the metal is iron.