find the value of x
m<2= x + 122
Answer:
x= -14
Step-by-step explanation:
Please see attached picture for full solution.
If AB= X and x=4, then the transitive property states
Answer:
AB=4
Step-by-step explanation:
The transitive property states if A=B and B+C than A+C Next substitute
AB=x and x=4 so AB=4
Hope this helps, if it did, please give me brainliest, it helps me a lot. :)
Have a good day!
An airline charges the following baggage fees: $25 for the first bag and $35 for the second. Suppose 51% of passengers have no checked luggage, 33% have one piece of checked luggage and 16% have two pieces. We suppose a negligible portion of people check more than two bags.
Required:
a. Build a probability model, compute the average revenue per passenger, and compute the corresponding standard deviation.
b. About how much revenue should the airline expect for a flight of 120 passengers? With what standard deviation? Note any assumptions you make and if you think they are justified.
Answer:
The average revenue per passenger is about $13.85
μ = $13.85
The corresponding standard deviation is $14.51
σ = $14.51
The airline should expect revenue of $1,662 with a standard deviation of $14.51 for a flight of 120 passengers.
Expected revenue = $1,662 ± 14.51
Step-by-step explanation:
An airline charges the following baggage fees:
$25 for the first bag and $35 for the second
Suppose 51% of passengers have no checked luggage,
P(0) = 0.51
33% have one piece of checked luggage and 16% have two pieces.
P(1) = 0.33
P(2) = 0.16
a. Build a probability model, compute the average revenue per passenger, and compute the corresponding standard deviation.
The average revenue per passenger is given by
μ = 0×P(0) + 25×P(1) + 35×P(2)
μ = 0×0.51 + 25×0.33 + 35×0.16
μ = 0 + 8.25 + 5.6
μ = $13.85
Therefore, the average revenue per passenger is about $13.85
The corresponding standard deviation is given by
σ = √σ²
Where σ² is the variance and is given by
σ² = (0 - 13.85)²×0.51 + (25 - 13.85)²×0.33 + (35 - 13.85)²×0.16
σ² = 97.83 + 41.03 + 71.57
σ² = 210.43
So,
σ = √210.43
σ = $14.51
Therefore, the corresponding standard deviation is $14.51
b. About how much revenue should the airline expect for a flight of 120 passengers? With what standard deviation?
For 120 passengers,
Expected revenue = 120×$13.85
Expected revenue = $1,662 ± 14.51
Therefore, the airline should expect revenue of $1,662 with a standard deviation of $14.51 for a flight of 120 passengers.
Product A is 8oz bottle of cough medication that sells for 1.36 Product B is a 16 oz bottle of cough medication that cost 3.20 which product has the lower unit
Answer:
Product A is the cheapest unit price.
Step-by-step explanation:
Since we have given that
Weight of a Product A = 8 oz
Cost at which it is sold = $1.36
Cost per unit for Product A will be
1.38/8= $0.17
Weight of a Product B = 16 oz
Cost at which it is sold = $3.20
Cost per unit for Product B will be
So, we can see that the unit price of "Product A" is lower than the unit price of product B .
Hence, Product A has the cheapest unit price.
11. If 4 < x < 14, what is the range for -x - 4?
Answer:
-18 < -x-4 < -8
Step-by-step explanation:
We start with the initial range as:
4 < x < 14
we multiplicate the inequation by -1, as:
-4 > -x > -14
if we multiply by a negative number, we need to change the symbols < to >.
Then, we sum the number -4, as:
-4-4> -x-4 > -14-4
-8 > -x-4 > -18
Finally, the range for -x-4 is:
-18 < -x-4 < -8
A school district performed a study to find the main causes leading to its students dropping out of school. Thirty cases were analyzed, and a primary cause was assigned to each case. The causes included unexcused absences (U), illness (I), family problems (F), and other causes (O). The results for the thirty cases are listed below:
U U U I F O O U I F F O U I I F I I O U I F F U U I I O F U
Required:
Construct a table summarizing the frequency distribution of the primary causes leading to student dropout.
Answer:
See below for the table.
Step-by-step explanation:
The results for the thirty cases are listed below:
U U U I F O O U I F F O U I I F I I O U I F F U U I I O F U
The table summarizing the frequency distribution of the primary causes leading to student dropout is:
[tex]\left|\begin{array}{c|c}$Cause&$Frequency\\----------&----\\\\$Unexcused absences (U)&9\\$Illness (I)&9\\$Family problems (F)&7\\$Other causes (O)&5\\-----------&---\\$Total&30\end{array}\right|[/tex]
Tanya can wash a car and vacuum its interior in 2 hours. Pat needs 5 hours to do this same job. If Tanya and Pat work together, how many hours will it take them to clean a car??
Answer:
It will take 1.43 hours for them to clean the car.
Step-by-step explanation:
The together rate is the sum of each separate rate.
In this problem:
Together rate: 1/x
Tanya's rate: 1/2
Pat's rate: 1/5
Together rate = Tanya's rate + Pat's rate
[tex]\frac{1}{x} = \frac{1}{2} + \frac{1}{5}[/tex]
[tex]\frac{1}{x} = \frac{5 + 2}{10}[/tex]
[tex]\frac{1}{x} = \frac{7}{10}[/tex]
[tex]7x = 10[/tex]
[tex]x = \frac{10}{7}[/tex]
[tex]x = 1.43[/tex]
It will take 1.43 hours for them to clean the car.
find the Pythagorean triplets of 5
Answer:
The Pythagorean Triplet that has 5 is 3-4-5
Step-by-step explanation:
We can prove this using Pythagorean Theorem: a² + b² = c²
3² + 4² = 5²
9 + 16 = 25
25 = 25
The sports bar owner runs a regression to test whether there is a relationship between Red Sox away games and daily revenue. Which of the following statements about the regression output is true?A. The average daily revenue for days when the Red Sox do not play away is $1,768.32.B. The average daily revenue for days when the Red Sox play away is $1,768.32.C. The average daily revenue for days when the Red Sox play away is $2,264.57.D. The average daily revenue for days when the Red Sox do not play away is $1,272.07.E. On average, the bar’s revenue is $496.25 higher on days when the Red Sox play away than on days when they do not.
SUMMARY OUTPUT
Regression Statistics
Multiple R 0.4746
R Square 0.2252
Adusted R square 0.2091
Standard Error 466.32
Observations 50
ANOVA
Significance F MS df 0.0005 13.95 3.03E 06 3.03E+06 Regression 1.04E+07 2.17E+05 48 Residual 135E+07 49 Total Lower 95% Upper 95% tStot Standard Error P-vatue Coefficients 1968.21 17.79 1,568.42 99 42 0.0000 1768.32 Intercept Red Sox away game 763.38 00005 3.74 229.13 132.85 (1-yes, 0-no) 496.25 The average daily revenue for days when the Red Sox do not play away is $1,768.32
Answer:
Options A, C and D are true.
- The average daily revenue for days when the Red Sox do not play away is $1,768.32.
- The average daily revenue for days when the Red Sox play away is $2,264.57.
- On average, the bar’s revenue is $496.25 higher on days when the Red Sox play away than on days when they do not.
Step-by-step explanation:
The complete Question is presented in the attached image to this solution.
Analyzing the options at a time
A) The average daily revenue for days when the Red Sox do not play away is $1,768.32.
This option is true as 1768.32 is the intercept which is the average daily revenue when the Red Sox=0, that is, 0=no, when red sox do not play away.
B) The average daily revenue for days when the Red Sox play away is $1,768.32.
This is false because when the Red Sox play away, the value is 1 and the average revenue = 1768.32 + 496.25 = $2,264.57
C) The average daily revenue for days when the Red Sox play away is $2,264.57.
This is true. I just gave the explanation under option B.
D) The average daily revenue for days when the Red Sox do not play away is $1,272.07.
This is false. The explanation is under option A.
E) On average, the bar’s revenue is $496.25 higher on days when the Red Sox play away than on days when they do not.
This is true. It is evident from the table that the 0 and 1 coefficient is 496.25. This expresses the difference in average daily revenue when the Red Sox games are played away and when they are not.
Hope this Helps!!!
I will Give brainliest to who ever can show me how to solve this killer!!!!!!! Using Descartes Rule and the rational zeros of polynomial equation, find the root (positive, negative and imaginary) of x^5-2x^4+x^3+x^2-2x+1=0
see if other people has already answered this question
Answer:
-1
1
1/2(1±i√3)
Step-by-step explanation:
x^5-2x^4+x^3+x^2-2x+1=0x^3(x^2-2x+1)+(x^2-2x+1)=0(x^3+1)(x-1)^2=0(x+1)(x^2-x+1)(x-1)^2=01. x+1=0 ⇒ x= -1
2. x-1= 0 ⇒ x= 1
3. x^2-x+1=0
x^2- 2*1/2x+1/4= -3/4(x-1/2)^2= -3/4x-1/2= ±√-3/4 ⇒ x-1/2=±i√3/2 ⇒ x= 1/2 ± i√3/2= 1/2(1± i√3)9. A line passes through (2, –1) and (8, 4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in standard form using integers.
Answer:
Step-by-step explanation:
(4+1)/(8-2)= 5/6
y + 1 = 5/6(x - 2)
y + 1 = 5/6x - 5/3
y + 3/3 = 5/6x - 5/3
y = 5/6x - 8/3
6(y = 5/6x - 8/3)
6y = 5x - 16
-5x + 6y = -16
Need help solving for x
Answer:
9.2
Step-by-step explanation:
The given triangle is a right angled triangle. To solve for any of the side length of such triangle, apply the trigonometry ratio formula which can easily be remembered as SOHCAHTOA.
SOH is Sin θ = opposite/hypothenuse,
CAH is Cos θ = Adjacent/hypotenuse
TOA is Tan θ = Opposite/adjacent
Thus, in the right triangle given, we have:
θ = 38°
Opposite side to the given angle = x
Hypotenuse = 15
We're going to use, sin θ = opposite/hypotenuse
Sin(38) = x/15
Multiply both sides by 15 to solve for x
15*sin(38) = x
15*0.616 = x
9.24 = x
x ≈ 9.2 (to nearest tenth)
A student's course grade is based on one midterm that counts as 1010% of his final grade, one class project that counts as 1515% of his final grade, a set of homework assignments that counts as 4040% of his final grade, and a final exam that counts as 3535% of his final grade. His midterm score is 6767, his project score is 8888, his homework score is 9191, and his final exam score is 7272. What is his overall final score? What letter grade did he earn (A, B, C, D, or F)? Assume that a mean of 90 or above is an A, a mean of at least 80 but less than 90 is a B, and so on.
Answer:
His overall final score is 81.5
He earned a B
Step-by-step explanation:
To find his overall grade, we multiply each of his grades by it's weight.
Grades:
67 on the midterm, which counts for 10% = 0.1
88 on the project, which counts for 15% = 0.15
91 on homework assignements, which counts for 40% = 0.4
72 on the final exam, which counts for 35% = 0.35.
What is his overall final score?
67*0.1 + 88*0.15 + 91*0.4 + 72*0.35 = 81.5
His overall final score is 81.5
At least 80 and less than 90 has a letter grade of B. 81.5 is in this range. So he earned a B
Create a bucket by rotating around the y axis the curve y=5 ln(x-2) from y=0 to y=4. If this bucket contains a liquid with density 760 kg/m3 filled to a height of 3 meters, find the work required to pump the liquid out of this bucket (over the top edge). Use 9.8 m/s2 for gravity.
Answer:
The work will be "1909212.015 J". The further explanation is given below.
Step-by-step explanation:
The given values are:
Liquid's density
= 760 kg/m³
Height
= 3 meters
Gravity
g = 3.8 m/s²
Value of y is:
y = 5 log (x-2)
y = 0
y = 4
As we know,
⇒ [tex]\Delta V=\pi r^2 \Delta y[/tex]
⇒ [tex]y =5log(x-2)[/tex]
⇒ [tex]\frac{y}{5} =log (x-2)[/tex]
⇒ [tex]e^{\frac{y}{5}}=(x-2)[/tex]
⇒ [tex]x=e^{\frac{y}{5}}+2[/tex]
Now,
[tex]\Delta F=ma[/tex]
[tex]=760 \pi (e^{\frac{y}{5}}+2)^2(9.8)\Delta y[/tex]
So that,
⇒ [tex]\Delta W = \Delta F.distance[/tex]
[tex]=\Delta F(4-y)[/tex]
The required work will be:
⇒ [tex]W=760\times 9.8 \pi \int_{3}^{0}(e^{\frac{y}{5}}+2)^2 (\Delta-y)dy[/tex]
[tex]=760\times 9.8 \pi[{-20(y-9)^{e^{\frac{y}{5}}}-2(y-8)y}][/tex]
[tex]=760\times 9.8 \pi[81.455][/tex]
[tex]=1909212.015 \ J[/tex]
The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.45 ounces and a standard deviation of 0.30 ounce. Each can holds a maximum of 12.75 ounces of soda. Every can that has more than 12.75 ounces of soda poured into it causes a spill and the can must go through a special cleaning process before it can be sold. What is the probability that a randomly selected can will need to go through this process?
Answer:
0.1587
Step-by-step explanation:
According to the situation, the solution and the data provided is as follows
mean = 12.45 ounces
Standard deviation = 0.30 ounces
maximum = 12.75 ounces
More than ounces of soda = 12.75
Based on the above information, the probability is
[tex]Z=\frac{X-\mu }{\sigma } \\\\Z=\frac{12.75-12.45 }{0.30 } \\\\\Z=\frac{0.30 }{0.30 } \\\\Z= 1 \\\\P(X> 12.75)=1-P(X< 12.75) \\\\\P(X> 12.75)=1-P(Z< 1) \\\\[/tex]
As we know that
P(Z<1) = 0.8413
So,
P (X > 12.75) = 1 - 0.8413
= 0.1587
Clara did not want to tell Carl how old she was. All she said was that every year on her birthday, her Mom put as many coins in her money box as how old she turned that day. Carl roughly estimated the number of coins in the box as not less than 110 but not more than 130 coins. How old is Clara?
The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disease/smoker 0.1, No Lung Disease/Smoker 0.17, Lung Disease/Nonsmoker 0.03, No Lung Disease/Nonsmoker 0.7. One 60-to-65 year old man is selected at random. What is the probability of the following event: He has lung disease given that he does not smoke?
Answer:
4.11% probability that he has lung disease given that he does not smoke
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Does not smoke
Event B: Lung disease
Lung Disease/Nonsmoker 0.03
This means that [tex]P(A \cap B) = 0.03[/tex]
Lung Disease/Nonsmoker 0.03
No Lung Disease/Nonsmoker 0.7
This means that [tex]P(A) = 0.03 + 0.7 = 0.73[/tex]
What is the probability of the following event: He has lung disease given that he does not smoke?
[tex]P(B|A) = \frac{0.03}{0.73} = 0.0411[/tex]
4.11% probability that he has lung disease given that he does not smoke
Probabilities are used to determine the chances of an event.
The probability that he has lung disease given that he does not smoke is 0.231
The required probability is calculated as:
[tex]\mathbf{P = \frac{P(Lung\ Disease\ and\ Non\ Smoker)}{P(Lung\ Disease)}}[/tex]
From the question, we have:
[tex]\mathbf{P(Lung\ Disease\ and\ Non\ Smoker) = 0.03}[/tex]
[tex]\mathbf{P(Lung\ Disease) = P(Has Lung Disease/smoker) + P(Lung Disease/Nonsmoker)}[/tex]
[tex]\mathbf{P(Lung\ Disease) = 0.1 + 0.03}[/tex]
[tex]\mathbf{P(Lung\ Disease) = 0.13}[/tex]
So, we have:
[tex]\mathbf{P = \frac{P(Lung\ Disease\ and\ Non\ Smoker)}{P(Lung\ Disease)}}[/tex]
[tex]\mathbf{P = \frac{0.03}{0.13}}[/tex]
[tex]\mathbf{P = 0.231}[/tex]
Hence, the probability that he has lung disease given that he does not smoke is 0.231
Read more about probabilities at:
https://brainly.com/question/11234923
Mia had $22 . Then she started to receive $4 a week as an allowance. She plans to save all of her money for a bicycle and draws a graph of her planned savings. Mia lets x represent the number of weeks she has received her allowance, and y represent her total amount of money. Which of the following ordered pairs is on Mia's graph? ANSWER CHOICES: (2,44) (5,42) (6,24) (1,22)
Answer: (5, 42)
Step-by-step explanation:
22 + 4x= 42
if we test the options we will see this is the only one that works
42 - 22 = 20
4x = 20
x= 5
which is equal to X the number of weeks they have gotten the allowance.
Referring to a line segment with endpoints A and B, what does it mean to refer to AB with no line over it?
Answer: length of AB
Step-by-step explanation:
[tex]\overline{AB}[/tex] represents the line segment from point A to point B
[tex]\overrightarrow{AB}[/tex] represents ray from point A to infinity through point B
AB represents the length of the line segment from point A to point B.
16. How much money will I need to have at retirement so I can withdraw $60,000 a year for 20 years from an account earning 8% compounded annually? a. How much do you need in your account at the beginning b. How much total money will you pull out of the account? c. How much of that money is interest?
Answer:
starting balance: $636,215.95total withdrawals: $1,200,000interest withdrawn: $563,784.05Step-by-step explanation:
a) If we assume the annual withdrawals are at the beginning of the year, we can use the formula for an annuity due to compute the necessary savings.
The principal P that must be invested at rate r for n annual withdrawals of amount A is ...
P = A(1+r)(1 -(1 +r)^-n)/r
P = $60,000(1.08)(1 -1.08^-20)/0.08 = $636,215.95
__
b) 20 withdrawals of $60,000 each total ...
20×$60,000 = $1,200,000
__
c) The excess over the amount deposited is interest:
$1,200,000 -636,215.95 = $563,784.05
Find the slope on the graph. Write your answer as a fraction or a whole number, not a mixed number or decimal.
Answer:
Step-by-step explanation:
(-2,2) (2,-4)
(-4-2)/(2+2)= -6/4= -3/2 is the slope of the graph
Suppose that the lenghth between 911 calls to a ceration police stattion is exponentially distribution with an average of 5 minutes between calls. What is the probability that they receive 10 calls in the next hours?
Answer:
0.1048
Step-by-step explanation:
The computation of probability that they receive 10 calls in the next hours is shown below:-
Average which is given in the question 5 minutes between calls = 5/60 calls an hour so it becomes 12 calls per hour
So,
P(X = 10)
[tex]= \frac{e^{-12}12^{10}}{10!}[/tex]
= 0.1048
Therefore for computing the probability that they receive 10 calls in the next hours we simply applied the above formula.
The shape in the figure is constructed from several identical squares. If the side of each square is 1 unit, what is the area and the perimeter of the shape?
Answer:
Area: 7 units²
Perimeter: 14 units
Step-by-step explanation:
Area of each square:
1 unit × 1 unit = 1 unit²
There are 7 squares:
1 unit² × 7 (squares) = 7 units²
The area of the shape is 7 units².
The perimeter of the shape is the length of the outer sides.
1 + 1 + 1 + 1/2 + 1/2 + 1 + 1 + 1/2 + 1 + 1/2 + 1 + 1 + 1 + 1 + 1 + 1 = 14 units
7.22. (a) A fair coin is tossed 100 times. Estimate the probability that the number of heads is between 40 and 60. Estimate the probability that the number is between 50 and 55.
Answer:
the probability that the number of heads is between 40 and 60 is 0.9535
the probability that the number of heads is between 50 and 55 is 0.3557
Step-by-step explanation:
From the given information:
A fair coin is tossed 100 times.
Let consider n to be the number of time the coin is tossed, So n = 100 times
In a fair toss of a coin; the probability of getting a head P(Head) = 1/2 = 0.5
If we assume X to be the random variable which follows a binomial distribution of n and p; therefore , the mean and the standard deviation can be calculated as follows:
Mean μ = n × p
Mean μ = 100 × 1/2
Mean μ = 100 × 0.5
Mean μ = 50
Standard deviation σ = [tex]\sqrt{n \times p \times (1-p)}[/tex]
Standard deviation σ = [tex]\sqrt{100 \times 0.5 \times (1-0.5)}[/tex]
Standard deviation σ = [tex]\sqrt{50 \times (0.5)}[/tex]
Standard deviation σ = [tex]\sqrt{25}[/tex]
Standard deviation σ = 5
Now, we've made it easier now to estimate the probability that the number of heads is between 40 and 60 and the probability that the number is between 50 and 55.
To start with the probability that the number of heads is between 40 and 60 ; we have:
P(40 < X < 60) = P(X < 60)- P(X < 40)
Applying the central limit theorem , for X is 40 which lies around 39.5 and 40.5 and X is 60 which is around 59.5 and 60.5 but the inequality signifies less than sign ;
Then
P(40 < X < 60) = P(X < 59.5) - P(X < 39.5)
[tex]P(40 < X < 60) = P( \dfrac{X - \mu}{\sigma}< \dfrac{59.5 - 50 }{5}) - P( \dfrac{X - \mu}{\sigma}< \dfrac{39.5 - 50 }{5})[/tex]
[tex]P(40 < X < 60) = P( Z < \dfrac{9.5 }{5}) - P( Z< \dfrac{-10.5 }{5})[/tex]
[tex]P(40 < X < 60) = P( Z <1.9}) - P( Z< -2.1)[/tex]
[tex]P(40 < X < 60) =0.9713 -0.0178[/tex]
[tex]P(40 < X < 60) =0.9535[/tex]
Therefore; the probability that the number of heads is between 40 and 60 is 0.9535
To estimate the probability that the number is between 50 and 55.
P(50 < X < 55) = P(X < 55)- P(X < 50)
Applying the central limit theorem , for X is 50 which lies around 49.5 and 50.5 and X is 55 which is around 54.5 and 55.5 but the inequality signifies less than sign ;
Then
P(50 < X < 55) = P(X < 54.5) - P(X < 49.5)
[tex]P(50 < X < 55) = P( \dfrac{X - \mu}{\sigma}< \dfrac{54.5 - 50 }{5}) - P( \dfrac{X - \mu}{\sigma}< \dfrac{49.5 - 50 }{5})[/tex]
[tex]P(50 < X < 55) = P( Z < \dfrac{4.5 }{5}) - P( Z< \dfrac{-0.5 }{5})[/tex]
[tex]P(50 < X < 55) = P( Z <0.9}) - P( Z< -0.1)[/tex]
[tex]P(50 < X < 55) =0.8159 -0.4602[/tex]
[tex]P(50 < X < 55) =0.3557[/tex]
Therefore; the probability that the number of heads is between 50 and 55 is 0.3557
What is the measure of x?
Answer:
x= 9 inches
Step-by-step explanation:
Hello
I can help you with this.
in this case, we have two similar triangles, let's see
Step 1
identify the rigth triangles.
1) the first triangle has these dimensions
hypotenuse( remember, the longest side)= unknown=H
adjacent side(the horizontal)=6 +x
opposite side(the vertical)=10
2) the second triangle has these dimensions
hypotenuse( remember, the longest side)= unknown=h
adjacent side(the horizontal)=6
opposite side(the vertical)=4.
As these triangles keep the same proportion and in both cases we know the length of the legs, we can establish a relationship
Step 2
establish a relationship
let's compare the opposite side and the adjacent side
triangle 1 (the bigger)
[tex]proportion= \frac{opposite\ side}{adjacent\ side}\\proportion= \frac{10}{6+x}[/tex]
Triangle 2
[tex]proportion= \frac{opposite\ side}{adjacent\ side}\\proportion= \frac{4}{6}\\proportion=\frac{2}{3}[/tex]
were the proportions are equal, so
[tex]\frac{10}{6+x}=\frac{2}{3}[/tex]
at this point, just isolate x to find its value
Step 3
isolate x
[tex]\frac{10}{6+x}=\frac{2}{3}\\multiply\ both\ sides\ by\ 3\\\frac{10*3}{6+x}=\frac{2*3}{3}\\\frac{30}{6+x} =2\\\\Multiply\ both\ sides\ by (6+x)\\\frac{30(6+X)}{6+x} =2(6+x)\\30=12+2x\\30-12=2x\\18=2x\\so\\x=\frac{18}{2} \\x=9[/tex]
remember the units of measure ( Inches)
x= 9 inches
I really hope it helps, have a nice day.
20x=60y What is x in terms of y? (Hope this isn't illogical)
Answer:
x=3y
Step-by-step explanation:
divide both sides by 20
20x = 60y
------ -------
20 20
x=3y
Answer:
x = 3y
Step-by-step explanation:
20x = 60y
Divide 20 into both sides.
20x/20 = 60y/20
1x = 6/2y
x = 3y
The volume of a cantaloupe is approximated by Upper V equals four thirds pi font size decreased by 5 r cubed . The radius is growing at the rate of 0.5 cm divided by week, at a time when the radius is 6.4 cm. How fast is the volume changing at that moment?
Answer:
308.67 cm ^ 3 / week
Step-by-step explanation:
A cantaloupe is approximately a sphere, therefore its approximate volume would be:
V = (4/3) * pi * (r ^ 3)
They tell us that dr / dt 0.5 cm / week and the radius is 6.4 cm
if we derive the formula from the volume we are left with:
dV / dt = (4/3) * pi * d / dr [(r ^ 3)]
dV / dt = (4/3) * pi * 3 * (r ^ 2) * dr / dt
dV / dt = 4 * pi * (r ^ 2) * dr / dt
we replace all the values and we are left with:
dV / dt = 4 * 3.14 * (6.4 ^ 2) * 0.6
dV / dt = 308.67
Therefore the volume is changing at a rate of 308.67 cm ^ 3 / week
There are 3 white counters and 1 black counters in a bag I take one of the counters at random what is the probability??
Answer:
0.25
Step-by-step explanation:
Out of the 4 counters only 1 is black so the probability is 1/4 or 0.25.
Answer:
0.25
Step-by-step explanation:
Since there are four marbles 100/4 =25 in this 100 is 1 thus the answer is 0.25
Crane Company reports the following for the month of June.
Date
Explanation
Units
Unit Cost
Total Cost
June 1 Inventory 150 $4 $600
12 Purchase 450 5 2,250
23 Purchase 400 6 2,400
30 Inventory 80
Assume a sale of 500 units occurred on June 15 for a selling price of $7 and a sale of 420 units on June 27 for $8.
Calculate cost of goods available for sale.
Calculate Moving-Average unit cost for June 1, 12, 15, 23 & 27. (Round answers to 3 decimal places, e.g. 2.525.)
Answer:
Crane CompanyJune Financial Reports
a) Cost of goods available for sale = $5,250
b) Moving-Average unit cost for:
i) June 1: = $5
ii) 12: = $4.75
iii) 15: = $4.75
iv) 23: = $5.75
v) 27: = $5.25
Step-by-step explanation:
a) Calculations:
Date Explanation Units Unit Cost Total Cost Moving Average Cost
June 1 Inventory 150 $4 $600 $4.000
12 Purchase 450 5 2,250 4.750
15 Sale 500 7 3,500 4.750
23 Purchase 400 6 2,400 5.750
27 Sale 420 8 3,360 5.250
30 Inventory 80
Cost of goods available for sale = Cost of Beginning Inventory + Cost of Purchases = $5,250 + ($600 + 2,250 + 2,400)
b) Moving-Average unit cost for:
i) June 1: Cost of goods available/Units of goods available = $5 ($600/150)
ii) 12: Cost of goods available/Units of goods available = $4.75 ($600 + 2,250/600)
iii) 15: Cost of goods available/Units of goods available = $4.75 ($475/100)
iv) 23: Cost of goods available/Units of goods available = $5.75 ($475 + 2,400)/500
v) 27: Cost of goods available/Units of goods available = $5.25 ($420/80)
Please please please do not answer if you are not 100% sure!
Answer:
B
Step-by-step explanation:
It can be figured out by using graph transformations.
When when subtracting directly next to x, it shifts the graph to the left while doing the opposite when adding. Since the graph is to the left, we know it has to be A or B since those are subtracting by 5
Outside of the absolute value, when subtracting, it makes the graph move down. That means we are looking for a -4 which is found in B