Answer:
true b, e
Explanation:
The expression that describes the diffraction of a grating is
d sin θ = m λ
where d is the separation between the slits, m is the order of the spectrum
let's analyze the different answers
a) False. The size (height) of the slits does not influence the resolution, the number of them per unit of length influences, the greater the number, the smaller the distance (d) this they
b) True. The spectrum is resolved on a screen, in the form that each wavelength corresponds to a fixed distance from the central maximum, for a given order
c) False. The exit slit selects a given wavelength, but does not deflect the beam from its path
d) False. The slit lets in light, but does not measure its intensity
e) True. For a continuous spectrum, the wavelength variation that passes through a slit is proportional to its width. For a discrete spectrum the width of the slit does not affect the wavelength
Stars fuse most of the hydrogen in the entire star before they die.
2 poir
True
False
(Electrical Physics)
The rate at which electrical energy is used may be measured in:
(a) joule second (b) watt second (c) watt (d) joule
Answer:
watt
Explanation:
Power is the rate at which energy is produced or consumed. Watts (W) measure rates of power over a period of time. A kilowatt (kW) is 1000 watts. A watt-hour (Wh) is a unit that measures the amount of electrical energy used over a period of time.
FREE BRAINIEST IF YOU ANSWER THIS
How long must a 400 W electrical engine work in order to produce 300 kJ of work?
The watt is a rate, similar to something like speed (miles per hour) and other time-interval related measurements.
Specifically, watt means Joules per Second. We are given that the electrical engine has 400 watts, meaning it can make 400 joules per second. If we need 300 kJ, or 3000 Joules, then we can write an equation to solve the time it would take to reach this amount of joules:
w * t = E
w: Watts
t: Time
E: Energy required
(Watts times time is equal to the energy required)
Input our values:
400 * t = 3000
(We need to write 3000 joules instead of 300 kilojoules, since Watts is in joules per second. It's important to make sure your units are consistent in your equations)
Divide both sides by 400 to isolate t:
[tex]\frac{400t}{400}[/tex] = [tex]\frac{3000}{400}[/tex]
t = 7.5 (s)
It will take 7.5 seconds for the 400 W engine to produce 300 kJ of work.
If you have any questions on how I got to the answer, just ask!
- breezyツ
The 400 W electrical engine must work for 12 minute 30 second in order to produce 300 kJ of work.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Power of the electrical engine = 400 Watt.
Work done by the electrical energy = 300 kJ
= 300 × 1000 Joule
= 300000 Joule.
Now from the definition of power:
Power = Work done/time interval
Hence, required time interval = work done/ power
= 300000 Joule/400 watt
= 750 second
= 12 minute 30 second.
Hence, a 400 W electrical engine must work for 12 minute 30 second in order to produce 300 kJ of work.
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A 0.156-kg ball is hung vertically from a spring. The spring stretches by 4.18 cm from its natural length when the ball is hanging at equilibrium. A child comes along and pulls the ball down an additional 5cm, then lets go. How long (in seconds) will it take the ball to swing up and down exactly 4 times, making 4 complete oscillations before again hitting its lowest position
Answer:
The answer is "[tex]=2.72 \ seconds \\\\[/tex]"
Explanation:
Using formula:
[tex]kr=mg \\\\k=\frac{0.156 \times 9.8}{0.418}\\\\[/tex]
[tex]=3.65741627\ \frac{N}{M}\\\\=3.65\ \frac{N}{M}\\\\[/tex]
Calculating the time period:
[tex]T=2\pi \sqrt{\frac{m}{k}}\\\\[/tex]
[tex]= 2 \pi \sqrt{\frac{0.156}{3.65}}\\\\= 2 \times 3.14 \sqrt{\frac{0.156}{3.65}}\\\\= 6.28 \sqrt{\frac{0.156}{3.65}}\\\\=6.28 \times 0.108210508\\\\=0.67956199\\\\=0.68\\\\[/tex]
The time to calculating the 4 oscillation:
[tex]\to 4T=4\times 0.68 =2.72 \ seconds \\\\[/tex]
The time taken by the spring to complete 4 complete oscillations will be t=2.72 sec
What are oscillations?Oscillation is the process of repeating variation of the quantity or the recitative or periodic variations with respect to the time.
Here it is given that
mass =0.156 kg
stretch x= 4.18 cm
Now from the formula
[tex]kx=mg[/tex]
[tex]k= \dfrac{0.156\times 9.81}{0.418}[/tex]
[tex]k=3.65\ \frac{N}{m}[/tex]
Now the time period will be calculated as:
[tex]T=2\pi\sqrt{\dfrac{m}{k}[/tex]
[tex]T=2\pi\sqrt{\dfrac{0.156}{3.65}[/tex]
[tex]T=6.28\times 0.108210508[/tex]
[tex]T=0.68\ sec[/tex]
Now for the 4 oscillations the total time will be
[tex]T=4\times 0.68=2.72\ sec[/tex]
Hence the time taken by the spring to complete 4 complete oscillations will be t=2.72 sec
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An astronaut brings a cube from the Earth to the Moon.
What is true about the inertial mass and weight of the cube?
Note that the gravitational acceleration on the Moon is about 1.6m/s^2
A) The inertial mass increases but the weight decreases.
B) Both the inertial mass and weight decrease.
C) The inertial mass decreases but the weight increases.
D) The inertial mass remains constant but the weight decreases.
Answer:
Answer D. Inertial mass constant, weight decreases.
Explanation:
Khan Academy
People travel from all over the world to see more than 30 glaciers at Glacier National Park in Alaska.
Which factor causes glacial movement downhill?
A. gravity
B. oceans
C. snow
D. wind
Which of the following is an example of charging by friction?
Answer: where is the examples?
Explanation:
1.00 x 10^3 kg of clear liquid (specific heat
capacity = 5.11 x 10^2 J/kg-°C) at a temperature
of 15.0°C gains 3.33 x 10° J of heat. What is the
final temperature of the liquid? (Assume the
melting point is less than 15.0°C and the boiling
point is greater than 62.0°C.)
Answer:
15.00000652 °C
Explanation:
From the question,
Q = cm(t₂-t₁)................ Equation 1
Where Q = heat gained by the liquid, c = specific heat capacity of the liquid, m = mass of the liquid, t₁ = Initial Temperature of the liquid, t₂ = Final temperature of the liquid.
Given: Q = 3.33 J, c = 511 J/kg°C, m = 1000 kg, t₁ = 15°C
Substitute these values into equation 1 and solve for t₂
3.33 = 511×1000(t₂-15)
3.33 = 511000(t₂-15)
(t₂-15) = 3.33/511000
(t₂-15) = 0.0000065
t₂ = 15+ 0.0000065
t₂ = 15.00000652 °C
The Sun's chemical composition was about 70%% hydrogen when it formed, and about 13%% of this hydrogen was available for eventual fusion in the core. (The rest remains in layers of the Sun where the temperature is currently too low for fusion.)Use the given data to calculate the total mass of hydrogen available for fusion over the lifetime of the Sun.
Answer:
1.8 × 10^29 kg
Explanation:
The computation of the total mass is shown below;
As we know that
The total mass of the sun is
= 2 × 10^30 kg
Since 70% of the mass involves hydrogen gas, so total mass of the hydrogen gas is
= 70% × 2 × 10^30 kg
= 1.4 × 10^30 kg
And, 13% available for fusion, so the hydrogen gas mass is
= 13% × 1.4 × 10^30 kg
= 1.8 × 10^29 kg
A heat pump with a COP of 3.0 is used to heat air contained in a 1205.4 m3 of well-insulated, rigid tank. Initially the pressure and the temperature inside the gas tank are 100 kPa and 7 oC, respectively. When running, the heat pump consumes 5 kW of electric power. How long does it take for the heat pump to raise the temperature of air in the tank to 22 oC
Answer:
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Explanation:
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ANSWER IS = B. 60 KG
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Two rubber bullets (each of the same mass) are fired at the same velocity towards two different blocks of equal mass. One block is made of clay and the bullet gets stuck in it, the clay block bullet begins to move in the direction the bullet was fired. The other block is made of aluminum and the bullet bounces off the block, the aluminum block also begins to move in the direction the bullet was fired. Which block (clay or aluminum) will move with greater velocity after being struck by the bullet
Answer:
Aluminum board will move with a higher velocity
Explanation:
The velocity of the block will be higher when the impulse imparted by the bullet is higher.
In case of bullet bouncing off, the impulse imparted on the aluminum board is high and hence, it will move with a high velocity as compared to that of the clay board.
what happens to the work done when a force is doubled and the distance moved remain the same?
Answer:
It is doubled
Explanation:
f2=2f1
x1=x2=x
W1=f1*x1=f1*x
W2=f2*x2=f2*x=2*(fi*x)=2*W1
The electric potential at a point in
space is 235 V. If a 0.0485 C
charge is placed there, what will its
potential energy U be?
(Unit = J)
Answer:
11.3975
Explanation:
Accellus said so
Answer:
11.3975
Explanation:
its for Acellus
The light ray is traveling from Acrylite into air. The refractive index for air is 1.00. If the angle of incidence and the angle of refraction are known, how could you determine the refractive index of Acrylite?
Answer:
Refraction. A light ray traveling through some plastic has a frequency of 5.5 x 1014 Hz. It is ... making an angle of 32° with the normal to the interface; it passes through the ... [5 points] (a) What is the refractive index of the glass? ... What you do know is the wavelength of the light in glass, 321 nm, and you know the frequency.
Explanation:
The refractive index of Acrylate is determined as: ratio of sine of incident angle to sine of refractive angle.
What is Snell's law?The relationship between the angles of incidence and refraction for light or other waves flowing through a border between two different isotropic media, such as water, glass, or air, is described by Snell's law, a formula.
The amount a light ray bends as it travels through different media is measured by the refractive index.
Given that: The refractive index for air is 1.00.
Let the angle of incidence from medium air to Acrylate is = i
the angle of refraction from medium air to Acrylate is = r.
Let the refractive index for Acrylate = n.
Then according to Snell's law:
1×sini = n× sinr
n = sini/sinr.
Hence, the refractive index of Acrylate is ratio of sine of incident angle to sine of refractive angle.
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William B. Hartsfield was a man of humble origins who became one of the greatest mayors of Atlanta. He served as mayor for six terms (1937–41, 1942–61), longer than any other person in the city's history. Hartsfield held office during a critical period when the color line separating the races began to change and the city grew . . . to a metropolitan population of one million. He is credited with developing Atlanta into the aviation powerhouse that it is today . . . . . . . On August 30, 1961, the city peacefully integrated its public schools. As a result, Atlanta began to acquire its reputation as "A City Too Busy to Hate."
–New Georgia Encyclopedia
During Hartsfield’s time in office, Atlanta became known as "A City Too Busy to Hate.” What factors supported this nickname? Check all that apply.
The city integrated its schools.
Atlanta became a leader in aviation.
The economy declined.
The population increased to one million.
Many people served as the city mayor.
Answer:
It's A, B, and D
A. The city integrated its school
B. Atlanta became a leader in aviation
D. The population increased to one million
Explanation:
A baseball was thrown off of a 35 meter high building. It lands 50 meters from the base of the building.
Wonderful.
Look out below !
Was the FAA notified ?
Acceleration is rate of change of
A-Position
B-Time
C-Velocity
D-Speed
B. Exercises
Exercise 1
Direction: identfy the plumbing symbols in each item Write your answer on the space
provided before each number
Answer:
please I do not understand that question
The brightness of a star depends on what
two things?
A. age and color
B. temperature and age
C. size and age
D. size and temperature
A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.55 m/s to the right relative to the plank.
Required:
What is the velocity of the plank relative to the surface of the ice?
Answer:
The speed of the plank relative to the ice is:
[tex]v_{p}=-0.33\: m/s[/tex]
Explanation:
Here we can use momentum conservation. Do not forget it is relative to the ice.
[tex]m_{g}v_{g}+m_{p}v_{p}=0[/tex] (1)
Where:
m(g) is the mass of the girlm(p) is the mass of the plankv(g) is the speed of the girlv(p) is the speed of the plankNow, as we have relative velocities, we have:
[tex]v_{g/b}=v_{g}-v_{p}=1.55 \: m/s[/tex] (2)
v(g/b) is the speed of the girl relative to the plank
Solving the system of equations (1) and (2)
[tex]45v_{g}+168v_{p}=0[/tex]
[tex]v_{g}-v_{p}=1.55[/tex]
[tex]v_{p}=-0.33\: m/s[/tex]
I hope it helps you!
The half-life of argon-44 is 12 minutes. Suppose you start with 20 atoms of
argon-44 and wait 12 minutes. How many atoms of argon-44 will be left?
A. 20 atoms
B. 40 atoms
C. 10 atoms
D. 5 atoms
SUBMIT
Answer:
C. 10
Explanation:
The half-life of argon-44 is 12 minutes, 10 atoms of argon-44 will be left. The correct option is C.
A radioactive substance's half-life is the amount of time it takes for half of the atoms in a sample to decay.
The half-life of argon-44 in this situation is 12 minutes. Starting with 20 argon-44 atoms, half of them will have disintegrated within 12 minutes, leaving 10 atoms.
This happens because radioactive decay is an exponential process with a constant rate of decay. Every half-life cuts the number of atoms in half.
So, if we waited another 12 minutes, half of the remaining 10 atoms would decay, leaving us with 5 atoms. This process is repeated, with half of the remaining atoms dying with each half-life.
Thus, the correct option is C.
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The scanning process and magnetic lenses used in a scanning electron microscope often results in fair to poor resolution and "fuzzy" images.
(A)True
(B)False
Answer:
(B)False is the answer.
Explanation:
Not only did Skid get shot out of a cannon when he was a clown in the circus, but he was also launched into the air by a vertically compressed spring. Skid of 55 kg is standing on a massless platform attached to a spring of constant 8700 N/m that is compressed 125 cm. Skid is launched from rest. He eventually leaves the platform and reaches a peak high above the platform. (a) What is the velocity of Skid when he leaves the platform
Answer:
v = 16.11 m / s
Explanation:
For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation
starting point. When the spring is compressed
Em₀ = K_e + U = ½ k x² + m g x ’
final point. The point where it leaves the platform
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
½ k x² + m g x ’= ½ m v²
v² = [tex]\frac{k}{m}[/tex] x² + g x
let's calculate
v² = [tex]\frac{8700}{55}[/tex] 1.25² + 9.8 1.25
v² = 247.159 + 12.25 = 259.409
v = 16.11 m / s
A car, initially at rest, travels from 0 m/s to 17.7 m/s in 21.7 s. What is the car's acceleration?
Black holes result from
Answer:
supernova explosion or death of massive star
Explanation:
"Most black holes form from the remnants of a large star that dies in a supernova explosion."
Astronomy Question
Who thinks Venus is the hottest planet instead of the lava planet?
say aye or nay
Answer:
AYE
Explanation:
3. A ball thrown vertically upward returns to its starting point in 4s. Find its initial speed. [4]
Answer:
9.8 ×4 equal 39.2 m/s This is v intial
Light with a wavelength of 600 nm shines onto a single slit, and the diffraction pattern is observed on a screen 2.5 m away from the slit. The distance, on the screen, between the dark spots to either side of the central maximum in the pattern is 25 mm. (a) What is the distance between the same dark spots when the screen is moved so it is only 1.5 m from the slit
Answer:
"6.67 mm" is the right solution.
Explanation:
The given values are:
L = 2.5 my = .0125λ = 600 nmAs we know, the equation
⇒ [tex]\frac{y}{L} =\frac{x \lambda}{a}[/tex]
On substituting the values, we get
⇒ [tex]\frac{.0125}{2.5}=\frac{(1)(600\times 10^{-9}) }{a}[/tex]
On applying cross multiplication, we get
⇒ [tex].0125a=2.5 (600\times 10^{-9})[/tex]
⇒ [tex]a=\frac{2.5(600\times 10^{-9})}{.0125}[/tex]
⇒ [tex]=1.2\times 10^{-4} \ m[/tex]
For new distance, we have to put this value of "a" in the above equation,
⇒ [tex]\frac{y}{1.5} =\frac{(1)(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]
⇒ [tex](1.2\times 10^{-4})y=1.5(600\times 10^{-9})[/tex]
⇒ [tex]y=\frac{1.5(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]
⇒ [tex]=3.22\times 10^{-3} \ m[/tex]
The total distance will be twice the value of "y", we get
= [tex]6.67\times 10^{-3} \ m[/tex]
or,
= [tex]6.67 \ mm[/tex]
What 2 environments once existed where the Grand Canyon is located today?
The entire park area is considered to be a semi-arid desert, but distinct habitats are located at different elevations along the 8,000-foot elevation gradient. Near the Colorado River, riparian vegetation and sandy beaches prevail.