C) As shorter wavelength illumination and better quality lenses are used, magnification will increase and the limit of resolution will increase.
What is wavelength illumination?Wavelength illumination is a way of measuring the intensity of a light source in terms of the wavelength of the light being emitted.
Light microscopes use light of different wavelengths and high-quality lenses to magnify and enhance images. Shorter wavelength illumination, such as UV light, can provide greater resolution because it has a higher frequency than longer wavelengths, such as visible light. Additionally, higher quality lenses provide greater magnification and allow for a larger field of view. Thus, as shorter wavelength illumination and better quality lenses are used, magnification will increase and the limit of resolution will also increase.
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A fish in a lake looks up at the
surface of the water. At what
distance d along the surface,
measured from the normal, is
a water-skimming insect safe
from the roving eye of the
fish?
the distance traveld by a body fallling freely from rest in one,two and three seconds are in the range of the object is equal
an air cannon fires a brick straight upward. the initial velocity of the brick and time required to reach its maximum height are recorded. which of the following statements describe the expected relationship between the time to maximum height and the initial velocity? assume that the effects of air resistance are negligible.
The greatest height is dictated by the starting vertical velocity. Because higher launch angles have a bigger vertical velocity component, increasing the launch angle increases the maximum height.
What is the relationship between maximum velocity and average velocity?The maximum velocity of a fully developed laminar viscous flow through a circular pipe is double the average velocity. The maximum velocity for fully developed laminar flow over parallel plates is equal to (3/2) times the average velocity.
The amount of distance an item travels in a given length of time is measured by its velocity. Here's a word equation that describes the link between distance, velocity, and time: Distance travelled divided by time equals velocity.
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An object's speed is 3.6 m/s with a momentum of 180 kgm/s. What is the mass of the object?
Answer:
To solve the problem we must know the concept of momentum.
What is Momentum?
Momentum is defined as the product of the mass of an object and the velocity of an object. It is a vector quantity.
$$\rm{Momentum = velocity \times Mass$$
The mass of the object is 50 kg.
Given to us
velocity of the object = 3.60 m/s
momentum of the object = 180 kg m/s
Mass of the object
We know that momentum is the product of the mass of the object and the velocity of the object,
$$\rm{Momentum = velocity \times Mass$$
Substitute the values,
180 = 3.60 \times \rm Mass180=3.60×Mass
\rm Mass = \dfrac{180\ kg\ m/s}{3.6\ m/s}Mass=
3.6 m/s
180 kg m/s
\rm Mass = 50\ kgMass=50 kg
Hence, the mass of the object is 50 kg.
each night different meteorologists give us the probability that it will rain the next day. to judge how well these people predict, we will score each of them as follows: if a meteorologist says that it will rain with probability p, then he or she will receive a score of
If a meteorologist says that it will rain with probability p, then he or she will receive a score of -10log(p) and a score of -10log(1-p) if it does not rain.
What will be the score if a meteorologist says that it will rain with probability p?The scoring system is called the Brier score, which is a commonly used method for evaluating accuracy of probabilistic forecasts. The Brier score ranges from 0 to 1, with score of 0 indicating perfect accuracy and score of 1 indicating total inaccuracy.
If a meteorologist says that it will rain with probability p, then he / she will receive a score of -10log(p) if it does rain. This is because log(p) is a measure of how uncertain the forecast is, and negative sign is used to penalize inaccurate forecasts.
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after being kicked, a soccer ball flies upward into the air, slowing down as it reaches its maximum height.T/F
False. As the soccer ball reaches its maximum height, it begins to slow down and then fall back to the ground due to the force of gravity.
What is gravity?Gravity is a natural force of attraction that exists between any two objects with mass. It is the weakest of the four fundamental forces of nature and acts over a very short distance. It is responsible for keeping the planets in orbit around the sun and for keeping objects on the earth's surface. Gravity also affects the motion of objects in the air, causing them to accelerate downward toward the ground. In addition, gravity affects the tides and other oceanic phenomena. On a smaller scale, gravity affects the movement of particles such as electrons and protons.
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a 56-kg pole vaulter running at 11 m/s vaults over the bar. her speed when she is above the bar is 1.4 m/s. neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar.
The altitude of the pole vaulter as she crosses the bar would be 6.1 meter due to energy conservation.
The energy is the first one, but when you jump you're in the air, so you have potential energy due to gravity, and kinetic energy because you're still moving in 1.4 m/s.
Using conservation of energy,
KEi+ PEi = PEf+ KEf
PE = mgh
KE = 0.5mv²
Now, m= 56 kg v= 1.4 m/s
so solving,
h= 6.1 meter
So, The altitude of the pole vaulter as she crosses the bar would be 6.1 meter due to energy conservation.
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a 1200 kg safe is 2.1 m above a heavy-duty spring when the rope holding the safe breaks. the safe hits the spring and compresses it 56 cm . What is the spring constant.
When a 1200 kilogram safe is 2.1 m above a heavy-duty spring and the rope holding the safe breaks, the spring constant is 199,136 N/m (roughly 200 kN/m). The safe collides with the spring, compressing it by 56 cm.
What is kinetic energy?In physics, an object's kinetic energy is the energy it has as a result of its motion. It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity. The body retains its kinetic energy after gaining it during acceleration until its speed changes. Kinetic energy is the energy that an item has as a result of its movement. If we wish to accelerate an item, we must apply force to it. Using force demands us to put in effort. After work is completed, energy is transferred to the item, and the thing moves at a new constant speed.
Here,
The spring constant is 200kN/m.
The work done on the spring by the the free falling safe is equal to the kinetic energy of the spring:
W1 =1/2kx²
The work done on the safe by gravity is the potential energy of the spring:
W2 = (mass of safe) x g x (height)
= 1000kg x 9.8 m/s^2 x (2 + 0.54)m
=1000kg x 9.8 m/s^2 x (2.54)m
= 24,892 N-m
W2 = W1 =24892 N-m
W=1/2kx²
Therefore, k = 199136 kN/m.
The spring constant is 199,136 N/m approximately 200 kN/m when a 1200 kg safe is 2.1 m above a heavy-duty spring when the rope holding the safe breaks. the safe hits the spring and compresses it 56 cm.
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the froude number, fr, is a dimensionless value that describes different flow regimes of open channel flow. if it depends on velocity v , gravitational constant g, and length l, use buckingham pi theorem to show.T/F
False. Buckingham Pi theorem states that if a physical relationship involves a certain number of independent variables, then the relationship can be written as a product of powers of a certain number of dimensionless groups.
What is Buckingham Pi theorem?Buckingham Pi theorem is a mathematical theorem that states that any physical system can be expressed as a combination of an appropriate number of variables, together with the appropriate number of independent dimensionless parameters. The theorem was developed by Edward Buckingham in 1914 and is considered to be the most general form of dimensional analysis.
The Froude number does not depend on the independent variables mentioned (velocity, gravitational constant, and length) so Buckingham Pi theorem is not applicable.
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kicked the ball in the air with an initial velocity of 12m/s at an angle of 40° above the horizontal. If the ball travels a horizontal distance of 15m , how long will it fly in the air?
The soccer ball rose 5.24 meters in the air.
VO =?, max H =?, range = 25m, angle A = 40°
Projectile motion is being used in this situation. Range = vo2 * sin 2A / g is the formula for range. calculating the initial velocity vo's square and its original value.
Range is equal to vo2*sin2A/g.
VO2 * SIN (2 * 40°) / 9.8 m/s = 25 m
vo2 = sin 80° / 9.8 m/s / 25 m
2 vo = 15.77 m/s and 2 vo = 248.8 (m/s) respectively.
The ball's starting speed is 15.77 m/s.
The height of the object, max H, can be calculated as follows: max H = vo * (sin A) * 2g max H = 248.8 (m/s) * (sin 40°) * 19.6 m/s * 2g max H = 5.24 meters
The soccer ball rose 5.24 meters in the air.
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A steel wire of length 1.93 m with circular cross section must stretch no more than 0.240 cm when a tensile (stretching) force of 450 N is applied to each end of the wire. What minimum diameter is required for the wire?
The minimum diameter required for the wire is 1.48 m when A steel wire of length 1.93 m with a circular cross-section must stretch no more than 0.240 cm when a tensile (stretching) force of 450 N is applied to each end of the wire.
Given,
wire length, l = 1.93 m
Δl = 0.240 cm = 0.24 x 10⁻² m
F = 450 N
we know that, young's modulus for steel
Y = 2.1 x 10¹¹ N/m²
let the radius of the wire is r
we know that,
Y = Fl/AΔl = (450 x 1.93)/(3.14 x r² x 0.24 x 10⁻²)
r² = 5.486 x 10⁻⁷ m²
or r = 7.4 x 10⁻⁴ m
so diameter of wire is d = 2r = 2 x 7.4 x 10⁻⁴ m
d = 1.48 x 10⁻³ m or d = 1.48 mm
Therefore, the minimum diameter required for the wire is 1.48 m when A steel wire of length 1.93 m with a circular cross-section must stretch no more than 0.240 cm when a tensile (stretching) force of 450 N is applied to each end of the wire.
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Infant brain mapping is being used to assess perceptual and cognitive activities including which of the following?
Language
Hearing
Vision
Infant brain mapping is being used to assess perceptual and cognitive activities including Vision, Hearing, and Language.
The very early offspring of humans are called infants or babies. Infant is a formal or specialized synonym for the phrase baby. It comes from the Latin word infants, which means "unable to talk" or "speechless." Other organisms' young may also be referred to by the names.
In everyday speech, an infant that is only a few hours, days, or even a few weeks old is referred to as a newborn. In medical contexts, an infant in the first 28 days following delivery is referred to as a newborn or neonate (from the Latin neonates, newborn); the word is applicable to premature, full-term, and postmature newborns.
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an object's elevation is a perspective cue to . group of answer choices distance shape shadowing size
A monocular cue called linear perspective helps us understand the depth and distance of an object.
Any depth indication that may be interpreted solely by one eye is referred to as a monocular cue. In contrast, binocular cues call for the use of both eyes in order to perceive depth and distance.
Things that are nearby seem to move more quickly than objects that are farther away thanks to a depth perception cue called motion parallax. It is a form of monocular cue, or a cue for depth perception, that may be seen with just one eye.
Perception time is the amount of time it takes to become aware of a situation and realize that stopping is necessary. About three-quarters of a second may pass during this. Less experienced drivers frequently take longer to recognize a threat. The distance a car goes during this time is called perception distance.
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two hypothetical metals are created with different elements that have the same atomic mass (g/mole) and the same atomic radius. metal a has a density of 9.50 g / cm 3 and metal b has a density of 8.73 g / cm 3 . if one of these metals has a bcc lattice structure and the other has an fcc lattice structure, identify the structure that corresponds to each of one of them. justify your answer.
Metal A has a more density(9.50 g/cm³) for the same atomic mass, so it is more likely to have an FCC lattice structure, whereas metal B has a comparatively less density(8.73 g/cm³), so it is more likely to have BCC lattice structure.
A body-centered cubic (bcc) lattice structure has 8 atoms at the corners of a cube and one atom in the center of the cube. This structure has a lower density compared to face-centered cubic (fcc) lattice structure, which has atoms at the corners and the centers of each face of a cube.
According to the given densities, metal A with a density of 9.50 g/cm³ is likely to have an FCC lattice structure, while metal B with a density of 8.73 g/cm³ is likely to have a BCC lattice structure. This is because the FCC structure has a higher density due to the more close-packed arrangement of atoms compared to the bcc structure.
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determine the moment of the couple formed by the two forces by resolving each force into horizontal and vertical components and adding the moments of the two resulting couples
The required moments of the resulting two couples is calculated to be 16.39 Nm.
Forces acting are two 60N forces
A and C are the corners of a 200-mm square plate
The equation for AC is given as(AC forms a hypotenuse, with two similar sides),
AC = √0.2²+0.2² = 0.2√2 m
sin75° = d/AC
d = 0.2√2 sin75° = 0.2732 m
m Fm = Fm × 0.2
m Fm = -30 V₃ 0.2
m Fm = -6 V₃
m Fv = -6 Nm
So, m = 16.39 Nm (clockwise)
Thus, the required moments of the resulting two couples is calculated to be 16.39 Nm.
The given question is incomplete. The complete question is 'Two parallel 60-N forces are applied as shown to the corners A and C of a 200-mm square plate.'
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A taxi hurries 95 km in 1 7/12 hours. What is its average speed in kilometers per hour?
85.83 km/hr is the average speed it travels at.
Explain about the speed.An object's speed can be determined if you are aware of the distance it covers in a given period of time. An automobile, for instance, is moving at a pace of 70 miles per hour if it covers 70 miles in an hour (miles per hour).
Speed (or rate, r) is a scalar quantity that represents the amount of distance travelled (d) over the amount of time changed (t), as shown by the equation r = d/t.
Distance divided by time can be used to calculate speed. The speed is determined by dividing the distance travelled (say, 3 meters) by the passing time (say, 3 seconds) (one meter per second) Speed is hence the rate at which an object's position changes in any direction.
By converting 7/12 to a decimal (7/12 = 0.58), you may determine how many hours are in total.
1 plus 0.58 equals 1.58 hours when you add up the total time.
Subtract the overall time from the entire distance (95km) (1.58 hours).
The result, 95 kilometers divided by 1.58 hours, is 85.83 km/h, which is the average speed.
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a brick 20cm long 10cm wide and 2cm thick has a mass of 5kg . determine the . Maximum pressure that can be exerted by the brick on a flat surface
Hence the maximum pressure exerted by the brick is 2450 dyne/cm²
Given the mass of the brick=5kg
Dimension of the brick=20cm*10cm*2cm.
So weight of the brick= F= mg
Where f= force on the body due to gravity
where m= mass, g= gravity.
So F= 5000*9.8
by doing the multiplication we get the result as
F= 49000 dyne where dyne is unit of force
Where surface area is 10cm*2cm is in contact with the ground then
Area= (10*2)= 20cm²
Applying pressure formula = F/Area= 49000/20
By dividing we get the answer as= 2450 dyne/cm²
When surface area is 20cm*2cm is in contact then
Area= 20cm*2cm= 40cm²
Applying pressure formula = F/Area= 49000/40 dyne/cm²= 1225 dyne/cm²
When the surface area is 20cm*10cm in contact then
Area= 20cm*10cm= 200cm²
By applying the pressure formula= F/Area= 49000/200=245 dyne/cm²
Hence the maximum pressure exerted by the brick is 2450 dyne/cm²
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Classify each of the following failures by identifying its category in Fig. 1.1, and explain the reasons for each choice in one or two sentences: (a) The plastic frames on eyeglasses gradually spread and become loose. (b) A glass bowl with a small crack breaks into two pieces when it is immersed, while still hot, into cold water (c) Plastic scissors develop a small crack just in front of one of the finger rings (d) A copper water pipe freezes and develops a lengthwise split that causes a leak (e) The steel radiator fan blades in an automobile develop small cracks near the base of the blades
We classified each of the following failures by identifying its category in the Figure shown:
Plastic eyeglass frames gradually stretch and loosen. This is an example of creep failure.A glass bowl with a small crack breaks into two pieces when immersed, still hot, in cold water. This is an example of thermal shock failure.A plastic scissors has a small crack just in front of one of the finger rings. This is an example of fatigue failure.A copper water pipe freezes and develops a longitudinal crack that causes a leak. This is an example of brittle fracture.The steel fan blades on the radiator fan are leaking. This is an example of creep failure.Explanation of each of the failures of the mentioned materials:This is an example of creep failure, which occurs when a material is subjected to constant stress over time and causes it to deform. Plastic eyeglass frames stretch and loosen due to constant stress from wearing them. This is an example of thermal shock failure, which occurs when a material is subjected to a sudden change in temperature, causing it to crack or break. The glass bowl broke in two when immersed in cold water while it was still hot. This is an example of fatigue failure, which occurs when a material is subjected to repeated cycles of stress, causing it to eventually crack or break. The plastic scissors developed a small crack due to repeated stress from use. This is an example of brittle fracture, which occurs when a material is subjected to high stress and fractures without any significant deformation. The copper water pipe froze and split longitudinally due to the high stress from the freezing temperatures. This is an example of creep failure, which occurs when a material is subjected to constant stress over time and causes it to deform. Steel radiator fan blades developed small cracks due to the constant stress of being used while an automobile develops small cracks near the base of the blades.Learn more about material failures:
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a student conducted an experiment where they burned a 5g strip of magnesium metal in an open flame. the result was a 3.5g of white ash collected in a crucible, a bright white flame, and smoke.
This experiment undoubtedly brought about the ignition of magnesium metal, which is an exceptionally receptive metal that promptly consumes within the sight of oxygen.
The ash gathered in the crucible is logical to the excess buildup of the magnesium after it has gone through ignition. The bright white fire and smoke are likewise normal for magnesium consumption.
As the metal consumes at a high temperature and produces a bright light. The ash gathered in the crucible is in all probability magnesium oxide, which is a white fine substance.
The weight of the ash(3.5g) is not exactly the underlying load of the magnesium strip (5g), this is because of the deficiency of magnesium as a gas during the burning system.
The contrast between the weight of the ash and the underlying load of the magnesium strip addresses the weight of the magnesium that was lost as a gas during the combustion.
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7. object has a mass of and is moving in the direction. it collides with object , which has a mass of 2 and is initially at rest. after the collision, object has a final velocity of in the direction. which of the following best describes the impulse object exerts on object during the collision? -2MV - Mv 0 +Mv E +2Mv
-2Mv best describes the impulse object exerts on object during the collision.
In physics, collision, which is also known as impact can be explained as the abrupt, powerful coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer.
Accidents can be generally defined as the following: A collision which occurs whenever two vehicles collide violently.
First collision is literally defined as the impact that a car suffers when it hits another object, and second collision is the impact suffered by the occupant, or occupants, of a crashed car, against the impacted car. Given the information on the question, that would be a first collision.
2Mv Mv +Mv +2Mv
2Mv Mv = Mv -2Mv
2(Mv)= Mv
Mv= -2Mv
-2Mv
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a wire loop is in a uniform magnetic field. current flows in the wire loop, as shown. what does the loop do?
The ring has a magnetic field travelling across it because of current I. The magnetic field as the paper goes through the ring is perpendicular to the internal plane, according to the right-hand thumb rule.
In proportion to a drop in the current I flowing from B to A, the magnetic field across the ring and magnetic flux both decrease. According to Lenz's law, the magnetic flux fluctuation is opposed by the current that is induced in the rings. This shows that the magnetic field produced by the induced current and the current I both point in the same general direction. The induced current in the ring is therefore flowing clockwise.
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At what distance of 1m from the source intensity of sound is 2 w / m² . What is the power of this wave
Answer:
25.13274 W (WATT) (Sound Power of the Sound Source)
134.002 dB (Sound Power Level)
002 (part 2 of 3) 10.0 points what is the magnitude of the potential difference vy x across the terminals y and x of the battery? answer in units of v. answer in units of v. 003 (part 3 of 3) 10.0 points what power is dissipated by the internal resistance of the battery? answer in units of w. answer in units of w.
The power dissipated by the battery is 100V2/R.
What is power dissipated?Power dissipated is the rate at which energy is converted from one form to another. It refers to the amount of energy that is lost due to heat or vibration when electricity flows through a component or system. Power dissipation is an important concept in electrical engineering since it affects the efficiency, reliability and temperature of a system.
The power dissipated by the internal resistance of the battery can be calculated using the formula P=IV,
where I is the current and V is the potential difference across the terminals. Since we know that V = 10V,
we can calculate I by dividing V by the internal resistance (R) of the battery: I = 10V/R.
The power dissipated by the battery is then given by P = IV = (10V/R)*(10V) = 100V2/R.
Thus,
In units of watts, the power dissipated by the battery is 100V2/R.
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two charged particles, one q and the other q, are held fixed a certain distance, 2d, apart. find the electric field at point p. for the coordinate system, take x to be to the right and y to be up
The vector sum of the electric fields resulting from each of the two charges at point P is the electric field. The field owing to q will point to the right, whereas the field due to -q will point to the left. As a result, the net electric field at point P is zero.
An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field. The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically. Electric charge or magnetic fields with variable amplitudes can produce an electric field. The area of space surrounding an electrically charged particle or object in which the charge body perceives force is known as the electric field.
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Two small identical conducting spheres are placed with their centers 0.30m apart. One is given a charge of 12 X 10^-9C, the other a charge of -18 X 10^-9C.
a.Find the electrostatic force exerted on one sphere by the other.
b. The spheres are connected by a conducting wire. Find the electrostatic force between the two after equilibrium is reached, where both spheres have the same charge.
a. 12*10^-5 N attractive is the force exerted on one sphere by the other. b. 9*10^-7 N repulsive is the force between the two after equilibrium is reached, where both spheres have the same charge.
The force between two charged particles is calculated as
F= q1*q2*K/r^2 .......................(i)
where q1 is the charge of the first body, q2 is the charge of the second body and r is the distance between them Here K is a constant that has the values of 9*10^9.
So for the finding a.
12 X 10^-9* -18 X 10^-9*9*10^9/(o.3)^2 ............ From ( i)
9*12*18*10^-9/0.09 which results to 12*10^-5 N
And Similarly for b we need to find the total average charge of both bodies will be.
(q1+q2)/2 ......(ii) (12 - 18)/2 => -6/2 = -3 nC .................( from ii)
and using (i) (3X10^-9)^2*9*10^9/ (o.3)^2 ...... (As q1 =q2)
which results in 9*10^-7 N
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given two strings s and t, both consisting of lowercase english letters and digits, your task is to calculate how many ways exactly one digit could be removed from one of the strings so that s is lexicographically smaller than t after the removal. note that we are removing only a single instance of a single digit, rather than all instances (eg: removing 1 from the string a11b1c could result in a1b1c or a11bc, but not abc).
I came up with this test case myself. If s = '3ab' and t = 'cd', return 1. If s = '123ab' and t = '423cd', return 6.
What are lexicograph?The study of lexicons is called lexicography, and it is separated into two distinct academic fields. It involves the creation of dictionaries. [1]
The process of compiling, writing, and editing dictionaries is known as practical lexicography.
Theoretical lexicography is the academic study of the semantic, orthographic, syntactic, and paradigmatic characteristics of the lexicon (vocabulary) of a language. It also develops theories of the elements and structures of dictionaries that connect the data in dictionaries, the information needs of users in various contexts, and the most effective ways for users to access the data included in printed and electronic dictionaries. This practise is sometimes known as "metalexicography."
On what defines lexicology as different from lexicography, there is some debate. Some people use the term "lexicology" to refer to theoretical lexicography, whereas others do not.
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positive charge is distributed uniformly on a plastic rod bent to form a quarter-circular arc (figure 1). figure1 of 1 a positively charged rod is bent so that it forms a concave rightward arc symmetrical about a horizontal dashed line going through the center of the rod. the center of curvature of the bent rod is marked with a black dot. part a what is the direction of the electric field at the center of the circle?
Radial direction of the electric field at the center of the circle.
What are Electric field?Take into consideration the little equivalent arc elements on either side of the horizontal first. Now determine the electric field they caused, how to fix it, and how to eliminate the ones that were directed in the other direction. Now, swap out the common expression for the electric field caused by charge density, integrate over the arc's length, and you'll get the necessary electric field.
The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also known as an E-field.
It can also refer to a system of charged particles' physical field. Electric charges and time-varying electric currents are the building blocks of electric fields.
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A student must conduct an experiment to verify the conservation of momentum for a closed two-cart system. Cart X and cart Y travel toward each other and eventually collide. The student has determined the following procedure.
Step 1: Measure the mass of cart X and cart Y with a balance.
Step 2: Use a motion sensor to record data of the velocity of each cart before, during, and after the collision.
Step 3: Use the data and ∑pf = ∑p0 to determine if the right-hand side of the equation is equal to the left-hand side of the equation.
Which of the following steps should the student add to the procedure so that the conservation of momentum can be experimentally verified?
answer choices
Conduct the experiment on a smooth, level surface.
Attach adhesive strips to each cart so that they stick together after they collide.
Ensure that the mass of each cart is the same.
Ensure that the initial speed of each cart is the same.
The surfaces should be frictionless . The vector sum of the momenta should be compared, because momentum is a vector quantity.
Define conservation of momentum ?
The law of conservation of momentum states that in an isolated system the total momentum of two or more bodies acting upon each other remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.The principle of conservation of momentum states that if two objects collide, then the total momentum before and after the collision will be the same if there is no external force acting on the colliding objects.Every moving object has momentum, and momentum is defined as the product of an object's mass and its velocity. As an equation, this can be written as p=mv p = m v , where p represents the momentum.To learn more about momentum refers to:
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a car burns fuel with a density of 700 kg/m3 under atmospheric conditions that produce an air density of 1.2 kg/m3. the car has a fuel rating of 36 mpg (miles per gallon) at a speed of 60 mph (miles per hour) and a frontal cross-section of 4.5 feet by 2.5 feet. 1. calculate
The drag coefficient of the car is calculated as equal to 0.0947.
What is drag coefficient ?A dimensionless quantity that is used to quantify the drag or resistance of an object in a fluid environment, such as air or water is called drag coefficient.
60 mph = 26.8 m/s
1 mpg = 0.425144 liters/kilometer
36 mpg = 15.60512 liters/kilometer
4.5 ft * 2.5 ft = 11.25 ft^2 = 1.042 m^2
The drag force can be calculated as:
Fd = 0.5 * Cd * A * r * v^2
where, Cd = drag coefficient (unitless), A = frontal area of the car (m^2), r = air density (kg/m^3), v = velocity of the car (m/s)
So, Fd = (15.60512 liters/kilometer) * 4.5 kg/liter / (3600 sec/hour) = 0.0066 N
Cd = Fd / (0.5 * A * r * v^2)
Cd = 0.0066 N / (0.5 * 1.042 m^2 * 1.2 kg/m^3 * 26.8 m/s^2) = 0.0947
The drag coefficient of the car is 0.0947.
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Question: A car burns fuel with a density of 700 kg/m3 under atmospheric conditions that produce an air density of 1.2 kg/m3. the car has a fuel rating of 36 mpg (miles per gallon) at a speed of 60 mph (miles per hour) and a frontal cross-section of 4.5 feet by 2.5 feet. 1. calculate the drag coefficient of the car.
Which of the following describes a benefit of the fact that oll never wears out?
Because oll never wears out, it can be used again and again.
Because oll never wears out, farmers will never run out of it.
Because oll never wears out, it never needs to be replaced.
O Because oll never wears out, its cost remains low.
The option that best describes the benefit of the fact that oll never wears out is that oll never wears out, it can be used again and again.
The correct option is A.
What is the benefit of durability in materials?Durability is the ability of material to last in usage for a long time.
Duravle materials provides benefits to the owners in that it:
allows for reuse of the material over and over.it reduces cost and expenses of the materialLearn more about durability at: https://brainly.com/question/1460183
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In professional football some players have microphones in their helmets that allow them to communicate with coaches on the sideline what is this indicate
The involvement of microphones in the helmet of some professional football players for the purpose of communication shows that there is an immense advancement in technology.
What are microphones?A microphone is defined as a device that is can be used to magnify a sound through its conversation to electrical signals.
Professional football is a type of game that is played by train individuals and it's made up of two teams that plays against each other.
The introduction of microphones in the helmet of these footballer helps them to effectively communicate with their coaches near by which was not soo years back.
Therefore this can be said to be an advancement in technology.
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