Which is the correct acceleration vs. time graph for the velocity vs. time graph shown in (Figure 8)?
Answers
Answer:
The correct option is the second option with horizontal bars at a = 6, a = -1, and a = 4 m/s²
Please find attached the table of values and a graph representing the correct option
Explanation:
The given data can be presented as follows;
Time (s), Velocity (m/s), Acceleration (m/s²)
0, -1, 6
0.5, 2, 6
1, 5, 6
0, 5, -1
0.5, 4.5, -1
1, 4, -1
1.5, 3.5, -1
2, 3, -1
2.5, 2.5, -1
3, 2, -1
0, 2, 4
0.5, 4, 4
1, 6, 4
1.5, 8, 4
2, 10, 4
From the data, and the graph the acceleration for the period from the time t = 0 to t = 1 is 6 m/s²
From t = 1 to t = 4, the acceleration is constant and equal to -1
From t = 4 to t = 6 the acceleration is also constant and equal to 4
Related Questions
6. If a vehicle needs 5s to complete 15m. Find the mean speed of it?
3) 3ms
4) 20ms
1) 75ms
2) 10ms
Answers
Answer:
3m/s
Explanation:
Time=5s
Distance =15m
Speed=distance/time
Putting the values
Speed=15m/5s
Speed=3m/s is the answer
Hope it will help you. :)
How would you express B⃗ using unit vectors? Express your answers in terms of the unit vectors x^ and y^. Use the unit vector button under the templates menu in the answer box to create unit vectors.
Answers
Answer:
B = B (cos θ x ^ + sin θ y ^)
Explanation:
To represent the magnetic field B using unit vectors, the magnitude of the field and the angle with respect to some coordinate axis must be known. Having this information, trigonometry can be used.
Suppose that the angle we have is with respect to the positive side of the x-axis, let's use trigonometry
cos θ = Bₓ / B
sin θ = [tex]B_{y}[/tex] / B
Bx = B cos θ
B_{y} = B sin θ
so the resulting vector is
B = Bₓ i ^ + B_{y} j ^
unit vectors
x ^ = i ^
y ^ = j ^
let's write the complete answer
B = B (cos θ x ^ + sin θ y ^)
The bold indicate vector
A car starts from rest and acquires a velocity of 50m/s in 3secs. Calculate i) acceleration ii) distance covered.
Answers
Answer: 75.02 m
Explanation:
u = 0 ( starts from rest )
v = 50 m/s
t = 3 s
( i ) a = v - u / t
= 50 - 0 /3
= 16.67
( ii ) s = ut + 1/2 at²
= 0 × 3 + 1/2 × 16.67 × 3 × 3
= 75.02 m
Hope this helps...
What are the laws of nature according to C.S. Lewis? Pls hurry
Answers
A tennis ball moves 22 meters southward then 12 meters northward then 16 meters southward and finally 34 northward
Answers
Answer:
The tennis ball ended 8 m north from the starting point.
Explanation:
If we label North as positive and south as negative for axis of reference, then the tennis ball performed the following displacements (in units of meters):
- 22 m + 12 m - 16 m + 34 m = 8 m
Which means that it ended 8 m north from the starting point.
716 decimeters + 840 centimeters = ____________ meters?
Answers
Answer:
80metre
Explanation:
1m=10decimetre,100 cm
80 meters
Explanation:1 m = 10 dm
716 dm = 716 : 0,1 m = 71, 6 m
1 m = 100 cm
840 cm = 840 : 0,01 m = 8, 4 m
716 dm + 840 cm =
= 71,6 m + 8,4 m
= 80 meters
An electric pump rated at 1000W, takes 16 seconds to pump 100 kg of water out to a tank at a height of 10 m. what is the efficiency of the motor?
Answers
Answer:
[tex] \boxed{\sf Efficiency \ of \ the \ motor = 62.5 \ \%} [/tex]
Given:
Input Power ([tex] \sf P_i [/tex])= 1000 W
Mass (m) = 100 kg
Height (h) = 10 m
Time (t) = 16 s
To Find:
Efficiency of the motor
Explanation:
[tex] \boxed{ \bold{Output \: power \: (P_o)= \frac{mgh}{t}}}[/tex]
[tex] \sf \implies P_o = \frac{100 \times 10 \times 10}{16} [/tex]
[tex] \sf \implies P_o = \frac{10000}{16} [/tex]
[tex] \sf \implies P_o = \frac{ \cancel{16} \times 625}{ \cancel{16}} [/tex]
[tex] \sf \implies P_o = 625 \: W[/tex]
[tex] \boxed{ \bold{Efficiency = \frac{Output \ Power \ (P_o)}{Input \ Power \ (P_i) } \times 100}}[/tex]
[tex]\sf \implies Efficiency = \frac{625}{10 \cancel{00}} \times \cancel{100}[/tex]
[tex]\sf \implies Efficiency = \frac{625}{10} [/tex]
[tex]\sf \implies Efficiency = 62.5 \: \%[/tex]
[tex] \therefore[/tex]
Efficiency of the motor = 62.5 %
A man is lifting a piano that weighs 800 N through a distance of 10 meters using a pulley system. The man pulls the rope a total distance of 100m. What force does the man need to apply to the rope?
Answers
Answer:
The force the man applied is 80 N
Explanation:
weight of the load, L = 800 N
distance traveled by the load, a = 10 m
distance traveled by the effort, b = 100 m
Output work = load x distance moved by the load
Output work = 800 x 10 = 8000 J
Input work = Effort x distance moved by effort
Input work = Effort x 100 m
Assuming an ideal machine; no friction effect, the input work will be equal to output work.
Effort x 100 m = 8000 J
Effort = 8000 / 100
Effort = 80 N
Therefore, the force the man applied is 80 N
A ball is shot into the air with initial speed of 40 m/s. How high will the ball go before falling back down?
A. 20m
B. 40m
C. 60m
D. 80m
Answers
Answer:
B. 40m
Explanation:
Which is an example of potential energy? a swimmer kicking their legs a car driving on the road an arrow flying at a target a yo-yo in someone’s hand
Answers
Answer:
The yo-yo :)
Explanation:
12. The windings of a particular type of DC motor are in its rotor. The magnetic field is reversed during the rotation of the rotor by means of the
A. field magnets.
B. commutator.
C. applied power source reversal.
D. armature coil split windings.
Answers
Answer:
B. commutator
Explanation:
The DC motor has a commutator, to keep the rotor rotating. The rotor of the DC motor usually stop spinning once it aligns with the magnetic field. However, the commutator would reverse the current through the stator and in this process reverse the magnetic field. This ensures continuous spinning of the rotor.
Therefore, the correct option is "B. commutator."
7 A steel sphere is released from a height
of 9 m on the surface of the Moon. It is
known that the acceleration due to gravity
on the Moon is 1 the acceleration due
6
to gravity on the surface of the Earth.
Calculate the time taken by the sphere to
hit the surface of the Moon.
A 1.8 S
C 3.3 s
B 2.6 s
D 4.2 s
Answers
Answer:
C 3.3 s
Explanation:
Given:
Δy = 9 m
v₀ = 0 m/s
a = ⅙ (9.8 m/s²) = 1.63 m/s²
Find: t
Δy = v₀ t + ½ at²
9 m = (0 m/s) t + ½ (1.63 m/s²) t²
t = 3.3 s
A truck of mass 500kg moving at 4m/s collides with another truck of mass 1500kg moving in the same direction at 2m/s. What is their common velocity just after the collision if they move off together? PLZ HELP ASAP
Answers
Answer:
m1u1+m2u2=(m1+m2)v.
500×4+1500×2=(500+1500)V.
2000+3000=2000V.
5000=2000V.
V=2.5m/s
How many seconds will it take for a satellite to travel 550 km at a rate of 130 m/s?
Answers
Answer:
4230.77s
Explanation:
We know: t=D/S, 550 km =550,000 m, so you can get the time by dividing 130 from 550000, you can get: 550000/130 approximately equals to 4230.77s. :) If I am correct, Mark the Brainlist, plz :D
It would take 4230.7692 seconds for a satellite to travel 550 km at a rate of 130 m/s
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
The mathematical expression for velocity is given by
velocity= total displacement/Total time
As satellite has to travel 550 km
1Km =1000 m
550 km = 550000 m
Time is taken by satellite to travel 550000 m by velocity rate of 130 m/s
Time = displacement/velocity
=550000/130 seconds
=4230.7692 seconds
Thus, the satellite will take 4230.7692 seconds
Learn more about Velocity from here
brainly.com/question/18084516
#SPJ2
A car rolls down a ramp in a parking garage. The horizontal position of the car in meters over time is shown below. Graph of vertical position (in meters) on y axis and time (in seconds) on x axis. The initial position is 12 m at t=0 s, and the position decreases linearly to 6 m at t=8 s. Then the position is constant at 6 m until t=16 s, then decreases linearly to 0 m at t=24 s. Graph of vertical position (in meters) on y axis and time (in seconds) on x axis. The initial position is 12 m at t=0 s, and the position decreases linearly to 6 m at t=8 s. Then the position is constant at 6 m until t=16 s, then decreases linearly to 0 m at t=24 s. What is the displacement of the car between 0\text{ s}0 s0, start text, space, s, end text and 24\text{ s}24 s24, start text, space, s, end text? 6 \text mmstart text, m, end text What is the distance traveled by the car between 0\text{ s}0 s0, start text, space, s, end text and 24\text{ s}24 s24, start text, space, s, end text?
Answers
Answer:
d_total = 12 m
Explanation:
This is a kinematics problem, in the attachment we can see the problem graph, they ask us how much the distance is worth for all the time of 24 s.
The total distance is
d_total = d₁ + d₂ + d₃
as in the graph the part of d₂ is horizontal (v=0) the distance is zero d₂ = 0
the distance d₁ is
d₁ = 12 -6 = 6 m
the distance d₃
d₃ = 6 -0 = 6 m
therefore the total distance traveled is
d_total = 6 + 0 + 6
d_total = 12 m
As a increases and c stays constant, b does what
Answers
Answer:
b decreases as a increases and c stays constant
It all depends on the definitions of a, b, and c, and the relationship among them. Your question doesn't give us any of this information.
What is the volume of a cone with a height of 27 cm and a radius of 13 round your answer to the nearest tenth
Answers
Answer:
4.775,94
Explanation:
FORMULA:
[tex]\frac{1}{3} * 3,14 * Rx^{2} * H[/tex]
one-third per "pi" (3.14), per radius squared, per height.
Answer:
vol = 4778.36 cm³
Explanation:
volume of a cone = 1/3 π r² h
height (h) = 27 cm
radius (r) = 13 cm
plug in values:
vol = 1/3 π (13)² 27
vol = 4778.36 cm³
A car is moving with a speed of 15ms-¹.How long does it take to cover a distance of 1.2km?
Answers
1.2 km × 1000 = 1200m
1200m : 15 = 80s
so it will take 80 seconds or 1 minute 20seconds.
Questions
3 pts
Convert 6.36 x 104 from scientific notation to standard decimal with the correct number of significant digits.
Answers
Answer:
Explanation:
standard decimal form of 6.36*10^4 is
6,3600.0
You serve a volleyball with a mass of 2 kg. The ball leaves your hand with a speed of 30 m/s. What is the KE of the ball? find the product
Answers
Answer:
KE= 900joules, product= 60kgm/s momentum
Explanation:
KE=1/2MV2= 1/2× 2×30×30=900J
PRODUCT= MOMENTUM= 30m/s×2kg= 60kgm/s
How does air pressure help to inflate a football?
Answers
Answer:
When air is flushed into the ball, the elastic lining inside is expanded. This happens because when too much air enters, there is a lacking of space inside. Therefore the air with pressure pushes the walls of the ball and results in inflation.(same like after you have excess food your stomach inflates)
It appears as though your vehicle is about to be hit on the right side (a broadside collision). What should you do to reduce damages from the collision?
Answers
Answer:
Turn the vehicle to the left, in order to reduce the momentum on the car during sackcloth
Explanation:
In the case of a collision on the right side, two things can be done to reduce the damage caused.
* Turn the vehicle to the left, in order to reduce the momentum on the car during sackcloth
* Decrease the speed, to have a less change in the amount of movement.
Plz help me ASAP How does sound travel from its source to your ear??? 1. By changes in air pressure 2. By vibrations in wires or strings 3. By electromagnetic wave 4. By infrared waves
Answers
Answer:
2. By vibrations in wires or strings.
There are other equally good substitutes for exercise. True False
Answers
Answer:
B is the answer to this question
Answer:
True
Explanation:
For Example
Walking is a form of exercising without realising it
when you think you are creating blood flow which is oxygen which generates energy with that being said could be considered exercising no matter what you do in a result of energy in the body you are exercising.
Which combination of variables will make an experiment the most reliable?
A. One dependent variable and one experimental variable
B. One controlled variable and many experimental variables
C. Two controlled variables
D. Two experimental variables
Answers
Answer:A
Explanation: it’s A
If our Solar System was compressed by a factor of 10 billion such that the Sun is about the size of a grapefruit here in downtown Atlanta, then the nearest star (also about the size of a grapefruit) would be approximately at the distance of
Answers
Answer: 3,602.4 km
Explanation:
Ok, the distance between the sun and the nearest star is 4.22 light-years.
1 light-year = 9.461x10^12 km
4.22 light-years. = 4.4*(9.461x10^12 km) = 41.6284x10^12km.
Now, the radius of the Sun is:
r1 = 693,340 km
The radius of the grapefruit is around:
r2 = 6cm
Then in this new scale, 6 centimeters are equivalent to 693,340 km.
Now, how many times there are 693,340 km in 41.6284x10^12km?
We can take the quotient:
N = (41.6284x10^12km/ 693,340 km) = 60,040,384.
Then, the distance between the sun-grapefuit and the nearest star will be 60,040,384 times 6 centimeters:
Distance = 60,040,384*6cm = 360,242,304 cm ≈ 3,602.4 km
Just need help with 1 and 2 please :D i’m having a bit of trouble :/
Answers
2. A) 400m
B)0m
C)d=1/2(vi+vf)t
400=1/2(0+vf)92
8.7m/s
D) 0m/s
E) Not sure but instantaneous velocity refer to velocity at a given point. Average velocity is just the average. Usually instantaneous velocity won’t be same as the average velocity.
Plz like if it helped.
how should an ammeter and voltmeter be connected in a circuit and why?? I need ans acc to grade 10th
Answers
Answer:
An ammeter should be connected in the series while the voltmeter in parallel.
Explanation:
Ammeter is the device used to measure the electric current. So , the total current flowing through the circuit must pass through the ammeter. Thus , it should be connected in series. While voltmeter is a device used to measure the potential difference between two ends. Therefore, voltmeter should be connected in parallel to measure the potential difference across two ends.
Newer aircraft jet catapult systems use magnets instead of steam. The launch still takes 1.19 seconds, but the acceleration is a about 47.41 m/s2. Determine the length of the runway on the carrier, assume the aircraft starts from REST
Answers
Answer:
33.6 m
Explanation:
Given:
v₀ = 0 m/s
a = 47.41 m/s²
t = 1.19 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (1.19 s) + ½ (47.41 m/s²) (1.19 s)²
Δx = 33.6 m
What is the mass of a car that has a kinetic energy if 4,320,000 J moving at 23 m/s?
Answers
Answer:
kinetic energy=1/2mv^2.
which is 4320000=1/2×m×23^2.
which is 4320000=1/2×m×529.
4320000=264.5m.
m=4320000/264.5.
m=16332.70~16333g
The mass of a car that has a kinetic energy of 4,320,000 J moving at 23 m/s would be 16332.70 Kg
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
Total mechanical energy is s the sum of all the kinetic as well as potential energy stored in the system.
ME = KE + PE
As given in the problem we have to calculate the mass of a car that has a kinetic energy of 4,320,000 J moving at 23 m/s
K.E = 4,320,000 J
v = 23 m/s
The total kinetic energy
KE = 1/2mv²
By substituting the respective values in the formula of kinetic energy
4,320,000 J =1/2m23²
m = 4,320,000×2/23²
m = 16332.70 Kg
Thus, The mass of a car that has a kinetic energy of 4,320,000 J moving at 23 m/s would be 16332.70 Kg
Learn more about mechanical energy from here
brainly.com/question/12319302
#SPJ5