Which is equivalent to the expression 8x(3x+7) A. 24x+15 B. 24x shift6 2+56 C.24x shift6x +56x D. 24x shift6 +15x

Answer:

50 gram

Step-by-step explanation:

The actual percentage recipe = 100%

Percentage Increase in recipe = 60%

Recipe used as a result of increment = 80 gram

Hence,

100% + 60% = 80

160% = 80g

If :

160% = 80

100% = x

Cross multiply

1.6x = 80 * 1

1.6x = 80

x = 80 / 1.6

x = 50

Recipe required 50 gram

Answer:

288

Step-by-step explanation:

the formula is 2(lw+wh+hl)

length - 8

width - 8

height 5

substitute the values and you get

2(64+40+40)

2(144)

= 288

Answer:

320

Step-by-step explanation:

Answer:

c. (6 3/7, 12 2/7)

Step-by-step explanation:

x= 38/7 + 1 = 5 3/7 +1 = 6 3/7

y= 16/7 + 10 = 2 2/7 + 10= 12 2/7

Answer:

[tex]141^{\circ}[/tex]

Step-by-step explanation:

The quadrilateral in the image is a cyclic quadrilateral, because it is circumscribed by a circle. In all cyclic quadrilaterals, each pair of opposite sides are supplementary (add up to 180 degrees). Therefore, we have the following equation:

[tex]m\angle T+39=180,\\m\angle T=\boxed{141^{\circ}}[/tex]

Answer: Use the app photo math, you just take a picture and it gives you the answer and shows you the steps:)

1) x> 5

2) x< 2

3) x<-6

4) x< 2

5) x> 2

6) x> - 7/2

Step-by-step explanation:

See the images below for the work:)  The images will be in order with the number the first problem will be the answer to the first.

Answer:

[tex]\sf 1)\:4x - 2 > 2x + 8[/tex]

Add 2 from both sides:

[tex]\sf 4x-2+2>2x+8+2[/tex]

[tex]\sf 4x>2x+10[/tex]

Subtract 2x from both sides:

[tex]\sf 4x-2x>2x+10-2x[/tex]

[tex]\sf 2x>10[/tex]

Divide both sides by 2:

[tex]\sf \cfrac{2x}{2}>\cfrac{10}{2}[/tex]

[tex]\boxed{\sf x>5}[/tex]

_______________________________

[tex]\sf 2)\: -3x - 6 > 4x - 20[/tex]

Add 6 from both sides:

[tex]\sf -3x-6+6>4x-20+6[/tex]

[tex]\sf -3x>4x-14[/tex]

Subtract 4x from both sides:

[tex]\sf -3x-4x>4x-14-4x[/tex]

[tex]\sf -7x>-14[/tex]

Multiply both sides by -1:

[tex]\sf\left(-7x\right)\left(-1\right)<\left(-14\right)\left(-1\right)[/tex]

[tex]\sf 7x<14[/tex]

Divide both sides by 7:

[tex]\sf \cfrac{7x}{7}<\cfrac{14}{7}[/tex]

[tex]\boxed{\sf x<2}[/tex]

_______________________________

[tex]\sf 3)\: 4(x + 1) < 3x - 2[/tex]

Apply distributive property:

[tex]\sf 4x+4<3x-2[/tex]

Subtract 4 from both sides:

[tex]\sf 4x+4-4<3x-2-4[/tex]

[tex]\sf 4x<3x-6[/tex]

Subtract 3x from both sides:

[tex]\sf 4x-3x<3x-6-3x[/tex]

[tex]\boxed{\sf x<-6}[/tex]

_______________________________

[tex]\sf 4)\: 2x + 3 + x < -2x + 1 + 12[/tex]

Combine like terms:

[tex]\sf (2x+x)= 3x[/tex]

[tex]\sf( 1+12)=13[/tex]

[tex]\sf 3x+3<-2x+13[/tex]

Subtract 3 from both sides:

[tex]\sf 3x+3-3<-2x+13-3[/tex]

[tex]\sf 3x<-2x+10[/tex]

Add 2x from both sides:

[tex]\sf 3x+2x<-2x+10+2x[/tex]

[tex]\sf 5x<10[/tex]

Divide both sides by 5:

[tex]\sf \cfrac{5x}{5}<\cfrac{10}{5}[/tex]

[tex]\boxed{\sf x<2}[/tex]

________________________________

[tex]\sf 5)\: 2(x - 1) > 4x + 4 - 5x[/tex]

Combine like terms:

[tex]\sf (4x-5x)=-x[/tex]

[tex]\sf 2\left(x-1\right)>-x+4[/tex]

Apply distributive property:

[tex]\sf 2x-2>-x+4[/tex]

Add 2 from both sides:

[tex]\sf 2x-2+2>-x+4+2[/tex]

[tex]\sf 2x>-x+6[/tex]

Add x from both sides:

[tex]\sf 2x+x>-x+6+x[/tex]

[tex]\sf 3x>6[/tex]

Divide both sides by 3:

[tex]\sf \cfrac{3x}{3}>\cfrac{6}{3}[/tex]

[tex]\boxed{\sf x>2}[/tex]

_______________________________

[tex]\sf 6)\: 2 + 4x -7 < 8x + 2 - 2x[/tex]

Subtract 2 from both sides:

[tex]\sf 2+4x-7-2<8x+2-2x-2[/tex]

[tex]\sf 4x-7<8x-2x[/tex]

Combine like terms:

[tex]\sf (8x-2x)=6x[/tex]

[tex]\sf 4x-7<6x[/tex]

Add 7 from both sides:

[tex]\sf 4x-7+7<6x+7[/tex]

[tex]\sf 4x<6x+7[/tex]

Subtract 6x from both sides:

[tex]\sf 4x-6x<6x+7-6x[/tex]

[tex]\sf -2x<7[/tex]

Multiply both sides by -1:

[tex]\sf \left(-2x\right)\left(-1\right)>7\left(-1\right)[/tex]

[tex]\sf 2x>-7[/tex]

Divide both sides by 2:

[tex]\sf \cfrac{2x}{2}>\cfrac{-7}{2}[/tex]

[tex]\boxed{\sf x>-\frac{7}{2}}[/tex]

_______________________________________

Answer:

Six.

Step-by-step explanation :

Each seamstress can sew one seam in twenty minutes, or 3 in an hour, or 6 in two hours. 150

make brainliest pls

Answer:

six each seamstresses can sew one seam in tewenty min

note: I don’t really like giving people answers. I like them to learn:

To find a(n) area of a triangle, all you need to do is use the triangle shape to make a rectangle and then calculate the area of the rectangle and divide it by the number of triangles you used to make the triangle.

for your triangle I can imagine it needs four triangles to make a rectangle.

unless you want to multiply 1/2x6x11 to get your answer.

hope this helped !

Answer:

D.

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

8*3=24

24 yd^2

3*8

Step-by-step explanation:

Answer:

2x - 6

Step-by-step explanation:

2(3 - x) - 12 + 4x =

6 - 2x - 12 + 4x =

-6 + 2x =

2x - 6

Answer:

111

Step-by-step explanation:

360 - 65 - 106 - 78 = 111

Answer:

640 cm²

Step-by-step explanation:

The ratio of the area of 2 similar polygons = the ratio of the square of their corresponding lengths

Thus:

Area of Trapezoid ABCD to Area of Trapezoid EFGH = AB² to EF²

Area of Trapezoid ABCD = ? = x

Area of Trapezoid EFGH = 40 cm²

AB = 20 cm

EF = 5 cm

Substitute

x:40 = 20²:5²

x/40 = 400/25

x/40 = 16

Cross multiply

x = 16*40

x = 640

Area of trapezoid ABCD = 640 cm²

Answer:

Base length of plane from control tower = 73,880 feet (Approx.)

Step-by-step explanation:

Given:

Height of plane from ground = 20,000 feet

Height of control tower = 200 feet

Angle of elevation from control tower = 15°

Find:

Base length of plane from control tower

Computation:

Height of plane from control tower = 20,000 - 200

Height of plane from control tower = 19,800 feet

Tan θ = Perpendicular / Base

Tan15 = 19,800 / Base length of plane from control tower

0.268 = 19,800 / Base length of plane from control tower

Base length of plane from control tower = 73,880 feet (Approx.)

Answer:

I think it is 5 units left and 7 units down, then rotate 270°.

Step-by-step explanation:

                  HOPE THIS HELPS YOU!!! :) :) :) :) :)

                    SORRY IF IT'S WRONG. :) :) :) :) :)

Answer:

160° and the angle (10x+50)° are congruent. So

160°=10x+50

subtract 50° from both sides

110=10x

divide 10 by both sides

11=x

The answer js

D.11

Answer:

27

Step-by-step explanation

6x - 3

6(5) - 3 || replace the x with its value

30 - 3 || multiply (also known as simplify)

27 || subtract 3 from 30

Answer:

It is Odd

Step-by-step explanation:

Mark as Brainliest

Answer:

Step-by-step explanation:

10). m(arc AB) = m(arc BC) = m(arc CA)    [given in the picture]

     m(arc AB) = [tex]\frac{360^0}{3}[/tex]

                      = 120°

     Therefore, m(arc ACB) = m(arc AC) + m(arc BC)

                                            = 120° + 120°

                                            = 240°

11). m(arc CD) = 127°  [Given]

    m(arc AB) = 51° [Given]

    m(arc AC) = m(arc BD) [Given]

    m(arc CD) + m(arc BD) + m(arc AB) + m(arc AC) = 360°

    127° + 2[m(arc BD)] + 51° = 360°

    178° + 2[m(arc BD)] = 360°

    2[m(arc BD)] = 360° - 178°

    m(arc BD) = 91°

    Since, m(arc CDB) = m(arc CD) + m(arc BD)

    Therefore, m(arc CDB) = 127°+ 91°

                                           = 218°

12). m(arc EH) + m(arc ED) + m(arc DH) = 360°

     180° + 53° + m(arc DH) =360°

     m(arc DH) = 360° - 233°

    m(arc DH) = 127°

Answer: 4,2,3,1,5,6

Step-by-step explanation:

Plato

Answer:

223.

Step-by-step explanation:

Money in hand = 130

Spent on transportation = 25

Received from friend = 125

Spent on fruits = 82

Received from mother = 75

So, Current money in hand = Money in hand - Spent on transportation + Received from friend - Spent on fruits + Received from mother

= 130 - 25 + 125 - 82 + 75

= 223

Hence, she has now 223.

Answer:

Around 33.33% increase

Step-by-step explanation

Answer:

54

Step-by-step explanation:

You add 5+19 and divide my 2

Given:

The equation is:

[tex]4x+2xy^2+44=y^3[/tex]

To find:

The equation of the tangent on the given equation at point (-3,2).

Solution:

We have,

[tex]4x+2xy^2+44=y^3[/tex]

Differentiate with respect to x.

[tex]4(1)+2[x(2yy')+y^2(1)]+0=3y^2y'[/tex]

[tex]4+4xyy'+2y^2=3y^2y'[/tex]

[tex]4+2y^2=3y^2y'-4xyy'[/tex]

[tex]4+2y^2=(3y^2-4xy)y'[/tex]

Isolate y'.

[tex]\dfrac{4+2y^2}{3y^2-4xy}=y'[/tex]

Now, we need to find the value of the derivative at point (-3,2).

[tex]y'_{(-3,2)}=\dfrac{4+2(2)^2}{3(2)^2-4(-3)(2)}[/tex]

[tex]y'_{(-3,2)}=\dfrac{4+8}{12+24}[/tex]

[tex]y'_{(-3,2)}=\dfrac{12}{36}[/tex]

[tex]y'_{(-3,2)}=\dfrac{1}{3}[/tex]

It means the slope of the tangent line is [tex]\dfrac{1}{3}[/tex].

The equation of tangent line that passes through the point (-3,2) with slope [tex]\dfrac{1}{3}[/tex] is:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-2=\dfrac{1}{3}(x-(-3))[/tex]

[tex]y-2=\dfrac{1}{3}x+1[/tex]

[tex]y=\dfrac{1}{3}x+1+2[/tex]

[tex]y=\dfrac{1}{3}x+3[/tex]

Therefore, the equation of tangent line is [tex]y=\dfrac{1}{3}x+3[/tex].